Plz, Help :/ you can choose any question you want or all of it if you pleased.

Answer: D. If the reaction occurs in the gas phase

Explanation:

Answer:

D is correct via A P e x

Explanation:

Answer:

1.) Atomic No. 19

No. of proton 19

No. of electron 19

symbol 39K19

2.) Atomic no. 26

Mass No. 56

No. of proton 26

Symbol 56Fe26

Answer:

fu-ck fick

Explanation:

The mole fraction of urea in the solution is 0.221.

The vapor pressure of a solution is related to the mole fraction of the solute in the solution by Raoult's law, which states that the partial vapor pressure of a component in a solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the solution.

Using this law, we can write:

P_total = P_urea + P_water

where P_total is the total vapor pressure of the solution, P_urea is the partial vapor pressure of urea, and P_water is the partial vapor pressure of water.

We are given that P_total = 294.7 mmHg and P_water = 359.8 mmHg.

Rearranging Raoult's law, we get:

X_urea = P_urea / P_total

Substituting the values we have, we get:

X_urea = (P_total - P_water) / P_total = (294.7 - 359.8) / 294.7 = -0.221

However, this answer doesn't make sense since the mole fraction of a component in a solution cannot be negative. Therefore, we need to take the absolute value of the answer, which gives:

X_urea = 0.221

Therefore, the mole fraction of urea in the solution is 0.221.

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Answer:

190n

Explanation:

190 190 and because it is easy to understand if you didn't understand my answer ask any man

Martina needs to use 677.7 milliliters of Solution B in order to make a mixture with 119 milliliters of pure alcohol.

To calculate the amount of Solution B she is using, we must first determine the total amount of pure alcohol in the resulting mixture. The total amount of pure alcohol in the mixture is 119 milliliters.

Using the following equation, we can calculate the amount of Solution B Martina is using:

Pure Alcohol (Solution A) + Pure Alcohol (Solution B) = 119

(18% x Amount of Solution A) + (13% x Amount of Solution B) = 119

Solving for Solution B, we get:

(13% x Amount of Solution B) = 119 - (18% x (Amount of Solution A - 200))

(13% x Amount of Solution B) = 119 - (18% x (Amount of Solution A - 200))

Amount of Solution B = (119 - (18% x (Amount of Solution A - 200)))/13%

Therefore, Martina is using 677.7 milliliters of Solution B.

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The binding energy of a nucleus refers to the minimum energy required to separate the nucleus into its constituent nucleons. The binding energy per nucleon (BE/A) is a more useful quantity than the absolute binding energy (BE) since it takes into account the number of nucleons present.

The more tightly bound a nucleus is, the higher its binding energy per nucleon. The equation that determines the binding energy is given by the formula, E=Δmc² where E is the binding energy, Δm is the mass defect, and c is the speed of light. The mass defect is the difference between the actual mass of a nucleus and the sum of the masses of its individual protons and neutrons. The mass of antimony-121 is the sum of the masses of its constituent nucleons, given by: Mass of antimony-121 = (71 x 1.00783 u) + (50 x 1.00867 u) = 120.90380 u The actual mass of antimony-121 is 120.90380 u. Using the mass of each nucleon and the actual mass of antimony-121, the mass defect of the nucleus can be determined as follows: Mass defect (Δm) = [71(1.00783 u) + 50(1.00867 u)] - 120.90380 u= 0.1471 u The binding energy can then be calculated using the formula: E = Δmc²= (0.1471 u)(1.66054 x 10^-27 kg/u)(2.99792 x 10^8 m/s)^2= 2.539 x 10^-10 J/mol To convert this to kilojoules per mole, we can divide by 1000:2.539 x 10^-10 J/mol = 2.539 x 10^-13 kJ/mol Therefore, the binding energy of antimony-121 is 2.539 x 10^-13 kJ/mol.

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Answer:

50°F,  70°F

Explanation:

Answer:

50 and 70 degrees F

Explanation:

got it right on the quiz on edge

The pH of the buffer solution is 4.76.

To calculate the pH of the buffer solution, we need to use the Henderson-Hasselbalch equation, which is given by:

pH = pKa + log([A-]/[HA])

where pKa is the dissociation constant of the weak acid, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

For acetic acid (CH3COOH), the pKa is 4.76.

Since the buffer solution contains equal concentrations of acetic acid and sodium acetate, we can assume that [A-] = [CH3COO-] = 1.00 M and M[HA] = [CH3COOH] = 1.00 M.

Therefore, plugging in these values into the Henderson-Hasselbalch equation, we get:

pH = 4.76 + log([1.00]/[1.00]) = 4.76

Therefore, the pH of the buffer solution is 4.76.

