\({\sf{ \frac{10}{50} = \frac{y}{125} \\ →50y = 10 \times 125 \\→ y = 25}}\)
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The principal advantage of the Dodge-Romig tables is: A. minimum inspection B. its desirability for receiving inspection C. smaller lot sizes D. simplicity
The principal advantage of the Dodge-Romig tables is their simplicity. Therefore, the correct answer is D. simplicity.
The Dodge-Romig tables are statistical sampling tables used in quality control to determine the acceptance or rejection
of a production lot based on sample size and the number of defects found in the sample.
The principal advantage of the Dodge-Romig tables is their simplicity.
They provide a quick and easy method for determining the acceptability of a production lot, without the need for
extensive calculations or statistical knowledge.
This means that they can be used by personnel with limited training in quality control.
The principal advantage of the Dodge-Romig tables is their simplicity. While they can be used for receiving inspection,
their main benefit is in minimizing inspection time and effort by providing clear guidelines for lot sampling and
acceptance based on size and level of defects.
Additionally, their use can facilitate smaller lot sizes and more efficient quality control processes.
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I Need Help With This Question
Answer:
Step-by-step explanation:
Dont do it. Just take the detention
The dean of Blotchville University boasts that the average class size there is 20. But the reality experienced by the majority of students there is quite different: they find themselves in huge courses, held in huge lecture halls, with hardly enough seats or Haribo gummi bears for everyone. The purpose of this problem is to shed light on the situation. For simplicity, suppose that every student at Blotchville University takes only one course per semester.
a) Suppose that there are 16 seminar courses, which have 10 students each, and 2 large lecture courses, which have 100 students each. Find the dean’s eye view average class size (the simple average of the class sizes) and the student’s eye view average class size (the average class size experienced by students, as it would be reflected by surveying students and asking them how big their classes are). Explain the discrepancy intuitively.
b) Give a short proof that for any set of class sizes (not just those given above), the dean’s eye view average class size will be strictly less than the student’s eye view average class size, unless all classes have exactly the same size.
a) Find the dean’s eye view average class size and the student’s eye view average class size:Given that there are 16 seminar courses, each having 10 students each.Number of students in seminar courses: 16 × 10 = 160There are 2 large lecture courses, each having 100 students each.
Number of students in large lecture courses: 2 × 100 = 200
Dean’s view average class size is the simple average of the class sizes:Let’s find the Dean’s view average class size. There are 18 courses in total.
This can be obtained by dividing the total number of students by the total number of classes.
Student’s view average class size = Total number of students/Total number of classes
= 360/18
= 20
Therefore, the dean’s eye view average class size is 46.67 (approximately) and the student’s eye view average class size is 20.
Now, we need to prove that D 2, then (k/(k + 1)) - (1/n) < 0.
Therefore, we have:
S - D< (c2 - c1)*[(k/(k + 1)) - (1/n)]< 0
Hence, S < D.Therefore, the dean’s eye view average class size will be strictly less than the student’s eye view average class size, unless all classes have exactly the same size.
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Find a positive number such that the sum of and is as small as possible. does this problem require optimization over an open interval or a closed interval? a. closed b. open
To find a positive number such that the sum of and is as small as possible, we need to use optimization. This problem requires optimization over a closed interval. The given problem is as follows, Let x be a positive number. Find a positive number such that the sum of and is as small as possible.
To find a positive number such that the sum of and is as small as possible, we need to use optimization. This problem requires optimization over a closed interval. The given problem is as follows, Let x be a positive number. Find a positive number such that the sum of and is as small as possible. So, we need to minimize the sum of and . Now, let's use calculus to find the minimum value of the sum.To find the minimum value, we have to find the derivative of the sum of and , i.e. f(x) with respect to x, which is given by f '(x) as shown below:
f '(x) = 1/x^2 - 1/(1-x)^2
We can see that this function is defined on the closed interval [0, 1]. The reason why we are using the closed interval is that x is a positive number, and both endpoints are included to ensure that we cover all positive numbers. Therefore, the problem requires optimization over a closed interval. This means that the minimum value exists and is achieved either at one of the endpoints of the interval or at a critical point in the interior of the interval.
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Find the slope of the line that passes through (12, 6) and (-8, -4).
1/2
2/1
-1/2
-2/1
None of the above.
Answer:
the answer of this question is 1/2
would lecture notes collected during your bachelor degree study; be a type of date?
No, lecture notes collected during a bachelor degree study are not a type of date. Lecture notes are a collection of the notes taken by a student during the lectures in the course of their bachelor degree study.
They are not the same as dates, which are the specified days on which something happens or is planned to happen. Lecture notes are usually written in the form of summaries of a lecture, which are usually made up of the important points that the student has noted down during the lecture.
They may also include diagrams, equations, and other visual aids that the student has used to illustrate the material covered. Lecture notes are not the same as dates, as they are not related to any specified days. They are simply summaries of the lecture topics discussed by the professor in the course of the student’s bachelor degree study.
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Three companies, A, B and C, make computer hard drives. The proportion of hard drives that fail within one year is 0.001 for company 0.002 for company B and 0.005 for company C. A computer manufacturer gets 50% of their hard drives from company A, 30% from company B and 20% from company C. The computer manufacturer installs one hard drive into each computer.
(a) What is the probability that a randomly chosen computer purchased from this manufacturer will experience a hard drive failure within one year? [4 marks]
(b) I buy a computer that does experience a hard drive failure within one year. What is the probability that the hard drive was manufactured by company C? [4 marks]
(c) The computer manufacturer sends me a replacement computer, whose hard drive also fails within one year. What is the probability that the hard drives in the original and replacement computers were manufactured by the same company? [You may assume that the computers are produced independently.] [6 marks]
(d) A colleague of mine buys a computer that does not experience a hard drive failure within one year. Calculate the probability that this hard drive was manufactured by company C. [6 marks]
(a) The probability of a computer failure from Company A is 0.001; from Company B is 0.002; and from Company C is 0.005.
Therefore, the probability that a computer will experience a hard drive failure within one year is:(0.50 x 0.001) + (0.30 x 0.002) + (0.20 x 0.005)= 0.0012. The probability of a randomly selected computer experiencing a hard drive failure within one year is 0.0012 or 0.12%.
(b) Bayes' theorem will be used to calculate this probability:Let A be the event that the computer's hard drive was manufactured by Company C. Let B be the event that the computer experienced a hard drive failure. P(A|B) is the probability that the hard drive was manufactured by Company C given that a hard drive failure was experienced.
P(A|B) = P(B|A) P(A) / P(B) Where: P(B|A) = 0.005 (the probability of failure if the hard drive was manufactured by Company C)P(A) = 0.20 (the proportion of hard drives that the computer manufacturer gets from Company C)P(B) = (0.50 x 0.001) + (0.30 x 0.002) + (0.20 x 0.005) = 0.0012 (as in part a)
Therefore: P(A|B) = (0.005 x 0.20) / 0.0012 = 0.0833 or 8.33%.
(c)Let A be the event that both hard drives were manufactured by Company A; B be the event that both hard drives were manufactured by Company B; and C be the event that both hard drives were manufactured by Company C. Then we need to find the probability of event A or B or C, given that a hard drive failure was experienced:P(A U B U C|F) = P(F|A U B U C) P(A U B U C) / P(F)where F is the event that the hard drive in the replacement computer fails.P(F|A U B U C) = P(F) = (0.50 x 0.001) + (0.30 x 0.002) + (0.20 x 0.005) = 0.0012P(A U B U C) = (0.50)^2 + (0.30)^2 + (0.20)^2 = 0.46P(F) = P(A U B U C) P(F|A U B U C) + P(A' n B n C) P(F|A' n B n C)= 0.46 x 0.0012 + 0.04 x 0.3 = 0.000552P(A U B U C|F) = P(F|A U B U C) P(A U B U C) / P(F)= (0.0012 x 0.46) / 0.000552 = 1.00or 100%. Therefore, the probability that the original and replacement computers were produced by the same company is 100%.
(d) Bayes' theorem will be used to calculate this probability:Let A be the event that the hard drive was manufactured by Company C. Let B be the event that the computer did not experience a hard drive failure. P(A|B) is the probability that the hard drive was manufactured by Company C given that no hard drive failure was experienced.P(A|B) = P(B|A) P(A) / P(B)Where:P(B|A) = 1 - 0.005 = 0.995 (the probability that the hard drive did not fail if it was manufactured by Company C)P(A) = 0.20 (as in part b)P(B) = 1 - (0.50 x 0.001) - (0.30 x 0.002) - (0.20 x 0.005) = 0.9988
Therefore:P(A|B) = (0.995 x 0.20) / 0.9988 = 0.1989 or 19.89%. Therefore, the probability that the hard drive was manufactured by Company C given that it did not fail is 19.89%.
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The probability that the hard drive was manufactured by company C given that a failure was not experienced by the computer within one year is approximately 0.256.
(a)Probability that a randomly chosen computer purchased from this manufacturer will experience a hard drive failure within one year = 0.5 x 0.001 + 0.3 x 0.002 + 0.2 x 0.005 = 0.0016
(b)Let's denote the event that a computer failure is experienced within one year by F and the event that the hard drive is made by company C by C.
Then we are required to calculate P(C | F), which is the probability that the hard drive was manufactured by company C given that a failure was experienced by the computer within one year. This can be found by using the Bayes' rule as follows:
\($$P(C|F) = \frac{P(F|C)P(C)}{P(F|A)P(A) + P(F|B)P(B) + P(F|C)P(C)}$$\)
where P(C) = 0.2, P(A) = 0.5 and P(B) = 0.3.$$P(F|A) = 0.001, P(F|B) = 0.002, P(F|C) = 0.005$$
Thus, we have:\($$P(C|F) = \frac{0.005 \times 0.2}{0.001 \times 0.5 + 0.002 \times 0.3 + 0.005 \times 0.2} \approx 0.476$$\)
Therefore, the probability that the hard drive was manufactured by company C given that a failure was experienced by the computer within one year is approximately 0.476.
(c)Let's denote the event that the original hard drive is manufactured by company A, B and C by A, B, and C respectively.
Similarly, let's denote the event that the replacement hard drive is manufactured by company A, B, and C by A', B', and C' respectively.
We are required to calculate P(A = A', B = B', C = C' | F), which is the probability that the hard drives in the original and replacement computers were manufactured by the same company given that a failure was experienced by both computers within one year.
This can be found by using the Bayes' rule as follows:
\($$P(A = A', B = B', C = C'|F) = \frac{P(F|A = A', B = B', C = C')P(A = A')P(B = B')P(C = C')}{P(F)}$$\)
where: \($$P(F) = P(F|A = A', B = B', C = C')P(A = A')P(B = B')P(C = C') + P(F|A \ne A', B \ne B', C \ne C')P(A \ne A')P(B \ne B')P(C \ne C')$$\)
Here, we are assuming that the probabilities of computer failure are independent of each other and the company that manufactured the hard drives of the two computers are independent of each other. Therefore, we have:
\($$P(F|A = A', B = B', C = C') = P(F|A)P(F|B)P(F|C) = 0.001 \times 0.002 \times 0.005$$\)
\($$P(F|A \ne A', B \ne B', C \ne C') = 0$$\)
Also, we have:$$P(A = A') = P(B = B') = P(C = C') = \frac{1}{3}$$
\($$P(A \ne A', B \ne B', C \ne C') = \frac{2}{3} \times \frac{2}{3} \times \frac{2}{3} = \frac{8}{27}$$\)
Thus, we have:$$P(A = A', B = B', C = C'|F) = \frac{0.001 \times 0.002 \times 0.005 \times (\frac{1}{3})^3}{P(F)}$$
\($$P(A \ne A', B \ne B', C \ne C'|F) = \frac{P(F) - 0.001 \times 0.002 \times 0.005 \times (\frac{1}{3})^3}{\frac{8}{27}}$$\)
Now, we need to find P(F). This can be done as follows:
\($$P(F) = P(F|A = A', B = B', C = C')P(A = A')P(B = B')P(C = C') + P(F|A \ne A', B \ne B', C \ne C')P(A \ne A')P(B \ne B')P(C \ne C')$$$$= 0.001 \times 0.002 \times 0.005 \times (\frac{1}{3})^3 + 0 = 4.6296 \times 10^{-8}$$Thus, we have:$$P(A = A', B = B', C = C'|F) = 0.0296$$\)
\($$P(A \ne A', B \ne B', C \ne C'|F) = 0.9704$$\)
Therefore, the probability that the hard drives in the original and replacement computers were manufactured by the same company given that a failure was experienced by both computers within one year is 0.0296.(d)Let's denote the event that the hard drive is made by company C by C and the event that a computer failure is not experienced within one year by F'. We are required to calculate P(C | F'), which is the probability that the hard drive was manufactured by company C given that a failure was not experienced by the computer within one year. This can be found by using the Bayes' rule as follows:
\($$P(C|F') = \frac{P(F'|C)P(C)}{P(F'|A)P(A) + P(F'|B)P(B) + P(F'|C)P(C)}$$\)
where P(C) = 0.2, P(A) = 0.5 and P(B) = 0.3.$$P(F'|A) = 0.999, P(F'|B) = 0.998, P(F'|C) = 0.995$$
Thus, we have: \($$P(C|F') = \frac{0.995 \times 0.2}{0.999 \times 0.5 + 0.998 \times 0.3 + 0.995 \times 0.2} \approx 0.256$$\)
Therefore, the probability that the hard drive was manufactured by company C given that a failure was not experienced by the computer within one year is approximately 0.256.
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Solve the inequality for y.
7y-24<-2(3-8y)
Histograms based on data on _________ ______ and ________ typically are skewed to the right.
By organizing countless data points into comprehensible ranges or bins, the histogram, which resembles a bar graph in appearance, condenses a data series into an understandable visual. So Histograms based on data on housing, prices and salaries typically are skewed to the right.
A histogram in statistics is a graphic depiction of the data distribution. The histogram is shown as a collection of rectangles that are next to one another, where each bar represents a different type of data.
A branch of mathematics called statistics is used in many different fields. Frequency is the term for how often numbers appear in statistical data; it can be shown as a table and is known as a frequency distribution.
A histogram is a bar graph-like data visualization that groups various class levels into columns along the horizontal x-axis. The numerical count or percentage of occurrences for each column in the data are shown on the vertical y-axis.
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PLEASE HELP ME ITS ALGEBRA 1 ANYONE PLEASE !!!
Answer:
answer of this question is r=0.94
Answer: oh god
Step-by-step explanation:
Someone please help me ASAP!!
Answer:
B' = (-6,6)
Step-by-step explanation:
The coordinates of B are (-2,2)
If the figure is to become 3 times as large, B' would be 3(-2,2) = (-6,6)
PLZZZZZ HELPPPP!!!! I NEED YOU RIGHT NOWSSSSSS
Answer:
its parallel!!!!!
its parallel because they have different slopes!!!
Help please! Find the approximate solution of this system of equations
Answer:
Option B
Step-by-step explanation:
We have to solve this system of equations by using the Substitution method so here goes,
\(Equation\ 1\\\\\y=x^2+5x+3\\\\Equation\ 2\\\\\ y=\sqrt{2x+5}\\\)
We insert equation 2 in equation 1 since both equations are equal to y so we equate both of them,
\(\sqrt{2x+5}=x^2+5x+3\\Square\ both\ sides\\\\\2x+5=(x^2+5x+3)^2 \\\)
To square the right hand side suppose
\(a=x^2+5x\\b=3\\(a+b)^2=a^2+2ab+b^2\\(x^2+5x)^2+2(x^2+5x)(3)+(3)^2\\\\((x^2)^2+2(x^2)(5x)+(5x)^2)+6(x^2+5x)+9\\x^4+10x^3+25x^2+6x^2+30x+9\\x^4+10x^3+31x^2+30x+9\\\)
Now,
\(2x+5=x^4+10x^3+31x^2+30x+9\\x^4+10x^3+31x^2+30x-2x+9-5=0\\x^4+10x^3+31x^2+28x+4=0\\\)
Apply Newton-Raphson method to quickly determine the approximate solution of the polynomial we get the values of x to be,
x ≈ -0.175 and x ≈ -1.22
now insert these values into equation 1 or 2 to get the values of y
we use the first value ,
\(y=x^2+5x+3\\y=(-0.175)^2+5(-0.175)+3\\y=2.155\\\)
now for the second value of x,
\(y=x^2+5x+3\\y=(-1.22)^2+5(-1.22)+3\\y=-1.612\)
now since the second set of values are not in the options we ignore the second set of values which are ( -1.22 , -1.612)
we use the first set of values which are (-0.175 , 2.155) which rounded off lead to (-0.2 , 2.1), so Option B is your answer
I also attached a graphical representation so you can verify the answer yourself , The approximate solution of this system of equation is the point of intersection between both the graphs which is marked on the image.
Determine whether the following equence i an arithmetic or geometric progreion. Give a reaon for your anwer. 100p,50p,25p,
Answer:
Geometric.
Step-by-step explanation:
It is Geometric because there is a common ratio between the terms.
50p/100p = 1/2
25p/50p = 1/2
The common ratio is 1/2.
Each term is obtained by multiplying by 1/2, so the next term in this progression is 25p * 1/2 = 12.5p.
Decide if the segments can make a triangle. Answer with Yes/No and explain your answer.
9: 8 cm, 12 cm, 16 cm
10: 5 in, 7 in, 20 in
9. Yes, since \(8+12>16\), meaning the side lengths satisfy the triangle inequality.
10. No, since \(5+7<20\), meaning the side lengths do not satisfy the triangle inequality.
6. Sam has a bank account that pays 4% simple interest. The balance is $880. How long will it take for the account to grow to $900?
Answer:
1 mounth
Step-by-step explanation:k
1/2 + 1/4
2/8
2/6
4/8
6/8
Negative 4,200 divided by 300
Answer:
-14
Step-by-step explanation:
Which value would make the inequality 4.5d > 31.5 true?
A. d=8
B. d=7
C. d=6
D. d=5
Answer:
d=8
Step-by-step explanation:
4.5(8)>31.5 works because 36>31.5
last week the tasha cola company had sales of 2,346.87 this week the company had sales of 8,867.14 Which is the estimate ofthe companys total sales for both weeks math problem
Answer:
11,214
Step-by-step explanation:
Given that :
Last week sales = 2,346.87
This week sales = 8,867.14
Total sales for bot weeks :
Last week sales + this week sales
2,346.87 + 8,867.14
= 11214.01
= 11,214
It is known that the length of a certain product X is normally distributed with u = 30 inches. How is the probability AX > 26) related to PX<26)? Multiple Choice PIX>26) is smaller than P(X<26). PIX>26) is the same as P(X<26). PIX>26) is greater than PX<26). No comparison can be made without knowing the value of the standard deviation o.
PIX>26) is greater than PX<26).
The probability PX<26) represents the probability that the length of product X is less than 26 inches. Since the mean (u) is given as 30 inches, PX<26) corresponds to the left tail of the normal distribution curve.
On the other hand, the probability PIX>26) represents the probability that the length of product X is greater than 26 inches. Since the normal distribution is symmetric, the right tail of the distribution is mirrored to the left tail. Therefore, PIX>26) corresponds to the area under the right tail of the normal distribution curve.
As the left tail (PX<26)) has a smaller area under the curve compared to the right tail (PIX>26)), it means that PIX>26) is greater than PX<26). However, the exact comparison between the two probabilities cannot be determined without knowing the value of the standard deviation (σ) of the product's length distribution.
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What would be your first step in completely factoring 6a” - 15a + 6?
A Look for factors of 6a² and 6
B
Factor out a common factor of a
C) Factor out a tommon factor of 6
D Factor out a common factor of 3
This is completely factored.
Answer:
Step-by-step explanation:
When you speak of common factors, you mean that every term must contain the common factor.
In addition terms are determined by isolated minus or plus signs.
The answer is D
3 goes into 15. six does not.
For what value of k does the equation have no solution? kx - 4 = 5x + 8
Answer:
Your answer is: k = 5+12/x
Isolate the variable by dividing each side by factors that don't contain the variable.
Step-by-step explanation:
Hope this helped : )
Which of the following is a line of symmetry for the figure shown?
Figure shows an arrow shape pointing up and down on a dot grid. Lines AB and CD run horizontally and parallel across the arrow. Line EF runs vertically through the center of the arrow.
A.
←→
A
B
B.
←→
C
D
C.
←→
E
F
D.
None of the above
Answer:
The line of symmetry for the given figure is EF which runs vertically through the center of the arrow. Therefore, the answer is C.
Step-by-step explanation:
Which rule describes the x-coordinates in the translation below?.
On a coordinate plane, triangle A B C is shifted 6 units up.
x + 0
x + 6
x – 6
x + 2
9514 1404 393
Answer:
(a) x + 0
Step-by-step explanation:
When translation is up or down, the x-coordinate doesn't change. It will be ...
x + 0
Answer:x+0
Step-by-step explanation:I HAVE DONE THIS BEFORE
Invested $10,000 into savings account that earns simple interest. After 8 years, the total amount was $14,800. Find the interest rate of the account.
The interest rate of the savings account is 6%. This means that for every year, the account earned 6% of the principal as interest.This is added to the original principal of $10,000 to get the total amount of $14,800.
To find the interest rate of a savings account, we need to use the formula for simple interest, which is:
Interest = Principal x Rate x Time
In this case, we know the principal (P) is $10,000, the time (T) is 8 years, and the total amount (A) after 8 years is $14,800. We can rearrange the formula to solve for the interest rate (R):
R = (A - P) / (P x T)
R = ($14,800 - $10,000) / ($10,000 x 8)
R = $4,800 / $80,000
R = 0.06 or 6%
In other words, the account earned $600 of interest each year for 8 years, resulting in a total of $4,800 of interest.
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HELP ASAP!!! WILL MARK BRAINLIEST!!!
Put the steps in order to solve equation
The steps are given below.
Given that an expression,
(8)(x) = (-8)(x-12)
x = 6
16x = 96
8x + 8x = -8x + 96 + 8x
8x = -8x + 96
16x/16 = 96/16
We need to put the steps in order to solve equation,
The steps to solving the problem are as follows, in the right order:
1. Begin with the following equation: (8)(x) = (-8)(x-12)
2. Simplify the problem on both sides: 8x = -8(x-12)
3. Divide the terms between the parenthesis by -8: 8x = -8x + 96
4. On the right side of the equation, combine like terms: 8x + 8x = -8x + 96 + 8x
5. Simplify both sides by incorporating comparable terms: 16x = 96
6. 16x/16 = 96/16 is used to multiply both sides of the equation by 16.
7. Rephrase the formula as x = 6
Consequently, x = 6 is the answer to the equation.
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What is the circumference of the circle below? (Round your answer to the nearest tenth)
Answer: B.
Step-by-step explanation: Remember, circumfrence is 2 pi r. multiply 6.1 and 2. That is 12.2. Then, use a calculator to multiply that to get approx 76.65. Round that up to 76.7.
a store owner wants to develop a new snack mix by mixing chocolate and trail mix. how many pounds of chocolate costing $21.10 per pound should be mixed with 14 pounds of trail mix costing $3.10 per pound to create a mixture worth $12.41 per pound.
To solve this problem, we can use the method of mixtures. Let x be the number of pounds of chocolate to be mixed with the trail mix. We can set up the following equation based on the given information:
(21.10x + 3.10(14)) / (x + 14) = 12.41
Simplifying and solving for x, we get:
21.10x + 43.40 = 12.41x + 173.54
8.69x = 130.14
x = 15
Therefore, the store owner should mix 15 pounds of chocolate costing $21.10 per pound with 14 pounds of trail mix costing $3.10 per pound to create a mixture worth $12.41 per pound.
To check this answer, we can verify that the total cost of the mixture equals the total cost of the chocolate and trail mix:
15(21.10) + 14(3.10) = 315 + 43.40 = 358.40
And the total weight of the mixture is:
15 + 14 = 29
So the cost per pound of the mixture is:
358.40 / 29 = 12.41
which matches the desired cost per pound.
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A school bus has seating for 75 students. There are 13 buses at a school. What is the maximum number of students
the buses can seat
225 students
750 students
975 students
985 students
Help
Answer:
75 students and 13 buses are just 75 x 13
975 students
Step-by-step explanation:
75 x 13 = 975