The polygons in each pair are similar. Find the scale factor of the smaller figure to the largerfigure. (Question 10)

Answer:

y=logx +5 is the transformed function of the given function,

Explanation:

Since given function y= logx

According to the graph, the transformed function is getting after shifting the function by 5 units upward.

Thus, transformed function must be equal to the parent function+5.

Therefore, required transformed function will be y = parent function+5⇒y=logx+5.

Answer: 20 loaves

Step-by-step explanation:

3/5 = .6

12/.6 = 20

I’m not 100% sure but this is what I believe is the answer

20 Loaves

Answer:

6 bags will be filled

Step-by-step explanation:

Here, we want to know the number of bags of trail that can be filled

From what we have in the question, each bag will hold 1/8 = 0.125

So we want 0.75 split into smaller bits of 0.125 each

The number of possible fillings will be;

0.75/0.125 = 6

The equations that have y-coordinate of the y-intercept as positive is 3. h(x) = (x - 1)² and 5. b(x) = (x + 1)(x + 2).

We have,

The graph's intersection with the y-axis is known as the y-intercept. Finding the intercepts for any function with the formula y = f(x) is crucial when graphing the function. An intercept can be one of two different forms for a function. The x-intercept and the y-intercept are what they are. A function's intercept is the location on the axis where the function's graph crosses it.

The y-intercept is obtained when the x-coordinate is 0.

Thus, substitute the value of x = 0:

1. f(x) = x² + 3x - 2

f(x) = 0 + 3(0) - 2

f(x) = -2

False

2. g(x) = x² - 10x

g(x) = 0 - 10(0)

g(x) = 0

3. h(x) = (x - 1)²

h(x) = (0 - 1)²

h(x) = 1

True

4. m(x) = 5x² - 3x - 5

m(x) = 5(0) - 3(0) - 5

m(x) = -5

False

5. b(x) = (x + 1)(x + 2)

b(x) = (0 + 1)(0 + 2)

b(x) = 2

True

Hence, the equations that have y-coordinate of the y-intercept as positive is 3. h(x) = (x - 1)² and 5. b(x) = (x + 1)(x + 2).

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The feasible region is not empty and the objective function is bounded because it achieves its minimum value at the corner point (0, 0). Hence, the solution to the given LP problem is (x, y) = (0, 0).

Given an LP problem Minimize \(c = x + 2y\) subject to the constraints \(x + 3y ≤ 223 8x + y ≤ 23 x ≥ 0, y ≥ 0\)

Now we can start solving this LP problem by drawing the graph for the given constraints :

Plotting the constraints on a graph.

We can see that the feasible region is the shaded region bounded by the lines x = \(0, y = 0, 8x + y = 23, and x + 3y = 223\)

Now we can check the corner points of this region for finding the optimal solution of the given problem.

Corner points of the feasible region are:

(0, 0), (0, 7.67), (2.88, 71.07), (23, 66.33), and (27.33, 65).

Now we can substitute these values of x and y into the objective function \(c = x + 2y\) and see which corner point gives us the minimum value of c.

The table below summarizes this calculation.

Corner point

\((x, y)c = x + 2y\) (0,0)0(0,7.67)15.34(2.88,71.07)145.03(23,66.33)112.67(27.33, 65)157.67.

Thus, we can see that the minimum value of the objective function \(c = x + 2y\) is achieved at (0, 0),

which is one of the corner points of the feasible region.

Therefore, the optimal solution of the given LP problem is \(x = 0\) and \(y = 0\)

Also, we can see that the feasible region is not empty and the objective function is bounded because it achieves its minimum value at the corner point (0, 0).

Hence, the solution to the given LP problem is \((x, y) = (0, 0)\)

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\( \: \: \: \: \: \: \red{ \underline{ \large{ \tt ꧁\: A \: N \: S \: W \: E \: R ꧂\: }}}\)

1. When Profit percent and Cost price are given , \( \large{ \tt{SP = \frac{CP(100 + P\%)}{100}}} \)

2. When Loss% & Cost price are given , \( \large{ \tt{SP = \frac{CP(100 - L\%)}{100}}} \)

3. When Profit / Gain percent and Selling price are provided , \( \large{ \tt{CP = \frac{SP \times 100}{100 + G\%} }}\)

4. When Loss % & SP are provided , \( \large{ \tt{CP = \frac{SP\times 100}{100 - L\%}}} \)

♡ Hope I helped ! ✧

☂ Have a wonderful day / night ! ☼

☃ \( \underbrace {\overbrace{ \mathfrak{Carry \: On \: Learning}} }\)✎

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Answer: 5) Decrease 6) -44.4%

Step-by-step explanation: Percent change formula is as follows: final - initial / initial

(10-18)/18 = -8/18 = 0.44444 to turn into a percent multiply by 100 to get 44.4 percent change when rounded

The result obtained when a decision alternative is chosen and a chance event occurs is known as consequence. The answer is: b.

