Identify the item that does not have kinetic energy.
A. A worm crawling
B. A falling leaf
C. An airplane flying
D. A butterfly sitting on a twig

Answer:

Delete your discord acc, and make another one. Prob should change email tbh. If he keeps doing it you can report him, because it's like online stalking.

Explanation:

Answer:

(a )people separate mixtures in order to ger a specific substance that they need.

Answer:

Radiation is being released from the reactor.

Explanation:

( A P E X )

Answer:

5.38 L

Option D.

Explanation:

2 NaOH(s) + 2 Al(s) + 6 H₂O(l)   →  2 NaAl(OH)₄(s)  + 3 H₂(g)

We convert mass of Al to moles:

4.32 g . 1 mol /26.98g = 0.160 moles

As NaOH is in excess, aluminum is the limiting reactant.

We see stoichiometry, were ratio is 2:3.

2 moles of Al can produce 3 moles of hydrogen

Our 0.160 moles may  produce (0.160 . 3)/2 = 0.240 moles of H₂.

We know that 1 mol of any gas at STP conditions is contained in 22.4L

So let's make the conversion factor:

0.240 mol . 22.4L / 1mol = 5.38 L

Answer:

The human population has increased by the billions, and we have been creating better and more complex technology over the years. So, overall there is a difference between now and 50 years ago.

Answer:

0.102 mol

Explanation:

Step 1: Write the balanced equation

PCl₅ + 4 H₂O ⇒ 5 HCl + H₃PO₄

Step 2: Calculate the moles corresponding to 7.36 g of H₂O

The molar mass of H₂O is 18.02 g/mol.

7.36 g × 1 mol/18.02 g = 0.408 mol

Step 3: Calculate the moles of PCl₅ required to react with 0.408 moles of H₂O

The molar ratio of PCl₅ to H₂O is 1:4.

0.408 mol H₂O × 1 mol PCl₅/4 mol H₂O = 0.102 mol PCl₅

The volume occupied by the 0.75 mole of the gas at 295 K and a pressure of 1.5 atm is 12.11 L

From the question given above, the following data were obtained:

Ideal gas equation is written as shown below:

PV = nRT

When we input the given parameters, the volume occupied is obatined as:

1.5 × V = 0.75 × 0.0821 × 295

Divide both sides by 4.31

V = (0.75 × 0.0821 × 295) / 1.5

V = 12.11 L

Thus, from the above calculation, we can say that the volume occupied by the gas is 12.11 L

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Answer:

Meaning, Advantages & Disadvantages of - Osmosis, Multiflash Distillatiob

Explanation:

Advantages - It assists equalising concentration of solute on two sides of membrane. Reverse Osmosis is used for efficient water softening, it is easy to maintain.

Disadvantages - It needs a lot of energy. A lot of pressure is required for deionisation. Water acidity level increases, as minerals get deionised.

Advantages - Its Cost efficient , distillation uses waste heat. It has High gain output ratio. Quality of feedwater is less significant, compared to reverse osmosis.

Disadvantages - It has high operating cost in case of waste heat unavailability. High temperature imply high corrosion & scale formation.

The sample containing 7.1 × 10^19 molecules of H2O corresponds to approximately 1.18 × 10^(-4) moles of H2O.

To determine the number of moles of H2O in a sample containing 7.1 × 10^19 molecules, we need to use Avogadro's number, which states that 1 mole of any substance contains 6.022 × 10^23 molecules.

Given that there are 7.1 × 10^19 molecules of H2O in the sample, we can calculate the number of moles using the following formula:

Moles = Number of molecules / Avogadro's number

Moles = 7.1 × 10^19 / 6.022 × 10^23

Moles ≈ 1.18 × 10^(-4) moles

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Hi!

\(\\ \sf\rightarrow pH=-log[H^+]\)

\(\\ \sf\rightarrow -log[H^+]=6.1\)

\(\\ \sf\rightarrow log[H^+]=-6.1\)

\(\\ \sf\rightarrow [H^+]=10^{-6.1}\)

\(\\ \sf\rightarrow [H^+]=7.94M\)

Answer:

See the explanation

Explanation:

We have to start by analyzing the molecule. In the molecule, we have two types of isomerism. In the double bond, we can have E or Z isomerism, and additionally, we have a chiral carbon (a carbon with 4 different bonds) (See figure 1). With this in mind, we can have 4 possible isomers.(See figure 2).

a) (3S)-2-(E)-ichthyothereol

b) (3R)-2-(E)-ichthyothereol

c) (3R)-2-(E)-ichthyothereol

d) (3R)-2-(Z)-ichthyothereol

I hope it helps!

Answer:

Basically a muscle is tissue but sometimes they are also called organ

So the answer should be D...a tissue

The muscle in Lane's arm would best be described as a tissue. Option D is correct.

The tissues in the body of an organism are made up of a group of cells that work as a building block for tissues to build up and after that these tissues make a group of them to develop the organs in the body.

Muscles are the form of tissues only which can be of different types too. These can be tears which can cause major injuries in the body as they help the body for the movement of the body.

A collection of cells with similar structures and functions is referred to as a tissue. The intercellular matrix, a nonliving substance, fills the spaces between the cells. There might be a lot of this in some tissues and not much in others.

Therefore, Option D is correct. The muscle in Lane's arm would best be described as a tissue.

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Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: \(V_{1}\) = 571 mL,       \(T_{1} = 26^{o}C\)

(a) \(T_{2} = 5^{o}C\)

The new volume is calculated as follows.

\(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL\)

(b) \(T_{2} = 95^{o}F\)

Convert degree Fahrenheit into degree Cesius as follows.

