Manuel's company uses shipping crates with dimensions 3 m x 3 m x 7 m. He has to ship 25 000 boxes with dimensions 10 cm x 10 cm x 20 cm. Calculate whether one crate will be enough.

Answer:

A

Step-by-step explanation:

the order of letter should resemble the same shape

Answer:

Below

Step-by-step explanation:

e^(-kt) = 1/2     when t = 11.43

so  k = .060642797

e^ (- .060642797 * 1) = .9411  <====   is left after one year

             which means the decay in one year is

                  1 - .9411 = .05884 = 5.88% per year

Answer:

Volume of the given pyramid = 1122.37 cubic feet

Step-by-step explanation:

Volume of the regular hexagonal pyramid = \(\frac{1}{3}(\text{Area of the base})(\text{Base})\)

Measure of internal angle of a polygon = \(\frac{(n-2)\times 180}{n}\)

Here, n = number of sides of the polygon

For a hexagon, n = 6

Measure of interior ∠C = \(\frac{(6-2)\times 180}{6}\)

                                       = 120°

Measure of ∠BCD = \(\frac{120}{2}\)

                              = 60°

By applying tangent rule in ΔCED,

tan(∠ECD) = \(\frac{\text{Opposite side}}{\text{Adjacent side}}\)

tan(60°) = \(\frac{DE}{CE}\)

\(\sqrt{3}=\frac{DE}{6}\)

DE = \(6\sqrt{3}\) feet

And cos(60°) = \(\frac{EC}{CD}\)

\(\frac{1}{2}=\frac{6}{CD}\)

CD = 12 feet

Area of ΔBCD = \(\frac{1}{2}(\text{Base})(\text{Height})\)

                        =  \(\frac{1}{2}(6\sqrt{3})(12)\)

                        = \(36\sqrt{3}\) feet

Area of hexagonal Base of the pyramid = \(6(36\sqrt{3})\)

                                                                  = 216√3 square feet

Since, lateral height of the pyramid (AC) = 15 feet

By applying Pythagoras theorem in ΔADC,

AC² = AD² + CD²

(15)² = AD² + (12)²

AD = \(\sqrt{225-144}\)

AD = 9 feet

Volume of the given pyramid = \(\frac{1}{3}(216\sqrt{3})(9)\)

                                                 = 648√3 cubic feet

                                                 = 1122.37 cubic feet

Answer:

x = 5

Step-by-step explanation:

2x + 3 = 4x - 7

Subtract 2x from both sides and you're left with 3 = 2x - 7

add 7 to both sides then you have 10 = 2x

divide both sides by 2 and you get x = 5

Answer:

x=5. So, PQ=RS, PS=QR, RP=PR[common side]

Step-by-step explanation:

4x-7=2x+3

x=5

The decision-maker is willing to pay a risk premium of $250 to eliminate the risk of lottery p', and a risk premium of $500 to eliminate the risk of lottery p?. Therefore, the decision-maker prefers lottery p?.

The decision-maker's utility function suggests that they have a logarithmic utility index, v(r) = In(2). To calculate the risk premia, we compare the expected utilities of the lotteries. For lottery p', the expected utility is E[v(p')] = (1/2) * v(-1000) + (1/2) * v(0) = (1/2) * In(2) + (1/2) * In(2) = In(2). For lottery p?, the expected utility is E[v(p?)] = v(-500) = In(2). Since both lotteries have the same expected utility, the decision-maker is indifferent between them in terms of expected utility.

However, the decision-maker is risk-averse, which means they prefer to eliminate risk when possible. To eliminate the risk of lottery p', the decision-maker is willing to pay a risk premium of $250 (which is half the difference between the potential losses of $1000 and $0). On the other hand, to eliminate the risk of lottery p?, the decision-maker is willing to pay a risk premium of $500 (the full potential loss amount).

Therefore, the decision-maker prefers lottery p? as they are willing to pay a higher risk premium to eliminate its risk.

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The Solution.

The given equation is

To determine the slope of the line, we shall express the equation in the y =mx + c , where m is the slope.

The slope of the given equation is 2/3.

But to obtain the slope a line that is perpendicular to the given line, we use the formula below:

Sum of the infinite geometric series = 79/9

A geometric series, or the first few terms of a geometric sequence, are the sum of an infinite number of terms with a constant ratio between them in mathematics.

