Joe and Steve are saving money. Joe starts with $105 and save $5 a week. Steve starts with $5 and saves $15 per week. After how many weeks will they have the same amount of money?

Based on the given confidence interval, there is evidence to support the claim that the true average echo duration of lightning flashes is 0.8 seconds.

To determine if the evidence supports the claim that the true average echo duration of lightning flashes is 0.8 seconds, we need to check if the value 0.8 falls within the confidence interval.

The 95% two-sided confidence interval for the true average echo duration is (0.743, 0.877). Since the value 0.8 falls within this interval, it means that the true average echo duration of lightning flashes of 0.8 seconds is within the range of values that is supported by the data.

Therefore, based on the given confidence interval, there is evidence to support the claim that the true average echo duration of lightning flashes is 0.8 seconds.

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The given equation is a quadratic equation of the form x^2 + 14x + 40 = 0. To find the solutions, we can apply the quadratic formula. The solutions for x are -10 and -4.

To solve the quadratic equation x^2 + 14x + 40 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by x = (-b ± √(b^2 - 4ac)) / (2a).

In our equation, a = 1, b = 14, and c = 40. Substituting these values into the quadratic formula, we get x = (-14 ± √(14^2 - 4*1*40)) / (2*1). Simplifying further, we have x = (-14 ± √(196 - 160)) / 2. This simplifies to x = (-14 ± √36) / 2.

Taking the square root of 36 gives us x = (-14 ± 6) / 2. This results in two possible solutions: x = (-14 + 6) / 2 = -8 / 2 = -4, and x = (-14 - 6) / 2 = -20 / 2 = -10. Therefore, the solutions to the equation are x = -10 and x = -4.


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Answer:

(0,6) and (-2, 0)

Step-by-step explanation:

All straight lines follow the equation, y = mx + c. where c is the y-intercept (the point where the line meets the y-axis) and m is the gradient.

In this equation, c = 6. So, the point where the line meets the y-axis is (0, 6).

Remember: the point where the line meets the y-axis always has an x-coordinate of 0 and the point where the line meets the x-axis has a y-coordinate of 0.

using this information, we can substitute y in the equation with 0 becoming

0 = 6 + 3x

now we can solve for x.

0 -6 = 3x

-6 / 3 = x

x = -2

the coordinate is (-2, 0)

Answer:

6746734

Step-by-step explanation:

first fo 45 minus 45 get 0 add then 56 plus 34

Answer:

1200

Step-by-step explanation:

1000(1+.05x4)

5%=.05

convert the months into years

The result of true and false is-

a) True: J and J' are opposite of y axis.

b) False: Location of L' is (-3, -4).

c) True: N and N' are at same distance.

d) False: L' is at 3 unit above x axis.

As per the given graph;

Part a: True: J and J' are opposite of y axis.

It is clear from the graph that J and J' lies on the opposite side of Y-axis.

The coordinate of J = (2, -6) and J' = (2, 6).

Part b: False: The location of L' is not (-3, -4)

The correct Location of L' is (3, 4) as seen from the graph.

Part c: True: N and N' are at same distance.

The coordinates of N and N' are (5, -5) and (5, 5).

Thus, they are at the same distance from the both axis.

Part d: False: L' is at 3 unit above x axis.

Point L' lies at the distance of 4 units from the x axis.

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In this case, Christopher divides the athletes into groups of varsity and junior varsity, which creates the strata. The type of sampling used in this scenario is stratified sampling.

Stratified sampling is a sampling method where the population is divided into homogeneous subgroups or strata, and individuals are randomly selected from each stratum in proportion to their representation in the population. In this case, Christopher divides the athletes into groups of varsity and junior varsity, which creates the strata.

By randomly selecting a proportionate number of individuals from each group, Christopher ensures that both varsity and junior varsity athletes are represented in the sample, maintaining the proportional representation of each group in the population. This method allows for more accurate and representative results by capturing the characteristics of both groups separately.


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Answer:

Step-by-step explanation:

Yes

Answer:

7/16

Step-by-step explanation:

\(\dfrac78 \times \dfrac24=\dfrac{7 \times 2}{8 \times 4}=\dfrac{14}{32}=\dfrac{7}{16}\)

Step-by-step explanation:

Given that,

The area of a blackboard is \(1\dfrac{1}{3}=\dfrac{4}{3}\ \text{yards}^2\)

The area of poster is \(\dfrac{8}{9}\ \text{yards}^2\)

We need to find the unit rate of the blackboard's area to the poster's area. So, it can be calcualted by dividing blackboard's area to the poster's area.

So,

\(\dfrac{\dfrac{4}{3}}{\dfrac{8}{9}}=\dfrac{4}{3}\times \dfrac{9}{8}\\\\=1.5\)

So, the rate of \(1.5\ \text{yard}^2\).

The equation that represents a line that is parallel to y = 5x - 4 and passes through the point (3, 4) is y = 5x - 11.

We are given that

Slope of parallel lines is the same, so slope of the line parallel to the given line will be m = 5

We have the slope and a point, using the point-slope form we can write the equation of the line:

\(\rightarrow\text{y} - 4 =5 \ (\text{x} - 3)\)

\(\rightarrow\text{y} = 5\text{x} - 15 + 4\)

\(\rightarrow\bold{y = 5x - 11}\)

Hence, the equation that represents a line that is parallel to y = 5x - 4 and passes through the point (3, 4) is y = 5x - 11.

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Your question is incomplete. The complete question is-

Which of the following equations represents a line that is parallel to y = 5x - 4 and passes through the point (3, 4)?

A. y = 5x - 7

B. y = 5x + 19

C. y = -1/5x -4

D. y = 5x - 11

The sample size necessary to estimate the mean GPA within a desired confidence level depends on the desired confidence level, margin of error, and the variability of the GPA. Without specific values for these parameters, it is not possible to determine the exact sample size required.

To calculate the necessary sample size, you need to consider the desired confidence level, margin of error, and the standard deviation of the GPA. The formula to calculate the sample size is:

n = (Z^2 * σ^2) / E^2

Where:

n = required sample size

Z = Z-score corresponding to the desired confidence level

σ = standard deviation of the GPA

E = margin of error (desired precision)

The Z-score depends on the desired confidence level. For example, if you want a 95% confidence level, the Z-score would be approximately 1.96. The standard deviation (σ) can be estimated from a pilot study or previous data. The margin of error (E) determines how precise you want the estimate to be.

To determine the sample size necessary to estimate the mean GPA within a desired confidence level, you need to specify the confidence level, margin of error, and the standard deviation of the GPA. By plugging in these values into the formula, you can calculate the required sample size. Keep in mind that a larger sample size generally leads to a more precise estimate, but it also requires more resources and time to collect the data.

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Answer:

6*10^-4 has a greater value.

Step-by-step explanation:

7*10^-9=   0.000000007

6*10^-4=   0.0006

Answer:

Step-by-step explanation:

Formula

A = L * w

P = 2*L + 2*w                         In Effect, you are trying to  find P

Givens

A = 80 m^2

w = x

L = x + 2

Solution

x*(x + 2) = 80                          Remove brackets

x^2 + 2x = 80                         Subtract 80 from both sides

x^2 + 2x - 80 = 80-80            Combine

x^2 + 2x - 80 = 0                    Factor the quadratic

(x - 8)(x + 10) = 0

x + 10 is an extraneous solution: x would = -10 which can't exist

x - 8 = 0

x = 8

w = 8

L = 8 + 2 = 10

L = 10

Fencing

P = 2L + 2w

P = 2*10 + 2*8

P = 20 + 16

P = 36 meters

Answer

36 meters of fencing is needed

Number of clients who do not play either the piano or the guitar is 22

To find the number of clients who do not play either instrument, we need to subtract the number of clients who play either the piano or the guitar or both from the total number of clients.

Let A be the set of clients who play the piano, and B be the set of clients who play the guitar. Then, we can use the formula A union B

|A ∪ B| = |A| + |B| - |A ∩ B|

where |A ∪ B| is the number of clients who play either the piano or the guitar or both, |A| is the number of clients who play the piano, |B| is the number of clients who play the guitar, and |A ∩ B| is the number of clients who play both instruments

Substituting the given values, we get

|A ∪ B| = 46 + 58 - 17

|A ∪ B| = 87

Therefore, the number of clients who do not play either instrument is:

109 - 87 = 22

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Answer:3 5/4 pound

Step-by-step explanation: I got you girl or boy

Answer:

-11 and -12

Step-by-step explanation:

Calipers are used in order to measure the accuracy of the object.

Rulers are used for measuring objects that are large and measure up to centimeters or even meters

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7 lightbulbs cost 12.6$ at the market.

The cost of 7 lightbulbs can be calculated by using the unit price of the lightbulbs at the market. The unit price is the cost of one lightbulb, and it can be found by dividing the total cost by the number of lightbulbs.
First, find the unit price of the lightbulbs:
Unit price = Total cost / Number of lightbulbs
Unit price = 9$ / 5
Unit price = 1.8$
Next, multiply the unit price by the number of lightbulbs you want to find the cost of:
Total cost = Unit price × Number of lightbulbs
Total cost = 1.8$ × 7
Total cost = 12.6$
Therefore, 7 lightbulbs cost 12.6$ at the market.

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The inclusion probability for unit 6 in a PPS sampling without replacement at the PSU level is calculated by dividing its size measure by the cumulative size measure, and then multiplying the result by the desired number of PSUs to be selected.

To determine the inclusion probability for unit 6 in a two-stage Probability Proportional to Size (PPS) sampling without replacement at the Primary Sampling Unit (PSU) level, follow these steps:

1. Calculate the size measure (e.g., population) for each PSU in the sampling frame.
2. Calculate the cumulative size measure for all PSUs.
3. Divide the size measure of unit 6 by the cumulative size measure to obtain the selection probability for unit 6.
4. Multiply the selection probability by the desired number of PSUs to be selected (e.g., n) to find the inclusion probability for unit 6.

In summary, the inclusion probability for unit 6 in a PPS sampling without replacement at the PSU level is calculated by dividing its size measure by the cumulative size measure, and then multiplying the result by the desired number of PSUs to be selected.

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Step-by-step explanation:

100℅=1225

43℅=x

criss cross

100℅x=526.75

100℅ 100℅

x=526.75 are studing science or engineering

100℅=1225

7%=x

do it like this

527 students at a university college  are studying science or engineering, 86 students own a car and 1005 students say it is a good college.

percentage, a relative value indicating hundredth parts of any quantity.

There are 1225 students at a university college.

43% are studying science or engineering

43/100×1225

0.43×1225

526.75

527

Hence 527 students at a university college  are studying science or engineering.

7% own a car

7/100×1225

0.07×1225

85.75=86

86 students at a university college own a car.

82% say it is a good college.

82/100×1225

0.82×1225

1004.5=1005

Hence, 1005 students at a university college say it is a good college.

Therefore, 527 students at a university college  are studying science or engineering, 86 students own a car and 1005 students say it is a good college.

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Answer:

$54.50

Step-by-step explanation:

3 pizzas + 2 breadsticks = $29.50

2 pizzas + 3 breadsticks = $23  

5 pizzas + 6 breadsticks = $x

multipy first equation by 3 and second by -2

9 pizzas + 6 breadsticks = $88.50

-4 pizzas -6 breadsticks = $-46

add the equations up,  9-4 pizzas + 6-6 breadsticks = $88.50-46

5 pizzas = $42.50 , divide by 5 both sides

1 pizza = $8.50

Substitute the price of a pizza, 2 pizzas + 3 breadsticks = $23  

2*8.50 + 3breadstiks = $23

17 + 3 breadsticks = $23  subtract 17 from both sides so

3 breadsticks = $23 -$17 divide by 3

1 breadstick = 6/3= $2

$5*8.50 for pizzas + $6*2 for breadsticks = $54.50

Answer:

Yes, it is TRUE

Hope my answer helps you ✌️

Answer:

c

Step-by-step explanation:

i'm taking the test right now

Probability is a branch of mathematics that deals with probability. It's also a number that expresses the probability of something occurring.

P(R) \(=\frac{1}{3}\)

Following are the calculation of the probability that are:

\(=(\frac{2}{1} \frac{1}{3}\frac{2}{3}) +(\frac{1}{3})^2 \\\\=\frac{4}{9} +\frac{1}{9}\\\\ =\frac{5}{9}\\\\\)

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DM is congruent to line CM because CDM is congruent to triangle CBM using the SAS congruence criteria for triangles.

Draw a diagram of the rectangle ABCD with M as the midpoint of AB. Draw lines CM and DM ( refer to the attached image). Since AB is a line segment, we know that AM is congruent to MB (because M is the midpoint of AB). Since ABCD is a rectangle, we know that AB is parallel to CD, and AD is parallel to BC. Thus, we have two pairs of parallel lines: AB and CD, and AD and BC.

Using the fact that opposite sides of a rectangle are congruent, we have CD = AB. Now, we have a pair of congruent sides (DM and CM) that are opposite each other in triangle CDM and CBM respectively. We also have another pair of congruent sides (CD and AB) that are opposite each other in both triangles. Finally, we know that the angle CMD is congruent to the angle CMB because they are vertical angles. By the Side-Angle-Side (SAS) congruence criterion, we can conclude that triangle CDM is congruent to triangle CBM.

Therefore, line DM is congruent to line CM by SAS congruence criteria.

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Answer: Answer In Photo

The Fourier Transform of the given signal can be determined by applying the properties of the Fourier Transform. To determine symmetry properties, we can analyze the mathematical expression of the signal and compare it with the conditions for even and odd signals.

The Fourier Transform of the signal x(t) = (t+1)σ(t+1) - 2tσ(t) + (t-1)σ(t-1), where σ(t) is the unit step function, can be determined by applying the properties of the Fourier Transform and using its definition.

To find the Fourier Transform, we can decompose the signal into three terms: (t+1)σ(t+1), -2tσ(t), and (t-1)σ(t-1). Each term represents a shifted and scaled version of the unit step function multiplied by a linear function of t.

Using the properties of linearity and time shifting, the Fourier Transform of each term can be determined. The Fourier Transform of the unit step function is 1/jω, and the Fourier Transform of a linear function of t is a scaled version of the Dirac delta function.

Analyzing each term separately and applying the properties, we can find the Fourier Transform of the signal x(t).

Regarding symmetry properties, we can determine if the signal is even, odd, or neither by analyzing its mathematical expression. If a signal is even, it satisfies x(-t) = x(t), and if it is odd, it satisfies x(-t) = -x(t). By substituting -t into the signal and comparing it with the original expression, we can determine if any symmetry property is fulfilled.

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If cholesterol level were changed to being measured in grams instead of milligrams, the correlation between fat content and cholesterol level would not be affected.

This is because correlation is a measure of the strength and direction of the linear relationship between two variables, and converting the units of measurement does not change the underlying relationship between the variables. So, the correlation coefficient of 0.75 would remain the same whether cholesterol level is measured in milligrams or grams.

The correlation between fat content and cholesterol level for the 20 different brands of American cheese slices is 0.75. If you change the measurement of cholesterol level from milligrams to grams (1 gram = 1000 milligrams), it will not affect the correlation. The correlation coefficient will remain 0.75, as it is unit-less and only represents the strength and direction of the relationship between the two variables.

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