The best model to use for this scenario is a Poisson random variables with a mean arrival rate of 300 users per hour.
The Poisson distribution is commonly used to model the number of events occurring in a fixed interval of time when the events are rare and randomly distributed. In this case, we have an average arrival rate of 5 unique users per minute, which translates to 300 users per hour (5 users/minute * 60 minutes/hour). The Poisson distribution is suitable for situations where the probability of an event occurring in a given interval is constant and independent of the occurrence of events in other intervals.
Using a binomial random variable with the chance of 5 successes out of 10 trials (p = 0.5) would not accurately represent the situation because it assumes a fixed number of trials with a constant probability of success. However, in this case, the number of users per hour can vary and is not limited to a fixed number of trials.
An exponentially distributed random variable with a mean arrival rate of 60 minutes per user is not appropriate either. This distribution is commonly used to model the time between events occurring in a Poisson process, rather than the number of events itself.
Similarly, a normally distributed random variable with a mean of 300 and a standard deviation of 60 is not suitable because it assumes a continuous range of values and does not accurately capture the discrete nature of the number of users.
To learn more about variables click here: brainly.com/question/15740935
#SPJ11
A rectangle has the following vertices: A(-1, 9), B(0, 9), C(0, -8), D(-1, -8). What is the area of rectangle ABCD?
The area of the rectangle is 17 square units.
How to find the area of the rectangle?The area of a rectangle is the product between the two dimensions (length and width) of the rectangle.
Here we know that the vertices are:
A(-1, 9), B(0, 9), C(0, -8), D(-1, -8)
We can define the length as the side AB, which has a lenght:
L = (-1, 9) - (0, 9) = (-1 - 0, 9 - 9) = (-1, 0) ----> 1 unit.
And the width as BC, which has a length:
L = (0, 9) - (0, -8) = (0 - 0, 9 + 8) = (0, 17) ---> 17 units.
Then the area is:
A = (1 unit)*(17 units) = 17 square units.
Learn more about area at
https://brainly.com/question/24487155
#SPJ1
Find the length of QR
Answer:
QR = 15
Step-by-step explanation:
The product of the length of the secant segment and its external part equals the square of the length of the tangent segment.
(QR+5) *5 = 10^2
(QR+5) *5 = 100
Divide each side by 5.
(QR+5) *5/5 = 100/5
(QR+5) = 20
Subtract 5 from each side.
QR = 20-5
QR = 15
through: (-2,-3) and (5,-3)
Answer:
0, -7 or Slope is Undefined
Step-by-step explanation:
y2 - y1 / x2 - x1
(x2 - y2) (x1 - y1)
Does a two-digit number exist such that the digits sum to 9 and when the digits are reversed the resulting number is 9 greater than the original number? identify the system of equations that models the given scenario. t u = 9 10t u = 10u t â€"" 9 t u = 9 10t u = 10u t t u = 9 tu = ut 9
The system of equations that models the given scenario is t + u = 9 and 10t + u = 10u + t - 9.
What is an equation?
An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated.
The answer would be "t + u = 9 and 10t + u = 10u + t - 9".
This can be found if you replaced t with 4 and u with 5.
Adding the 2 digits would give you 9.
Use the formula "10t + u = 10u + t - 9".
Replace t and u with 4 and 5 then simplify. 10*4 + 5 = 10*5 + 4 - 9. Simplifying you'd get 45 = 54 - 9 or 45 = 45 which makes the statement true.
Thus making "t + u = 9 and 10t + u = 10u + t - 9" the answer.
To learn more about the equation from the given link
https://brainly.com/question/28218072
#SPJ4
12. List Sine, Cosine, targent cosecent secont
and contangent radies shor
Theta=4/3
No decimals
Reduce and Rationalize all
Fractions,
The identities are represented as;
sin θ = 4/5
tan θ = 4/3
cos θ = 3/5
sec θ = 5/3
cosec θ = 5/4
cot θ = 3/4
How to determine the valuesTo determine the values of the identities, we need to know that there are six trigonometric identities listed thus;
sinetangentcotangentsecantcosecantcosineFrom the information given, we have that;
The opposite side of the triangle is 4
The adjacent side is 3
Using the Pythagorean theorem, we have that;
x² = 16 + 9
x = √25
x = 5
For the sine identity, we have;
sin θ = 4/5
For the tangent identity;
tan θ = 4/3
For the cosine identity;
cos θ = 3/5
For the secant identity;
sec θ = 5/3
For the cosecant identity;
cosec θ = 5/4
For the cotangent identity;
cot θ = 3/4
Learn more about trigonometric identities at: https://brainly.com/question/22591162
#SPJ1
If I drove 15 1/2 miles in 2/5 hours, what is my average speed in miles per hour?
Answer:
(15 1/2 ) divided by 2/5= 38 3/4 miles per hour
A submarine at -144 meters dives to a depth 6 times its
original depth. What depth does the submarine dive?
Answer:
......
Step-by-step explanation:............
The figure below to the left is a graph of f(x), and below to the right is g(x).
The figure below to the left is a graph of f(x), a
(a) What is the average value of f(x) on 0≤x≤2? avg value = __________
(b) What is the average value of g(x) on 0≤x≤2? avg value = __________
(c) What is the average value of f(x)?g(x) on 0≤x≤2? avg value = _________
(d) Is the following statement true?
Average(f)?Average(g)=Average(f?g)
A. Yes
B. No
The average value of both f(x) and g(x) on 0≤x≤2 is 1/4. The average value of (f.g) on 0≤x≤2 is 0 and the statement avg(f) . avg(g) = avg(f . g) is false.
avg value of a function = 1/(b - a) ∫f(x) with limts a and b. Here a and b are the constraints under which the average has to be calculated.
a)
Hence average value of f(x) on 0≤x≤2
= 1/2 ∫f(x) with 0 and 2 as intervals
Since integration is basically the area under the curve we get
avg of f(x) = 1/2[area under curve from 0 to 1 + Area under the curve from 1 to 2]
Since from 0 to 1, the figure is a triangle and beyond that a straight line we get
1/2[1/2 X 1 X 1 + 0]
= 1/4 sq units
b)
Similarly, the average value of g(x) on 0 ≤ x ≤ 2
1/2[area from 0 to 1 + area from 1 to 2]
= 1/2[0 + 1/2]
= 1/4 sq units
c) here we need to find the average of f(x) . g(x)
Here we see that f(x) is 0 from x = 1 to x = 1 while g(x) id 0 from x = 0 from x = 1
Hence we see that on multiplying the functions, the resultant has to be a 0 function.
Hence its average value will be 0.
d)
Average(f) . Average(g) = 1/4 X 1/4
= 1/16
Average of (f.g) = 0
Hence the statement is false
To learn more about the average function visit
https://brainly.com/question/14402983
#SPJ4
Complete Question
The figure attached to the left is a graph of f(x), and below to the right is g(x).
The figure below to the left is a graph of f(x), a
(a) What is the average value of f(x) on 0≤x≤2? avg value = __________
(b) What is the average value of g(x) on 0≤x≤2? avg value = __________
(c) What is the average value of f(x) . g(x) on 0≤x≤2? avg value = _________
(d) Is the following statement true?
Average(f) . Average(g)=Average(f.g)
A. Yes
B. No
(1 point) a stone dropped into a still pond sends out a circular ripple whose radius increases at a constant rate of 2.7 ft/s. (a) how rapidly is the area enclosed by the ripple increasing when the radius is 3 feet? the area is increasing at
When the radius of the ripple is 3 feet, the area enclosed by the ripple is increasing at a rate of approximately 50.92 square feet per second.
To understand how the area of the ripple changes over time, let's start with the formula for the area of a circle:
A = πr²
where A is the area and r is the radius of the circle. Since the radius of the ripple is increasing at a constant rate of 2.7 ft/s, we can use the chain rule of differentiation to find the rate of change of the area with respect to time (t):
dA/dt = dA/dr x dr/dt
where dA/dt is the rate of change of the area, dA/dr is the derivative of the area with respect to the radius (which is 2πr), and dr/dt is the rate of change of the radius (which is given as 2.7 ft/s).
Substituting these values into the equation, we get:
dA/dt = 2πr x 2.7
Now, we can plug in the given value of the radius (r = 3 ft) to find the rate of change of the area at that point in time:
dA/dt = 2π(3) x 2.7
= 16.2π
≈ 50.92 ft²/s
To know more about area here
https://brainly.com/question/14994710
#SPJ4
a plane traveled miles with the wind in hours and miles against the wind in the same amount of time. find the speed of the plane in still air and the speed of the wind.
Let's represent the speed of the plane in still air as "p" and the speed of the wind as "w".
When the plane is traveling with the wind, its speed is (p + w) and against the wind, its speed is (p - w).
Given that it travels d1 miles with the wind in t hours and d2 miles against the wind in the same time, we can form the following equations:
d1 = t(p + w)
d2 = t(p - w)
Now, we need to solve for "p" and "w". Divide the first equation by t, and the second equation by t as well:
d1/t = p + w
d2/t = p - w
Add the two equations together to eliminate "w":
(d1/t) + (d2/t) = 2p
Solve for "p":
p = (d1 + d2) / (2t)
Now, substitute the value of "p" in either equation to solve for "w":
w = (d1/t) - p
Once you have the specific values for d1, d2, and t, plug them into the equations to find the speed of the plane in still air (p) and the speed of the wind (w).
learn more about speed here:brainly.com/question/28224010
#SPJ11
Graph 2x+y<1Y>1/2x+2
We need to graph the next given inequalities:
\(\begin{gathered} 2x+y<1 \\ \text{and} \\ y>1/2x+2 \end{gathered}\)For 2x+y<1.
We need to find the x-intercept and y-intercept
To find the y-intercept, set x=0
\(\begin{gathered} 2(0)+y<1 \\ \text{Then} \\ y<1 \\ \text{The y-intercept is the point (0,1)} \end{gathered}\)To find the x-intercept, set y=0
\(\begin{gathered} 2x+0<1 \\ \text{solve for x} \\ x<\frac{1}{2} \end{gathered}\)The symbol "<" means less than, so we get the next graph:
For the second inequality y>1/2x+2
To find the y-intercept, set x=0
plsss help me!!!!!!!!!!!!!!!!!!
Answer:
105 = (5x-70)
Step-by-step explanation:
You are trying to find x so you would have to place that in to finally get to the end where x = 5
In 1980 the population of alligators in a particular region was estimated to be 1200. In 2008 the population had grown to an estimated 7500. Using the Malthusian law for population growth, estimate the alligator population in this region in the year 2020.
The Malthusian law for population growth states that the rate of population growth is proportional to the current population size.
Mathematically, we can express this as:
dP/dt = rP
where P is the population size, t is time, and r is the growth rate.
Assuming a constant growth rate, we can integrate this equation to get:
ln(P) = rt + C
where C is an integration constant. We can solve for C using the initial population estimate:
ln(1200) = r(1980) + C
C = ln(1200) - r(1980)
Substituting the values of C and P from the second estimate (P=7500 in 2008), we get:
ln(7500) = r(2008) + ln(1200) - r(1980)
Solving for r, we get:
r = [ln(7500) - ln(1200)] / (2008 - 1980) = 0.0496
Using this value of r, we can predict the alligator population in 2020, which is 12 years after the second estimate (2008). We have:
ln(P) = rt + ln(7500)
ln(P) = 0.0496(12) + ln(7500) = 9.058
P = e^9.058 = 8656
Therefore, the estimated alligator population in the region in the year 2020 is 8656.
To learn more about Malthusian law please click on below link
https://brainly.com/question/15210976
#SPJ4
Find the sum of 2/3 and 5/12 in simplest form.
"The result is irrational because it cannot be written as the ratio of two integers and its decimal expansion does not terminate or repeat.
1) Note that we have here two irrational numbers:
\(2\sqrt[]{3}+5\sqrt[]{12}\)2) We can simplify a little bit more, the square root of 12 like this:
\(\begin{gathered} 5\sqrt[]{12} \\ 5\sqrt[]{2^2\cdot3} \\ 5\cdot2\sqrt[]{3} \\ 10\sqrt[]{3} \end{gathered}\)Note that now, we have two radicals with the same radicand. So we can proceed with that:
\(\begin{gathered} 2\sqrt[]{3}+5\sqrt[]{12} \\ 2\sqrt[]{3}+10\sqrt[]{3} \\ 12\sqrt[]{3} \end{gathered}\)3) We can now answer the 2nd part.
"The result is irrational because it cannot be written as the ratio of two integers and its decimal expansion does not terminate or repeat.
the table below shows the heights of several books. Jean stacks a dictionary on top of her novel. how high is the stack of the two books.tablenovel: 3/4dictionary:4 1/2A. between 4 1/2 and 5 inchesB between 5 1/2 and 6 inchesC. between 5 and 5 1/2 inchesFIRST TO ANSWER wILL BE MARKED BRAINLEST AND WILL GET 5 STARS
Given:
novel: 3/4
dictionary: 4 1/2
Let's first convert the two given height into similar fractions (with the sa
Can anyone give me the answers to these questions please?
Answer:
Step-by-step explanation:
1.
y=mx+b
slope=m=3 (4,2)
Hence y=3x+b (1)
We substitute valueы of x=4 and y=2 into the equation (1):
2=3(4)+b
2=12+b
2-12=12+b-12
-10=b
Thus, b=-10
Hence y=3x-10
2.
y=mx+b
slope=m=-2 (0,3)
Hence y=-2x+b (1)
We substitute valueы of x=0 and y=3 into the equation (1):
3=-2(0)+b
3=0+b
3=b
Thus, b=3
Hence y=-2x+3
3.
y=mx+b
slope=m=-1 (1,-7)
Hence y=-x+b (1)
We substitute valueы of x=4 and y=2 into the equation (1):
-7=-(1)+b
-7=-1+b
-7+1=-1+b+1
-6=b
Thus, b=-6
Hence y=-x-6
And so on ...
Write an increasing exponential equation and state the starting point (also known asthe y-intercept)
The general form of an increasing exponential equation is:
\(y=A\cdot(1+r)^{b\cdot x}\)With the following restrictions:
\(\begin{gathered} A>0 \\ r>0 \\ b>0 \end{gathered}\)Here, A is the starting point (the y-intercept), because y = A when x = 0.
a sports analyst claims that the mean batting average for teams in the american league is not equal to the mean batting average for teams in the national league because a pitcher does not bat in the american league. what hypothesis test would be used to test that batting average for teams in the american league is not equal to the batting average in the national league?
Hypothesis test used to test the batting average of the two given team national league and American league is given z-test.
As given in the question,
Given : Mean batting for American league is not equal to Mean batting for National league.
Here two teams are given representing sample size of the population.Hypothesis tests help us to make decisions or conclusion about the value of the given parameters, such as the population mean. Based on it two approaches are used for conducting a hypothesis test one is the critical value and the P-value test.If in the given data population standard deviation (σ) can be calculated, a hypothesis test used for one population mean is z-test. A z-test represents the hypothesis test which is used to test a population mean, μ, against a considered population mean, μ₀.Therefore, hypothesis test used to test the batting average of the national league and American league is given z-test.
Learn more about hypothesis test here
brainly.com/question/17099835
#SPJ4
A 35 foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground 28 feet from the base of the building. How high up the wall does the ladder reach?
Given the information on the problem, we can draw the following right triangle:
we can find how high the ladder reach using the pythagorean theorem:
\(\begin{gathered} (35)^2=(28)^2+h^2 \\ \Rightarrow h^2=(35)^2-(28)^2=1225-784=441 \\ \Rightarrow h=\sqrt[]{441}=21 \\ h=21ft \end{gathered}\)therefore, the ladder reaches 21 ft high up on the wall
10. A line has equation y=3kx−2k and a curve has equation y=x 2
−kx+2, where k is a constant. a) Find the set of values of k for which the line and curve meet at two distinet points. b) For cach of two particular values of k, the line is a tangent to the curve. Show that these two tangents meet on the x-axis. 11. The equation x 2
+px+q=0, where p and q are constants, has roots −3 and 5 . a) Find the values of p and q. b) Using these values of p and q, find the value of the constant r for which the equation x 2
+px+q+r=0 has equal roots. 12. A curve has equation y=x 2
−4x+4 and a line has the equation y=mx, where m is a constant. a) For the case where m=1, the curve and the line intersect at the point A and B. b) Find the coordinates of the mid-point of AB. c) Find the non-zero value of m for which the line is the tangent to the curve, and find the coordinates of the point where the tangent touches the curve. Answer: 1. ( 2
1
,0) 9. a) 25−(x−5) 2
2. a) (3x− 2
5
) 2
− 4
25
b) (5,25) b) − 3
1
3
10. a) k>1,k<− 2
1
a) The set of values of k for which the line and curve meet at two distinct points is k < -2/5 or k > 2.
To find the set of values of k for which the line and curve meet at two distinct points, we need to solve the equation:
x^2 - kx + 2 = 3kx - 2k
Rearranging, we get:
x^2 - (3k + k)x + 2k + 2 = 0
For the line and curve to meet at two distinct points, this equation must have two distinct real roots. This means that the discriminant of the quadratic equation must be greater than zero:
(3k + k)^2 - 4(2k + 2) > 0
Simplifying, we get:
5k^2 - 8k - 8 > 0
Using the quadratic formula, we can find the roots of this inequality:
\(k < (-(-8) - \sqrt{((-8)^2 - 4(5)(-8)))} / (2(5)) = -2/5\\ or\\ k > (-(-8)) + \sqrt{((-8)^2 - 4(5)(-8)))} / (2(5)) = 2\)
Therefore, the set of values of k for which the line and curve meet at two distinct points is k < -2/5 or k > 2.
b) To find the two values of k for which the line is a tangent to the curve, we need to find the values of k for which the line is parallel to the tangent to the curve at the point of intersection. For m to be the slope of the tangent at the point of intersection, we need to have:
2x - 4 = m
3k = m
Substituting the first equation into the second, we get:
3k = 2x - 4
Solving for x, we get:
x = (3/2)k + (2/3)
Substituting this value of x into the equation of the curve, we get:
y = ((3/2)k + (2/3))^2 - k((3/2)k + (2/3)) + 2
Simplifying, we get:
y = (9/4)k^2 + (8/9) - (5/3)k
For this equation to have a double root, the discriminant must be zero:
(-5/3)^2 - 4(9/4)(8/9) = 0
Simplifying, we get:
25/9 - 8/3 = 0
Therefore, the constant term is 8/3. Solving for k, we get:
(9/4)k^2 - (5/3)k + 8/3 = 0
Using the quadratic formula, we get:
\(k = (-(-5/3) ± \sqrt{((-5/3)^2 - 4(9/4)(8/3)))} / (2(9/4)) = -1/3 \\or \\k= 4/3\)
Therefore, the two values of k for which the line is a tangent to the curve are k = -1/3 and k = 4/3. To show that the two tangents meet on the x-axis, we can find the x-coordinate of the point of intersection:
For k = -1/3, the x-coordinate is x = (3/2)(-1/3) + (2/3) = 1
For k = 4/3, the x-coordinate is x = (3/2)(4/3) + (2/3) = 3
Therefore, the two tangents meet on the x-axis at x = 2.
Learn more about " line and curve" : https://brainly.com/question/30162650
#SPJ11
Hi, it would be a load of help if someone could explain the working for this question.
Three bricklayers Maric, Hugh and Ethan are cladding a new home. If Maric were to work alone, the job would take him 8 days to complete. If Hugh were to work alone, the job would take him 6 days to complete, and if Ethan were to work by himself, the job would take him 12 days to complete.a If the three men work together, how long will it take them to complete the job
Step-by-step explanation:
the work will be finished in 26 daysplease mark the answer as the brainliest
Two trains made the same 300 mile run. one train traveled 20 mph faster than the other. It arrived 4 hours earlier. find the speed of each train.
Let s be the speed of the slowest train and t the time it takes to travel 300 miles.
We know that:
\(s\cdot t=300\text{ miles}\)Since the second train has a speed of s+20 mph and travels the same 300 miles using 4 hours less time, then:
\((s+20mph)\cdot(t-4h)=300\text{ miles}\)Isolate t from the first equation:
\(t=\frac{300\text{ miles}}{s}\)Substitute the expression for t in the second equation to find an expression only in terms of s:
\((s+20mph)(\frac{300\text{miles}}{s}-4h)=300\text{miles}\)Use the distributive property to rewrite the product of the quantities on the left hand side of the equation:
\(\begin{gathered} (s+20mph)(\frac{300\text{miles}}{s}-4h)=300\text{miles} \\ \Rightarrow \\ (s+20\text{mph)}\cdot\frac{300\text{miles}}{s}-(s+20\text{mph)}\cdot4h=300\text{miles} \\ \Rightarrow \\ s\cdot\frac{300\text{miles}}{s}+20\text{mph}\cdot\frac{300\text{miles}}{s}-4h\cdot s-4h\cdot20\text{mph}=300\text{miles} \end{gathered}\)Simplify the products when possible. 4h times 20 mph is equal to 80 miles:
\(300\text{miles}+\frac{(20\text{mph)}(300\text{miles)}}{s}-4h\cdot s-80\text{miles}=300\text{miles}\)Substract 300 miles from both sides of the equation:
\(\frac{(20\text{mph)}(300\text{miles)}}{s}-4h\cdot s-80\text{miles}=0\)Multiply both sides by s:
\((20\text{mph)}(300\text{miles)}-4h\cdot s^2-80\text{ miles}\cdot s=0\)This is a quadratic equation for s. Write the equation in standard form:
\(-4h\cdot s^2-80\text{ miles}\cdot s+(20\text{ mph})(300\text{miles)}=0\)Use the quadratic formula to isolate s:
\(s=\frac{80\text{ miles}\pm\sqrt[]{(80\text{ miles})^2-4(-4h)(20mph)(300miles)}}{2(-4h)}\)Observe that the term -4(-4h)(20mph)(300miles) is equal to +96000 squared miles, and 80 miles squared is equal to 6400 squared miles:
\(s=\frac{80\text{ miles}\pm\sqrt[]{6400+96000}\text{ miles}}{-8h}\)Factoring out the units, we get:
\(s=\frac{80\pm\sqrt[]{102400}}{-8}\text{ mph}\)Since the square root of 102400 is equal to 320:
\(s=\frac{80\pm320}{-8}\text{mph}\)Taking the positive value of the plus/minus sign, we get:
\(s=\frac{80+320}{-8}\text{ mph}=\frac{400}{-8}\text{ mph }=-50\text{ mph}\)Taking the negative value of the plus/minus sign, we get:
\(s=\frac{80-320}{-8}\text{ mph}=\frac{-240}{-8}\text{ mph}=30\text{ mph}\)Since we first stated that s*t=300 miles and the time cannot be a negative number, the only acceptable answer is s=30 mph.
Since the velocity of the second train is s+20 mph and s=30mph, then the velocity of the second train is 50 mph.
Check the answer by verifying if all the conditions are satisfied. The problem says that the second train arrives 4 hours earlier.
The first train takes a time of 300 miles / 30 mph = 10 h.
The second train takes a time of 300 miles / 50 mph = 6h, 4 hours earlier.
Therefore, the velocities of the trains are 30 mph and 50 mph.
Jordan doesn't know how to graph y > 2x + 1 . Can you explain to him using the words below how to do it?
Vocabulary to use:
slope, y-intercept, shade above/below, and dotted/solid line
Answer:
Step-by-step explanation:
Formula: Y= mx+b
m = slope | b = y-intercept
Equation: Y>2x+1
The Y-Intercept is the (1)
Shade above the dotted line because it is >.
You always shade on the left if the left side of the equation is > than the right.
If ≥ Then the line is Solid |||| If > Then the line is dotted.
Determine whether the following statement is somedmes, always, or never true. Justify your argument. The volume of a cone with radius r and height h equals the volume of a prism with height h. If the base area of the cone is 3 times as great as the base area of the prism, then the statement trise
The statement is sometimes true. It depends on the relationship between the radius of the cone, the height of the cone, and the height of the prism.
The volume of a cone is given by the formula\(V_{cone} = (1/3)\pi r^2h\), where r is the radius of the cone and h is the height of the cone.
The volume of a prism is given by the formula\(V_{prism} = Bh\), where B is the base area of the prism and h is the height of the prism.
To determine if the statement is true, we need to compare the volumes of the cone and the prism.
If the base area of the cone is 3 times as great as the base area of the prism, it means that \(B_{cone} = 3B_{prism\).
Substituting these values into the volume formulas, we have \(V_{cone} = (1/3)\pi r^2h\) and \(V_{prism} = 3B_{prism} h\).
By comparing these formulas, we can see that the volume of the cone is indeed three times the volume of the prism, given the condition that \(B_{cone} = 3B_{prism\).
However, it is important to note that this relationship depends on the specific values of the radius and height of the cone and the height of the prism. If these values do not satisfy the condition \(B_{cone} = 3B_{prism\), then the statement would not hold true. Therefore, the statement is sometimes true, but it is not always true.
Learn more about cone here: https://brainly.com/question/16419032
#SPJ11
Find the value of x if AC = 24.
3x + 2
5x - 10
A
B
С
Enter your math answer
Answer:
x=4
Step-by-step explanation:
3x+2+5x-10=24
8x-8=24
8x=32
x=4
Answer:
x=4
Step-by-step explanation:
Let me know if you need step by step, it doesn't look like it though.
I hope this helps!!
M is directly proportional to r cubed. When r=4, M=160.
A) Work out the value of M when r=2.
B) Work out the value of r when M=540.
Answer:
A. M= 20
B. r = 6
Step-by-step explanation:
M=kr³
where k is the constant
M= 160 , r 4
160= k(4)³
k = 160/4³= 2.5
A. when r= 2 , M= kr³
M= 2.5(2)³ = 20
B. when M= 540, find r
M= kr³
r³ = M/k
r³ = 540/2.5
r³= 216
r = 6
A worker uses a forklift to move boxes that weigh either 40 pounds or 65 pounds each. Let x be the
number of 40-pound boxes and y be the number of 65-pound boxes. The forklift can carry up to
either 45 boxes or a weight of 2,400 pounds. Which of the following systems of inequalities
represents this relationship?
Answer:
40x+65y≤2,400 and x+y≤45
Step-by-step explanation:
determine the unit normal vector to the curve with vector equation \vec r \, (t) =<1^t,\ln(4/t^2), \, \ln(e/(t^4)) > r (t)=<1 t ,ln(4/t 2 ),ln(e/(t 4 ))> at the point where t=2t=2.
the unit normal vector to the curve with vector equation \vec r \, (t) =<1^t,\ln(4/t^2), \, \ln(e/(t^4)) > r (t)=<1 t ,ln(4/t 2 ),ln(e/(t 4 ))> at the point where t=2t=2 is \vec n = <0,0,-1>
A unit normal vector is a normal vector with magnitude 1, and it points in the direction that is perpendicular to the tangent to the curve at a given point.
To determine the unit normal vector to a curve, it's important to find the tangent first and then find the normal. In this case, we're looking for the unit normal vector to the curve with the vector equation \vec r (t) =<1^t,\ln(4/t^2), \ln(e/(t^4)) > at the point where t = 2.
To find the unit normal vector to the curve with the vector equation \vec r (t) =<1^t,\ln(4/t^2), \ln(e/(t^4)) > at the point where t = 2, it is necessary to find the tangent to the curve and then find the normal. This is a crucial step in understanding the geometry of curves in 3D space.
To find the tangent to the curve, we'll differentiate the vector equation with respect to t and evaluate it at t = 2. The derivative of \vec r (t) is given by:
d\vec r/dt = <1, -2t^-3, -4e^-t^-4>
So the tangent to the curve at t = 2 is:
d\vec r/dt = <1, -2(2)^-3, -4e^-2^-4> = <1, 1.5, -1.648721>
Next, we'll find the normal to the tangent by taking the cross product of the tangent with a fixed vector, for example, the unit vector i = <1,0,0>. The cross product of two vectors results in a vector that is perpendicular to both of them.
The cross product of the tangent and the unit vector i is given by:
\vec T x \vec i = <1, 1.5, -1.648721> x <1,0,0> = <0,0,-1.5>
Since the magnitude of the normal is not 1, we'll normalize it by dividing it by its magnitude:
\vec n = \vec T x \vec i / ||\vec T x \vec i|| = <0,0,-1.5> / ||<0,0,-1.5>|| = <0,0,-1>
So the unit normal vector to the curve with the vector equation \vec r (t) =<1^t,\ln(4/t^2), \ln(e/(t^4)) > at the point where t = 2 is given by:
\vec n = <0,0,-1>
This is the unit normal vector that points in the direction that is perpendicular to the tangent to the curve at t = 2. The magnitude of 1 ensures that it's a unit vector and the direction points towards the normal direction.
To know mare about unit normal vector refer here:
https://brainly.com/question/29752499#
#SPJ11
Which of the following expressions represents
the product of 3k and the sum of m and
one third of n?
Answer:
\(3k (m + \frac{1}{3}n)\)
Step-by-step explanation:
Sum of m and one - third of n is :
\(= m + \frac{1}{3}n\)
Product of 3k to the sum is :
\(=3k \times (m + \frac{1}{3}n)\)
Given Q=10L 0.75
K 0.5
,w=5,r=4 and cost constraint =60, find the values of L and K using the Lagrange method which maximize the output for the firm
The optimal values of L and K that maximize output while satisfying the cost constraint are L = 10/3 and K = 10.
Q = 10L⁰.⁷⁵K⁰.⁵, w = 5, r = 4, and the cost constraint = 60, we have to find the values of L and K using the Lagrange method which maximizes the output for the firm.
Let's formulate the Lagrange equation:
For Q = 10L⁰.⁷⁵K⁰.⁵, we have that the marginal products are
MPL = ∂Q/∂L = 7.5K⁰.⁵L⁻.²⁵ and
MPK = ∂Q/∂K = 5L⁰.⁷⁵K⁻.⁵.
The Lagrange function to maximize Q subject to the cost constraint is: L(K, λ) = 10L⁰.⁷⁵K⁰.⁵ + λ[60 - 5L - 4K]
Differentiate L(K, λ) w.r.t. L, K, and λ and set them to zero:
∂L(K, λ)/∂L = 7.5K⁰.⁵L⁻.²⁵ - 5λ = 0 ...........(1)
∂L(K, λ)/∂K = 5L⁰.⁷⁵K⁻.⁵ - 4λ = 0 ...........(2)
∂L(K, λ)/∂λ = 60 - 5L - 4K = 0 ...........(3)
From (1), we get:λ = 1.5K⁰.⁵L⁰.²⁵ .........(4)
Substituting (4) in (2), we get:
5L⁰.⁷⁵K⁻.⁵ - 6K⁰.⁵L⁰.²⁵ = 0
=> 5L⁰.⁷⁵K⁻.⁵ = 6K⁰.⁵L⁰.²⁵K/L = (5/6) L⁰.⁵/(0.5)K⁰.⁵
=> L/K = (5/6) (2) = 5/3
Now from (3), we have: 60 = 5L + 4K
Substituting L/K = 5/3 in the above equation, we get:
60 = 5 (5/3) K + 4K
Simplifying this equation, we get:
K = 6L = 10K = 10
From the above solutions, we can conclude that the values of L and K using the Lagrange method which maximizes the output for the firm are:
L = 5K/3 = 10/3 and K = 10.
You can learn more about constraint at: brainly.com/question/17156848
#SPJ11