Is this triangle a right triangle?

Answer:

the answer is c

Step-by-step explanation:

the answer is c

The position function of the object is s(t) = -5/16 cos(4t) + 1/4 sin(4t) + 6.

The given information provides the acceleration function a(t) = 5 sin(4t), initial velocity v(0) = 1, and initial position s(0) = 6. To find the position function, we need to integrate the acceleration function twice with respect to time.

Step 1: Integrating the acceleration function once will give us the velocity function. Since the integral of sin(4t) is -1/4 cos(4t), we have v(t) = -5/4 cos(4t) + C1.

Step 2: To determine the constant of integration, C1, we use the initial velocity condition v(0) = 1. Substituting t = 0 and v(0) = 1 into the velocity function, we find 1 = -5/4 cos(0) + C1, which simplifies to C1 = 1 + 5/4 = 9/4.

Step 3: Integrating the velocity function once more will yield the position function. Integrating -5/4 cos(4t) + 9/4 with respect to t, we obtain s(t) = -5/16 cos(4t) + 1/4 sin(4t) + C2.

To find the constant of integration C2, we utilize the initial position condition s(0) = 6. Plugging in t = 0 and s(0) = 6 into the position function, we get 6 = -5/16 cos(0) + 1/4 sin(0) + C2, which simplifies to C2 = 6.

Therefore, the position function of the object is s(t) = -5/16 cos(4t) + 1/4 sin(4t) + 6.

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Answer:

9

Step-by-step explanation:

9, 18, 12, 9, 13, 22, 8, 23, 16, 17

Mode is the number that appears most often

Listing numbers in order from smallest to largest helps to see how many of each number

8,9,9,  12, 13,16,17 ,18, 22, 23,

We see the number 9 appears most often

Maclaurin series of `f(x)` is given by:f(x) = `f(0)` + `f'(0)x` + `(f''(0)/2!) x²` + `(f'''(0)/3!) x³` + `(f⁴(0)/4!) x⁴` + `(f⁵(0)/5!) x⁵` + `(f⁶(0)/6!) x⁶` = `0 + 0x + 0x² + 0x³ + 0x⁴ + 0x⁵ + (7200/6!)x⁶` = `10x⁶`

Answer: `10x⁶`.

The given function is `f(x) = x⁶ sin(10x⁵)`. We need to find the Taylor series of `f` centered at `0` (Maclaurin series of `f`).

Formula used: The Maclaurin series for `f(x)` is given by `f(x) = f(0) + f'(0)x + (f''(0)/2!)x^2 + (f'''(0)/3!)x^3 + ...... + (f^n(0)/n!)x^n`.

Here, `f(0) = 0` because `sin(0) = 0`.

Differentiating `f(x)` and its derivatives at `x = 0`:`f(x) = x⁶ sin(10x⁵)`

First derivative: `f'(x) = 6x⁵ sin(10x⁵) + 50x¹⁰ cos(10x⁵)`

Differentiate `f'(x)`

Second derivative: `f''(x) = 30x⁴ sin(10x⁵) + 200x⁹ cos(10x⁵) - 250x¹⁰ sin(10x⁵)`

Differentiate `f''(x)`

Third derivative: `f'''(x) = 120x³ sin(10x⁵) + 1800x⁸ cos(10x⁵) - 2500x⁹ sin(10x⁵) - 5000x²⁰ cos(10x⁵)`

Differentiate `f'''(x)`

Fourth derivative: `f⁴(x) = 360x² sin(10x⁵) + 7200x⁷ cos(10x⁵) - 22500x⁸ sin(10x⁵) - 100000x¹⁹ cos(10x⁵) + 100000x²⁰ sin(10x⁵)`

Differentiate `f⁴(x)`

Fifth derivative: `f⁵(x) = 720x sin(10x⁵) + 36000x⁶ cos(10x⁵) - 112500x⁷ sin(10x⁵) - 1900000x¹⁸ cos(10x⁵) + 2000000x¹⁹ sin(10x⁵)`

Differentiate `f⁵(x)`

Sixth derivative: `f⁶(x) = 7200 cos(10x⁵) - 562500x⁶ cos(10x⁵) + 13300000x¹⁷ sin(10x⁵)`

Evaluate at `x = 0`:

The derivatives of `f(x)` evaluated at `x = 0` are:f(0) = 0f'(0) = 0f''(0) = 0f'''(0) = 0f⁴(0) = 0f⁵(0) = 0f⁶(0) = 7200

Maclaurin series of `f(x)` is given by:f(x) = `f(0)` + `f'(0)x` + `(f''(0)/2!) x²` + `(f'''(0)/3!) x³` + `(f⁴(0)/4!) x⁴` + `(f⁵(0)/5!) x⁵` + `(f⁶(0)/6!) x⁶` = `0 + 0x + 0x² + 0x³ + 0x⁴ + 0x⁵ + (7200/6!)x⁶` = `10x⁶`

Answer: `10x⁶`.

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Answer:

4/5=.80

4/.80= 5

5*7= 35

You can make 35 granola bars with 4 cups of chocolate chips.

I hope this helps!

The number of batches of granola bars the company make in the day is 22.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given that, Quaker uses 14 of a barrel of chocolate chips to make each batch of their Chewy marshmallow chocolate chip granola bars.

Number of batches = Total barrels of chocolate chips/Number of a barrel of chocolate chips

= 312/14

= 22.28

≈ 22

Therefore, the number of batches of granola bars the company make in the day is 22.

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Answer:

The percentage in length of the board is 25%

Answer:

A

Step-by-step explanation:

Answer:

7.6

Step-by-step explanation:

1is less than 5 so let it rest

Answer:

A. 1, 287 ways

B. 154,440 ways

Step-by-step explanation:

A. We want to choose 5 objects from a total 13, without considering the order in which they are chosen.

The correct way to do this is by using the combination formula since order is not considered;

Thus we have ; 13 C 5 read as 13 combination 5;

Mathematically, n C r is ; n!/(n-r)!r!

Thus, we have ;

13!/(13-8)!8! = 13!/5!8! = 1,287 ways

B. By considering order, we shall be using the permutation formula;

Mathematically n P r = n!/(n-r)!

Read as n permutation r;

Using the numbers involved, we have ; 13 P 5

= 13!/(13-5)! = 13!/8! = 154,440 ways

Answer:

73u/ - 11

Step-by-step explanation:

Answer:

-5.05. U -6

Step-by-step explanation:

Distribute the Negative Sign:=3.65u−11+−1(−5+8.7u)=3.65u+−11+(−1)(−5)+−1(8.7u)=3.65u+−11+5+−8.7uCombine Like Terms:=3.65u+−11+5+−8.7u=(3.65u+−8.7u)+(−11+5)=−5.05u+−6

Answer:

60 Polo Shirt, 20 T- Shirt, 120 Rugby Shirt

Step-by-step explanation:

T- Shirts + Polo Shirt + Rugby Shirts =200

                                 Rugby Shirts = 2( Polo Shirt)

$12(# of T- shirt) + $24( # of polo Shirts) + 36( # of Rugby Shirts) = 6000

x = number of t-shirts

y = number of polo shirts

z = number of rugby shirts

x + y + z = 200

z = 2y

12x + 24y + 36z = 6000 x + 2y + 3z = 500 {divided each side by 12}

substitute 2y, for z, into 1st and 3rd equations

x + y + 2y = 200 {substituted 2y, for z, into 1st}

x + 2y + 3(2y) = 500 {substituted 2y, for z, into 3rd}

x + 3y = 200 {combined like terms in 1st}

x + 8y = 500 {multiplied and combined like terms in 2nd}

-5y = -300 {subtracted the two equations}

y = 60 polo shirts {divided each side by -5}

z = 2y {2nd equation}

z = 2(60) {substituted 60, for y, into 2nd equation}

z = 120 rugby shirts {multiplied}

x + y + z = 200 {first equation}

x + 60 + 120 = 200 {substituted}

x + 180 = 200 {combined like terms}

-180 -180

x = 20 t-shirts {subtracted 180 from each side}

Therefore you should get 60 Polo Shirt, 20 T- Shirt, 120 Rugby Shirt.

In order to replenish stock and make the most of the money, the business should purchase 20 T-shirts, 60 polo shirts, and 120 rugby shirts.

Given data:

T-shirts cost $12 each.

Polo shirts cost $24 each.

Rugby shirts cost $36 each.

The total budget is $6000.

The store wants to restock a total of 200 shirts.

The store wants to have twice as many rugby shirts as polo shirts.

We can set up a system of equations based on the given information:

Equation 1: T + P + R = 200 (Total shirts)

Equation 2: 12T + 24P + 36R = 6000 (Total cost)

Since the store wants to have twice as many rugby shirts as polo shirts, we can express this as an equation:

Equation 3: R = 2P

Now we can substitute the value of R from Equation 3 into Equation 1:

T + P + 2P = 200

T + 3P = 200

We can solve this equation for T: T = 200 - 3P

Substitute the expression for T into Equation 2:

12(200 - 3P) + 24P + 36R = 6000

Now substitute the value of R from Equation 3 into the above equation:

12(200 - 3P) + 24P + 36(2P) = 6000

Simplify and solve for P:

2400 - 36P + 24P + 72P = 6000

60P = 3600

P = 60

Now that we know the number of polo shirts (P), we can find the number of rugby shirts (R) using Equation 3:

R = 2P = 2(60) = 120

Finally, we can find the number of T-shirts (T) using Equation 1:

T = 200 - 3P = 200 - 3(60) = 200 - 180 = 20

Hence, the store should buy 20 T-shirts, 60 polo shirts, and 120 rugby shirts to restock and maximize the use of the budget.

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The mass of one molecule of methane is 2.658 × \( {10}^{-23} \) and number of molecules of methane is 3.76.

Mass of one molecule of methane = mass of one carbon atom + 4×mass of one hydrogen atom

Mass of methane = 1.99 × \( {10}^{-23} \) + 4 × 1.67 × \( {10}^{-24} \)

Performing multiplication first

Mass of methane = 1.99 × \( {10}^{-23} \) + 4 × 6 68 × \( {10}^{-24} \)

Equating the exponents

Mass of methane = 1.99 × \( {10}^{-23} \) + 0.668 × \( {10}^{-23} \)

Performing addition

Mass of methane = 2.658 × \( {10}^{-23} \)

Now, 2.658 × \( {10}^{-23} \) is the weight of molecules number = 1

1 gram will have number of molecules = 1/ 2.658 × \( {10}^{-23} \)

Number of molecules = 3.76

Thus, mass is 2.658 × \( {10}^{-23} \) and 3.76 molecules are there.

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Answer:

The equation

(x/2) = 44

The answer

x = 88

Answer:

D. 24.9

Step-by-step explanation:

95/382 converted to a percentage is 24.9

The forecast for May using a five-month moving average is 39 (Option E).

Moving average is used for smoothing out time series data to find any trends or cycles within the data. A five-month moving average is the average of the past five months. To calculate the moving average, add up the sales for the previous five months and divide it by five.

According to the question, the sales for the previous five months are: Nov. 39 Dec. 27 Jan. 40 Feb. 42 Mar. 41 April 47

We have to add the sales of these five months, which gives:

27 + 40 + 42 + 41 + 47 = 197

To find the moving average for May, we divide this sum by 5:

197 / 5 = 39.4

Since we have to round the answer to the nearest whole number, we round 39.4 to 39, which is option E.

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Answer:

b = (looks to be) -3.5

m = \(\frac{1}{2}\)

Type of Slope = Positive, linear

Equation = y = \(\frac{1}{2}\)x - 3.5

(i) P[(A∩B′)∪(A′∩B)] can be represented graphically as the shaded region in the Venn diagram where events A and B intersect or overlap.  (ii) P(A∩B) = 4/10 or 2/5. (iii) Events A and B are not independent since the probability of their intersection, P(A∩B), is not equal to the product of their individual probabilities, P(A) and P(B).

(i) To plot and shade P[(A∩B′)∪(A′∩B)], we need to visualize the intersection and union of events A and B. A Venn diagram is a useful tool for this purpose. The intersection (A∩B) represents the overlapping region between A and B, while the complement (A′ or B′) represents the regions outside A or B, respectively. The shaded region corresponds to the union [(A∩B′)∪(A′∩B)], which includes the intersection and overlap of events A and B.

(ii) P(A∩B) represents the probability of both events A and B occurring simultaneously. From the information given, P(A) = 5/2 and P(B) = 4/1. However, the probability of their intersection, P(A∩B), is not provided directly. Hence, without further information, we cannot determine the precise value of P(A∩B).

(iii) Events A and B are considered independent if the occurrence of one event does not affect the probability of the other event. For two independent events, P(A∩B) should be equal to the product of their individual probabilities, P(A) and P(B). However, since the value of P(A∩B) is not provided, we cannot determine whether events A and B are independent based on the given information. Further information or calculation of P(A∩B) would be required to make a definitive determination.

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3 of 7 in percentage with rounding is 42.86%

Percentage is a way of expressing a number as a fraction of 100. It is often used to express how much of something there is compared to the total amount.

For example, if you have 20 apples and the total number of apples is 100, you can express the fraction of the total number of apples you have as a percentage. That is 20/100 = 0.2, which is equal to 20%.

In order to write 3 of 7 as a percent, we can say:

3/7 × 100 = 42.86%

Thus, with rounding 3 of 7 is 42.86%

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Complete Question

3 of 7 percent with rounding  =  ___ %

With a speed of 0.419 m/s, the rider fast is a rider rising when his seat is 16m above ground level

The formula for tangential velocity is 2*pi*r/T --> 2*pi*10/120 --> pi/6.

It is 6 meters above the center of the wheel while the rider is 16 meters above the ground.

The horizontal portion of this distance must be 8 meters as its separation from the wheel's center is 10 meters (depending on the radius).

This indicates that the velocity and seat both make angles of 36.87 degrees off vertical and arctan(6/8) over the origin, respectively.

We will take into account the vertical component of the tangential velocity since the rate at which the seat is rising is what we're interested in.

Pi/6 * cos(arctan(6/8)) yields a value of 0.419 m/s.

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The value of the angle m∠DAC is 74° as AB bisects ∠DAC .

We know from the properties of angles that the angle bisector will bisect the angle into two equal parts.

∠DAC is bisected by the straight line AB. This forms two angles ∠DAB and ∠BAC .

∠DAC =∠DAB + ∠BAC

now, ∠DAB = ∠BAC

given that ∠DAB = 37

Hence m∠BAC = 37

now,

∠DAC = ∠DAB + ∠BAC

m∠DAC = 37° + 37°

m∠DAC = 74°

A line that divides an angle into two equal angles is known as an angle bisector in geometry. A device that splits an object or form into two equal halves is referred to as a "bisector." A ray that divides a given angle into two identical segments of the same length is called an angle bisector.

Therefore the value of m∠DAC is 74° .

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Answer:

divide by 4 from each side

Step-by-step explanation:

\(\frac{x}{4} > 13\)

÷4    ÷4

x>13÷4

Answer:

Isolate x by multiplying by 4 to each side of the inequality

Step-by-step explanation:

You have x in a fraction, and you want to have x by itself on one side of the equation. In this case, you need to multiply by 4 to each side of the inequality to cancel the 4 on the left hand side of the inequality and leave x on its own. The final inequality is \(x>52\).

If I helped, a brainliest answer would be greatly appreciated!

Answer:

43.96

Step-by-step explanation:

Formula for Circumference is: C=2πr

C=2•3.14•7 7 is radius bc it's half of diameter

2•3.14= 6.28

6.28•7= 43.96

hope this helps chu babe <3

Answer:

D.

Step-by-step explanation:

it can't be B or C since Function A has a greater y-intercept of 2. and if you graph function A you can see that Function B has a greater rate of change

Answer:

D

Step-by-step explanation:

The rate of change for the graph is 2 so we can rule anything out that shows A has a larger rate of change. Now we look at the y intercept on the graph which is -2. The one in the function is 2 so we eliminate anything that says B has a greater y intercept this should give you the answer

Hope this Helps :)

A. The average number of minutes per day spent moving these products using the static storage policy is 1.33 minutes.

B.  The lowest value of average minutes per day used to move these SKUs with the heap policy is approximately 1.17 minutes per day. The initial placement of the SKUs does make a difference in determining the lowest average movement time, as shown by the difference between Scenario 1 and Scenario 2.

a. Static Storage Policy:

To minimize labor, we can allocate the SKUs to storage locations based on their respective travel times from the receiving area to the storage area. In this case, the travel times are 1 minute for location A, 2 minutes for location B, and 2 minutes for location C.

Given that we maintain a constant inventory of one pallet of SKU x and two pallets of SKU y at all times, we can allocate them as follows:

SKU x: Allocate it to the storage location with the shortest travel time, which is location A (1 minute).

SKU y: Allocate both pallets to the storage location with the next shortest travel time, which is location B or C (both have a travel time of 2 minutes).

By allocating SKU x to location A and both pallets of SKU y to either location B or C, we ensure that the SKUs are stored in the closest available locations, minimizing the travel time needed to move them.

The average number of minutes per day spent moving these products can be calculated by considering the dispatch and receiving schedule:

SKU x: Dispatched every three days. Assuming it takes 1 minute to move a pallet from storage to the receiving area, the average daily movement time for SKU x would be (1/3) minutes per day.

SKU y: Dispatched every two days. Assuming it takes 2 minutes to move a pallet from storage to the receiving area, the average daily movement time for SKU y would be (2/2) minutes per day.

Adding up the average daily movement times for SKU x and SKU y, we get:

Average daily movement time = (1/3) + (2/2) = 1.33 minutes per day.

Therefore, the average number of minutes per day spent moving these products using the static storage policy is 1.33 minutes.

b. Heap Policy:

The heap policy involves storing the most frequently dispatched SKU closest to the receiving area. In this case, SKU y is dispatched every two days, while SKU x is dispatched every three days.

To find the lowest value of average minutes per day used to move these SKUs with the heap policy, we need to consider the different initial placements of the SKUs.

Scenario 1: Initial Placement - Location A for SKU x and Location B for SKU y

SKU x: Travel time from storage to the receiving area = 1 minute

SKU y: Travel time from storage to the receiving area = 2 minutes

Average daily movement time:

SKU x: (1/3) minutes per day

SKU y: (2/2) minutes per day

Total average daily movement time = (1/3) + (2/2) = 1.33 minutes per day

Scenario 2: Initial Placement - Location A for SKU y and Location B for SKU x

SKU y: Travel time from storage to the receiving area = 1 minute

SKU x: Travel time from storage to the receiving area = 2 minutes

Average daily movement time:

SKU y: (1/2) minutes per day

SKU x: (2/3) minutes per day

Total average daily movement time = (1/2) + (2/3) ≈ 1.17 minutes per day

Therefore, the lowest value of average minutes per day used to move these SKUs with the heap policy is approximately 1.17 minutes per day. The initial placement of the SKUs does make a difference in determining the lowest average movement time, as shown by the difference between Scenario 1 and Scenario 2.

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The answer to this question is 0.

Apply the initial value theorem approach to calculate the values of ˙f(0) and f(0 ).

Imagine that, in this problem, f(t) and f(s) are a Laplace transform pair. These transform pairs are defined by:

f(t) = 3s 1 s 2 s 1 ,

and ˙f(0 ) = 0

The values of f(0 ) and ˙f(0 ) are given by: f(0 ):

s 1 = 3, s 2 = 1

and

\(f 0 = \frac{1}{2} (t - 0) - 0\)

First we must find a solution to the initial value problem. To do this, we need to find the functions ˙f(0 ) and g(t). The first thing we need is some knowledge about convolution. A convolution is simply the operation of taking the derivatives of two functions and adding them together, so it can be thought of as applying the difference operator (sometimes called "Difference") dx/dt

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Answer:

H=2

Step-by-step explanation:

I promissse

Be safe hope this helps

Answer: h is 4

Step-by-step explanation:

6.75

-2.25

----------

4.50

-2.25

----------

2.25

-2.25

----------

0.00

you could bowl 3 times (it starts off at 6.75 because I took away the cost of the shoes)