Particle 1 is a point charge with q=3.3 C. It enters an electric field with field strength of 5.6 N/C. What force does Particle 1 experience?

Answers

Answer 1

Particle 1, being a point charge with a charge of q=3.3 C, will experience a force when entering an electric field with a field strength of 5.6 N/C.

The force experienced by Particle 1 can be calculated using the formula F = qE, where F is the force, q is the charge of the point charge, and E is the electric field strength. Plugging in the values, we get F = (3.3 C) x (5.6 N/C) = 18.48 N. Therefore, Particle 1 will experience a force of 18.48 N.
To calculate the force Particle 1 experiences, we need to consider the point charge, electric field, and field strength of 5.6 N/C.

Step 1: Identify the given values
- Point charge (q) = 3.3 C
- Electric field strength (E) = 5.6 N/C
Step 2: Use the formula for the force experienced by a point charge in an electric field:
Force (F) = q * E
Step 3: Plug in the given values:
F = (3.3 C) * (5.6 N/C)
Step 4: Calculate the force:
F = 18.48 N
Particle 1 experiences a force of 18.48 N in the electric field with a field strength of 5.6 N/C.

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Related Questions

What factors affect an objects kinetic energy?

Answers

Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

While investigating the relationship between voltage, current, and resistance, students connected different batteries to different circuits
and recorded measurements of battery voltage and current flowing through the battery. They then produced the model shown below.


Based on the data provided in the graphical model, what claim can be made about the resistance of the circuit?

A._The resistance of the circuits increased as battery voltage increased.

B._ The resistance of the circuits decreased as a battery voltage increased.

C._ The resistance of the circuits remained constant as the battery voltage increased.

D._ The resistance of the circuits could have either increased or decreased as the battery voltage increased.

While investigating the relationship between voltage, current, and resistance, students connected different

Answers

Produced the model is the resistance of the circuits decreased as a battery voltage increased (option-B).

What connection does there exist between voltage and current, current and resistance, and voltage and resistance?

Ohm's Law describes how current, voltage, and resistance are related to one another. According to this, as long as the temperature doesn't change, the current flowing through a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit.

The more work a certain quantity of electrons can accomplish at a given voltage. The quantity of electrons that are presently moving through any one point in a circuit at any particular time is known as the current. At the same voltage, a larger current can perform more work. Current times voltage equals power.

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Answer:

b

Explanation:

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Jan can run at 7.5 m/s and Mary at 8.0 m/s. On a race track Jan is given
a 25 m head start, and the race ends in a tie. How long is the track?

Answers

SOLUTION:

Let's call the length of the race track as "x".

To solve for "x", we can use the formula:

\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

Since the race ends in a tie, we know that Jan and Mary both took the same amount of time to run the race. Let's call this time "t".

For Jan:

\(\implies \text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

\(\implies t = \dfrac{x - 25}{7.5}\)

For Mary:

\(\implies\text{ Time} = \dfrac{\text{ Distance}}{\text{ Speed}}\)

\(\implies t = \dfrac{x}{8.0}\)

Since both expressions represent the same time, we can set them equal to each other and solve for "x":

\(\implies \dfrac{x - 25}{7.5} = \dfrac{x}{8.0}\)

Multiplying both sides by 60 (the least common multiple of 7.5 and 8.0) to get rid of the decimals:

\(\implies 8(x - 25) = 7.5x\)

\(\implies 8x - 200 = 7.5x\)

\(\implies 0.5x = 200\)

\(\implies x = 400\)

\(\therefore\) The length of the race track is 400 meters.

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Calculate the mmoi of a tire that weighs 15.0 kg and has a radius of 30.0 (treat it as a hoop )

Answers

Answer:

Kinetic Energy and Work: The mass moment of inertia of the wheel about ... The wheel is made from a 5-kg thin ring and two 2-kg slender ... determine the maximum angular velocity of the wheel if it is ... velocity of the pulley at the instant the 20-lb weight moves ... The spool has a mass of 40 kg and a radius of gyration of.

