If the thickness of an absorber is 1.5 cm and 36.45% of a beam is attenuated by the absorber, what is the half-value layer?

Answer:

B my brother say that it was

(A) the original charge of the system is 21,250 μC. (B)  the final potential difference across the capacitor is 850 V. (C) The final energy of the system is 11,740,750 μJ.

To compute the original charge of the system, we can use the formula;

Q = C × V

where Q will be the charge, C will be the capacitance, and V will be the potential difference.

For the 25.0 μF capacitor charged to 850 V;

Q₁ = C₁ × V₁

= (25.0 μF) × (850 V)

Q1 = 21,250 μC

Therefore, the original charge of the system is 21,250 μC.

When the charged capacitor is connected in parallel to the uncharged capacitor, the potential difference across both capacitors becomes equal. This means the final potential difference across the capacitors will be the same as the initial potential difference of the charged capacitor, which is 850 V.

Therefore, the final potential difference across the capacitor is 850 V.

The energy stored in a capacitor can be calculated using the formula:

E = 0.5 × C × V₂

where E will be the energy, C will be the capacitance, and V will be the potential difference.

For the 25.0 μF capacitor with a potential difference of 850 V:

E₁ = 0.5 × C1 × V1²

= 0.5 × (25.0 μF) × (850 V)²

E₁ = 9,018,750 μJ

For the 8.00 μF capacitor with a potential difference of 850 V:

E₂ = 0.5 × C₂ × V2²

= 0.5 × (8.00 μF) × (850 V)²

E2 = 2,722,000 μJ

The final energy of the system is the sum of the energies of both capacitors;

E_final = E₁ + E₂

= 9,018,750 μJ + 2,722,000 μJ

E_final = 11,740,750 μJ

Therefore, the final energy of the system is 11,740,750 μJ.

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--The given question is incomplete, the complete question is

"A 25.0 μf capacitor is charged to a potential difference of 850 v . the terminals of the charged capacitor are then connected to those of an uncharged 8.00 μf capacitor. A) compute the original charge of the system B)compute the final potential difference across the capacitor C)compute the final energy of the system."--

Explanation:

hamburger cheesecake

The nominal terms they're extensively utilized in press passages, literary works and so on. The nominal phrases are made from a noun, that is, right call or pronoun.

After removing Noun phrases in the sentences so, new sentences are: -

1. The defenders of the castle of Chapultepec, Ninos Héroes

2. Antonio López de Santa Anna, Most Serene Highness, the country

3. Some American ships, the port of heroic Veracruz

4. Those ships, the invading army, modern weapons

5. The Americans, the humid jungle

6. Foreign soldiers, the City of Palaces

7. The eaglets of the ksksn military college, the death

Nouns can be categorized into various types, including proper nouns, common nouns, concrete nouns, abstract nouns, and collective nouns. For example, New York City, John, or Coca-Cola. Common nouns, on the other hand, are general and refer to people, places, or things without specifying them. Examples include city, man, or soda.

Nouns are essential components of sentences and are used to identify and describe people, places, things, or ideas. Examples include table, cat, or car. Abstract nouns refer to intangible concepts such as love, courage, or knowledge. Collective nouns refer to a group of things or people, such as a flock of birds, a team of players, or a school of fish.

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Complete Question:-

Underline the noun phrases in these sentences

1. The defenders of the castle of Chapultepec were the taken Ninos Héroes

2. Antonio López de Santa Anna, Most Serene Highness, ruled the country

3. Some American ships arrived at the port of heroic Veracruz

4. In those ships, the invading army arrived with modern weapons

5. The Americans crossed the humid jungle quickly

6. "Foreign soldiers soon arrived at the City of Palaces and invaded it

7. It was then that the eaglets of the ksksn military college fought to the death

The coefficient of determination (r^2) is 0.04, indicating a low degree of explanatory power. The coefficient of nondetermination (1 - r^2) is 0.96, suggesting a high amount of unexplained variation in the dependent variable.

1. Calculate the coefficient of determination (r^2):
  - Square the given value of r: 0.2 * 0.2 = 0.04.
  - The coefficient of determination (r^2) is 0.04.

2. Calculate the coefficient of nondetermination (1 - r^2):
  - Subtract the value of r^2 from 1: 1 - 0.04 = 0.96.
  - The coefficient of nondetermination is 0.96.

The coefficient of determination (r^2) measures the proportion of the dependent variable's variation that is explained by the independent variable. In this case, 0.04 indicates that only 4% of the dependent variable's variation is explained by the independent variable.

The coefficient of nondetermination (1 - r^2) represents the proportion of the dependent variable's variation that is not explained by the independent variable. Here, 0.96 implies that 96% of the dependent variable's variation is not explained by the independent variable.

In conclusion, given r = 0.2, the coefficient of determination (r^2) is 0.04, indicating a low degree of explanatory power. The coefficient of nondetermination (1 - r^2) is 0.96, suggesting a high amount of unexplained variation in the dependent variable.

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Answer:

-25

Explanation:

To solve this all you need to do is find the difference the difference between 35 and 10 is 25 however the number is getting smaller so this is negative displacement, therefore it is -25 displacement.

The ant’s aunt travels from the 35.00 cm mark to the 10.00 cm mark. The Aunt’s displacement is 25 cm.

Displacement is vector quantity. It has both magnitude and direction. It is expressed in m. Displacement is nothing but distance from mean position. Main difference between distance and displacement is distance is a total distance travelled by a body and displacement is distance from mean position. for example when a body moves from a point and travels to exact initial point where it has started, then distance will be the total distance it has travelled and displacement is zero cause mean position of point and final position of points are same.

Displacement is given by,

x = x₂ - x₁

where x₂ is final position and  x₁ is initial position.

given,

x₂ = 10 cm

x₁ = 35 cm

Displacement x = 10-35 = -25 cm

negative sign represents, ant is moving in negative x direction.

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The ant’s travels from the 35.00 cm mark to the 10.00 cm mark. The Aunt’s displacement is 25 cm.

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The magnitude of the total resistive force acting on a car to maintain a constant velocity on a flat road is directly proportional to the power required to keep the car moving.

If a car needs to generate 1 hp to maintain a constant velocity, then the total resistive force acting on the car would be equal to 1 hp. This force is a combination of several resistive forces such as friction, air resistance, and rolling resistance.

Friction between the tires and the road is an important resistive force that affects the motion of the car. Rolling resistance is created when the car's tires deform slightly as they roll, and this also adds to the total resistive force.

Air resistance, or drag, is also a major resistive force that affects the car's motion. Air resistance increases with higher velocities and affects the amount of power required to maintain a given speed.

Therefore, the magnitude of the total resistive force acting on a car to maintain a constant velocity on a flat road is equal to the power required to keep the car moving, which in this case is 1 hp.

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Answer:17.24 m/s

Explanation:

Answer:

C. Every person has a raw, magnetic energy.

Explanation:

Have taken the pre-test.

density = mass / volume

mass = 81.34 - 62

= 19.34 g

volume = 24.6 ml

density = 0.786 g/ml

The electric potential in the region of space around a 1nc charge is positive.

Electric potential is the amount of work required to move a unit charge from one point to another in an electric field. It is a scalar quantity, meaning it has magnitude but no direction. The sign of electric potential depends on the charge of the object creating the electric field. A positive charge creates a positive electric potential, while a negative charge creates a negative electric potential.

In the case of a 1nc charge, the electric potential in the region of space around it will be positive, as the charge itself is positive. This means that work must be done to move a positive charge away from the 1nc charge, and work will be done by the electric field to move a negative charge towards the 1nc charge.

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Answer:

11.25 m

Explanation:

From the question given above, the following data were obtained:

Spring constant (K) = 1.2 N/m

Energy (E) = 76 J

Compression (e) =?

Energy stored in a spring is given by the following equation:

E = ½Ke²

Where:

E => Energy stored in the spring.

K => spring constant

e => Extention or compression

With the above formula, we can obtain how much the spring has been squashed as follow:

Spring constant (K) = 1.2 N/m

Energy (E) = 76 J

Compression (e) =?

E = ½Ke²

76 = ½ × 1.2 × e²

76 = 0.6 × e²

Divide both side by 0.6

e² = 76 / 0.6

Take the square root of both side.

e = √(76 / 0.6)

e = 11.25 m

Thus, the spring has been squashed by 11.25 m

Answer:

4km

Explanation:

Distance=speed x time

Knowing this we know the time and speed

so it is 8 x .5= D

And 8 x .5 =4

If you have any questions let me know

The linear momentum of an object can be calculated using the formula:

Linear Momentum = Mass × Velocity

In this case, we are given the mass of the object as 2 kg. However, we are not directly given the velocity of the object. Instead, we are given the kinetic energy of the object, which can be related to its velocity.

