answer:
sorry i don't know the answer but are you an army ?
Air is being pumped into a spherical balloon at the rate of 7 cm³/sec. What is the rate of change of the radius at the instant the volume equals 36n cm³ ? The volume of the sphere 47 [7] of radius r is ³.
the rate of change of the radius at the instant the volume equals 36π cm³ is 7 / (36π) cm/sec.
The volume V of a sphere with radius r is given by the formula V = (4/3)πr³. We are given that the rate of change of the volume is 7 cm³/sec. Differentiating the volume formula with respect to time, we get dV/dt =(4/3)π(3r²)(dr/dt), where dr/dt represents the rate of change of the radius with respect to time.
We are looking for the rate of change of the radius, dr/dt, when the volume equals 36π cm³. Substituting the values into the equation, we have: 7 = (4/3)π(3r²)(dr/dt)
7 = 4πr²(dr/dt) To find dr/dt, we rearrange the equation: (dr/dt) = 7 / (4πr²) Now, we can substitute the volume V = 36π cm³ and solve for the radius r: 36π = (4/3)πr³
36 = (4/3)r³
27 = r³
r = 3 Substituting r = 3 into the equation for dr/dt, we get: (dr/dt) = 7 / (4π(3)²)
(dr/dt) = 7 / (4π(9))
(dr/dt) = 7 / (36π)
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Describe the graph of y = 1/2 x − 10 − 3 compared to the graph of y = 1 x .
The graph of y = [1/2(x -10)] - 3, compared to the graph of 1/x, represents these following transformations:
Horizontal compression by a scale factor of 2.Translation right 10 units.Translation down 3 units.What is a translation?A translation happens when either a figure or a function is moved horizontally or vertically on the coordinate plane.
The four translation rules for functions are defined as follows:
Translation left a units: f(x + a).Translation right a units: f(x - a).Translation up a units: f(x) + a.Translation down a units: f(x) - a.The translations for this problem are given as follows:
x -> x - 10: shift right 10 units.y -> y - 3: shift down 3 units.Additionally, there was a multiplication by 2 in the domain, meaning that the parent function was horizontally compressed by a factor of 2.
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Mr. Duncan earns 75$ a day plus 35$ for each car he sells. if c is his total earnings and x is the number of cars he sold, what is the equation
Answer: c= 35x + 75
Step-by-step explanation:
If he earns $75 then that will be the constant amount which means it will never change, plus $35 for x cars, will give us the expression 35x + 75 and that has to equal c which is his total earnings.
Answer:
c = 35x + 75Step-by-step explanation:
Daily pay = $75Commission for each car = $35Total earnings for x cars sold:
c = 35x + 75Bernard says “When you halve a whole number that ends in 8, you always
get a number that ends in 4”
Write down an example to show that Bernard is wrong.
is this a trick question?
Answer:
Bernad is WRONG.
Step-by-step explanation:
Let us take the number '18' (ends with 8)
The half of 18 is '9' (doesn't end with 4)
Let us take the number '38' (ends with 8)
The half of 38 is '19' (doesn't end with 4)
Therefore, Bernard is wrong.
Bernard is wrong because When you halve a whole number that ends in 8, you always cannot get a number that ends in 4”
What is an arithmetic operation?It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
It is given that:
Bernard says “When you halve a whole number that ends in 8, you always get a number that ends in 4”
It can be written mathematically:
Let's suppose the number is '18' (ends with 8)
The half of 18 = 9 (doesn't end with 4)
Let's suppose the number is '38' (ends with 8)
The half of 38 = 19 (doesn't end with 4)
Thus, Bernard is wrong because When you halve a whole number that ends in 8, you always cannot get a number that ends in 4”
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Please help me. I suck at math
Answer:
Answer is ...Obtuse
Step-by-step explanation:
\( \frac{m<ABC}{2} = m< CBD\)
\( \frac{5x + 4}{2} = \frac{3}{2} x + 21\)
\( \frac{5x + 4}{2} = \frac{3x + 42}{2} \)
\(5x + 4 = 3x + 42\)
\(5x - 3x = 42 - 4\)
\(2x = 38\)
\(x = 19\)
\(substituting \: x = 19 \: \:in \: \: \: \: \: \: \: \\ m<ABC =\: \: 5x + 4, \)
We get,
m<ABC =
\((5 \times 19) + 4 = 99\)
Hence <ABC is obtuse
A truck can be rented from Company A for $80 a day plus $0.40 per mile. Company B charges $20 a day plus $0.70 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.
