PLZ PLZ PLZ SOMEBODY ANSWERS THIS!!!!

Answer:

$60 + $9 = $69

Step-by-step explanation:

Answer:

Total bill = $60.00

Step-by-step explanation:

Tip = $9.00

Percentage = 15%

15% of x = 9

15/100 x = 9

x = 9 x 100/ 15 = 60

Total bill = $60.00

I hope im right!!

Answer:

0

Step-by-step explanation:

g(-1)=3×(-1)²-2×(-1)-5 g(-1)=3×1+2-5 g(-1)=3+2-5 g(-1)=5-5 g(-1)=0 ......

The value of g(x) = 3x² - 2x - 5, at x = -1 is g(-1) and it is equal to zero.

A function can be defined as the outputs for a given set of inputs.

The inputs of a function are known as the independent variable and the outputs of a function are known as the dependent variable.

Given, A function g(x) = 3x² - 2x - 5.

Now, The value of g(-1) is the same as x = - 1 in g(x).

Therefore, g(-1) = 3(-1)² - 2(-1) - 5.

g(-1) = 3 + 2 - 5.

g(-1) = 0.

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Answer:

5

Step-by-step explanation:

EF = 47 - 7x = 1/2 BC = 1/2 * (14+4x)

solve for x

x=6

so EF = 47-7*6 =  5

Producing rDNA involves isolating and cleaving DNA, inserting fragments into a vector, and transforming host cells. rDNA can be introduced via transformation, transfection, or viral vectors. Clinical applications include protein production, gene therapy, vaccines, and diagnostics.

Producing a recombinant DNA (rDNA) vector involves several general steps. Here are the three main steps involved in the process:

Isolation and Cleavage of DNA:

The first step is to isolate the desired DNA fragments from the source organism. This can be done using various techniques such as PCR (Polymerase Chain Reaction) or restriction enzyme digestion. Restriction enzymes are enzymes that cut DNA at specific recognition sites. By using the appropriate restriction enzymes, the desired DNA fragment and a vector DNA can be cut at specific sites. The vector is usually a plasmid, which is a small circular DNA molecule.

Insertion of DNA Fragments into the Vector:

Once the DNA fragments and vector have been cut, they are mixed together and joined through a process called ligation. DNA ligase is used to catalyze the formation of covalent bonds between the ends of the DNA fragments and the vector. This creates a recombinant DNA molecule containing the desired DNA fragment within the vector. The recombinant DNA molecule is then introduced into host cells for replication.

Transformation of Host Cells:

The recombinant DNA molecules need to be introduced into host cells to produce multiple copies of the recombinant DNA. This is typically done using a process called transformation. Host cells, such as bacteria or yeast, are treated in a way that makes them more receptive to taking up the recombinant DNA. Methods for transformation include heat shock, electroporation, or using chemical agents. Once the host cells have taken up the recombinant DNA, they can be grown in culture to produce large quantities of the desired DNA fragment.

Introduction of rDNA into Cells:

Recombinant DNA can be introduced into cells using various methods, depending on the type of cells being targeted. Some common techniques include:

Transformation: As mentioned earlier, host cells, such as bacteria or yeast, can be treated to make them receptive to taking up the recombinant DNA. This can be achieved by exposing the cells to heat shock, electroporation, or using chemical agents.

Transfection: This method is used for introducing rDNA into eukaryotic cells, including animal cells. It involves the use of techniques such as calcium phosphate precipitation, liposome-mediated transfection, or electroporation.

Viral Vectors: Certain viruses, such as retroviruses, adenoviruses, or lentiviruses, can be modified to carry the recombinant DNA. These viral vectors can then infect target cells and deliver the rDNA into the host genome.

Clinical Applications of rDNA:

Recombinant DNA technology has revolutionized biomedical research and has led to numerous clinical applications. Some important applications include:

Production of Therapeutic Proteins: rDNA technology allows for the production of large quantities of therapeutic proteins, such as insulin, growth factors, clotting factors, and monoclonal antibodies. These proteins can be used to treat various diseases, including diabetes, cancer, and genetic disorders.

Gene Therapy: rDNA vectors can be used to deliver functional copies of genes into target cells to correct genetic defects. This holds promise for the treatment of inherited diseases caused by single gene mutations, such as cystic fibrosis and muscular dystrophy.

Vaccine Development: Recombinant DNA technology has been instrumental in the development of vaccines. By expressing specific antigens from pathogens, recombinant vaccines can be created to stimulate an immune response without causing disease.

Diagnostic Tools: Recombinant DNA techniques are used to produce specific DNA or RNA probes for diagnostic purposes. These probes can detect the presence of specific genes or mutations associated with diseases, aiding in early detection and personalized medicine.

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Answer:

hi

Step-by-step explanation:

Answer:

\((2 {n}^{2} ) ^{4} \\ 2 \times 2 \times 2 \times 2 \times {n}^{2 \times 4} \\ {2}^{4} \times {n}^{8} \\ = 16 {n}^{8} \)

x = 4, y = -2/7

1. Multiply the first equation by -1:

-3x-7y = -10

2. Add the two equations together:

-3x-7y = -10

+ x + y=2

-2x = -8

3. Divide both sides by -2 to solve for x:

-2x/2 = -8/2

x = 4

4. Substitute x=4 into the equation 3x+7y=10:

3(4) + 7y = 10

5. Simplify the equation and solve for y:

12 + 7y = 10

7y = -2

y = -2/7

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Answer:

-6

Step-by-step explanation:

just substitute -1 for x

15(-1)+9 = -15+9 = -6

Answer:

13............=y......

The probability that at most 13 of the residers in the sample entered a jury process in the once 12 months is 0.000158.

A normal distribution, also known as a Gaussian distribution or bell wind, is a probability distribution that's symmetric and bell- shaped. It's characterized by its mean( μ) and standard divagation( σ).

Given

Sample size( n) = 500

Probability of an individual entering a jury process( p) = 15 = 0.15

We want to calculate the probability that at most 13 of the residers in the sample entered a jury process.

Let X be the arbitrary variable representing the number of residers who entered a jury process in the sample.

Using the binomial accretive distribution function( CDF), we can calculate the probability as follows

P( X ≤ 13 of n) = Σ( k = 0 to k = 0.13 n)( n C k)

Here, n = 500

p = 0.15

k = int(0.13 n)

So, binom.cdf( int(0.13 500), 500,0.15) ≈0.000158

Thus, The likelihood that 13% of the sample's residents received a jury summons in the previous year is 0.000158.

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The question attached here is seems to be incomplete, the complete question is

What proportion of US Residents receive a jury summons each year? A polling organization plans to survey a random sample of 500 US Residents to find out. Let be the proportion of residents in the sample who received a jury summons in the previous 12 months. According to the National Center for State Courts, 15 \% of US residents receive a jury summons each year. Suppose that this claim is true.

5. Calculate the probability that at most 13% of the residents in the sample received a jury summons in the past 12 months.

We can calculate the product of 5/8 and 4 to be 5/2 using multiplication.

Multiplication is one of the four basic mathematical operations, along with addition, subtraction, and division.

The result of a multiplication operation is a product.

There are four different methods for multiplying: addition, long multiplication, grid multiplication, and drawing lines.

So, we have:
5/8 and 4

5/8 is in the form p/q which represents the fraction that must be multiplied by 4.

Now, calculate the product as follows:

5/8 * 4

5/2

Therefore, we can calculate the product of 5/8 and 4 to be 5/2 using multiplication.

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The Java program Factorial.java implements a recursive method to compute the factorial of a nonnegative integer less than 11.

The Factorial.java program in Java utilizes a recursive method to calculate the factorial of a given number. The recursive method follows the mathematical definition of factorial, where the factorial of a number n is n multiplied by the factorial of (n-1). The program first checks if the input number is within the valid range (0 to 10). If it is, the program calls the recursive method to calculate the factorial. The base case of the recursive method is when the input number is 0 or 1, where the factorial is defined as 1. For any other number, the method recursively calls itself with the number decreased by 1 until it reaches the base case. The factorial value is calculated by multiplying the current number with the factorial of the decreased number. Finally, the program displays the computed factorial as output.

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In the inductive step of the proof for this theorem, it must be shown that if q(k) is true for some positive integer k, then q(k+1) must also be true. This can be done by assuming q(k) is true and using it to prove that q(k+1) is also true.

To do this, one typically starts by assuming q(k) is true and using it to establish some new statement, often denoted q'(k+1), which is related to q(k+1). Then, one must show that q'(k+1) implies q(k+1), which completes the inductive step.

The key idea behind this approach is that by proving that q(k) implies q(k+1), and establishing the base case that q(1) is true, we can conclude that q(n) is true for all positive integers n. This is because the inductive step ensures that the truth of q(k) implies the truth of q(k+1) for any k, and so we can use this to "chain" together the truth of q(1), q(2), q(3), and so on, for all positive integers n.

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Student is asking for the same question solved two minutes ago.

Answer:

567 minutes each month.

Step-by-step explanation:

Let x be the number of minutes of talk time used each month.

The cost for talk time beyond 500 minutes is $0.08 * (x - 500)

The cost for email is $27.70 * 0.3 = $8.31

The total monthly cost is $27.70 + $0.08 * (x - 500) + $8.31 = $35.99

The total cost for 9 months is $35.99 * 9 = $323.91

So we can set up the equation:

$27.70 + $0.08 * (x - 500) + $8.31 * 9 = $367.29

Solving for x, we get:

x = 567

So the number of minutes of talk time used each month is 567 minutes.

Answer:

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Answer:

the answer is 4:1

Step-by-step explanation:

as 5x2=10

20x2=40

40:10 or

\( \binom{40}{10} \)

if you cancel them it is 4:1

Answer:

It's A have a good day!

Step-by-step explanation:

The 95% confidence interval for the true proportion of people who favor candidate is (0.419,0.481).

A random sample of 1000 people was condidered for testing.

Number of people in sample favoured candidate

= 450

So, sample proportion, p = 450/1000 = 0.45

Confidence level= 95% i.e, alpha = 1 - 0.95=0.05, From standard normal Z- table, the value of Z( 0.025) is equals to 1.96..

Confidence interval formula,

CL = p ± Z× √(p×(1-p)/n)

Lower bound of interval is ,

=0.45 - 1.96× √(0.45× (1-0.45)/1000)

= 0.45 - 1.96× √(0.45× 0.55/1000)

= 0.45 - 1.96× √(0.0002475)

=0.419165~ 0.419

So the Upper bound is

= p + Z×√(p×(1-p)/n)

= 0.45 + 1.96× √(0.45× (1-0.45)/1000)

= 0.45 + 1.96× √(0.0002475)

= 0.480835 ~0.481

Hence, the required confidence interval is (0.419,0.481).

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The number of small vehicles that were washed in total is: 60

Algebraic word problems are problems that require converting a sentence into an equation and solving that equation. Usually in real-life scenarios variables represent unknown quantities.

We are given:

5x + 10y = 800

replace y with 50 to get:

5x + 10(50) = 800

5x+500 = 800

5x = 800-500

5x = 300

x = 300/5

x = 60

60 small vehicles were washed in total.

proof: 5x+10y = 800

replace x=60 and y=50

      so; 5(60) +10(50) =800

            300 + 500 = 800

                    800 = 800

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Answer:

Step-Opens up with a vertex at (4,-1)by-step explanation:

Answer:

51.5 thermes of gas were used

The amount of chlorine in the pool at the start of any given week, we need to know the amount of chlorine in the pool at the start of the previous week.

Let Cn be the amount of chlorine in the pool at the start of the nth week.

We can start by finding the amount of chlorine in the pool at the start of the second week. Since 40% of the chlorine evaporates, we have:

C2 = 0.6(C1 + 16)

Now, we can use this formula to find the amount of chlorine in the pool at the start of the third week:

C3 = 0.6(C2 + 16)

We can continue this process to find a recursive rule for Cn:

Cn = 0.6(Cn-1 + 16)

where C1 = 34.

This formula tells us that to find the amount of chlorine in the pool at the start of any given week, we need to know the amount of chlorine in the pool at the start of the previous week. We can use this formula repeatedly to find the amount of chlorine in the pool at the start of any week.

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These constants can be determined by applying initial conditions or boundary conditions specific to the problem. Once the values of C1 and C2 are determined, the general solution becomes a particular solution that satisfies the given conditions.

To find the general solution, we assume a solution of the form y(t) = e^(rt) and substitute it into the differential equation. This leads to the characteristic equation r^2 + 11r - 12 = 0.

Solving the quadratic equation, we find two roots: r1 = -12 and r2 = 1. These roots correspond to the exponential terms e^(-12t) and e^(t) in the general solution.

Since the equation is linear, the general solution is the linear combination of the individual solutions associated with the roots. Therefore, the general solution is y(t) = C1e^(-12t) + C2e^(t), where C1 and C2 are constants of integration.

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Use the change-of-base identity to rewrite the equation as

2 log(x³) / log(4x) = 5 log(x) / log(2x)

Multiply both sides by log(4x) log(2x), noting that this is only valid if x > 0 and neither x = 1/2 nor x = 1/4 :

2 log(x³) log(2x) = 5 log(x) log(4x)

Bring down the exponent in the first logarithm:

6 log(x) log(2x) = 5 log(x) log(4x)

Move everything to one side and factorize:

6 log(x) log(2x) - 5 log(x) log(4x) = 0

log(x) (6 log(2x) - 5 log(4x)) = 0

Then either

log(x) = 0   or   6 log(2x) - 5 log(4x) = 0

In the first equation, after taking the exponential of both sides, we get

exp(log(x)) = exp(0)   →   x = 1

In the second equation, we have

6 log(2x) = 5 log(4x)

Expand the logarithms into sums:

6 (log(2) + log(x)) = 5 (log(4) + log(x))

6 log(2) + 6 log(x) = 5 log(4) + 5 log(x)

Simplify:

log(x) = 5 log(4) - 6 log(2)

4 = 2², so

log(x) = 5 log(2²) - 6 log(2)

log(x) = 10 log(2) - 6 log(2)

log(x) = 4 log(2)

log(x) = log(2⁴)

log(x) = log(16)

Take the exponential of both sides to get

exp(log(x)) = exp(log(16))   →   x = 16

Answer:

x=1, x=16

Step-by-step explanation:

Answer:

there should be 14, 45 pound boxes

Step-by-step explanation:

1000-190= 810

810/45=14 boxes

Answer:

how do I solve this

where is the photo

Answer:

6 teaspoons

Step-by-step explanation:

2 teaspoons = 1/3 tsp of salt

6 teaspoons = 1 tsp of salt

This was done by multiplying 2 by 3 since 3 thirds (3/3) make one whole.

So if 2 teaspoons are used for 1/3 teaspoon of salt, 4 teaspoons would be used for 2/3 teaspoon of salt and 6 teaspoons would be used for 1 teaspoon of salt.

Answer: I don't know for myself.

Step-by-step explanation:

I hope this help

\(\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}\)

It would be written as a =± 11