In a fluid mechanics experiment, a student measured and expressed pressure as −4.7 psi (gage), the corresponding absolute pressure of this measurement would be Question 2 The pressure may vary across a fluid particle True False Question 3 Bourdon tube pressure gage uses a elastic and A. tube to measure pressure. Question 4 Inclined tube manometer can be used to measure small pressure differences accurately True False We can neglect the effect of elevation changes on the pressure for stationary gases in the tanks and pipes, however if the elevation changes are in the order of thousands of feet then we must consider the variation of specific weights and hence the pressure changes. True False Question 6 Piezometer tube can measure the pressure of gas while manometer tube is only suitable for measuring liquid True False Question 7 For fluids at rest, the pressure gradient in the vertical direction at any point in the fluid depends only on the A of the fluid at that point.
Answers
2. True. The pressure can vary across a fluid particle.
3. True. A Bourdon tube pressure gauge uses an elastic tube to measure pressure.
4. True. An inclined tube manometer can be used to measure small pressure differences accurately.
5. False. The statement is incorrect. In fluid mechanics, when considering stationary gases in tanks and pipes, the effect of elevation changes on pressure can be neglected.
6. False. A piezometer tube and a manometer tube both can be used to measure the pressure of both gases and liquids.
7. Density. For fluids at rest, the pressure gradient in the vertical direction at any point in the fluid depends only on the density (ρ) of the fluid at that point.
Question 2: True
The pressure can vary across a fluid particle.
In fluid mechanics, pressure is a scalar quantity that can change with position within the fluid.
Each fluid particle can experience a different pressure depending on factors such as depth, velocity, and external forces.
Question 3: True
A Bourdon tube pressure gauge uses an elastic tube to measure pressure.
When the pressure is applied to the tube, it deforms, and this deformation is used to determine the pressure reading.
Question 4: True
An inclined tube manometer can be used to measure small pressure differences accurately.
It consists of a U-shaped tube with one end connected to the source of pressure and the other end open to the atmosphere.
By measuring the height difference of the fluid levels in the two arms of the manometer, small pressure differences can be determined.
Question 5: False
The statement is incorrect. In fluid mechanics, when considering stationary gases in tanks and pipes, the effect of elevation changes on pressure can be neglected.
The pressure changes are mainly determined by variations in temperature, volume, and other factors, while the effect of elevation changes is typically small and can be disregarded.
Question 6: False
A piezometer tube and a manometer tube both can be used to measure the pressure of both gases and liquids.
A piezometer tube is a simple device that measures static pressure, while a manometer tube is a more versatile device that can measure both static and dynamic pressures.
Question 7: Density
For fluids at rest, the pressure gradient in the vertical direction at any point in the fluid depends only on the density (ρ) of the fluid at that point.
The pressure gradient is the change in pressure with respect to vertical distance and can be expressed as dP/dz = -ρg, where dP/dz is the pressure gradient, ρ is the density of the fluid, and g is the acceleration due to gravity.
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Related Questions
help will mark as brainliest
Answers
Answer: i guess d is the correct answer
Answer:
D
Explanation:
I used this and passed my test! good luck!
What does the idea of multifactorial causation in drug effects suggest?
Taking several different drugs at the same time produces unpredictable effects.
Each person will have the same physiological response to a drug, but there can be different psychological responses.
Taking several different drugs at once increases their effectiveness. T
he effects of a drug depend on the dosage and the user’s personal makeup and experience.
Answers
According to the theory of multifactorial causation in drug effects, a drug's effects are influenced by dosage, the user's individual characteristics, and past experiences.
Dosage forms, sometimes also referred to as unit doses, are pharmaceutical drug products in the form in which they are marketed for use, with a particular combination of active ingredients and inactive ingredients (excipients), in a particular configuration (such as a capsule shell, for example), and apportioned into a specific dose. If two items are both amoxicillin, for instance, one comes in 500 mg capsules and the other in 250 mg chewable tablets. When each drug product is separately packaged, the term "unit dose" can also occasionally refer to non-reusable packaging), while the FDA distinguishes between the two terms as "packaging" or "dispensing" of unit doses. Depending on the situation, the term "multiple-unit dosage" might apply to various drug products packaged together or to a single drug product containing multiple pharmaceuticals.