Answer:
Answer:
800 miles
Step-by-step explanation:
Let the amount of miles = m
Company A charges a flat rate of $160 a day, and $0.60 per mile:
total = 0.60m + 160
Company B charges a flat rate of $80 a day, and $0.70 per mil:
total = 0.70m + 80
Step-by-step explanation: Rank me brain list or thanks it :) Hope it helps!
-3(6v-3w-5)
i have to use the distributive property to remove the parentheses
Answer:
-18v + 9w +15
Step-by-step explanation:
-3(6v-3w-5)
You can use a table or multiply each term
-3(6v) + -3(-3w) + -3(-5)
= -18v + (9w) + (15)
= -18v + 9w + 15
The figure below shows two parallel lines intersected by a third line. What is the value of x?
Answer:
X=13
Step-by-step explanation:
can someone explain this please?
Answer:
Hey there!
Our equation can be: 2y+3=4y+2
Hope this helps :)
Answer:
2y+3=4y+2
I hope you got it..
Suppose there are two samples from populations A and B. The sample from population A is of size 18 and the sample from population B is of size 21. The sample from population A has a sample variance of 8490 and the sample from population B has a sample variance of 6330. Find the pooled sample variance.
Round your answer to 2 decimal places.
The pooled sample variance, rounded to 2 decimal places, is 7,316.22.
To find the pooled sample variance of the two samples from populations A and B, follow these steps,
1. Calculate the weighted variance for each sample:
- For sample A: (Sample size A - 1) * Sample variance A = (18 - 1) * 8490 = 17 * 8490 = 144,330
- For sample B: (Sample size B - 1) * Sample variance B = (21 - 1) * 6330 = 20 * 6330 = 126,600
2. Calculate the total degrees of freedom:
- Total degrees of freedom = (Sample size A - 1) + (Sample size B - 1) = 17 + 20 = 37
3. Calculate the pooled sample variance:
- Pooled sample variance = (Weighted variance A + Weighted variance B) / Total degrees of freedom = (144,330 + 126,600) / 37 ≈ 7,316.22
The pooled sample variance, rounded to 2 decimal places, is 7,316.22.
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A 5-pound sack of potatoes is supposed to weigh 5
pounds. However, actual weights of the sacks vary
somewhat. An inspector selects a random sample of 50
sacks of potatoes from the large packaging plant and
weighs them
The inspector will calculate the sample mean and use
that to determine if there is convincing evidence that the
true mean weight of all sacks of potatoes differs from 5
pounds.
Answer:
t test for one mean.
met
met
met
Step-by-step explanation:
The data below are manufacturing defects per 100 cars for the 30 brands of cars sold in a particular country. Many of these values are larger than 100 because one car might have many defects. 105 | 142 | 206 | 150 | 103 | 143 140 | 153 144 137 160 166 | 177 163 | 114 | 133 | 128 | 161 | 216 171 212 | 181 173 134 | 121 | 175 179 174 189 169 n USE SALT Use these data to construct a boxplot. 230 2200 210 200 190 180 170 160 150 140 130 120 110 1000 2300 2200 220 140 130 120 110 100 0 220 220 230 220 210 21 210 200 2000 2000 19001 1900 1900 180 1801 180 1700 170 170 160 160 160 1500 1500 150 140 140 140 1300 130 120 120 130 120 110 1000 1900 110 110 100 1000 3) LG) Write a few sentences describing the important characteristics of the boxplot. defects per 100 cars, the median is The distribution is ---Select--- with ---Select--- . The minimum value is defects per 100 cars, the lower quartile is defects per 100 cars, the upper quartile is defects per 100 cars, and the maximum value is defects per 100 cars.
Minimum value is 103, lower quartile (Q1): median of first 15 values s 137, median (Q2): median of all 30 values is 153.5, upper quartile (Q3): median of last 15 values is 174 and maximum value is 216
To construct a boxplot from the given data, follow these steps:
1. Arrange the data in ascending order.
2. Find the minimum value, lower quartile (Q1), median (Q2), upper quartile (Q3), and maximum value.
Arranged data:
103, 105, 114, 121, 128, 133, 134, 137, 140, 142, 143, 144, 150, 153, 160, 161, 163, 166, 169, 171, 173, 174, 175, 177, 179, 181, 189, 206, 212, 216
Minimum value: 103
Lower quartile (Q1): Median of first 15 values = 137
Median (Q2): Median of all 30 values = 153.5
Upper quartile (Q3): Median of last 15 values = 174
Maximum value: 216
Based on the calculated values, the important characteristics of the boxplot are as follows:
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Tell whether the angles are complementary or supplementary. Then find the value of x.
a circular wire loop of radius 5 cm and 12 turns has a steady current of 3 amps going through it. the loops lies in the horizontal plane.
The magnetic field at the center of the circular wire loop is approximately 2π × 10⁻⁵ Tesla.
The formula for the magnetic field at the center of a circular wire loop is given by:
B = (μ₀ × I × N) / (2 × R)
Where:
B is the magnetic field at the center of the loop,
μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A),
I is the current passing through the loop,
N is the number of turns in the loop, and
R is the radius of the loop.
Given:
Radius of the circular wire loop, R = 5 cm = 0.05 m
Number of turns, N = 12
Current, I = 3 A
Substituting these values into the formula, we have:
B = (4π × 10⁻⁷ T·m/A) × (3 A) × (12) / (2 × 0.05 m)
Simplifying further:
B = (2π × 10⁻⁶)× (36) / (0.1)
B=2π × 10⁻⁵ T
Therefore, the magnetic field at the center of the circular wire loop is 2π × 10⁻⁵ Tesla.
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Which statement correctly compares the function shown on this graph with
the function y = 2x - 5?
A. The function shown on the graph has a smaller rate of change and lower starting point.
B. The function shown on the graph has a smaller rate of change, but a higher starting point.
C. The function shown on the graph has a greater rate of change and a higher starting point.
D. The function shown on the graph has a greater rate of change, but a lower starting point.
The correct option is Option C: The function shown on the graph has a greater rate of change and a higher starting point.
What is the rate of change of function?The rate of change of function is the change in the value of the function with respect to x value.
rate of change of function f(x)= df(x)/dx= f'(x)
Here the function given in the question is y=2x-5
rate of change of function= f'(x)= df(x)/dx= dy/dx= d(2x-5)/dx= 2
the starting point of the function f is y-intercept of the function.
the y-intercept of the function is the point where the function touches the y-axis which can be calculated by putting x value is equals to 0.
y= 2x-5
⇒y= 2*0-5
⇒y= -5
The starting point of function is -5.
Given the graph has slope = |y-intercept| / |x intercept|
= 4/1 =4
rate of change of graph = slope of graph= 4
similarly, the y-intercept of the function is the point where the function touches the y-axis which can be calculated by putting x value is equals to 0.
The y-intercept of the graph= the starting point of the graph= -5
Therefore the function in the graph has a higher rate of change as well as a higher starting point.
From the above, it is clear that the correct option is Option C: The function shown on the graph has a greater rate of change and a higher starting point.
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The entry for a science exhibition is $5 for students and four dollars more than the students for adults. On a particular day, 600 people visited the exhibition and $3500 was collected. How many students and adults visited on that day?
Answer:
475 students, 125 adults
Step-by-step explanation:
x + y= 600......equation 1
5x +9y= 3500.......equation 2
From equation 1
x +y = 600
x= 600-y
Substitute 600-y for x in equation 2
5(600-y) +9y= 3500
3000-5y+9y= 3500
3000+4y= 3500
4y= 3500-3000
4y= 500
y= 500/4
y= 125
Substitute 125 for y in equation 1
x + y= 600
x + 125= 600
x = 600-125
x= 475
Hence there are 475 students and 125 adults
A group of students is arranging squares into layers to create a project. The first layer has 5 squares. The second layer has 10 squares. Which formula represents an arithmetic explicit formula to determine the number of squares in each layer ?
Answer: Its B i just took the test
Step-by-step explanation:
what is the cost of 1.2kg cheese if 200g is $9.75
Answer:
$58.50
Step-by-step explanation:
1.2 kg = 1200g
To get from 200 to 1200, we time 6, so we take $9.75 times 6 to get the price.
$9.75 times 6 = $58.50
So, the cost of 1.2kg cheese is $58.50
The answer is $58.50
I have attached the explanation! :)
Which of the following are mutually exclusive events of an experiment in which two coins are tossed?
{TT, HH} and {TT}
{HT, TH} and {TH}
{TT, HT} and {HT}
{TT, HH} and {TH}
Answer:
{TT, HH} and {TH}
Step-by-step explanation:
Mutually exclusive just means the three pairs of letters are all different and does not repeat. Only the last choice has three unique pairs of letters: TailTail, HeadHead, and TailHead.
3. A leaking tap drips water at 0,5 ml/sec. Convert this rate to l/h.
Answer: 1.8 L/h
Step-by-step explanation:
To convert the rate of water dripping from a tap from millilitres per second (ml/sec) to litres per hour (L/h), we need to use conversion factors.
Step 1:
First, let's convert the rate from millilitres per second to litres per second.
There are 1000 millilitres in a litre, so we can divide the rate in millilitres per second by 1000 to get the rate in litres per second:
\(\LARGE \boxed{\textsf{0.5 ml/sec $\div$ 1000 = 0.0005 L/sec}}\)
Step 2:
We can convert the rate from litres per second to litres per hour. There are 3600 seconds in an hour, so we can multiply the rate in litres per second by 3600 to get the rate in litres per hour:
\(\LARGE \boxed{\textsf{0.0005 L/sec $\times$ 3600 = 1.8 L/h}}\)
Therefore, the rate of water dripping from the tap is 1.8 L/h.
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Anna invests $875 into an account and receives 4% simple interest for 24 months. How much simple interest will she earn??
Answer:
$70
Step-by-step explanation:
1. I = PRT
2. Sub in what you know into the equation:
I = $875 (principal amount) x 0.04 (4%) x 2 (24 months = 2 years)
3. 875 x 0.04 x 2 = 70
4. Anna will receive $70 in simple interest
Answer:
£70
Step-by-step explanation:
simple interest (I) is calculated as
I = \(\frac{PRT}{100}\)
where P is principal, R is rate of interest and T is time in years.
Note that 24 months = 2 years, thus
I = \(\frac{875(4)(2)}{100}\) = \(\frac{7000}{100}\) = £70
2/8+3/7+4/9=whats the sum of this
Answer:
= 1 32/252
Step-by-step explanation:
You are developing a simulation moel of a service system and are trying to create an input model of the customer arrival process. You have the following four observations of the process of interest: [86,24,9,50] an dyou are considering either an exponential distribution or a uniform distribution for the model. Using the data to estimate any necessary distribution parameters, develop Q-Q plots for both cases. Note that your graph doesn't have to be perfectly to scale, but it does have to be readable and you need to specifically compute the graph values.
I understand how to find the Quantiles by using (i-0.5)/n but how do I find the exponential Quartiles and Uniform Quartiles. From that data how do I estimate the parameters?
To estimate the parameters for the exponential and uniform distributions based on the given data, you can use the method of moments or maximum likelihood estimation.
To estimate the parameter for the exponential distribution, you can use the fact that the mean of an exponential distribution is equal to the reciprocal of the rate parameter (λ). In this case, you can calculate the sample mean of the data (86 + 24 + 9 + 50) / 4 = 42.25. Since the mean of the exponential distribution is equal to 1/λ, you can estimate the rate parameter as λ = 1 / 42.25.
For the uniform distribution, you need to estimate the minimum (a) and maximum (b) values. The minimum value can be estimated as the minimum observation in the data, which is 9. The maximum value can be estimated as the maximum observation, which is 86.
Once you have estimated the parameters, you can construct Q-Q plots. In a Q-Q plot, you plot the quantiles of the observed data against the quantiles of the theoretical distribution. For the exponential distribution, you can use the quantile function to calculate the expected quantiles. For the uniform distribution, you can calculate the quantiles using the formula (i-0.5)/n, where i ranges from 1 to n and n is the number of observations.