The formula for kinetic energy is:

Kinetic Energy = 0.5 × Mass × \(Velocity^2\)

Given that the kinetic energy is 10 J and the mass is 2 kg, we can rearrange the formula to solve for the velocity:

10 J = 0.5 × 2 kg × \(Velocity^2\)

Dividing both sides of the equation by 1 kg and multiplying by 2, we get:

20 = \(Velocity^2\)

Taking the square root of both sides, we find:

Velocity ≈ √20 ≈ 4.47 m/s

Now that we know the velocity of the object, we can calculate its linear momentum using the formula:

Linear Momentum = Mass × Velocity

Linear Momentum = 2 kg × 4.47 m/s

Linear Momentum ≈ 8.94 kg·m/s

Therefore, the linear momentum of the 2-kg object is approximately 8.94 kg·m/s.

Linear momentum is a vector quantity and represents the quantity of motion of an object. It depends on the mass of the object and its velocity. In this case, the kinetic energy is used to determine the velocity of the object, which is then used to calculate the linear momentum.

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Answer:

27N

Explanation: workdone = force * distance

         Hence Force= workdone/distance

                               = 405/15

                               = 27N

Answer:

150000N

Explanation:

Given parameters:

Mass  = 6000kg

Acceleration due to gravity  = 25m/s²

Unknown:

Weight of the spacecraft on Jupiter  = ?

Solution:

Weight is the vertical force on a body;

         Weight = mass x acceleration

     Weight  = 6000 x 25  = 150000N

Approximately 1377.46 N of force is required on the input piston to lift the car weighing 1.80 × \(10^{4}\) N.

The force required on the input piston of the hydraulic jack can be calculated using the principle of Pascal's law, which states that the pressure exerted in a fluid is transmitted equally in all directions.

The ratio of the output force to the input force is equal to the ratio of the output piston area to the input piston area:

Force (output) ÷ Force (input) = Area (output) ÷ Area (input)

We can rearrange this equation to solve for the input force:

Force (input) = Force (output) × (Area (input) ÷ Area (output))

Given that the weight of the car is 1.80 × \(10^{4}\) N, the output force is 1.80 × \(10^{4}\) N. The input piston area is 0.0540 \(m^{2}\), and the output piston area is 0.710 \(m^{2}\).

Plugging these values into the equation, we have:

Force (input) = (1.80 × \(10^{4}\) N) × (0.0540 \(m^{2}\) ÷ 0.710 \(m^{2}\))

Simplifying the expression gives us:

Force (input) ≈ 1377.46 N

Therefore, approximately 1377.46 N of force is required on the input piston to lift the car weighing 1.80 × \(10^{4}\) N.

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Answer:

3 m/s^2

Explanation:

Acceleration = change in speed  /  change i time

                      = 15 m/s  / 5 s =  3 m/s^2

Answer:

72 m

Explanation:

Given:

v₀ = 0 m/s

v = 60 m/s

a = 25 m/s²

Find: Δx

v² = v₀² + 2aΔx

(60 m/s)² = (0 m/s)² + 2 (25 m/s²) Δx

Δx = 72 m

The substance is zircon, of which interference analysis is done.

Wavelength of light in solid = λ = 329 nm

Wavelength of light from he-ne laser = λ' = 633 nm

Interference effect = n =

= n =  λ' / λ

= n = 633 / 329

= n = 1.92

The interference, in physics, is the net effect of the combination of two or more wave trains moving on intersecting or coincident paths. The effect is that of the addition of the amplitudes of the individual waves at each point affected by more than one wave.

Thus the substance is zircon.

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Answer: 300 J

Explanation:

Force = 150 KJ

Distance = 2.0 m

The minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically would be 2940 Joules, as the work done is the product of the force applied to the displacement of the object, therefore the correct answer is option B.

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force × Displacement

As given in the problem we have to find out the minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically.

The minimum work done = 150 × 9.8 × 2

                                          = 2940 Joules

Thus, The minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically would be 2940 Joules.

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Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.

Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500

Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000

a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units

Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units

b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production

Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit

Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit

c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production

Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700

Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300

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Kepler's laws are fundamental principles of celestial mechanics and continue to be valid for all planets in our solar system, including the ones discovered after Kepler's era.

Kepler's laws of planetary motion are fundamental principles that describe the motion of planets around the Sun and were derived based on observational data available to Johannes Kepler during the 16th and 17th centuries. However, these laws are not limited to the six planets known in Kepler's time.

Kepler formulated three laws of planetary motion:

1. Kepler's First Law (Law of Ellipses): Planets orbit the Sun in elliptical paths, with the Sun located at one of the two foci of the ellipse. This law applies to all planets, including those discovered after Kepler's time.

2. Kepler's Second Law (Law of Equal Areas): An imaginary line connecting a planet to the Sun sweeps out equal areas in equal time intervals. This law holds for all planets, regardless of when they were discovered.

3. Kepler's Third Law (Harmonic Law): The square of a planet's orbital period is proportional to the cube of its average distance from the Sun. This law applies to all planets, both the ones known in Kepler's time and the ones discovered later.

Kepler's laws are fundamental principles of celestial mechanics and continue to be valid for all planets in our solar system, including the ones discovered after Kepler's era. They provide important insights into the motion and behavior of celestial bodies.

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Answer:

We know that the period of a pendulum is written as:

T = 2*pi*√(L/g)

where:

g = gravitational acceleration = 9.8m/s^2

pi = 3.1415...

L =  length of the pendulum, in this case, is the length of the brass pendulum.

Now, we know that the brass dilates when the temperature increases.

Then if the temperature increases, the value of L will increase, which means that the period T will also increase, because L is in the numerator of T.

If the period increases the complete motion of the pendulum needs more time, this would mean that the clock will run slower.

If the temperature decreases, the opposite occurs, the value of L decreases, and then the period also decreases, which means that the clock will run faster.

At the point X after 2 seconds, the stone has a magnitude of velocity equal to 10 m/s, and its direction is purely horizontal.

When a stone is projected horizontally in a vacuum, it only experiences horizontal motion due to the absence of air resistance. The vertical motion is governed by the force of gravity alone. In this scenario, the stone will undergo uniform horizontal motion with a constant horizontal velocity.

Given that the stone is projected horizontally with a velocity of 10 m/s, its horizontal velocity remains constant throughout the motion. After 2 seconds, the stone will have traveled a horizontal distance equal to the product of its horizontal velocity and the time, which is 10 m/s * 2 s = 20 m. Therefore, the stone will be located 20 meters horizontally from the point of projection. Since the stone is moving horizontally, its vertical velocity remains zero throughout the motion. The magnitude of the velocity at this point is equal to the horizontal velocity, which is 10 m/s. However, since the stone is moving horizontally, there is no vertical component of velocity.

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Parts of the mixer become hot because some of the electrical energy is converted into heat energy.

When electrical energy flows through a wire, it encounters resistance, which causes the wire to heat up. In a mixer, the electric motor converts electrical energy into mechanical energy to rotate the blades, but some of the electrical energy is lost as heat due to resistance in the motor's winding and other electrical components. This heat energy can accumulate in the mixer's parts and cause them to become hot. In many electrical devices, heat is an undesirable byproduct of energy conversion and can lead to reduced efficiency, damage, or safety hazards.

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--The complete Question is,  Fill in the blanks. " Parts of the mixer become hot because some of the electrical energy is changed into____"--

Answer:

a=2.5m/s²

Explanation:

a=F/m

=25N./10kg

If the distance from one wave crest to the next is 10 ft., the depth to the wave base be 5 ft.

The depth to the wave base can be estimated using the rule of thumb that states the depth is approximately equal to half the wavelength of the wave. In this case, if the distance from one wave crest to the next is 10 ft, then the wavelength of the wave would also be 10 ft. According to the rule of thumb, the depth to the wave base would be approximately half the wavelength, which is 10 ft divided by 2, resulting in a depth of 5 ft. This rule assumes that the waves are deep-water waves, meaning that the water depth is significantly greater than the wavelength of the wave.

It also assumes that the wave energy is dissipated entirely within the water column and not affected by the seafloor or other factors. It's important to note that this is a simplified estimation and actual wave behavior can be more complex, especially in shallower water or in the presence of other factors such as wave shoaling, wave breaking, and wave refraction. Detailed wave studies and measurements are necessary for accurate assessments of wave behavior and depths.

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