Answer:
3.68 m/s
Explanation:
Full answer in the attached picture
Which is most likely the reason parents and their children have similar physical traits? Responses They live in the same home. They have similar genetic structures. They are born in similar environments. They have similar blood types.
The most likely reason parents and their children have similar physical traits is that (b) they have similar genetic structures.
Physical traits are largely determined by genes, which are segments of DNA passed down from parents to their offspring. Genetic information contains instructions for the development of various physical characteristics, such as eye color, height, and facial features. Therefore, children inherit genetic variations from their parents that contribute to the similarities in their physical traits.
Genes are responsible for the transmission of hereditary traits, and variations in these genes can result in different physical appearances. Children receive half of their genetic material from their biological mother and the other half from their biological father, leading to a combination of genetic traits from both parents. This genetic inheritance process explains why children often share physical characteristics with their parents, such as hair color or body structure.
While living in the same home and being born in similar environments can influence certain aspects of physical traits, such as lifestyle choices or exposure to certain factors, these factors do not have as direct and significant an impact as genetic inheritance. They may contribute to some environmental influences, but genetic factors are the primary drivers of physical trait similarities between parents and their children.
The similarity in blood types between parents and children is a result of genetic inheritance as well. Blood type is determined by specific genes, and children inherit their blood type alleles from their parents. However, blood type alone does not account for the full range of physical traits shared between parents and children, as it is just one characteristic among many that are determined by genetics.
In summary, while living in the same home and being born in similar environments can have some influence, the primary reason parents and their children have similar physical traits is due to their shared genetic structures. Genetic inheritance is the key factor that determines the passing down of physical characteristics from one generation to the next.
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What is sound waves
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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A light elastic string, of natural length g metres and modulus mg N, has one end attached to a fed point O, and the other end attached to a particle of mass m kg. If the particle hangs in equilibrium vertically below O, what will the extension in the string be? Give your answer in metres to 1 decimal place.
The particle from the previous question is dropped from a point § metres directly below O and enters into simple harmonic motion centred on the equilibrium point once the string is under tension. If the equation of motion when under tension is › = -n?, where x is the displacement from the
equilibrium position, then find the constant n.
In the previous question, how long after it is dropped does the particle enter simple harmonic motion? Give your answer in seconds.
What is the amplitude of the simple harmonic motion in the previous two questions? Give your answer in metres to 2 decimal places.
How long does it take the particle in the previous three questions to come to instanteous rest for the first time? Give your answer in seconds to 2 decimal places.
The extension in the string when the particle hangs in equilibrium is e = mg/k. The constant n in the equation of motion is n = (2π/T)²m. The time it takes for the particle to enter simple harmonic motion is t = √(2§/g).
To find the extension in the string when the particle hangs in equilibrium, we need to consider the forces acting on the particle. The weight of the particle is mg, acting vertically downward. The tension in the string exerts an equal and opposite force, mg, to balance the weight. Since the particle is in equilibrium, the total force acting on it is zero.When the particle is dropped from a point below O, it will stretch the string due to its weight. Let's denote the extension of the string as e. The tension in the string will now be greater than mg because it needs to support the weight of the particle and provide the necessary centripetal force for the simple harmonic motion.The extension in the string is given by Hooke's law: F = kx, where F is the force, k is the modulus of the string, and x is the extension. In this case, the force is the tension in the string, and the extension is e. Thus, we have mg = ke. Rearranging the equation, we get e = mg/k.
To find the constant n in the equation of motion, › = -n?, we can use the fact that the period of simple harmonic motion is given by T = 2π√(m/k), where m is the mass of the particle and k is the spring constant. Comparing this with the equation of motion, we see that ω² = n/m. Since ω = 2π/T, we can substitute ω in terms of T and solve for n: n = (2π/T)²m.
To determine when the particle enters simple harmonic motion, we need to find the time it takes for the string to reach its equilibrium position. Since the particle is dropped from a point § meters below O, it will accelerate towards the equilibrium position due to the tension in the string. The time taken for this free-fall motion can be calculated using the equation of motion for constant acceleration: § = ½gt². Solving for t, we get t = √(2§/g).The amplitude of the simple harmonic motion is equal to the maximum displacement from the equilibrium position. In this case, the maximum displacement is equal to the initial dropped distance, § meters.To determine the time it takes for the particle to come to instantaneous rest for the first time, we need to find the time period of the simple harmonic motion. The time period, T, is given by T = 2π√(m/k). To find the time it takes to come to rest, we need to consider half of the time period, T/2.The amplitude of the simple harmonic motion is equal to the initial dropped distance, § meters. The time it takes for the particle to come to instantaneous rest for the first time is T/2, where T is the time period of the simple harmonic motion.