By comparing the observed quantiles with the expected quantiles on the Q-Q plot, you can visually assess the fit of the data to the chosen distributions.
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pls help everyone this is due tomorrow at 8 am <3
Answer:
e=19.6h
Step-by-step explanation:
If in 21 hours, she earns 411.60 dollars, then we need to find how much she makes in ONE hour.
21 h 1 hour
--------- = ------------------
411.60 dollars xdollars
To get from 21 to 1, I would have to divide by 21, right? So, do the same for the denominators.
411.60 / 21= $19.6
Now, since we know the unit rate, we can make an equation!
e=19.6h
Math question help please
Step-by-step explanation:
I will help you 180 g flour
the value of “y” varies directly with “x”. if y= 56, then x= 4
A pair of angles whose sum is 90 degrees.
Answer: Complementary angles are pair angles with the sum of 90 degrees
Step-by-step explanation: When talking about complimentary angles, always remember that the angles appear in pairs. One angle is the complement of the other angle.
Hope this helps :)
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Each floor of a doll house is 12.5 inches tall. If the height of the doll house is 75 inches, how many floors does the doll house have? You must show your work help please
\(\bigstar\boxed{\large\bf{\leadsto 6\:floors}}\)
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀
\(\begin{gathered}\rm{ \underline{ \underline{ \red{Given}}}}\begin{cases}\sf{height\:of\:one\:floor\:of\:dollhouse =12.4\:in} & \\ \\\sf{Height\:of\: dollhouse=75\:in}&\end{cases}\\\\\end{gathered} \)
To find :Total number of Floors in dool house➜ Therefore , Total number of floors can be find out by dividing the total height of dollhouse by the length of one floor
\(\bf{=\cancel{ \dfrac{75}{12.5}}}\)
\(\bf{= 6}\)
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀
Choose the function whose graph is given by:
y
+
2
NE
فما
2
3
6X
-2
O A. y = cos x-1
B. y=cOS X-2
O C. y= sin x + 1
HELP PLS !!!!
Answer:
The answer is D
Step-by-step explanation:
We should note that the function y = sin x = b/r has a maximum value of 1 at x = π/2, since at that point b is equal to r
Option B is correct, y= cosx - 2 is the function whose graph is given in attachment.
What is Trigonometry?Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.
A function is a process or a relation that associates each element x of a set X, the domain of the function, to a single element y of another set Y (possibly the same set), the codomain of the function.
The graph of equation y= cos x - 2 is showing in the picture.
The equation y= cosx - 2 is showing the given graph.
Hence, Option B is correct, y= cosx - 2 is the function whose graph is given in attachment.
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alexio has $100$ cards numbered $1$-$100$, inclusive, and places them in a box. alexio then chooses a card from the box at random. what is the probability that the number on the card he chooses is a multiple of $2$, $3$ or $5$? express your answer as a common fraction.
Answer:
37/50
Step-by-step explanation:
You want the fraction of integers in the range [1, 100] that are divisible by 2, 3, or 5.
DivisibilityAttached is a Venn diagram showing how the divisibility of numbers from 1 to 100 stacks up. Circle A includes all 50 numbers divisible by 2; Circle B counts all 33 numbers divisible by 3; and Circle C counts the 20 numbers divisible by 5.
Where the circles overlap, there are counts of the numbers divisible by the relevant combination of factors. For example, there are 3 numbers divisible by 2, 3, and 5. (They are 30, 60, 90.)
ProbabilityIn all, there are 74 numbers in the range 1–100 that are divisible by 2, 3, or 5.
The probability that a card chosen at random will have a number divisible by 2, 3, or 5 is 74/100 = 37/50.
P( 2, 3, or 5 divides N) = 37/50.
__
Additional comment
Roughly, the number of numbers in range [A, B] divisible by n is (B -A)/n. This is how we arrived at the counts shown in the attachment. For example, There are 100/(2·5) = 10 numbers divisible by both 2 and 5. Of those, there are 10/3 = 3 divisible also by 3. So, the number 3 is found in the area ABC, and the number 10-3=7 is found in the area AB'C.
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