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Newton’s Second Law of motion says that the acceleration of an object is related to the force and mass of the object. This equation is used to describe the relationship: F=ma, where f is the force, a is the acceleration, and m is the mass for the object in motion.
If a ball starting at rest has a mass of 0.25 kilograms and is pushed with a force of 3.5 N, then what is the acceleration for the object from the applied force? SHOW YOUR WORK.
Answers
Answer:
14metre squared
Explanation:
acceleration=force/mass
What is the average speed of a bird that flies 1.55 km in 30 minutes
Answers
Answer:
the average speed in annual work out is 46.5
At what decibel Level two sounds starts to becomeHarmful to the ears and the hearing?
Answers
Sound intensity more than 70 dB (noise) for a long period of time may start to damage your hearing.
A loud noise with sound intensity more than 120 dB can cause immediate harm to your ears.
in an electric geyser ______ energy is converted into____ energy
Answers
Answer:
in an electric geyser electrical energy is converted into heat energy
Explanation:
c. If the box experiences a force of 15 N to the left, along with the 20 N force acting to the right, what is the net force on the box?
Answers
According to the data given in the question the net force on the box is of 5 N.
What does net force mean?All of the forces that are applied to an object are added up to form the net force. As a consequence of the fact that it (force) is a vector and therefore that two forces with identical magnitudes and opposing directions cancel each other out, the resultant force is the total of the forces, or put another way, the net force is just the total of all the forces.
Given data :
Force on box to the left side (F1) = 15 N
Force on box to the right side (F2) = 20 N
Because both forces are in opposite direction
Hence,
Net force = F2 - F1
Net force = 20 - 15
Net force = 5 N.
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A capacitor is discharged through a 20.0 Ω resistor. The discharge current decreases to 22.0% of its initial value in 1.50 ms.
What is the time constant (in ms) of the RC circuit?
a) 0.33 ms
b) 0.67 ms
c) 1.50 ms
d) 3.75 ms
Answers
The time constant (in ms) of the RC circuit is 3.75 ms. Hence, the correct option is (d) 3.75 ms.
The rate of decay of the current in a charging capacitor is proportional to the current in the circuit at that time. Therefore, it takes longer for a larger current to decay than for a smaller current to decay in a charging capacitor.A capacitor is discharged through a 20.0 Ω resistor.
The discharge current decreases to 22.0% of its initial value in 1.50 ms. We can obtain the time constant of the RC circuit using the following formula:$$I=I_{o} e^{-t / \tau}$$Where, I = instantaneous current Io = initial current t = time constant R = resistance of the circuit C = capacitance of the circuit
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The time constant of the RC circuit is approximately 0.674 m s.
To determine the time constant (τ) of an RC circuit, we can use the formula:
τ = RC
Given that the discharge current decreases to 22.0% of its initial value in 1.50 m s, we can calculate the time constant as follows:
The percentage of the initial current remaining after time t is given by the equation:
I(t) =\(I_oe^{(-t/\tau)\)
Where:
I(t) = current at time t
I₀ = initial current
e = Euler's number (approximately 2.71828)
t = time
τ = time constant
We are given that the discharge current decreases to 22.0% of its initial value. Therefore, we can set up the following equation:
0.22 =\(e^{(-1.50/\tau)\)
To solve for τ, we can take the natural logarithm (ln) of both sides:
ln(0.22) = \(\frac{-1.50}{\tau}\)
Rearranging the equation to solve for τ:
τ = \(\frac{-1.50 }{ ln(0.22)}\)
Calculating this expression:
τ ≈ 0.674 m s
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Two spheres, 1.00 kg each, whose centers are 2.00m apart, would have what gravatational force between them? (gravitational constant = 6.67×10⁻¹¹ m³ kg⁻¹ s⁻²)
Answers
The gravitational force between the two spheres of mass 1 kg will be 1.6675 × 10⁻¹¹ Newtons.
What is Gravitational force?The gravitational force could be described as a force of attraction or the attractive force which attracts all the physical forms which are having some mass. Gravitational force is by far the weakest recognized natural force on this planet.
F = Gm₁m₂/ r²
F = Gravitational force,
G = Gravitational constant,
m₁ and m₂ are the masses of the two objects,
r is the distance between the two objects.
F = Gm₁m₂/ r²
F = 6.67 × 10⁻¹¹ × 1 × 1/ (2)²
F = 6.67 × 10⁻¹¹/ 4
F = 1.6675 × 10⁻¹¹ N
Therefore, the gravitational force will be 1.6675 × 10⁻¹¹ Newtons.
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according to the second law of thermodynamics what property do natural processes tend to increase
Answers
Answer:Entropy can be thought of as a measure of the dispersal of energy. It measures how much energy has been dispersed in a process. The flow of any energy is always from high to low. Hence, entropy always tends to increase.
Explanation:
A rectangular loop of wire with a cross-sectional area of 2.936 m2 carries a current of 6.488 A. The loop is free to rotate about an axis that is perpendicular to a uniform magnetic field strength of 1.108 T. The plane of the loop is initially at an angle of 59.914o to the direction of the magnetic field. What is the magnitude of the torque on the loop ?
Answers
ANSWER:
10.58 Nm
STEP-BY-STEP EXPLANATION:
Given:
Area (A) = 2.936 m²
Current (i) = 6.488 A
Magnetic field (B) = 1.108 T
Angle (θ)= 59.914°
To calculate the torque we must resort to the following formula:
\(\begin{gathered} \tau=MB\sin\alpha \\ \\ \alpha=90\degree-\theta=90-59.914\degree \\ \\ \alpha=30.086\degree \end{gathered}\)We need to know the magnetic moment, as follows:
\(\begin{gathered} M=NIA \\ \\ M=1\cdot6.488\cdot2.936 \\ \\ M=19.05\text{ A}\cdot m^2 \end{gathered}\)In this way we can calculate the torque:
\(\begin{gathered} \tau=19.05\cdot1.108\cdot\sin(30.086\degree) \\ \\ \tau=10.58\text{ Nm} \end{gathered}\)Therefore, the magnitude of the torque on the loop is 10.58 Nm
When negative charges concentrate at one end of an object that is made of a conducting material, the object is
Answers
ANSWER:
polarized
STEP-BY-STEP EXPLANATION:
When negative charges are concentrated at one end of an object that is made of a conductive material, this happens when the object is polarized.
Which statement describes what most likely occurs when a compass is placed next to a simple circuit made from a battery, a light bulb, and a wire?
A. A magnetic field created by the compass increases the current in the electrical circuit.
B. A magnetic field created by the compass causes the light bulb to stop working.
C. A magnetic field created by the electric current places negative charges on the compass.
D. A magnetic field created by the electric current causes the compass needle to move.
Answers
A magnetic field created by the electric current causes the compass needle to move. Option D is the correct answer.
When an electric current flows through a wire, it creates a magnetic field around the wire. The direction of the magnetic field is determined by the direction of the current. When a compass is placed next to the wire, the magnetic field created by the current causes the compass needle to move.
In a simple circuit made from a battery, a light bulb, and a wire, the electric current flows from the battery, through the wire, and through the light bulb, and then back to the battery. This creates a magnetic field around the wire, which can cause the compass needle to move when it is placed next to the wire. Hence, option D is correct choice.
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Is this conversion correct?
11.3g/ cm^3 to kg/ m^3
Since 1000 g = 1 kg and 100 cm = 1 m
Therefore, (11.3 x 1000)/ 100
= 113 kg/ m^3
Answers
11.3 g/cm³ equals to 1130 kg/m³.
What is density?The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol ρ, however Latin letter D may also be used. Density is calculated mathematically by dividing mass by volume.
Given that 11.3 g/cm³.
Know that
1000 grams = 1 kg
1 grams = 1/1000 kg.
100 cm = 1 m
1 cm = 1/100 m.
Therefore, 1 cm³ = (1/100)³ m³
= 1/1000000 m³
Hence, 1 g/cm³ = (1/1000) ÷ (1/1000000) kg/m³
= 1000000/1000 kg/m³
= 1000 kg/m³.
Hence, 11.3 g/cm³ = (11.3 × 1000) kg/m³
= 1130 kg/m³
Hence, 11.3 g/cm³ equals to 1130 kg/m³.
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The acceleration due to gravity on the moon is 1.6 2. If an astronaut weighs 96 N on
the moon, what is the astronaut's mass on Earth? (2 points)
Answers
Answer:
60kg
Explanation:
F= ma
96 = m ×1.6
m= 96/1.6
=60 kg
Radiation transfers
thermal
energy by
waves. These waves transfer energy from a warmer object to a cooler object, with or without
Answers
Answer:
Radiation travels by Waves!!
Explanation:
BONUS:Thermal radiation is a longitudinal wave.
Hope this helped
Answer:
Radiation transfers energy by ⇒ electromagnetic waves. These waves transfer energy from a warmer object to a cooler object, with or without ⇒ matter .
Explanation:
edge2022
a motorcycle covers a distance of 8.5 km in 15 minutes. Calculate the distance covered by the motorcycle in per second
Answers
1min=60sec
15min=60•15
15min=900sec
Now, let’s create a ratio. We want to find the unit rate (most simplified rate) of distance covered by the motorcycle.
Recall that d=s•t, where d=distance, s=speed, and t=time.
So, we know the distance is d=8.5 and the time is t=900sec, but we need the speed (“s”)
8.5km=(900sec)•s
Divide both sides by 900:
8.5km/900sec=s
.009km/sec=s
So, your answer is .009km/sec
A particular solid is an excellent conductor of thermal energy. Is it more likely to be a metal or a non-metal?
Answers
use e=mc^2 to calculate the power output of the sun. use the fact that the sun converts 4 millions of matter into energy. Please help
Answers
The sun produces 3.6 x 10^26 joules of energy every second
How to calculate power ?
Power is a measure of the rate at which work is done or energy is transferred. It is defined as the amount of energy transferred per unit time. The formula for calculating power is P = E/t, where P is power, E is energy, and t is time. In other words, power is the energy consumed or produced per unit time. For example, if a machine consumes 1000 Joules of energy in 10 seconds, its power output would be 100 Joules per second (P = 1000 J / 10 s). The unit of power is the Watt (W), which is equivalent to one Joule per second (1 W = 1 J/s). Power is a crucial concept in physics and engineering, as it is used to measure the efficiency of machines and energy systems.
To calculate the power output of the sun, we can use the formula E=mc^2, where E is the energy released, m is the mass converted to energy, and c is the speed of light.
Given that the sun converts 4 million tons of matter into energy every second, we can find the energy released per second as follows:
m = 4 million tons = 4 x 10^9 kg (1 ton = 1000 kg)
c = 3 x 10^8 m/s (speed of light)
E = mc^2 = (4 x 10^9 kg) x (3 x 10^8 m/s)^2 = 3.6 x 10^26 J/s
This is the power output of the sun, which is also known as its luminosity. Therefore, the sun produces 3.6 x 10^26 joules of energy every second
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place yourself facing the edge of an open door. position your feet astride the door with your nose and abdomen touching the door's edge. try to rise on your tiptoes. why can't this be done?
Answers
Answer:
It would not be possible to rise on your tiptoes in this position because of the principle of the conservation of angular momentum. When you try to rise on your tiptoes, your body will rotate around the axis formed by the edge of the door, which is perpendicular to the plane of the door. However, since your body is already in contact with the door, the door will prevent your body from rotating and your feet will stay fixed on the ground. Therefore, you will not be able to rise on your tiptoes in this position.
Explanation:
This exercise is impossible to do because it requires both strength and balance. The position of the body is unnatural and so it is difficult to maintain balance while lifting the toes up.
Additionally, the door’s edge provides no support and so the body cannot be stabilized in order to rise on the toes. Furthermore, the door’s edge is likely to be hard and uncomfortable to be in contact with and so it is difficult to concentrate and focus on the task of rising on the toes.
The exercise also requires a great deal of strength in the calves and legs, as well as in the core, in order to be able to lift the body up on the toes. Without the necessary strength, it is impossible to sustain the effort of rising on the toes, even if the balance and stability is successfully maintained.
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on this figure of a continental collision, which continent would have had subduction-related magmatism before the collision?
Answers
The continent on the right would have has subduction-related magmatism before the collision.
What does continental collision mean?Continental collision is a plate tectonic process that happens along convergent boundaries on Earth. Continental collision is a variation in subduction, in which the subduction zone is obliterated, mountains are formed, and two continents are sutured together. Continental collision is unique to this planet and provides a fascinating example of how our oceanic and continental crusts behave during subduction.
Continental collision is not an instantaneous process; it may take tens of millions of years for the faulting and folding produced by the collision to cease. The collision between India and Asia has been ongoing for over 50 million years and shows no signs of abating.
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Part E
List several examples of drag, elastic force, and tension force that you've observed in your life.
Answers
Various examples of drag, elastic and tension forces are mentioned.
What is elastic and tension force?Elastic force is a type of force that occurs when an object is stretched or compressed, and it resists the deformation of the object. This force is proportional to the amount of stretching or compression, and it causes the object to return to its original shape when the force is removed.
Tension force is a type of force that is transmitted through a string, rope, wire or cable when it is pulled tight by forces acting at either end. This force acts to transmit the tension through the length of the string, keeping it taut and preventing it from breaking.
What is an example of drag that is observed in life?A person biking into a headwind experiences air resistance, which is a type of drag force.
What is an example of elastic force observed in life?A stretched rubber band or a compressed spring both exhibit elastic force.
What is an example of tension force observed in life?A person pulling a wagon by a rope exerts a tension force on the rope. Another example of tension force can be observed when a weight is hung from a rope or chain, creating tension within the rope or chain.
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a train is sitting still at the top of 990-m mountain. it then coasts down the mountain and back up another mountain that is 520 m high. what is the train's speed at the top of the second hill?
Answers
Answer:
Explanation:
At the top of 520 m high mountain , the train will lose potential energy due to loss of height from 990 m to 520 m and gain kinetic energy .
Loss of height = 990 - 520 = 470 m
Loss of potential energy = m x g x 470 where m is mass of the train .
Gain of kinetic energy = 1/2 m v² where v is velocity of train at the top of 550 m high mountain .
1/2 m v² = m x g x 470
v² = 2 x 9.8 x 470
v = 95.98 m /s
How can you warm up for baseball?
Answers
A car is stationary. It accelerates at 0.8 ms^2
for 10 s and then at 0.4 ms^2
for a further 10 s. Use
the equations of motion to deduce the car’s final displacement. You will have to split the journey
into two parts, since the acceleration changes after 10 s.
Answers
Answer:
the car’s final displacement is 60 m
Explanation:
Given;
initail velocity of the car, u = 0
acceleration of the car, a = 0.8 m/s²
time of motion, t = 10 s
The first displacement of the car:
\(x_1 = ut + \frac{1}{2} at^2\\\\x_1 = 0 + \frac{1}{2} (0.8)(10)^2\\\\x_1 = 40 \ m\)
The second displacement of the car;
acceleration, a = 0.4 m/s², time of motion, t = 10 s
\(x_2 = ut + \frac{1}{2} at^2\\\\x_2 = 0 + \frac{1}{2} (0.4)(10)^2\\\\x_2 = 20 \ m\)
The final displacement of the car;
x = x₁ + x₂
x = 40 m + 20 m
x = 60 m
Therefore, the car’s final displacement is 60 m
A sledgehammer of mass m = 1.9 kg falls freely vertically downward from a height of h = 2.6 m at an initial speed of v = 11 m/s before striking a partially buried piling. After the blow the piling has moved d = 0.075 m deeper.How much kinetic energy, in joules, does the sledgehammer have just before striking the piling?
Answers
Answer:
Kinetic energy= 114.9J
Explanation:
Greetings !
Given values :-
mass= 1.9kg
height=2.6m
velocity= 11m/s
displacement (d)= 0.075m
Required value :-
Kinetic energy (KE)
Solution :-
Firstly, recall the Kinetic energy equation
\(ke = \frac{1}{2} mv {}^{2} \)
substitute known variables into the equation
\(ke = \frac{1}{2} (1.9)(11) {}^{2} \)
solve for Kinetic energy
\(ke = 114.9j\)
Hope it helps!!!
n moles of an ideal diatomic gas with internal energy E = =nRT are taken through the cyclic process shown on the P-V diagram where P1=2P3 and V2=2V3. V2 a) What are the values of work W, change in internal energy AEint, and heat transfer Q in process 1-2? Express your answers in terms of P3 and V3. b) What are the values of work W, change in internal energy AEint, and heat transfer Q in process 2-3? Express your answers in terms of P3 and V3. c) What are the values of work W, change in internal energy AEint, and heat transfer Q in process 3-1? Express your answers in terms of P3 and V3. d) Calculate the efficiency of the cycle.
Answers
a. Therefore, we have: ΔEint = 2P3(V1 - 2V3).
b. Q = ΔEint = (4/5)nCv(T2 - T3) = (4/5)nR(T2 - T3).
c. Therefore, we have: ΔT = T1 - T3 = (P1V1 - P3V3)/nR = (2P3V1 - P3V3)/nR = P3(V1 - V3)/nR and Q = ΔEint + W = nCv(T1 - T3) + 2P3(V1 - V3)
d. In step two of the process, the diatomic gas expands isobarically from volume V1 to volume V2, then cools isochronally from V2 to V3.
a. The work done in process 1-2 is given by:
W = P1(V2 - V1)
Since P1 = 2P3 and V2 = 2V3, we have:
W = 2P3(2V3 - V1)
The change in internal energy in process 1-2 is given by:
ΔEint = Q - W
Q = P1(V2 - V1) = 2P3(2V3 - V1)
b) In process 2-3, the gas is undergoing an isochoric heating from volume V3 to volume V2, followed by an isobaric compression from volume V2 to volume V1.
The work done in process 2-3 is zero since the volume is constant.
The change in internal energy in process 2-3 is given by:
ΔEint = Q - W
Since the process is isochoric, the heat transfer Q is given by:
Q = ΔEint = nCvΔT = nCv(T2 - T3)
PV = nRT
For a diatomic gas, we have:
Cv = (5/2)R/2 = (5/4)R
Substituting for P and V, we have:
Cv(T2 - T3) = (5/4)nR(T2 - T3) = (5/4)ΔEint
Therefore, we have:
Q = ΔEint = (4/5)nCv(T2 - T3) = (4/5)nR(T2 - T3)
c) In process 3-1, the gas is undergoing an isobaric compression from volume V3 to volume V1, followed by an isochoric heating from volume V1 to volume V2.
The work done in process 3-1 is given by:
W = P1(V1 - V3) = 2P3(V1 - V3)
The change in internal energy in process 3-1 is given by:
ΔEint = Q - W
Process is isochoric, the heat transfer Q is given by:
Q = ΔEint = nCvΔT = nCv(T1 - T3)
ΔT = T1 - T3
From the ideal gas law, we have:
PV = nRT
Substituting for P and V, we have:
T = PV/nR
Therefore, we have:
ΔT = T1 - T3 = (P1V1 - P3V3)/nR = (2P3V1 - P3V3)/nR = P3(V1 - V3)/nR
Q = ΔEint + W = nCv(T1 - T3) + 2P3(V1 - V3)
d) The efficiency of the cycle is given by:
η = (Wnet / QH) x 100%
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Two point charges each have a value of 3. 0 c and are separated by a distance of 4. 0 m. what is the electric field at a point midway between the two charges?
Answers
The electric field at the point midway between the two charges is zero.
The electric field at a point midway between two point charges can be determined using the principle of superposition. In this case, the two charges have a value of 3.0 C each and are separated by a distance of 4.0 m.
To calculate the electric field at the midpoint, we can consider each charge separately. Let's call the midpoint P.
1. The electric field due to the first charge:
- The distance from the first charge to P is half of the total separation distance, which is 2.0 m.
- Using Coulomb's law, the electric field due to the first charge is given by E1 = (k × q1) / r², where k is the electrostatic constant (9 × 10⁹ Nm²/C²), q1 is the value of the first charge (3.0 C), and r is the distance from the charge to the point (2.0 m).
- Plugging in the values, E1 = (9 × 10⁹ Nm²/C² × 3.0 C) / (2.0 m)².
2. The electric field due to the second charge:
- The distance from the second charge to P is also 2.0 m.
- Using Coulomb's law, the electric field due to the second charge is given by E2 = (k × q2) / r², where q2 is the value of the second charge (3.0 C).
- Plugging in the values, E2 = (9 × 10⁹ Nm^2/C² × 3.0 C) / (2.0 m)².
3. The total electric field at the midpoint:
- Since electric field is a vector quantity, we need to consider the direction of each electric field.
- The electric fields due to the two charges are in opposite directions (towards or away from each other).
- The magnitudes of the two electric fields are equal because the charges are identical.
- Therefore, the electric fields add up to zero at the midpoint P, resulting in a net electric field of zero.
In summary, the electric field at a point midway between two point charges with a value of 3.0 C each, separated by a distance of 4.0 m, is zero. This means that the electric field vectors due to the two charges cancel each other out at the midpoint.
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A rock is kicked horizontally off the edge of the cliff at a velocity of +15.0 m/s. If the canyon below is 80.0 m deep, how far from the edge of the cliff does the model rocket land?
Answers
Answer:
60.6 m
Explanation:
For vertical displacement of 80 m , initial velocity downwards u = 0
h = ut + 1/2 g t²
80 = 0 + 1/2 x 9.8 x t²
t = 4.04 s
During this period , rock will be displaced horizontally with uniform velocity .
horizontal displacement = 15 x 4.04 = 60.6 m .
answers At the beginning of 2019, Robotics Inc. acquired a manufacturing facility for $12.3 million. $9.3 million of the purchase price was allocated to the building. Depreciation for 2019 and 2020 was calculated using the straight-line method, a 20-year useful life, and a $1.3 million residual value. In 2021, the estimates of useful life and residual value were changed to 15 total years and $530,000, respectively.
Answers
Answer:
$613,077
Explanation:
Calculation for the depreciation on the building for 2021
First step is to calculate the depreciation expense for the year 2019 and 2020 using this formula
Depreciation expense = (Purchase price - Residual value) ÷ (Useful life)
Let plug in the formula
Depreciation expense= ($9,300,000 - $1,300,000) ÷ (20 years)
Depreciation expense= ($8,000,000) ÷ (20 years)
Depreciation expense= $400,000
Second step is to calculate the book value for the year 2021 using this formula
Book value = Purchase price - Depreciation expenses *2 years
Let plug in the formula
Book value= $9,300,000 - $400,000 × 2
Book value= $8,500,000
Last step is to calculate the depreciation for 2021 using this formula
2021 Depreciation=(Book value-Residual value)÷Useful life
2021 Depreciation= ($8,500,000 - $530,000) ÷ (15 years - 2 years)
2021 Depreciation=$7,970,000÷13 years
2021 Depreciation= $613,077
Therefore the depreciation on the building for 2021 will be $613,077