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The number of atoms of Oxygen (O) in 7. 23 moles of Ca(NO₃)₂ = 2.61 × 10²⁵ atoms.

To determine the number of atoms of O in 7.23 moles of Ca(NO₃)₂, we need to use the formula for the number of atoms, which is:
Number of atoms = Number of moles × Avogadro's number × Number of atoms in one molecule
Avogadro's number is 6.022 × 10²³ atoms/mole.
In one molecule of Ca(NO₃)₂, there are 6 atoms of O.
So, the number of atoms of O in 7.23 moles of Ca(NO₃)₂ is:
Number of atoms of O = 7.23 moles × 6.022 × 10²³ atoms/mole × 6 atoms/molecule

= 2.61 × 10²⁵ atoms of O
Therefore, there are 2.61 × 10²⁵ atoms of O in 7.23 moles of Ca(NO₃)₂.

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The temperature of the 45.0 g piece of metal changed from 241 °C to 32.0 °C. is 0.48 j/ 9°C.

Temperature is a measure of the average kinetic energy of the atoms or molecules in the system. The zeroth law of thermodynamics says that no heat is transferred between two objects in thermal equilibrium; therefore, they are the same temperature.

In other words, Temperature is the measure of hotness or coldness of a body measured using Celsius, Kelvin, and Fahrenheit scales. The change in temperature is based on the amount of heat released or absorbed. The S.I unit of temperature is Kelvin. The Temperature formula is given by, Δ T = Q / mc.

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The equilibrium constant of the dissociation of potassium hydrogen tartrate (KHT) is equal to the square of the bitartrate concentration due to the dissociation of KHT into two hydrogen ions (H+) and bitartrate ions (HC₄H₄O₆⁻) as shown below:

KHT ⇌ H+ + HC₄H₄O₆⁻

Here, the equilibrium constant expression for the dissociation reaction of KHT can be written as follows:

Kc = [H+] [HC₄H₄O₆⁻]/ [KHT]

As we know, KHT dissociates into two moles of bitartrate ion (HC₄H₄O₆⁻) and one mole of hydrogen ion (H+). So, after the dissociation of KHT, the concentration of the bitartrate ion (HC₄H₄O₆⁻) will be double that of the hydrogen ion (H+).

Therefore, the concentration of hydrogen ion (H+) will be equal to the square root of the concentration of bitartrate ion (HC₄H₄O₆⁻).

Hence, Kc = [H+]²[HC₄H₄O₆⁻]/ [KHT] = [HC₄H₄O₆⁻]²/ [KHT]

This is the reason why the equilibrium constant of the dissociation of KHT is equal to the square of the bitartrate concentration.

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Answer:

Become Visible

Explanation:

A chemical equation is said to be balanced if it obey the law of conservation of mass. The numbers which are used to balance the chemical equations are called the coefficients.

In a balanced chemical equation, the number of atoms of reactants and products are equal on both sides of the equation. The coefficients are essential in order to balance the equation.

Here the oxidation half reaction is:

2I⁻ (aq) → I₂ (s) + 2e⁻

The balanced reduction half reaction is:

MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ → Mn²⁺ (aq) + 4H₂O (l)

Balance the number of electrons exchanged as:

5 × equation - 1 + 2 × equation 2

10 I⁻ (aq) + 2MnO₄⁻ (aq) + 16 H⁺ (aq) + 10e⁻ → 5I₂ (s) + 2Mn²⁺ (aq) + 8H₂O (l) + 10 e⁻

Remove similar species on both sides of the equation;

10 I⁻ (aq) + 2MnO₄⁻ (aq) + 16 H⁺ (aq)  →  5I₂ (s) + 2Mn²⁺ (aq) + 8H₂O (l)

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Answer:

B) They will react because X and Y can share two pairs of electrons to become stable

Explanation:

The electron configurations of two elements x and y are given :

X: 1s2 2s2 2p6

Y: 1s2 2s2 2p6 3s2 3p6

The statement that is true for both the elements is that, they both will react as they both can share two pairs of electrons to become stable.

To become stable the outermost shell or p orbital should have 8 electrons, so element X  can gain 2 atoms to become stable.

Element Y can also react as it can also share two atoms to fulfill its 3p orbital and will stable.

Hence, the correct option is "B".

Answer:

he main ingredient in most plastic material is a derivative from crude oil and natural gas. There are many different types of plastics – clear, cloudy, solid colour, flexible, rigid, soft, etc. Plastic products are often a polymer resin which is then then mixed with a blend of additives (See polymer vs. plastic).

