Solve the following for [HI] and [I2]: 2HIg —-> H2g+ I2g in a container given that Keq = 0.020 and [H2] = 0.50 mol/l

Answer:

ans.........❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️❣️

Answer:

\(1 \: mole \: weighs \: 18 \: g \\ 4.7 \: moles \: weigh \: (4.7 \times 18) \: g \\ = 84.6 \: g\)

Answer:

The event placed in order is;

b, a, c, d

Explanation:

1) b) The marble is placed on a wooden sled

Before the marble is lifted up the ramp, it is placed on a wooden sled that allows the pulley system which can be attached to the wooden sled to lift it up the ramp

2) a) The marble is moved up the ramp using the pulley system

The attached pulley system is then used to move the marble up the ramp

3) c) Iron wedges are used to break the massive marble

The massive marble is broken into pieces that can be worked upon by each mason

4) d) Masons begin carving the marble

The masons (more than one mason) begin carving the pieces of marbles into shape

Answer:

C - raising the temperature of a gas

Explanation:

as you raise temperature, kinetic energy rises, and so does pressure

Answer:

C.

raising the temperature of the gas

Explanation:

Edg. 2020

Other guy is right i got 100%

Answer:

It is the temperature at which a substance changes from a liquid to a solid.

Have a good day!

The temperature at which a substance  changes from a liquid to a solid is called  its freezing point. Hence, option d is the correct definition of freezing point.

Freezing point is a physical property of a substance which measures the temperature at which its liquid state converts to solid state where, the two phases are in equilibrium.

For example, water freezes at 0 degree Celsius to form ice. Hence, 0°C is the freezing point of water. The freezing point of substance is affected by the bond type, molecular weight, temperature and pressure as well the impurities if any.

The more the intermolecular forces between the molecules, more easy to convert it into solid. Hence, the freezing point will be lower. If there is any impurities present, the freezing point depression will occurs.

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The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.

Given:

Power rating of the refrigerator = 500 W

Running time per day = 12 hours

Number of days = 30

First, we need to convert the power rating from watts to kilowatts:

Power rating = 500 W / 1000 = 0.5 kW

Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:

Energy used = Power rating × Running time × Number of days

Energy used = 0.5 kW × 12 hours/day × 30 days

Energy used = 180 kWh

Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.

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Sulfur dioxide (SO2) is typically formed by the combustion or oxidation of sulfur-containing materials. In the context of industrial processes, sulfur dioxide is commonly produced by burning sulfur-rich fuels such as coal and oil.

In nature, sulfur dioxide can also be formed by volcanic activity, as well as through the bacterial and chemical breakdown of organic matter that contains sulfur.Sulfur dioxide can be produced by the reaction of sulfur or sulfur-containing compounds with oxygen. For example, when sulfur is burned in the presence of oxygen, sulfur dioxide is formed according to the following reaction:

S (s) + O2 (g) → SO2 (g)

The reaction can also occur between sulfur compounds, such as hydrogen sulfide (H2S), and oxygen:

2 H2S (g) + 3 O2 (g) → 2 SO2 (g) + 2 H2O (g)

Sulfur dioxide is an important gas in the atmosphere, as it plays a role in regulating climate and air quality. However, high concentrations of sulfur dioxide can be harmful to human health and the environment, and so it is important to control and monitor its release into the environment.

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Applications of anaerobic respiration is generating microbial fuel cell

Anaerobic respiration is the because of lack of oxygen they carry out respiration in the absence of oxygen to produce the energy they require called as anaerobic respiration

Anaerobic respiration is useful generating microbial fuel cell which employ bacteria that respire solid electron acceptor to transfer electron from reduced compound to an electrode this process can simultaneously degrade organic carbon waste and generate electricity

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Answer:

a syringe is a pump consisting of a sliding plunger that fits tightly in a tube.

Explanation:

a syringe is a pump consisting of a sliding plunger that fits tightly in a tube. the plunger can be pulled and pushed inside the precise cylinderell to, or burial, letting the syringe draw in or expel a liquid or gas through an office at the open end of the two.

Answer:

The plunger can be pulled and pushed inside the precise cylindrical tube, or barrel, letting the syringe draw in or expel a liquid or gas through an orifice at the open end of the tube.