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Calculate the net force on the particle q1.
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
A ball is dropped from a height of 78.4 m above the ground. How long does it take to hit the ground?
Answer: it would take 4 seconds
Explanation:
A cannon is evaluated at an angle of 45 degree. It fires a ball with a speed of 300 m/s. What is the horizontal range of the ball
Answer:
The horizontal range of the cannonball is 9180.4 meters.
Explanation:
The horizontal range of a cannonball can be calculated using the following formula:
range = (speed * speed * sin (2 * angle)) / acceleration due to gravity
In this case, we are given that the cannon is fired at an angle of 45 degrees and that the speed of the ball is 300 m/s. We can plug these values into the formula to calculate the horizontal range of the ball:
range = (300 * 300 * sin (2 * 45)) / 9.8
= (90000 * sin (90)) / 9.8
= (90000 * 1) / 9.8
= 9180.4 m
A cat runs and jumps from one roof top to another which is 5 meters away and 3 meters below
Answer: 6.45 m/s
Explanation:
Find out the time value
3 = 1/2*a*T^2
6/10 = t^2
t = 0.77 seconds
and the distance is given as 5 m
thus speed,= distance/time.
Putting values,
speed = 5/0.77
= 6.45 m/s
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accelerat
ion due to gravity and radius of gyrations experiment table
The acceleration due to gravity is the acceleration gained by an object due to gravitational force.
What is acceleration due to gravity?The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. Its vector nature which includes both magnitude and direction makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on earth's surface is 9.8 m/s².
The distance a body's entire mass can be concentrated without changing its moment of rotational inertia about an axis through its center of mass is known as the radius of gyration.
Note that your information was incomplete and an overview was given.
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A milliammeter whose resistance is 120 ohm has full scale deflection with a current of 5mA. How will you use it to measure a maximum current of 100 A
Answer:
If 99.995 A pass thru a shunt and 5 mA pass thru the meter, the meter will have full scale deflection for a current of 100 A.
By Ohm's Law
99.995 Rs = .005 Rm
Rs = .005 / 99.995 * 120
Rs = .006 ohms
Using a shunt resistance of .006 Ω will produce the required result.
The value of the shunt resistor should be very low to divert most of the current, use a shunt resistor with a value of 0.0012 ohms.
The value of the shunt resistor (Rs) is:
Rs = (Rm × Im) ÷ (If - Im)
where:
Rs = Shunt resistor value
Rm = Resistance of the milliammeter
Im = Full-scale current of the milliammeter
If = Maximum current we want to measure
The shunt resistor value:
Rs = (120 × 5 ) ÷ (100 - 5)
Rs = (0.12 ) ÷ (100 - 0.005)
Rs = 0.12 ÷ 99.995
Rs = 0.00120018 ohms
Since the value of the shunt resistor should be very low to divert most of the current, use a shunt resistor with a value of 0.0012 ohms.
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Calculate Time
d
12. A vehicle drives a distance of 26000 m at a speed of 65m/s, calculate the time taken for
this journey.
13. A train travels at a speed of 16 m/s and travel a distance of 3200 m, calculate the time it
takes the train to complete this journey.
urs 14. Calculate the time it takes to travel a distance of 672 km at a speed of 96 km/h.
15. A beetle travels at a speed of 0.09 m/s, it travels a distance of 1.08 m before it is caught
in a jar. Calculate the time taken for the beetle to run.
