Problem 1 (30 points) Consider two objects of masses m₁= 9.636 kg and m₂ = 3.459 kg. The first mass (m₂) is traveling along the negative y-axis at 54.35 km/hr and strikes the second stationary mass m₂, locking the two masses together. a) (5 Points) What is the velocity of the first mass before the collision? m1 m/s b) (3 Points) What is the velocity of the second mass before the collision? Vm2=< m/s c) (1 Point) The final velocity of the two masses can be calculated using the formula number: (Note: use the formula-sheet given in the introduction section) d) (5 Points) What is the final velocity of the two masses? m/s e) (4 Points) Choose the correct answer: f) (4 Points) What is the total initial kinetic energy of the two masses? Ki= J g) (5 Points) What is the total final kinetic energy of the two masses? Kf= h) (3 Points) How much of the mechanical energy is lost due to this collision? AEint

Therefore, the velocity of the ball just before it hits the ground is approximately 22.1 m/s. Therefore, the closest value to this option is 21.0 m/s.

When a ball of mass 0.25 kg falls from a height of 50 m, we can calculate its velocity using the principle of conservation of energy. According to this principle, the sum of the potential and kinetic energy of an object remains constant.

Therefore, we can equate the potential energy at the initial height to the kinetic energy at the final velocity.Let's calculate the potential energy of the ball at the initial height

:Eg = mghEg = 0.25 kg × 9.81 m/s² × 50 m

Eg = 122.625 J

This is the energy that the ball has due to its position. As it falls, this energy is transformed into kinetic energy. At the moment the ball reaches the ground, all the potential energy has been transformed into kinetic energy

.Ek = 1/2mv²Ek = Egv² = 2Ek/mv = √(2Ek/m)

Let's plug in the values we obtained:Eg = 122.625 Jm = 0.25 kgv = √(2Ek/m)

We obtain:v = √(2 × 122.625 J / 0.25 kg)v = √(245.25 J/kg)v = 22.116 m/s

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Answer:

to find the slope you need to find the change in distance then you divide by the corresponding change in time

eg

( 4-2) ÷ (2-1)

= 2m/s

Answer:

3 N

Explanation:

From the question given above, the following data were obtained:

Mass of block = 100 Kg

Net force = 3 N

From the question given above, we were told that the net force acting on the block is 3 N.

Thus, 3 N remains the net force acting on the block.

Answer:

The increase in gravitational potential energy is the same in both cases

Explanation:

It is easier to climb a mountain in a zigzag way rather than climbing on a straight line but since the distance is the same ( vertical height ) , mass and gravity is the same. Hence the increase in gravitational potential energy is the same in both cases.

gravitational potential energy = mgh ( same in both cases )

m = mass

g = acceleration due to gravity

h = distance ( vertical height )

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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Answer:

scalar d = 54000 m , v_average = 16,667 m / s

vector    d = -4000 m , moved 4000 to the west

                 v_average = 0                

Explanation:

his is a uniform motion exercise, but we must be careful with quantities that are scalars and vector quantities

The distance traveled is a scalar

       d = d₁ + d₂

       d = 25000 + 29000

       d = 54000 m

the speed is a scalar, in the exercise it is not specified if the speed of each trajectory or the average speed. Therefore we will calculate the two

       v₁ = d₁ / t₁

       v₁ = 25000/1500

       v₁ = 16,667 m / s

       v₂ = 29000/1740

        v₂ = 16,667 m / s

Since the two speeds are equal, the average speed is

       v = (v1 + v2) / 2

       v_average = 16,667 m / s

now let's calculate the displacement that is a vector, so it has direction in addition to modules

suppose the eastward direction is positive and the bold are vectors

      d = d₁ - d₂

       d = 25000 - 29000

        d = -4000 m

this means that it moved 4000 to the west

velocity is a vector, we assume positive eastward movement

        v₁ = 16,667 m / s

         v₂ = - 16,667 m / s

         v_average = (v1 -v2) / 2

         v_average = 0

Answer:

512.5 mJ

Explanation:

Let the two identical charges be q = +35 µC and distance between them be r₁ = 46 cm. A charge q' = +0.50 µC located mid-point between them is at r₂ = 46 cm/2 = 23 cm = 0.23 m.

The electric potential at this point due to the two charges q is thus

V = kq/r₂ + kq/r₂

= 2kq/r₂

= 2 × 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C/0.23 m

= 630/0.23  × 10³ V

= 2739.13 × 10³ V

= 2.739 MV

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

So, the new electric potential at this point is

V' = kq/r₃ + kq/r₄

= kq(1/r₃ + 1/r₄)

= 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C(1/0.35 m + 1/0.11 m)

= 315 × 10³(2.857 + 9.091) V

= 315 × 10³ (11.948) V

= 3763.62 × 10³ V

= 3.764 MV

Now, the work done in moving the charge q' to the point 12 cm from either charge is

W = q'(V' - V)

= 0.5 × 10⁻⁶ C(3.764 MV - 2.739 MV)

= 0.5 × 10⁻⁶ C(1.025 × 10⁶) V

= 0.5125 J

= 512.5 mJ

Work done will be:  \(512.5 \mu J\).

Given:

q = +35 µC

q' = +0.50 µC

r₁ = 46 cm

r₂ = 46 cm/2 = 23 cm = 0.23 m

The electric potential at this point due to the two charges q is thus

\(V = \frac{kq}{r_2}+\frac{kq}{r_2}\\\\ V= \frac{2kq}{r_2}\\\\V= \frac{2 * 9 * 10^9Nm^2/C^2 * 35 * 10^{-6} C}{0.23 m}\\\\V= \frac{630}{0.23*10^3}V\\\\V= 2739.13 * 10^3 V\\\\V= 2.739 \mu V\)

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now;

r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and

r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

Thus, the new electric potential at this point is

\(V' = \frac{kq}{r_3} + \frac{kq}{r_4}\\\\V= kq(\frac{1}{r_3}+\frac{1}{r_4})\\\\V= 9 * 10^9 Nm^2/C^2 * 35 * 10^{-6} C (\frac{1}{0.35m}+\frac{1}{0.11m})\\\\V= 315 * 10^3(2.857 + 9.091) V\\\\V= 315 * 10^3 (11.948) V\\\\V= 3763.62 * 10^3 V\\\\V= 3.764 \mu V\)

Now, the work done in moving the charge q' to the point 12 cm from either charge is:

\(W = q'(V' - V)\\\\W= 0.5 * 10^{-6} C(3.764 MV - 2.739 MV)\\\\W= 0.5 *10^{-6} C(1.025 * 10^6) V\\\\W= 0.5125 J\\\\W= 512.5 \mu J\)

Thus, the work done will be: \(512.5 \mu J\).

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The energy required for the phase change from solid to liquid for a substance is known as the heat of fusion (C)

The amount of energy that must be supplied to a solid substance (usually in the form of heat) in order to cause a change in the substance's physical state and convert it into a liquid is referred to as the latent heat of fusion, which is also known as the enthalpy of fusion (when the pressure of the environment is kept constant). Because of the usage of this energy in the process of counteracting the attractive force that exists between the molecules, the kinetic energy of the particles does not increase, and as a result, the temperature does not go up.

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Answer:B. 100 Newtons

Explanation:

F=ma, this mean that the force is equal to the mass (10 kg) multiplied by the acceleration (10 \(m/s^{2}\)). Plug mass and acceleration to solve: \(F=10*10\) ∴ \(F=100\).

The required force  to move a 10 kilogram object 10 meters per second squared be 100 Newton. So, Option(B) is correct.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Given parameters:

Mass of the object = 10 kilogram.

Acceleration of the object: a = 10 meter per second squared.

So, from Newton's 2 nd law of motion, we get:

required force = mass × acceleration

= 10 × 10 Newton

= 100 Newton.

Hence, required force  to move a 10 kilogram object 10 meters per second squared be 100 Newton.

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The most significant difference between the three point and the four-point starter is that in three-point starter the no voltage coil (NVC) is connected in series with the field winding whereas in four-point starter the NVC is directly connected to the supply voltage.

☆...hope this helps...☆

_♥︎_mashi_♥︎_

Answer:

Yes

Explanation:

The core of an electromagnet serves to stabilize the magnetic field created by the wire. The thicker the core, the more metal there is to amplify the current. Therefore, a thicker core does make an electromagnet stronger. Hope this helps!

