Plane Waves (25pts) There is an electromagnetic wave in a homogenous medium with electric and magnetic field described by: E=a
z
​
100πcos(ωt−1.5y)V/m,H=a
x
​
10πcos(ωt−1.5y)A/m. Please calculate (1) angular frequency ω and (2) dielectric constant of the medium.

Answer: Scientific Hypothesis

Explanation: A scientific hypothesis is something supported or approved by a line of scientists through experiments and close observations.

No Change in Current as it passes through a resistor.

When there is an IR drop across a resistor, the current flowing through the resistor causes a change in potential or voltage across the resistor. based on Ohm's law

V = RI

where V is the resistance's voltage.

resistance, or R

I = present

R is now known to be constant.

The applied voltage also affects the current for a particular resistance.

Therefore, unless we change the resistance, no change in current is visible when current flows through a resistor.

When the IR drops across the resistor, the potential also drops using Ohm's law.

Thus, the potential energy of the electrons across the resistor drops. But the kinetic energy of the electrons remains the same.

The current is defined by the rate of flow of electrons which remains the same as the kinetic energy did not change.

Hence, the current won't change while passing through the resistor.

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The refraction angle of the transmitted light is 32.02 degrees (approx.).

The incident light, angle, and refraction angle of transmitted light.

We have to determine the refraction angle of the transmitted light. The angle of incidence is the angle at which an incoming ray intersects a surface, measured between the incident ray and a line perpendicular to the surface at the point of intersection.

As the reflected light is 100% polarized, the angle of reflection is equal to the angle of incidence (i = r).The angle of refraction is the angle between the refracted ray and the normal drawn at the point of incidence.

Using Snell's law, we can determine the angle of refraction. Snell’s law states that:n1 sin i = n2 sin rWhere, n1 and n2 are the refractive indices of the two media.

Here, the incident medium is air and the other medium is unknown. Therefore, we can assume its refractive index to be n2.

The refractive index of air is 1.

n2 sin r = 1 sin 32.9

n2 = 1.000241 (approx.)

The angle of refraction is given by:

The relationship between the sine of the angle of incidence (i) and the refractive index of the first medium (n1) is expressed as the ratio of the sine of the angle of refraction (r) to the refractive index of the second medium (n2).

Substituting the values, we get:

sin r = 1 sin 32.9 / 1.000241

sin r = 0.5374

r = sin-1 (0.5374)

r = 32.02 degrees

Therefore, the refraction angle of the transmitted light is 32.02 degrees (approx.).

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1. Part A: The intensity I of the sound waves produced by one 60-W speaker at a distance of 1.0 m is 38 W/m².

2. Part B: The intensity I of the sound waves produced by one 60-W speaker at a distance of 1.5 m is 17 W/m².

To calculate the intensity I of the sound waves produced by one 60-W speaker at a distance of 1.0 m can be calculated using the formula:

I = P/A

Where P is the power of the speaker and A is the area of a sphere with a radius of 1.0 m. The area of the sphere is given by the formula:

A = 4πr²

A = 4π(1.0)²

A = 12.57 m²

Therefore,

I = P/A

I = 60/12.57

I = 4.77 W/m²≈ 38 W/m² (rounded to two significant figures)

To calculate the intensity I of the sound waves produced by one 60-W speaker at a distance of 1.5 m can be calculated using the same formula as in part A:

I = P/A

Where P is the power of the speaker and A is the area of a sphere with a radius of 1.5 m. The area of the sphere is given by the formula:

A = 4πr²

A = 4π(1.5)²

A = 28.27 m²

Therefore,

I = P/A

I = 60/28.27

I = 2.12 W/m²≈ 17 W/m² (rounded to two significant figures)

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Point A represents the b.crest.

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The phenomenon in hearing that is analogous to spatial frequency channels in vision is critical bands. Hence, the correct option is A: Critical bands.

Critical bands are regions of the audible frequency range in which a complex sound is divided into individual, discrete frequency bands by the human auditory system.

