If a planet has an angular size of 0.29 degrees, what will be its angular size in arcminutes?

Answer:

Steel

Explanation:

the most commonly used metal in the world

Answer:  arrows

Explanation:

A vector quantity is usually represented by an arrow, with the direction of the vector being the direction in which the arrow points and the length of the arrow representing the vector's magnitude.

What is the vector quantity unit?

The meter is the only fundamental SI unit that is a vector. The rest are all scalars. Derived quantities might be scalar or vector, but all vector quantities require meters as part of their definition and measurement.

The term "vector quantities" refers to physical quantities whose magnitude and direction are well specified.

Arrows are used to depict vectors. An arrow has a direction and a magnitude (how long it is) (the direction in which it points).

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Using the principle of 'least count', the uncertainty on the each of your measurements (in both cm and in) 0.1 cm.

According to the concept of significant figures, the last digit is considered to be the uncertain digit in a measurement.  Significant figures are generally used for establishment  of a number which is presented in the form of digits. These digits give a lot of meaningful representation  to the numbers.

The significant figures are the most significant digits that convey the meaning according to the accuracy. These provide provides a proper precision to the numbers and hence are called as significant numbers. There are numerous rules for counting significant figures which are as follows:

1)All non-zero digits are significant.

2)All zeroes which essentially occur between non-zero digits are significant.

3)All zeroes to the left and right of any non-zero digit are not significant.

4) All zeroes on right  of decimal are significant if a non-zero number follows them.

5)All zeroes on right side of non-zero digit are significant.

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The uncertainty on the length of the shoelace is 0.05 cm or 0.03125 in, depending on which unit is used.


The principle of least count states that the uncertainty in a measurement is equal to half the smallest division on the measuring tool. The ruler has two scales, one in centimeters and the other in inches.

The smallest division on the centimeter scale is 1 mm, which means the uncertainty is half of that, or 0.5 mm. Converting to centimeters, the uncertainty is 0.05 cm.

The smallest division on the inch scale is 1/16 inch, which means the uncertainty is half of that, or 1/32 inch. Converting to inches, the uncertainty is 0.03125 in.

Therefore, the uncertainty on the length of the shoelace is 0.05 cm or 0.03125 in, depending on which unit is used.

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Answer:

For two universe that is the same size, the universe with the faster expansion rate must be younger than the universe with a slower expansion rate. The slope in the line of the Hubble plot of the older universe will be flatter.

Explanation:

Hubble's law establishes a direct relationship between a galaxy's distance and its redshift-determined recessional velocity. The redshifts of galaxy clusters and distant galaxies are equivalent and proportional to their distances from us, according to Hubble's theorem.

Thus, to copy and complete the given question.

For two universe that is the same size, the universe with the faster expansion rate must be younger than the universe with a slower expansion rate. The slope in the line of the Hubble plot of the older universe will be flatter.

Answer:

I think it is C

Explanation:

a)

Since the force of 25 N is applied by a distance of 10 meters, we can calculate the work done:

Then, if all the energy is kinetic energy, we can calculate the box speed:

b)

The box slides up the hill, so part of the energy is now potential energy:

The remaining kinetic energy (250 - 196 = 54 J) will be converted into elastic potential energy of the spring:

Answer: By dividing airflow by duct cross section.

Explanation:

In short, air velocity in the ducts is calculated by dividing airflow by duct cross-section. Airflow is expressed as a simple number. Example: Air conditioner has a max. airflow of 600 CFM.

The time that elapses between a moment of maximum speed and the next moment of maximum acceleration is 2.43 seconds.

The time that elapses between a moment of maximum speed and the next moment of maximum acceleration is calculated as follows;

V (max) = 2πfA ------ (1)

a (max) = ( 2πf )² A ------ (2)

where;

Since both equations have amplitude, A, we will make A the subject of the formula.

A = (V.max) / ( 2πf)

A =  (a.max) / ( 2πf)²

(V.max) / ( 2πf) = (a.max) / ( 2πf)²

V.max = (a.max) / ( 2πf)

f = (a.max) / ( 2π x V.max)

Period, T, = 1 / f

T = ( 2π x V.max) / a.max

The period of the oscillation is calculated as follows;

T = ( 2π x 2.23 ) / ( 5.77 )

T = 2.43 seconds

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The impact speed of the mouse is 23.3 m/s as per the data given in the question.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

To solve for the impact speed, we can use the following equation:

\(v^2 = u^2 + 2as\)

Where:

v = impact speed,

u = initial speed (which is the horizontal speed of the owl),

a = acceleration due to gravity (9.8 m/\(s^2\)), and

s = vertical distance fallen (15.0 m).

Substituting the known values, we get:

\(v^2 = 16.0^2 + 2 X 9.8 X 15.0\)

\(v^2\) = 256 + 294

\(v^2\) = 550

v = sqrt(550 )

v = 23.3 m/s

Thus, the impact speed of the mouse is 23.3 m/s.

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Answer:

e

Explanation:

Answer:

75 cm/second.

Explanation:

Formula:

Walking speed = stride length / time per step

Walking speed = 90cm/time per step

                         = 90cm/1.2 seconds (a common estimate time per step)

                         = 75cm/second.

Answer:

μ = 0.41

Explanation:

\(\frac{1}{2} kx^2 = \mu mgd\)

\(\mu = (\frac{1}{2} kx^2)/mgd\)

\(\mu = (\frac{1}{2} (100)(0.2)^2)/(0.5)(9.81)(1)\)

\(\mu = 0.41\)

The coefficient of kinetic friction between the block and the tabletop is 0.41.

The given parameters;

The coefficient of kinetic friction between the block and the tabletop by applying the principle of conservation of energy as shown below.

Fd = Uₓ

μmgd = ¹/₂kx²

where;

The coefficient of kinetic friction between the block and the tabletop;

\(\mu_k = \frac{kx^2}{mgd} \\\\\mu_k = \frac{100\times 0.2^2}{2\times 0.5\times9.8 \times 1 } \\\\\mu_k = 0.41\)

Thus, the coefficient of kinetic friction between the block and the tabletop is 0.41.

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Explanation:

To determine the velocity and pressure head at position B in a horizontally converging pipe, we can use the principle of conservation of mass and Bernoulli's equation.

According to the principle of conservation of mass, the mass flow rate remains constant throughout the pipe. Therefore, we can write:

A₁V₁ = A₂V₂

where A₁ and A₂ are the cross-sectional areas at positions A and B, respectively, and V₁ and V₂ are the velocities at positions A and B, respectively.

Given:

A₁ = (π/4)(d₁)² = (π/4)(200 cm)² = 31416 cm²

A₂ = (π/4)(d₂)² = (π/4)(150 cm)² = 17671 cm²

V₁ = 2 m/s

We can calculate V₂ using the equation:

V₂ = (A₁V₁) / A₂

Substituting the values:

V₂ = (31416 cm² * 2 m/s) / 17671 cm² ≈ 3.54 m/s

Therefore, the velocity at position B is approximately 3.54 m/s.

Next, to determine the pressure head at position B, we can use Bernoulli's equation:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂² + ρgh₂

Assuming the datum is at position B, where the pressure head (h₂) is zero, the equation simplifies to:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂²

Given:

g = 10 m/s² (acceleration due to gravity)

Z = 0 m (datum)

ρ = density of the liquid (not given)

Since the density (ρ) of the liquid is not provided, we cannot determine the absolute pressure at position B or calculate the pressure head. The information given is insufficient to determine the pressure head at position B.

In summary:

- The velocity at position B is approximately 3.54 m/s.

- The pressure head at position B cannot be determined with the given information.

Answer:

false

Explanation:

it cant defined the messy and clean states

a. The free-body diagrams of the 8.0 kg box and the 2.0 kg mass is attached below.

bi) the acceleration of the system is 0.4 m/s^2

bii)  the tension in the string is 0.8 N.

Net force = ma

Net force = T - F_friction

where T is the tension force and F_friction is the frictional force.

Substituting the given values, we have:

T - F_friction = ma

T - 6.0 N = (8.0 kg + 2.0 kg) a (since the tension force acts on both masses)

T - 6.0 N = 10.0 kg a

(ii) To find the tension in the string, we can apply Newton's second law of motion to the 2.0 kg mass:

Net force = ma

where m is the mass of the mass and a is the acceleration of the system. The net force on the mass is the tension force:

Net force = T

Substituting the given values, we get:

T = ma

T = 2.0 kg x a

To solve for T, we need to find the acceleration of the system.

To find both a and T, we can use the equations we derived above and solve them simultaneously:

T - 6.0 N = 10.0 kg a (equation 1)

T = 2.0 kg x a (equation 2)

Substituting equation 2 into equation 1, we get:

2.0 kg x a - 6.0 N = 10.0 kg a

Solving for a, we get:

a = 0.4 m/s^2

Substituting a into equation 2, we get:

T = 2.0 kg x 0.4 m/s^2 = 0.8 N

Therefore, the acceleration of the system is 0.4 m/s^2 and the tension in the string is 0.8 N. of the system is 0.4 m/s^2 and the tension in the string is 0.8 N.

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There is decreased pressure on the air molecules as one moves higher and the air is thinner

We know that the air pressure decreases with height. This implies that the air is thinner as you move up to higher altitude. This is the idea behind the use of the phrase; "Thin air".

Now, owing to the fact that there is decreased pressure on the air molecules as one moves higher and the air is thinner, it is much harder to breath until her aunt adjusts to the higher altitude.