When a decision alternative is chosen and a chance event occurs, the result is referred to as a consequence. A consequence represents the outcome or outcome state that arises from the combination of a decision and a chance event.

It is the result or effect that occurs based on the chosen alternative and the unpredictable element introduced by the chance event.

Consequences are an essential concept in decision theory and decision analysis, as they help evaluate the potential outcomes and impacts of different choices and events. By considering the consequences associated with each decision alternative, decision-makers can assess the desirability or utility of different outcomes and make informed choices.

Hence, the correct option is: b. consequence.

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The total number of samples will be 1109 .

Given ,

Margin of error 0.02

Here,

According to the formula,

\(Z_{\alpha /2} \sqrt{pq/n}\)

Here,

p = proportions of scientist that are left handed

p = 0.09

n = number of sample to be taken

Substitute the values,

\(Z_{0.01} \sqrt{0.09 * 0.91/n} = 0.02\\ 2.33 \sqrt{0.09 * 0.91/n} = 0.02\\\\\\\)

n ≈1109

Thus the number of samples to be taken will be approximately 1109 .

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B. The given k is a zero of the polynomial function.

To determine whether -5 is a zero of the polynomial function f(x)=x³+7x²+2x-40, we can use synthetic division. By dividing the polynomial by (x+5), we perform the following steps:

1. Write down the coefficients of the polynomial: 1, 7, 2, -40.
2. Bring down the first coefficient, 1, and multiply it by -5 to get -5.
3. Add -5 to the second coefficient, 7, to get 2. Multiply 2 by -5 to get -10, and add it to the third coefficient, 2, to get -8.
4. Multiply -8 by -5 to get 40, and add it to the fourth coefficient, -40, to get 0.
5. The last number in the synthetic division is 0, indicating that -5 is a zero of the function.
Therefore, the main answer is B. The given k is a zero of the polynomial function.

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The correct answer is c. Inferential Statistics.

Inferential statistics is the branch of statistics that allows for drawing conclusions about a population based on the information collected from a sample. When conducting research or surveys, it is often impractical or impossible to collect data from an entire population.

Instead, a representative sample is chosen, and inferential statistics are used to make inferences or predictions about the larger population. By analyzing the characteristics and patterns observed within the sample, inferential statistics enable researchers to make generalizations or draw conclusions about the population as a whole.

This process involves applying various statistical techniques, such as hypothesis testing and confidence intervals, to estimate population parameters and assess the reliability of the conclusions. Magnitude statistics, central tendency, and effect size are important concepts in statistics, but they do not specifically address the ability to draw population-level conclusions from sample data.

Magnitude statistics focuses on the size of the effect or relationship between variables, central tendency measures summarize the central values of a dataset, and effect size quantifies the strength of an effect or relationship.

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Given,

The fraction is

The fraction decomposed by Tammi is,

The fraction decomposed by Orlando is,

The fraction formed by the Tammi's decomposed form,

The fraction formed by the Orlando's decomposed form,

Here, the forming fraction is 1 3/4. Hence, both are correct.

Answer: The answer is 327

Explanation: 93×100/25 = 327

Answer:

Step-by-step explanation:

there are 60 minutes in an hour, so just multiply the 60 minutes by the amount of one minute (150)

150 x 60 =

9000

Answer:

143°

When solving angle problems, make sure to label the other angles (even the ones that are not asked) and use them to relate to each other to find the answer.

The following C code generates an arithmetic sequence with N terms using the given general term expression and recurrence relation:

#include <stdio.h>

int main() {

   int N;

   printf("Enter the number of terms: ");

   scanf("%d", &N);

   int sequence[N];

   sequence[0] = 1;

   for (int i = 1; i < N; i++) {

       sequence[i] = sequence[i - 1] + 2;

   }

   printf("The general term: ");

   for (int i = 0; i < N; i++) {

       printf("%d ", sequence[i]);

   }

   printf("\nThe recurrence relation: ");

   for (int i = 0; i < N; i++) {

       printf("%d ", sequence[i]);

   }

   return 0;

}

The program starts by including the necessary header file stdio.h for input and output operations.

The main() function is defined, which is the entry point of the program.

A variable N is declared to store the number of terms inputted by the user.

The user is prompted to enter the number of terms using the printf() function and the input is read using the scanf() function.

An array sequence of size N is declared to store the arithmetic sequence.

The first term of the sequence is assigned as 1 (sequence[0] = 1).

A loop is started from i = 1 to N - 1 to calculate the remaining terms of the sequence.

Inside the loop, each term is calculated using the recurrence relation: sequence[i] = sequence[i - 1] + 2.

After calculating the sequence, the program prints the general term by looping through the sequence array and displaying each term using the printf() function.

Similarly, the program prints the recurrence relation by looping through the sequence array and displaying each term.

Finally, the return 0 statement indicates successful program execution and the program terminates.

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Answer:

11 years 7 months 7 days(if 31 days a months) and change 7 days to 9 days if assuming 30 days a moths

Answer:

115 lbs = 52.16 kilograms

Step-by-step explanation:

115 pounds is a little over 52kg

inConsider the h(x) as the parental function

To determine the function g(x), there were two transformations performed to the parental function.

-First, they added 1 to the x-term, which results on a horizontal translation of one unit to the left

-Second, there were subtracted 8 units to the function, which results in a vertical translation down:

So the function g(x) has the same shape as function h(x) but its vertex is on the coordinates (-1,-8)

Answer: Substitute the value of the variable into the equation and simplify.

−

408

v

a

2

l

u

t

e

2

−

14

Step-by-step explanation:

Answer: 6.3

Step-by-step explanation:

Answer:

28.47

Step-by-step explanation:

Answer:

F

Step-by-step explanation:

Given

\(\frac{a^2-b^2}{2+d^3}\) ← substitute given values into the expression

= \(\frac{6^2-4^2}{2+(\frac{1}{2}) ^{3} }\)

= \(\frac{36-16}{2+\frac{1}{8} }\)

= \(\frac{20}{\frac{17}{8} }\)

= \(\frac{20}{2.125}\)

≈ 9.4118 ( to 4 dec. places ) → F

To estimate the regression in the given model Yi = B0 + B1Xi + B2Ziui, where the variance of Ui is Σi^2 = Σ(zi^2), you can use the method of weighted least squares (WLS). The weights for each observation can be determined by the inverse of the variance of Ui, that is, wi = 1/zi^2.

In the given model, Yi = B0 + B1Xi + B2Ziui, the error term Ui is assumed to have a constant variance, given by Σi^2 = Σ(zi^2), where zi represents the individual values of Z.

To estimate the regression coefficients B0, B1, and B2, you can use the weighted least squares (WLS) method. WLS is an extension of the ordinary least squares (OLS) method that accounts for heteroscedasticity in the error term.

In WLS, you assign weights to each observation based on the inverse of its variance. In this case, the weight for each observation i would be wi = 1/zi^2, where zi^2 represents the variance of Ui for that particular observation.

By assigning higher weights to observations with smaller variance, WLS gives more importance to those observations that are more precise and have smaller errors. This weighting scheme helps in obtaining more efficient and unbiased estimates of the regression coefficients.

Once you have calculated the weights for each observation, you can use the WLS method to estimate the regression coefficients B0, B1, and B2 by minimizing the weighted sum of squared residuals. This involves finding the values of B0, B1, and B2 that minimize the expression Σ[wi * (Yi - B0 - B1Xi - B2Ziui)^2].

By using the weights derived from the inverse of the variance of Ui, WLS allows you to estimate the regression in the presence of heteroscedasticity, leading to more accurate and robust results.

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Answer: Since both terms are perfect squares, factor using the difference of squares formula,  

a 2  −  b 2 =  ( a + b )  ( a − b)  where  a = 11  and  b = x . ( 11+x) (11-x)

He will break even on the 25th month.

The cost to start the business is $20,000 and the monthly costs are $8,000.

He has been earning $8,800 every month in revenue.

Profit = Selling Price - Cost Price

Therefore,

let

x = number of month

Hence,

selling price = 8800x

cost price = 20000 + 8000(x) = 20,000 + 8000x

Therefore,

profit =  8800x - (20,000 + 8000x)

profit = 8800x - 20000 - 8000x

profit = 8800x - 8000x - 20000

profit = 800x - 20000

Hence,

The month when they will break even is as follows:

8800x = 20,000 + 8000x

20000 = 8800x - 8000x

20000 = 800x

x = 20000 / 800

x = 25

Therefore, he will break even on the 25th month.

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Answer:

the square root is 2.82

Step-by-step explanation:

24-16=8

√8=2.82

Classroom objects can be categorized as vertical or horizontal. Examples of vertical objects include doors, bookshelves, and clocks, while horizontal objects include desks, tables, and chairs.

In a classroom, there are many objects that are vertical and horizontal. Here are ten examples of each:

Vertical objects in a classroom:

1. Door                     6. Clock

2. Cabinet               7. Electrical outlets

3. Bookshelf            8. Light switches

4. Whiteboard         9. Window blinds

5. Flagpole             10. Bulletin board

Horizontal objects in a classroom:

1. Desks                  6. Keyboard trays

2. Chairs                 7. Carpet tiles

3. Tables                 8. Ceiling tiles

4. Countertops       9. Whiteboard markers

5. Shelves              10. Paper trays

These are just a few examples of vertical and horizontal objects that can be found in a classroom.

It is important to recognize the different shapes and orientations of objects in our environment, as they can affect the way we perceive and interact with them.

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