~+lil more info +~

Plastics are made from natural materials such as cellulose, coal, natural gas, salt and crude oil through a polymerisation or polycondensation process. Plastics are derived from natural, organic materials such as cellulose, coal, natural gas, salt and, of course, crude oil.

Knowing the number of electrons in the K atom is necessary before we can write the potassium octet (there are 19 electrons).

The electron, the smallest constituent part of an atom, has a negative electrical charge .Protons and electrons each occurs in similar numbers in neutral atoms. One atom and one proton are all that the hydrogen atom has. On the other hand, the uranium atom possesses 92 protons, which means 92 electrons.

The electrons are an atom's negatively charged building blocks. The total negative charge of an atom's electrons counteracts the charge of its protons in the elementary particle.

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Answer:The overall ionic formula for a compound must be electrically neutral, meaning it has no charge. When writing the formula for the ionic compound, the cation comes first, followed by the anion, both with numeric subscripts to indicate the number of atoms of each.

Explanation:

Explanation:

At the start of the citric acid cycle, a molecule of oxaloacetate accepts a two-carbon acetyl group from acetyl CoA to form citrate. This reaction kicks off the citric acid cycle; thus, oxaloacetate is required for the cycle to take place.

To begin the citric acid cycle, an oxaloacetate molecule accepts a two-carbon acetyl group from acetyl CoA to form citrate. Because this reaction initiates the citric acid cycle, oxaloacetate is required for the cycle to occur.

The Krebs cycle, also known as the citric acid cycle or TCA cycle, is a chain of reactions that occurs in the mitochondria and is used by almost all living cells to produce energy through aerobic respiration. It consumes oxygen and emits water and carbon dioxide as byproducts.

All aerobic organisms use a series of chemical reactions to generate energy by converting acetate derived from carbohydrates, fats, and proteins into carbon dioxide.

The citric acid cycle involves the attachment of an acetyl group from acetyl CoA to a four-carbon oxaloacetate molecule to form a six-carbon citrate molecule.

Thus, Citrate is oxidized in a series of steps, releasing two carbon dioxide molecules for each acetyl group fed into the cycle.

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Magnesium loses two electrons to oxygen to form Mg²⁺ and O²⁻ ions. The ionic formula for this compound can be predicted by writing the formula unit that balances the charges of the two ions. The ionic formula for magnesium oxide is MgO.

The Lewis dot structure of magnesium is Mg with two dots representing its valence electrons. The Lewis dot structure of oxygen is O with six dots representing its valence electrons.

Magnesium and oxygen form an ionic compound because magnesium loses two electrons to oxygen to form Mg²⁺ and O²⁻ ions. The ionic formula for this compound can be predicted by writing the formula unit that balances the charges of the two ions.

Since Mg²⁺ has a 2+ charge and O²⁻ has a 2- charge, the ionic formula for magnesium oxide is MgO.

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Answer:

I think it is more that one is correct, so sorry if I'm wrong, if it isn't, it is one of the electron bonding ones

Answer:

The answer is larynx. I believe it is anyways. Sorry if i'm wrong.

Answer:

The vocal folds, also known as vocal cords, are located within the larynx (also colloquially known as the voice box) at the top of the trachea.

Explanation:

A building is found to contain a radioactive gas. Thirty hours later, 60% of the initial amount of gas is still present.So, we have to calculate the half-life of the radioactive gas.

(a) Write a model for the percentage of the initial amount of the radioactive gas present after t hours. (Round all numerical values to three decimal places.)

Formula used to find the amount of radioactive gas present after t hours:

So, the remaining amount of radioactive gas is 40%.That is, r(t) = 40% = 0.40r₀and t = 30So, the formula becomes:

(b) Calculate the half-life of the radioactive gas. (Round your answer to three decimal places.)From the formula,r(t) = r₀ (1/2)^(t/T)When t = T, r(t) = 1/2 of r₀r(T) = r₀/2Divide both sides by r₀r(T)/r₀ = 1/2We have r(T)/r₀ = 0.5, and the formula becomes 0.5 = (1/2)^(T/T)0.5 = (1/2)^1T = 1Therefore, the half-life of the radioactive gas is one hour.Answer Half-life of the radioactive gas = 1 hour.

Radioactive is the ability of an unstable atomic nucleus to become stable through emission of radiation. This capability involves the process of splitting unstable atomic nuclei resulting in energy loss by emitting radiation, such as alpha particles, beta particles with neutrinos and gamma rays. What is radioactive impact? It is necessary to know, radioactive substances from nuclear radiation are compounds that are harmful to humans and other living things. The effects of nuclear radiation not only damage human DNA, but can also cause cancer. The effects of nuclear radiation can damage the atoms in the body and damage DNA.

