_ May Occur if the chosen sample is too small for a study.
a) Participation Bias
b) response Bias
c)non-response Bias
d) sampling Bias
e) Reasearcher Bias

The most reasonable temperature for a snowy day is given as follows:

C. -6°C

Considering that it snows, the temperature is either negative or very low positive, as snow only happens on temperatures close to freezing (like 2º C) or negative.

17ºC and 26ºC are far from cold enough to generate snow, hence the most reasonable temperature for a snowy day is given as follows:

C. -6°C

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Answer:

The rate at which the distance from the goose to the pond is increasing is approximately 42.875 feet per second.

Step-by-step explanation:

We assume that goose is flying at constant velocity. After reading carefully the statement of the problem, we create the following geometrical diagram, which is included at the end of this explanation and represents the following Pythagorean identity:

\(x^{2}+y^{2} = r^{2}\) (Eq. 1)

Where:

\(x\) - Horizontal distance of the goose from pond, measured in feet.

\(y\) - Vertical distance of the goose from pond, measured in feet.

\(r\) - Resultant distance of the goose from pond, measured in feet.

We find the rate of change in time at which resultant distance is increasing by differentiating on (Eq. 1):

\(2\cdot x \cdot \dot x + 2\cdot y \cdot \dot y = 2\cdot r \cdot \dot r\)

\(x\cdot \dot x + y\cdot \dot y = r\cdot \dot r\)

\(\dot r = \frac{x\cdot \dot x + y\cdot \dot y}{\sqrt{x^{2}+y^{2}}}\) (Eq. 2)

Where:

\(\dot x\) - Rate of change of horizontal distance, measured in feet per second.

\(\dot y\) - Rate of change of vertical distance, measured in feet per second.

\(\dot r\) - Rate of change of resulting distance, measured in feet per second.

If we know that \(x = 500\,ft\), \(y = 300\,ft\), \(\dot x = 50\,\frac{ft}{s}\) and \(\dot y = 0\,\frac{ft}{s}\), the rate at which the distance from the goose to the pond is increasing is:

\(\dot r = \frac{(500\,ft)\cdot \left(50\,\frac{ft}{s}\right)+(300\,ft)\cdot \left(0\,\frac{ft}{s} \right) }{\sqrt{(500\,ft)^{2}+(300\,ft)^{2}}}\)

\(\dot r \approx 42.875\,\frac{ft}{s}\)

The rate at which the distance from the goose to the pond is increasing is approximately 42.875 feet per second.

The intervals of each behavior of the function are given as follows:

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Answer:

13.6

Step-by-step explanation:

5 divided into 68 is basically the same thing as 68 divided by 5.

68/5 is equal to 13.6

By looking at the matrix, we can say that matrix A is skew-symmetric. (option b)

To check whether a matrix is skew-symmetric, we need to verify if it satisfies the condition \(A^T\) = -A.

Taking the transpose of matrix A, we get:

\(A^T\) =  | 0 2 -3 |

         | -2 0 -1 |

         | 3 1 0 |

Subtracting A from \(A^T\), we get:

\(A^T\) - A = | 0 2 -3 |             | 0 -2 3 |

             | -2 0 -1 |      -       | 2 0 1 |

              | 3 1 0 |               | -3 -1 0 |

=      | 0 4 -6 |

       | -4 0 -2 |

       | 6 2 0 |

Since \(A^T\) - A is equal to the negative of A, we can conclude that matrix A is skew-symmetric. This means that the elements on the main diagonal are all zero, and the elements below the main diagonal are the negatives of the corresponding elements above the main diagonal.

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Answer:

nice hand writing

Step-by-step explanation:

ANSWER

$166.67

EXPLANATION

We have that the equation that Luis has used to represent the given situation is:

4(t + 25) = 4(t + 50) - 4(0.15t)

where t = price per ticket for which the two airlines have the same total cost

From the question, we have to find the ticket price, t.

We do that by simplifying the equation given.

That is:

4(t + 25) = 4(t + 50) - 4(0.15t)

Expand the bracket:

4t + 100 = 4t + 200 - 0.6t

Collect like terms:

4t - 4t + 0.6t = 200 - 100

0.6t = 100

t = 100 / 0.6

t = $166.67

That is the ticket price that satisfies the situation.

Answer:

Step-by-step explanation:

6) We would like to find out the area of the following arcs with ,

As we know that the area of sector is given by ,

\(\longrightarrow Area =\dfrac{\theta}{360^o}\times \pi r^2 \)

Here on substituting the respective values , we have ,

\(\longrightarrow Area =\dfrac{75}{360}\times \dfrac{22}{7}\times 16m \times 16m \\\)

Simplify,

\(\longrightarrow \underline{\underline{Area =167.61 \ m^2}}\)

8) Again we would like to find out the area with ,

Firstly we know that ,

\(\longrightarrow \pi \ rad = 180^o\)

So ,

\(\longrightarrow 2\pi rad = 360^o \)

Therefore , the formula becomes ,

\(\longrightarrow Area =\dfrac{\theta}{2\pi}\times πr^2 \)

Substitute ,

\(\longrightarrow Area =\dfrac{19\pi}{12\times 2\pi}\times \pi r^2\\ \)

So that,

\(\longrightarrow Area =\dfrac{19}{24}\times \dfrac{22}{7}\times 14ft \times 14ft \\ \)

Simplify,

\(\longrightarrow \underline{\underline{ Area = 487.66 ft^2 }}\)

And we are done !

#1

Area

#2

Area

Answer:

\(h = 7.69cm\)

Step-by-step explanation:

Given

\(Volume = 455cm^3\)

\(l = h\)

Where:

\(h \to height\)

\(l \to base\ length\)

Required

The height

The volume is calculated as:

\(Volume = l^2 * h\)

This gives:

\(Volume = h^2 * h\)

\(Volume = h^3\)

Rewrite as:

\(h^3 =Volume\)

So, we have:

\(h^3 = 455cm^3\)

Take cube roots

\(h = \sqrt[3]{455cm^3}\)

\(h = 7.69cm\) --- approximated

Answer:

1/9

Step-by-step explanation:

8/9 ÷ 8/1

8/9 x 1/8 = 8/72

The GCF for 8 and 72 is 8

\(\frac{8}{72}\)÷\(\frac{8}{8}\)=\(\frac{1}{9}\)

Answer: 1/9

see below for work ⤵

The length of the arc CD is 14.13 centimeters.

Remember that for an arc defined by an angle a in a circle of radius R, the length of the arc is given by:

L  = (a/360°)*2*pi*R

Where pi = 3.14

Here the angle is a = 45°

And R = 18cm, so we can replace that in the formula above to find the length.

L = (45°/360°)*2*3.14*18cm = 14.13cm

That is the length of the arc CD.

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The answer of the given question based on the percent is , 20.49 trillion is about 52.84% larger than 13.4 trillion.

Percentage is a way of expressing a quantity or value as a fraction of 100. It is a widely used method for describing proportions, rates, changes, and comparisons in various fields such as mathematics, economics, statistics, science, and everyday life. The term "percent" literally means "per hundred", and it is represented by the symbol "%". To convert a number to a percentage, we multiply it by 100 and add the symbol "%".

To find the percent larger that 20.49 trillion is to 13.4 trillion, we can use the following formula:

Percent change = (New value -Old value) /Old value * 100%

Plugging in the values we have:

Percent change = (20.49 trillion - 13.4 trillion) / 13.4 trillion * 100%

= 7.09 trillion / 13.4 trillion * 100%

= 52.84%

Therefore, 20.49 trillion is about 52.84% larger than 13.4 trillion.

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Answer: 12250 Grams

Step-by-step explanation:

1 Kilogram = 1000 grams.

12 Kilograms x 1000 Grams = 12000 Grams.

1/4 = 0.25

0.25 Kilograms x 100 Grams = 250 Grams

12000 + 250 = 12250.

Answer: 12250 Grams.

