PLEASE HELP ME ANYONEEE I ONLY HAVE AN HOUR LEFT IM SO DESPERATE PLS OMGGGG!!!!

Answer:

3 times

Step-by-step explanation:

The bag is three pounds

The bowl hold 1 pound and her rabbit rats 1 pound

Therefore you can fill it 3 times per bag :))

(3/1=3)

Answer:

Asia can fill the bowl 3 times and it would feed her rabbit 3 days.

The initial height of the rocket is 24 metres, the rocket hit the ground in 0.88 seconds and the height of the rocket after 4 seconds is 24 metres.

A quadratic equation is a second-order polynomial equation in a single variable x , ax²+bx+c=0. with a ≠ 0 .

The initial height of the rocket is given by the value of h when t = 0:

h(t)=-4t² + 16t + 24

h(0)=-4(0)² + 16(0) + 24

h(0)=24

So the initial height of the rocket is 24 metres.

The rocket will hit the ground when its height is 0 metres, so we can set h = 0 in the equation and solve for t:

0 = -4t²+ 16t + 24

-4t² + 16t + 24 = 0

t=-0.88 seconds

So the rocket will hit the ground after approximately 0.88 seconds.

The height of the rocket after 4 seconds is given by:

h(4)== -4(4)²+ 16(4) + 24

=-64+64+24

=24

So the height of the rocket after 4 seconds is 24 metres.

Hence, the initial height of the rocket is 24 metres, the rocket hit the ground in 0.88 seconds and the height of the rocket after 4 seconds is 24 metres.

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Answer:

Distance between points = 8.6

Step-by-step explanation:

Formula :

Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2

Solution :

Distance between two points = √(−2−−9)2+(−6−−1)2(-2--9)2+(-6--1)2

= √72+(−5)272+(-5)2

= √49+2549+25

= √7474 = 8.6023

Distance between points (-9, -1) and (-2, -6) is 8.6023

Answer:

0.857

Step-by-step explanation:

                   ----------------

               7  |   6

7 goes 0 times into 6, so we write a 0.

                       0.

                   ----------------

               7  |   6.0

Add .0 to 6 to get 6.0

7 goes 8 times into 60.

8 × 7 = 56

                       0.8

                   ----------------

               7  |   6.0

                  -    5.6

                ------------

60 - 56 = 4

Write another 0, 6.00, and bring down a zero.

                       0.8

                   ----------------

               7  |   6.00

                  -    5.6

                ------------

                           40

7 goes 5 times into 40.

                      0.85

                   ----------------

               7  |   6.00

                  -    5.6

                ------------

                           40

                      -    35

                      ---------

40 - 35 = 5

Add another 0 to 6.00 to get 6.000; bring down that zero.

Now you have 50.

                      0.857

                   ----------------

               7  |   6.000

                  -    5.6

                ------------

                           40

                      -    35

                      ---------

                              50

7 goes 7 times into 50.

7 × 7 = 49

Add a zero, bring down a zero,

                      0.857

                   ----------------

               7  |   6.0000

                  -    5.6

                ------------

                           40

                      -    35

                      ---------

                              50

                          -   49

                         -----------

                                  10

7 goes 1 time into 10.

You end up with 0.8571

                     0.8571

                   ----------------

               7  |   6.0000

                  -    5.6

                ------------

                           40

                      -    35

                      ---------

                              50

                          -   49

                         -----------

                                  10

                              -     7

                          -----------

                                    3

0.8571 rounds to 0.857

Answer:

3/10

Step-by-step explanation:

4+6+10

=20

6/20

=3/10

The percent of the front page taken up by the prom story is 20%

From the question, we have the following parameters that can be used in our computation:

The front page

From the front page, we have

Area front page = 5 * 4

Area front page = 20

Also, we have

Prom = 2 * 2

Prom = 4

So, we have

Percentage = 4/20 * 100%

Evaluate

Percentage = 20%

Hence, the percent of the front page taken up by the prom story is 20%

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Answer:

  (c)

Step-by-step explanation:

You want the graph that has a domain of x ≥ 5.

The domain of a function is the set of x-values for which the function is defined. A domain of x ≥ 5 means the function is defined for x-values at least 5. The graph of the function will extend from x=5 indefinitely to the right.

Graph C is like that.

Answer:

3.6

Step-by-step explanation:

18/5 =3.6

5/5 = 1

18 - 15 =3. 15/5= 3

the remaining

3/5 = 0.6

3+0.6=3.6

The area of the triangle with angle B = 128°, side a = 86, and side c = 37 is approximately 2302.7 square units.

To find the area of a triangle when one angle and two sides are given, we can use the formula for the area of a triangle:

Area = (1/2) * a * b * sin(C),

where a and b are the lengths of the two sides adjacent to the given angle C.

In this case, we have angle B = 128°, side a = 86, and side c = 37. To find side b, we can use the law of cosines:

c² = a² + b² - 2ab * cos(C),

where C is the angle opposite side c. Rearranging the formula, we have:

b² = a² + c² - 2ac * cos(C),

b² = 86² + 37² - 2 * 86 * 37 * cos(128°).

By substituting the given values and calculating, we find b ≈ 63.8.

Now, we can calculate the area using the formula:

Area = (1/2) * a * b * sin(C),

Area = (1/2) * 86 * 63.8 * sin(128°).

By substituting the values and calculating, we find the area of the triangle to be approximately 2302.7 square units.

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The angles will be x = 8° and y = 21°

given information:

∠AOB = 180°

∠EOG = 90°

∠EOF and ∠FOG are complementary angles. Complementary angles are those whose sum is equal to 90° and it is given to us in the question.

∠EOG = ∠EOF + ∠FOG

90° = 27° + 3y

90 - 27 = 3y

63 / 3 = y

y = 21°

Similarly  ∠AOE , ∠AOG and ∠GOB are supplementary to each other. Supplementary angles are those whose sum is equal to 180°

∠AOB = ∠AOE + ∠AOG + ∠GOB

180° = x + 90° + 8x + 18°

180 - 90 - 18 = 9x

9x = 72

x = 72 / 9

x = 8°

Hence we can clearly say that x = 8° and y = 21°

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Answer:

2

Step-by-step explanation:

Convert them to mixed fractions and then find the lcd.

Hope this helps.

The responses to the linear optimization questions are;

Question 1

The optimal daily profit is $380

Question 2

The combination of x and y that yield the optimal value is the option;

x = 0, y = 3

Linear programming is a method by which the optimal solution can be obtained from a model represented mathematically and in which the constraints of the model have linear relationships.

Question 1

Let B represent the number of bear claws, C the almond-filled croissant, F represent the flour, Y represent the amount of yeast and A represent the number of almonds.

The amount of ingredient per each produce is therefore;

B = 6·F + 1·Y + 2·A

C = 3·F + 1·Y + 4A

The amount of ingredient available for the days production is as follows;

Ingredient available; 6600·F + 1400·Y + 4800·A

The constraints are therefore

6·B + 3·C ≤ 6,600

B + C ≤ 1,400

2·B + 4·C ≤ 4800

The maximizing function is therefore;

Profit = 0.2·B + 0.3·F

The equations of the lines are therefore;

B = 1,100 - 0.5·C

B = 1400 - C

B = 2400 - 2·C

The vertices of the feasible region are;

(0, 1100), (600, 800), (1000, 400), 1200, 0)

The values of the maximizing function at the vertices of the feasible region are;

Profit, P = 0.2×1100 + 3×0 = 220

At point (600, 800), P = 0.2×800 + 0.3×600 = 340

At point (1000, 400), P = 0.2×400 + 0.3×1000 = 380

At point (1200, 0), P = 0.2×0 + 0.3×1200 = 360

Question 2

Maximize $3·x + $15·y

Subject to the following constraints;

2·x + 4·y ≤ 12

5·x + 2·y ≤ 10

x, y ≥ 10

The equations are therefore;

4·y ≤ 12 - 2·x

y ≤ 3 - 0.5·x...(1)

5·x + 2·y ≤ 10

2·y ≤ 10 - 5·x

y ≤ 5 - 2.5·x...(2)

x ≥ 10, y ≥ 10

The coordinates of the vertices of the feasible region are;

(0, 3), (1, 2.5), and (2, 0)

The values of the maximizing function are therefore;

At (0, 3), M = $3 × 0 + $15 × 3 = $45

At (1, 2.5), M = $3 × 1 + $15 × 2.5 = $40.5

At (2, 0), M = $3 × 2 + $15 × 0 = $6

The combination of x and y that yield the optimum is therefore;

(x, y) = (0, 3)

x = 0, and y = 3

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Answer:

$12.60

Step-by-step explanation:

12x.05 = .6 then .6+12 is 12.6

sorry if this is wrong lol

Answer:

\(12(1 + x)\)

Step-by-step explanation:

We will use order of operations to simplify this expression.

We will evaluate the brackets first.

3(5+7)-6(4-2x) =

\(3(12) - 6(4 - 2x) \\ = 36 - 6(4 - 2x) \\ = 36 - 24 + 12x \\ = 12 + 12x\)

You can further simplify it by factorising it:

\(12 + 12x \\ = 12(1 + x)\)

\(\huge\text{Hey there!}\)

\(\mathsf{3(5 + 7) - 6(4 - 2x)}\)

\(\mathsf{= 3(5) + 3(7) - 6(4) - 6(-2x)}\)

\(\mathsf{= 15 + 21 - 24 + 12x}\)

\(\mathsf{= 36 - 24 + 12x}\)

\(\mathsf{= 12 + 12x}\)
\(\mathsf{= 12x + 12}\)

\(\huge\text{Therefore, your answer should be:\boxed{\mathsf{12x + 12}}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

The frequency count that should be recorded for the soup category is 6.

Subtraction is the process of taking one number away from another number. The sign used to represent subtraction is -.

The frequency count on the table should be equal to the number of students. Thus, in order to determine the frequency count for the soup category, subtract 22 from the total frequency count.

The frequency count for the soup category = 22 - (5 + 8 + 2 + 1 ) = 6

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Tom sold 27 raffle tickets and Steve sold 98 raffle tickets.

Two algebraic expressions having the same value and symbol '=' in between are called an equation.

Given:

Together, Steve and Tom sold 125 raffle tickets for their school.

Steve sold 17 more than three times as many raffle tickets as Tom.

Let s be the number of raffle tickets sold by Steve and t be the raffle tickets sold by Tom.

So,

3t + 17 + t = 125

4t = 108

t = 27

And s = 98

Therefore, Steve sold 98 and Tom sold 27 tickets.

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Answer:

It will take her 318 minutes.

Step-by-step explanation:

26.5 times 12 equals 318

Answer:

The domain is all real numbers

The range is  \(y \leq 3\)

Step-by-step explanation:

The domain is the values that the input can take.

X can be from - infinity to infinity

The domain is all real numbers

The range is the values that the output can take

Y can be from - infinity to 3

The range is  \(y \leq 3\)

Answer:

thats the diagram of landlines stocks in a nutshell

Step-by-step explanation:

hahaha

The equivalent equation to the given one is:

h = A*t/(b - c)

We want to find an equation equivalent to the one below:

A = h*(b - c)/t

If we solve the equation for t, we would get:

t  = h*(b - c)/A

If we solve the equation for h, we will get:

h = A*t/(b - c)

If we solve the equation for b, we will get:

A = h*(b - c)/t

A*t/h = b - c

A*t/h + c = b

And if we solve it for c, we will get:

c = b - A*t/h

Then the correct option is the last one;

h = A*t/(b - c)

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The parameters that are needed to calculate a probability are listed as follows:

Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.

The total number of periods is given as follows:

5 + 6 + 4 = 15.