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Therefore, 800ml of a 1.25m aqueous ammonia solution contains 1000moles of ammonia.

Ammonium hydroxide appears as an aqueous solution with no color. Ammonia concentrations might reach as high as 30%. The eyes become irritated by the solution's ammonia fumes. Ammonium hydroxide is created when ammonia is dissolved in water. A solution of ammonia in water is referred to as ammonia solution, ammonia water, ammonium hydroxide, aqua ammonia, aqueous ammonia, or ammonia. The symbols for it are NH3 and NH4.

Making an Aqueous Ammonia Solution: Ammonia is dissolved in water to create an aqueous solution. Ammonia dissolves in water at a relatively rapid pace, making water back suction a possibility. Rubber tubing is used to link a funnel to the delivery tube's exterior end in order to prevent this.

Ammonia produced by industry is used as fertilizer in agriculture to the tune of 80%. In addition to these uses, ammonia is made into plastics, explosives, textiles, pesticides, dyes, and other chemicals. Additionally, it is used to clean water sources.

Concentration (C) = number of moles (n) / volume (v)

number of moles (n) = concentration × volume

Concentration = 1.25M

Volume =800 L = 800dm³

n = 1.25 × 800

n = 1000 moles

There are 1000 moles of ammonia in the solution.

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The t-shirt is made of natural materials and some synthetic materials made from natural materials.

We know that there are various types of fabrics. These fabrics may be natural or synthetic, the natural materials include cotton. Polyester and rayon are synthetic fibers that are made from naturally occurring materials.

Thus the statement that is true about the cloth is that; the t-shirt is made of natural materials and some synthetic materials made from natural materials.

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- In the reaction N₂(g) + 3H₂(g) → 2NH₃(g), the rate of disappearance of N₂ is 0.016 M/s, and the rate of disappearance of H₂ is 0.048 M/s.

- In the reaction CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g), the rate of appearance of CO₂ is 2.6 M/s, and the rate of appearance of H₂O is 5.2 M/s.

To determine the rate of disappearance or appearance of reactants or products in a chemical reaction, we can use the stoichiometric coefficients from the balanced equation. Let's analyze the given reactions:

1. N₂(g) + 3H₂(g) → 2NH₃(g)

The stoichiometric coefficients in this equation tell us that for every 1 mole of N₂ that reacts, 2 moles of NH₃ are produced. Therefore, the rate of disappearance of N₂ is equal to half the rate of appearance of NH₃, as it is consumed at half the rate. Since the reaction rate of NH₃ is given as 0.032 M/s, the rate of disappearance of N₂ would be:

Rate of disappearance of N₂ = 0.032 M/s ÷ 2 = 0.016 M/s

Similarly, for every 1 mole of N₂ that reacts, 3 moles of H₂ are consumed. Therefore, the rate of disappearance of H₂ is three times the rate of disappearance of N₂. Thus, the rate of disappearance of H₂ would be:

Rate of disappearance of H₂ = 0.016 M/s × 3 = 0.048 M/s

2. CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

The stoichiometric coefficients in this equation tell us that for every 1 mole of CH₄ that reacts, 1 mole of CO₂ is produced. Therefore, the rate of appearance of CO₂ is equal to the rate of disappearance of CH₄. Since the reaction rate of CH₄ is given as 2.6 M/s, the rate of appearance of CO₂ would also be:

Rate of appearance of CO₂ = 2.6 M/s

Furthermore, for every 1 mole of CH₄ that reacts, 2 moles of H₂O are produced. Therefore, the rate of appearance of H₂O is twice the rate of disappearance of CH₄. Thus, the rate of appearance of H₂O would be:

Rate of appearance of H₂O = 2.6 M/s × 2 = 5.2 M/s

These rates are determined based on the stoichiometric relationships between reactants and products in each equation.

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the original pressure of the gas was 1.728 atm.

To solve this problem, we can use the ideal gas law, which relates the pressure, volume, number of moles, and temperature of a gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.

Assuming that the number of moles and the temperature of the gas remain constant, we can write:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume of the gas, and P2 and V2 are the final pressure and volume.

Substituting the given values, we get:

P1 x 5.00 L = 0.720 atm x 12.0 L

Solving for P1, we get:

P1 = (0.720 atm x 12.0 L) / 5.00 L

P1 = 1.728 atm

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Answer:

W has the most potential energy