Answer:

2251.86

Step-by-step explanation:

hope this works

The multiplication is gives 2400.

Significant figures are the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value.

Given number:

288.7 x 7.8

Now, rounding to 1 significant figure

288. 7 = 300

7.8 = 8

So, the multiplication is as follows:

=300* 8

= 2400

Hence, the multiplication is 2400.

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The approximate 90% confidence interval for this situation is given as follows:

(70244, 70632).

The bounds of the confidence interval are given by the rule presented as follows:

\(\overline{x} \pm z\frac{\sigma}{\sqrt{n}}\)

In which:

From the z-table, the critical value for a 95% confidence interval is given as follows:

z = 1.645.

The parameters are given as follows:

\(\overline{x} = 70438, \sigma = 645.3, n = 30\)

The lower bound of the interval is given as follows:

\(70438 - 1.645 \times \frac{645.3}{\sqrt{30}} = 70244\)

The upper bound of the interval is given as follows:

\(70438 + 1.645 \times \frac{645.3}{\sqrt{30}} = 70632\)

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\(\huge \bf༆ Answer ༄\)

Let's solve ~

As per the given function rule , y = -6x + 1 , the values will be 31, 7, 1, -5 -5 , 1, 1, -6X+1, -17.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a connection between inputs in which each input is connected to precisely one output. Each function has a range, codomain, and domain. The usual way to refer to a function is as f(x), where x is the input. A function is often represented as y = f. (x).

The relationship between the input or domain and the output or range is known as the function rule. If and only if there is a single value in the range for each domain value, a relation is a function.

As per the given function rule in the question i.e y = -6x + 1

X                         Y

-5                         31

-1                          7

0                           1

1                           -5

1                           -5

0                            1

0                            1

X                   -6X +1

3                         -17

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0.4286 is not rounded to hundredth rounded is 0.44

I think the answer is 0.43

The value of x would be 21 if the angle between one of the sides and the bisector measures (2x+3)°.

An angle bisector is defined as a line that divides an angle into two equal angles.

Draw the given angle first, then cut it in half, and then draw the angle's bisector.

A right angle is bisected by a ray. The angle between one of the sides and the bisector measures (2x+3)°

We have to determine the value of x

As per the given condition, the required solution would be:

⇒ (2x+3) = 90/2

⇒ (2x+3) = 45

⇒ 2x = 42

⇒ x = 21

Therefore, the value of x would be 21.

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The rate (in km/h) at which the distance from the plane to the radar station is increasing a minute later is 0 km/h (rounded to the nearest whole number).

To solve this problem, we can use the concepts of trigonometry and related rates.

Let's denote the distance from the plane to the radar station as D(t), where t represents time. We want to find the rate at which D is changing with respect to time (dD/dt) one minute later.

Given:

The plane is flying with a constant speed of 360 km/h.

The plane passes over the radar station at an altitude of 1 km.

The plane is climbing at an angle of 30°.

We can visualize the situation as a right triangle, with the ground radar station at one vertex, the plane at another vertex, and the distance between them (D) as the hypotenuse. The altitude of the plane forms a vertical side, and the horizontal distance between the plane and the radar station forms the other side.

We can use the trigonometric relationship of sine to relate the altitude, angle, and hypotenuse:

sin(30°) = 1/D.

To find dD/dt, we can differentiate both sides of this equation with respect to time:

cos(30°) * d(30°)/dt = -1/D^2 * dD/dt.

Since the plane is flying with a constant speed, the rate of change of the angle (d(30°)/dt) is zero. Thus, the equation simplifies to:

cos(30°) * 0 = -1/D^2 * dD/dt.

We can substitute the known values:

cos(30°) = √3/2,

D = 1 km.

Therefore, we have:

√3/2 * 0 = -1/(1^2) * dD/dt.

Simplifying further:

0 = -1 * dD/dt.

This implies that the rate at which the distance from the plane to the radar station is changing is zero. In other words, the distance remains constant.

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Answer:

  (a)  twenty-eight ninths, square root of nineteen, cube root of eighty-eight

Step-by-step explanation:

When ordering a list of numbers by hand, it is convenient to convert them to the same form. Decimal equivalents are easily found using a calculator.

The attachment shows the ordering, least to greatest, to be ...

  \(\dfrac{28}{9}.\ \sqrt{19},\ \sqrt[3]{88}\)

__

Additional comment

We know that √19 > √16 = 4, and ∛88 > ∛64 = 4, so the fraction 28/9 will be the smallest. That leaves us to compare √19 and ∛88, both of which are near the same value between 4 and 5.

One way to do the comparison is to convert these to values that need to have the same root:

  √19 = 19^(1/2) = 19^(3/6) = sixthroot(19³)

  ∛88 = 88^(1/3) = 88^(2/6) = sixthroot(88²)

The roots will have the same ordering as 19³ and 88².

Of course, these values can be found easily using a calculator, as can the original roots. By hand, we might compute them as ...

  19³ = (20 -1)³ = 20³ -3(20²) +3(20) -1 = 8000 -1200 +60 -1 = 6859

  88² = (90 -2)² = 90² -2(2)(90) +2² = 8100 -360 +4 = 7744

Then the ordering is ...

  28/9 < 19³ < 88²   ⇒   28/9 < √19 < ∛88

Answer:

the ordering is

28/9 < 19³ < 88²   ⇒   28/9 < √19 < ∛88

Step-by-step explanation:

The anwser would be 33 because 33=33 as an absolute value

The absolute value of a number is how far away the number is from zero. The absolute value is ALWAYS positive.

What is the absolute value of -33?

The negative version of the number is also | 33 |

Answer:

All conjecture postulates and theorems prove a logical argument.

This is my opinion

Step-by-step explanation:

Theorems are the basics of mathematics.

They are verified multiple times in past.

They are certified by all famous mathematicians of world.

Some famous theorems are

Answer:1. 25

               2.  16,25 (16 and a 1|4)

               3. 16

Step-by-step explanation

proportion e.g. 8- 10

                           20- more

                           20|8 * 10

                            = 25

(A) The range and IQR for boxplot 1 is 10 and 6 respectively.

(B) The range and IQR for boxplot 2 is 12 and 7 respectively.

The interquartile range defines the difference between the third and the first quartile.

The formula for the interquartile range is given below.

Interquartile range = Upper Quartile – Lower Quartile = Q­3 – Q­1

The range is the difference between the lowest and highest values.

The formula for the interquartile range is given below.

Range = Maximum – Minimum

(A) For boxplot 1, we need to find the range and IQR from the given data set.

So, let 34 be the maximum and 24 be the minimum.

\(\text{Range}=\sf 34-24\)

\(\text{Range}=\sf10\)

Therefore, the range is 10.

Now time to find the IQR.

So, let 33 be Q3 and 27 be Q1.

\(\text{IQR}=\sf 33-27\)

\(\text{IQR}=\sf 6\)

Therefore, the IQR is 6.

(B) Now for boxplot 2, we will do the same thing as from part A.

Let's find the range.

So, let 24 be the maximum and 12 be the minimum.

\(\text{Range}=\sf 24-12\)

\(\text{Range}=\sf12\)

Hence, the range is 12.

Now for the IQR.

So, let 22 be Q3 and 15 be Q1.

\(\text{IQR}=\sf 22-15\)

\(\text{IQR}=\sf 7\)

Hence, the IQR is 7.

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Answer:

20x+40

Step-by-step explanation:

Hey there! first, we multiply 5 x 4x = 20x. then we multiply 5 x 8 = 40

now we add them but in the 20x there is x so we can't add them but we can write them as 20x + 40

Answer:

\(\huge\boxed{\sf{20x+40}}\)

Step-by-step explanation:

Hello.

The Distributive Property states that

a(b+c)=ab+ac \(\mapsto\) we multiply a times b and c

Now, simplify the given expression:

5(4x+8)

20x+40

I hope it helps.

Have a great day.

\(\boxed{imperturbability}\)

Answer: L is the answer for the question

Step-by-step explanation: