In the diagram below, which particle is anti-matter?
e+
p
pn
v

In The Diagram Below, Which Particle Is Anti-matter?e+ppnv

Answers

Answer 1

The anti-matter particle in the diagram is e+ (positron), which has the same mass as an electron but a positive charge opposite that of an electron. (matter particle).

The other particles in the diagram are all matter particles (p, p, n, and v).

In the picture, e+ (positron) is the anti-matter particle since it has the same mass as an electron but a positive charge that is opposite to that of an electron. (matter particle).

Anti-matter is matter's polar opposite, composed of particles with the same mass but opposite charge as matter particles.

When matter and anti-matter particles collide, they annihilate each other and emit a massive amount of energy in the form of gamma rays. grasp the fundamental laws of physics and the beginnings of the world requires a thorough grasp of anti-matter.

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Related Questions

The Fastest Moving Planet In A Solar System Is:? A. The Smallest Planet. B. Any Planet, Because They All Move At The Same Speed. C. The Planet Nearest The Sun. D. The Planet Farthest From The Sun.

Answers

The planet that moves the fastest in a solar system is the planet nearest the Sun.

The correct option is C. The Planet Nearest The Sun.

What is a Solar System?

A solar system is a collection of planets, moons, comets, asteroids, and other objects that revolve around a single star. The sun is the center of our solar system, and it includes all of the matter and energy that orbits around it, including Earth and all the other planets.

Sun, the star around which Earth and the other planets of the solar system revolve, has a huge gravitational field. Planets move around the sun in a fixed orbit at varying speeds, depending on their distance from the sun. Because planets are closer to the sun, their gravitational pull is greater, resulting in a faster orbital speed for them.

The planet nearest the sun in the solar system is Mercury. Due to its proximity to the sun, it orbits at a speed of around 48 km/s, making it the fastest planet in the solar system, with an orbital period of 88 Earth days.

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How does the interaction of a nonelectrolyte and water differ from the interaction of an electrolyte and water? give examples of each.

Answers

The interaction of a nonelectrolyte and water differs from the interaction of an electrolyte and water because nonelectrolytes do not conduct current while electrolytes can conduct current.

The solution that does not let the current pass through any state either liquid or molten is called nonelectrolyte.

For example, sugar and alcohol are nonelectrolytes.

On the contrary, electrolytes are those mediums, compounds, or substances that allow electric charges to pass through them.

In this way they conduct electricity.

For example, when an ionic substance dissolved in water forms an ionic solution it let the current pass through such as NaCl, HCl, etc. Sodium chloride dissolves in water forming ions of sodium and chloride ions and making the solution electro conductive.

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a -kg bullet is fired with a velocity of 108.6 m/s toward a 5.99-kg block moving at a speed of 0.280 m/s in the same direction. the bullet emerges with a speed of 20.7 m/s and with a small piece of the block with a mass of 0.0016 kg sticking to it. what is the kinetic energy lost in the collision?

Answers

The speed of the bullet is 721m/s as it leaves

The speed of the bullet is 937m/s as it enters block 1 .

From the question, we have

+x direction is to the right (so all velocities are positive valued).

(a) Applying momentum conservation,

(0.0035kg)ν=(1.8035kg)(1.4m/s)  

⇒ν=721m/s .

(b) We use momentum conservation to connect the moment the bullet initially contacts the first block to the moment it has passed through it (using the speed v from section (a)).

(0.0035kg)V  =(1.20kg)(0.630m/s)+(0.00350kg)(721m/s)

V =937m/s .

Linear Momentum:

The product of an object's mass, m, and its velocity, v, is the vector quantity known as linear momentum. It is represented by the letter "p," which is also used to denote momentum. Please be aware that the body's momentum always points in the same direction as its vector of velocity. Because it is a conserved quantity, a system's overall momentum is always constant. kg/s is the unit of linear momentum.

Complete question:

a 3.50g bullet is fired horizontally at two blocks at rest on a frictionless table. The bullet passes through block  1  (mass 1.20kg ) and embeds itself in block 2 (mass 1.80kg ). The blocks end up with speeds ν 1=0.630m/s  and ν2 =1.40m/s (Fig.9-58b). Neglecting the material removed from block 1 by the bullet, find the speed of the bullet as it (a) leaves and (b) enters block 1 .

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a -kg bullet is fired with a velocity of 108.6 m/s toward a 5.99-kg block moving at a speed of 0.280

state Newton second law of motion​

Answers

Newton 2ns law state that external forces that exert on an object is proportional to the mass and the acceleration of an object

Formula : ΣF = ma

ask me if you're confused with my answer

What is the magnetic moment of the rotating ring?

Answers

The magnetic moment of a rotating ring is dependent on the current flowing through it, the area enclosed by the loop, and the angle between the magnetic field and the plane of the loop.

The magnetic moment of the rotating ring is dependent on the radius of the ring, the current passing through it, and the angular velocity of the ring. The magnetic moment of a ring that rotates at a constant angular speed in a magnetic field is given by the formula:μ = Iπr²where,μ = magnetic momentI = current flowing through the ringr = radius of the ringBy applying the Lorentz force,

the magnetic moment can be calculated as:μ = IAwhere,μ = magnetic momentI = current flowing through the ringA = area enclosed by the current loopWhen the ring is rotating, the magnetic moment is given by the formula:μ = IA cos(θ)where,μ = magnetic momentI = current flowing through the ringA = area enclosed by the current loopθ = angle between the magnetic field and the plane of the loopTherefore, the magnetic moment of a rotating ring is dependent on the current flowing through it, the area enclosed by the loop, and the angle between the magnetic field and the plane of the loop.

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State the basic assumptions of kinetic theory
I SWEAR IF ANOTHER BOT SENDS ME A "LiNk To ThE aNsWeR" I WILL COMMIT ARSON ON BRAINLY

Answers

Answer:

i got you there

Explanation:

the kinetic theory is that what ever that is in motion stays in motion

Spherical star clusters that are distributed around the central core of the galaxy are called ______

Answers

Spherical star clusters that are distributed around the central core of the galaxy are called globular clusters.

Globular clusters.

Globular clusters are compact and spherical collections of stars that orbit around the center of a galaxy. They are typically found in the outer regions of galaxies and are composed of hundreds of thousands of stars that are tightly bound together by gravity.

Therefore, the term for spherical star clusters that are distributed around the central core of the galaxy is globular clusters.

Globular clusters are dense groups of stars that orbit the core of a galaxy, forming a spherical distribution. They contain a large number of stars, often ranging from tens of thousands to millions, held together by gravitational forces. These clusters are primarily composed of older, low-mass stars.

the term you are looking for to describe spherical star clusters distributed around a galaxy's central core is "globular clusters."

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A 500- m -long ski slope drops at an angle of 6.4∘ relative to the horizontal.

If 20% of the gravitational potential energy change is converted into kinetic energy, how fast is the skier traveling at the bottom of the slope?

Answers

The speed of the skier at the bottom of the slope is 15.1 m/s.

What is the speed of the skier at the bottom of the slope?

The speed of the skier at the bottom of the slope is calculated by applying the principle of conservation of energy.

Kinetic energy at bottom = percentage of potential energy converted into kinetic energy.

K.E = 20%P.E

K.E = 0.2P.E

¹/₂mv² = 0.2 mgh

¹/₂v² = 0.2gh

v² = 2 (0.2gh)

v = √2(0.2gh)

where;

h is the height of the slope

sin (6.4) = h /L

h = L x sin(6.4)

h = 500m x sin (6.4)

h = 58.28 m

v =  √2(0.2 x 9.8 x 58.28 )

v = 15.1 m/s

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The power of the kettle was 1.5 kW. The 0.2kg heating element took 5 seconds to heat from 20 °C to 100 °C. Calculate the specific heat capacity of water using this information.

Answers

Answer:

Specific heat capacity, c = 468.75 J/Kg°C

Explanation:

Given the following data;

Power = 1.5 kW to Watts = 1.5 * 1000 = 1500 Watts

Time = 5 seconds

Mass = 0.2 kg

Initial temperature = 20°C

Final temperature = 100°C

To find specific heat capacity;

First of all, we would have to determine the energy consumption of the kettle;

Energy = power * time

Energy = 1500 * 5

Energy = 7500 Joules

Next, we would calculate the specific heat capacity of water.

Heat capacity is given by the formula;

\( Q = mcdt\)

Where;

Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity of water. dt represents the change in temperature.

dt = T2 - T1

dt = 100 - 20

dt = 80°C

Making c the subject of formula, we have;

\( c = \frac {Q}{mdt} \)

Substituting into the equation, we have;

\( c = \frac {7500}{0.2*80} \)

\( c = \frac {7500}{16} \)

Specific heat capacity, c = 468.75 J/Kg°C

PLZ HELP EASY
DEFINE magnitude.

Answers

Answer:

the great size or extent of something

Explanation:

Answer:

The absolute size,extent or importance of something.

how fast is a cat that runs 3 kilometers in 0.5 hours

Answers

Yes very very fast needs to be on time

I already did part a and the magnitude for all the parts. I need help finding the direction.

I already did part a and the magnitude for all the parts. I need help finding the direction.

Answers

b)

Given that,

A=10 N at 0°

B=20 N at 180°

As we can see these two vectors are in opposite directions.

Thus the resultant vector will be in the direction of the vector with the higher magnitude.

In vector addition we can write,

\(C=10\cos 0^0+20\cos 180^0\)

Where C is the resultant vector.

Thus magnitude of R will be equal to,

\(R=-10\text{ N}\)

The negative sign indicates that the direction of the C is along the negative x-axis.

Thus the magnitude of C is 10 N and the direction of the C is 180°

a)

Given,

A= 10 N at 0°

B=20 N at 0°

The the vector C is

\(C=10\cos 0^0+20\cos 0^0=30\text{ N}\)

The direction of R will be along the direction of these two vectors, as they are in the same direction.

Thus the magnitude of the vector C will be 30 N and the direction of the vector C is 0°

c)

Given,

A=10 N at 180°

B=20 N at 180°

Thus the vector C is

\(C=10\cos 180^0+20\cos 180^0=-30\text{ N}\)

The direction of the vector C will be along the direction of the negative x-axis, as these two vectors are along the negative x-axis.

Thus the magnitude of the vector C is 30 N and the direction of the vector C is 180°

d)

Given,

A= 10 N at 0°

B=20 N at 90°

The x-component of the vector C will be,

\(C_x=10\cos 0^0+20\cos 90^0=10\text{ }\hat{\text{i}}\)

The y- component of C will be,

\(C_y=10\sin 0^0+20\sin 90^0=20\text{ }\hat{j}\)

The magnitude of vector C is given by,

\(\begin{gathered} C=\sqrt[]{C^2_x+C^2_y}_{} \\ =\sqrt[]{10^2+20^2} \\ =22.36\text{ N} \end{gathered}\)

The direction of the vector C will be,

\(\begin{gathered} \theta=\tan ^{-1}\frac{C_y}{C_x} \\ =\tan ^{-1}\frac{20}{10} \\ =63.43^0 \end{gathered}\)

Thus the magnitude of C will be 22.36 N and the direction of C will be 63.43°

e)

Given that

A= 10 N at 90°

B=20 N at 0°

The x-component of the vector C will be

\(C_x=10\cos 90^0+20\cos 0^0=20\text{ }\hat{\text{i}}\)

The y-component of the vector C will be

\(C_y=10\sin 90^0+20\sin 0^0=10\text{ }\hat{j}\)

The magnitude of the vector C will be

\(\begin{gathered} C=\sqrt[]{C^2_x+C^2_y}_{} \\ =\sqrt[]{20^2+10^2} \\ =22.36\text{ N} \end{gathered}\)

The direction of vector C will be,

\(\begin{gathered} \theta=\tan ^{-1}\frac{C_y}{C_x} \\ =\tan ^{-1}\frac{10}{20} \\ =26.56^0 \end{gathered}\)

Thus the magnitude of the vector C will be 22.36 N and the direction of the vector C will be 26.56°

Assume that g is 10 N/kg and that air resistance and other
frictional forces are negligible.
1 )An object has a mass of 6 kg What is its gravitational potential energy
a( 4 m above the ground
b) 6 m above the ground?

2) An object of mass 6 kg has a speed of 5 m/s.
a What is its kinetic energy?
b What is its kinetic energy if its speed is doubled?


3 A ball of mass 0.5 kg has 100 J of kinetic energy. What
is the speed of the ball?

help with this its very important plss​

Answers

Answer:

1) Given acceleration due to gravity as 10N/kg

N/kg is the same as m/s². From W=mg

making g subject ... you have g = W/m

where m is in kg and W is in N

hence we have N/kg

So g=10ms-²

Gravitational Potential Energy=mgh

At height 4m

PE=6 x 10 x 4

=240J.

At height 6m

PE=6 x 10 x 6

=360J.

2) KE=1/2mv²

=1/2 x 6 x 5² =75J

When the speed is doubled... it becomes 2x

so V = 2x5=10ms-¹

KE=1/2 x 6 x 10² =300J.

3) KE=1/2mv²

KE is given as 100J

mass=0.5kg

Making V the subject

you have v² =2KE/m

v²=2 x 100/0.5

v²=400

taking square root

v=20ms-¹.

Have a great day✌

HELP ASAP

What happens when the mantle melts?

Answers

It produces oceanic crust,

With convection, hot mantle material rises closer to the Earth's surface, raising the geothermal gradient in the area. This causes the temperature in the earth's mantle to rise, which causes the mantle to partially melt. The partial melt contains both liquid and crystals that need a higher temperature to melt.

Partial melting is an important process in geology with respect to the chemical differentiation of crustal rocks. On the Earth, partial melting of the mantle at mid-ocean ridges produces oceanic crust, and partial melting of the mantle and oceanic crust at subduction zones creates continental crust.

find the resultant resistance of the circuit​

find the resultant resistance of the circuit

Answers

Answer:

R = 1.71 ohms

Explanation:

Two resistors are connected in parallel. There equivalent resistance is given by :

\(\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\)

Put all the values,

\(\dfrac{1}{R}=\dfrac{1}{3}+\dfrac{1}{4}\\\\R=1.71\ \Omega\)

So, the resultant resistance of the circuit is equal to 1.71 ohms.

Magnesium Oxide Reaction

Answers

Answer:

When magnesium reacts with oxygen, it produces light bright enough to blind you temporarily. Magnesium burns so bright because the reaction releases a lot of heat. As a result of this exothermic reaction, magnesium gives two electrons to oxygen, forming powdery magnesium oxide (MgO).

Answer:

Mg+O2 -----MgO

balanced equation

2Mg+O2-------2MgO

Station A
? Arrival Time for P Wave
minu
? Arrival Time for 5 Wave
? S-P Lag Time (secs)
? Distance from Epicenter (km)
30
Station B
TIME(econd
Station B
? Arrival Time for P Wave
wwwwwwww
? Arrival Time for S Wave
? S-P Lag Time (secs)
? Distance from Epicenter (km)
30
TIME (second)
-Buon C
Station C
? Arrival Time for P Wave
10
призми мили
? Arrival Time for S Wave
? S-P Lag Time (secs)
100
300
200
Distance from Epicenter
? Distance from Epicenter (km)
90
TIME (second)
NOW: Use your information above to determine which earthquake these seismographs represent. Check the correct box!
90
2
8
8
*PART THREE:
MYSTERY EARTHQUAKE
/Mark the start of the P Wave AND S Wave
Find the Lag Time
Use the Lag Time Graph to determine each
Stations' distance to the epicenter.
Based on the Distances, choose which map
depicts your earthquake!
Graph
Lag time of S-wave behind P-wave
(seconds)
100 0
8
Nasme
8

Answers

It is 37 because it is 378

21. Of the following sources, which supplies the most commercial energy in the world today?A. A. SolarB. B. OilC. C. BiomassD. D. NuclearE. E. Hydroelectric

Answers

The most commercial energy in the world is supplied by oil. Option B

Is oil a commercial energy source?

Oil is a commercial energy source. Oil, also known as petroleum, is a fossil fuel that is extracted from underground reservoirs and refined into a variety of products, including gasoline, diesel fuel, jet fuel, and heating oil. These products are used to power vehicles, heat homes, generate electricity, and fuel industrial processes, making oil a major source of energy for many countries around the world.

Oil is one of the most widely used energy sources in the world, due to its high energy density, ease of transportation, and versatility in use. It is a non-renewable resource, meaning that it will eventually run out, and its extraction and use have a significant impact on the environment

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the silvered wall of a vacuum bottle takes care of heat flow by
Radiation
Convection
Conduction
Conduction and convection

Answers

the answer is radiation :)

Evaporation requires the particles to _____ energy.
Answer:
create
release
absorb
destroy

Answers

Answer:

Release

Explanation:

The water is heated until

determine the volume change in ft3, when 1 lb of water, initially saturated liquid, is heated to saturated vapor while pressure remains constant at 450 lbf/in2

Answers

The volume change will be;6.80465 ft3/lb. (which is equal to 6.80465 ft3). The volume change in ft3, when 1 lb of water, initially saturated liquid, is heated to saturated vapour while pressure remains constant at 450 lbf/in2 is 6.80465 ft3.

When 1 lb of water, initially saturated liquid, is heated to saturated vapour while pressure remains constant at 450 lbf/in2, the volume change in ft3 can be determined as follows;

Firstly, use the given information to calculate the specific volume of water using the table of the properties of superheated water from the steam tables at 450 lbf/in2. The specific volume of water is calculated to be 0.01615 ft3/lb.

Then, determine the specific volume of the water in the vapour state at 450 lbf/in2 using the steam tables. It is equal to 6.8208 ft3/lb. The difference in the specific volume of the water in its two states (initially saturated liquid to saturated vapour) is then determined to be 6.8208 - 0.01615 = 6.80465 ft3/lb.

Since 1 lb of water has been heated from a saturated liquid state to a saturated vapour state, the change in volume will be equal to the difference in the specific volumes of the water in its two states.

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Estimate the number of apples that is the energy equivalent of 1 gallon of gasoline.

Answers

Estimating the number of apples that is the energy equivalent of 1 gallon of gasoline is difficult, as the energy content of both substances is different. However, we can calculate the energy content of one gallon of gasoline and compare it to the energy content of one apple. So, approximately 1,045,454 medium-sized apples will be the energy equivalent of one gallon of gasoline.

Explanation:

What is the energy content of 1 gallon of gasoline?

The energy content of gasoline is measured in British Thermal Units (BTUs). According to the US Energy Information Administration, one gallon of gasoline contains approximately 115,000 BTUs.Therefore, to calculate the number of apples that are the energy equivalent of one gallon of gasoline, we need to determine the energy content of one apple.

Calculating the energy content of apples:

The energy content of an apple varies depending on its size and type, but on average, one medium-sized apple contains about 95 calories or 0.00011 BTUs.To calculate how many apples are equivalent to one gallon of gasoline, divide the BTU content of gasoline by the BTU content of one apple:115,000 BTUs ÷ 0.00011 BTUs/apple ≈ 1,045,454 applesTherefore, approximately 1,045,454 medium-sized apples are the energy equivalent of one gallon of gasoline.

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A bullet travelling horizontally with speed of 30m/s strike a wooden plank normal it surface, passing through it with a speed of 10m/s. Find the time taken by the the bullet to pass through the wooden plank of 5cm thickness

Answers

The bullet takes 0.0025 seconds to pass through the wooden plank of 5 cm thickness when it is traveling horizontally with an initial speed of 30 m/s and a final speed of 10 m/s.

The time taken by the bullet to pass through the wooden plank can be determined using the equation of motion for constant acceleration.

Given:
Initial speed (u) = 30 m/s


Final speed (v) = 10 m/s


Distance (s) = 5 cm = 0.05 m

To find the time taken (t), we need to calculate the acceleration (a) first. We can use the equation:

v² = u² + 2as

Rearranging the equation, we have:

a = (v² - u²) / (2s)

Substituting the given values:

a = (10² - 30²) / (2 * 0.05)

Simplifying the expression:

a = (-800) / (0.1)


a = -8000 m/s²

The negative sign indicates that the acceleration is in the opposite direction of the initial velocity.

Next, we can use the equation of motion:

v = u + at

Substituting the values:

10 = 30 + (-8000) * t

Simplifying the equation:

-8000t = -20

Dividing by -8000:

t = 20 / 8000
t = 0.0025 s

Therefore, the time taken by the bullet to pass through the wooden plank of 5 cm thickness is 0.0025 seconds.


To find the time taken by the bullet to pass through the wooden plank, we need to calculate the acceleration first using the equation of motion.

By rearranging the equation and substituting the given values, we can find the acceleration.

Then, using the equation of motion again, we can solve for time.

The negative sign in the acceleration indicates that it is in the opposite direction of the initial velocity.

The resulting time is 0.0025 seconds.

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In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is the most ideal state for that system?

In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is

Answers

Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.

Thermal energy is the energy possesed by a system due to its temperature.

In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.

Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy

ANSWER:

A. Entropy

Most crashes occur at intersections because __________.
*
2 points
drivers fail to search and identify a safe path of travel when approaching an intersection
drivers don't identify or understand the risks
drivers fail to develop good driving habits to effectively manage the risks
all of the above

Answers

Most crashes occur at intersections because Drivers fail to search and identify a safe path of the travel when approaching an intersection. Drivers don't identify or understand the risks. Drivers fail tp develop good driving habits to effectively manage the risks.

Most crashes occur at intersections because of the following reason:

1) Drivers fail to search and identify a safe path of the travel when approaching an intersection.

2) Drivers don't identify or understand the risks.

3) Drivers fail tp develop good driving habits to effectively manage the risks.

Thus, Most crashes occur at intersections because all of the above reason. Most crashes occur at intersections because Drivers fail to search and identify a safe path of the travel when approaching an intersection. Drivers don't identify or understand the risks. Drivers fail tp develop good driving habits to effectively manage the risks.

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LR 125 ml/hr via gravity flow using tubing calibrated at 15 gtt/ml. Calculate the flow rate. A. 8 gtt/min B. 15 gtt/min C. 25 gtt/min D. 31 gtt/min.

Answers

The calculated flow rate is 31.2 gtt/min, which indicates a fractional value. Depending on the precision of the measurement, rounding may be necessary. So among the choices, option D. 31 gtt/min is correct.

To calculate the flow rate in drops per minute (gtt/min), we need to consider the volume infused per unit of time and the calibration of the tubing.

Given:

Infusion rate: 125 ml/hr

Tubing calibration: 15 gtt/ml

To convert the infusion rate from ml/hr to ml/min, we divide by 60 (since there are 60 minutes in an hour):

125 ml/hr ÷ 60 min/hr = 2.08 ml/min

Now, to find the flow rate in gtt/min, we multiply the infusion rate in ml/min by the tubing calibration factor:

2.08 ml/min × 15 gtt/ml = 31.2 gtt/min

The calculated flow rate is 31.2 gtt/min.

Among the answer choices, D. 31 gtt/min is the closest value to the calculated flow rate. However, it is important to note that the calculated flow rate is 31.2 gtt/min, which indicates a fractional value. Depending on the precision of the measurement, rounding may be necessary.

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What is the speed of a wave with a frequency of 100 hz and a wave length of .5 m?

Answers

Answer:

Explanation:

There are 2 ways to help with this. Explain the details, which are fairly simple in this topic, or give the formula. My hope is that an explanation will last longer than memorizing the formula. I give you both.

If a wave has frequency, f, of 3 Hz, its period, T, is

1

3

s

. The wavelength,

λ

, is 5 meters. That means that in the time of one period, the wave travels 5 m.

In general,

S

p

e

e

d

=

distance

time

In applying this general definition of speed

to a wave, we have

speed of the wave

=

wavelength

period

Note: we generally use v for speed of a wave. Using the variable names, then that last formula is written

v

=

λ

T

Since

T

=

1

f

, we can also say that

v

=

λ

f

So, using that last formula

v

=

5

m

3

H

z

=

15

m

s

Note: the unit Hz is equivalent to what it was called 100 years ago,

cycles

second

(

also cps

)

. Cycles is not a true unit, so the Hz contributed only the "per second" to the result

15

m

s

.

Answer: the speed is =30ms^-1 The speed of a wave is given by "speed" (ms^-1)= "frequency(Hz)" xx "wavelength (m)" The frequency is f=100Hz The wavelength is lambda=0.3m The speed is v=lambdaf=0.3*100=30ms^-1

Explanation:

if we neglect air resistance, what would be the speed of the raindrop when it reaches the ground? assume that the falling raindrop maintains its shape so that no energy is lost to the deformation of the droplet. for comparsion a pistol bullet has a typical muzzle velocity of about 200 m/s.

Answers

If air resistance is neglected, the raindrop will reach the ground with a speed determined solely by the force of gravity, which is approximately 9.8 m/s².

When air resistance is neglected, the only force acting on the raindrop is gravity. According to Newton's second law of motion, the force acting on an object is equal to its mass multiplied by its acceleration. In this case, the acceleration is due to gravity, which is approximately 9.8 m/s² on Earth.

Since the raindrop maintains its shape and does not lose energy to deformation, there are no additional forces or factors affecting its speed. Therefore, the speed of the raindrop as it reaches the ground is solely determined by the time it takes to fall under the influence of gravity.

By using the equations of motion, we can calculate the time it takes for the raindrop to fall from a certain height. Once we have the time, we can multiply it by the acceleration due to gravity to determine the final speed of the raindrop when it reaches the ground.

It is important to note that this calculation assumes ideal conditions and neglects factors such as air resistance, which can significantly affect the actual speed of a falling raindrop. In reality, air resistance slows down the raindrop, causing it to reach the ground at a lower speed than what would be predicted by neglecting air resistance.

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5. An object travels with constant speed through 1km for one minutes and 20 seconds and accelerates with 0.125m/s² for 20 seconds, what is the total displacement? A) 1250 m B) 275 m C) 1275 m D) 1225m​

Answers

Answer:

C)  Total displacement = 1275 m or 1.275 km

Explanation:

We'll break this into two parts:  

1) Displacement during constant speed, and

2) Displacement during the acceleration phase.

Constant Speed

The displacement for this segment is already stated:  1 km.  But the information includes the time, which will allow us to calculate the speed of travel.  We'll need this for the next phase of acceleration.

Distance = Speed x Time

Speed = Distance/Time

Time = 1 minute + 20 sec, or 80 sec.

Speed = 1 km/80 sec

Speed = 0.0125 km/sec

Since we'll be using meters (not km) in the next step, convert 0.0125 km/sec to m/sec with a conversion factor:  

  (0.0125 km/sec)*(1000m/1 km) = 12.5 m/sec

Acceleration Phase

The obect is moving at a speed of 12.5 m/sec (from above) and then accelerates at a rate of 0.125 m/sec^2 for 20 seconds.

The distance (s) an object travels during this acceleration (a) is gven by:

  s = vi*t + (1/2)a*t^2,

where vi is the initial velocity (12.5 m/sec in this case), a is the acceleration (0.125 m/sec^2), and t is the time (20 seconds).

s = (12.5 m/sec)(20 sec) + (1/2)(0.125 m/sec^2)*(20 sec)^2

s = 275 meters

Now add the two distances:

1) Constant Speed Phase = 1000 m

2)  Acceleration Phase    =  275 m

Total displacement = 1275 m or 1.275 km

The photoelectric effect describes when light shines on a piece of metal, and the metal releases electrons. Which characteristic of light behavior best helps explain this effect?

Light carries particles called photons.
Light moves as waves.
Light has an electric field and a magnetic field.
Light has waves with different frequencies.

Answers

Answer:

The characteristic of light behavior that best helps explain the photoelectric effect is that light carries particles called photons. When the photons of light strike the metal surface, they transfer their energy to the electrons in the metal, and if the energy of the photons is high enough, they can cause electrons to be emitted from the metal surface. This phenomenon is known as the photoelectric effect, and it was first explained by Albert Einstein in 1905.

a. Light carries particles called photons.

The photoelectric effect can be explained by the particle nature of light, where light is considered to be composed of individual particles called photons. When a photon is absorbed by a metal atom, it transfers its energy to an electron, which can then be emitted from the metal as a photoelectron. This effect can only occur if the energy of the photon is greater than the work function of the metal (the minimum amount of energy required to remove an electron from the metal). The frequency of the light is directly proportional to the energy of the photons, so higher frequency light (shorter wavelength) is required to eject electrons from the metal surface.
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