Level: Standard
2) Given: -2(x - 4) = 3(x + 12); Prove: x = -5.6
Statements
Reasons

Answer: The answer to that would be 3.

Step-by-step explanation: So 5 / 1  2/3 = 3

Sorry my handwriting is so sloppy! Hope it helps!

Hi there & welcome to brainly !

Answer:

\( \huge{ \boxed{ \bold{ \tt{ \frac{3}{2}}}}} \)

Step-by-step explanation:

A ( 1 , 7 ) , B ( - 1 , 4 )

Slope = ?

Let A ( 1 , 7 ) ↦ ( x₁ , y₁ )

Let B ( - 1 , 4 ) ↦ ( x₂ , y₂ )

Finding the slope :

\( \boxed{ \tt{slope \: ( \: m)= \frac{y2 - y1}{x2 - x1} }}\)

\( \sf{↦ \: slope = \frac{4 - 7}{ - 1 - 1}} \)

\( \sf{↦ \: slope = \frac{ - 3}{ - 2}} \)

\( \sf{↦ \: slope = \boxed{ \sf{ \frac{3}{2} }}}\)

And we're done !

Hope I helped!

Best regards! :D

~TheAnimeGirl

Answer:true

Step-by-step explanation:

Answer: The correct answer is 25%

The answer is (a) (30, 50). To find the 98% confidence limits,

We can use the formula:

\(98% confidence limits = sample mean ± (Z-score for 98% confidence level) * (standard error)\)

We don't know the sample mean or the standard error, but we do know the 90% confidence limits. We can use these to estimate the standard error:

Standard error = (90% confidence limits upper bound - 90% confidence limits lower bound) / (1.645 * 2)

Standard error = (47 - 33) / (1.645 * 2) = 4.73

Now we can use this to estimate the 98% confidence limits:

98% confidence limits = sample mean ± (2.33) * (4.73)

We know that the range of the 90% confidence limits is 14 (47 - 33). The range of the 98% confidence limits will be wider than this, so we can eliminate options b), c), and e).

Now we just need to check which of the remaining options gives us a range wider than 14. We can do this by subtracting the lower limit from the upper limit:

a) (30, 50) -> range = 20
d) (38, 45) -> range = 7

Therefore, the answer is (a) (30, 50).

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Answer:

0

Step-by-step explanation:

- Anything multiplied by 0 will always result in 0.

Question 1: The item not included in the cost of merchandise inventory is "Purchase discounts."

2: The total cost of the merchandise is $3,332.00.

5: The company's gross margin and operating expenses, are $211,000 and $191,720.

Merchandise inventory expenses normally consist of the price paid for the inventory, deductions from the purchase price resulting from purchase returns and allowances, and freight expenses paid by the purchaser.

Although purchase discounts reduce the cost of merchandise inventory, they are not considered part of it. Instead, they are treated as a distinct discount in the accounting records.

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Answer:

your equations would be 3x+1y=86 and x+y=42

the answer would be 22 field goals and 20 extra po

Step-by-step explanation:

The appropriate simulation applet to calculate an approximate p-value is 0.0077.

The strong evidence that a short delay hinders the memorization process is strong data suggests that a brief delay impairs memorization.

Delay or no delay, answer: the number of words remembered

The mean distance between words remembered with and without delay over time is null, or zero.

Alt: The mean distance in words remembered over the long term (with no delay minus with delay) is higher than 0.

Yes, the majority of the lines do skew to the right. The mean for no delay is 10.55 whereas that for with delay is 8.7.

The mean distance in words remembered is 1.85.

1)0.0077 as the p-value

2)Strong data suggests that a brief delay impairs memorization.

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Answer:

(0,4)

Step-by-step explanation:

Given the line equation:

y = 3x + 2

Given the points :

(100, 302)

x = 100 ; y =302

302 = 3(100) + 2

302 = 300 + 2

(2, 8)

8 = 3(2) + 2

8 = 6 + 2

(0, 4)

4 = 3(0) + 2

4 ≠ 2

(9,29)

29 = 3(9) + 2

29 = 17 + 2

Answer:

B)

Step-by-step explanation

I am not sure

The eigenvectors v1 and v2 are such that when multiplied by matrix A, they result in scalar multiples of themselves (scaled by their respective eigenvalues).

An eigenvector is a non-zero vector that, when multiplied by a matrix, results in a scalar multiple of itself. In other words, if A is a square matrix and v is an eigenvector of A, then Av = λv, where λ is the eigenvalue associated with v.

Given the eigenvalues and eigenvectors for matrix A as λ1 = 2, v1 = [-5 1]ᵀ and λ2 = 6, v2 = [5 4]ᵀ, we can say that:

- Av1 = λ1v1 = 2[-5 1]ᵀ = [-10 2]ᵀ
- Av2 = λ2v2 = 6[5 4]ᵀ = [30 24]ᵀ

Therefore, the eigenvectors v1 and v2 are such that when multiplied by matrix A, they result in scalar multiples of themselves (scaled by their respective eigenvalues).

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Answer:

Y= 5/2x+0

Step-by-step explanation:

find the slope and y intercept, which would be 5/2 and 0.

:))

The two consecutive positive integers are 5 and 6.

Let the two consecutive positive integers be x and x + 1. We are given that the product of these integers is 3 less than three times their sum. This can be expressed as:
\(x(x + 1) = 3(x + x + 1) - 3\)
Now we can solve for x:
\(x^2 + x = 6x + 3 - 3\)
\(x^2 + x = 6x\)
\(x^2 - 5x = 0\)
Factoring the left side of the equation, we get:
\(x(x - 5) = 0\)
From this equation, x can be 0 or 5.

However, since the question asks for positive integers, we can't use x = 0. Therefore, x = 5.

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We have proven that no two events a and b can be independent unless either a or b is the whole sample space or the empty set below.

A sample space can be defined as the set of all possible outcomes of any experiment.

We are already aware that the outcomes of this die are going to be (1,2,3,..p). If we have a pair of proper events A, B which are independent, this would mean that = A∩B={∅}  (i)

This is a contradiction. So, now we suppose that = A∩B=C, for some proper event C (ii)

Using the values of (i) and (ii), we get -

= |C|p=P(A∩B)=P(A)P(B)=|A||B|p2.

= p|C|=|A||B|.

From this, we understand that neither A nor B are going to be full spaces and hence, no two events a and b are independent and 0<|A|<p and 0<|B|<p. Since |C| is also going to be less than 0 and p is prime, p divides either |A| or |B|.  if p was not prime (say, p=4), then you would only need the factors of p to divide either |A|,|B|, so, it becomes necessary for p to be a prime number. Hence, proved.

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In the equation y = $7.20x + $790, "y" represents the total cost. An equation is a mathematical statement that shows the relationship between two or more variables. In this equation, there are two variables - "x" and "y". The variable "x" represents the number of units produced or sold, while "y" represents the total cost.

The coefficient of "x" in the equation, which is 7.20, represents the variable cost per unit. This means that for each unit produced or sold, there is an additional cost of $7.20. The constant term, which is $790, represents the total fixed costs. Fixed costs are those costs that do not vary with the number of units produced or sold.To find the total cost of producing or selling a certain number of units, we can plug in the value of "x" into the equation and solve for "y". For example, if we want to find the total cost of producing 100 units, we can substitute x=100 into the equation:
y = $7.20(100) + $790
y = $720 + $790
y = $1510
Therefore, the total cost of producing 100 units is $1510. In summary, "y" represents the total cost in the given equation, which is determined by both fixed and variable costs.
In the equation y = $7.20x + $790, "y" represents option C: total costs. This equation has two components: "$7.20x" represents the variable costs per unit, where x is the number of units, and "$790" represents the total fixed costs. By adding these two components together, you get the total costs (y) for producing x units.

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Answer: ∠AOB=112°

Step-by-step explanation:

Then in our case ∠AOB -central ; ∠ACB= inscribed  

Then :

let ∠AOB=2∠ACB=2α ; ∠ACB=α

Then :

∠COA+∠COB+2α=360 (because the full angle is O)

∠СOA+∠COB=360-2α  

And we know :

∠СOA+∠COB+∠CAO+∠ACB+∠CBO=360

360-2α+α+∠CAO+∠CBO=360  

360-a=360-∠CAO-∠CBO

\(\boxed{\angle ACB=\alpha =\angle CAO+\angle CBO} } \sf - \\\\This \ formula always \ works \ , \ the \ main \ thing \ is \ to \ remember \ it\)

Then :

α=(32+24)=56°  ; ∠AOB=2α=56*2=112°

The finite difference approximation for a Neumann boundary condition, \(\left(\frac{df}{dx}\right)\), at node \(n\) (right boundary) to \(O(h^2)\) is given by

\(\left(\frac{df}{dx}\right)_n \approx \frac{f_{n-2} - 4f_{n-1} + 3f_n}{2h}\),

where \(f_{n-2}\), \(f_{n-1}\), and \(f_n\) represent the function values at nodes \(n-2\), \(n-1\), and \(n\) respectively, and \(h\) represents the spacing between the nodes.

To derive this approximation, we start with the Taylor series expansion of \(f_{n-1}\) and \(f_n\) around \(x_n\):

\(f_{n-1} = f_n - hf'_n + \frac{h^2}{2}f''_n - \frac{h^3}{6}f'''_n + \mathcal{O}(h^4)\),

\(f_{n-2} = f_n - 2hf'_n + 2h^2f''_n - \frac{4h^3}{3}f'''_n + \mathcal{O}(h^4)\).

By subtracting \(4f_{n-1}\) and adding \(3f_n\) from the second equation, we eliminate the first-order derivative term and retain the second-order derivative term. Dividing the result by \(2h\) gives us the desired finite difference approximation to \(O(h^2)\).

In conclusion, the finite difference approximation for a Neumann boundary condition, \(\left(\frac{df}{dx}\right)\), at node \(n\) (right boundary) to \(O(h^2)\) is \(\left(\frac{df}{dx}\right)_n \approx \frac{f_{n-2} - 4f_{n-1} + 3f_n}{2h}\). This approximation is obtained by manipulating the Taylor series expansion of \(f_{n-1}\) and \(f_n\) to eliminate the first-order derivative term and retain the second-order derivative term, resulting in a second-order accurate approximation.

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Answer:

Step-by-step explanation:

45 / 2.25 = 20 games

The table of values that represents exponential decay is (c)

From the question, we have the following parameters that can be used in our computation:

The table of values

An exponential function is represented as

y = abˣ

Where

Rate = b

When the rate is less than 1, then the table represents a decay

i.e when y reduces as x increases

The table that has the above features is the table (c)

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The answer is:

Rational

Work/explanation:

23² = 529

529 is a whole number.

All whole numbers are rational.

These are numbers that can be expressed in the form of p/q, where q ≠ 0.

Can 529 be expressed in p/q form? Well, we can try.

529 = 529/1, which is p/q form.

Answer:

{2(x-3)}/2

I hope that's helpful

There is no interval of convergence for the given series ∑(from n=1 to infinity) of 4434, as it does not converge.

To find the interval of convergence for the given series ∑(from n=1 to infinity) of 4434, we first need to recognize that this series is a constant series, meaning that each term is the same constant value, in this case, 4434.

The interval of convergence for a constant series is dependent on the value of the constant. Since the constant value is non-zero, the series diverges, as it does not approach a finite value when summed to infinity.

Therefore, there is no interval of convergence for the given series ∑(from n=1 to infinity) of 4434, as it does not converge.

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Answer:

It's 38.

Step-by-step explanation:

the sum of three consecutive even integers is 108, the largest number in the sequence would be 38.

I hope this helps you!

Answer:

We can use algebra to solve this problem. Let's call the smallest of the three consecutive even integers x. Since the integers are consecutive and even, the next two integers will be x+2 and x+4.

The problem states that the sum of three consecutive even integers is 108, so we can write an equation:

x + (x+2) + (x+4) = 108

We can simplify this equation by combining like terms:

3x + 6 = 108

3x = 102

x = 34

So, the smallest of the three consecutive even integers is 34.

The next two integers will be x+2 = 34+2 = 36 and x+4 = 34+4 = 38

The largest number of the three consecutive even integers is x+4 = 38.

Answer:

14

Step-by-step explanation:

ACQ, (According to the question)

x=10

2x - 8

What we have to do is, we have to substitute the value of x with the equation's x, so,

=> 2* 10 - 8

=> 20 - 8

=> 14

Hope it helps :)

Answer:

\(\frac{9}{16}\)

Step-by-step explanation:

We first distribute \(\frac{3}{4}\):

\(\frac{3}{4} (\frac{1}{2}) +\frac{3}{4} (\frac{1}{4} )\)

\(\frac{3}{8} +\frac{3}{16}\)

We find the common denominator and simplify:

\(\frac{6}{16} +\frac{3}{16}\)

\(\frac{9}{16}\)

Answer:

12x^3 + 19x^2 + x - 5

Step-by-step explanation:

To solve this, I set up the problem like this:

(3x^2 + x - 1)(4x + 5)

Now, just distribute everything from the first set of ( ) to the second set of ( ). Here's what you should have when you do that:

12x^3 + 15x^2 + 4x^2 + 5x - 4x - 5

Now, you would just combine like terms, which would get you to the final answer.

Hope this helps!

12x³ + 19x² + x -5

Polynomials are expressions that have multiple terms.

Breaking Apart Polynomials

When multiplying by a polynomial, we can break apart one of the polynomials, and multiply by each term individually. This means to multiply 3x² + x - 1 by 4x + 5, we can break apart the binomial into its separate terms. Instead of trying to multiply everything at once, we can multiply the trinomial by 4x and then multiply the trinomial by 5. Finally, add together the 2 products for the final answer.

Multiplying Polynomials

First, let's multiply the trinomial by 4x.

To find the product, multiply each term of the trinomial by 4x, then add them back together.

So, the first product is 12x³ + 4x²- 4x. Next, let's multiply 5(3x² + x - 1) the same way.

This means that the second product is 15x² + 5x - 5. Finally, let's add the 2 products together.

Then, simplify the expression.

This gives us our final answer. The product of 3x² + x - 1 and 4x + 5 is 12x³ + 19x² + x - 5.

Answer:

20 mins

Step-by-step explanation:

Answer:

20 mins

Step-by-step explanation:

ok first you divide 275 by 5 (so theh amount typed by the time)

them you get 55 (thats amount per min)

1100 divided by 55 so you get 20

20 minuets for that

To dilate a triangle, you have to measure the vertical and horizontal from the point to the center of dilatation. The ratio of dilated vertical and horizontal must be the same from the original triangle.

As a note, the center of dilatation is a fixed point that the figure is dilated ,and scale factor is a constant ratio between the original figure distance to center of dilatation with the dilated figure.

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