Explanation:

Answer:

the molar mass of the components making up Ca(NO₃)₂ are as follows;

Ca - 40 g/mol

N - 14 g/mol

O - 16 g/mol

the molar mass of the compound is calculated as follows;

Ca(NO₃)₂ --> 40 + 2(14 + 16x3)

              = 164 g/mol

1 mol of the compound weighs 164 g

Therefore 0.433 mol = 164 g/mol x 0.433 mol

                                = 71.0g

the mass of 0.433 mol of the compound is 71.0 g

A hydrogen energy system is made up of hydrogen production, transportation, storage, utilization etc. Whether a hydrogen-based energy system is environmentally cleaner than a fossil fuel system depends on the source of energy used to produce the hydrogen.

Hydrogen is known to carry some amount of energy carrier and can also deliver or store a large amount of energy. Hydrogen is often used in fuel cells to generate electricity, or power and heat.

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In a redox reaction at standard conditions, the values for Eº (of the cell) and ∆Gº must be Eº is positive and ∆Gº is negative for the cell to be spontaneous. The correct answer is option B.

In a spontaneous redox reaction, the standard cell potential (Eº) must be positive, indicating that the reaction is thermodynamically favorable. A positive Eº value indicates that the reaction proceeds in the forward direction as written.

Furthermore, the standard Gibbs free energy change (∆Gº) must be negative for a spontaneous reaction. A negative ∆Gº value indicates that the reaction has a tendency to proceed spontaneously, with the products having a lower free energy than the reactants.

Therefore, for a redox reaction to be spontaneous at standard conditions, Eº must be positive (indicating thermodynamic favorability) and ∆Gº must be negative (indicating spontaneity).

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In a redox reaction at standard conditions, the values for Eº (of the cell) and ∆Gº must be Eº is negative and ∆Gº is negative for the cell to be spontaneous.

The redox reaction consists of two half-cells, one is oxidation and the other is reduction. When both half-cells are connected, electrons are transferred from the half-cell that gets oxidized to the half-cell that gets reduced, producing a flow of electrons from the anode to the cathode. Electrons move from the half-cell with a lower standard electrode potential (Eº) to the half-cell with a higher standard electrode potential (Eº). The spontaneity of a redox reaction can be determined by the sign of Gibb's free energy change (∆Gº) and the standard electrode potential (Eº) of the redox reaction. If Eº is positive, the reaction is spontaneous. If Eº is negative, the reaction is non-spontaneous. ∆Gº is directly proportional to the negative value of Eº, therefore, if Eº is negative, ∆Gº will be positive and if Eº is positive, ∆Gº will be negative. In summary, Eº is positive, and ∆Gº is negative for a cell to be spontaneous. Eº is negative, and ∆Gº is positive for a cell to be non-spontaneous.

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Vascular and nonvascular organisms in the plant kingdom use photosynthesis to get nutrients.

All plants make use of photosynthesis to get food.

Vascular plants have vascular tissues such as xylem, phloem, etc. while non-vascular plants are devoid of vascular tissues.

Vascular tissues are used to conduct water (xylem) and manufactured foods (phloem) around the body of plants.

Lower plants have other means (such as diffusion and pseudo-vascular tissues) to conduct materials around their own bodies.

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Answer:

A meteorologist studies meteorology which is the study of the atmosphere in order to predict/forecast the weather.

Explanation:

I hope this helps.

Answer:

they study the atmosphere and atmospheric events of our weather

Explanation:

The equilibrium concentration of PH3 gas is 4.32 * 10^-2 mol/L at 80 degrees Celsius.

The equilibrium constant for the reaction of PH3BCl3 decomposing into PH3 and BCl3 is given as Kc = 1.87 * 10^-3 at 80 degrees Celsius.

The balanced equation for the reaction is:

PH3BCl3(s) <=> PH3(g) + BCl3(g)

Since the solid PH3BCl3 is not included in the equilibrium constant expression, the equilibrium constant is simply equal to the product of the concentrations of PH3 and BCl3 gas.

At equilibrium, the concentration of PH3 gas will be equal to the concentration of BCl3 gas.

Therefore, the equilibrium concentration of PH3 gas is equal to the square root of the equilibrium constant, or:

sqrt(1.87 * 10^-3) = 4.32 * 10^-2

Therefore, the equilibrium concentration of PH3 gas is 4.32 * 10^-2 mol/L.

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To determine the amount of energy transferred to an alpha particle (4He), we need to know the specific context or process in which the energy transfer occurs.

However, in general, the energy transferred to an alpha particle can be calculated in certain scenarios. For example, in a nuclear reaction such as alpha decay, the energy transferred to the alpha particle can be determined by subtracting the total energy of the parent nucleus from the total energy of the daughter nucleus and any emitted particles.