The force squeezing the plates of the parallel plate capacitor together is approximately 1,106,250 N.

To find the force squeezing the plates of a parallel plate capacitor together, we can use the formula:

F = (1/2) × ε₀ × εᵣ × A × (V/d)²

Where:

F is the force

ε₀ is the vacuum permittivity (ε₀ ≈ 8.85 × \(10^{-12\) F/m)

εᵣ is the relative permittivity (dielectric constant)

A is the area of the plates

V is the potential difference applied to the plates

d is the separation between the plates

Given:

Area of the plates (A) = 1.0 m²

Separation between the plates (d) = 1 mm = 0.001 m

Relative permittivity (εᵣ) = 25

Potential difference (V) = 1.0 kV = 1000 V

Now let's substitute the values into the formula to calculate the force:

F = (1/2) × ε₀ × εᵣ × A × (V/d)²

F = (1/2) × (8.85 × \(10^{-12\) F/m) × 25 × 1.0 m² × (1000 V / 0.001 m)²

Simplifying the calculation:

F = 0.5 × 8.85 × 25 × 1.0 × (10³ / \(10^{-3\))² N

F = 0.5 × 8.85 × 25 × 1.0 × 10^6 N

F ≈ 1106250 N

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To approximate the annual energy consumption and cost of operation for an air conditioner, we can use the following formulas:Annual energy consumption (kWh) = Cooling load (Btu/hr) / SEERAnnual cost of operation ($) = Annual energy consumption (kWh) * Energy cost ($/kWh)

Given:

SEER (Seasonal Energy Efficiency Ratio) = 14

Cooling load = 36,000 Btu/hr

Energy cost = $0.10/kWh

Let's calculate the annual energy consumption and cost of operation for the given locations:

a. For a home in San Francisco, CA:

No specific temperature or cooling hours are mentioned, so let's assume an average annual cooling hours of 1,800.

Annual energy consumption = 36,000 Btu/hr / 14 SEER = 2,571.43 kWh

Annual cost of operation = 2,571.43 kWh * $0.10/kWh = $257.14

b. For a home in Miami, FL:

Again, assuming an average annual cooling hours of 2,500.

Annual energy consumption = 36,000 Btu/hr / 14 SEER = 2,571.43 kWh

Annual cost of operation = 2,571.43 kWh * $0.10/kWh = $257.14

c. For a home in Columbia, MO:

Assuming an average annual cooling hours of 1,500.

Annual energy consumption = 36,000 Btu/hr / 14 SEER = 2,571.43 kWh

Annual cost of operation = 2,571.43 kWh * $0.10/kWh = $257.14

d. For a home in Birmingham, AL:

Assuming an average annual cooling hours of 2,000.

Annual energy consumption = 36,000 Btu/hr / 14 SEER = 2,571.43 kWh

Annual cost of operation = 2,571.43 kWh * $0.10/kWh = $257.14

In all cases (San Francisco, Miami, Columbia, Birmingham), the approximate annual energy consumption of the air conditioner is 2,571.43 kWh, and the annual cost of operation is $257.14. Please note that these calculations assume constant cooling load and do not account for other factors such as climate variations or specific usage pattern.

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Answer:  Energy is transferred between organisms in food webs from producers to consumers. The energy is used by organisms to carry out complex tasks. The vast majority of energy that exists in food webs originates from the sun and is converted (transformed) into chemical energy by the process of photosynthesis in plants.

The method by which machines increase range of motion and speed of movement so that resistance can be moved farther or more quickly than an applied force is not described in the following.

The earth pulls your body downward, which is known as gravity. The location where your body's mass is concentrated is known as your center of gravity. A hypothetical location where the force of gravity seems to act is the center of gravity (COG) of an organism.

No relative motion exists between the two contact surfaces in a rolling motion. Therefore, in a rolling motion, the friction does not do any work. Because of this, rolling friction is lower than sliding or kinetic friction.

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Answer:

Q  =  mc(θ₂-θ₁)

47 calories =  10 g *c*(50.4 - 25)

47cal = 10*c* 25.4

47 /(10*25.4) = c

0.185 = c

Specific heat of iron = 0.185 cal/g°C

Explanation:

Answer:

A 2.5 g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tree's trunk. What is the initial kinetic energy of the bullet? 153.125 J Correct: Your answer is correct.Jan 8, 2020

Explanation:

Answer:

Eat more healthy foods and keep more active.

Explanation:

Answer:

I think it might be A: Alec but tell me if I'm wrong

Explanation:

Answer:

a

Explanation:

i did it on e d g e n u i t y

Answer:

Learn vocabulary, terms, and more with flashcards, games, and other study tools. ... the complete transfer of valence electron(s) between atoms. It is ... The compound is neutral overall, but consists of positively charged ions called cations and negatively ... an ion with net negative charge, having more electrons than protons.

Explanation:

Therefore, the power dissipated by the R2 resistor in the circuit is 18W.

To determine the power dissipated by the R2 resistor in the circuit, we need to use the formula P = V^2/R, where P is power, V is voltage, and R is resistance. We know that R1 is 5.0Ω, but we need to find the voltage across R2. To do this, we can use Ohm's Law, which states that V = IR, where I is current.
In this circuit, the current is the same throughout, so we can use the total current, which is given by I = V/R1. Therefore, V = IR1 = I x 5.0Ω.
Now we can calculate the power dissipated by R2: P = V^2/R2 = (I x 5.0Ω)^2/2.5Ω.
Substituting the value of I from above, we get P = (V/R1 x 5.0Ω)^2/2.5Ω.
Simplifying this expression, we get P = (V^2 x 5.0Ω)/12.5Ω.
To find the value of V, we can use Kirchhoff's voltage law, which states that the sum of voltages in a closed loop is zero. Applying this to the circuit, we get V - IR1 - IR2 = 0.
Substituting the value of I from above and rearranging, we get V = I(R1 + R2) = (V/R1 x 5.0Ω)(5.0Ω + 2.5Ω).
Solving for V, we get V = 7.5V.
Substituting this into the expression for power, we get P = (7.5V^2 x 5.0Ω)/12.5Ω = 18W.
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The diameter of the discs is 2 × 0.003 m = 0.006 m.

The electric field between two parallel charged discs can be calculated as E = V/d, where V is the potential difference between the discs and d is the separation distance between them. The charge Q on one of the discs can be calculated as Q = ne, where n is the number of electrons transferred from one disk to the other and e is the charge of an electron.

Using the equations for electric field and charge, we can find the separation distance d between the discs as follows:

\(E = \frac{V}{d} = \frac{Q}{A\epsilon_0}\)

d = Q/(AEε 0 ) = ne/(Aε 0 E)

\(d= 9.4 * 10^{9} * 1.60 * 10^{-19} / (\pi (d/2)^{2} * 8.85 * 10^{-12} * 1.0 * 10^{5})\)

Rearranging and solving for d, we find:

\(d = \sqrt{9.4 * 10^9 * 1.60 * 10^-19 / (\pi * 8.85 * 10^{-12} * 1.0 * 10^5)} \\\\ = \sqrt{1.0 * 10^{-7}}m = 0.003 m\)

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Answer:

0.18 m/s²

Explanation:

The total time taken to cover a 10 km race is 27 min, 43.6 seconds.

At 25 min, Pre was at 7.71 km mark. Therefore the average speed = 7.71 km / 25 min = 7710 m / (25 * 60) s = 5.14 m/s

The distance remaining = 10 km - 7.71 km = 2.29 km = 2290 m

The remaining time = 27 min, 43.6 seconds - 25 min = 2 min 43.6 second = 163.6 seconds

She accelerates for 60 seconds, therefore the distance covered (S) during the acceleration (a) is:

S₁ = 5.14(60) + 0.5a(60)² = 308.4 + 1800a

She maintains the speed for the remaining distance (S₂). The remaining time = 163.6 seconds - 60 seconds = 103.6 seconds. The final speed after the acceleration = (5.14 + 60a) m/s

S₂ = (5.14 + 60a)* 103.6 = 532.5 + 6216a

S₁ + S₂ = 2290 m

(308.4 + 1800a) + (532.5 + 6216a) = 2290

8016a + 840.9 = 2290

8016a = 1449.1

a = 0.18 m/s²

The force on charge at point B due to the other two charges is 2.71 × 10⁻¹¹ N.