Given Geometric sequences,

0.79, 0.079, 0.0079, 0.00079, 0.000079

so, the geometric series is:

0.79 + 0.079 + 0.0079 + 0.00079 + 0.000079 +........

The first term of given geometric series is 0.79

The second term of given series is 0.079

Therefore, the common ration is= 0.079/0.79 = 1/10

The Sum of infinite geometric series is given by, S= a/(1-r)

a here denotes the first term of the series

r denotes the common ration

so,

S = 0.79/{1-(1/10)}

or, S = 0.79/(9/10)

0r, S = 0.79 * (10/9)

0r, S = 79/9

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Answer:

x = {2,3,4}    (if x can only be positive whole numbers)

Step-by-step explanation:

For a triangle exists, the side lengths of the triangle must be such that the sum of the two shorter sides must be greater than the third side.

This also is equivalent to any two sides must have a sum greater than the third side.

So

7+10 > x^2, => x^2 < 17 => x < sqrt(17)     (maximum)

7+x^2 > 10, => x^2 >3 => x > sqrt(3)

Therefore

sqrt(3) < x < sqrt(17)

If x must be an integer,

2< x < 4, or x = {2,3,4}

The best answer regarding the effects of carbon monoxide is option c, CO results in less oxygen loading hemoglobin but unloading is not changed.

Carbon monoxide binds up more tightly to the hemoglobin as compared to the oxygen molecules. This reduces the oxygen-carrying capacity of the blood and results in less oxygen loading onto hemoglobin.

However, once oxygen is already bound to hemoglobin, CO does not significantly affect its release or unloading. Therefore, option c is the most accurate statement among the given choices.

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a. This equation states that the ending inventory for period j (sj) is equal to the beginning inventory from the previous period (sj-1) plus the production quantity in period j (xj), minus the demand in period j (dj).

b. This constraint ensures that the production quantity in period j (xj) does not exceed the production capacity for that period (Cj).

c. This constraint ensures that the ending inventory for period j (sj) is greater than or equal to the required inventory level for that period (Ij).

a. The mathematical relationship or model that shows ending inventory as a function of beginning inventory, production, and demand can be represented as:

sj = sj-1 + xj - dj

This equation states that the ending inventory for period j (sj) is equal to the beginning inventory from the previous period (sj-1) plus the production quantity in period j (xj), minus the demand in period j (dj).

b. If the production capacity for period j is given by Cj, the constraint that should be added is:

xj ≤ Cj

This constraint ensures that the production quantity in period j (xj) does not exceed the production capacity for that period (Cj).

c. If inventory requirements for period j mandate an ending inventory of at least Ij, the constraint that should be added is:

sj ≥ Ij

This constraint ensures that the ending inventory for period j (sj) is greater than or equal to the required inventory level for that period (Ij).

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Part a: The expression that represents the area of the rectangle is A = (3x + 5)(6x + 11). To calculate the area, we must multiply the two sides of the rectangle together. The length of the rectangle is 3x + 5 units and the width of the rectangle is 6x + 11 units. Therefore, the area is (3x + 5)(6x + 11).

Part b: The degree of the expression obtained in part a is 2 and the classification is a binomial.

Part c: The closure property for polynomials states that the result of combining two polynomials is also a polynomial. In part a, we combined two polynomials, 3x + 5 and 6x + 11, to form the expression (3x + 5)(6x + 11). This expression is also a polynomial, demonstrating the closure property for polynomials. The closure property for polynomials allows us to combine two polynomials and still have a polynomial as the result. This is important in mathematics because it allows us to simplify equations and solve problems more quickly and efficiently.