It is also important to note that energy transfer can occur through various mechanisms, such as collisions, electromagnetic interactions, or chemical reactions. The calculation of energy transfer typically requires specific data and context related to the system and process involved.

If you can provide additional details or clarify the specific scenario in which the energy transfer is occurring, I would be happy to assist you further in calculating the amount of energy transferred to the alpha particle.

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metal ore

i got this question before and answered this one correctly trust me its right

Answer:

metal ore

Explanation:

Answer:

See explanation

Explanation:

Period 3 elements include; Na, Mg, Al, Si, P,S,Cl and Ar

Across the period, the chlorides of the elements change from solid to gas. The chlorides of metals are solid while the chlorides of non metals are gaseous.

Also, the chlorides become more volatile across the period. The formulas of the chlorides change from MCl to MCl2 to MCl3 to MCl4, MCl5 and MCl6 respectively across the period where M is a period 3 element.

The pH of the solutions of chlorides of period 3 elements change from neutral to acidic across the period. The pH of the chlorides of metals are neutral while the chlorides of the nonmetals usually yield acid solutions.

The enthalpy change for the dissolution of KBr in water is -71.56 kJ/mol.

To calculate the enthalpy change for the dissolution of KBr in water, we can use the following formula:

ΔH = -q / n

where ΔH is the enthalpy change, q is the heat absorbed or released by the reaction, and n is the number of moles of KBr dissolved.

First, let's calculate the heat absorbed or released by the reaction using the following formula:

q = m × c × ΔT

where q is the heat, m is the mass of the solution, c is the specific heat capacity of water (4.184 J/g·°C), and ΔT is the temperature change.

m = 11.4 g KBr + 100.0 g water = 111.4 g

ΔT = 24.88°C - 20.34°C = 4.54°C

q = 111.4 g × 4.184 J/g·°C × (-4.54°C) = -20891 J

The negative sign indicates that the reaction releases heat to the surroundings.

Next, let's calculate the number of moles of KBr dissolved:

n = mass / molar mass

molar mass of KBr = 39.10 g/mol (from periodic table)

n = 11.4 g / 39.10 g/mol = 0.2918 mol

Finally, we can calculate the enthalpy change:

ΔH = -q / n = -(-20891 J) / 0.2918 mol = 71560 J/mol

To convert J/mol to kJ/mol, we divide by 1000:

ΔH = 71.56 kJ/mol

Therefore, the enthalpy change for the dissolution of KBr in water is -71.56 kJ/mol.

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Answer:

Beta particles have a charge of minus 1.

Explanation:

Hope this helps!

Answer:

MARK AS BRAINLIEST ANSWER

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Explanation:

Beta particles have a mass which is half of one thousandth of the mass of a proton and carry either a single negative (electron) or positive (positron) charge. As they have a small mass and can be released with high energy, they can reach relativistic speeds (close to the speed of light)

HOPE IT HELPS YOU

Answer:

The correct answer is option D

Ali is using a specialized headphone that cancels the extra noise in the atmosphere.

Megan is using a transmitter to convert electrical signals into radio waves.

Kristoff is using a microphone to convert sound waves into the electrical signals.

Jenna is using the radio to convert radio waves into sound waves.

Answer:

D

Explanation:

Got it right on edgen :)

You'll need 34.7 mL of 0.183 M KOH to reach the stoichiometric point in the titration of 21.74 mL of 0.292 M C₆H₅OH. Titration is a laboratory technique used to determine the concentration of a solution by reacting it with a known concentration solution.

In this case, we are titrating a solution of 0.292 m C₆H₅OH with a solution of 0.183 m KOH. The stoichiometric point in this reaction is the point at which the number of moles of the added titrant (KOH) is equal to the number of moles of the analyte (C₆H₅OH).

At this point, the reaction is complete, and the resulting solution is neutral. We can calculate the number of moles of C₆H₅OH using its concentration and volume:
moles of C₆H₅OH = concentration x volume = 0.292 x 0.02174 = 0.006342 moles

To reach the stoichiometric point, we need an equal number of moles of KOH.
moles of KOH = moles of C₆H₅OH = 0.006342 moles

We can then use the concentration of KOH to calculate the volume needed to reach the stoichiometric point:
moles of KOH = concentration x volume
0.006342 moles = 0.183 mol/L x volume
Volume = 0.006342 moles / 0.183 mol/L = 0.0347 L or 34.7 mL

Therefore, we need 34.7 mL of 0.183 M KOH to reach the stoichiometric point in the titration of 21.74 mL of 0.292 M C₆H₅OH. It is important to note the given Ka value of phenol is not used in this calculation since it is not directly related to the stoichiometry of the reaction.

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At the point when one isomer of C₆H₁₄O responds with hydrogen iodide, the hydroxyl bunch of the liquor is supplanted by an iodine molecule, bringing about the development of an alkyl iodide. The particular item framed will rely upon the isomeric design of C₆H₁₄O and the response conditions.

Assuming that the hydroxyl bunch is appended to the optional carbon of the pentanol atom, the response will yield C₆H₁₃I. This response is an illustration of nucleophilic replacement, where the nucleophilic iodide particle replaces the leaving bunch on the carbon chain. The subsequent alkyl iodide item can have different applications in natural amalgamation.

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From the reaction between one isomer of 3-methyl-1-pentanol and HI (hydrogen iodide), you would expect to obtain an alkyl iodide as the product. This reaction is an example of a nucleophilic substitution reaction, where the iodide ion (I-) acts as a nucleophile and replaces the hydroxyl group (-OH) of the alcohol.

The isomer of 3-methyl-1-pentanol can be either 3-methyl-1-pentanol itself or one of its structural isomers. The specific structure of the alcohol is important in determining the resulting alkyl iodide. For example, if the hydroxyl group is attached to the third carbon atom (CH_3-CH_2-CH(OH)-CH_2-CH_3), the reaction with HI would produce 3-iodo-3-methylpentane.

The reaction proceeds by the nucleophilic attack of the iodide ion on the carbon atom attached to the hydroxyl group, leading to the formation of an alkyl iodide and water as a byproduct. The reaction can be represented as follows:

3-methyl-1-pentanol + HI → 3-iodo-3-methylpentane + H_2O

It is important to note that the reaction conditions, such as temperature and concentration, can influence the outcome of the reaction. Additionally, the stereochemistry of the starting alcohol can also affect the stereochemistry of the product. Overall, the reaction between an isomer of 3-methyl-1-pentanol and HI results in the formation of an alkyl iodide.

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The concentration of TCE is 28ppm, convert this to molarity. The molecular weight of TCE is 132g/mole. The molarity of TCE is, therefore, 0.000212 M.

The term ppm stands for parts per million. This term is used to describe the concentration of a substance present in a given solution or mixture. To find the molarity of TCE, the given concentration of TCE in ppm needs to be converted into molarity.

The given concentration of TCE is 28ppm.

1 ppm = 1 mg/L1mg/L = 10^-3 g/L

The molecular weight of TCE is 132g/mole.

Conversion of ppm to g/L is given as follows:

28 ppm = 28 mg/L

=28 x 10^-3 g/L

Number of moles of TCE in 1 L is:

mass of TCE/molecular weight of TCE = 28 x 10^-3/132

= 0.000212 mole/L.

The molarity of TCE is, therefore, 0.000212 M.

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If the bears don't pack on enough pounds before they hibernate, they won't enough energy that will sustain them during the hibernation period.

Hibernation is a condition when an animal slows its heart rate to save energy and survive the winter without eating much.

Some animals just slow down and move less frequently during hibernation, but others go into a deep sleep and don't wake up till spring.

If the bears don't pack on enough pounds before they hibernate, they won't return to the mountains to den for the winter.

Packing on enough pounds will provide them with enough energy that will sustain them during the hibernation period.

Thus, If the bears don't pack on enough pounds before they hibernate, they won't enough energy that will sustain them during the hibernation period.

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Phosphoric acid has three equivalence points, corresponding to its three dissociable protons. In this lab, you should be able to see all three equivalence points if you perform a complete titration of the acid.

Phosphoric acid, which has the chemical formula H3PO4, is a triprotic acid. This means it has three acidic hydrogen atoms that can be donated to a base in an acid-base reaction.
Therefore, phosphoric acid has three equivalence points. An equivalence point is reached when the number of moles of the base added to the acid is equal to the number of moles of acidic hydrogens in the acid.
In a lab setting, you should be able to observe all three equivalence points if you carefully titrate the phosphoric acid with a strong base, such as sodium hydroxide (NaOH), and use an appropriate indicator or a pH meter to monitor the changes in pH during the titration.

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