16. Carlisle is a distance of 35 miles away from Lockerbie. If I travelled at a constant speed
5147
deudate the time takon for this journey
12. The time taken for the journey is 400 s
13. The time taken for the train is 200 s
14. The time taken is 7 h
15. The time taken for the beetle is 12 s
16. The time taken for the journey is 0.0068 h
How do i determine the time taken?The time taken in each case as given by the question can be obtain as follow:
12. The time taken for the journey
Distance traveled = 26000 mSpeed = 65 m/s Time taken =?Time taken = Distance / Speed
Time taken = 26000 / 65
Time taken = 400 s
13. The time taken for the train
Distance traveled = 3200 mSpeed = 16 m/s Time taken =?Time taken = Distance / Speed
Time taken = 3200 / 16
Time taken = 200 s
14. The time taken to travel
Distance traveled = 672 kmSpeed = 96 Km/h Time taken =?Time taken = Distance / Speed
Time taken = 672 / 96
Time taken = 7 h
15. The time taken for the beetle
Distance traveled = 1.08 mSpeed = 0.09 m/s Time taken =?Time taken = Distance / Speed
Time taken = 1.08 / 0.09
Time taken = 12 s
16. The time taken for the journey
Distance traveled = 35 milesSpeed = 5147 mile per hourTime taken =?Time taken = Distance / Speed
Time taken = 35 / 5147
Time taken = 0.0068 h
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A particle P of mass 0.4 kg is moving under the action of a single force −→F (in Newtons). At time t (in seconds), the velocity of particle P is given by v = (6t + 4)−→i + (t 2 + 3t) −→j (m/s). When t = 0 s, P is at the position −→O = (–3 −→i + 4−→j ) m. When t = 4 s, P is at the point S. (a) Calculate the magnitude of F when t = 4 s. (b) Calculate the distance OS.
The distance from O to S is 64.5 m.
(a) The force acting on the particle P can be found using Newton's second law, which states that the net force on an object is equal to its mass times its acceleration. In this case, the acceleration is the time derivative of the velocity:
−→a = d−→v/dt = 6−→i + (2t+3)−→j (m/s^2)
The net force is therefore:
−→F = m−→a = 0.4(6−→i + (2t+3)−→j) = 2.4−→i + (0.8t+1.2)−→j (N)
At t = 4 s, we have:
−→F = 2.4−→i + (0.8(4)+1.2)−→j = 2.4−→i + 4.8−→j
The magnitude of the force is:
|−→F| = √(2.4^2 + 4.8^2) = 5.34 N (rounded to two decimal places)
Therefore, the magnitude of the force when t = 4 s is approximately 5.34 N.
(b) The displacement vector from O to S is:
−→OS = −→OP + −→PS
where −→OP = −3−→i + 4−→j (given) and −→PS is the displacement vector from P to S. We can find −→PS by integrating the velocity vector from t = 0 to t = 4:
−→PS = ∫(6t+4)−→i + (t^2+3t)−→j dt = [(3t^2+4t)−→i + (1/3)t^3+(3/2)t^2] from 0 to 4
−→PS = 44−→i + 46.67−→j (m)
Therefore,
−→OS = −3−→i + 4−→j + 44−→i + 46.67−→j = 41−→i + 50.67−→j (m)
The distance |−→OS| is:
|−→OS| = √(41^2 + 50.67^2) = 64.5 m (rounded to one decimal place)
Therefore, the distance from O to S is approximately 64.5 m.
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hat a 15 kg body is pulled along a horizontal fictional table by a force of 4N what is the acceleration of the body
Answer:
Acceleration of the body is:
\(a=0.27\,\,m/s^2\)
Explanation:
Use Newton's second Law to solve for the acceleration:
\(F=m\,\,a\\a=\frac{F}{m} \\a=\frac{4\,N}{15\,\,kg} \\a=0.27\,\,m/s^2\)
What are the characteristics of a realistic fiction story?
The fictional people and circumstances in realistic literature are meant to represent our society and reality. Growing up and facing personal and societal issues are the main topics.
Which is better, fiction or nonfiction?In a word, the primary distinction between fiction and non-fiction is that fiction is the product of imagination, whereas non-fiction is entirely founded on facts and truth. To better grasp the two genres, let's now get in-depth with them.
Describe what fiction is.While it may be based on a factual tale or circumstance, fiction is literature that was formed from the author's imagination and is not meant to be taken seriously as truth. Novels, short stories, and novellas are examples of literature in the fiction category.
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A car traveling 85 km/h is 250 m behind a truck
traveling 73 km/h.
Time needed = t = 20.83 s
Further explanationGiven
car speed = 85 km/h
truck speed = 73 km/h
Required
the time it takes for the car to reach the truck
Solution
When the car reaches the truck, the distance between them will be the same
x car - 250 m = x truck
General formula for distance (d) :
d = v.t
So the equation becomes :
85t-250 = 73t
12t=250
t = 20.83 s
The ratio of the magnitude of the charge of a proton compared to the magnitude of the charge on an electron is
A 1:1
B 1:3
C 1:1.63 E18
D 1:1.67 E-27
E 1:9.11 E-31
Answer: A 1:1
Explanation:
They both have a magnitude of 1.6 x 10^-19 C.
The ratio of the magnitude of the charge of a proton compared to the magnitude of the charge on an electron is 1:1 option (A) is correct.
What is an atom?It is a basic unit of matter everything is made from the atom. It consists of three small particles in it named electron, proton, and neutron. The electron has a negative charge, a proton has a positive charge, and a neutron has no charge.
We know the charge on the proton:
\(\rm Q_p = 1.6 x 10^{-19} \ C\)
And charge on the electron:
\(\rm Q_e = -1.6 x 10^{-19} \ C\)
The absolute value of charge on the electron:
\(\rm |Q_e| = 1.6 x 10^{-19} \ C\)
\(\rm \dfrac{\rm Q_p} {\rm |Q_e| }= \dfrac{1.6 x 10^{-19}}{ 1.6 x 10^{-19}}\)
= 1:1
Thus, the ratio of the magnitude of the charge of a proton compared to the magnitude of the charge on an electron is 1:1 option (A) is correct.
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Which equation is correct according to Ohm’s law? Which equation is correct according to Ohm’s law? A.) V = IR B.) I = R/V C.) R = I/V D.) R = IV
Answer:
\(V = IR\)
Explanation:
Required
Which equation represents ohm's law?
Literally, ohm's law implies that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R).
Mathematically, this can be represented as:
\(I\ \alpha\ \frac{V}{R}\)
Convert the expression to an equation
\(I\ =\ \frac{V}{R}\)
Multiply both sides by R to make V the subject
\(I\ * R\ =\ \frac{V}{R} * R\)
\(I\ * R\ =V\)
Reorder
\(V = I\ * R\)
\(V = IR\)
Option (a) is correct; Others are not
Answer:
V=ir
Explanation:
Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. The correct answers from the choices are:
v = ir
A spring is used to launch a ball vertically into the air. The spring
has a spring constant of 200 N/m and is compressed by
5 cm. A ball of mass 10 g is placed just above the spring. Calculate:
a) the energy stored in the spring
b) assuming the spring transfers all of its energy to the ball, the
velocity of the ball just as it launches
c) the height reached by the ball assuming all the Ek
is converted
into GPE.
Answer:
A spring is used to launch a ball vertically in to the air. the spring has a spring constant of 200 N/m and is compressed by 5 cm.A ball of mass 10 g is placed just above the spring.Calculate [A]the energy stored in the spring [B] assuming the spring transfers all of its energy to the ball,the velocity of the ball just as it launches [C] the height reached by the ball assuming all the Ek is converted in to GPE
Explanation:
Elastic energy = gravitational energy
½ kx² = mgh
h = kx² / (2mg)
h = (200 N/m) (0.05 m)² / (2 × 0.010 kg × 9.8 m/s²)
h = 2.55 m
a cleaner pushes a 4.50 kg laundry cart in such a way that the net external force on it is 60.0 N. Calculate the magnitude of it's accerlation
Answer:
Explanation:
F = ma so filling in:
60.0 = 4.50a and
a = 13.3 m/s/s
Describe the environment of Antarctica.
Answer:
Antarctica is a desert. It does not rain or snow a lot there. When it snows, the snow does not melt and builds up over many years to make large, thick sheets of ice, called ice sheets. Antarctica is made up of lots of ice in the form of glaciers, ice shelves and icebergs.
A loudspeaker, mounted on a tall pole, is engineered to emit 75% of its sound energy into the forward hemisphere, 25% toward the back. You measure an 85 dB sound intensity level when standing 3.5 m in front of and 2.5 m below the speaker. What is the speaker’s power output?
Answer:
"0.049 W" is the correct answer.
Explanation:
According to the given question,
\(r = \sqrt{(3.5)^2+(2.5)^2}\)
\(=\sqrt{8.5}\)
\(SL=85\)
As we know,
⇒ \(SL=10 \ log(\frac{I}{I_o} )\)
\(85=10 \ log(\frac{I}{10^{-12}} )\)
\(I=3.162\times 1^{-4} \ W/m^2\)
Now,
⇒ \(P_{front} = I(2\pi r^2)\)
\(=(3.162\times 10^{-4})(2\pi\times 18.5)\)
\(=0.0368 \ W\)
\(=0.75 \ P\)
or,
\(=0.049 \ W\)
Give the negative of the following vectors: A = 6.0 units SE and B = 7.5 units 67 0
N of W.
The magnitude of the resultant of the two vectors when the position of vector A is known is \(R = \sqrt{92.25 - 90 cos(\theta)} \ \ \ units\).
The given parameters;
vector A = 6 units SEvector B = 7.5 units 67⁰ N WThe resultant of the two vectors is calculated by applying parallelogram law as shown below;
\(R^2 = a^2 + b^2 - 2ab \ cos(\theta)\\\\R^2 = (6)^2 + (7.5)^2 - 2(6 \times 7.5) cos(\theta)\\\\R^2 = 92.25 - 90 cos(\theta)\\\\R = \sqrt{92.25 - 90 cos(\theta)}\)
Thus, the magnitude of the resultant of the two vectors when the position of vector A is known is \(R = \sqrt{92.25 - 90 cos(\theta)} \ \ \ units\).
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You have been assigned to a group project, and one of your partners is Keith. You have never interacted with Keith before this project, but you now have an opportunity to get to know him a bit. The group project takes about two weeks and your main interactions with him are within the context of working on the project:
Keith seems to be a man with a plan. He is quick to want to discuss project roles, a progression timeline, and a structured way to complete the project. The professor makes previous project templates available, and Keith is pretty adamant that the group follows them. Despite some group member's objections, he does not want to do anything creative and just wants to stick with what people have done in the past. This becomes somewhat of a contention point within the group, as several of the members get annoyed at Keith's "my way or the highway" attitude and that he does not seem to really care for their opinions.
Despite some contentions, the group seems to socially function well. Keith seems to be okay with interacting with everyone, but definitely seems more tired than most at the end of group gatherings. He even mentions to you that he goes home and spends alone time in order to recharge from being in the extended social situation. Despite all of the planning and organizing, the group comes pretty close to the submission deadline, with several tasks and not a lot of time to complete them. However, Keith does not seem to be bothered at all and does not seem to be anxious about missing the submission deadline.
Based on the information you have available to you, do the following:
A – Explain the personality trait (please don't just list off the adjectives I have in my notes)
B. Rate Keith on each of the Big 5 personality traits (1 – being lower in the trait, 5 being higher in that trait).
C. Make sure you explain your rationale (i.e. – show me you know what the trait means and explicitly tell me in what way Keith is/isn't exhibiting it/how it's consistent with your explanation for part A). For sample behaviors, you can Copy/paste from the prompt if you want – just put the stuff in quotes/ different color
A. Keith appears to have a Type A personality. He is highly organized and has a strong desire for structure and order, which is evident from his insistence on following the project templates.
He also seems to be somewhat inflexible in his approach to the project, which can be seen from his unwillingness to consider alternative ideas and his "my way or the highway" attitude. Additionally, his need to recharge after social interactions indicates that he may be introverted.
B. Openness: 3, Conscientiousness: 5, Extraversion: 2, Agreeableness: 2, Neuroticism: 3.
C. Keith demonstrates high conscientiousness, as he is organized, methodical, and committed to completing the project.
He is less agreeable, as he appears to be unwilling to consider alternative ideas and can be inflexible in his approach.
Keith's introversion is consistent with his need to recharge after social interactions, and he does not exhibit high levels of extraversion.
Finally, while he does not seem to be anxious about the project deadline, he also does not exhibit high levels of neuroticism.
Overall, Keith's personality seems to be consistent with the Type A personality, which is characterized by high levels of conscientiousness and a need for structure and order.
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What is part of the first stage in the process of technological design?
reporting a solution
building a prototype
researching information
designing a solution
Researching information
Explanation: Edge 2020
hope this helps :3. pls mark me brainiest Brainliest
Answer:
It is C.
Explanation:
Got it right on edge.
Is Saturn less dense than water which has a
density of 997 kg/m³? Find out by calculating the density of Saturn in kg/m³. The mass of Saturn is 5.68 x 1026 kg, and its radius is 5.6 x 107 m.