The frequency of each class is given as follows:

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Answer:

1:72

Step-by-step explanation:

The scale of a drawing is the ratio of the length in the drawing to the real length.

Drawing length: 7 inches

Real length: 42 ft × 12 in. / ft = 504 in.

Scale:

7 in. to 504 in.

Divide both numbers by 7:

1 in. to 72 in.

Scale: 1:72

The value of the number is x = 34.

Let's break down the problem and solve it step by step.

1. "Five less than twice the value of a number": This can be represented as 2x - 5, where x is the number.

2. "Three times the quantity of 4 more than 1/2 the number": This can be represented as 3 * (x/2 + 4).

According to the problem statement, the two expressions are equal. We can set up the equation as follows:

2x - 5 = 3 * (x/2 + 4)

Now, let's solve the equation:

2x - 5 = 3 * (x/2 + 4)

Distribute the 3 to both terms inside the parentheses:

2x - 5 = (3/2)x + 12

Multiply through by 2 to eliminate the fraction:

2(2x - 5) = 2((3/2)x + 12)

4x - 10 = 3x + 24

Next, let's isolate the x term by moving the constant terms to the other side of the equation:

4x - 3x = 24 + 10

Simplify:

x = 34

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The 4 on the right is 10 times larger than the 4 on the left! (=^.^=)

Answer:

Given:

Area of the sector (A) = 104π/9 square inches

Central angle (θ) = 65 degrees

The formula for the area of a sector of a circle is:

A = (θ/360) * π * r^2

We can rearrange this formula to solve for the radius (r):

r^2 = (A * 360) / (θ * π)

Plugging in the given values:

r^2 = (104π/9 * 360) / (65 * π)

r^2 = (104 * 40) / 9

r^2 = 4160 / 9

r^2 ≈ 462.22

Taking the square root of both sides:

r ≈ √462.22

r ≈ 21.49

Therefore, the radius of the circle is approximately 21.49 inches.

Answer: 8 inches

Step-by-step explanation:

a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.

In base seven, we have the following conversions:

1 long = 1 unit

1 flat = 10 units

1 block = 10 flats

To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.

So, the fewest number of multibase blocks required would be 2 flats.

Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.

In base three, we have the following conversions:

1 long = 1 unit

1 flat = 3 units

1 block = 3 flats

To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.

So, the fewest number of multibase blocks required would be 3 flats and 1 unit.

Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

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The equation of a line is not unique to its graph; this means that multiple lines can have the same slope and y-intercept. Therefore, this equation is a possible match, making option D the correct answer.

The equation of the graph shown below could be `y = 3x - 2`.

We are given an equation of the line that can fit the graph shown.

To determine which equation it is, we can compare the graph to each of the answer choices:

A. y = -10:

This is the equation of a horizontal line that is 10 units below the x-axis.

It is not the equation of the graph shown.B. 2x - 3y = -9:

To convert this equation to slope-intercept form, we need to solve for y:

2x - 3y = -93y = 2x + 9y

= (2/3)x + 3

This is the equation of a line with a slope of 2/3, meaning it has a positive slope.

The graph shown has a negative slope, so this equation is not a match.C.

-4x + 2y = -6:

To convert this equation to slope-intercept form, we need to solve for y:

-4x + 2y = -62y

= 4x - 6y

= 2x - 3

This is the equation of a line with a slope of 2, meaning it is steeper than the graph shown.

This equation is not a match.D. y = 3x - 2:

This equation is already in slope-intercept form, meaning it has a slope of 3 and a y-intercept of -2.

The graph shown has a slope of -3 and a y-intercept of -2.

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Answer:

The equation of the line is;

Explanation:

Given that the line is perpendicular to the equation;

So, the slope of the line will be the negative inverse of the slope of the equation above;

Also, the line passes through the point;

Applying the point-slope form of linear equation;

Substituting the values of the slope and coordinates;

Therefore, the equation of the line is;

Answer:

X = -2 - 2(square root)3 or x = -2 + 2 (square root )3

Step-by-step explanation: