Neil Gehrels is the head of the Swift satellite team. Why is he certain the burst he discovered is not from the explosion of a massive star?

a) The mass of the block of ice is 56.9kg

b) If the worker stops pushing at the end of 4.30 s, The distance the block moves in the next 4.20s is 9.96m

Explanation:

a) The given data are:

F = 76.0 N, t = 5.30 s, V = ?, u = 0, a = ?, d = 10.0 m, μ = 0

We know that:

F = ma

where

F is the force applied to the object

m is its mass

a is the acceleration produced by the force

We need to find the mass of the block so we can find its acceleration.

Using F = ma and substituting the values given, we have:76.0 = ma a = 76.0/m

We know that:

d = ut + 1/2at²

where

d is the distance covered by the object

u is its initial velocity, t is time

a is the acceleration of the object since it has been given that the block starts from rest.

u = 0 => d = 1/2at² = (76/m)(5.30/2)² = 14.0 m

Dividing by d = 10.0

we have:

10/14 = 1/1.4 = m/76m = (1/1.4) × 76 = 54.3 kg

Rounding to one decimal place, the mass of the block is 56.9 kg.

b) When the worker stops pushing the block, the force applied is zero so the acceleration of the block becomes zero too.

From 0 s to 4.30 s, the block has travelled a distance of:

d₁ = ut + 1/2at² = (0)(4.30) + (1/2)(76/m)(4.30)² = 69.5/m m

From 0 s to 5.30 s, the block travelled a distance of d = 10.0 m

Therefore, from 4.30 s to 5.30 s, the block travelled:

d - d₁ = 10.0 - 69.5/m

Substituting the value of m, we get:

d - d₁ = 10 - 69.5/56.9 = 9.96 m

Thus, the distance the block moves in the next 4.20 s is 9.96 m.

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The hot balloon would move with less supply of energy when surrounded by the red dye in the water  than when surrounded by cool air.

We know that the hot air balloon is the kind of experiment that we can be able to use to demonstrate buoyancy. In this kind of experiment that we are talking about here, it follows that we put the hot air balloon in  the red dye in the water bin with what happens to a hot air balloon surrounded by cool air.

It is know that the density is the ratio of the mas to the volume of the object. The density of the gas in the balloon is quite important here. The gas in the hot air balloon when surrounded by the hot air which has les density then it is going to need less supply of energy to move but more energy would be needed when it surrounded by cool air.

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Answer:

The spring constant is 907.2 N/m

Explanation:

v^2 = u^2 + 2as

Where:

v = final velocity

u = initial velocity

a = acceleration

s = displacement

As the spring is clamped to the table, the only displacement is horizontal, so the only acceleration is due to gravity. The final velocity is 0, as the ball lands on the floor. Therefore, we can use the equation of motion to determine the initial velocity of the ball:

v^2 = u^2 + 2as

0 = u^2 + 2g(1.6 m)

u = √ (2g(1.6 m))

We know that acceleration due to gravity is 9.8 m/s^2, so:

u = √ (2 * 9.8 * 1.6) = 4.6 m/s

Now we can use the conservation of energy to solve for the spring constant.

The spring constant can be determined by using the equation:

PE = 1/2 kx^2

where PE is the potential energy stored in the spring, k is the spring constant, and x is the compression of the spring.

KE = 1/2 mv^2

where KE is the kinetic energy of the ball, m is the mass of the ball, and v is the initial velocity of the ball

The sum of the potential energy stored in the spring and the kinetic energy of the ball is conserved, so:

1/2 kx^2 = 1/2 mv^2

We can now substitute the values we know into the equation:

1/2 k * (0.2)^2 = 1/2 * (19g) * (4.6m/s)^2

Solving for k:

k = (19g * (4.6m/s)^2 ) / (0.2m)^2

k = 907.2 N/m

Note that the unit of mass is gram (g) and it needs to be converted to kg to make the units consistent.

it will experience great force

the required equation for centripetal force is F = k m¹ v¹ r⁻¹.

A particle traveling uniformly in a circle experiences a centripetal force, F, which is dependent on the mass (m), velocity (v), and radius (r) of the circle.

the F formula using the dimensions method is

Suppose F = k mᵃvᵇrⁿ. (i)

Where a, b, and n are the respective powers of m, v, and r and k is the dimensionless constant of proportionality.

Upon putting the measurements of various amounts in (i)

we get

[M¹L¹T‐²] = Mᵃ[LT‐¹]ᵇ Lⁿ

=> [M¹L¹T‐²] = Mᵃ Lᵇ Lⁿ T⁻ᵇ

=> [M¹L¹T-²] = Mᵃ Lᵇ⁺ⁿ T⁻ᵇ

on comparing both sides we get

a = 1

b+n = 1

-b = -2 => b = 2

Then n = -1

Onputting these values in (i),

we get

F = k m¹ v¹ r⁻¹

Or

F=k(mv²)/r

This is the required equation for centripetal force.

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Although being a fossil fuel, natural gas is cleaner and more effective than other conventional fuels. According to the Center for Liquefied Natural Gas, natural gas emits fewer greenhouse gases and pollutants than its competitors. Thus, it is true.

The methane and other hydrocarbon molecules in the decomposing organisms contain chemical energy that was previously obtained by photosynthesis from the sun. Burning natural gas can provide power as well as heat homes.

Methane makes up the majority of natural gas, but it also includes ethane, propane, and heavier hydrocarbons. Moreover, it has trace amounts of water, nitrogen, carbon dioxide, and hydrogen sulphide.

Therefore, it is true that therm is a unit that is generally used to measure the energy contained in natural gas.

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To convert the ideal-gas equation to relate Ppsig, Vft³, nlb-mole, and T°F and the total amount of gas is calculated by converting the moles of CO and N to lb-mole and to estimate the temperature needed to increase the gas pressure to 3000 psig, Convert the obtained temperature in K to °F.

The equation relating P (psig), V (ft³), n (lb-mole), and T* (°F) is:

P = 14.7 * P(atm), V = 28.3168 * V(L), n

= 2.20462 * n(mol), and T*

= (9/5) * T(K) - 459.67 and to calculate the total amount of gas in lb-mole, multiply the number of moles of CO by its molar mass and convert to lb-mole and to estimate the temperature in °F required to increase the gas pressure to 3000 psig.

(a) To convert the equation, we need to apply the following conversions:
- To convert P from atm to psig, multiply by 14.7 (since 1 atm = 14.7 psig).
- To convert V from liters to ft³, multiply by 28.3168 (since 1 liter = 0.0353 ft³).
- To convert n from mol to lb-mole, multiply by 2.20462 (since 1 mol = 2.20462 lb-mole).
- To convert T from K to °F, use the conversion formula:

T* = (9/5) * T(K) - 459.67.

(b) To calculate the total amount of gas in lb-mole, multiply the number of moles of CO by its molar mass (using the periodic table) and convert to lb-mole by multiplying by the molar mass of CO (28.01 lb/lb-mol). To calculate the mass of CO in lb, multiply the number of moles of CO by its molar mass (28.01 g/mol) and convert to lb by dividing by 453.59237 g/lb.

(c) To estimate the temperature in °F required to increase the gas pressure to 3000 psig, rearrange the ideal gas equation to solve for T*. Substitute the known values: P = 3000 psig (pressure limit), V = 3.5 ft³ (volume), n = 30.0 mole (number of moles), and solve for T*. Note that this estimate may not be accurate at high pressures.

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Answer:

a on edge

Explanation:

Answer:

built in potential Vbi = +0.5V

barrier height = 0.139 V

doping concentration = 5.39 × 10²³cm³

Explanation:

When a light rain falls after oil and gasoline have leaked onto the road surface, it can cause the car to become less responsive and more difficult to control.

This is because the oil and gasoline act as a slippery layer on the road surface, which reduces the friction between the tires and the road. The rainwater can then mix with the oil and gasoline, making the layer even more slippery and reducing the vehicle's grip on the road.

To help mitigate this issue, drivers should be aware of their surroundings and the potential for slippery surfaces, and should adjust their speed and driving accordingly. Additionally, using tires with greater tread, or using more aggressive tires designed for wet and slippery conditions, can also help increase the vehicle's grip on the road.

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Our Milky Way formerly lived a life that was very eventful: between 13 and 8 billion years ago, it led a life of frenzied activity, merging with other galaxies and devouring a lot of hydrogen to create stars.

Maosheng Xiang and Hans-Walter Rix from the Heidelberg-based Max Planck Institute for Astronomy have recreated the tumultuous adolescence of our galaxy using fresh data.

The exact ages of 250,000 Milky Way stars have to be determined by the researchers in order to accomplish this.

A few more mergers with galaxies that were somewhat smaller than the Milky Way also occurred. They shook things up and produced the so-called star halo that surrounds the Milky Way disk.

Therefore, Our Milky Way formerly lived a life that was very eventful: between 13 and 8 billion years ago, it led a life of frenzied activity, merging with other galaxies and devouring a lot of hydrogen to create stars.

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Answer:

mutation

Explanation:

Genetic variations in a population are caused by random mutations.

Genetic variations refer to the differences in DNA sequences between individuals in a population. These variations are the result of random mutations that occur in the DNA of organisms over time. Mutations are changes in the genetic code, and they can happen spontaneously during the process of DNA replication or due to external factors such as radiation, chemicals, or environmental influences.

When cells replicate, they sometimes make errors in copying their DNA, leading to new genetic information. These mutations can be neutral, harmful, or occasionally beneficial. Harmful mutations may lead to genetic disorders, whereas beneficial mutations can provide certain individuals with advantages in adapting to their environment.

Over generations, genetic variations accumulate in a population. Natural selection then plays a crucial role in determining which variations are advantageous and which are not. If a particular genetic variation offers a survival or reproductive advantage, it is more likely to be passed on to future generations, leading to evolutionary changes in the population.

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Answer:

The best description of the general direction that the blue line points is East direction

Answer:

c. east

Explanation:

Answer:

true?

Explanation:

If the radius of the cylinder is halved and length is kept unchanged then the density of air inside the cylinder will increase.

As it can be said that density is inversely proportion to the square of the radius.

Density of Cylinder

Density is the ratio of mass to volume.

The formula for density is: ρ= m/v.

The formula for the Mean Density of a cylinder is:

                                         ρ= m/ (π•r²•h)

where:

ρ is the density of the cylinder

m is the mass of the cylinder

h is the height of the cylinder

So, with increase in radius the of the cylinder there is decrease in the density of cylinder.

And on decreasing the radius of the cylinder there is increase in the density of the cylinder.

As it can be said that density is inversely proportion to the square of the radius.

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Answer:

One way is to polish the surface and the other way is to use oil or grease between the surfaces.

Explanation:

Hope this is right lol :)

Answer:

a) t = 14.2 s ,  v = -92 m / s , b) v = - 59.16 m / s ,   t = 0.916 s

c)  t = 7.75 s ,   x = 387.5 m

d) t = 10.64 s , x = 463.9 m ,   v = 92.2 m / s

Explanation:

This is an exercise in kinematics, suppose we take the upward direction as positive

a) is thrown up vertically.

Let's use the equation

          y = y₀ + v₀ t - ½ g t²

When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²

         0 = y₀ + v₀t - ½ g t²

         ½ 10 t² - 50 t - 300 = 0

Let's solve the quadratic equation

         t² - 10 t - 60 = 0

         t = [10 ±√ (10² + 4 60)] / 2

         t = [10 ± 18.4] / 2

         t₁ = 14.2 s

         t₂ = -4.2 s

since time must be a positive quantity, the correctors result t = 14.2 s

the speed at this point is

         v = v₀ - g t

         v = 50 - 10 14.2

         v = -92 m / s

the sign indicates that the body is going down

b) in this case the initial velocity is vo = -50 m / s

let's calculate the velocity on the ground

    v² = v₀² - 2g (y-y₀)

    v² = 50 2 - 2 10 ((0- 300)

    v² = 3500

    v = + - 59.16 m / s

as the body is going down the correct sign is the negative

    v = - 59.16 m / s

the time it takes to arrive is

        v = v₀ - g t

        t = (v₀ - v) / g

        t = (-50 + 59.16) / 10

        t = 0.916 s

c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0

         y = y₀ + v₀ t - ½ g t²

         0 = 300 + 0 - ½ 10 t²

         t = √ (2 300/10)

         t = 7.75 s

the horizontal displacement at this time is

        x = v₀ₓ t

        x = 50 7.75

        x = 387.5 m

d) as it is thrown with an angle let's find each component of the velocities

      v₀ₓ = v₀ cos 30

      \(v_{oy}\) = v₀ sin 30

       v₀ₓ = 50 cos 30 = 43.3 m / s

       v_{oy} = 50 sin 30 = 25 m / s

we look for the time of descent

     y = y₀ + v_{oy} t - ½ g t²

     0 = y₀ + v_{oy} t - ½ g t²

     0 = 300 + 25 t - ½ 10 t²

     t² - 5t - 60 = 0

   we solve the second degree equation

     t = [5 ±√ (5² + 4 60)] / 2

     t = [5 ± 16.28] / 2

     t₁ = 10.64 s

     t₂ = -5.64 s

since the time must be positive the result is t = 10.64 s

the range on the x axis is

       x = v₀ₓ t

       x = 43.6 10.64

       x = 463.9 m

the ground speed is

      v_{y} = \(v_{oy}\) - g t

      v_{y} = 25 - 10 10.64

      v_{y} = -81.4 m / s

speed is

       v = √ (v₀ₓ² + v_{y}²)

       v = √ (43.3² + 81.4²)

       v = 92.2 m / s

Answer: static friction

Explanation:

During sliding, contact points do not get enough time to get interlocked properly. Therefore, less friction. But, when the object is at rest, the surfaces interlock well, therefore friction is more. This explains why sliding friction is less than static friction.

Answer:A.

i know its a, i did quiz

Answer:

I. 0 m/s

II. 20 m/s

III. Part BC

Explanation:

I. Determination of the initial velocity.

From the diagram given above,

The motion of the car starts from the origin. This implies that the car start from rest and as such, the initial velocity of the car is 0 m/s

II. Determination of the maximum velocity attained.

From the diagram given above, we can see clearly that the maximum velocity is 20 m/s.

III. Determination of the part of the graph that represents zero acceleration.

It important that we know the meaning of zero acceleration.

Zero acceleration simply means the car is not accelerating. This can only be true when the car is moving with a constant velocity.

From the graph given above, the car has a constant velocity between B and C.

Therefore, part BC illustrates zero acceleration.

Answer:

\(\huge\boxed{\sf d = 3590.76\ m}\)

Explanation:

Velocity = v = 11.5 m/s

Time = t = 312.24 s

Displacement = d = ?

d = v × t

d = 11.5 × 312.24

\(\rule[225]{225}{2}\)

Answer:

200 kg

Explanation:

Answer:

m= 50

Explanation:

m=f/a    this is the formula for mass

m= 25/0.5    you substitute the numbers with their variables   they you divide them to get the mass

m= 50

The solar wind, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, is a highly ionized plasma.

The solar wind, which is a stream of charged particles (plasma) emitted by the Sun, exhibits characteristics of a highly ionized plasma. As it travels from the Sun to the Earth, the solar wind encounters variations in temperature, density, pressure, and speed. In this case, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, the solar wind can be classified as a highly ionized plasma.

During a Coronal Mass Ejection (CME), eruptive phenomena on the Sun's surface cause a sudden release of a large amount of plasma and magnetic fields into space. This disturbance leads to an increase in the temperature of the solar wind to around 10^7 K and an increase in its speed to approximately 10^3 km/s. This enhanced energy and velocity result in a significant disruption of the solar wind's flow, making it a turbulent fluid.

Turbulent fluids are characterized by chaotic and irregular motion, with strong fluctuations and mixing. The increased temperature and speed during a CME generate turbulent behavior within the solar wind, leading to the disruption and mixing of plasma particles along its trajectory.

To determine the type of fluid flow, the Reynolds number (Re) is often used. It relates the flow's characteristics, such as velocity and length, to the fluid's viscosity. In this case, since the solar wind is a plasma and has negligible viscosity, the Reynolds number is extremely high, well above the turbulent threshold of 4000. Therefore, the solar wind with increased temperature and speed due to a CME can be classified as a turbulent fluid.

In summary, the solar wind, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, is a highly ionized plasma. However, during a Coronal Mass Ejection (CME), the temperature and speed of the solar wind increase significantly, leading to turbulent fluid behavior.

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Answer:

The volume of an object is a measure of the amount of space occupied by that object

Explanation:

Answer: A student might use a graduated cylinder to measure volume of a chemical solution in milliliters

Explanation:

Volume is the quantity of three-dimensional space enclosed by a closed surface,an often quantified numerically using the SI derived unit, the cubic metre.

Answer:

A. Two small objects hsgsggahahahahahshgsgegwfw

speed.

Light refracts when traveling from air into glass because of a change in light's speed.

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Answer:

5.4 watts

Explanation:

There are 3 formulas of power (P) but since the problem gives us the current (I) and voltage (V). We can use the following formula:

\( \displaystyle{ P=IV}\)

We know that I or current is 0.045 amps and the voltage is 120 volts. Hence, substitute in:

\( \displaystyle{P=0.045 \: \text{amps} \: \times \: 120 \: \text{volts}} \\ \\ \displaystyle{P=5.4 \: \text{watts}}\)

Therefore, the power produced is 5.4 watts

Answer: A.

5.4 watts

Explanation: edmentum

A bullet and a base ball

Objects with a small mass can produce a large acceleration if they experience a large force. This is described by Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass.

It's important to note that while these objects can produce a large acceleration, they can also cause significant damage or harm if not handled properly. It's important to always take appropriate safety precautions when working with objects that have the potential to produce large forces and accelerations.

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Answer:

C. An article written by a scientist

Explanation:

Research-based original articles written by a scientist can act as a primary source of information. Textbooks, dictionaries and encyclopedias are generally classified as secondary sources and are rarely primary sources.

Answer:

by using formula,

wavelength= velocity/frequency

= 120/6

= 20 meter

Ans: 20 meter

Answer:

wavelength= velocity

= 120/6= 20 meter

Explanation: