Tell whether the conditional is true (T) or false (F).
(3^(2)#16) -> (5+5 =10)
The conditional is ____ becausethe antecedent is____ and the consequent is ____

Answers

Answer 1

The conditional is True (T) because the antecedent is false (3^(2) > 16) and the consequent is True (5 + 5 = 10).

Let's evaluate the conditional statement correctly.

The conditional statement is: (3^(2) > 16) -> (5 + 5 = 10)

To determine the truth value of this conditional statement, we need to evaluate both the antecedent and the consequent.

Antecedent: 3^(2) > 16

This is False because 3^(2) = 9, which is not greater than 16.

Consequent: 5 + 5 = 10

This is True because 5 + 5 does equal 10.

Since the antecedent is False and the consequent is True, the conditional statement as a whole is False (F).

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Related Questions

11. Kevin started a ping pong club at his school,
and the table shows the number of participants
in the club over several years. Find the rate of
change in the number of participants.

Answers

Answer:

16

Step-by-step explanation:

Add 16

Answer:

16

Step-by-step explanation:

Question involving derivatives and limits...

What is the limit as x approaches 2 of (3 f(x) - 15) / (x-2)... where f(2) is 5. The answer is not 0, I checked.
the derivative f'(2) is 1/8 in case that's needed

it can be either 3/8, , 3.545, or 3/2

Answers

Answer:

undefined

Step-by-step explanation:

Elimination method of solving linear equations7x+4y=29x-4y=30

Answers

Answer:

x = 2, y = -3

Explanation:

Given the simultaneous equation

7x+4y=2

9x-4y=30​

Add both equations

7x + 9x = 2 + 30

16x = 32

x = 32/16

x = 2

Substitute x = 2 into equation 1

From 1;

7x + 4y = 2

7(2) + 4y = 2

14 + 4y = 2

4y = 2-14

4y = -12

y = -12/4

y = -3

Hence the solution to the equation is (2, -3)

Angie runs 7 mph for the first half of a marathon, 13.1
miles, but twists her knee and must walk 2 mph for the
second half. What was her average speed? Round to 2
decimal places.

Answers

Answer:

Step-by-step explanation:

For the first half of the Marathon, we need to find the time.

t = d/r

r = 7 mph

d = 13.1

t = 13.1 / 7

t = 1.87 hours.

For the second half of the Marathon we need the time as well.

t = d/r

r = 2 mph

d = 13.1

t = 13.1 / 2

t = 6.55 hours.

Now to find the average speed, you will need the total time and the total distance

Total distance = 13.1 + 13.1 = 26.2 miles

Total time = t1 + t2

Total time = 1.87 hours + 6.55 hours.

Total time =  8.42

average speed = Total Distance / total time

average speed = 26.2 / 8.42 = 3.11 miles per hour

whatsssss those fromm greatesttt to leassttt

whatsssss those fromm greatesttt to leassttt

Answers

greatest to smallest :  \(= \sqrt[3]{88} ,\sqrt{19} ,\frac{28}{9}\)

Fraction: A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, in which the numerator is divided by the denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator

Square root: In mathematics, a square root of a number x is a number y such that y² = x; in other words, a number y whose square is x. For example, 4 and −4 are square roots of 16, because 4² = 16

Use this fraction calculator for adding, subtracting, multiplying, and dividing fractions. Answers are fractions in the lowest terms or mixed numbers in reduced form.

Input proper or improper fractions, select the math sign, and click Calculate. This is a fraction calculator with steps shown in the solution.

If you have negative fractions insert a minus sign before the numerator. So if one of your fractions is -6/7, insert -6 in the numerator and 7 in the denominator.

A fraction is a part of a whole. In arithmetic, the number is expressed as a quotient, in which the numerator is divided by the denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator.

Solution :

\(\sqrt[3]{88} \\\sqrt[3]{2.2.2.11} \\2\sqrt[3]{11} \\\sqrt[3]{11} = 2.224\\2.2.224\\4.448 ...(1)\\\\\\\frac{28}{9} = 3.333 ...(2)\\\\ \sqrt{19} = 4.359 ...(3)\\\\Form 1 , 2 & 3 \\\\greatest number to smallest number = 4.448 , 4.359 ,3.333\\= \sqrt[3]{88} ,\sqrt{19} ,\frac{28}{9}\)

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Write a story that can be represented using the equation y=x+1/5x

Answers

A story that can be represented using the equation y=x+1/5x is "John has an apple and he cut another apple into 5 equal parts and took on part. What's the rural fraction of apple that he has?

How to illustrate the equation?

An equation is the statement that illustrates the variables given. In this case, two or more components are taken into consideration to describe the scenario. It is vital to note that an equation is a mathematical statement which is made up of two expressions that are connected by an equal sign.

In this case, if John has an apple and he cut another apple into 5 equal parts and took on part.

This can be illustrated as:

y = x + 1/5x

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You are making a salad. The ratio of olives to croutons is 5 : 3. You put 12 croutons in your salad. How many olives do you put in your salad?

Answers

Answer:

20

Step-by-step explanation:

12/3 (the number of croutons) = 4

Since 4 is your base number, you would multiply 4 x 5.

20 olives

Answer:

20

Step-by-step explanation:

Ratio of olives : croutons is 5 : 3.

If you put 12 croutons, you put 4 times the amount of croutons in the ratio since 12/3 = 4.

That means you must also put 4 times the number of olives.

4 * 5 = 20

Answer: 20

Find the length of QR

Find the length of QR

Answers

Answer:

QR = 15

Step-by-step explanation:

The product of the length of the secant segment and its external part equals the square of the length of the tangent segment.

(QR+5) *5 = 10^2

(QR+5) *5 = 100

Divide each side by 5.

(QR+5) *5/5 = 100/5

(QR+5)  = 20

Subtract 5 from each side.

QR = 20-5

QR = 15

The sales tax on a $44.00 purchase is $2.42. At this rate, what would be the tax on goods worth $60.00?

Answers

Answer:

We can use proportions to find out the tax on goods worth $60.00:

Let x be the tax on goods worth $60.00.

Then, we can set up the following proportion:

tax/sales = tax rate

or

2.42/44 = x/60

To solve for x, we can cross-multiply and simplify:

44x = 2.42 * 60

44x = 145.20

x = 145.20/44

x = 3.3 (rounded to the nearest cent)

Therefore, the tax on goods worth $60.00 would be $3.30.

Step-by-step explanation:

Suppose that a certain population satisfies the initial value problem dy/dt = r (t) y - k, y(0) = y_0, where the growth rate r(t) is given by r(t) = (1 + sin t)/5, and k represents the rate of predation. (a) Suppose that k = 1/5. Plot y versus t for several values of y_0 between 1/2 and 1. (b) Estimate the critical initial population y_c below which the population will become extinct. (c) Choose other values of k and find the corresponding y_c for each one. (d) Use the data you have found in parts (b) and (c) to plot y_c versus k.

Answers

(a) The plot of y versus t for several values of y₀ between 1/2 and 1 shows oscillations with higher y₀ resulting in larger oscillations.

(b) The critical initial population \(y_c\) below which the population becomes extinct is \(y_c\) = 2.5k.

(c) For different values of k, the corresponding critical initial populations \(y_c\) are found

(d) The relationship between the critical initial population \(y_c\) and the predation rate k can be summarized as \(y_c\) = 2.5k.

(a) Plotting y versus t for several values of y₀ between 1/2 and 1:

To solve the initial value problem dy/dt = r(t) * y - k, y(0) = y₀, we need to integrate the differential equation numerically.

Given:

- r(t) = (1 + sin t) / 5

- k = 1/5

We can observe the following:

For each value of y₀ between 1/2 and 1, the population y will exhibit a fluctuating behavior over time. The sine function in r(t) causes the growth rate to oscillate, leading to oscillations in the population as well. The magnitude of the oscillations depends on the initial population y₀.

Higher values of y₀ will result in larger oscillations, while lower values will lead to smaller oscillations. As time progresses, the population may increase or decrease depending on the interplay between the growth rate and the predation rate.

(b) Estimating the critical initial population \(y_c\) below which the population will become extinct:

To estimate the critical initial population \(y_c\), we need to find the value of y₀ for which the population becomes extinct. This occurs when the population y drops to zero or a very small positive value.

For the given differential equation dy/dt = r(t) * y - k, we can see that when y is very close to zero, the rate of decrease (k) dominates over the growth rate (r(t) * y). Therefore, we can set up the following equation:

0 = r(t) * y - k

Solving this equation for y, we find:

y = k / r(t)

Substituting r(t) = (1 + sin t) / 5, we have:

y = 5k / (1 + sin t)

To find the critical initial population \(y_c\), we need to determine the smallest value of y for all t. Since the minimum value of sin t is -1, the smallest value of y is obtained when sin t = -1, yielding:

\(y_c\) = 5k / (1 - (-1))

   = 5k / 2

   = 2.5k

Therefore, the critical initial population \(y_c\) is 2.5 times the predation rate k.

(c) Choosing other values of k and finding the corresponding \(y_c\) for each one:

Let's consider different values of k and calculate the corresponding critical initial population \(y_c\) using the formula derived in part (b):

For k = 1/10:

\(y_c\) = 2.5 * (1/10) = 1/4 = 0.25

For k = 1/4:

\(y_c\) = 2.5 * (1/4) = 5/8 = 0.625

For k = 1/2:

\(y_c\) = 2.5 * (1/2) = 5/4 = 1.25

For k = 1:

\(y_c\) = 2.5 * 1 = 2.5

For k = 2:

\(y_c\) = 2.5 * 2 = 5

For k = 5:

\(y_c\) = 2.5 * 5 = 12.5

These are the corresponding critical initial populations \(y_c\) for different values of k.

(d) Plotting \(y_c\) versus k:

Using the values of \(y_c\) and k calculated in part (c), we can plot \(y_c\) versus k:

k       |   \(y_c\)

-------------------

1/10   |  0.25

1/4    |  0.625

1/2    |  1.25

1       |  2.5

2      |  5

5      |  12.5

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Suppose that a certain population satisfies the initial value problem dy/dt = r (t) y - k, y(0) = y_0,

____ : referring to the fact that the distance between two or more points is equal.

Answers

The term that refers to the fact that the distance between two or more points is equal is "equidistant".

In geometry, the concept of equidistance is important when dealing with circles, which are sets of points that are equidistant from a single point called the center. This property is what allows circles to be defined in terms of their radius, which is the distance between the center and any point on the circle.

Equidistance is also important in other areas of mathematics and science. For example, in physics, equidistant points can be used to define a plane or surface that is perpendicular to a given line or axis. This is useful in many applications, such as designing electronic circuit boards or constructing buildings.

The concept of equidistance is not limited to mathematics and science, however. It can also be applied in everyday life. For instance, if you are planning a road trip and want to visit several destinations that are equidistant from your starting point, you can use this information to help plan your route and estimate your travel time.

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Zaboca Printing Limited (ZPL) has only one working printer. Eight (8) customers submitted their orders today Monday 6th June 2022. The schedule of delivery of these orders are as follows:

Jobs (in order of arrival) Processing Time (Days) Date Due
A 4 Monday 13th June 2022
B 10 Monday 20th June 2022
C 7 Friday 17th June 2022
D 2 Friday 10th June 2022
E 5 Wednesday 15th June 2022
F 3 Tuesday 14th June 2022
G 8 Thursday 16th June 2022
H 9 Saturday 18th June 2022
All jobs require the use of the only printer available; You must decide on the processing sequence for the eight (8) orders. The evaluation criterion is minimum flow time.

i. FCFS

ii. SOT

iii. EDD

iv. CR

v. From the list (i to iv above) recommend the best rule to sequence the jobs

Answers

The recommended rule to sequence the jobs for minimum flow time is the EDD (Earliest Due Date) rule.

The EDD rule prioritizes jobs based on their due dates, where jobs with earlier due dates are given higher priority. By sequencing the jobs in order of their due dates, the goal is to minimize the total flow time, which is the sum of the time it takes to complete each job.

In this case, applying the EDD rule, the sequence of jobs would be as follows:

D (Due on Friday 10th June)

F (Due on Tuesday 14th June)

E (Due on Wednesday 15th June)

C (Due on Friday 17th June)

G (Due on Thursday 16th June)

H (Due on Saturday 18th June)

A (Due on Monday 13th June)

B (Due on Monday 20th June)

By following the EDD rule, we aim to complete the jobs with earlier due dates first, minimizing the flow time and ensuring timely delivery of the orders.

Therefore, the recommended rule for sequencing the jobs in this scenario is the EDD (Earliest Due Date) rule.

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Evaluate the line integral ∫ C

F⋅dr where F=⟨4sinx,−5cosy,5xz⟩ and C is the path given by r(t)=(−2t 3
,3t 2
,2t) for 0≤t≤1 ∫ C

F⋅dr=

Answers

The numerical value of the line integral depends on the specific values of cos(−2) and sin(3).

To evaluate the line integral ∫CF⋅dr, where F = ⟨4sinx, −5cosy, 5xz⟩ and C is the path given by\(r(t) = (−2t^3, 3t^2, 2t)\) for 0 ≤ t ≤ 1, we need to substitute the values of F and dr into the integral expression and evaluate it over the given path.

First, let's express dr in terms of t:

dr = (dx/dt) dt i + (dy/dt) dt j + (dz/dt) dt k

Now, we substitute F and dr into the line integral:

∫CF⋅dr = ∫[0,1] (4sinx dx + (-5cosy) dy + (5xz) dz)

= ∫[0,1] (4sinx dx) + ∫[0,1] (-5cosy dy) + ∫[0,1] (5xz dz)

Integrating each term separately:

∫[0,1] (4sinx dx) = [-4cosx] from x

\(= −2t^3 to x\)

= 0

\(= -4cos(0) - (-4cos(−2t^3))\)

\(= -4 + 4cos(−2t^3)\)

∫[0,1] (-5cosy dy) = [-5siny] from y = 0 to y

\(= 3t^2\)

\(= -5sin(3t^2) - (-5sin(0))\)

\(= -5sin(3t^2)\)

∫[0,1] (5xz dz) = 5∫[0,1] (xt) dt

= 5∫[0,1]\((−2t^4) dt\)

= 5\([-(2/5)t^5]\) from t = 0 to t = 1

= -2

Now, we can combine all the terms:

∫CF⋅dr\(= (-4 + 4cos(−2t^3)) + (-5sin(3t^2)) - 2\)

Finally, we evaluate the line integral over the given path from t = 0 to t = 1:

∫CF⋅dr\(= (-4 + 4cos(−2(1)^3)) + (-5sin(3(1)^2)) - 2\)

= (-4 + 4cos(−2)) + (-5sin(3)) - 2

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A child is playing hiding game in which three of his friends each hide in a different place, and the child tries to find them. he guesses correctly that his friends are hiding in closets, and there are 10 closets in which they might hide. he searches these closets at random. what is the probability he will not find any of his friends in the first 4 closets he checks

Answers

To calculate the probability that the child will not find any of his friends in the first 4 closets he checks, we need to consider the number of ways the friends can be distributed among the closets.

How we can analysis the profitability?

Let's analyze the possibilities step by step:

The first friend can hide in any of the 10 closets.

After the first friend has chosen a closet, the second friend can hide in any of the remaining 9 closets.

Similarly, after the first and second friends have chosen their closets, the third friend can hide in any of the remaining 8 closets.

The total number of ways the friends can choose their closets is given by the product of the number of choices for each friend, which is 10 x 9 x8 = 720.

Now, let's consider the number of ways the friends can be distributed such that none of them are found in the first 4 closets. The child needs to choose 4 closets out of the total 10 closets for searching, and the friends need to choose their closets from the remaining 6 closets.

The number of ways to choose 4 closets out of 10 is given by the combination formula: C(10, 4) = 10! / (4! x (10 - 4)!) = 210.

Similarly, the number of ways the friends can choose their closets from the remaining 6 is given by the product of the number of choices for each friend, which is 6 x 5 x 4 = 120.

Therefore, the total number of ways the friends can distribute themselves among the closets such that none of them are found in the first 4 closets is 210 x 120 = 25,200.

Finally, the probability that the child will not find any of his friends in the first 4 closets he checks is the ratio of the number of successful outcomes (where none of the friends are found) to the total number of possible outcomes:

Probability = Successful outcomes / Total outcomes = 25,200 / 720 = 35 / 1 = 35.

Hence, the probability is 35/1 or simply 35.

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A coordinate plane with a line passing through (negative 3, negative 5), (0, 1), and (2, 5). A function f(x) is graphed. What is the slope of the function? m = What is the y-intercept of the function? b = Which equation represents the graph of the function?

Answers

\(\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}\)

Actually Welcome to the Concept of the Functions.

so after plotting the graphs, we get as,

==> m = 2.5

==> b = 0

==> y = mx+c

a straight line

A coordinate plane with a line passing through (negative 3, negative 5), (0, 1), and (2, 5). A function

Answer:

your answer is, because i got it right your welcome

Step-by-step explanation:

A coordinate plane with a line passing through (negative 3, negative 5), (0, 1), and (2, 5). A function

_____ was a social system in which life centered around a feudal lord's castle or house. ​

Answers

The social system in which life centered around a feudal lord's castle or house was known as feudalism.

What was Feudalism?

Feudalism was a political, economic, and social structure that dominated Western Europe during the Middle Ages. It was a social system in which life centered around a feudal lord's castle or house, as mentioned in the question.

The king granted fiefs to nobles in exchange for loyalty and service, who in turn granted land to lesser nobles called vassals. The vassals then promised to serve the nobleman, known as their lord, by providing military service, money, or other benefits. The vassals had serfs who worked on the land and paid rent to the lord.

They were granted protection in return for their service, and this was the primary method of social organization during the Middle Ages.

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What is order of magnitude?

Answers

The magnitude of the number of the minutes in the school is 2.

What magnitude is 0 in?

Although the order of magnitude of zero is not specified, it is occasionally stated to have a magnitude of. Zero is less than any other positive number, and so is its order of magnitude, according to this infinitely negative order of magnitude.

Can a magnitude order be negative?

There can be no negative magnitude. The component of the vector that lacks direction is its length (positive or negative).

The order of magnitude is the approximate representation of the logarithmic of the order's value and is typically considered to be 10 taken as the base.

On a scale of 10 logarithmic, the difference in the order of magnitude can be quantified.

The value storage is where you may find the number into the various magnetic.

As a result, the number of minutes spent in school is 2.

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Complete question -

What is the Order of Magnitude of the number of minutes in a school day?

Solve for a :4a-7=5a+1

Answers

Answer:

A= -8

Step-by-step explanation:

Subtract 5a from both sides.

Combine 4a and −5a to get −a.

Add 7 to both sides.

Finally, Multiply both sides by −1.

Pls mark brainliest.

Answer:

a = -8

Step-by-step explanation:

4a - 7 = 5a + 1

subtract 1 from both sides of the equation

4a - 7 - 1 = 5a + 1 - 1

4a - 7 - 1 = 5a

4a - 8 = 5a

subtract 4a from both sides of the equation

4a - 4a - 8 = 5a - 4a

-8 = 5a - 4a

-8 = 1a

-8 = a

Find an orthogonal matrix A where the first row is a multiple of (3,3,0). A=

Answers

Putting it all together, we get:

A:

[-3 0 0]

[ 0 1 0]

[ 0 0 -1]

which is an orthogonal matrix with the first row being a multiple of (3, 3, 0).

An orthogonal matrix is a square matrix whose columns and rows are orthonormal vectors, i.e., each column and row has unit length and is orthogonal to the other columns and rows.

Let's start by finding a vector that is orthogonal to (3, 3, 0). We can take the cross product of (3, 3, 0) and (0, 0, 1) to get such a vector:

(3, 3, 0) x (0, 0, 1) = (3*(-1), 3*(0), 3*(0)) = (-3, 0, 0)

Note that this vector has length 3, so we can divide it by 3 to get a unit vector:

(-3/3, 0/3, 0/3) = (-1, 0, 0)

So, the first row of the orthogonal matrix A can be (-3, 0, 0) or a multiple of it. For simplicity, we'll take it to be (-3, 0, 0).

To find the remaining two rows, we need to find two more orthonormal vectors that are orthogonal to each other and to (-3, 0, 0). One way to do this is to use the Gram-Schmidt process.

Let's start with the vector (0, 1, 0). We subtract its projection onto (-3, 0, 0) to get a vector that is orthogonal to (-3, 0, 0):

v1 = (0, 1, 0) - ((0, 1, 0) dot (-3, 0, 0)) / ||(-3, 0, 0)||^2 * (-3, 0, 0)

= (0, 1, 0) - 0 / 9 * (-3, 0, 0)

= (0, 1, 0)

We can then normalize this vector to get a unit vector:

v1' = (0, 1, 0) / ||(0, 1, 0)|| = (0, 1, 0)

So, the second row of the orthogonal matrix A is (0, 1, 0).

To find the third row, we take the cross product of (-3, 0, 0) and (0, 1, 0) to get a vector that is orthogonal to both:

(-3, 0, 0) x (0, 1, 0) = (0, 0, -3)

We normalize this vector to get a unit vector:

v2' = (0, 0, -3) / ||(0, 0, -3)|| = (0, 0, -1)

So, the third row of the orthogonal matrix A is (0, 0, -1).

Putting it all together, we get:

A:

[-3 0 0]

[ 0 1 0]

[ 0 0 -1]

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Is this correct please check the answer quickly

Is this correct please check the answer quickly

Answers

Answer:

Step-by-step explanation:

No, this is not correct.

Step 1: Find the directional distance from every vertex on the blue image to  the center, Point C.

Point A is 1 unit left and 4 units upwards to Point C.

Point B is 4 units right and 5 units upwards to Point C.

Point C is the center of the dilation, so that point will not change.

Step 2: Apply the scale factor to the directional distances to know the distances of the new images.

The scale factor is 2 so

Point A' should be 2 units left and 8 units upwards to Point C.

Point B' should 8 units right and 10 units upwards to Point C.

Step 3:  Move the point in respect to Point C.

The new image should have the these points.

One point that is 2 units left and 8 units upwards to Point C.

Another point that is Point B' should 8 units right and 10 units upwards to Point C.

One point that coincides  with  Point C.

You work for an electric company and make a base pay of $200 every two weeks. You earn and extra $15 for each hour you work. Write a function to model this scenario using f(h) for the amount of money made and h for the hours of worked

Answers

Answer:

a

Step-by-step explanation:

Write the following phrase as an expression. "the product of 6 and n" Please helpMEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Answers

Answer:

6n=

Step-by-step explanation:

I hope this helps you

The expression is 6n.

What is an Expression ?

An expression is a mathematical statement that has variables , constants and mathematical operators.

The phrase 6 and n in expression form is

6n

Therefore, the expression is 6n.

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what is the quotient of the expression
\( \frac{21a {}^{3} b - 14ab {}^{2} + 7ab}{7ab} \)

Answers

The quotient of the expression is 3a^2 - 2b + 1

a data analyst is cleaning survey data. the results for an optional question contain many nulls. what function can the analyst use to eliminate the null values from the results?

Answers

The Analyst can use COALESCE function to eliminate the null values from the results.

The SQL Coalesce functions is used to handle NULL values. During the expression evaluation process the NULL values are replaced with the user-defined value. It  returns the first non-NULL value from a series of expressions.

The SQL Coalesce function evaluates the arguments in order and always returns first non-null value from the defined argument list.

Few Properties of COALESCE Function

Expressions must be of same data-typeIt can contain multiple expressionsThe SQL Coalesce function is a syntactic shortcut for the Case expressionAlways evaluates for an integer first, an integer followed by character expression yields integer as an output.

SYNTAX -

COALESCE ( expression [ ,...n ] )  

Hence, the analyst can use COALESCE function to eliminate the null values from the results.

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find the volume of the figure. HELP ASAP DUE SOON.

find the volume of the figure. HELP ASAP DUE SOON.

Answers

Answer: 2123.72

Step-by-step explanation:

Answer:

2123.72

Step-by-step explanation:

Form for Cylinder- V=πr^2h

π=3.14

r=6.5

h=16

π × 6.5^2 × 16 =2123.71663383

Rounded 2123.72

Hope this helps! Brainiest please!:)

10/9= 2/3xd
what is the value of D

Answers

Answer:

d=5/3x

Step-by-step explanation:

Let's solve for d.

(2/3x)(d)=10/9

Step 1: Divide both sides by (2x)/3.

2/3dx / 2x/3=10/9 / 2x/3

d=5/3x




5. Let H be the hemisphere H = {(x,y,z) € R³ : x² + y² + z² = 16, z ≤ 0} and F(x,y,z) = (0, 2y, -4). Compute the flux integral JF.Nas where N is directed in the direction positive z-coordinate

Answers

To compute the flux integral JF.Nas, where N is directed in the positive z-coordinate direction, we need to evaluate the surface integral over the hemisphere H with the vector field F(x, y, z) = (0, 2y, -4).

The surface integral can be computed using the formula JF.Nas = ∬ F · N dS, where F is the vector field, N is the unit normal vector to the surface, and dS represents the infinitesimal area element on the surface.

Since N is directed in the positive z-coordinate direction, it is given by N = (0, 0, 1).

To evaluate the surface integral, we need to parameterize the hemisphere H. We can use spherical coordinates to parameterize the surface, where x = r sinθ cosϕ, y = r sinθ sinϕ, and z = r cosθ, with the constraint r = 4 and θ ∈ [0, π/2] and ϕ ∈ [0, 2π].

Substituting the parameterization into F · N, we have F · N = (0, 2y, -4) · (0, 0, 1) = -4.

The surface integral becomes JF.Nas = ∬ -4 dS.

Integrating over the surface of the hemisphere H, we obtain the flux integral.

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7) If the side length of the cube is 12 feet, find the surface area,

Answers

Answer:

91.26 ft2

Step-by-step explanation:

Given, length of side =.9 ft

The total surface area of a cube = 6× side 2

=6×3.9×3.9

=91.26ft

2

Answer:

=> 864ft²

Step-by-step explanation:

Given :

=> side length of cube = 12 feet

=> The surface area of cube = 6a²

=> 6×12×12

=> 864 ft ²

In the circle, m S=27°, mRS = 110°, and RU is a tangent. The diagram is not drawn to
scale.
What is m U?
28°
41.5°
56°
83°

In the circle, m S=27, mRS = 110, and RU is a tangent. The diagram is not drawn toscale.What is m U?2841.55683

Answers

The measure of the angle U of the circle is m∠U = 28°

Given data ,

In the triangle ΔSRU , the measure of angle is calculated as ∠SRU,

180° - 110° = 70°

70°/2 = 35°

∠SRU = 35° + 90° = 125°

Central Angle = 2 x Angle in other segment

Then angle U from the triangle is determined using this formula,

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

So,

The measure of ∠U = 180° - ∠SRU - ∠S

The measure of ∠U = 180° - 125° - 27°

The measure of ∠U = 28°

Hence , the angle of circle is ∠U = 28°

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many new york urban area kids resorted to what manner of making money as a possible way out of their life in the 1980's and 1990's?

Answers

In the 1980s and 1990s, many urban area kids in New York turned to "Selling Drugs" as a means of supplemental income as a means of escape.

Drugs selling during 1980s and 1990s:

The crack epidemic that ravaged New York City with in 1980s was beginning to fade by the early 1990s, and crime rates were also declining.

But in some districts of New York City, drug trafficking has grown so visible and widespread that it seems like everyone is aware of where it is happening and who is involved. However, getting rid of it is a different story.A significant number of drug sellers operate shamelessly and without concern for being apprehended. This is demonstrably true the Police Department's stated intention to crack down upon street-level sales and the significant funds invested in the Tactical Narcotics Team (T.N.T.)

Thus, during the 1980s and 1990s, many urban area kids in New York turned to "Selling Drugs" as a means of supplemental income as a means of escape.

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