Is it possible to turn in a circle at a constant velocity? How or how is it not possible?

Answer:

get egg and try to make in not crack when it falls by exerting the momentum of the fall into something other than the egg ex. make a box full of bubble wrap and put your egg in it

Explanation:

Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

Answer:

–1652 N. The negative sign indicate that the force is in opposite direction to car.

Explanation:

The following data were obtained from the question:

Mass (m) of car = 1400 kg

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Force (F) applied on the car =?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Acceleration (a) =?

a = (v – u) /t

a = (12 – 25) /11

a = –13/11

a = –1.18 m/s²

Finally, we shall determine the force on the car as follow:

Acceleration (a) = –1.18 m/s²

Mass (m) of car = 1400 kg

Force (F) applied on the car =?

F = ma

F = 1400 × –1.18

F = –1652 N

Thus, the force on the car is –1652 N. The negative sign indicate that the force is in opposite direction to car.

If metal is required to cast the cubical metal box, it would require 784cm3 of solid static electricity iron.

Unbalanced electric charge on such a material's surface is known as static electricity. In contrast for dynamic (moving) electricity, which takes the shape of electric currents, static electricity is defined as being fixed or immovable. A typical atom is neutral, meaning it has an equal number of protons and electrons.

Although static electricity does not directly endanger human life, it can nonetheless shock us and, if we were on an elevated surface, might inflict serious injuries.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Answer:

D. X-rays have more energy than ultraviolet waves.

Answer:

1.7 m/s

Explanation:

Relevant Data provided as per the question below:-

Radius = 15.0 cm

Time = 0.56 s.

Based on the above information

The computation of the speed of the object is shown below:-

\(Velocity = \frac{2\times \pi \times Radius}{Time}\)

\(Velocity = \frac{2\times \frac{22}{7} \times 0.15}{0.56}\)

\(= \frac{0.942857}{0.56}\)

= 1.683 m/s

or

= 1.7 m/s

Therefore for computing the speed of the object or velocity we simply applied the above formula by considering the pi and all other given data

Answer:

See explanation

Explanation:

We convert the speed of the car to ms-1

90 × 1000/3600 = 25 ms-1

a) from;

F= ma

a= F/m

a= 8400/1050 = 8 ms-2

b) from

v= u - at

v= 0

u = 25 ms-1

a= 8 ms-2

t= ?

t = u/a = 25/8 = 3.1 s

From;

v^2 = u^2 - 2as

v= 0 ms-1

u^2 = 2as

s = u^2/2a

s= (25)^2/2 × 8

s= 625/16

s = 39 m

A. The acceleration of the car when the brakes were applied is –8 m/s².

B. The time taken for the car to stop is 3.13 s.

C. The distance travelled by the car while the brakes were applied is 39.06 m.

A. Determination of the acceleration of car.

Force (F) = –8400 N (opposite direction)

Mass (m) = 1050 kg

Force = mass × acceleration

–8400 = 1050 × a

Divide both side by 1050

a = –8400 / 1050

NOTE: The negative sign indicates that the car is coming to rest.

B. Determination of the time taken for the car to stop.

Initial velocity (u) = 90 Km/h = (90 × 1000)/3600 = 25 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = –8 m/s²

v = u + at

0 = 25 + (–8 × t)

0 = 25 – 8t

Collect like terms

0 – 25 = –8t

–25 = –8t

Divide both side by –8

t = –25 / –8

Therefore, the time taken for the car to stop is 3.13 s

C. Determination of the distance travelled by the car.

Initial velocity (u) = 25 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = –8 m/s²

v² = u² + 2as

0² = 25² + (2 × –8 × s)

0 = 625 – 16s

Collect like terms

0 – 625 = –16

–625 = –165

Divide both side by –16

s = –625 / –16

Therefore, the distance travelled by the car is 39.06 m

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Answer:

What??? maybe not keep doing what you are doing.

Explanation:

I don't know

Remember Coulomb's law: the magnitude of the electric force F between two stationary charges q₁ and q₂ over a distance r is

\(F = \dfrac{kq_1q_2}{r^2}\)

where k ≈ 8,98 × 10⁹ kg•m³/(s²•C²) is Coulomb's constant.

8.1. The diagram is simple, since only two forces are involved. The particle at Q₂ feels a force to the left due to the particle at Q₁ and a downward force due to the particle at Q₃.

8.2. First convert everything to base SI units:

0,02 µC = 0,02 × 10⁻⁶ C = 2 × 10⁻⁸ C

0,03 µC = 3 × 10⁻⁸ C

0,04 µC = 4 × 10⁻⁸ C

300 mm = 300 × 10⁻³ m = 0,3 m

600 mm = 0,6 m

Force due to Q₁ :

\(F_{Q_2/Q_1} = \dfrac{k (6 \times 10^{-16} \,\mathrm C)}{(0,3 \, \mathrm m)^2} \approx \boxed{6,0 \times 10^{-5} \,\mathrm N} = 0,06 \,\mathrm{mN}\)

Force due to Q₃ :

\(F_{Q_2/Q_3} = \dfrac{k (12 \times 10^{-16} \,\mathrm C)}{(0,6 \, \mathrm m)^2} \approx \boxed{3,0 \times 10^{-5} \,\mathrm N} = 0,03 \,\mathrm{mN}\)

8.3. The net force on the particle at Q₂ is the vector

\(\vec F = F_{Q_2/Q_1} \, \vec\imath + F_{Q_2/Q_3} \,\vec\jmath = \left(-0,06\,\vec\imath - 0,03\,\vec\jmath\right) \,\mathrm{mN}\)

Its magnitude is

\(\|\vec F\| = \sqrt{\left(-0,06\,\mathrm{mN}\right)^2 + \left(-0,03\,\mathrm{mN}\right)^2} \approx 0,07 \,\mathrm{mN} = \boxed{7,0 \times 10^{-5} \,\mathrm N}\)

and makes an angle θ with the positive horizontal axis (pointing to the right) such that

\(\tan(\theta) = \dfrac{-0,03}{-0,06} \implies \theta = \tan^{-1}\left(\dfrac12\right) - 180^\circ \approx \boxed{-153^\circ}\)

where we subtract 180° because \(\vec F\) terminates in the third quadrant, but the inverse tangent function can only return angles between -90° and 90°. We use the fact that tan(x) has a period of 180° to get the angle that ends in the right quadrant.

Answer:

Scintillators are materials that are able to convert high energy radiation such as X or gamma-rays to a near visible or visible light. They are widely used as detectors in medical diagnostics, high energy physics and geophysical exploration (ref. Knoll).

https://web.stanford.edu › scintillators

What are scintillator materials? - Stanford: Advanced Optical Ceramics Laboratory

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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The outdoor activities u prefers most is swimming because I feel relaxed after that.

The outdoor activities I am more interested in but I have not tried is mountain climbing.

Outdoor activities refers to exercises or activities that is carried out outside an enclosed areas. These include swimming, mountain climbing, running and the rest.

Therefore, The outdoor activities u prefers most is swimming because I feel relaxed after that.

The outdoor activities I am more interested in but I have not tried is mountain climbing.

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Answer:

1/2 m v^2 - G M m / R      escape velocity equal to energy at surface

v^2 = 2 G M / R = 2 * 6.67E-11 * 7.4E22 / 1.7E6

v^2 = 2 * 6.67 * 7.4 / 1.7 * 105 = 5.81E6

v = 2410 m/s = 2400 m/s

The acceleration of the hanging mass while the wheel's speed is increasing is 5,625 m/s².

Acceleration is a vector quantity that measures the rate of change of an object's velocity. It is defined as the rate at which an object's velocity changes over time. Acceleration can be positive, negative, or zero. Acceleration can be caused by forces such as gravity, friction, or thrust.

The acceleration of the hanging mass is determined by the torque (τ) and the moment of inTherefore, the acceleration of the hanging mass can be calculated as a = τ/I = (F×r)/(mr²) = F/(mr). In this case, F = 50 g, r = 30 cm and m = 16 spokes. We can convert the mass from grams to kilograms by dividing by 1000, giving us m = 0.016 kg.

Plugging these values into the equation, we get a = 50/(0.03×0.016) = 5,625 m/s².

Therefore, the acceleration of the hanging mass while the wheel's speed is increasing is 5,625 m/s².

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Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

Answer:

The drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires. According to the ideal gas law, this leads to a decrease in tire pressure. The low tire pressure light in vehicles is triggered when the pressure falls below a certain threshold, alerting the driver to check and adjust the tire pressure.

Explanation:

The ideal gas law, represented by the equation PV = nRT, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of an ideal gas. In this case, we can analyze how the drop in temperature affects the tire pressure.

When the temperature drops, according to the ideal gas law, the pressure of a gas will decrease if the volume and the number of moles remain constant. This is because the decrease in temperature causes a decrease in the average kinetic energy of the gas particles, leading to less frequent and less forceful collisions with the tire walls, resulting in a decrease in pressure.

In the context of the tire pressure, the air inside the tires behaves as an ideal gas. When the temperature drops overnight, the air inside the tires also cools down, causing a decrease in its temperature. As a result, the average kinetic energy of the air molecules decreases, leading to a decrease in pressure inside the tires.

The low tire pressure light comes on as a result of this drop in pressure. The tire pressure monitoring system in modern vehicles is designed to detect significant deviations from the recommended tire pressure. When the pressure drops below a certain threshold, typically due to temperature changes or a puncture, the light is triggered to alert the driver to check and adjust the tire pressure.

Therefore, the drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires, resulting in a decrease in tire pressure, which triggers the low tire pressure warning light.

Hope this helps!

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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Hi there!

We know the following kinematic equation:

vf = vi + at

Where:

vf = final velocity

vi = initial velocity

a = acceleration

t = time

In this instance, the ball is experiencing a constant acceleration of that of gravity, thus:

vf = 12 + 10(1) = 22 m/s (if downward is considered positive in this instance)

The frequency that the driver hears from the siren is 276 Hz

To determine the frequency heard by the driver, we need to consider the Doppler effect. The Doppler effect describes the change in frequency of a sound wave as a result of the relative motion between the source of the sound wave and the observer. When the fire engine approaches the driver, the relative velocity between the fire engine and the observer is the sum of their velocities:

Velocity of the fire engine relative to the observer = Velocity of the fire engine - Velocity of the observer

= 15 m/s - (-5 m/s)

= 20 m/s (since the observer is moving in the opposite direction)

Using the formula for the Doppler effect, we can calculate the observed frequency (f'):

f' = f (v + vo) / (v + vs)

where:

f = original frequency of the siren (285 Hz)

v = speed of sound in air (approximately 343 m/s)

vo = velocity of the observer (5 m/s)

vs = velocity of the source (15 m/s)

Plugging in the values into the formula:

f' = 285 Hz * (343 m/s + 5 m/s) / (343 m/s + 15 m/s)

f' = 285 Hz * 0.972

f' ≈ 276 Hz

the frequency that the driver hears from the siren is 276 Hz

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Note- The complete questions is "A fire engine is driving East at a velocity of 15 m/s. The fire engine is equipped with a siren that emits a constant tone with a frequency of 285 Hz. At the same time, a different person is driving on the same road but in the opposite direction, West, at a velocity of 5 m/s with the window down. The question asks, what frequency does the driver hear from the siren?"

In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.

Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct

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Answer: D - Both the sphere and the object are positive​.

Answer:

\(\huge\underline\color{green}{Answer \: ☘}\)

In the case of a water wave in the ocean, the medium through which the wave travels is the ocean water. In the case of a sound wave moving from the church choir to the pews, the medium through which the sound wave travels is the air in the room.

hope helpful~

the rope wouldnt move, the force of both dogs pulling us also called tension

Answer: 2.6 times less force

Explanation: I did the assignment <3

Answer:

Gravitational Force, Attraction, and Mass Quick

Explanation:

1)the mass of the object and the planet’s gravitational acceleration

2)2.6 times less force

3)The Earth has a greater gravitational attraction than the Moon.

4)980 N

5)The force would need to be greater, so they would not perform as well.

I did it and have a 5/5 100%

Answer:

a

Explanation:

A student bought a 1.55-ounce chocolate bar and left it in a car on a hot day.  Exactly 1.55 ounces of chocolate are in the melted bar. Hence, option (A) is correct.

In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.

The change caused by an applied force is smaller the more mass a body has. The kilogram serves as the unit of mass in the International System of Units (SI).

As mass does not depends on the state of the object, exactly same mass of chocolate are in the melted bar that it was in chocolate bar. So, 1.55 ounces of chocolate are in the melted bar. Hence, option (A) is correct.

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Answer:

b. the cylinder

Explanation:

From the information given:

We understood that the mass of the sphere, cylinder, and rod length is the same with the same angular speed.

Taking their moments:

For the solid sphere; \(\text{The moment of inertia :}\) \(I_s\) = \(\dfrac{2}{5} \times m \times r^2\)

The moment of inertia of the cylinder, \(I_c = 0.5\times m \times r^2\)

The moment of inertia of rod, \(I_r =\dfrac{ m * r^2 }{12}\)

The rotational kinetic energy is directly corresponding to the moment of inertia.

Thus, the cylinder has the greatest rotational kinetic energy.