If we use to construct the latches on the windows and doors, then the magnetism will keep thee latches secure.

a. True
b. False

The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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Answer:

0.78 m * (11.25 * 2π rad/min)

Explanation:

Given:

Angular velocity of the merry-go-round, ω = 11.25 rpm

Distance of the child from the center of the merry-go-round, r = 0.78 m

Time taken to reach the angular velocity from rest, t = 1.5 minutes

We can use the following formulas to solve the problem:

Angular velocity (ω) is defined as the rate of change of angular displacement with respect to time:

ω = Δθ/Δt

Angular acceleration (α) is defined as the rate of change of angular velocity with respect to time:

α = Δω/Δt

The linear velocity (v) of a point on the edge of a rotating object is given by:

v = r * ω

The linear acceleration (a) of a point on the edge of a rotating object is given by:

a = r * α

Let's solve for the child's angular velocity (part A):

Given:

ω = 11.25 rpm

To convert rpm to rad/min, we use the conversion factor: 1 rpm = (2π rad) / (1 min)

ω = 11.25 rpm * (2π rad/min) / (1 rpm) = 11.25 * 2π rad/min

So, the child's angular velocity (ω) is 11.25 * 2π rad/min.

Now, let's solve for the child's angular acceleration (part B):

Given:

t = 1.5 minutes

Using the formula α = Δω/Δt, we can find the angular acceleration:

α = Δω/Δt = (ω - 0) / t

Substituting the given values:

α = (11.25 * 2π rad/min - 0) / (1.5 min)

So, the child's angular acceleration (α) is (11.25 * 2π rad/min) / (1.5 min).

Finally, let's calculate the linear velocity or speed of the child (bonus part):

Using the formula v = r * ω, we can find the linear velocity or speed of the child:

v = r * ω = 0.78 m * (11.25 * 2π rad/min)

So, the child's linear velocity or speed is 0.78 m * (11.25 * 2π rad/min).

A. The child's angular velocity is 0.375π rad/s, B. The child experienced an angular acceleration of  0.00414 rad/s^2, and BONUS. The child is moving at 0.92 m/s.

Angular velocity is a measure of how fast an object is rotating or moving in a circular path. It is defined as the rate of change of angular displacement with respect to time and is typically measured in units of radians per second (rad/s). Angular velocity is a vector quantity, meaning it has both magnitude (the numerical value) and direction (either clockwise or counterclockwise). It is related to linear velocity (the speed of an object moving in a straight line) by the formula:

v = rω,

where v is linear velocity, r is the radius of the circular path, and ω is the angular velocity.

Here in the question,

A) To find the angular velocity, we can use the formula:

angular velocity (ω) = 2π x frequency (f)

We know that the merry-go-round is turning at 11.25 revolutions per minute (rpm), so the frequency is:

f = 11.25 rpm = 11.25/60 Hz = 0.1875 Hz

Now we can plug in the frequency to find the angular velocity:

ω = 2π x 0.1875 Hz = 0.375π rad/s

So the child's angular velocity is 0.375π rad/s.

B) We can use the formula for angular acceleration:

angular acceleration (α) = (final angular velocity - initial angular velocity) / time

We know the initial angular velocity is 0 (since the child starts from rest) and the final angular velocity is 0.375π rad/s (from part A). The time is given as 1.5 minutes, but we need to convert it to seconds:

time = 1.5 minutes x 60 seconds/minute = 90 seconds

Now we can plug in the values:

α = (0.375π rad/s - 0) / 90 s ≈ 0.00414 rad/s^2

So the child experienced an angular acceleration of approximately 0.00414 rad/s^2.

BONUS - To find the child's speed, we can use the formula:

speed (v) = radius x angular velocity

We know the child is standing 0.78 m from the center of the merry-go-round (i.e., the radius) and the angular velocity is 0.375π rad/s (from part A). Plugging in the values:

v = 0.78 m x 0.375π rad/s ≈ 0.92 m/s

So, the child is moving at approximately 0.92 m/s

Therefore, The child has an angular velocity of 0.375 rad/s, an angular acceleration of 0.00414 rad/s2, and is moving at 0.92 m/s.

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Answer:

-17.89 m/s  (or 17.89m/s downward)

edit:

if we round this to the nearest whole number, the answer is -18m/s (or 18m/s downward)

Explanation:

recall that one of the equations of motion can be expressed as:

v² = u² + 2as,

where

v = final velocity = given as 20 m/s

u = initial velocity = given as 7.0 m/s

a = acceleration. Since it is freefalling downwards, the acceleration it would experience would be the acceleration due to gravity = -9.81 m/s²

s = displacement (we are asked to find)

simply substitute the known values into the equation:

v² = u² + 2as

20² = 7² + 2(-9.81)s

400 - 49 = -19.62s

-19.62s = 351

s = 351/-19.62

s = -17.8899

s = -17.89 m/s (or -18 m/s rounded to nearest whole number)

A watermelon is thrown down from a skyscraper with a speed of v7.0 m/s. It lands with an impact velocity of 20 m/s. We can ignore air resistance.

What is the displacement of the watermelon?

Answer: -18

Answer:

Eubacteria Kingdom :)

Explanation:

Answer: eubacteria

Explanation:

When the liquid cools down, it loses heat energy.

As the liquid cools, it loses heat energy. As a result, its particles slow down in movement and come closer to one another. Attractive forces begin to hold particles and the crystals of a solid form.

If water is cooled, it can change into ice. If ice is warmed, it can change into a liquid state. Heating a substance makes the molecules move very fast whereas cooling a substance makes the molecules move very slowly.

Heating a liquid increases the speed of the molecules present in it. An increase in the molecule's speed competes with the attraction between molecules and results in the molecules moving apart whereas Cooling a liquid decreases the movement of the molecules.

So we can conclude that the liquid cools down when it loses heat energy.

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In a motor, a current-carrying loop is placed in a magnetic field. The interaction between the current in the loop and the magnetic field produces a torque on the loop, causing it to rotate. The rotating loop is connected to a shaft, which can be used to perform mechanical work. Therefore, option d, "A shaft connected to the rotating coil is attached to some external device," is the correct answer. The motor's mechanical energy is transferred to the external device through the shaft, allowing the motor to perform mechanical work.

Moving magnetic fields cause electrons to be pulled and pushed. There are loosely held electrons in metals like copper and aluminum. By rotating a coil of wire around a magnet or vice versa, an electrical current is produced by pushing the wire's electrons.

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There are around 3.8179x10⁻⁹ seconds between the crests of each wave.

The number of cycles per second is the unit of frequency in Hertz. To find the time interval for a known frequency, just divide 1 by the frequency (for example, a frequency of 100 Hz has a time interval of 1/(100 Hz) = 0.01 seconds; a frequency of 500 Hz has a time interval of 1/(500Hz) = 0.002 seconds, etc.). The wavelength is the separation between a specific location and that same location in the next wave cycle.

T = 1/f

By changing the value of f, we obtain:

T = 1 / 262x10⁻⁹ Hz

T = 3.8179x10⁻⁹ seconds

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Answer:

1. True

2. False

3. True

4. False

Explanation:

a) In this case, length of the copper rod is 3.6 m which is much larger than the distance 4.9 cm to the point at which electric field is to be determined. Therefore, yes, cylindrical symmetry holds.

b) In this case, length of the copper rod is 8.9 cm which is of the same order of magnitudes the distance 4.9 cm to the point at which electric field is to be determined. Therefore, no, cylindrical symmetry does not hold.

c) In this case, length of the copper rod is 3.8 m which is much larger than the distance 4.9 cm to the point at which electric field is to be determined. Therefore, yes, cylindrical symmetry holds.

d) In this case, length of the copper rod is 3.6 m which is of the same order of magnitudes the distance 4.9 cm to the point at which electric field is to be determined. Therefore, no, cylindrical symmetry does not hold.

Answer:

3g/mL

Explanation:

The density of a substance can be calculated using the formula;

Density = mass/volume

Where;

Density = g/mL

mass = grams (g)

volume = (mL)

According to this question, 45.0g of a sample placed in a graduated cylinder causes the water level to rise from

25.0mL to 40.0mL. This means that the volume of the sample is 40mL - 25mL = 15mL

Using D = m/v

D = 45/15

D = 3g/mL

Hence, the density of the sample is 3g/mL

(a) F(x) = 0.503 x, where x is in meters and F is in newtons, is the formula given for the force. We can see that this equation's proportionality constant, C, must be expressed in newtons per meter. C is therefore measured in N/m in the SI.

(b) The work done by the force as the particle moves from x = 3.0 m to x = 1.5 m can be calculated using the formula for work, which is W = ∫ F(x) dx, where the integral is taken over the distance moved. Therefore, we have:

W = ∫ 0.503 x dx from x = 3.0 to x = 1.5

W = [0.503/2 x^2] from x = 3.0 to x = 1.5

W = [0.503/2 (1.5^2 - 3.0^2)]

W = -1.129 J

The work done by the force is -1.129 joules.

(c) At x = 3.0, the force is given to be in the opposite direction to the particle's velocity. Therefore, the force is opposing the motion of the particle. We can use the work–kinetic energy theorem to determine the change in kinetic energy of the particle between x = 3.0 and x = 1.5, and hence its speed at x = 1.5. The work–kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we have:

W_net = ΔK

In this case, the only force acting on the particle is the given force, and we have already calculated the work done by this force as -1.129 J. Therefore, we have:

W_net = -1.129 J

ΔK = 1.129 J (since the work done is negative, indicating a decrease in kinetic energy)

We can use the formula for kinetic energy, K = (1/2)mv^2, to find the particle's speed at x = 1.5. Therefore, we have:

ΔK = (1/2)m(v^2 - v_0^2)

1.129 = (1/2)(1.5)(v^2 - 12^2)

v^2 = 12^2 - (2/1.5)(1.129)

v^2 = 56.49

v = 7.52 m/s

The particle's speed at x = 1.5 is 7.52 m/s.

(d) kinetic energy theorem states that the net work done on an object is equal to its change in kinetic energy. In this case, the net work done by the given force Is -1.129 J, the initial kinetic energy of the particle (since we are told its speed at x = 3.0).

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The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Answer:

d

Explanation:

Answer:

The number of hailstones striking the window per unit time is:

n = 580 hailstones / 41 s = 14.1463 hailstones/s

The mass of each hailstone is 7 g = 0.007 kg, and its speed is 6.7 m/s. The kinetic energy of each hailstone is:

K = (1/2) * m * v^2 = (1/2) * 0.007 kg * (6.7 m/s)^2 = 0.167 N*m

The angle of incidence is 31°, so the angle between the hailstones and the normal to the window is 59°. The average force on the window is the rate of change of momentum of the hailstones. The momentum of each hailstone before the collision is:

p1 = m * v * cos(59°) * (-i) + m * v * sin(59°) * j

where i and j are the unit vectors in the x- and y-directions, respectively. The negative sign in front of the i-vector indicates that the hailstone is moving to the left (in the negative x-direction).

The momentum of each hailstone after the collision is:

p2 = m * v * cos(59°) * i + m * v * sin(59°) * j

The change in momentum of each hailstone is:

Δp = p2 - p1 = 2 * m * v * cos(59°) * i

The rate of change of momentum (i.e., the force) is:

F = n * Δp / Δt

where Δt is the time for each hailstone to strike the window. This time is equal to the width of the window divided by the component of the velocity perpendicular to the window, which is:

Δt = 1.346 m / (v * sin(59°)) = 1.346 m / (6.7 m/s * sin(59°)) = 0.139 s

Substituting the values, we get:

F = 14.1463 hailstones/s * 2 * 0.007 kg * 6.7 m/s * cos(59°) * (-i) / 0.139 s

F = 28.051 N * i

Therefore, the average force on the window is 28.051 N, in the negative x-direction.

Explanation:

Answer:

Explanation:

It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.

Answer:

Ionic charges refer to the electrical charges of ions, which are atoms or molecules that have gained or lost electrons. These charges result from the loss or gain of electrons during chemical reactions.

When an atom loses one or more electrons, it becomes a positively charged ion known as a cation. The cation carries a positive charge equal to the number of electrons lost.

Conversely, when an atom gains one or more electrons, it becomes a negatively charged ion known as an anion. The anion carries a negative charge equal to the number of electrons gained.

The magnitude of the ionic charge depends on the number of electrons gained or lost, which is determined by the element's position in the periodic table and its electron configuration. For example, sodium (Na) loses one electron to become a +1 charged cation (Na+), while chlorine (Cl) gains one electron to become a -1 charged anion (Cl-).

You can use fixture wires: For installation in luminaires where they are enclosed and protected and not subject to bending and twisting and also can be used to connect luminaires to their branch circuit conductors.

Fixture wires are flexible conductors that are used for wiring fixtures and control circuits. There are some special uses and requirements for fixture wires and no fixture can be smaller than 18 AWG

In modern fixtures, neutral wire is white and the hot wire is red or black. In some types of fixtures, both wires will be of the same color.

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Answer:

08 and 09 with be 67

Explanation:

i know this because it was the vase major

The mass rate of change of the space probe is approximately 28.49 kg/s .

To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:

F = ma

In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:

F = (Δ m /Δt) * v

where;

Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:

F_net = m * g - (Δ m /Δt) * v

Plugging in the values and solving for delta m / delta t, we get:

2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s

Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s

Δm / Δt ≈ 28.49 kg/s

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The CH4 molecule will have the biggest dipole moment. The symmetric of the molecules is established using the dipole moment.

A dipole moment is defined.

The size of the charge Q at each end of something like the molecules dipole times the space r seen between charges gives rise to the dipole moment (), which is a measure representing net molecular polarity. We can learn about a molecule's charge separation from its dipole moments.

What is the water dipole moment?

Its anisotropy has been calculated experimentally to be 1.855 D for a shallow groundwater monomers (1) An individual water molecule's dipole moment is known to be greatly increased in water clustered and cell contents due to polarization and molecular orbitals effects.

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The molecule with the largest dipole moment (a) co2 (b) h2o (c) ch4 (d) c2h4 (e) ph3

Answer: D

Explanation: it seem right to me I really don't know if this right but I hope this helps

The GPE (Gravitational potential energy) of the balloon of mass 250 kg is 367500 J.

To calculate the GPE of the balloon, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the GPE of the balloon is 367500 J.

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Explanation:

the answer to this question would be mj.us 1 and minus 3

Answer:

Explanation:

Mass of disk = 0.14 kgSpring constant = 155 N/mLength = 4 cmWe need to calculate the speed Using energy conservationWhere, k = spring constantx = compressed lengthm = mass of the discPut the value into the formulaHence, The speed with which the disk slides across the surface is 1.33095 m/s.

The current flowing through the 1Ω resistor in the circuit is 0.66 A.

The emf of the cells, V = 1.1 V

Internal resistance of the cells, r = Ω

Resistance across the circuit, R = 1 Ω

According to Kirchhoff's current law, the total current flowing into and out of a junction in an electrical circuit is equal.

According to Kirchoff's current law,

(1.1 - V'/2) + (1.1 - V'/2) + (1.1 - V'/2) = V'/1

3/2(1.1 - V') = V'

3.3 - 3V' = 2V'

5V' = 3.3

Therefore, the terminal velocity of the battery is,

V' = 3.3/5

V' = 0.66 V

Therefore, according to Ohm's law, the current flowing through the 1Ω resistor is given by,

I = V'/R

I = 0.66/1

I = 0.66 A

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The heat energy required to change a 0.3 kg ice cube from a solid at -20 °C to steam at 120 ℃ is 915.78 kJ.

The process of changing a 0.3 kg ice cube from solid at -20 ℃ to steam at 120 ℃ involves the following steps:

1. First, the ice cube must be warmed from -20 ℃ to 0 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

Since the ice is at a constant temperature, ΔT is equal to 0.

Hence, no heat is required to change the temperature of the ice cube from -20 ℃ to 0 ℃.

2. Second, the ice cube must be melted at 0 ℃.

The heat required to melt the ice cube can be calculated using the formula Q = mL, where Q is the heat required, m is the mass of the substance, and L is the latent heat of fusion of the substance.

For water, the latent heat of fusion is 334 J/g.

Hence, the heat required to melt the 0.3 kg ice cube is 0.3 kg x 334 J/g = 100.2 kJ.

3. Third, the liquid water must be warmed from 0 ℃ to 100 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For water, the specific heat capacity is 4.184 J/g℃.

Hence, the heat required to warm the 0.3 kg of liquid water from 0 ℃ to 100 ℃ is 0.3 kg x 4.184 J/g℃ x 100 ℃ = 125.52 kJ.

4. Fourth, the liquid water must be boiled at 100 ℃ to form steam at 100 ℃.

The heat required to boil the liquid water can be calculated using the formula Q = mL, where Q is the heat required, m is the mass of the substance, and L is the latent heat of vaporization of the substance.

For water, the latent heat of vaporization is 2260 J/g.

Hence, the heat required to boil the 0.3 kg of liquid water is 0.3 kg x 2260 J/g = 678 kJ.

5. Fifth, the steam must be heated from 100 ℃ to 120 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For steam, the specific heat capacity is 2.010 J/g℃.

Hence, the heat required to heat the 0.3 kg of steam from 100 ℃ to 120 ℃ is 0.3 kg x 2.010 J/g℃ x 20 ℃ = 12.06 kJ.6.

The total heat required to change the 0.3 kg ice cube from solid at -20 ℃ to steam at 120 ℃ is the sum of the heat required for each step.

Hence, the total heat required is 100.2 kJ + 125.52 kJ + 678 kJ + 12.06 kJ = 915.78 kJ.

Therefore, the heat energy required to change a 0.3 kg ice cube from a solid at -20 °C to steam at 120 °℃ is 915.78 kJ.

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Answer:

Absolute magnitude

Explanation:

The brightness a star would have if it were at 10 pc from Earth is called Absolute magnitude.

a) , it would take approximately 0.4638 seconds for the magnetic energy to decay to 13% of its maximum value.. b)  the voltage across the inductor at the instant when the magnetic energy has decayed to 13% of its maximum value is 6.4 times the initial current in the circuit.

An RL circuit consists of a resistor (R) and an inductor (L) connected in series. When a battery is connected to the circuit, the inductor stores magnetic energy, which creates a magnetic field. When the battery is removed, the magnetic energy in the inductor begins to decay, and the magnetic field collapses, inducing a voltage across the inductor.

a) The time constant (τ) of an RL circuit is given by the formula:

τ = L/R

where L is the inductance in henries, and R is the resistance in ohms. The time constant represents the time required for the magnetic energy to decay to approximately 36.8% of its maximum value.

In this case, L = 5 H and R = 22 ohms. Therefore, the time constant of the circuit is:

τ = L/R = 5 H / 22 ohms = 0.2273 seconds

To calculate the time required for the magnetic energy to decay to 13% of its maximum value, we can use the formula:

t = -ln(0.13) * τ

where ln is the natural logarithm. Plugging in the values, we get:

t = -ln(0.13) * 0.2273 seconds

t = 0.533 seconds

Therefore, it would take approximately 0.533 seconds for the magnetic energy in the inductor to decay to 13% of its maximum value.

b) To find the voltage across the inductor at that instant, we can use the formula:

V = L * di/dt

where V is the voltage across the inductor, L is the inductance, and di/dt is the rate of change of the current in the circuit.

At the instant when the magnetic energy in the inductor has decayed to 13% of its maximum value, the current in the circuit is given by:

I = I0 * e^(-t/τ)

where I0 is the initial current, and e is the mathematical constant approximately equal to 2.71828. Plugging in the values, we get:

I = I0 * e^(-0.533/0.2273)

I = 0.292 * I0

Therefore, the rate of change of current (di/dt) at that instant is given by:

di/dt = I / τ = (0.292 * I0) / 0.2273

Now, we can calculate the voltage across the inductor:

V = L * di/dt = 5 H * (0.292 * I0 / 0.2273)

V = 6.4 * I0 volts

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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a) The rms value of the applied voltage E1 is given by:

E1 = (B*N1*lc*S)/(4.44*sqrt(2)*ȝr)

E1 = (1.2*200*90*0.95)/(4.44*sqrt(2)*10000)

E1 = 4.8 V

b) The current in the winding is given by:

I1 = (E1*sqrt(2))/(N1*lc*S)

I1 = (4.8*sqrt(2))/(200*90*0.95)

I1 = 0.0267 A

c) The rms voltage Er induced in the second winding is given by:

Er = (B*N2*lc*S)/(4.44*sqrt(2)*ȝr)

Er = (1.2*400*90*0.95)/(4.44*sqrt(2)*10000)

Er = 9.6 V