In 88 minutes, he uses 132 balloons to make 22 identical balloon sculptures. How many minutes does it take to make one balloon sculpture? How many balloons are used in one sculpture?

Answers

Answer 1

Answer:

a) How many minutes does it take to make one balloon sculpture?

= 4 minutes

b) How many balloons are used in one sculpture?

= 6 balloons

Step-by-step explanation:

In 88 minutes, he uses 132 balloons to make 22 identical balloon sculptures.

a) How many minutes does it take to make one balloon sculpture?

22 identical balloon sculptures = 88 minutes

1 balloon sculpture = x

x = 88 minutes/22

x = 4 minutes

b) How many balloons are used in one sculpture?

22 balloon sculptures = 132 balloons

1 balloon sculpture = x

Cross Multiply =

22x = 132 balloons

x = 132 balloons/22

x = 6 balloons


Related Questions

what is 2x2 (im in college)

Answers

Answer:

4

Step-by-step explanation:

hope this helps lol

let x and y be two independent random variables with distribution n(0,1). a. find the joint distribution of (u,v), where u

Answers

To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v)

The joint distribution of (u, v), where u and v are defined as

\(u = \frac{x}{{\sqrt{x^2 + y^2}}}\)  and \(v = \frac{y}{{\sqrt{x^2 + y^2}}}\), is given by:

\(f_{U,V}(u,v) = \frac{1}{{2\pi}} \cdot e^{-\frac{1}{2}(u^2 + v^2)}\)

To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v):

\(J = \frac{{du}}{{dx}} \frac{{du}}{{dy}}\)

\(\frac{{dv}}{{dx}} \frac{{dv}}{{dy}}\)

Substituting u and v in terms of x and y, we can evaluate the partial derivatives:

\(\frac{{du}}{{dx}} &= \frac{{y}}{{(x^2 + y^2)^{3/2}}} \\\frac{{du}}{{dy}} &= -\frac{{x}}{{(x^2 + y^2)^{3/2}}} \\\frac{{dv}}{{dx}} &= -\frac{{x}}{{(x^2 + y^2)^{3/2}}} \\\frac{{dv}}{{dy}} &= \frac{{y}}{{(x^2 + y^2)^{3/2}}}\)

Therefore, the Jacobian determinant is:

\(J &= \frac{y}{{(x^2 + y^2)^{\frac{3}{2}}}} - \frac{x}{{(x^2 + y^2)^{\frac{3}{2}}}} \\&= -\frac{x}{{(x^2 + y^2)^{\frac{3}{2}}}} + \frac{y}{{(x^2 + y^2)^{\frac{3}{2}}}} \\J &= \frac{1}{{(x^2 + y^2)^{\frac{1}{2}}}}\)

Now, we can find the joint density function of (u, v) as follows:

\(f_{U,V}(u,v) &= f_{X,Y}(x,y) \cdot \left|\frac{{dx,dy}}{{du,dv}}\right| \\&= f_{X,Y}(x,y) / J \\&= f_{X,Y}(x,y) \cdot (x^2 + y^2)^{\frac{1}{2}}\)

Substituting the standard normal density function

\(f_{X,Y}(x,y) &= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(x^2 + y^2)} \\f_{U,V}(u,v) &= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(x^2 + y^2)} \cdot (x^2 + y^2)^{\frac{1}{2}} \\&= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(u^2 + v^2)}\)

Therefore, the joint distribution of (u, v) is given by:

\(f_{U,V}(u,v) &= \frac{1}{2\pi} \cdot \exp\left(-\frac{1}{2}(u^2 + v^2)\right)\)

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To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v)

The joint distribution of (u, v) is a bivariate normal distribution with mean (0,0) and variance-covariance matrix

\(\begin{bmatrix}2 & 0 \0 & 2\end{bmatrix}\)

The joint distribution of (u, v) can be found by transforming the independent random variables x and y using the following formulas:

\( u = x + y\)
\( v = x - y \)

To find the joint distribution of (u, v), we need to find the joint probability density function (pdf) of u and v.

Let's start by finding the Jacobian determinant of the transformation:

\(J = \frac{{\partial (x, y)}}{{\partial (u, v)}}\)

\(= \frac{{\partial x}}{{\partial u}} \cdot \frac{{\partial y}}{{\partial v}} - \frac{{\partial x}}{{\partial v}} \cdot \frac{{\partial y}}{{\partial u}}\)

\(= \left(\frac{1}{2}\right) \cdot \left(-\frac{1}{2}\right) - \left(\frac{1}{2}\right) \cdot \left(\frac{1}{2}\right)\)

\(J = -\frac{1}{2}\)

Next, we need to express x and y in terms of u and v:

\(x = \frac{u + v}{2}\)

\(y = \frac{u - v}{2}\)

Now, we can find the joint pdf of u and v by substituting the expressions for x and y into the joint pdf of x and y:

\(f(u, v) = f(x, y) \cdot |J|\)

\(f(u, v) = \left(\frac{1}{\sqrt{2\pi}}\right) \cdot \exp\left(-\frac{x^2}{2}\right) \cdot \left(\frac{1}{\sqrt{2\pi}}\right) \cdot \exp\left(-\frac{y^2}{2}\right) \cdot \left|-\frac{1}{2}\right|\)

\(f(u, v) = \frac{1}{2\pi} \cdot \exp\left(-\frac{u^2 + v^2}{8}\right)\)



Therefore, the joint distribution of (u, v) is given by:

\(f(u, v) = \frac{1}{2\pi} \cdot \exp\left(-\frac{{u^2 + v^2}}{8}\right)\)



In summary, the joint distribution of (u, v) is a bivariate normal distribution with mean (0,0) and variance-covariance matrix

\(\begin{bmatrix}2 & 0 \0 & 2\end{bmatrix}\)


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I need help with this question ​

I need help with this question

Answers

Step-by-step explanation:

30-10= 20

20 more students prefer cashews than walnuts.

Answer:

20

Step-by-step explanation:

30-10 = 20

Identify the unit rate in the graph.
(show work)

Identify the unit rate in the graph.(show work)

Answers

Answer:

it is b because if you count the points it 11 of them

Step-by-step explanation:

a television station shows commercials for 1312 minutes each hour. how many 45-second commercials can it show? enter your answer in the box. commercials

Answers

The number of 45-second commercials can it show, based on the given informations and values provided, it is calculated to show approximately 1749 number of 45-second commercials each hour.

There are 60 seconds in a minute, so there are 60/45 = 4/3 45-second commercials in a minute.

If the television station shows commercials for 1312 minutes each hour, then in one hour, it can show 1312 x 4/3 = 1749.33... 45-second commercials.

Since it's not possible to show a fraction of a commercial, we need to round the result to the nearest whole number.

Therefore, the television station can show approximately 1749 number of 45-second commercials each hour.

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Please I need somone's help with this problem

Please I need somone's help with this problem

Answers

Answer:

wich problem i see multiple ?

Write and solve an inequality to find the values of x for which the perimeter of the rectangle is less
than 140.

Write and solve an inequality to find the values of x for which the perimeter of the rectangle is lessthan

Answers

The value of x for which the perimeter of the rectangle is less than 140 is,

x ≤ 33.

What is an inequality?

In mathematics, "inequality" refers to a relationship between two expressions or values that are not equal to each other. To solve the inequality, you may multiply or divide each side by the same positive number, add the same amount to each side, take the same amount away from each side, and more. You must flip the inequality sign if you multiply or divide either side by a negative number.

Given:

A rectangular shape with sides x + 4 and x.

And the perimeter of the rectangle is less than 140.

That means,

2(2x + 4) ≤ 140

4x + 8 ≤ 140

4x ≤ 140 -8

4x ≤ 132

x ≤ 33

Therefore, the solution of the inequality is x ≤ 33.

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Please help me! Please!

Please help me! Please!

Answers

Answer:

here is your aneswer

the answer. will be 40

a student can study 0, 1, or 2 hours for a history test on any given night. how many different ways can she study a total of 3 hours for the test on three consecutive nights?

Answers

The number of ways to study for 3 hours for 3 nights is 7.

i.e

(0, 1, 2), (0, 2, 1), (1, 0, 2), (1, 2, 0), (1, 1, 1), (2, 0, 1), (2, 1, 0)

What is a combination?

It is an arrangement of a set of numbers from a total set where the order of the set is not relevant.

We have,

Number of study hours = 3

Number of days = 3

Types of hours.

= 0, 1, and 2

The number of ways to study for 3 hours for 3 nights.

= (0, 1, 2), (0, 2, 1), (1, 0, 2), (1, 2, 0), (1, 1, 1), (2, 0, 1), (2, 1, 0)

Thus,

The number of ways to study for 3 hours for 3 nights is 7.

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ow many groups of
1
5
5
1

start fraction, 1, divided by, 5, end fraction are in
4
44?

Answers

By the calculations below, there are 20 groups of 1/5 in 4.

Division of Fractions: Finding Groups

To find out how many groups of 1/5 are in 4, we can use the concept of division of fractions.

Recall that dividing by a fraction is the same as multiplying by its reciprocal. So, we can rewrite the problem as:

4 ÷ 1/5

To find the reciprocal of 1/5, we flip the fraction:

1/5 → 5/1

Now, we can rewrite the division problem as multiplication:

4 ÷ 1/5 = 4 × 5/1

Multiplying across gives:

4 × 5/1 = 20

Therefore, there are 20 groups of 1/5 in 4.

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ANSWER QUICKLY PLEASE!!

a credit card company charges a 4% balance transfer fee. If you want to transfer a balance of 2,100 to this credit card what fee would you pay?


a) $40

b) $84

c) $400

d) $840

Answers

For the fee,4/100*2100=84
The fees=84

an outlier in a data set can significantly affect the value of the mean but not the median. True or False

Answers

The required statement "outlier in a data set can significantly affect the value of the mean but not the median" is true.

What is mean?

The average of a group of variables is referred to as the mean in mathematics and statistics. There are several methods for calculating the mean, including simple arithmetic means (adding the numbers together and dividing the result by the number of observations), geometric means, and harmonic means.

According to question:

The average of a group of variables is referred to as the mean in mathematics and statistics.

There are several methods for calculating the mean, including simple arithmetic means (adding the numbers together and dividing the result by the number of observations), geometric means, and harmonic means.

Thus, given statement is true.

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Find the mean, median, and mode of the following data set

17, 18, 13, 15, 12, 11, 35, 18, 14

Answers

Answer: Mean- 17

Median- 15

Mode- 18

Step-by-step explanation: Your welcome. Branliest, please.

What figurative language is this. Please help:
“We lay down our arms so we can reach out our arms to one another.”

Answers

Answer:

This sounds like a classic case of a homophone!

A homophone refers to the figurative speech which occurs when two words are spelled the same and they sound the same, but they have different meanings!

Hope this helped!

which one of the following is NOT a polynomial option 1. x^2-2x+3 option 2. 11x-9. option 3. 3/y

which one of the following is NOT a polynomial option 1. x^2-2x+3 option 2. 11x-9. option 3. 3/y

Answers

Answer:

option 3

Step-by-step explanation:

A car moving at a constant speed travels 78 feet in 2 seconds. How many feet will it travel in 60 seconds?

Answers

Answer:

2340 ft.

Step-by-step explanation:

Step 1:

78 : 2       Ratio

Step 2:

39 : 1        Convert

Step 3:

39 × 60     Multiply

Answer:

2340 ft.

Hope This Helps :)

a box has a width of 15 inches and a length of 16 inches. the volume of the box is increasing at a rate of 569 cubic inches per second, with the width and length being held constant. what is the rate of change, in inches per second, of the height when the height is 6 inches?

Answers

The rate of change in height when height is 6 inches is 2.37 inches per second approximately.

We know that the volume of cube with length L, width W and height H is given by,

V = L*B*H

So given that the length is 15 inches

the width is 16 inches

Let the height be h inches.

So now the volume is given by,

V = 15*16*h

Differentiating the volume with respect to time 't' we get,

dV/dt = 15*16 dh/dt

Now given that the rate of change in volume per second is 569 cubic inches.

So, dV/dt = 569

So, 15*16 dh/dt = 569

dh/dt = 569/(15*16) = 569/240 = 2.37 (approx)

So the rate of change in height is 2.37 inches approximately.

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(x + 3)(x^2 - 5x + 7)
write in standard form once you find answer.

(x + 3)(x^2 - 5x + 7)write in standard form once you find answer.

Answers

Answer is:

x^3-2x^2-8x+21

PLEASE LOOK AT THE PICTURE I NEED HELP ASAP!!

PLEASE LOOK AT THE PICTURE I NEED HELP ASAP!!

Answers

Answer:

D. 2-i

Step-by-step explanation:

:)

math

Answer:

B, 2+i

Step-by-step explanation:

I hope this helps.

Ex. 900. x(t)= C0 + C1*sin(w*t+theta1) + C2*sin(2*w*t+theta2)
x(t)= A0 + A1*cos(w*t) + B1*sin(w*t) + A2*cos(2*w*t) + B2*sin(2*w*t)
A0= 2, A1=-8, B1=-7, A2=-2, B2=-7, w=600 rad/sec.
Express all angles between plus and minus 180 degrees.
Determine C0, C1, theta1 (deg), C2, theta2 (deg)

Answers

The final values of the angles are:

C0 = A0 = 2

C1 = B1 = -7

theta1 = 0 degrees

C2 = B2 = -7

theta2 = 0 degrees

Here, we have,

To determine the values of C0, C1, theta1 (in degrees), C2, and theta2 (in degrees), we need to match the given expressions for x(t) with the given values for A0, A1, B1, A2, B2, and w.

Comparing the expressions:

x(t) = C0 + C1sin(wt+theta1) + C2sin(2wt+theta2)

x(t) = A0 + A1cos(wt) + B1sin(wt) + A2cos(2wt) + B2sin(2w*t)

We can match the constant terms:

C0 = A0 = 2

For the terms involving sin(wt):

C1sin(wt+theta1) = B1sin(w*t)

We can equate the coefficients:

C1 = B1 = -7

For the terms involving sin(2wt):

C2sin(2wt+theta2) = B2sin(2wt)

Again, equating the coefficients:

C2 = B2 = -7

Now let's determine the angles theta1 and theta2 in degrees.

For the term C1sin(wt+theta1), we know that C1 = -7. Comparing this with the given expression, we have:

C1sin(wt+theta1) = -7sin(wt)

Since the coefficients match, we can equate the arguments inside the sin functions:

wt + theta1 = wt

This implies that theta1 = 0.

Similarly, for the term C2sin(2wt+theta2), we have C2 = -7. Comparing this with the given expression, we have:

C2sin(2wt+theta2) = -7sin(2w*t)

Again, equating the arguments inside the sin functions:

2wt + theta2 = 2wt

This implies that theta2 = 0.

Therefore, the final values are:

C0 = A0 = 2

C1 = B1 = -7

theta1 = 0 degrees

C2 = B2 = -7

theta2 = 0 degrees

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1. Differentiate the function f(x) = ln (81 sin^2 (x)) f’(x) 2. Differentiate the function P(t) = in ( √t2 + 9) p' (t) 3. if x2 + y2 + z2 = 9, dx/dt = B, and dy/dt = 4, find dz/dt when (x,y,z) = (2,2,1)
dz/dt =

Answers

First you will get 4dz

Can I have help with this question

Can I have help with this question

Answers

Answer:

a) 450,000,000,000  (450 Billion)

b) 3500

Step-by-step explanation:

a) (5 x 9) · 10^(3+7)

   45 x 10^10

b) (7 ÷ 2) · 10^5-2

   3.5 x 10^3

Answer:

a) 45,000,000,000,000

b) 3,500

Step-by-step explanation:

Where there is an exponent and the base is 10, the exponent is how many zeros to add to the end of the number.

a) (5x10,000)x(9x100,000,000)

50,000x900,000,000

45,000,000,000,000

b)(7x1,000,000)/(2x1,000)

7,000,000/2,000

3,500

how to safely store deposits if you have more than $250,000

Answers

If you have more than $250,000 to deposit, you should consider spreading your money across multiple accounts or banks to ensure that your funds are fully insured by the FDIC (Federal Deposit Insurance Corporation).

If you have more than $250,000 to deposit, you can safely store your deposits by spreading them across multiple accounts and/or banks. This strategy is commonly referred to as "deposit insurance coverage" and is provided by the Federal Deposit Insurance Corporation (FDIC). In this way, if any one bank fails, you will still have access to your insured funds through the other banks.

A second option is to use the CDARS program. The Certificate of Deposit Account Registry Service is a program that can be utilized by investors to deposit their funds in CDARS member banks. The service allocates these deposits across multiple banks to guarantee that the funds are fully insured.

The third option is to seek the services of an FDIC-insured bank that offers deposit insurance coverage beyond the $250,000 limit. These banks may provide higher deposit insurance coverage, and you can inquire with your bank to determine if they offer this service.

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the joint probability density function of x and y is given by f(x,y)={x y8,0,0

Answers

The probability that x is less than 0.5 and y is greater than 0.6 is 0.0087.

The given joint probability density function of x and y is:

f(x,y) = {

x × y^8, 0 <= x <= 1, 0 <= y <= 1,

0, elsewhere

}

To determine the marginal probability density function of x, we integrate the joint probability density function over the y-axis:

f(x) = \(\int [0,1] x\times y^8 dy\)

=\(x \times [y^{9/9}]_{[0,1]}\)

= x/9

Similarly, to determine the marginal probability density function of y, we integrate the joint probability density function over the x-axis:

f(y) = \(\int[0,1] x \times y^8 dx\)

= \(y^8 \times [x^{2/2}] _{[0,1]}\)

= \(y^{8/2}\)

To determine the probability that x is less than 0.5 and y is greater than 0.6, we use the joint probability density function and integrate over the given region:

P(x < 0.5 and y > 0.6) = \(\int[0.6,1] \int[0,0.5] x\times y^8 dx dy\)

= \(\int[0.6,1] y^{8/2} \times [x^{2/2}][0,0.5] dy\)

= \(\int[0.6,1] y^{8/16} dy\)

= \([y^9/144][0.6,1]\)

= 0.0087

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The probability that x is less than 0.5 and y is greater than 0.6 is approximately 0.00011.

To determine the probability that x is less than 0.5 and y is greater than 0.6, we need to integrate the joint probability density function over the specified region.

Given the joint probability density function:

f(x, y) = {

x × y^8, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1,

0, elsewhere

}

To find the probability, we integrate the joint density function over the region:

P(x < 0.5 and y > 0.6) = ∫∫R f(x, y) dxdy

= ∫[0,0.5] ∫[0.6,1] (x × y^8) dy dx

= ∫[0,0.5] [((x × y^9)/9) |_0.6^1] dx

= ∫[0,0.5] (x/9 - (0.6^9 × x)/9) dx

= [(x^2)/18 - (0.6^9 × x^2)/18] |_0^0.5

= [(0.5^2)/18 - (0.6^9 × 0.5^2)/18] - [0 - 0]

= (1/72 - (0.6^9)/18) ≈ 0.00011

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make r the subject of this formula
v=3 cubed (square root p+ r)

Answers

Answer:

\(r = {(\frac{v}{27} ) } ^{2} \: - p \)

Step-by-step explanation:

\(v = {3}^{3} \sqrt{p + r} \\ v = 27 \sqrt{p + r} \\ \frac{v}{27} = \frac{27 \sqrt{p + r} }{27} \\ \)

\(\frac{v}{27} = \sqrt{p + r} \\ {(\frac{v}{27} ) }^{2} = p + r \\ {(\frac{v}{27} ) } ^{2} \: - p = r \\ \)

Answer:

\(\displaystyle r=\frac{v^2 }{3^{6} }-p\)

Step-by-step explanation:

\(v=3^3(\sqrt{p+r} )\)

Divide both sides by 3³.

\(\frac{v}{3^3 } =\frac{3^3(\sqrt{p+r} )}{3^3}\)

\(\frac{v}{3^3 } =\sqrt{p+r}\)

Square both sides.

\((\frac{v}{3^3 }) ^2 =(\sqrt{p+r})^2\)

\(\frac{v^2 }{3^{3 \times 2} }=(\sqrt{p+r})^2\)

\(\frac{v^2 }{3^{6} }=p+r\)

Subtract p from both sides.

\(\frac{v^2 }{3^{6} }-p=p+r-p\)

\(\frac{v^2 }{3^{6} }-p=r\)

Switch sides.

\(r=\frac{v^2 }{3^{6} }-p\)

Compare the rates for different numbers of texts. If Roger's father wants to get a 600-text message plan, what is the difference in price for the Dial It Up and Ring Ring plans?

Answers

Answer:

\(\$6\)

Step-by-step explanation:

Given

See comment for complete question

Required

The difference in the cost of 600 text messages plan

Representing the given data as; Cost to Number of text messages, we have:

\(Dial\ Up = \$5 : 100\)

and

\(Ring\ Ring= \$8 : 200\)

Multiply the dial-up by 6 to get the cost of 600

\(Dial\ Up = \$5 *6 : 100 * 6\)

\(Dial\ Up = \$30 : 600\)

So, the cost of 600 text messages is $30 --- for dial-up

Multiply the Ring Ring by 3 to get the cost of 600

\(Ring\ Ring= \$8 *3: 200*3\)

\(Ring\ Ring= \$24: 600\)

So, the cost of 600 text messages is $24 --- for Ring Ring

The difference (d) is:

\(d = \$30 - \$24\)

\(d = \$6\)

What will be printed by the following program? Select one: str1 = "part1" str2 = "part2" for x in str1: print (x, end=" " )
a. x×××× b. part2 c. part1 d. part2

Answers

The character of the string "str1" = part1 will be printed.

The correct option is C.

We have,

str1 = "part1"

str2 = "part2" for x in str1: print (x, end=" " )

The program will print each character of the string "str1" on a separate line, followed by a space.

In this case, the string "str1" is "part1", so the program will print "p a r t 1" (with spaces in between each character).

The string "str2" is not involved in the loop, so it will not be printed.

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how do you do factors of 5 grade

Answers

Answer:

If we divide 5 by any other integer, then the remainder will be a non-zero positive integer.

Step-by-step explanation:

A car and a truck leave the same intersection, the truck heading north at 60mph and the car heading west at 55mph. At what rate is the distance between the car and the truck changing when the car and the truck are 30 miles and 40 miles from the intersection, respectively

Answers

1 mile away because ones going faster than the other and so they will be one mile apart

Savvas Realize
In Allentown, Pennsylvania, there are two hamburger shops, Jenny's Burgers and the Burger Hut. Jenny's Burgers sells a record 36 burgers in 5 hours. The next day, Burger Hut broke the record for 108 burgers in 5 hours. How many times more is the record of Burger Hut then Jenny's Burgers?
How do you know?

Answers

Answer: the record is 3 times higher

Step-by-step explanation:

The record Jenny's Burgers sold was:

36 burgers in 5 hours

The record Burger Hut sold was:

108 burgers in 5 hours

We have to divide the record of Burger Hut by Jenny's Burgers.

108 divided by 3 is 36.

So, the record is 3 times higher. Hope this helps!

Answer:

3 times the quantity

Step-by-step explanation:

108 divided by 36 equals 3 times the quantity

Other Questions
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