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The measures of the angles are

1. Angle TLN, MZQ and NLM

The angles TLN and NLM are supplementary angles

So, we have

TLN + NLM = 180

This gives

3x - 18 + y = 180

Also, we have

TLN + MZQ = 180

So, we have

3x - 18 + 5x + 14 = 180

Evaluate the like terms

8x -4 = 180

This gives

8x = 184

Divide

x = 23

Substitute x = 23 in 3x - 18 + y = 180

3 x 23 - 18 + y = 180

Evaluate

51 + y = 180

So, we have

y = 129

The above computations imply that:

TLN = 3 x 23- 18 = 51 degrees

NLM = y = 129 degrees

MZQ = 5 x 23 + 14 = 129 degrees

2. Angle JZQ and TLN

The above means that

JZQ = TLN

So, we have

9x + 9 = 8x + 19

Evaluate

x = 10

So, we have

JZQ = TLN = 9 * 10 + 9

JZQ = TLN = 99 degrees

3. Angle ZMR, LMO and LMR

The angles ZMR and LMO are congruent angles

So, we have

ZMR = LMO

This gives

x + 14 = 2x - 6

Evaluate

x = 20

Also, we have

LMR + LMO = 180

So, we have

y + 2x - 6 = 180

y + 2 x 10 - 6 = 180

y + 14 = 180

So, we have

y = 166

The above computations imply that:

LMO= ZMR = 20 + 14 = 34 degrees

LMR = y = 166 degrees

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The first derivatives for the given functions are:

For \(y = 3x^2 + 5x + 10,\) the first derivative is dy/dx = 6x + 5.

For  \(y = 100200x + 7x,\) the first derivative is dy/dx = 100207.

For \(y = ln(9x^4),\) the first derivative is dy/dx = 4/x.

To find the first derivative for each of the given functions, we'll use the power rule, constant rule, and chain rule as needed.

For the function\(y = 3x^2 + 5x + 10:\)

Taking the derivative term by term:

\(d/dx (3x^2) = 6x\)

d/dx (5x) = 5

d/dx (10) = 0

Therefore, the first derivative is:

dy/dx = 6x + 5

For the function y = 100200x + 7x:

Taking the derivative term by term:

d/dx (100200x) = 100200

d/dx (7x) = 7

Therefore, the first derivative is:

dy/dx = 100200 + 7 = 100207

For the function \(y = ln(9x^4):\)

Using the chain rule, the derivative of ln(u) is du/dx divided by u:

dy/dx = (1/u) \(\times\) du/dx

Let's differentiate the function using the chain rule:

\(u = 9x^4\)

\(du/dx = d/dx (9x^4) = 36x^3\)

Now, substitute the values back into the derivative formula:

\(dy/dx = (1/u) \times du/dx = (1/(9x^4)) \times (36x^3) = 36x^3 / (9x^4) = 4/x\)

Therefore, the first derivative is:

dy/dx = 4/x

To summarize:

For \(y = 3x^2 + 5x + 10,\) the first derivative is dy/dx = 6x + 5.

For y = 100200x + 7x, the first derivative is dy/dx = 100207.

For\(y = ln(9x^4),\) the first derivative is dy/dx = 4/x.

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Answer:

y-4=3(x+2)

Step-by-step explanation:

Plug into point slope equation with slope m and point (x1,y1)

y-y1=m(x-x1)

y-4=3(x+2)

the probability of choosing a number with a first digit of 6 and a second digit of 4 from the interval (0,1) is 1/90, which is approximately 0.011 or 1.1%.

The probability of choosing a number with a first digit of 6 and a second digit of 4 from the interval (0,1) can be calculated using the concept of uniform distribution.

Since the interval (0,1) contains an infinite number of possible outcomes, we can think of the probability of selecting a number with a first digit of 6 and a second digit of 4 as the ratio of the number of outcomes that satisfy this condition to the total number of possible outcomes.

The first digit of a number between 0 and 1 can be any of the digits 1 to 9, with equal probability. Therefore, the probability of selecting a number with a first digit of 6 is 1/9.

Similarly, the second digit of a number between 0 and 1 can also be any of the digits 0 to 9, with equal probability. Therefore, the probability of selecting a number with a second digit of 4 is 1/10.

Since the selection of the first digit and the second digit are independent events, we can calculate the joint probability of selecting a number with a first digit of 6 and a second digit of 4 by multiplying the individual probabilities:

P(First digit is 6 and second digit is 4) = P(First digit is 6) x P(Second digit is 4)

P(First digit is 6 and second digit is 4) = (1/9) x (1/10)

P(First digit is 6 and second digit is 4) = 1/90

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Answer:

|a|=42+72+(−4)2−−−−−−−−−−−−−√

=16+49+16−−−−−−−−−−√

=81−−√

=9

Step-by-step explanation:

Find the dot product

a⋅b=(4,7,−4)⋅(3,−1,1)

=4⋅3+7⋅(−1)+(−4)⋅1

=12−7−4

=1

Find the magnitude of a

|a|=42+72+(−4)2−−−−−−−−−−−−−√

=16+49+16−−−−−−−−−−√

=81−−√

=9

Scalar projection of b on to a is given by

compab=a⋅b|a|

Substitute the values of the a⋅b and |a|, to get

compab=19

Vector projection of b onto a is given by

projab=[compab]a|a|

Substitute the values of the compab and |a|, to get

projab=[19](4,7,−4)9=(481,781,−481)

Result: compab=19projab=(481,781,−481)

Answer:

4 pack priced at £2.04 is the better pack

Step-by-step explanation:

2.04/4=£0.51 per roll

4.68/9=£0.52 per roll

I think the 9pack is better

I hope it was helpful to you

Answer:

20

Step-by-step explanation:

20x1

=20

10+10

=20

15+5

=20

Answer:

¿Qué trabajo te interesa más? ¿Por qué?

ACADEMIA DE IDIOMAS busca profesor de inglés. Se requiere diploma y experiencia mínima de. Horas flexibles. Escribir a

ZOOLÓGICO necesita persona responsable para cuidar y dar de comer a los animales. Debe ser paciente y enérgica. Llamar  

EMPRESA DE TRANSPORTE necesita conductores de camiones con conocimientos básicos de mecánica. Posibilidad de trabajar tiempo completo.  peluquera con experiencia. Se requiere una persona simpática, creativa e interesada en la moda.Calle de las Terrazas, Cuzco.

Step-by-step explanation:

The initial speed of the ball traveling when it leaves the bat is  95.9 mph and the angle at it initially forms with the horizon is  39.49°.

A parallelogram is a four-sided shape having two sets of parallel sides, with the opposite sides being equal in length and the angles opposite each other being equal. A triangle is a three-sided shape with three angles, the sum of which adds up to 180 degrees.

∠x + ∠y + ∠z = 180°

The baseball was hit by the batter with a starting speed of 74 miles per hour horizontally and a lift of 61 miles per hour. The initial speed

v = √(v(h)² + v(c)²)

v = √((74)² + (61)²)

v = 95.9 mph

The angle made will be -

Ф = tan⁻¹(61/74) = 39.49°

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Tammy received 19 phone calls on the first evening, 13 phone calls on the second evening, and 76 phone calls on the third evening.

Let's use algebra to solve the problem.

Let x be the number of phone calls Tammy received on the first evening.

According to the problem, she received 6 fewer calls on the second evening than on the first evening. This means that the number of phone calls she received on the second evening is x - 6.

The problem also states that she received 4 times as many calls on the third evening as she did on the first evening. This means that the number of phone calls she received on the third evening is 4x.

We know that Tammy received a total of 108 phone calls over the three evenings. We can use this information to set up an equation:

x + (x - 6) + 4x = 108

Simplifying the equation:

6x - 6 = 108

Adding 6 to both sides:

6x = 114

Dividing both sides by 6:

x = 19

Therefore, Tammy received 19 phone calls on the first evening, 13 phone calls (19 - 6) on the second evening, and 76 phone calls (4 x 19) on the third evening.

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Complete question is:

Over the last three evenings, Tammy received a total of 108 phone calls at the call center. The second evening, she received 6 fewer calls than the first evening. The third evening, she received 4 times as many calls as the first evening. How many phone calls did she receive each evening?

B) The alpha value of the reliability coefficient is one way to establish the validity of a questionnaire.

In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign.

Here,

The alpha value of the reliability coefficient, also known as Cronbach's alpha, measures the internal consistency of a questionnaire. It indicates how well the items on the questionnaire are related to each other and form a consistent measure of the concept being assessed. A high alpha value indicates that the items on the questionnaire are measuring the same underlying concept and that the questionnaire is reliable.

Correlation between the score on the questionnaire and another measure of the same concept (Option A) and consistency by which multiple subjects are able to complete the questionnaire without error (Option D) can also provide information about the reliability of a questionnaire.

The alpha value of the reliability coefficient is one way to establish the validity of a questionnaire.

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The volume of the  is right triangular prism is   600 cubic feet.

In a right triangular prism, the area of the triangular base is 50 square feet, and the height of the prism is 12 feet. To find the volume of the prism, we can use the formula:

Volume = Base Area × Height

Step 1: Identify the base area, which is given as 50 square feet.
Step 2: Identify the height of the prism, which is given as 12 feet.
Step 3: Multiply the base area by the height to find the volume.

Volume = 50 square feet × 12 feet = 600 cubic feet

So, the volume of the right triangular prism is 600 cubic feet.

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Step-by-step explanation:

125 -30 = 95..

125 - 60 = 65

Answer:

It's 3 I think

Make me brainly

Answer:

x = -1

Step-by-step explanation:

6 -8x = 6x -9x +11

Combine like terms

6 -8x = -3x+11

Add 8x to each side

6-8x +8x = -3x+8x +11

6 = 5x+11

Subtract 11 from each side

6-11 = 5x+11-11

-5 =5x

Divide each side by 5

-5/5 = 5x/5

-1 =x

Answer:

j'ai écrit ci-dessous

Step-by-step explanation:

Salut, j'utilise un traducteur, mais revenons à votre question

Je ne suis donc pas sûr de la question a, mais j'essaierai d'y répondre plus tard.

Pour la question b, il a utilisé la formule "a-b" je pense. C'est déjà indiqué dans le tableau. D'accord, je vais essayer de trouver la question a maintenant !

Edit

salut je suis de retour! donc d'après mes découvertes, le pgcd (si pgcd est le plus grand diviseur commen) serait 207. C'est parce que vous pouvez diviser les deux par 207, et une fois que vous le faites, vous ne pouvez plus le diviser par des nombres égaux.

2277/207 = 11

1449/207 = 7

J'espère que cela t'aides!

The average number of trees planted by students at Arlington High School decreased by 20% when comparing the first planting session (5 trees per participant) to the upcoming session (4 trees per participant).

To calculate the percent of decrease, we can use the following formula:

Percent decrease = ((Initial value - Final value) / Initial value) * 100

For the first planting session, the initial value is 5 trees per participant, and for the upcoming session, the final value is 4 trees per participant. Plugging these values into the formula:

Percent decrease = ((5 - 4) / 5) * 100 = (1 / 5) * 100 = 20%

Therefore, the percent of decrease in the average number of trees planted is 20%. This means that the average number of trees planted per participant decreased by 20% from the first planting session to the upcoming session

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The equivalent system of first-order differential equations is:

To transform the given differential equation into an equivalent system of first-order differential equations, we can introduce new variables. Let's define:

x1 = x

x2 = x'

x3 = x''

x4 = x'''

Now, we can rewrite the original equation in terms of these new variables:

x4 - 5x'' - 3x' + 53sin(3t) = 0

Replacing the derivatives with the new variables, we have:

x4 = x4

x3 = x'''

x2 = x'

x1 = x

Now, we have a system of first-order differential equations:

x1' = x2

x2' = x3

x3' = x4 - 5x2 - 3x1 + 53sin(3t)

x4' = ?

We need to find an expression for x4' by differentiating one of the equations. Let's differentiate the equation x3' = x4 - 5x2 - 3x1 + 53sin(3t) with respect to t:

x4' = x3'' = (x4 - 5x2 - 3x1 + 53sin(3t))'

Differentiating each term, we get:

x4' = x4' - 5x2' - 3x1' + 159cos(3t)

Simplifying, we have:

x4' = -5x2 - 3x1 + 159cos(3t)

Therefore, the equivalent system of first-order differential equations is:

x1' = x2

x2' = x3

x3' = x4 - 5x2 - 3x1 + 53sin(3t)

x4' = -5x2 - 3x1 + 159cos(3t)

Note: The given differential equation is of the fourth order, so the resulting system has four first-order equations to represent it.

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Answer:look close because that is the question

Step-by-step explanation:

Answer

A) f(w) = 80w + 30

B) w represents the number of weeks and f(w) the number of flowers that bloomed

C) 2830 flowers

Step-by-step explanation

A) To find the function f, which represents the number of flowers that bloomed, as a function of w, the number of weeks, we have to evaluate f(s) with s = s(w) = 40w, as follows:

B) w represents the number of weeks and f(w) the number of flowers that bloomed, like before.

C) Substituting w = 35 weeks into f(w), we get: