The equation used for calculating work in symbols?

see

below

Explanation:

refractive index = speed of light in vacuum / speed of light in medium

light travels at a speed of 3.0 x 10^8 m/s in vacuum

refractive index = 3.0 x 10^8 / 2.0 x 10^8

refractive index = 1.5

hope this helps, please mark it

Answer:

The net displacement is

\(R= \sqrt{A^2+B^2+2AB \cos \theta}\)

\(=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m\)

Explanation:

Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement

Given data

A = 15 m

B = 25 m

Angle between the vectors A and B is θ = 30°

The net displacement is

\(R= \sqrt{A^2+B^2+2AB \cos \theta}\)

\(=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m\)

Answer:

1. B

2. B

3. D

4. A

Hope this was correct! A lot of the answers are already in the article itself and the wording is just different. I suggest now that for information retainment, you read the article again with the correct points in mind and see if you can spot the points where the answers are stated!

The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.

The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.

Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.

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Metallic conductivity refers to the ability of metals to conduct electricity due to the presence of free electrons in their structure, while electrolytic conductivity refers to the ability of solutions to conduct electricity due to the movement of ions within the solution.

Conductance is the measure of a material's ability to conduct an electric current, and it is defined as the reciprocal of resistance. The SI unit of conductance is the siemens (S).

The concentration of ions in a solution can affect its conductivity. Generally, the higher the concentration of ions in a solution, the higher its conductivity. This is because a higher concentration of ions provides more particles that can move and conduct an electric current. However, this relationship is not always linear and can depend on the specific properties of the ions and the solution.

Answer:

796110

Explanation:

(4.81)(1000)+7.913(105)

=4810+7.913(105)

=4810+(7.913)(100000)

=4810+791300

=796110

(C) 200 N

Explanation:

The acceleration due to gravity on earth \(g_{E}\) is given by

\(g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}\)

where \(G\) = universal gravitational constant

\(\:\:\:\:\:\:\:\:\:\:\:\:M_{R}\) = mass of the earth

\(\:\:\:\:\:\:\:\:\:\:\:\:R_{E}\) = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity \(g_{K}\) is

\(g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}\)

\(\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}\)

\(\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}\)

or

\(g_{K} = (\dfrac{2}{9})\:g_{E}\)

If we multiply both sides by Superman's mass, we get his weights on both planets:

\(mg_{K} = (\dfrac{2}{9})\:(mg_{E})\)

\(W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N\)

Comets circle the Sun in an elliptical orbit. They can spend hundreds of thousands of years in the depths of the solar system before returning to the Sun at perihelion. Kepler's Laws apply to comets, as they do to all other circular bodies.

Comets are thought to circle the sun in either the Oort cloud or the Kuiper belt. As another star passes through the solar system, its gravity pulls the Oort cloud and/or Kuiper belt lower, forcing comets to fall into a highly elliptical orbit around the sun.

The Sun's gravitational influence on the comet is not proportional to its velocity.

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just ask safari

Explanation:

The speed of the proton is 3.81 × 105 m/s, the radius of the path is 1.25 × 10-3 m, the radius of the path is 9.13 × 10-3 m,  the radius of the path is 3.99 × 10-3 nm.

(a) The formula to calculate the speed of a proton moving in a circular path with the same radius as an electron is:

v = r B q/m

Here, r = radius of the circular path

B = strength of the magnetic field

q = charge of the particle

m = mass of the particle

v = velocity of the particle Substituting the given values of r, B, and m and solving for v:7.30 × 106

v= 3.81 × 105 m/s Therefore, the speed of the proton is 3.81 × 105 m/s.

(b) The formula to calculate the radius of the path of a proton with the same speed as an electron is: r = m v / q B Here, m = mass of the particle

v = velocity of the particle

q = charge of the particle

B = strength of the magnetic field Substituting the given values of m, v, and q and B as the proton has the same speed as the electron: = 1.25 × 10-3 m Therefore, the radius of the path is 1.25 × 10-3 m.

(c) The formula to calculate the radius of the path of a proton with the same kinetic energy as an electron is:r = (m_{1} / m_{2})^{1/2} r_{2}Here,

m1 = mass of the proton

m2 = mass of the electron

r2 = radius of the path of the electron Substituting the given values of m1 and m2 and r2 as 7.30 × 106:

r = 9.13 × 10-3 m Therefore, the radius of the path is 9.13 × 10-3 m.

(d) The formula to calculate the radius of the path of a proton with the same momentum as an electron is:r = p / q BHere, p = momentum of the electron

q = charge of the particle

B = strength of the magnetic field Substituting the given value of p and q and B as 7.30 × 10-31 kg m/s and 1.60 × 10-19 C and 1.10 × 10-5 T: r = 3.99 × 10-3 nm Therefore, the radius of the path is 3.99 × 10-3 nm.

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Answer:

Explanation:

We are basically needing to solve for the time in the equation d = rt, where d is the distance around Mars (aka the circumference), r is the velocity, and t is time. We need to find the circumference and the velocity. We will begin with the velocity.

Because the gravitational attraction between Phobos and Mars provides the centripetal acceleration necessary to keep Phobos in its (sort of) circular path, the equation we use for this is:

\(F_g=F_c\) which says that Force supplied by gravity is equal to the centripetal force. Expanding that:

\(\frac{Gm_{Phobos}m_{Mars}}{r^2}=\frac{m_{Phobos}v^2}{r}\)

When we move that around mathematically to solve for the velocity value, what we end up with is:

\(v=\sqrt{\frac{Gm_{Mars}}{r}\) and filling in:

\(v=\sqrt{\frac{(6.67*10^{-11})(6.42*10^{23})}{9.38*10^6} }\) and we get that

v = 2100 m/s

Now for the circumference:

C = 2πr and

C = 2(3.1415)(9.38 × 10⁶) so

C = 5.9 × 10⁷

Putting that all together in the C = vT equation:

5.9 × 10⁷ = 2100T so

T = 2.8 × 10⁴ sec or 7.8 hours

Answer:

C: Maximum potential energy is at point R

Explanation:

Just did test

1. The momentum of the bowling ball after the force was applied is 397.5 Ns.

2. The bowling ball is moving at a speed of 48.7 m/s.

The difference of time between a sound from the stage reaching your ear directly and the same sound reaching your ear after reflecting from the back wall would be 0.036s.

An echo is a reflection of sound that comes to the audience with a delay after the direct sound in audio signal processing and acoustics. The delay is directly proportionate to the separation between the source and the listener of the reflecting surface. One the kind audio effect that involves significantly delaying a signal is an echo effect. In this instance, after some period of time, listeners hear the same signal repeated clearly. When there is a noticeable delay in the sound, listeners can differentiate individual echoes.

The person seated in the middle row:

The distance sound traveled to middle row => 25/2 = 12.5m

The total distance the sound traveled to full length of auditorium and to the middle row => 25+12.5 => 37.5m

t1 => d1/v => 12.5/343 => 0.036s

t2 => d2/v => 25/343 => 0.072s

t2-t1 => 0.036s

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True. The active elements of fractal computation are indeed the pixels, which are the individual units that make up a digital image.

Fractal computation involves performing complex calculations and iterations on these pixels to generate the intricate patterns and structures that characterize fractals.

True. In the context of fractal computation, the active elements are the pixels, as they represent the individual data points that are calculated and displayed to form the fractal image.

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A. Total momentum in a closed system is conserved

the law of momentum conservation states that The total amount of momentum before the collision is the same as the total momentum after the collision. Regardless of the change of momentum of each object.

Answer:

Explanation:

An atom losses or gains electrons to fill the outermost shell. In this process , ionic bonds are formed. Chemical bonds are formed when electrons are shared.

Using the formula Ma=Rw/Ra, the mechanical advantage may be determined by only comparing the circumference of the spin to the circumference of axle. It is not a mechanical wheel called an MA= FE/FR.

One of three pieces that make up the Mechanical Cart, the Mechanical Wheel Component may be found in a Treasure Bag after defeating The Sisters in Expert Mode.

The Hardmode item known as The Clockwork Worm is used to call forth The Destroyer. The Worm is Made from Night Souls. Iron, copper, and rotten chunks at quite a Mythril Hammer station. When used at night, it transports the player to The Destroyer.

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Sorry your tired, ill try to make it worth reading.

One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.

Answer:

0.9 m

Explanation:

Hooke’s Law

\(\large\boxed{F = ke}\)

where:

Given values:

Substitute the given values into the formula to find k:

\(\implies 2.0=0.30k\)

\(\implies k=\dfrac{2.0}{0.30}\)

\(\implies k=\dfrac{20}{3}\; \sf N/m\)

To find the extension if the force applied is 6 N, substitute the found value of k and the given value of F into the formula and solve for e:

\(\implies 6=\dfrac{20}{3}e\)

\(\implies 18=20e\)

\(\implies e=\dfrac{18}{20}\)

\(\implies e=0.9\; \sf m\)

Option B, C, and E are correct. First principle of motion options that address the issue include Before an item may move, it must be subjected to a net force. The inertia rule is another term for the first principle of Newton's theory of motion.

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Complete question: Inertia is an object's natural tendency to remain in constant motion or at rest. An object moving through outer space, for example, will continue moving in one direction and at a constant speed due to its inertia, if no other forces act on it. Why do planets constantly change the direction in which they move?

A. Most planets do not have any inertia, so their motion constantly changes.

B. The force of gravity acts on planets and changes the direction of their motion.

C. Each planet's inertia is constantly changing from one moment to the next.

D. There are no forces acting on the planets as they move in orbits around the Sun.

The rocket will cover \(1 \times 10^3\rm \ m\) distance in 4. 5 s. Acceleration can be defined as the change in velocity.

Acceleration can be defined as the change in speed or the direction of the object.

From kinamatic equation:

\(D = v_{t} +\dfrac 12at^2\)

Where,

\(D\) - final velocity =  445 m/s

\(v_0\) -  initial valocity = 0 m/s

\(a\) - acceleration = 99. 0 m/s²

\(t\) - time =  4. 50 s

Put the values in the formula,

\(D = 0\times ( 4.5) + \dfrac12\times (99)(4.5)^2\\\\D = 1002 {\rm \ m}\\\\D = 1 \times 10^3\rm \ m\)

Therefore, the rocket will cover \(1 \times 10^3\rm \ m\) distance in 4. 5 s.

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The largest measurement is 10 km, followed by 10 m, 10 cm, 10 mm, and finally 10 nm as the smallest measurement.

To order these length measurements from largest to smallest. Here's the ordered list:

1. 10 km (10,000 meters)
2. 10 m (10 meters)
3. 10 cm (0.1 meters)
4. 10 mm (0.01 meters)
5. 10 nm (0.00000001 meters)

An object or event's attributes are quantified through measurement so that they can be compared to those of other things or occurrences. Measurement, then, is the process of establishing how big or little a physical quantity is in relation to a fundamental reference quantity of the same kind.

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The crown is not made up of pure gold as its density which is calculated is observed to be less than that of the pure gold.

The formula for an object's density is ρ = m/v.

where,

m is mass

v is volume

Mass of the crown is given as 1 kg.

When submerged in water, its mass becomes 0.92 kg.

So, volume of water displaced is 0.08 L.

Density of pure gold is given as, ρ gold = 19.3 kg/L

The amount of water that is displaced has the same volume as the crown. Let us calculate the density of crown,

ρ crown = m/v = 1/0.08 = 12.5 kg/L

Comparing the above obtained value with the density of pure gold we have, ρ crown < ρ gold.

Thus, the crown is not made up of pure gold.

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The estimated set-up time for the D Flip-flop circuit in a Master/Slave configuration using Transmission Gate MUXs and the CMOS RC Delay model approach is [insert value]. The estimated hold time is [insert value].

In a D Flip-flop circuit constructed in a Master/Slave configuration, the set-up time refers to the minimum amount of time required for the input data signal (D) to be stable before the clock signal (CLK) transitions. The hold time, on the other hand, refers to the minimum amount of time that the input data signal (D) must remain stable after the clock signal (CLK) transitions.

To estimate the set-up time and hold time, we can consider the CMOS RC Delay model approach, which takes into account the delays caused by the resistance and capacitance in the circuit. Additionally, we will use Transmission Gate MUXs in the latches to facilitate the data transfer.

The wider transistors in the circuit, being 3.5 times wider than standard, result in lower resistance and thus reduce the RC delay. The standard resistance value of 12k Ohms is used as a reference for calculations. Similarly, the standard capacitance of 0.18ff is considered.

The loading in the circuit consists of identical inverters that are 4 times wider than the standard size. However, the interconnection wiring loading is ignored for simplicity.

By analyzing the specific circuit design and the given parameters, we can calculate the estimated set-up time and hold time values.

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The gravitational potential energy of an object depends on its mass, height, and the strength of the gravitational field.

The formula for gravitational potential energy is:

PE = mgh.  

A gravitational field is a region in space around an object where the force of gravity is felt. All objects with mass have a gravitational field, and the strength of the gravitational field depends on the mass of the object and the distance from the object. The concept of a gravitational field was first introduced by Isaac Newton, who developed the law of universal gravitation. According to this law, the force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them.  

The gravitational field is the vector quantity that describes the direction and strength of the force of gravity at any point in space. The gravitational field is a fundamental concept in physics and has many important applications, including in celestial mechanics, where it is used to describe the motion of planets and other celestial objects. The study of gravitational fields has also led to many important discoveries in cosmology, including the existence of black holes and the large-scale structure of the universe.

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The efficiency of the machine is 50%.

What is an of efficiency of a machine?

The efficiency of a machine is determined by its ability to perform a task with minimal waste of energy or resources. Efficiency can be measured in terms of energy, time, cost, or quality of output. Factors that affect efficiency include the design of the machine, the quality of its components, and the skill of its operator.

 An example of the efficiency of a machine is a washing machine that uses less energy and water to get the same amount of clothing clean as a traditional machine.

The efficiency of the machine can be calculated using the formula:

Efficiency = (Output Work / Input Work) x 100%

Output Work = ma * height = 500 kg * 20 m = 10000 J (Joule)

Input Work = Power * Time = 2000 W * 10 s = 20000 J (Joule)

Efficiency = (10000 J / 20000 J) x 100% = 50%.

So the efficiency of the machine is 50%.

Therefore, 50% is the answer.

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The mass of Rhea, one of Saturn's moons, can be calculated using its radius and acceleration due to gravity at its surface.

The mass of  Rhea, one of Saturn's 62 moons, has a radius of 764 km and an acceleration due to gravity of 0.265 m/s2 at its surface. Using the formula for acceleration due to gravity, GM/R² = g, where G is the gravitational constant, M is the mass of the object (in this case, Rhea), R is the radius of the object (in this case, the radius of Rhea), and g is the acceleration due to gravity at the surface of the object, we can calculate the mass of Rhea to be approximately 2.31 x 10²¹ kg.

This calculation assumes that Rhea has a uniform density throughout its interior, which is a common assumption for small celestial bodies like moons.

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When x = 13, the right-hand side of the equation is equal to 702720. Therefore, the dimensions of the box are 154 by 288 by 26.

The volume of the box is given by the formula:

V = lwh

where:

V is the volume in cubic inches

l is the length in inches

w is the width in inches

h is the height in inches

We are given that the volume of the box is 702720 cubic inches. We are also given that the piece of material is 167 inches long and 301 inches wide. When we cut squares from each corner, the length and width of the piece of material are reduced by 2x inches. The height of the box is also 2x inches.

We can write the following equation to represent the volume of the box:

702720 = (167 - 2x)(301 - 2x)(2x)

We can solve for x by expanding the left-hand side of the equation and then using trial and error to find a value of x that makes the right-hand side equal to 702720.

When x = 13, the right-hand side of the equation is equal to 702720. Therefore, the dimensions of the box are 154 by 288 by 26.

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The equation to determine the maximum distance the spring will be compressed when the car hits it is x = \(\sqrt{(2mgh)/k}\).

When the car rolls down the hill, it gains kinetic energy equal to its potential energy at the top of the hill: mgh. This kinetic energy will be transferred to the spring upon impact with the crash barrier. The spring will compress until all the kinetic energy is stored as potential energy in the spring.

Using the conservation of energy principle, we can equate the initial potential energy of the car with the potential energy stored in the compressed spring:
mgh = (1/2)kx²

where x is the maximum distance the spring will be compressed. Solving for x, we get:
x = \(\sqrt{(2mgh)/k}\)

So, the maximum distance the spring will be compressed is dependent on the mass of the car (m), the height of the hill (h), the spring constant (k), and the acceleration due to gravity (g).

In summary, the equation to determine the maximum distance the spring will be compressed when the car hits it is x = \(\sqrt{(2mgh)/k}\).

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