The net reaction of the calvin cycle is the conversion of co2 into the three-carbon sugar g3p. Along the way, reactions rearrange carbon atoms among intermediate compounds and use the atp and nadph produced by the light reactions. In this exercise, you will track carbon atoms through the calvin cycle as required for the net production of one molecule of g3p.

Answer:

\(F_A =5.625*10^1^6N\)

Explanation:

From the question we are told that

50,000 years ago,

A giant 4.5 107-kg meteor

180-m-deep hole

20,000 m/s

Generally for this problem the energy change is given as

       \(\triangle E=\frac{1}{2} mv^2 +mgd\)

Having the potential and kinetic energy in place

Mathematically  solving for Average force\(F_A\)

       \(\triangle E=F_a*d\)

\(F_A =\frac{1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160}{160}\)

Therefore Average force \(F_A\) is given by

\(F_A =5.625*10^1^6N\)

Answer:

B or D

Explanation:

The half-typical reaction's reduction potential is as follows: Mg = Mg2+(aq) + 2e- (s) is -2.36 V. To determine the reaction's standard reduction potential: 3Mg2+(aq) + 6e- 3Mg(s).

The Nernst equation may be used to determine how the standard reduction potential corresponds to the actual cell potential under non-standard circumstances: Ecell = (RT/nF)lnQ - E°cell where n is the total number of electrons transported during the reaction, Ecell is the cell potential, E°cell is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, F is the Faraday constant, and Q is the reaction quotient. The standard reduction potential for the reaction 3Mg(s) 3Mg2+(aq) + 6e- may be computed as follows: E°cell equals -(G°/nF) where G° is the reaction's standard Gibbs free energy change.

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Answer:

1 : 2 (30 : 60)

Explanation:

The rate of increase of the Earth's gravity field at latitudes 30° and 60° are in the ratio 1 : 2 because 30 : 60 simplified is 1 : 2.

If the answer does not ask for the ratio to be simplified leave its as 30 : 60.

By using the blackbody radiation formula, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

We need to know about black body radiation to solve this problem. The energy radiated by a black body object is proportional to the area and the fourth power of temperature. It can be determined as

P = A . e . σ . T⁴

where P is power, A is surface area, e is emissivity, σ is Stefan Boltzmann's constant ( 5.67 x 10¯⁸ W/m²K⁴) and T is temperature.

From the question above, we know that

P1 = 10 watt

P2 = 100 watt

T1 = T1

By using the black body radiation formula, the ratio of temperature is

T1⁴ / T2⁴ = P1 / P2

Hence,

T1⁴ / T2⁴ = P1 / P2

T1⁴ / T2⁴ = 10 / 100

T1⁴ / T2⁴ = 1 / 10

T2⁴ = 10T1⁴

T2 = ⁴√(10T1⁴)

T2 = T1 x 10⁰'²⁵

Thus, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

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The average speed of the ball at the given time of motion is 0.25 m/s.

The given parameters:

The average speed of the ball at the given time of motion is calculated as follows;

\(v = \frac{tota \ distance}{Total \ time} \\\\V = \frac{9}{18 + 18} \\\\V = 0.25 \ m/s\)

Thus, the average speed of the ball at the given time of motion is 0.25 m/s.

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Answer:

false is the answer . in my point of view

Responder:

Explicación:

La fórmula se utiliza para convertir grados Celsius (° C) en grados Fahrenheit (° F).

x ° C = (y ° F - 32) × 5/9.

Convertir 24 ° C a Fahrenheit

24 = (y ° F - 32) × 5/9.

24 * 9 = 5 (y ° F-32)

216 = 5 años ° F-160

5 ° F = 216 + 160

5 ° F = 376

y ° F = 376/5

y ° F = 75.2

24 ° C = 75.2 ° F

Para convertir Kelvin a Fahrenheit, usaremos la expresión;

(K - 273.15) × 9/5 + 32

Dado K = 24kelvin

24K a ° F = (24− 273.15) × 9/5 + 32

= -249.15 (9/5) + 32

= -448.47 + 32

= -416.47 ° F

24K = = -416.47 ° F

Answer:

the correct is the letter D

Wave variables

In the section on motion in two dimensions, we defined the phrases below to describe harmonic motion:

The amount by which a moving object deviates from its equilibrium position is known as its amplitude.

The number of events per unit of time is known as frequency.

Period is how long an oscillation lasts.

The underlying relevance of each of these factors for waves is the same. But it's helpful to express the ideas in a way that expressly mentions waves: Amplitude is the distance a wave travels between its resting state and its maximum movement.

The quantity of waves that pass by a specific location each second is known as its frequency.

Period is the length of time a wave cycle lasts.

In addition to their wave length and wave velocity, waves are determined by amplitude, frequency, and period.

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The three categories of atomic solids are network covalent, body-centered cubic, and face-centered cubic.

Network Covalent: Network covalent solids are composed of atoms connected by strong covalent bonds in a continuous three-dimensional network. This category includes substances like diamond and quartz. In these solids, each atom is bonded to its neighboring atoms through covalent bonds, forming a strong and rigid structure. Network covalent solids have high melting points and are generally hard and brittle.

Body-Centered Cubic (BCC): Body-centered cubic solids have a crystal structure in which atoms are arranged in a cubic lattice, with an atom located at the center of the cube and additional atoms at each corner. Iron and chromium are examples of metals that exhibit a body-centered cubic structure. BCC metals have relatively high melting points and good mechanical properties due to the close-packed arrangement of atoms.

Face-Centered Cubic (FCC): Face-centered cubic solids also have a cubic lattice structure, but in this case, there is an additional atom located at the center of each face of the cube. Examples of metals with a face-centered cubic structure include aluminum, copper, and gold. FCC metals have similar properties to BCC metals, with high melting points and good mechanical strength.


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Answer:

From spectral lines astronomers can determine not only the element, but the temperature and density of that element in the star.

Answer:

The answer would be the chemicals in the atmosphere of the star.

Answer:

The highest frequency electromagnetic waves are microwaves.

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Answer:

The single touch method of making a magnet is a simple way to magnetize a ferromagnetic material, such as a piece of iron. The process involves taking a magnet and bringing it into contact with the material to be magnetized, while moving it along the length of the material in a single direction. This process aligns the magnetic domains within the material, causing it to become magnetized. The strength of the resulting magnet depends on the strength of the magnet used and the length of time it is in contact with the material.

The process of making an electromagnet involves using an electric current to create a magnetic field. To make an electromagnet, a wire is wound into a coil around a magnetic core, such as an iron rod. When an electric current flows through the wire, it creates a magnetic field around the coil, which in turn magnetizes the magnetic core. The strength of the resulting magnet depends on the strength of the current flowing through the wire, the number of coils in the wire, and the type of magnetic core used. Electromagnets are commonly used in a variety of applications, including electric motors, speakers, and MRI machines.

Explanation:

First, we shall determine the equivalent of R₂ and R₃. Details below:

R = (R₂ × R₃) / (R₂ + R₃)

R = (9 × 3) / (9 + 3)

R = 2.25 Ω

Now, we shall determine the equivalent resistance, Rₜ for the circuit. Details below:

Rₜ = R₁ + R

Rₜ = 2 + 2.25

Equivalent resistance (Rₜ) = 4.25 Ω

The total current, Iₜ can be obtained as follow:

Current = Voltage / resistance

Iₜ = 34 / 4.25

Total current (Iₜ) = 8 A

Voltage in series connection are different.

V₁ is in series connection with the total voltage of V₂ and V₃. Thus, it's value can be obtained as follow:

V = IₜR₁

V₁ = 8 × 2

V₁ = 16 V

Voltage in parallel connection is the same through out the circuit.

Thus, V₂ and V₃ are in parallel connection. Thus we can obtain their value as follow:

V₂ = V₃ = IₜR

V₂ = V₃ = 8 × 2.25

V₂ = V₃ = 18 V

We can obtain I₁ as shown below:

I₁ = V₁ / R₁

I₁ = 16 / 2

current 1 (I₁) = 8 A

We can obtain I₂ as shown below:

I₁ = V₂ / R₂

I₂ = 18 / 9

current 2 (I₂) = 2 A

We can obtain I₃ as follow:

I₃ = V₃ / R₃

I₃ = 18 / 3

current 3 (I₃) = 6 A

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The student took five measurements of length using a centimeter ruler. The measured values were 21.4 cm, 23.8 cm, 19.3 cm, 17.4 cm, and 23.9 cm. To calculate the value with uncertainty using the center value with error method, first you need to find the average or mean of the measured values. This is done by adding the five measured values together and then dividing the sum by 5. In this case, the mean is 21.16 cm.

Next, you need to calculate the standard deviation. The standard deviation is a measure of how much the values differ from the mean. To calculate the standard deviation, first you need to subtract the mean from each of the measured values. Then, square each of the differences and add them together. Finally, divide the sum by the number of values minus one, which in this case is 4. The standard deviation is 1.45 cm.

Finally, the value with uncertainty using the center value with error method is 21.16 +/- 1.45 cm. This means that the student’s measured length is estimated to be 21.16 cm, with a margin of error of 1.45 cm.

To summarize, the student took five measurements of length with a centimeter ruler and used the center value with error method to calculate the value with uncertainty. This method involves finding the mean and standard deviation of the measured values, and then expressing the result as the mean +/- the standard deviation. In this case, the value with uncertainty is 21.16 +/- 1.45 cm.

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The acceleration of the particle after 1 minute is \(18 units/min^2.\)

To find the acceleration, we need to differentiate the position function twice with respect to time.