Density of Saturn:
The density of water at STP, which is \(997 kg/m^3\), we can see that Saturn is less dense than water.
To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is \(997 kg/m^3\).
Saturn's density can be computed using the following formula:
density equals mass divided by volume
Saturn's mass and volume may be computed given its mass and radius.
The volume of Saturn can be determined using the sphere volume formula:
volume =\((4/3) \pi (r^3)\)
where r is Saturn's radius.
Filling in the blanks:
volume = \((4/3) \pi (5.6 \times 107) m^3\)
8.27 x 1023 \(m^3\)volume
Saturn's mass is given as \(5.68 \times 10^{26} kg.\)
We can now compute Saturn's density:
density equals mass divided by volume
density= \((5.68 x 10^{26 }kg\)) /\((8.27 \times 10^{23 }\)m³) a density of\(687 kg/m^3\)
This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.
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Is light a particle or a wave? Is metal a good heat shield? Is the reason that nothing can go faster than light because we have not tried hard enough? Is there any difference between antimatter, dark matter, dark energy, and degenerate matter?
Answer:
Light can act as a wave or a particle. This is called light wave-particle duality, simply that the light has both the characteristics of fluctuations, but also has the characteristics of particles. Light can propagate forward like a wave, and sometimes show the characteristics of particles.
Metal is not heat resistant and therefore it is not a good heat shield. For example pots are made out of metal because they are good conductors of heat.
Light is said to be the fastest, it is because we have not discovered anything faster than light. If someone discover's something faster than light then that will become the fastest. It is not that we have tried hard enough, it is just that our technology, research and veiw of outer space is limited. Implementing good research and technology requires a lot of money, time and expertise. We have much better things to do than to discover something faster then light because even if it's discovered what can we do with it, with our severe lacking research and technology, it's practically useless and good as updating some newspaper articles. When even light can give us a headache.
Dark matter, antimatter, dark energy and degenerate matter can be said to be different. I'm not sure about the intricasies but all have different energy frequencies and effects. Not sure but please do research about it.
Hope this helps you.
If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?
Answer: 207 W
Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:
where
m = 47 kg is the mass of the object
g = 9.8 m/s^2 is the acceleration of gravity
is the change in height
Substituting,
Now we can calculate the power used, which is given by
Hope this helps I'm sorry if i'm wrong but I tried :(
A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at 32.4° above the forward direction. Find the magnitude and direction (relative to the forward direction) of the resultant force which these engines exert on the rocket.
The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.
What is the resultant force the two engines exert on the rocket?The resultant force on the rocket is calculated thus:
The 513N thrust is resolved into vertical and horizontal components;
Horizontal component: 513N cos(32.4°) = 433.14 N
Vertical component: 513N sin(32.4°) = 274.88 N
Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N
Total force at right angles:
0 + 274.88 N = 274.88 N
The resultant force (F) is then given as follows:
F² = a² + b²
F² = (1158.14 N)² + (274.88 N)²
F = √1,416,847.27
F = 1,190.3
To find the direction:
tan X 274.88 N / 1,158.14 N
X = tan⁻¹ 0.237346089419241
X = 13.35°
Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.
In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.
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Pulse transfers a
disturbance. while wave is a
disturbance that transfers energy.
Answer:
Pulse transfers a single disturbance, while wave is a continuous disturbance that transfers energy.
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How much work is done (in Joules) by a weightlifter in raising a 60-kg barbell from the floor to a height of 2m? Work done =
Answer:
1176 Nm or J
Explanation:
W = F*d
F = 60kg * 9.8 kgm/s^2 = 588 N
W = 588 N * 2m = 1176 N*m
The formula for calculating work is Work = Force Distance. The SI unit for work is the joule (J) or Newton meter (N m). One joule is the amount of work done when one Newton of force moves a one-meter object.
1176 N × m = work
What is a work done?The formula for calculating work is Work = Force Distance. The SI unit for work is the joule (J) or Newton meter (N m). One joule is the amount of work done when one Newton of force moves a one-meter object.The product of displacement and the component of the object's applied force in the displacement direction is the work done by a force. When we push a block with some force'F'and the body moves with some acceleration, we are doing work.When energy is transferred from one store to another, work is performed. When a force causes an object to move, work is done.
W = F.d
F = 60kg × 9.8 kgm/s²= 588 N
W = 588 N × 2m = 1176 N × m.
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