if the magnitude of charges on these source charges is arranged in a descending order, which is the correct sequence?a. a, b, c, db. b, d, c, ac. c, a, b, dd. d, b, a, ce. b, c, a, d

Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

The following propositions are true with regard to an object's points rotating around a fixed point. They all rotate at the same pace. All of them experience the same angular acceleration

The angular speed for a circular motion about a particular point is equal at all locations along the circular path and is calculated as;

Where

α=ω÷t

The number of rotations about a fixed point is N.

The time of motion is T.

As a result, the position of an item spinning around a fixed point has no bearing on its angular speed.

The specified same angular acceleration is

Each object in the circular path will move at a different tangential speed and acceleration depending on its position.

We may therefore draw the conclusion that the claims that are true for all points in the object spinning about a fixed point are that they all have the same angular acceleration and angular speed.

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Answer:

0.13m/s

Explanation:

jhghffhjffhjfhjfhjf

The simplified units for the given expression are kg•m^2•s^-

When simplifying the given units, we can apply the conversion factor of 1J = 1kg•s^-2•m^2. Let's break down the steps to simplify the units.

Start with the given units - kg•s^-1 (m•s^-2)^2.

Simplify the units inside the parentheses - (m•s^-2)^2 = m^2•s^-4.

Apply the conversion factor - 1J = 1kg•s^-2•m^2.

To simplify the units, we multiply the kg and m^2 terms and multiply the s^-1 and s^-2 terms. This results in kg•m^2•s^-3, which is the simplified form of the given expression.

In this simplified form, the kg represents mass, the m^2 represents area, and the s^-3 represents the inverse of time cubed. This unit can be used to measure energy, as indicated by the conversion factor of 1J.

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Answer:

Y: transparent objects i think

Answer:

The answer is B: X: Opaque Objects ; Y: Transparent Objects

Explanation:

The X column describes that the light that shines on that object is reflective, slightly absorptive, and no light passes through it. This describes opaque objects.  Opaque objects are mostly made up of solids, such as rocks and apples.

The Y column describes that the light that shines on it is sometimes refracted, sometimes absorbed, and sometimes reflected, but the light almost always passes through it.  This describes transparent objects. Transparent objects are mostly clear, so you can see through them, such as glass vases and windows.

Answer:

(B)

Explanation:

Because what ever angle the surface is, the light will reflect of of it perpendicular.

Answer:

true :D

Explanation:

Answer: power, renewable, extinct, solar, wind

Would appreciate brainliest <3

Answer:

chemical

mechanical

electrical

nuclear

thermal

brainliest ?

To optimize the performance of a solar cell for a specific wavelength, the thickness of the Si layer needs to be considered. Given the absorption coefficient for Si at 1000nm, three thicknesses are provided: 100μm, 180μm, and 300μm. The goal is to determine which thickness would yield better performance based on Beer-Lambert's law and the given parameters of minority carrier diffusivity and lifetime.

Beer-Lambert's law states that the absorption of light in a material is directly proportional to the thickness of the material and the absorption coefficient. In the case of a solar cell, thicker Si layers allow for more absorption of light. However, excessively thick layers may also lead to increased recombination of minority carriers, affecting the overall efficiency.

To determine the better performance, we need to consider the balance between light absorption and carrier recombination. A thicker Si layer will provide higher light absorption, but it may also lead to longer carrier diffusion lengths and increased recombination. Conversely, a thinner layer may have lower light absorption but potentially shorter carrier diffusion lengths and reduced recombination.

Based on the given information, it is not possible to definitively determine which thickness (100μm, 180μm, or 300μm) would yield the best performance without additional information about the diffusion length and recombination rates. A comprehensive analysis involving the specific characteristics of the solar cell and its design parameters would be necessary to make an informed decision.

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On gas-loaded accumulators, safety devices like relief valves, burst discs, and temperature fuse plugs are all used as  precautionary measures to maintain the efficiency​.

Accumulators are pressurized containers that can hold fluid. When a system needs a boost in power, this stored energy can be used, recharged, and then used again. The right precautions should be taken to keep pressure and temperatures under control because this stored energy can be hazardous.

On accumulators, a number of modest but crucial accessories can be placed to stop the release of this stored energy and guarantee that temperatures stay within their safe operating range.

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Answer:

p is =force x 10 whch is constant

A train has an initial velocity of 44meter per second and an acceleration of 4meter per second.The final velocity after 10 seconds is 84m/s.

As we know,

Acceleration= Final velocity-Initial velocity /time.

where acceleartion = a=4m/s².

Initial velocity= u= 44m/s

let final velocity be v

Time =t = 10seconds.

Therefore, the equation is:

a=v-u/t

Substituting the values in the given equation, we get:

4=v-44/10

Now cross multiplying,

4×10 = v-44

40=v-44

40+44=v

v=84m/s

Therefore, the final velocity after 10 seconds is 84m/s.

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The linear velocity in miles per hour of one of the teeth at the edge of the 15 inch diameter blade is approximately 178.2 mph.

Given that the blade on a typical table saw rotates at 4000 revolutions per minute and the diameter of the blade is 15 inches. Linear velocity is defined as the distance travelled per unit time. The formula for calculating the linear velocity of an object is given by; v = rω Where: v = Linear velocity, ω = Angular velocity. Angular velocity is defined as the angle swept by the object in radians per unit time. The formula for calculating angular velocity is given by;ω = (2πn) / 60 Where:ω = Angular velocity, n = Rotational speed. ω = (2π × 4000) / 60ω = 418.88 rad/s.  The diameter of the blade is given as 15 inches, hence the radius will be half of the diameter. r = d / 2r = 15 / 2r = 7.5 inches. Next, we need to convert the radius from inches to miles.1 mile = 63360 inches, r = 7.5 / 63360 miles, r = 0.00011847 miles. Substitute the value of r and ω in the formula v = rωv = 0.00011847 × 418.88v = 0.0495 miles/s. To convert miles per second to miles per hour, we multiply by 3600.v = 0.0495 × 3600v = 178.2 mph.

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Answer:

Push-ups. Let M1 be the mass of the body and M2 be the mass of weights. Assume that M1 must be heavier than M2. Since M1 is heavier, M1 requires more force, and therefore work to be applied, let F1=M1*g. To bring our body back up, we need a force bigger or equal (if already in motion) to F1.

Let F2 = M2*g

Since F1 has to be bigger than F2 due to mass, we can build an equation for energy. Let X be a displacement, which is equal in both situations. Constructing a change of energy equation we can see that work done to lift the body is greater:

W1=F1*x

W2=F2*x

Where W1 is the work of the hands-on body, and W2 is the work of lifting weights. W1 has to be larger than W2. Since more work in W1, more muscle will be needed to complete a repetition, but only assuming that M1 > M2.

If the fundamental frequency of the string is f, then the nth harmonic has a frequency n*f.

Firstly we know that standing waves are produce for 100, 200, 250, 300 Hz. So as each of these frequencies are multiples of f, f <= 50.

But we also know that there are no standing waves between the frequencies of 250 and 300. Thus f>= 50

Thus, f=50Hz

Fundamental frequency = 50 Hz

frequency of third harmonic = 150 Hz

Frequency, in physics, the variety of waves that skip a set factor in unit time; also, the number of cycles or vibrations gone through all through one unit of time by a body in periodic movement

Frequency is expressed in devices of hertz (Hz), that is equal to one occasion consistent with 2d.

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The solar wind, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, is a highly ionized plasma.

The solar wind, which is a stream of charged particles (plasma) emitted by the Sun, exhibits characteristics of a highly ionized plasma. As it travels from the Sun to the Earth, the solar wind encounters variations in temperature, density, pressure, and speed. In this case, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, the solar wind can be classified as a highly ionized plasma.

During a Coronal Mass Ejection (CME), eruptive phenomena on the Sun's surface cause a sudden release of a large amount of plasma and magnetic fields into space. This disturbance leads to an increase in the temperature of the solar wind to around 10^7 K and an increase in its speed to approximately 10^3 km/s. This enhanced energy and velocity result in a significant disruption of the solar wind's flow, making it a turbulent fluid.

Turbulent fluids are characterized by chaotic and irregular motion, with strong fluctuations and mixing. The increased temperature and speed during a CME generate turbulent behavior within the solar wind, leading to the disruption and mixing of plasma particles along its trajectory.

To determine the type of fluid flow, the Reynolds number (Re) is often used. It relates the flow's characteristics, such as velocity and length, to the fluid's viscosity. In this case, since the solar wind is a plasma and has negligible viscosity, the Reynolds number is extremely high, well above the turbulent threshold of 4000. Therefore, the solar wind with increased temperature and speed due to a CME can be classified as a turbulent fluid.

In summary, the solar wind, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, is a highly ionized plasma. However, during a Coronal Mass Ejection (CME), the temperature and speed of the solar wind increase significantly, leading to turbulent fluid behavior.

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A ray of light parallel to the optic axis of a concave mirror is reflected back through the focal point.

The reflection of a ray of light parallel to the principal axis of a concave mirror will pass through the focal point F' after reflection.

The point where the parallel beam intersects the principal axis after reflection is the focal point F' of the concave mirror.

A concave mirror also known as a converging mirror, is a spherical mirror that bulges inward.

When an object is placed in front of a concave mirror, the light rays that emanate from the object are reflected from the mirror's surface, and the image is formed.

When the object is located at the focal point F of the mirror, the light rays are reflected parallel to the mirror's axis of symmetry, generating an image at infinity.

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Answer:

0.832

Explanation:

8.320 x 10 to the negative 1st power is 0.832

Answer:

How we know, the equation is:

W = mg

Replacing according our data:

W = 53 kg × 9,8 m/s^2

Resolving:

W = 519,4 N

The weight of the object is of 519,4 Newtons.

An x-ray burst in an x-ray binary system and a nova are similar in that they both involve a sudden release of energy.

An X-ray burst in an X-ray binary system is similar to a nova in the following ways:

1. Both events involve the transfer of mass: In an X-ray binary system, mass is transferred from a donor star to a compact object (usually a neutron star). In a nova, mass is transferred from a donor star to a white dwarf.

2. Both events result in a sudden release of energy: An X-ray burst occurs when the accumulated mass on the surface of the compact object undergoes rapid nuclear fusion, producing a sudden burst of X-rays. In a nova, the transferred mass on the surface of the white dwarf ignites in a thermonuclear explosion, resulting in a sudden brightening of the star.

3. Both are temporary events: Both X-ray bursts and novae are short-lived phenomena. X-ray bursts typically last from a few seconds to a few minutes, while novae usually fade back to their pre-outburst brightness over several days to months.

4. Both are recurrent phenomena: X-ray bursts and novae can occur multiple times in the same system as long as the mass transfer process continues.

In summary, X-ray bursts and novae are similar in that they both involve mass transfer between two stars, result in a sudden release of energy, are temporary events, and can recur over time.

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Answer:

2s

Explanation:

As we know that ,

\(\longrightarrow\) v = u + at

\(\longrightarrow\) t = v - u / a

\(\longrightarrow\) t = (18 - 12)m/s ÷ 3m/s²

\(\longrightarrow\) t= 6/3 s

\(\longrightarrow\) t = 2s

Answer:

1.01×10^20 molecules of ozone.

Explanation:

Data obtained from the question include:

Volume (V) = 2 L

Temperature (T) = 275 K

Pressure (P) = 1.89×10¯³ atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) of ozone =.?

Using the ideal gas equation, we can obtain the number of mole of ozone as follow:

PV = nRT

1.89×10¯³ x 2 = n x 0.0821 x 275

Divide both side by 0.0821 x 275

n = (1.89×10¯³ x 2) /(0.0821 x 275)

n = 1.67×10¯⁴ mole.

Therefore the number of mole of ozone in 2 L of air is 1.67×10¯⁴ mole.

Finally, we shall determine the number of molecules present in 1.67×10¯⁴ mole of ozone.

This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of ozone contains 6.02×10²³ molecules.

If 1 mole of ozone contains 6.02×10²³ molecules,

therefore, 1.67×10¯⁴ mole of ozone will contain = 1.67×10¯⁴ x 6.02×10²³ = 1.01×10^20 molecules.

Therefore, 1.01×10^20 molecules of ozone are present in 2 L of air.

The correct answer for  the coefficient of static friction must be at least 0.51 for the car to round the curve without sliding.

The coefficient of static friction between the tires and the road must be at least 0.51 for a car to round a level curve of radius 140 m at a speed of 120 km/h.

First, we need to convert the speed from km/h to m/s:
120 km/h * (1000 m / 1 km) * (1 h / 3600 s) = 33.33 m/s

Next, we can use the formula for centripetal acceleration:
a_c = v^2 / r
where a_c is the centripetal acceleration, v is the speed, and r is the radius of the curve.

Plugging in the given values:
a_c = (33.33 m/s)^2 / 140 m = 7.86 m/s^2

The force of friction is what provides the centripetal force to keep the car on the curve. The force of friction is given by: F_f = μ_s * F_N
where F_f is the force of friction, μ_s is the coefficient of static friction, and F_N is the normal force.

Since the car is on a level curve, the normal force is equal to the weight of the car:
F_N = m * g
where m is the mass of the car and g is the acceleration due to gravity.

The centripetal force is also equal to the mass of the car times the centripetal acceleration:
F_c = m * a_c

Setting the force of friction equal to the centripetal force and solving for the coefficient of static friction:
μ_s * m * g = m * a_c
μ_s = a_c / g

μ_s = 7.86 m/s^2 / 9.8 m/s^2
μ_s = 0.51
Therefore, the coefficient of static friction must be at least 0.51 for the car to round the curve without sliding.

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Answer:

Kinetic Energy

Explanation:

Potential Energy is where something is building up energy to move.

Answer:

Kinetic Energy

Explanation:

Answer:

Compare brands first, but purchase the one that has lots of commercial advertisements, Compare ingredients and purchase the brand that is safe to use with soft contact lenses, Compare prices and purchase the most inexpensive brand.

Explanation:

Answer:

The orbital velocity an aircraft orbiting around a heavenly body is found as follows;

At the orbital velocity, \(F_G\) = \(F_C\)

Where;

\(F_G\) = The gravitational force = \(\dfrac{G \cdot M \cdot m}{R_E^2}\)

\(F_C\) = The centripetal force = \(\dfrac{m \cdot v_0^2}{R_E}\)

Therefore

\(v_0 = \sqrt{\dfrac{G \cdot M}{R_E} }\)

Therefore, at the orbital velocity of the spacecraft, the centripetal force attracting the person away from the central region heavenly body is equal to the gravitational force pulling the person towards the center of the heavenly body (which was felt as her or his weight), and the person feels weightless while inside the orbiting spacecraft

Explanation:

TNT has a heat of combustion of -3406 kJ/mol compared to sugar's -5639 kJ/mol.

what is heat of combustion?

The quantity of heat released when a specific amount of a substance undergoes burning is known as the heat of combustion, also known as the calorific value or the energy value. In most cases, the terms "heat of combustion" and "calorific value" are interchangeable. Calorific value is the term used to describe the total amount of energy released during the complete combustion of a given mass of a substance in the presence of (an adequate amount of) oxygen under typical conditions of pressure and temperature.

TNT has a heat of combustion of -3406 kJ/mol compared to sugar's -5639 kJ/mol.

TNT is an explosive because it explodes more quickly due to its lower heat of combustion. Sugar is not explosive and will take a lot longer to heat up or burn.

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Answer:

-5 m/s^2

Explanation:

10/2=5 and is is a stop so it is negitive

Answer:

linear motion

Explanation:

the birds in the sky show oscillatory motion when they flap their wings

Explanation:

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. ... Since the force required to lift it is equal to its weight, it follows that the gravitational potential energy is equal to its weight times the height to which it is lifted. PE = kg x 9.8 m/s2 x m = joules.

So, the PE is

3 x 9.8 x 4.5 = 132.3 J