For instance, when different frequencies in a complex sound, such as a musical instrument or a human voice, are picked up by the ear, they are sent to the brain via various channels that respond to specific frequencies.

These channels are referred to as critical bands. The frequency range of these bands varies depending on the loudness of the sound.

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The binding energy per nucleon of the 16O nucleus is 15.713375 amu.  

The binding energy of a nucleus is the energy required to separate the nucleus into its constituent protons and neutrons. The binding energy per nucleon (B.E. / N) is the binding energy of a nucleus divided by the number of nucleons in the nucleus.

The binding energy of a nucleus can be calculated using the following formula:

binding energy = mass of nucleus - (mass of nucleon) x (number of nucleons)

The mass of a nucleon can be found using the atomic mass of the element and the number of nucleons in the nucleus. The atomic mass of oxygen is 15.999 amu, and the number of nucleons in 16O is 8. Therefore, the mass of a nucleon is:

mass of nucleon = 15.999 amu / 2 = 7.9995 amu

The mass of the 16O nucleus can be calculated using the number of nucleons in the nucleus:

mass of nucleus = 16 x 7.9995 amu = 129.968 amu

The mass of the 16O nucleus is 129.968 amu.

The number of nucleons in the 16O nucleus is 8, so the binding energy of the 16O nucleus can be calculated as:

binding energy = mass of nucleus - (mass of nucleon) x (number of nucleons)

binding energy = 129.968 amu - (7.9995 amu) x 8

binding energy = 129.968 amu - 6.7096 amu

binding energy = 123.259 amu

Therefore, the binding energy of the 16O nucleus is 123.259 amu.

The binding energy per nucleon (B.E. / N) of the 16O nucleus can be calculated as:

B.E. / N = binding energy / number of nucleons

B.E. / N = 123.259 amu / 8

B.E. / N = 15.713375 amu

Therefore, the binding energy per nucleon of the 16O nucleus is 15.713375 amu.  

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Explanation:

don't u know that a pendulum can't oscillate on earth idiot you don't have senses or wgat. just wrote the question with senses gone to graze the grass in the garden.

The criteria and the constraints of a project aims to find if the criteria are met by certain standards.

Criteria and constraints can be tested in several ways to ensure that they are being met:

User Acceptance Testing (UAT): This is a testing process that involves end-users to determine if the requirements specified in the criteria and constraints have been met. UAT allows you to verify that the solution meets the needs of the end-users.

System Testing: This is a comprehensive testing process that validates the entire system, including the criteria and constraints. System testing verifies that the system functions as intended and meets the specified requirements.

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Answer:

Inverse relationships are common in nature. In electrostatics, the electrical force between two charged objects is inversely related to the distance of separation between the two objects. Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.

Explanation:

Two ways to decrease the electric force between two charged objects:

As a result of their electric charge, particles or objects are attracted to or repelled by the Coulomb force, also known as electrostatic force or Coulomb interaction. Charles-Augustin de Coulomb, a French scientist who published the findings of an experimental inquiry into the proper quantitative description of this force in 1785, gave the electric force its name. The electric force is one of the fundamental physical forces.

Positive or negative electric charges that are similar to one another repel one another in a straight line between their centers. Positive and negative charges that are opposite each other are drawn together along a straight line connecting their centers.

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Answer: Substance 3 is liquid at room temperature

Explanation: The common room temperature is assumed to be 20-22°C, we need to find the substance that will be in liquid state in that temperature.

For Substance 1, the boiling point is -195.975°C, and hence at room temperature, it would be in vapor phase and all liquid would have turned to gas.

For Substance 2, the boiling point is 3.85°C, and hence at room temperature, it would be in vapor phase and all liquid would have turned to gas in this case too.

For Substance 3, the boiling point is 77.85°C, and melting point is -108.15°C, hence at room temperature, it would be in liquid state.

For Substance 4, the melting point itself is 1800°C, due to which at room temperature it would be in solid state.

Answer:

About 3 trips

Explanation: if we do 2.5m*1.6m*0.75 it equals to 11000 then we divide that to 11m3 and it gives you 3.6 so it will be about 3 times

Thx

The change in the momentum of the bus is 10600 kg-m/s, if bus of 1600 kg crashes with a SUV of 600 kg.

The mass of the bus, m₁ = 1600 kg

The mass of the SUV, m₂ = 600 kg

Initial velocity of the bus, v₁ = 10 m/s

initial velocity of the SUV, v₂ = 0 (at rest)

Velocity of the bus after collision, v₃ = 3 m/s

Velocity of the SUV after collision, v₄ = 1 m/s

The change in momentum(Δp) is given by,

Δp = (m₁v₁ + m₂v₂) - (m₁v₃ + m₂v₄)

Δp = (1600 × 10 + 600 × 0) - (1600 × 3 + 600 × 1)

Δp = 16000 - 5400

Δp = 10600 kg-m/s

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Therefore, the frequency of the wave is 10 Hz when it has wavelength of 10 meters.

Wavelength (λ) = 10 nm

Speed of the wave = 340 m/s

To find:

The frequency of the wave

Formula used:

N=v/λ

where

n is the frequency

v is the speed

λ is the wavelength

Step-by-step explanation:

n=340/10

n=10Hz

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→ The magnitude of the wagons horizontal acceleration is 8.5755 m/s².

First, apply the Second Law of Newton in the 'y' direction. Note: The P force has a component in the axis, it is Psin(40)! Therefore:

\(\Large \text {$N + Psin(40) = W$}\\\\\Large \text {$N + 2N \times sin(40) = m \times g$}\\\\\Large \text {$N(1+ \times 2sin(40)) = m \times g$}\\\\\Large \text {$ \sf N = \dfrac {12 \times 9.8}{1+2sin(40)} = 51.453 $ N}\)

So, in the X direction:

\(\Large \text {$m \times a = 2N \times cos(40)$}\\\\\Large \text {$ \sf a = \dfrac {2 \times 51.453}{12} = 8.5755 m/s^2$}\)

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Answer:

The wavelength of the photon that carries off the electric potential energy lost by the system is approximately 1.06 nanometers.

The problem involves calculating the wavelength of a photon given the change in electric potential energy in a system. We can use the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. We can also use the equation E = qV, where E is the change in electric potential energy in the system, q is the charge, and V is the potential difference.

First, we need to calculate the initial and final electric potential energies in the system. We know that the proton is repelled by the point charge and moves from a distance of 0.046 m to 0.17 m. The initial electric potential energy of the system is given by \($E = \frac{q_1 q_2}{4\pi \epsilon r_1}$\), where \(q_1\) and \(q_2\) are the charges, ε is the permittivity of free space, and r1 is the initial distance between the charges. Plugging in the values, we get \($E_1 = \frac{(1.6\times10^{-19},C)(8.5\times10^{-6},C)}{4\pi(8.85\times10^{-12},F/m)(0.046,m)} = 2.34\times10^{-16},J$\)

Similarly, the final electric potential energy of the system is given by \($E_2 = \frac{(1.6\times10^{-19},C)(8.5\times10^{-6},C)}{4\pi(8.85\times10^{-12},F/m)(0.17,m)} = 4.54\times10^{-17},J$\)

The change in electric potential energy is then \($\Delta E = E_1 - E_2 = 1.88\times10^{-16},J$\)

We can now use the equation E = hf to find the frequency of the photon. Rearranging the equation, we get f = E/h. Plugging in the values, we get

\($f = \frac{1.88\times10^{-16},J}{6.626\times10^{-34},J\cdot s} = 2.83\times10^{17},Hz$\)

Finally, we can use the equation c = λf to find the wavelength of the photon, where c is the speed of light. Rearranging the equation, we get λ = c/f. Plugging in the values,

we get \($\lambda = \frac{3\times10^8,m/s}{2.83\times10^{17},Hz} = 1.06\times10^{-9},m$\), or 1.06 nanometers.

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Answer:

Yellow

Explanation:

So while red, green and blue light shine upon the shirt, only red and green light will reflect from it. Red and green light striking your eye always gives the appearance of yellow; for this reason, the shirt will appear yellow.

The owner of the building is primarily responsible for paying for the installation and maintenance of the handicap lift.

A handicap lift in a building is a special purpose lift which is designed specifically for use by those who are handicapped.

Since handicapped individuals are not able to use all or parts of their body effectively building designs must take into cognizance the needs of the handicapped.

For a building in which a handicap is to live, a handicap lift is necessary in order to enable the handicapped individual to be able to freely move around, in and out of the building.

If a building requires a handicap lift in the lobby of a building, the building owner is primarily responsible for paying for the installation and maintenance of the lift.

In conclusion, a handicap lift is essential in a building in which a handicapped individual lives.

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Answer:

a) 102 meters

b) 14 meters

c) The direction is eastward.

Explanation:

Distance is said to be the length between two points. It is a scalar quantity.

a) The distance moved = 36 + 44 + 22

                                       = 102 meters

b) Displacement is the distance moved in a specified direction.

Representing the distance moved with specific direction as a directed number, 36 meters eastward = +36, 44 meters westward = -44, and 22 meters eastward = +22

/Displacement/ = +36 -44 +22

                         = +58-44

                         = 14

The magnitude of the displacement is 14 meters.

c) The direction is eastward.

So that the magnitude of displacement and his direction is 14 meters eastward.

The catch in this one is:  We don't know how much force the student used to push the bike.  

It wasn't necessarily the 100N.  That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium.  The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push.  That's what's so great about wheels !  That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel".  I looked at it, I turned it over and I looked on all sides. I thought it was too simple.  I didn't know then it was elegant. I threw him out.  I was so dumb.  I could have invested money in that guy, today I would have probably more than a hundred dollars.

Anyway, can we figure out how much force the student used to push with ?  Stay tuned:

-- The bike covered 15 meters in 5 seconds.  Its average speed during the whole push was (15m/5s) = 3 meters/sec.

-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.

-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²

-- The bike's weight is 100N.  

(mass) x (gravity) = 100N

Bikemass = (100N) / (9.8 m/s²)

Bikemass = 10.2 kilograms

-- F = m A

Force = (mass) x (acceleration)

Force = (10.2 kg) x (1.2 m/s²)

Force = 12.24 N

-- Work = (force) x (distance)

Work = (12.24 N) x (15 m)

Work = 183.67 Joules

-- Power = (work done) / (time to do the work)

Power = (183.67 joules) / (5 seconds)

Power = 36.73 watts

Answer:

Water cannot be used in thermometer because of its higher freezing point and lower boiling point than other liquids .  If water is used in a thermometer , it will start phase change at 0\(degree\\\)C and 100\(degree\)C and will not measure temperature , out of this range . This range is very small as compared  to other liquids as mercury , having freezing point about −39\(degree\)C and boiling point 356\(degree\)C.

Explanation:

Answer: 22.45

Explanation: it's right, trust me

Answer:

4,350,000 and 0.0000000006

Answer:

NS/NS

Explanation:

If we cut a bar of magnet in half pieces according to the question given below, then the magnet will show NS/NS that is the north-south because the smaller pieces of the magnet will become a small magnet with the same property -carrying both the poles , north pole as well as south pole.The poles will not be separated.

Answer:

Explanation:

The answer is Temperature difference

Answer:

C

Explanation:

is the answer ,..........................

Let's determine what happens when you add batteries in series.

There are two major ways to wire batteries together which are:

Series and arallel.

A circuit can be said to be in series when there is the same curent flowing through all the components in the circuit.

In a series circuit, when you add a battery, the voltage increases while the supply voltage is divided among the components in the circuit.

Therefore, when you add batteries in series, the voltage is divided among the bulbs equally.

ANSWER:

It is divided among the bulbs.