In a fit, a toddler throws straight down his favorite 2.5 kg toy with an initial velocity of 2.9 m/s.
What is the magnitude of the change in velocity of the toy from t = 0.15 seconds to t = 0.4 seconds?

Answers

Answer 1

The magnitude of the change in velocity of the toy from t = 0.15 seconds to t = 0.4 seconds is 2.9 m/s.

The magnitude of the change in velocity of the toy from t = 0.15 seconds to t = 0.4 seconds can be calculated using the following steps:

Step 1: Calculate the acceleration of the toy using the formula:

v = u + at

Where,

v = final velocity = 0 (because the toy comes to rest when it hits the ground)

u = initial velocity = 2.9 m/s

t = time taken = 0.4 s - 0.15 s = 0.25 s

a = acceleration

Substituting the given values,

0 = 2.9 + a(0.25)

Therefore, a = -11.6 m/s²

Step 2: Calculate the change in velocity using the formula:

∆v = a∆t

Where,

∆v = change in velocity

∆t = time interval = 0.4 s - 0.15 s = 0.25 s

Substituting the given values,

∆v = (-11.6 m/s²) x (0.25 s)

∆v = -2.9 m/s

Therefore, the magnitude of the change in velocity of the toy from t = 0.15 seconds to t = 0.4 seconds is 2.9 m/s.

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Related Questions

which forces are capable of affecting particles or objects from large distance

Answers

Answer:

only long-range force that affects all particles is the gravitational force.

Explanation:

In nature there are four fundamental forces: nuclear, weak, gravitational and electrical.

The last two are long-range, that is, the forces are zero for infinite distances, the current gravitational on all the particles and the electric one acts on the charged particles, without the chosen charge it is zero, the forces is also zero.

Consequently the only long-range force that affects all particles is the gravitational force.

An underlying theme of astronomy is that the...
a) fundamental physical laws differ randomly from galaxy to galaxy, but they can be learned for a given galaxy by detailed observation.
b) fundamental physical laws governing the universe change in a predictable way with increasing distance from Earth.
c) the universe is a hodgepodge of unrelated things behaving in arbitrary and unexplainable ways.
d) entire universe is governed by a single set of fundamental physical laws.

Answers

Answer:

d) entire universe is governed by a single set of fundamental physical laws.

Explanation:

Astronomy is the field of study that researches and studies about the objects beyond Earth. The phenomena occurring in the universe and their effects on the planet Earth are all death under the subject of astronomy. The discovery and the origin of the Earth, the heavenly bodies and their existence are covered under astronomy. The fundamental laws of the astronomy proves to be equivalent for all the bodies. These laws are universal that helps in the research of the science of universe.

what is the difference between copernicus and kepler description of planetary orbits?

Answers

Answer:

Kepler refined the Copernican model. Orbits are not circles along which planets move at a constant speed, but ellipses, in the central focus of which is the Sun. The planet moves in an ellipse with a variable speed depending on the distance to the Sun. On this basis, Kepler significantly simplified the Copernican model and formulated the laws of planetary motion in their orbits.

Discuss how directions fields and Euler's method are related. Draw the direction field and use Euler's method to approximate the solution at t = 10 using step size 1, for the initial value problem y'= -3y, y(0) = 5.

Answers

By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.

Euler's method is defined as a numerical technique which is  used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.

In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.

Step 1:

We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].

Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:

Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25

Step 2:

Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:

Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125

Thus,  by using Euler's method with two steps, the approximate value of Y(2) is 2.125.

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The complete question is

Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3

A cyclist cycle the rout in 3 h and 30 min. If he cycles 49 km, calculate her average speed.

Answers

Answer:

14 km/h

Explanation:

The average speed of the cyclist could be calculated by the following formula:

average speed = total distance/total time

                         = 49/3.5

                         = 14 km/h

Hope this helps!

Rank these quantites from greatest to least at each point: a) Momentum, b)KE, c)PE, Rank the scale readings from highest to lowest

Answers

The ranking from greatest to least at each point, without specific context or values, would be: Momentum - Greatest, Kinetic Energy - Greatest, Potential Energy - Greatest.

When considering the three points: momentum, kinetic energy (KE), and potential energy (PE), and without specific context or values, the ranking from greatest to least for each point would be as follows:

a) Momentum: Greatest, Middle, Least.

b) Kinetic Energy: Greatest, Middle, Least.

c) Potential Energy: Greatest, Middle, Least.

It's important to note that these rankings are based on a general understanding and can vary depending on the specific situation or system being considered.

The precise values and order of these quantities depend on factors such as mass, velocity, height, and other relevant variables, which may alter their relative magnitudes and rankings in a given scenario.

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Problem 27.20
The cornea of a normal human eye has an optical power of +42.0diopters.
Part A
What is its focal length?
ANSWER:

Answers

The focal length of the cornea can be calculated using the formula: 1/f = (n-1) x (1/R1 - 1/R2)
where f is the focal length, n is the refractive index of the cornea (assumed to be 1.38), and R1 and R2 are the radii of curvature of the front and back surfaces of the cornea, respectively.

Assuming the cornea is a spherical surface with a radius of curvature of 7.8 mm for the front surface and 6.5 mm for the back surface, we can plug in the values: 1/f = (1.38-1) x (1/7.8 - 1/6.5)
Solving for f, we get: f = 2.33 mm
Therefore, the focal length of the cornea of a normal human eye is approximately 2.33 mm.
Hello! I'd be happy to help you with your question.
The cornea of a normal human eye has an optical power of +42.0 diopters. To find the focal length, you can use the following formula:
Focal Length (f) = 1 / Optical Power
In this case, the Optical Power is 42.0 diopters. Therefore, the focal length is:
Focal Length (f) = 1 / 42.0 = 0.0238 meters, or 23.8 millimeters.
So, the focal length of the cornea in the human eye is approximately 23.8 millimeters.

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A spring is compressed between two blocks, one with a mass of 2 kg and the other with a mass of 3 kg. If the 2 kg block has an average acceleration of 6 m/s^2 when the spring acts on it, what will be the average acceleration of the 3 kg block???

Answers

Answer:

2=6

3=9

Explanation:

I think this is right I'm not sure but I have done problems like this and did based on what I remember.

The average acceleration of the 3 kg block is 4 m/s².

The given parameters;

mass of first block = 2 kgmass of second block = 3 kgacceleration of the first block, = 6 m/s/s

According to Newton's third law of motion, action and reaction are equal and opposite.

The force exerted on both blocks are equal and opposite.

\(F = ma\\\\m_1 a_1 = m_2a_2\\\\a_2 = \frac{m_1 a_1}{m_2}\\\\a _2 = \frac{2\times 6}{3} \\\\a_2 = 4 \ m/s^2\)

Thus, the average acceleration of the 3 kg block is 4 m/s².

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Question 28 Marks: 1 Radon is detected in a home through measurment ofChoose one answer. a. geiger rays b. beta particles c. alpha particles d. UV rays

Answers

The correct answer is c. alpha particles. Radon is a radioactive gas that can be found in homes and buildings. It is detected through the measurement of alpha particles, which are emitted by the decay of radon atoms.

This measurement is usually done using a device called a radon detector, which can provide an accurate reading of the radon levels in a home. It is important to regularly test for radon in order to ensure that the levels are safe for occupants.

Radon is detected in a home through the measurement of alpha particles.

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Is this statement true or false?

There are SEVEN days between a NEW MOON and a FIRST QUARTER MOON.

If its false than how many days are between a new moon and a first quarter moon?

Answers

Answer:True

Explanation:there are approximately 29.531 on the new moon and and 7.31 I think for the first quarter then it’s 7 days between them if u calculate their sped that light travels and that number it might be the same but the statement is true not false

Answer:

The full cycle of moon phases averages 29.531 days. A quarter of that is 7.38 days. So "7 days" is a pretty good approximation for casual conversation. It's true.

Explanation:

uh i think that was my explanation soooooo like yall have a good day and if you are working at 1am just know it is not gonna be so hard one day it is gonna get better hehe

Bumper car A (331 kg) moving east at 3.87 m/s hit stationary car B (208 kg). After, the car A moves .88 m/s east. What is the velocity of car B?

Answers

Answer:

Ub = 221.99m/s

Explanation:

(Ma x Ua)+(Mb x Ub) = (Ma + Mb)V

(331 x 3.87)+(208 x Ub) = (331 + 208)88

(1257.8) + (208 x Ub) = 47432

(208 x Ub) = 47432 - 1257.8

(208 x Ub) = 46174.2

Ub = 46174.2/208 = 221.99m/s

Ub = 221.99m/s

Answer:

4.75

Explanation:

M1V1 + M2V2 = M1V3 + M2V4

[(331*3.87) , 90°] + 0 = [(331*0.888) , 90°] + M2V4

M2V4 = 987.042 , 90°

divide through by M2

V4 = 4.75 m/s east

A kangaroo jumps straight up with an initial vertical velocity 2. 4 m/s we want to find the maximum height of the jump we can ignore air resistance

Answers

A kangaroo jumps straight up with an initial vertical velocity 2. 4 m/s we want to find the maximum height of the jump we can ignore air resistance. Hence, maximum height of the kangaroo is 29 cm.

Kinetic formula (D) v^2 = v_o^2 + 2a Δx would be most useful here.

All things are drawn to the Earth by an unseen force of attraction. The term gravity or gravitational pull is used to describe this force of attraction. You may have noticed that if you toss something upward, it rises to a certain height before crashing to the ground.

Here, the kangaroo jumps straight with initial vertical velocity v_0 = 2.4 m/s.

When it obtains maximum height, its final velocity v = 0 m/s.

And, acceleration due to gravity acts downwards, that is, opposite to the direction of kangaroo's jumping. so, acceleration of it, a = - g = - 9.8 m/ s^2.

From equation (D), we can write,

v^2 = v_o^2 + 2a Δx

= + 2a Δx

= 0^2 = 2.4^2 + 2 .(-9.8). Δx

= Δx = 2.4^2 /(2*9.8)

=0.29 m.

= 29 cm.

Hence, maximum height of the kangaroo is 29 cm.

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Complete question is:

A kangaroo jumps straight up with an initial vertical velocity of 2.4m/s. We want to find the maximum height of the jump. We can ignore air resistance. Which kinematic formula would be most useful to solve for the target unknown?

Excitation of vibrational motion of molecules is associated with which region of the electromagnetic spectrum?.

Answers

Excitation of the vibrational motion of molecules is associated with the microwave region of the electromagnetic spectrum.

The electromagnetic spectrum due to the vibrational motion of the molecules will lie inside the microwave region. as a result, inside the microwave region of the electromagnetic spectrum, the vibrational movement of the molecules will deliver an upward push to absorption.

The electromagnetic (EM) spectrum is the range of all varieties of EM radiation. Radiation is the power that travels and spreads out as it is going – the visible light that comes from a lamp in your property and the radio waves that come from a radio station are two forms of electromagnetic radiation.

Electromagnetic radiation is made while an atom absorbs power. The absorbed energy causes one or extra electrons to exchange their locale in the atom. when the electron returns to its unique role, an electromagnetic wave is produced.

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A spherical balloon has a radius of 7,15 m and is filled with helium. How large a cargo can it lift l, assuming that the skin and structure of the balloon have a mass of 930 kg

Answers

Answer:

The lifting force of a balloon is equal to the weight of the air it displaces, minus the weight of the balloon itself and any cargo it is carrying. We can calculate the lifting force using the following formula:

Lifting force = (4/3) x π x r^3 x ρair x g - m_balloon - m_cargo

where:

- r is the radius of the balloon (in meters)

- ρair is the density of air (in kg/m^3), which we'll assume is 1.2 kg/m^3 at sea level and standard temperature

- g is the acceleration due to gravity (in m/s^2), which we'll assume is 9.81 m/s^2

- m_balloon is the mass of the balloon (in kg)

- m_cargo is the mass of the cargo (in kg)

- π is pi (approximately 3.14)

Substituting in the values given in the problem, we get:

Lifting force = (4/3) x π x (7.15 m)^3 x (1.2 kg/m^3) x 9.81 m/s^2 - 930 kg - m_cargo

Simplifying and solving for m_cargo, we get:

m_cargo = (4/3) x π x (7.15 m)^3 x (1.2 kg/m^3) x 9.81 m/s^2 - 930 kg - Lifting force

Plugging in the lifting force we want the balloon to have, which we'll call L, we get:

m_cargo = (4/3) x π x (7.15 m)^3 x (1.2 kg/m^3) x 9.81 m/s^2 - 930 kg - L

Assuming we want the balloon to lift 5000 kg of cargo, we can solve for L:

L = (4/3) x π x (7.15 m)^3 x (1.2 kg/m^3) x 9.81 m/s^2 - 930 kg - 5000 kg

L = 281,581 N

Therefore, to lift 5000 kg of cargo, the balloon needs to have a lifting force of approximately 281,581 N.

What type of interaction allows the sidewalk to heat up and cook the egg? absorption diffraction reflection transmission

Answers

By the processes of heat transfer, the sidewalk absorbs heat by radiation and cooks the egg.

What is heat energy?

Heat energy is a form of energy that is due to difference in temperature between two bodies.

Heat energy always flow from hotter to colder bodies

The processes of heat transfer include;

conductionconvectionradiation

The sidewalk absorbs heat by radiation and cooks the egg.

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Answer:

absorption

Explanation:

HELPPPPPP

The free body diagram for an object is drawn below. Calculate the net force acting on the object. If this object is 10 kg, how/where will it accelerate

HELPPPPPPThe free body diagram for an object is drawn below. Calculate the net force acting on the object.

Answers

Answer:

sowi d ko po knows hehe need ko lang po ng points

Explanation:

hope u understand

An airplane travels for 2.5 hours at an average rate
of 130 miles per hour. Use the distance formula, d=rt, to find how
far the plane travels.

Answers

The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.

To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.

Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.

Using the formula, we can calculate the distance traveled as follows:

d = rt

d = 130 mph × 2.5 hours

Multiplying the rate (130 mph) by the time (2.5 hours) gives us:

d = 325 miles

Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.

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Mess Me and You will have nonsense Explain how this riddle relates to mutation in DNA

Answers

Deoxyribonucleic acid is a polymer composed of two polynucleotide chains that coil around each other to form a double helix.

What makes a nonsense mutation nonsense?

A nonsense mutation occurs in the DNA when a sequence changes itself and gives rise to a stop codon rather than a codon specifying an amino acid. The presence of the new stop codon results in the production of a shortened protein that is non-functional.

A nonsense mutation is also known as base substitution which results in a stop codon in such a position from where there was not one before, which causes the premature termination of protein synthesis and, more than likely, a complete loss of function in the finished protein.

So we can conclude that a nonsense mutation always causes a loss of amino acids.

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A physicist observes that a cannonball shot horizontally from a cannon travels 1.000 m before falling to the ground. Which of the following statements correctly explains this observation using Newton's laws?
O Objects tend to remain in the state of motion they are in unless acted upon by an unbalanced force. Friction and gravity acted on the cannonball, slowing it down and slamming it into the ground
O Objects at rest tend to remain in their cument state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion
The force on the cannonball produced by the cannon was less than the force of friction on the cannonball, causing the cannonball to slow down and fall to the ground.
O The force on the cannonball produced by the cannon exactly equaled the force of friction on the cannonball, balancing the forces and causing it to fall to the ground.

Answers

The correct statement that explains the observation using Newton's laws is objects at rest tend to remain in their current state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion. Here option A is correct.

According to Newton's first law of motion, an object will continue moving at a constant velocity in a straight line unless acted upon by an external force. In this case, when the cannonball is shot horizontally from the cannon, it initially possesses a forward velocity due to the force applied by the cannon. However, once the cannonball is in motion, the only forces acting on it are gravity and friction.

Gravity acts vertically downward, causing the cannonball to accelerate downward. Friction acts horizontally in the opposite direction to the motion of the cannonball. As the cannonball moves forward, friction opposes its motion and gradually slows it down.

Since there is no force continuously propelling the cannonball forward, and the forces of friction and gravity act on it, the cannonball eventually comes to a stop and falls to the ground. Hence option A is correct.

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A 178g sample of some unknown material is heated to 94. 0c. It is placed in a perfectly insulated container along with 136g of water at an initial temperature of 26C. After a short time, the temperature of both the material and water become equal at 35C. The specific heat of water is 4. 18 J/g in this temperature rang. What is the specific heat capacity of the material?

Answers

The specific heat capacity of the material is approximately -0.471 J/g°C.

How to find the specific heat capacity

To solve this problem, we can use the principle of conservation of energy. The heat gained by the water is equal to the heat lost by the unknown material.

The formula to calculate the heat gained or lost by a substance is:

Q = m * c * ΔT

Where:

Q is the heat gained or lost

m is the mass of the substance

c is the specific heat capacity of the substance

ΔT is the change in temperature

In this case, the heat gained by the water is equal to the heat lost by the material. We can set up the following equation:

m_water * c_water * ΔT_water = m_material * c_material * ΔT_material

Given:

m_water = 136 g

c_water = 4.18 J/g°C

ΔT_water = (35°C - 26°C) = 9°C

m_material = 178 g

ΔT_material = (35°C - 94°C) = -59°C (negative because the material lost heat)

Substituting the values into the equation:

136 g * 4.18 J/g°C * 9°C = 178 g * c_material * -59°C

Simplifying the equation:

4949.44 J = -10502 g°C * c_material

Dividing both sides of the equation by -10502 g°C:

c_material = 4949.44 J / -10502 g°C

Calculating the value:

c_material ≈ -0.471 J/g°C

The specific heat capacity of the material is approximately -0.471 J/g°C. The negative sign indicates that the material releases heat as it cools down, which is consistent with the given information that the material lost heat.

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The 200-mm test tube also contained some water (besides the metal) that was subsequently added to the calorimeter (in Part A.4.). Considering a higher specific heat for water, will the temperature change in the calorimeter be higher, lower, or unaffected by this technique error?

Answers

Answer:

The temperature  change in the calorimeter will be lower

Explanation:

Water is an example of a molecular substance. They have relatively low melting points and boiling points usually below 300° C . Water reacts with metals to a degree varying with their position in the electrochemical series.

The specific heat of water is 4179.6 Joules which is relatively high . This typically implies that water absorbs a larger amount of heat but the increase in temperature of its boiling points is relatively low. Thus; in the 200-mm test tube that contains water and was subsequently added to the calorimeter , the heat present was initially absorbed by the water and that does not result to an increase in the temperature change in the calorimeter. Thus the temperature change in the calorimeter will be lower.

find the resistance of a 0.85 km length of such wire used for power transmission in ω.

Answers

Resistance of 0.85 km length of wire used for power transmission in ω can be found using the following steps:Given data:Length of wire, L = 0.85 km = 850 m.

Cross-sectional area of wire, A = 7.5 × 10-7 m2.Using the formula,R = (ρL)/AWhere, R is the resistance of the wire, L is the length of the wire, A is the cross-sectional area of the wire, and ρ is the resistivity of the wire.Resistivity of the wire can be calculated using the formula,ρ = RA/LWhere, ρ is the resistivity of the wire, R is the resistance of the wire, A is the cross-sectional area of the wire, and L is the length of the wire.

Substituting the given values in the formula,

ρ = (RA)/L

= (7.5 × 10-7 × R)/850ρ

= R/(1133333.33)R

= ρ × L/A

= ω × L/A (since ω is the unit of resistivity)

Now, substituting the given values in the formula,R = 0.0174 ω (approximately)Therefore, the resistance of a 0.85 km length of wire used for power transmission in ω is approximately 0.0174 ω.

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When pushing on a wall while wearing skates, what provides the force that causes you to accelerate away from the wall?

Answers

Vision and there lies

a 25.0 μf capacitor is charged to a potential difference of 850 v . the terminals of the charged capacitor are then connected to those of an uncharged 8.00 μf capacitor.

Answers

(A) the original charge of the system is 21,250 μC. (B)  the final potential difference across the capacitor is 850 V. (C) The final energy of the system is 11,740,750 μJ.

To compute the original charge of the system, we can use the formula;

Q = C × V

where Q will be the charge, C will be the capacitance, and V will be the potential difference.

For the 25.0 μF capacitor charged to 850 V;

Q₁ = C₁ × V₁

= (25.0 μF) × (850 V)

Q1 = 21,250 μC

Therefore, the original charge of the system is 21,250 μC.

When the charged capacitor is connected in parallel to the uncharged capacitor, the potential difference across both capacitors becomes equal. This means the final potential difference across the capacitors will be the same as the initial potential difference of the charged capacitor, which is 850 V.

Therefore, the final potential difference across the capacitor is 850 V.

The energy stored in a capacitor can be calculated using the formula:

E = 0.5 × C × V₂

where E will be the energy, C will be the capacitance, and V will be the potential difference.

For the 25.0 μF capacitor with a potential difference of 850 V:

E₁ = 0.5 × C1 × V1²

= 0.5 × (25.0 μF) × (850 V)²

E₁ = 9,018,750 μJ

For the 8.00 μF capacitor with a potential difference of 850 V:

E₂ = 0.5 × C₂ × V2²

= 0.5 × (8.00 μF) × (850 V)²

E2 = 2,722,000 μJ

The final energy of the system is the sum of the energies of both capacitors;

E_final = E₁ + E₂

= 9,018,750 μJ + 2,722,000 μJ

E_final = 11,740,750 μJ

Therefore, the final energy of the system is 11,740,750 μJ.

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--The given question is incomplete, the complete question is

"A 25.0 μf capacitor is charged to a potential difference of 850 v . the terminals of the charged capacitor are then connected to those of an uncharged 8.00 μf capacitor. A) compute the original charge of the system B)compute the final potential difference across the capacitor C)compute the final energy of the system."--

Force 1: The force which pulls objects towards the surface of a planet.
Force 2: The force which attracts iron nails towards a magnet.
Which statement is true about the forces?
Force 1 describes gravitational force, which is a contact force. Force 2 describes
magnetic force, which is a non-contact force.
Force 1 describes gravitational force, which is a contact force. Force 2 describes
magnetic force, which is a contact force.
Force 1 describes gravitational force, which is a non-contact force. Force 2 describes
magnetic force, which is a non-contact force.
Force 1 describes gravitational force, which is a non-contact force. Force 2 describes
magnetic force, which is a contact force.

Answers

Answer: Friction is an important thing in life and we use it to move things or friction is used on us.

Explanation: Friction happens when you rub against something or when someone or something rubs against you.

A current of 0.2 A flows through a conductor for 5minutes. How much charge would have passed through the conductor?​

Answers

As we know,

\(electric \: \: current = \dfrac{charge}{time} \)

so, let's solve for charge (q) :

time = 5 minutes = 5 × 60 seconds = 300 seconds.

\(0.2 = \dfrac{q}{300} \)

\(q = 300 \times 0.2\)

\(q = 60\)

hence, the charge = 60 coulombs (C)

A double-concave lens has equal radii of curvature of 15.1 cm. An object placed 14.2 cm from the lens forms a virtual image 5.29 cm from the lens. What is the index of refraction of the lens material?
a) 1.77
b) 1.90
c) 1.82
d) 1.98

Answers

A double-concave lens has equal radii of curvature of 15.1 cm. An object placed 14.2 cm from the lens forms a virtual image 5.29 cm from the lens. 1.90 is the index of refraction of the lens. Therefore, the correct option is option B.

A lens's index of refraction is a measurement of how much light passing through it may be bent relative to the speed of light in a vacuum. It is a crucial component of a lens since it affects how well it can concentrate light and produce images. A lens's index of refraction might change based on the kind of material that was used to make it. Glass, plastic, and crystal are examples of frequently encountered materials with high indexes of refraction. A lens can be made narrower while yet having the same optical power the higher its index of refraction. Typically, a lens's index of refraction is indicated by the letter "n."

\($\frac{1}{f} = (n-1)\left(\frac{1}{R_1}-\frac{1}{R_2}+\frac{(n-1)d}{nR_1 R_2}\right)$\)

\($\frac{1}{f} = (n-1)\left(-\frac{2}{|R|}\right)$\)

\($n-1 = -\frac{1}{2}\left(\frac{1}{f}\right)\left(\frac{|R|}{15.1\text{ cm}}\right)$\)

\($\frac{1}{f} = \frac{1}{d_o}+\frac{1}{d_i}$\)

\($\frac{1}{f} = \frac{1}{14.2\text{ cm}}-\frac{1}{5.29\text{ cm}}\)

\(= -0.0983\text{ cm}^{-1}$\)

\($n-1 = \frac{1}{2}(0.0983\text{ cm}^{-1})(1.00)\)

\(= 1.90\)

n = 1.90

Therefore, the correct option is option B.

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If an object is moving at 5m/s north and an balanced force is acting on it, it will continue to move at that same velocity.

Answers

Answer:An object having balanced forces definitely cannot be accelerating.

Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 1,510 liters has an internal pressure of 1.20atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 253atm pushing on it, how big will that bubble be? You must show your work to receive full credit.

Answers

1500 I think so but I not sure

The volume should be 7.16 L

Boyles law:

Since there is a submarine with a volume of 1,510 liters has an internal pressure of 1.20atm. Also, there should be a pressure of 253atm pushing on it.

Here we used the Apply boyles law

So,

1510*1.20 = volume *253

So, the volume should be 7.16 L

hence, the volume is 7.16 L

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When a pot of water sits on a hot stove the metal is He did and then transferred into heat to the world of student claims that conduction is the only type feet transfer occurring which statement explains why the students idea is incorrect

Answers

Answer:

Hello your question is poorly written hence I will just give the difference between conduction and convection

answer :

Conduction occurs when there is direct contact between solids and source of heat. while convection occurs when there is transfer of thermal energy due to movement of liquid or gas

Explanation:

when a pot of water is placed on a hot stove the pot is heated through conduction because the metal pot is in direct conduct with the heat from the stove ( which is the primary source of heat in this scenerio ).

while the heat transfer from the hot pot to the water is executed through convection this is because heat transfer via convection requires the movement of liquid or gas.  as the warmer liquid moves over to the top the cooler liquid goes below inside the pot that way the whole liquid becomes warm .

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