The most likely cause of excessive body lean and sway while cornering is:
O Worn upper control arm bushings.
OA broken stabilizer link
O Sagged coil springs
O Worn strut rod bushings

The atmospheric pressure on earth is 1 atm. This pressure is equivalent to the mercuric pressure of 760 mmHg. The atmospheric pressure on the surface of Venus is 9200 kpa which is equivalent to 69017 mmHg.

Pressure is the force acting per unit area. In the atmosphere, the gaseous particles and dust exerts a pressure in the atmosphere. The atmospheric pressure depends on the temperature.

There are various units for pressure. Normally the atmospheric pressure is expressed in atm unit. The mmHg pressure is based on the raise in mercuric level with respect to increase in pressure.

1 mmHg = 0.0013133 atm

hence, 760 mmHg = 1 atm

On the surface of Venus, the pressure is 9200 kilopascal.

1 mmHg = 0.133 KPa

then 9200 KPa = 9200/0.133 = 69017 mmHg pressure.

Therefore, height of mercuric column will be 69017 mm in Venus surface.

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The decision of the country's highest court may then be appealing to that Supreme Court of both the U. S., but only in cases where the issue involves federal law.

In particular, followers of hip-hop, surfing, and post - punk culture will find their clothing appealing. Every person who appreciates streetwear will discover the ideal item thanks to Supreme's wide range of clothing.

Rebellious and distinctive brand image! Despite giving a venture - capital group a 50% ownership in the company, Supreme has been able to keep its skater roots and fan base. To top it all off, the Supremes' emblem is distinctive, outstanding, and simple to recognize.

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The final temperature of the mixture of ice and soda is equal to 5 °C with a specific heat of soda and ice.

From the given,

mass of soda = 12 oz

temperature (Ts) = 12.5 °C

mass of ice (Mice) = 0.17 Kg

The temperature of ice (Tice) = -19.5°C

Specific heat of ice (Cice) = 2090 J/kg°C

Specific heat of water (Cwater) = 4186 J/kg°C

Latent heat of fusion of ice (Lf) = 334 kJ/kg.

The final temperature (T₂)=?

Mass of water = 12 / 35.274 = 0.34 kg

The heat lost by soda = heat gained by the ice

heat (Q) = m×c×ΔT where m is mass, C is specific heat and ΔT is a change in temperature.

M(soda)×C(water)×ΔT = M(ice)×Lf + M(ice)×C(ice)(T₂-T₁) + M(ice)×C(w)(T₂-0)

0.34×4186×(T₂-12.5) = (0.17×334) + (0.17× 2090×(T₂ + 19.5)+ (0.17×4186×T₂)

17790.5 - 1423.24 (final temp)= 6985.13 + 711.62 (final temp)

10805.37 = 2134.56 (final.temp)

T₂= 10805.37 / 2134.56

   = 5 °C.

Thus, the final temperature of the mixture is 5°C.

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Answer:

The square of orbital period is proportional to the cube of the semi-major axis.

Explanation:

I just took the quick check

The charge R is positive and the charge L is negative hence, the correct option is option D.

The electric charges are of two types and they are positive and negative charge. There is an attractive force between the two charges. The electric field is formed around the charges and the electric field is denoted by using field lines around it.

The field lines are emerging from positive charge and end up in a negative charge. The field lines never intersect with each other. Hence, from the given, the field lines emerging from the positive charge(R) and end up in the negative charge(L).

Hence, the ideal solution is option D.

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Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

An independent-measures t hypothesis test is appropriate when - d.  there are two separate samples containing different subjects.

When you wish to compare the means of just two groups—no more, no less—use an independent samples t test! This test is typically used to detect whether two population means differ. This process employs samples to infer information about populations, making it an inferential statistical hypothesis test. The two sample t test is another name for the independent samples t test. You can reject the null hypothesis if the p-value is less than your threshold for significance (for example, 0.05). The two means difference is statistically significant. The data from your sample is convincing enough to support the conclusion that the two-population means are not equal.

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Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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Answer:

Ethene

Explanation:

although the correct term is Ethylene

Answer:

15mm

Explanation:

We know that for circular holes first dark spot is given by

sin စ = 1.22 λ/D

Also we know that at the same time

tan စ = r/L

So

r = L tanစ = 6 x tan( arcsin(1.22x 500 x10^9/0.50 x 10^ 3))

= 0.0073 m = 7.3 mm

However since the size is twice that so 14.6 mm which is approx 15mm

a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

Answer:

45kw45_32+675&453try to get it done

Answer:

A: 9 kg

Explanation:

on edge! hope this helps!!~ ∩(︶▽︶)∩

Explanation:

The application of total Internal Reflection occurs in a mirage. Option A

1) We know that a charge can be positive or negative. If the charge is negative, we call it an electron. If the charge is positive, we call it a proton. Now we know that the magnitude of charge on each electron is 1.6×10-19 C. Hence, the magnitude of charge on five electrons = 5 * 1.6×10-19 C = 8.0×10-19 C. Option D

2) The details of question 2 are not shown hence the question can not be answered.

3) Looking at the electronic configuration of the element;  1s22s22p63s23p5, it is clear to see that it has the ns2 np5 outermost configuration that is common to halogens thus it;

4) The atom is composed of the protons, neutrons and electrons. Given the nuclide identified as 230/92U we have  92 protons, 138 neutrons and 92 electrons. Option C

5) The application of total Internal Reflection occurs in a mirage. Option A

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Answer:

M = 50 kg / sec * 60 sec = 3000 kg       water that falls

PE = M g h     initial potential energy of water

PE = 3000 kg * 9.8 m/s^2 * 20 m = 588,000 joules of energy lost

Answer:

Period of a Mass on a Spring. The period of a mass m on a spring of spring constant k can be calculated as T=2π√mk T = 2 π m k .

Explanation:

Answer:

We are given:

V1 = 5.5L          T1 = -38 C   or   235 k

V2 = 1.3L           T2 = T

From the gas equation:

PV = nRT

Since the pressure (P) , number of moles (n) and the universal gas constant (R) are constants, we can write the same equation as:

V / T = k  (where k is a constant)

so a bit more insight, since the values noted above are constant, when multiplied by each other, they will provide us with a constant number irrespective of the value of the variables

Changing the variables for the first case:

V1 / T1 = k   (where k is the same constant) ----------------(1)

Similarly,

V2 / T2 = k  (again, k has the same value)----------------(2)

From (1) and (2):

k is the common value

V1 / T1 = V2 / T2

Replacing the variables

5.5 / 235 = 1.3 / T

T = 1.3 * 235 / 5.5

T = 55.54 k

Therefore, at 55.54 K the gas will have a volume of 1.3L

Answer:

The current is \(I = 6.59*10^{-5} \ A\)

Explanation:

From the question we are told that

  The speed is  \(v = 5.48*10^{5} \ m/s\)

   The radius is \(r = 2.12 *10^{-10} \ m\)

Generally the period of the orbiting electron is mathematically represented as

        \(T = \frac{2 \pi * r }{v}\)    

=>    \(T = \frac{2 * 3.142 * 2.12 *10^{-10} }{ 5.48 *10^{5}}\)    

=>    \(T = 2.43 *10^{-15} \ s\)

Gnerally the effective current associated with this orbiting electron

     \(I = \frac{e}{T}\)

Here e is the charge on an electron with value  \(e = 1.60 *10^{-19} \ C\)

So

      \(I = \frac{1.60 *10^{-19}}{2.43 *10^{-15}}\)

=> \(I = 6.59*10^{-5} \ A\)

Answer:

they are identical.

Explanation:

use coulomb law. the size of that line is just to confuse students because some sick teacher gets off on making you miss points. coulombs law says the magnitude of electric field is proportional to the size of the charge. here they are all +/-1 they are the same.

The true statement is "The electric force between A and B is greater than the electric force between C and D." The correct answer is B.

Electric force, also known as Coulomb force, is the attraction or repulsion between electrically charged particles. It is a fundamental force of nature that arises from the interaction of charged particles with each other. Electric force is described mathematically by Coulomb's law, which states that the magnitude of the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The direction of the force depends on the sign of the charges, with like charges repelling each other and opposite charges attracting each other.

Here in the Question,

The electric force between two charged objects depends on the magnitude of the charges and the distance between them. In this case, object A has a positive charge and object B has a negative charge, so there is an attractive force between them. Object C also has a positive charge, but it is separated by a larger distance from the negative charge at point D, so the electric force between C and D is weaker than the force between A and B.

Option A is not true because the distance between A and B is smaller than the distance between C and D, so the forces cannot be identical in magnitude.

Option C is not true because, as explained above, the force between A and B is greater than the force between C and D.

Option D is not true because the forces between A and B and between C and D are not opposite in direction, so they cannot cancel each other out.

Therefore, The correct answer is B. The electric force between A and B is greater than the electric force between C and D.

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The current flowing through the 1Ω resistor in the circuit is 0.66 A.

The emf of the cells, V = 1.1 V

Internal resistance of the cells, r = Ω

Resistance across the circuit, R = 1 Ω

According to Kirchhoff's current law, the total current flowing into and out of a junction in an electrical circuit is equal.

According to Kirchoff's current law,

(1.1 - V'/2) + (1.1 - V'/2) + (1.1 - V'/2) = V'/1

3/2(1.1 - V') = V'

3.3 - 3V' = 2V'

5V' = 3.3

Therefore, the terminal velocity of the battery is,

V' = 3.3/5

V' = 0.66 V

Therefore, according to Ohm's law, the current flowing through the 1Ω resistor is given by,

I = V'/R

I = 0.66/1

I = 0.66 A

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Answer:

theory of plate tectonics

Explanation:

Answer:

What he said above me

Explanation:

I did the test and it was right

Answer:

36 kmp or 22.37 mph

The height to which the spans rise when they buckle is 2.04 m

thermal expansion is given as :

ΔL = αLΔT

Where:

ΔL = change in length

α = coefficient of thermal expansion

L = original length

ΔT = change in temperature

Calculate  the change in length of the bridge spans:

ΔL = αLΔT

ΔL = (1.2 x 10^-5) x (400) x (20)

ΔL = 0.096 m

We apply Pythagorean theorem to find the height to which the spans rise when they buckle:

h^2 = (400 + 2ΔL)^2 - 400^2

h^2 = (400 + 2(0.096))^2 - 400^2

h^2 = 4.1664

h = 2.04 m

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Answer:

1500kg

Explanation:

Assuming that the women push the car in the same direction, then the total force is:

Fnet = 425 N ⋅  3

= 1275 N

To find the mass, we use Newton's second law of motion, which states that,

F = ma

where:

   ·F is the force applied in newtons

   ·m is the mass of the object in kilograms

   ·a is the acceleration of the object in meters per second squared.

So we get:

        F

m=  ⁻⁻⁻⁻⁻

        a

     1275N

= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

  0.85 m/s²

=  1500 kg

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Answer: headline, dateline, introduction

Explanation: its correct im not explaining

Answer:

Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).

Explanation:

The force required to accelerate an object can be calculated using the formula:

force = mass x acceleration

where "mass" is the mass of the object being accelerated, and "acceleration" is the rate at which the object's velocity is changing.

In this case, the mass of the object is 500 kg, and the acceleration is 10 m/s^2. Plugging these values into the formula gives:

force = mass x acceleration

force = 500 kg x 10 m/s^2

force = 5000 N

Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).