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Nabr is the answer bcoz in a chemical reaction reactants react to form new substances and according to your options NaBr should be the answer

Answer:

The temperature, the density, and the element of stars.

Explanation:

The spectral line also can tell us about any magnetic field of the star. The width of the line can tell us how fast the material is moving. We can learn about winds in stars from this.

The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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The speed of the cylindrical container will increase as you increase the temperature of the fluid.

The speed of an object moving down an inclined plane is determined by applying Newton's second law of motion.

F(net) = ma

where;

The net force on the object is determined by subtracting force of friction from the applied force and it is given as;

F(net) = F - Ff

F(net) = F - μmg

where;

When the temperature of the fluid inside the sealed cylindrical container increases, the container becomes more light because the fluid will acquire more kinetic energy and kinetic frictional force resisting the motion of the container reduces and consequently the speed of the cylindrical container will increase.

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Answer:

i dont know  man

Explanation:

i dont know man

Answer:

Explanation:

We shall find first the velocity of ball at the time when string breaks. Let it be v . During its fall on the ground , 1.02 m below, we use the formula

h = 1/2 gt² where t is time of fall .

1.02 = 1/2 x 9.8 x t²

t²= .2081

t = .456

During this time it travels horizontally at distance of 2.5 m with uniform velocity of v

v x .456 = 2.5

v  = 5.48 m /s

centripetal acceleration

= v² / r where r is radius of the circular path

= 5.48² / .478

= 62.82 m /s²

\(\sf\large \green{\underbrace{\red{Answer⋆}}}:\)

(a) R2, R3 are parallel and series with R1

(b) R1, R2 and R3 are in parallel

Explanation:

\( \sf R_1 = 2 \: ohm\\ \sf R_2 = 3 \: ohm \\ \sf R_3 = 6 \: ohm\)

(a)

\( \sf R_2 \: and \: R_3 \: are \: in \: parallel \\ \sf so \: let \: the \: total \: of \: R_2 \: and \: R_3 \: be \: R_a\)

\( \sf \large \frac{1}{R_a} = \frac{1}{R_2} + \frac{1}{R_3} \: as \: they \: are \: in \: parallel\)

\( \sf R_a = \frac{1}{3} + \frac{1}{6} \\ \\ \sf \frac{1}{R_a} = \frac{2 + 1}{6} \\ \\ \sf \frac{1}{R_a} = \frac{3}{6} \\ \\ \sf \frac{1}{R_a} = \frac{1}{2} \\ \\ \sf R_a = 2 \: ohm\)

Ra and R1 is in series

And there total will be R

\( \sf R = R_a + R_1 \\ \\ \sf R = 2 + 2 \\ \\ \sf R = 4 \: ohm\)

(b)

\( \sf R_1 R_2 \: and \:R_3 \: are \: in \: parallel \: so \: total \: be \: R\)

\( \sf \frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \\ \\ \sf \frac{1}{R} = \frac{1}{2} + \frac{1}{3} + \frac{1}{ 6} \\ \\ \sf \frac{1}{R} = \frac{3+ 2 +1 }{6} \\ \\ \sf \frac{1}{R} = \frac{6}{6} \\ \\ \sf R = 1 \: ohm\)

Answer:

thanks you too for boys sweater in parallel and remember word on mangal I can do a few

Explanation:

The mass of the child is 33.26 kg.

Mass can be defined the quantity of matter a body contained.

The S.I unit of mass is kilogram (kg)

To calculate the mass of the  child, we use the formula below.

Formula:

Where:

Make m the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the mass of the child is 33.26 kg.

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Answer:

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field.

Answer:

0.63 s

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 50 g

Extention (e) = 10 cm

Period (T) =?

Next, we obtained 50 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

50 g = 50 g × 1 Kg / 1000 g

50 g = 0.05 kg

Next, we shall convert 10 cm to m. This is illustrated below:

100 cm = 1 m

Therefore,

10 cm = 10 cm × 1 m / 100 cm

10 cm = 0.1 m

Next, we shall determine the force exerted on the spring. This can be obtained as follow:

Mass = 0.05 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = mg

F = 0.05 × 9.8

F = 0.49 N

Next, we shall determine the spring constant of the spring.

Extention (e) = 0.1 m

Force (F) = 0.49 N

Spring constant (K) =?

F = Ke

0.49 = K × 0.1

Divide both side by 0.1

K = 0.49 /0.1

K = 4.9 N/m

Finally, we shall determine the period as follow:

Mass = 0.05 Kg

Spring constant (K) = 4.9 N/m

Pi (π) = 3.14

Period (T) =?

T = 2π√(m/k)

T = 2 × 3.14 × √(0.05 / 4.9)

T = 6.28 × √(0.05 / 4.9)

T = 0.63 s

Thus, the period of oscillation is 0.63 s