The distance between charge at point C and B is given as r₁Distance, r₁ = AB = 2m

The distance between charge at point A and B is given as r₂ r₂ = AB/cos (ACB) r₂ = 2m/cos 41.81°r₂ = 2.88m

The force between charge at point C and B is given by Coulomb's Law as, F₁ = kq₁q₂/r₁² Where, k is Coulomb's constant, 9 × 10⁹ Nm²C⁻²q₁ and q₂ are charges on point C and B respectively.

Substitute the values: F₁ = (9 × 10⁹ × 0.225 × 10⁻⁶ × 1)/(2)²F₁ = 1.0125 × 10⁻¹¹ N

Now, the force between charge at point A and B is given by Coulomb's Law as, F₂ = kq₁q₂/r₂² Where, q₁ and q₂ are charges on point A and B respectively.

Substitute the values: F₂ = (9 × 10⁹ × 0.18 × 10⁻⁶ × 1)/(2.88)²F₂ = 2.51 × 10⁻¹¹ N

The force acting on point B due to charges at points A and C is the vector sum of forces F₁ and F₂.F = √(F₁² + F₂²)F = √(1.0125 × 10⁻¹¹)² + (2.51 × 10⁻¹¹)²F = √(1.025 × 10⁻²² + 6.305 × 10⁻²²)F = √(7.33 × 10⁻²²)F = 2.71 × 10⁻¹¹ N

Thus, the force on charge at point B due to the other two charges is 2.71 × 10⁻¹¹ N.

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This motion of the balloon is an example of buoyancy, which is the upward force exerted by a fluid on an object immersed in it.

When the balloon is neutrally buoyant, it means that the weight of the balloon and the weights attached to it is equal to the weight of the water displaced by the balloon.

If you push the balloon down to a greater depth and then release it, the balloon will rise back up to its original position.

This is because the balloon is still partially inflated and contains air, which is less dense than water. When you push the balloon down, the water pressure compresses the air in the balloon, causing it to become smaller in size.

When you release the balloon, the compressed air expands and pushes the balloon upwards towards the surface of the water.

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Answer:

The higher the skater is the more potential energy he has. As his height decreases, his potential energy decreases and his kinetic energy increases.

Explanation:

Make me BRAINLIST please

Answer:

The higher the skater is the more potential energy he has. As his height decreases, his potential energy decreases, and his kinetic energy increases. ... Explore how the skater's change in speed relates to the potential and kinetic energy of the skater.

Explanation:

(Via Uteach)

Answer:

yes because it caries a message on ecological and evolutionary assembly of the classified vegetation and flora. Its known to be called a Vegetation map or Vegetation Mapping.

Explanation:

Yes, it will be safe to have the turbine component operate at 1150°C

Based on the given information, the melting temperatures of iron and titanium are 1538°C and 1668°C, respectively. In an iron-titanium alloy, these two elements are combined, resulting in an intermediate melting temperature. This alloy would have a higher melting temperature than pure iron and lower than pure titanium.

Operating the turbine engine at 1150°C would be safe, as this temperature is significantly below the melting temperatures of both elements. It provides a sufficient margin of safety for the alloy, ensuring that it remains solid and stable during operation. Additionally, alloys typically have improved mechanical properties, such as increased strength and resistance to wear, compared to their constituent elements. This makes iron-titanium alloys suitable for high-temperature applications like turbine engines.

In summary, using an iron-titanium alloy for a turbine engine operating at 1150°C should be safe and appropriate due to its enhanced mechanical properties and melting temperature range.

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Answer: Push of the ball on the earth. The reaction force is equal and opposite to the action force, according to Newton's Third Law of Motion.

Explanation: In other words, when the earth pulls the ball downward with a force, the ball pushes back on the earth with an equal and opposite force. This occurs because forces are always pairs of equal and opposite forces, known as action-reaction forces. The action force is the force that initiates the interaction, while the reaction force is the force that responds to the action force. In this case, the action force is the pull of the earth on the ball, while the reaction force is the push of the ball on the earth.