Explanation:

A 5.5 Kg rock falling in air experience a force due to air resistance of 50N. What is the acceleration

Answers

Answer:

F1 = ma = 5.5 kg * 10 m/s² = 55 N  (force acts downwards)

F2 = - 50 N (force acts upwards)

net force = 5 N (downwards)

F = ma

a = F/m

a = 5 / 5.5

a = 0.91 m/s²

Explanation:

Since the object is falling downwards, the air resistance acts upwards. We also have a force acting downwards since the rock experiences gravitational acceleration (the value of g above is 10 m/s² for the sake of easier calculation but you can also set it to be 9.81 m/s² which is the more accurate value). Since the air resistance and force due to gravity are acting in opposite directions and force is a vector, we have to put a minus in front of F1 or F2 (it doesn't matter which direction you chose to be the positive one) . Then we calculate the net force, aka the difference between F1 and F2. Finally, knowing the force and the mass, we can calculate the acceleration.

What is the change in momentum of a 50. kg
woman goes from running at 8.0 m/s to 0.0
m/s?

Answers

Answer:

400 kg-m/s

Explanation:

Given that,

Mass of the woman, m = 50 kg

Initial velocity, u = 8 m/s

Final velocity, v = 0 m/s

We need to find the change in momentum of the woman. It can be given by :

\(\Delta p=m(v-u)\\\\=50\times (8-0)\\\\=400\ kg-m/s\)

So, the change in momentum is 400 kg-m/s.

a uniform meter stick is freely pivoted about the 0.20m mark. if it is allowed to swing in a vertical plane with a small amplitude

Answers

The period of the pendulum is approximately 2.01 seconds.

The period of a simple pendulum is determined by its length and the acceleration due to gravity. In this case, the length of the pendulum is 0.20 meters.

The period (T) of a pendulum can be calculated using the formula:

T = 2π√(L/g)

where L is the length of the pendulum and g is the acceleration due to gravity.

Substituting the given values into the formula:

T = 2π√(0.20/9.8)

Calculating the expression:

T ≈ 2π√(0.0204)

T ≈ 2π(0.143)

T ≈ 0.902π

T ≈ 2.01 seconds

Therefore, the period of the pendulum is approximately 2.01 seconds.

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Which element is a metalloid? selenium (Se) polonium (Po) phosphorus (P) iodine (I)

Answers

Answer:

Polonium(Po)

Explanation:

Answer:

B. polonium (Po)

Explanation:

i took the test

if the first ball swinging has a mass of 4-kg and the rest of the balls are 2-kg, what would the collisions look like?

Answers

If the first 4-kg ball has a collision with a 2-kg ball, we would expect the 2-kg ball to experience a larger change in velocity than the 4-kg ball due to the difference in mass.

When considering the motion of objects, one important factor to consider is collisions. In this scenario, we are given information about the masses of a series of balls, and we are asked to consider what the collisions between the balls might look like.

If the first ball swinging has a mass of 4-kg and the rest of the balls are 2-kg, then the collisions between the balls will depend on a number of factors, including the speed and direction of each ball.

One thing we can say for certain is that when two balls collide, their momentum will be conserved. This means that the total momentum of the two balls before the collision is equal to the total momentum of the two balls after the collision. Additionally, the kinetic energy of the balls will be conserved in an elastic collision, meaning that the total kinetic energy of the two balls before the collision is equal to the total kinetic energy of the two balls after the collision.

In this scenario, if the first 4-kg ball collides with a 2-kg ball, we would expect the 2-kg ball to experience a larger change in velocity than the 4-kg ball due to the difference in mass. This would cause the 4-kg ball to continue swinging in a path that is less affected by the collision, while the 2-kg ball may change direction more significantly.

If multiple balls are involved in a collision, the situation becomes more complex, and the outcome will depend on the speed, direction, and angle of each ball involved in the collision. However, the principles of conservation of momentum and kinetic energy will still apply to each collision, ensuring that these physical quantities are conserved before and after the collision.

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If you want a charged object to become neutral,then you have to ————-? A.Touch it with a positively charged object B.Touch it with neutral objects C.Touch it with a negativity charged object D.Touch it with the ground

Answers

A) Touch it with a positively charged object

Answer: D.Touch it with the ground

Explanation:

The charged object can become neutral if touched with the ground in a process known as grounding.

If the charged object is negatively charged, excess electrons will flow into the ground thus making the object neutral. If the object is positively charged, electrons will flow from the ground into the object and neutralise it.

If a runners power is 400 W as runs, how much chemical energy does she convert into other forms in 10.0 minutes?

Answers

Answer:

If a runner's power is 400 watts as she runs , then the chemical energy she converts into other forms in 10.0 minutes would be 240,000 Joules . This information may be found in several of the search results provided, including result numbers 1, 2, 4, 5, 6, 8, and 9.

Explanation:

Which of these shows the position of the Sun, Moon, and Earth when a full moon phase occurs? (8.7B)

Answers

Answer:

Lunar eclipse

Explanation:

Lunar eclipse occurs when Earth comes in between sun and Moon. The moon is either partially or fully blocked and the moon sighting appears to be black from earth since the light rays coming from sun are blocked by Earth. Lunar eclipse occurs only at full moon. The moon is aligned with the position of earth and sun so that they all form a straight line.

Suppose a blanket has a sock stuck to it due to static electricity. When you pull the sock off of the blanket, what happens to the potential energy between them?

Answers

Explanation:

When you pull the sock off of the blanket, the socks gain electrons out of blanket. This makes socks slightly negatively charged. The potential energy of the socks rise whereas potential energy of the blanket reduces. This happens because of exchange of electrons between socks and blanket.

Which of the following changes will increase current?
OA. Decreasing power
OB. Increasing volume
OC. Increasing resistance
OD. Increasing voltage

Answers

Option D
Increasing voltage





What is the all time speed record for completing the iditarod?.

Answers

Question:

•What is the all time speed record for completing the iditarod?

Answer:

•In 2016, Dallas broke his own record, finishing in 8 days, 11 hours, 20 minutes and 16 seconds. In 2017, Mitch Seavey broke all previous records by finishing in 8 days, 3 hours, 40 minutes and 13 seconds, which currently stands as the fastest winning time for the Iditarod.

Explanation:

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With the aid of diagram(s), explain the configuration of a tensile force measurement using strain gauge (without bridge). Derive the relationship between the change in resistance and the tensile force, P. With the derived relationship, determine the change in resistance for a strain gauge that is installed on a beam that is being pulled axially by a 50 kN tensile force. Given that for the strain gauge, F = 2, R = 1200, and for the beam, E = 200 10 kNm 2, width = 5cm and thickness = 1cm.

Answers

In a tensile force measurement using a strain gauge, the strain gauge is typically attached to the surface of the material experiencing the tensile force. The strain gauge is a resistive sensor that changes its electrical resistance in response to the deformation or strain of the material.

When a tensile force is applied to the material, it causes the material to deform. This deformation results in a change in the length and cross-sectional area of the material. The strain gauge, being bonded to the surface of the material, also experiences this deformation, which causes a change in its resistance.
The relationship between the change in resistance (∆R) and the tensile force (P) can be derived using the concept of strain and the gauge factor (GF) of the strain gauge. The gauge factor is a constant that represents the sensitivity of the strain gauge and is typically provided by the manufacturer.
The relationship is given by the equation:
∆R = GF * R * ε
Where:
∆R is the change in resistance of the strain gauge,
GF is the gauge factor of the strain gauge,
R is the initial resistance of the strain gauge,
ε is the strain experienced by the material.
To determine the change in resistance for a strain gauge installed on a beam being pulled axially by a 50 kN tensile force, additional information is required. Specifically, the length of the beam and the modulus of elasticity (E) of the material. With this information, the strain (ε) can be calculated using the equation
ε = δL / L
Where:
δL is the change in length of the beam,
L is the initial length of the beam.
Once the strain is determined, the change in resistance can be calculated using the derived relationship ∆R = GF * R * ε, where GF and R are given as 2 and 1200, respectively.

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what are the products of coal​

Answers

Answer:

coal tar is one of the product of coal

Coal tar is one of the main ones or products of coal

Draw a picture showing the possible phases of the moon in this binary star
system, do they look the same or different from those we see in the sky in
reality? (You might want to think about scale and how far the suns would be
when considering your answer.)

(Help ASAP)

Answers

Is this what your talking about if not sorry
Draw a picture showing the possible phases of the moon in this binary starsystem, do they look the same

A fluid of specific gravity 1.0 is flowing through a horizontal conduit at a velocity 2.0 m/s before descending 11 m to a lower portion of the conduit where it travels horizontally at 9.0 m/s. What is the pressure difference (P_lower- P−​upper) between the lower portion and the upper portion of the conduit? Your Answer: Answer units

Answers

The pressure difference (P2 - P1) between the lower portion and the upper portion of the conduit is -38,555 Pa.

Given data: Specific gravity (SG) = 1.0

             Velocity at upper portion (V1) = 2.0 m/s

      Distance from upper portion (H1) = 0 m

  Velocity at lower portion (V2) = 9.0 m/s

Distance from lower portion (H2) = 11 m

To find: Pressure difference (P2 - P1) between the lower portion and the upper portion of the conduit

     Formula used:P + (1/2)ρV² + ρgh = constant Where, P = pressureρ = density

               V = velocityg = acceleration due to gravity

        h = height

Let's consider upper portion,

Using the above-mentioned formula:P1 + (1/2)ρV1² + ρgH1 = constant -----(1)

P1 = constant - (1/2)ρV1² - ρgH1P1 = constant - (1/2)ρ

V1² - ρg(0)  //

At upper portion, height (H1) = 0,  g= 9.81 m/s²P1 = constant - (1/2)ρV1² -------(2)

Let's consider the lower portion:Using the above-mentioned formula:

                                P2 + (1/2)ρV2² + ρgH2 = constant ----- (3)

                             P2 = constant - (1/2)ρV2² - ρgH2 -------(4)

Subtracting equation (2) from equation (4), we get,

                      P2 - P1 = - 1/2 ρ (V2² - V1²) + ρg (H2 - H1)              

                          = - 1/2 ρ (9.0 m/s)² - (2.0 m/s)² + ρg (11 m - 0 m)

                          = -0.5 ρ (81 - 4) + ρg (11)

                          = -0.5 × 1000 × 77 + 9.81 × 11

                          = -38,555 Pa

Therefore, the pressure difference (P2 - P1) between the lower portion and the upper portion of the conduit is -38,555 Pa.

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What effect will a change in wind direction have upon maintaining a 3° glide slope at a constant true airspeed?

Answers

A change in wind direction will not have a significant effect on maintaining a 3° glide slope at a constant true airspeed, but it may require some minor adjustments in heading or pitch to compensate for any deviations caused by the wind.

A change in wind direction will have an effect on maintaining a 3° glide slope at a constant true airspeed. The glide slope is determined by the vertical and horizontal components of the aircraft's velocity. If there is a crosswind, it will cause the aircraft to drift off course, which could lead to a deviation from the desired glide slope. The pilot will have to adjust the aircraft's heading to compensate for the crosswind and maintain the desired glide slope.

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Which nucleus completes the following equation?
Cle+?
OA. S
OB. S
16
OC. Ar
18
OD. 39 y
18

Which nucleus completes the following equation?Cle+?OA. SOB. S16OC. Ar18OD. 39 y18

Answers

The equation below is completed by the chromium nucleus.

Where can one locate chrome?

Chromium is mostly found in chromite. The locations where this ore can be found include South Africa, India, Kazakhstan, and Turkey. In an electric arc furnace, chromite is often reduced with carbon to generate chromium metal, as is chromium(III) oxide when it is reduced with silicon or aluminum.

Why is chromium necessary?

An important mineral called chromium helps insulin work properly in the body by regulating blood sugar levels. Your body uses the hormone insulin to convert sugar, starchy carbs, and other foods into the energy you require for daily activities.

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Define 1 kg of mass as international standard​

Answers

The kilogram is the Standard International System of Units unit of mass. It is defined as the mass of a particular international prototype made of platinum-iridium and kept at the International Bureau of Weights and Measures.

Answer:

1 kg is defined as the mass of a cylindrical Platinum iridium alloy whose height is equal to its diameter

A force of 100 N to the east and a force or 100 N to the west both act on an object of 10 kg. What is the acceleration of the object?

A. 10 m/s2 to the east

B. 100 m/s2 to the west

C. 0 m/s2, it does not accelerate

D. 100 m/s2 to the east

Answers

Answer:

C, it doesnt accelerate

Explanation:

F=ma

F = 100 east + 100 west

F = 100 east + (-100 east)

F = 0

0 = ma

in order to isolate acceleration, we would be dividing 0 by mass, which would equal 0

The resistance to the motion of an object is

Answers

Answer:

Inertia

Explanation:

Part of Newton's Laws of Motion

you weigh 150 pounds, and your friend is dragging you on a sled up a hill by pulling on a rope with 50 n of force. you are moving in a straight line and at constant speed. your acceleration is:_____

Answers

The acceleration of the person being dragged on the sled is zero. The acceleration due to gravity is approximately 9.8 m/s², the mass of the person is approximately 68.04 kg (150 pounds / 2.2046).

The person being dragged on the sled is moving at a constant speed, which means there is no change in velocity. According to Newton's second law of motion, the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The person's weight of 150 pounds can be converted to mass using the formula: mass = weight / acceleration due to gravity.

Since the person is moving at a constant speed, the net force acting on them must be zero. The force of 50 N exerted by the friend pulling the rope is balanced by the force of friction opposing the motion.

Therefore, the acceleration of the person being dragged on the sled is zero. The force of friction in this case is equal in magnitude and opposite in direction to the force applied by the friend. This balance of forces allows the person to maintain a constant speed while being dragged up the hill.

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water moves past a water wheel, causing it to turn. the force of the water is 200 n, and the radius of the wheel is 10 m. calculate the torque around the center of the wheel.

Answers

The torque around the center of the wheel is 2000 Nm. Torque is the product of force and distance.

In this case, the force is the force of the water, which is 200 N, and the distance is the radius of the wheel, which is 10 m.

Torque = Force x Distance Torque = 200 N x 10 mTorque = 2000 Nm Therefore, the torque around the center of the wheel is 2000 Nm.

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A bicyclist is traveling at +25 m/s when he begins to decelerate at -4 m/s2. How fast is he traveling after 5 seconds?

Answers

Answer:

The bicyclist goes at 5 m/s

Explanation:

Motion With Constant Acceleration

It's a type of motion in which the velocity of an object changes uniformly in time.

The equation that rules the change of velocities is:

\(v_f=v_o+at\)

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

It's given a bicyclist is traveling at v0=+25 m/s and decelerates at \(a=-4\ m/s^2\). We are required to calculate the speed after t=5 seconds.

Applying the formula:

\(v_f=25+(-4)*5\)

\(v_f=25-20=5\)

\(v_f=5\ m/s\)

The bicyclist goes at 5 m/s

HEAT TRANSFER INTO a system from the surroundings is considered a POSITIVE transfer of energy. True or False?

Answers

True heat transfer into a system from the surroundings is considered a positive transfer

True, heat transfer into a system from the surroundings is considered a positive transfer of energy. This is because the system is gaining energy from its surroundings, causing its internal energy to increase. This can be represented by a positive value for heat transfer (Q) in the equation for the change in internal energy of a system: ΔU = Q - W, where W is the work done by the system. If heat is transferred out of the system and into the surroundings, it would be considered a negative transfer of energy and represented by a negative value for Q.

apply the necessary conversions to find: a) the speed in m/s equal to 78.0 mi/h b) the area in ft2 of a rectangle with sides 18.6 m and 3.82 m. c) the height in cm of a person who is 5 ft 7 in tall.

Answers

The speed in m/s equal to 78.0 mi/h AND  the area in ft2 of a rectangle with sides 18.6 m and 3.82 m AND the height in cm of a person who is 5 ft 7 in tall.

a) To find the speed in m/s equal to 78.0 mi/h, we use the conversion factor,

1 mi = 1609.344 meters and 1 h = 3600 s.78.0 mi/h = (78.0 mi/h) x (1609.344 m/mi) x (1 h/3600 s)= 35.0 m/s

Therefore, the speed in m/s equal to 78.0 mi/h is 35.0 m/s.

b) The area in ft2 of a rectangle with sides 18.6 m and 3.82 m is calculated as follows:

First, we convert the sides from meters to feet using the conversion factor

1 m = 3.281 ft.18.6 m = 18.6 m x (3.281 ft/m) = 61.024 ft3.82 m = 3.82 m x (3.281 ft/m) = 12.532 ft

The area is given by the formula A = L x W, where L is the length and W is the width.

A = (61.024 ft) x (12.532 ft)A = 765.69 ft2Therefore, the area in ft2 of a rectangle with sides 18.6 m and 3.82 m is 765.69 ft2.

c) The height in cm of a person who is 5 ft 7 in tall can be found by converting the height to inches and then to centimetres.

1 ft = 12 in5 ft = 5 ft x 12 in/ft = 60 in5 ft 7 in

= 60 in + 7 in = 67 in1 in = 2.54 cm67 in

= 67 in x (2.54 cm/in) = 170.18 cm

Therefore, the height in cm of a person who is 5 ft 7 in tall is 170.18 cm.

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2) Which tricks do you use to reduce pressure in everyday activities?

Answers

Answer:

Explanation:

Increase activity and exercise more. ...

Lose weight if you're overweight. ...

Cut back on sugar and refined carbohydrates. ...

Eat more potassium and less sodium. ...

Eat less processed food.

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