noting i had the answer

Answer:

they are quantities with magnitude without direction e.g weight,

Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

To better understand crash dynamics we have to look at "the laws of motion."

The laws of motion

The laws of motion were introduced by Sir Isaac Newton in 1687 in his book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), which defined the laws of motion, or three fundamental laws that govern the movement of bodies. The laws of motion, according to Newton, govern the motion of an object or a system of objects that interact.

It defines the concepts of force and mass, and the fundamental dynamics of motion.The following are the laws of motion:Every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. The velocity of an object changes proportional to the force applied to it, and the acceleration of an object is proportional to both its force and its mass. For every action, there is an equal and opposite reaction.

Therefore, these laws are necessary to fully grasp crash dynamics because they explain how objects respond to outside forces that cause them to accelerate or decelerate.

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Answer:

c

Explanation:

electronic balance must always be at zero to prevent errors in measured value

In order to get the most accurate mass measurement, you must calibrate your electronic balance properly so that it gives you a zero mark when empty, therefore the correct answer is option C.

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

Any additional quantity of that type can be stated as a multiple of the measurement unit.

Hence, the right response is option C because you must correctly calibrate your electronic balance such that it displays a zero mark when empty in order to acquire the most accurate mass measurement.

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Answer:

Where is the quantity?

Explanation:

Plz show the question properly

Answer:

0.25m/s^2

Explanation:

F = ma

a = F/m

(Newton's Second Law)

Answer:

θ₁ = 0.5 revolution

Explanation:

We will use the conservation of angular momentum as follows:

\(L_1=L_2\\I_1\omega_1=I_2\omega_2\)

where,

I₁ = initial moment of inertia = 18 kg.m²

I₂ = Final moment of inertia = 3.6 kg.m²

ω₁ = initial angular velocity = ?

ω₂ = Final Angular velocity = \(\frac{\theta_2}{t_2} = \frac{2\ rev}{1.2\ s}\) = 1.67 rev/s

Therefore,

\((18\ kg.m^2)\omega_1 = (3.6\ kg.m^2)(1.67\ rev/s)\\\\\omega_1 = \frac{(3.6\ kg.m^2)(1.67\ rev/s)}{(18\ kg.m^2)}\\\\\omega_1 = \frac{\theta_1}{t_1} = 0.333\ rev/s\\\\\theta_1 = (0.333\ rev/s)t_1\)

where,

θ₁ = revolutions if she had not tucked at all = ?

t₁ = time = 1.5 s

Therefore,

\(\theta_1 = (0.333\ rev/s)(1.5\ s)\\\)

θ₁ = 0.5 revolution

Answer:

2 m = E / c^2      where m is mass of electron

E = h v     where v is the frequency ( nu) of the incident photon

E = h c / y      where y is the incident wavelength (lambda)

2 m = h / (c y)

y = h / (2 m c)      wavelength required

y = 6.62 * 10E-34 / (2 * 9.1 * 10E-31 * 3 * 10E8)  m

y = 3.31 / 27.3 E-11 m

y = 1.21 E -12 m   = .0121 Angstrom units

The volume of the vegetable oil is  0.00003998 m³.

The density of vegetable oil,

ρ = 913 kg/m³

The mass of vegetable oil,

m = 0.0365 kg

To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.

The formula for density is:

ρ = m/V

where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:

V = m/ρSubstituting the given values of mass and density in the above formula,

We get:

V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)

Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.

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The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer:

Yes, you would consider the mass × gravity at the centre of gravity of the object in question to cause a moment, hence it should be included in your resolution

The distance between two consecutive nodes and the amplitude after 0.56s are m/2 and 1.75×10^(-4) m respectively.

= 2π/(4π÷m)

= m/2

Displacement after 0.56 s = 0.008×cos(50π×0.56s)

=1.75×10^(-4) m

Thus, we can conclude that the distance between consecutive nodes and displacement after 0.56 s are m/2 and 1.75×10^(-4) m respectively.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The particle displacement y of air molecules due to a sound wave is given by y=0.008coswtsinkz where k=4π÷m and w=50π rads/s.

Calculate:

I) the distance between 2 consecutive nodes

ii) the amplitude after 0.565s

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According to the Law of Conservation of Mechanical Energy, if there are no external or non-conservative forces acting on a system (such as friction), then, the total mechanical energy of the system remains constant.

The mechanical energy of a system is the sum of its kinetic energy K and its potential energy U:

The kinetic energy of a particle with mass m and speed v is:

And the potential energy of a particle with mass m located at a height h is:

Where g is the acceleration of gravity on the surface of Earth.

When the roller coaster car is located at the top of the 30.00-meter hill, its kinetic energy is 0 and its potential energy is:

Then, the total mechanical energy of the roller coaster car is:

On the other hand, the potential energy of the car when it is halfway down is:

Since the total mechanical energy is the same, we can find the kinetic energy of the car when it is halfway down using the law of conservation of mechanical energy:

Therefore, the potential and kinetic energy of the car when it is halfway down the hill at a height of 15.0 meters are:

Using PE for potential energy and KE for kinetic energy:

Therefore, the correct choice is the second option.

Answer:

356°C.

Explanation:

(1). The first step to the solution to this particular Question/problem is to determine the Biot number, and after that to check the equivalent value of the Biot number with plate constants.

That is, Biot number = (length × ∞)÷ thermal conductivity. Which gives us the answer as ∞. Therefore, the equivalent value of the ∞ on the plates constant = 1.2732 for A and 1.5708 for λ.

(2). The next thing to do is to determine the fourier number.

fourier number = [α = 97.1 × 10−6 m2/s × 15 s] ÷ (.05m)^2 = 0.5826.

(3). The next thing is to determine the temperature at the center plane after 15 s of heating.

The temperature at the center plane after 15 s of heating = 500°C [ 25°C - 500°C ] [1.2732] × e^(-1.5708)^2 ( 0.5826).

The temperature at the center plane after 15 s of heating = 356°C.

The correct answer for the isolated systems is options 2 & 4.

2) A ball is dropped from the top of a building. The system is the ball and the earth.

4) A car slides to a halt in an emergency. The system is the car.

In both of these systems, the isolated system is the object in motion, either the ball dropped from the top of the building or the car sliding to a halt in an emergency. The conservation of linear momentum is applicable because the system does not interact with any external forces or objects.

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Technically, ALL of the planets do.

The effect is greatest inside Mercury, because Mercury is the one closest to the Sun.

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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This may shock you:

We NEVER feel speed, velocity, or motion, as long as it's constant.

We only feel CHANGES in speed, velocity, or motion.

That means speeding up, slowing down, or changing direction.

As long as we're moving in a straight line at a constant speed, we don't feel anything.

The masses of the two objects MA and MB in the binary system are 4 Mo respectively.

The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.

Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:

MA + MB = 8 Mo

We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:

d(A to B) / d(Binary System) = 1/3

We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:

d(A to B) + d(B to binary system) = d(Binary system)

Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):

d(A to B) + 1/3d = d(Binary system)

3d(A to B) + d = 3d(Binary system)

Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:

3d(A to B) + d = 3(d(A to B) + d(B to binary system))

2d(A to B) = 2d(B to binary system)

d(A to B) / d(B to binary system) = 1

So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:

MA = MB

Substituting this into the first equation, we get:

2MA = 8 Mo

MA = MB = 4 Mo

Therefore, the mass of each object is 4 Mo.

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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The speed of the object is the same at the same height going up and coming down. The speed on the way down would be lower than the speed on the way up due to the energy lost to air resistance.

The initial state is an object being thrown vertically upwards, while the final state is the object reaching the same height on its way down.

In first energy system diagram, Kinetic energy decreases and potential energy increases. At the intermediate height, the object has zero kinetic energy and maximum potential energy. In the second diagram, potential energy decreases while its kinetic energy increases until it reaches the same intermediate height as before, where the object has maximum kinetic energy and zero potential energy. Therefore, the speed of the object is the same at the same height going up and coming down.

In second method, object has kinetic energy and potential energy due to gravity at the initial state, and at the final state, it has kinetic energy but no potential energy. Comparing the two states, object's kinetic energy at the final state is the same as its initial kinetic energy but opposite in direction. Therefore, the speed of the object is the same at the same height going up and coming down.

The condition where the speed going up and coming down at the same height would not be the same is if there is air resistance acting on the object.

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Explanation:

Nuclear to chemical is the type of energy conversion that occurs when atoms are split in a chain reaction and a large explosion occurs.

The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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The properties that determine the escape velocity of an object launched from a spacecraft in orbit around a planet are the mass of the planet, the distance between the spacecraft and the center of mass of the planet, and the mass of the object. The radius of the spacecraft and the radius of the planet are not directly related to the escape velocity, although they may affect the launch and trajectory of the object.

Escape velocity is the minimum velocity required for an object to escape the gravitational pull of a massive body such as a planet, moon, or star, and move away from it infinitely without being pulled back by the gravity.

The escape velocity of an object launched from a spacecraft in orbit around a planet is determined by the following properties:

1. The mass of the planet: The escape velocity is directly proportional to the mass of the planet. The greater the mass of the planet, the greater the escape velocity required to escape its gravitational pull.

2. The distance between the spacecraft and the center of mass of the planet: The escape velocity is inversely proportional to the square root of the distance between the spacecraft and the center of mass of the planet. The farther the spacecraft is from the planet, the lower the escape velocity required to escape its gravitational pull.

3. The mass of the object: The escape velocity is directly proportional to the mass of the object. The greater the mass of the object, the greater the escape velocity required to escape the planet's gravitational pull.

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Answer: low = 1.73 m and high = 0.129 m

Explanation: All you have to do is use the formula (Wavelength = Velocity/Frequency. Which would be 340m/s divided by 196 Hz and then 340m/s divided by 2637Hz.

The wavelength of a wave is its speed divided by frequency. The wavelength corresponds to the lower frequency of 196 Hz is 1.73 m and that for 2637 Hz is 0.12 m. Hence the wavelength range is 1.73 m to 0.12 m.

Frequency of a wave is the number of wave cycles per unit time. It is the inverse of the time period. Thus, its unit is s⁻¹ which is equal to Hz. Frequency of a wave is inversely proportional to the wavelength.

The relation between speed and frequency with wavelength of the wave is given by,

c = νλ

Given frequency  ν1 = 196 Hz.

speed of sound wave c = 340 m/s

then, wavelength at this frequency λ1 = 340 m/s / 196 Hz = 1.73 m.

For a frequency ν2 = 2637 Hz.

λ2 = 340 m/s/ 2637 Hz = 0.12 m.

Therefore, the range of wavelength of the notes from the violin will be in between 1.73 m to 0.12 m.

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Answer:

ladder: inclidine plane

broom:lever

shovel: lever

Answer: We get chemical energy from foods, which we use to run about, and move and talk  kinetic and sound energy  Chemical energies are stored in fuels which we burn to release thermal energy - this is one way of making electricity, see Electricity for more information



hope this helps

"Compression of rock is nothing but squeezing the rock together and shearing is pushing the rock in opposing directions."

It squeezes the boulder as a whole and should cause the pulls to shear. This is because compression causes the weight necessary for rocks to be squeezed. Additionally, the rock's draws shouldn't be spaced apart. It shouldn't be going in opposing ways either.

When rocks are compressed together, they fold, fracture, or even shatter. Compression stress is the most prevalent stress at convergent plate boundaries. There is stress when rocks are being torn apart. Under stress, rocks either lengthen or fragment.

Due to the compression pushing the hanging wall up in relation to the footwall, if the fault arises in a scenario of compression, it will be a reverse fault.

Compressional stresses cause a rock to shorten. A rock elongates or pulls apart as a result of tensional pressures. Shear forces cause rocks to slide past one another.

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The acceleration (a) of driver is - 1.771 m/s²

Acceleration is the rate of change of the velocity of an object with respect to time. Its unit is m/s² and can be given as,

a = dv/dt

Where , dv and dt is the small change in velocity and time of an object.

We are given that,

The distance traveled by the driver = s = +2170 m

The time taken by the driver = t = 35. 0 s

The initial velocity of driver = u = + 62.0 m/s

Therefore , to get the acceleration of the driver with the equation of motion

v = u + at

Here v is the final velocity which can be taken zero then putting the values in above equation can be get ,

0 = (+62. o m/s) + (a) 35.0s

a = -  (+62. o m/s) /( 35.0s)

a = - 1.771 m/s²

Hence , the negative sign of acceleration shows that , when the driver is slowing down , then acceleration is in the opposite as the velocity. i.e. the acceleration is - 1.771m/s²

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