Given:

\(s(t) = 2t^3 + 3t^2 + t\)

To find the velocity, differentiate s(t) with respect to t:

\(v(t) = d/dt [2t^3 + 3t^2 + t]\)

\(v(t) = 6t^2 + 6t + 1\)

To find the acceleration, differentiate v(t) with respect to t:

\(a(t) = d/dt [6t^2 + 6t + 1]\)

\(a(t) = 12t + 6\)

Now, substitute t = 1 to find the acceleration after 1 minute:

\(a(1) = 12(1) + 6\)

\(= 12 + 6\)

\(= 18\)

Therefore, the acceleration after 1 minute is \(18 units/min^2\)

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The name of the substance is silver based on the specific heat capacity value.

The specific heat capacity of the substance is calculated by applying the following formula for heat capacity.

Q = mcΔθ

where;

c = Q / mΔθ

The specific heat capacity of the substance is calculated as;

c = (5875 J ) / ( 500 g x 50 )

c = 0.235 J/kgK

The substance that has the same specific heat capacity calculated above is silver.

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Given :

h= 1.57 m, x = 3.17 m, and vb = 3.03 m/s .

To Find :

The upward velocity \(v_b\) of cylinder .

Solution :

Component of \(v_a\) along string \(v_s= v_acos\ \theta\) .

Now ,

\(tan\ \theta=\dfrac{h}{x}\\\\cos\ \theta=\dfrac{x}{\sqrt{x^2+h^2}}\)

Now , from the figure :

\(2v_b=v_s\\\\2v_b=v_acos\ \theta\\\\v _a=\dfrac{2v_b}{cos\ \theta}\\\\v_a=\dfrac{2v_b\sqrt{x^2+h^2}}{x}\)

Putting all given values in above equation :

\(v_a=\dfrac{2\times 3.03\times \sqrt{3.17^2+1.57^2}}{3.17}\\\\v_a=6.76\ m/s\)

Therefore , value of \(v_a\) is 6.76 m/s .

Hence , this is the required solution .

Một đại lượng vectơ là một lực. Đại lượng vectơ là đại lượng có cả độ lớn và hướng, như chúng ta đã dạy trong phần trước. Bạn phải xác định cả độ lớn (kích thước hoặc số) và hướng của lực tác dụng lên một vật thể để mô tả hoàn toàn nó.

The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s

We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.

According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.

We know that;

\(F_{t}\) = \(p_{f}\) -\(p_{i}\)

F = force

t = time taken

\(p_{f}\)= final velocity

\(p_{i}\) = initial velocity

\(p_{f}\) = \(F_{t}\)  + -\(p_{i}\)

\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7

\(p_{f}\)  = 2.4 * 10^7 + 7.5 * 10^7

\(p_{f}\)  = 9.9 * 10^7 Kg m/s

Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.

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Missing parts;

A  space probe is traveling in outer space with a momentum that has a magnitude of  7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0  * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.

Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to decrease in strength

The strength of the magnetic field produced by an electromagnet decreases as the distance from the electromagnet increases. This means that if the distance between the electromagnet and the compass increases, the magnetic field that the compass is experiencing will weaken.

As a result, the observed effect of the compass will decrease in strength as the distance between the electromagnet and the compass increases.

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Answer:

1. 7,230,000

2. -8,120

3. 45.21

4. 61,240,000

5. 8,470

6. 956,300

7. 1,250,000,000

8. 63,330

9. 455,000

Its been a while since I learned this so Im really hoping that I remembered it correctly.

Answer:

•Helps to maintain va proper pH in the body which supports cell function.

•Carries electrolytes such as sodium and potassium to our muscles.

In 1957, Sputnik I was propelled into orbit around the planet. Its speed when it was at its perigee was was approximately 7.935 x 10^3 m/s.

The speed of an object in orbit around Earth can be calculated using the vis-viva equation:

v = sqrt(GM/(r))

where v is the velocity of the object, G is the gravitational constant, M is the mass of the Earth, and r is the distance of the object from the center of the Earth.

Given the perigee distance of 6.41 x 10^6 m and the mass of the Earth being 5.972 x 10^24 kg, the velocity of Sputnik I at its perigee would be:

v = sqrt((6.67 x 10^-11 N*(m^2)/(kg^2) * (5.972 x 10^24 kg)) / (6.41 x 10^6 m))

v = 7.935 x 10^3 m/s

So, the speed of Sputnik I when it was at its perigee was approximately 7.935 x 10^3 m/s.

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Answer:

Heyo!

Explanation:

Science, they would claim, can describe elements of the natural world but not explain them. For many scientists, this is a distinction without a difference. The Nobel Prize-winning physicist Steven Weinberg, an eloquent advocate for science's place in the realm of ideas, takes this distinction at face value - in order to demonstrate that science does indeed explain something.

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