\((1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C\)

The new volume is calculated as follows.

\(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL\)

(c) \(T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C\)

The new volume is calculated as follows.

\(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL\)

Answer:

Explanation:

Molal freezing point depression constant of butanol Kf = 8.37⁰C /m

ΔTf = Kf x m , m is no of moles of solute per kg of solvent .

mol weight of butanol = 70 g

235.1 g of butanol = 235.1 / 70 = 3.3585 moles

3.3585 moles of butanol dissolved in 4.14 kg of water .

ΔTf = 8.37 x 3.3585 / 4.14

= 6.79⁰C

Depression in freezing point = 6.79

freezing point of solution = - 6.79⁰C .

13.1% m/v is  the mass percent by volume of 44.1 g of glucose (C₆H₁₂O₆, MM = 180.2 g/mol) in 325 mL of solution.

\(% m/v=mass solute/volume solution * 100%=42.6g/325mL *100%=13.1%m//v\)% m/v = mass solute/volume solution x 100%

\(% m/v=mass solute/volume solution * 100%=42.6g/325mL *100%=13.1%m//v\)% m/v =44.1g/325 mL x 100%

\(% m/v=mass solute/volume solution * 100%=42.6g/325mL *100%=13.1%m//v\)% m/v =13.1% m/v

An object's volume in three dimensions is determined by the area encompassed inside its boundaries. It is also known as the object's capability on occasion. Calculating how much is required to fill an object can be done using its volume; for example, how much water is required to fill a bottle, aquarium, or water tank.

The most fundamental and typical kind of three-dimensional form is a sphere. Spheres are frequently seen as balls, globes, holiday lights, oranges, etc.

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Answer:

less

Explanation:

the more heat it has, the less a given heat will affect it

Answer:

more heat

Explanation:

Answer:

True

Explanation:

Answer:No, the Cell Membrane does I'm pretty sure

Explanation:

The value that is going to show us that there a large amount of B at equilibrium is 9×105 and 5000.

The term reversible reaction is a reaction that could go in either direction. This implies that the reaction could go either in the forward or in the reverse direction as we can see from the equation that we have in the question above.

If the reaction is such that does go in a reversible manner, we know that there would be more B if the equilibrium constant is high and this means that the value that would give a level of B is 9×105 and 5000. This is because these values are large and positive and show a complete conversion of reactants to products.

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Answer: 9.53 *2= 19.06

Explanation:

The law of multiple proportions states that if two elements combines to form more than one compound the ratio of masses of the second element which combines to the fixed mass of the first element will always be the ratios of the small whole numbers.

in case of carbon monoxide, mass of carbon will be the same of mass of oxygen.

But in case of carbon dioxide, if carbon is 9.53 units then oxygen will be twice as that of carbon.

CO2, so 9.53*2= 19.06 grams of oxygen will combine with 9.53 grams of carbon to form carbon dioxide.

d. The mass of the reactants and products is equal and is not dependent on the physical state of the substances explains the correct statement about the law of conservation of mass.

The law of conservation of mass is the law that states that matter or energy can neither be created nor destroyed. This means that the amount of matter in the universe is always the same. The law of conservation of mass is a fundamental law of physics and it is always obeyed by all physical processes.

The amount of matter in a closed system (one that is not subject to outside influences) will remain constant over time.

It is always obeyed even under the most extreme conditions, such as during nuclear reactions.

Hence, the correct option is d.

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The term molefraction is an important method which is used to calculate the concentration of a solution. It is mainly employed to calculate the concentration of a binary solution. Here the molefraction is 1 / 5. The correct option are D, D and B.

Molefraction of any component of a solution is defined as the ratio of the number of moles of that component to the total number of moles of the solution. The sum of molefraction of solute and solvent is one.

Here the molefraction of nitrogen = Moles of nitrogen / Total number of moles

1. 'x' of 'N' = 2 / 5 + 3 + 2 = 0.2 or 1 / 5

2. Molefraction of Argon = 0.60 / 0.40 + 0.04 + 0.60 = 0.57

Partial pressure = Molefraction × Total pressure

0.57 × 6.3 = 3.59 atm

3. 20 cm³ mixture contains:

20 × 1 mole / 22400 m³ = 8.9286 × 10⁻⁴

1 mole occupies 22400 cm³

8.9286 × 10⁻⁴ × 22400 cm³ / 1 mole = 20 cm³

Thus the correct option are D, D and B.

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16.52 milliliters of 8.54×10⁻² M Ba(OH)2(aq) are required to titrate 54.90 mL of 5.14×10⁻² M HNO₃

A titration is a procedure that uses a known solution to determine the concentration of an unknown solution. Until the reaction is finished, the titrant (the known solution) is typically supplied from a buret to a known volume of the analyte (the unknown solution).

Titration is an essential technique in analytical chemistry, and it is also known as volumetric analysis.

n-factor for Ba(OH)₂ =2

Thus, dilution equation becomes:

n × M₁V₁= M₂V₂

2 x 8.54 x 10⁻² x V₁ = 5.14 x 10⁻² x (54.90/1000)

V₁= 16.52 × 10⁻³¹

V₁   = 16.52 ml

Thus, 16.52 milliliters of 8.54×10⁻² M Ba(OH)2(aq) are required to titrate 54.90 mL of 5.14×10⁻² M HNO₃

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Answer:

Explanation:

Consider the given reaction,

A+B +C

\(rate=k[A]^m[B]^m\)

Reaction is first order with respect to reactant B.

The pseudo order rate is

\(rate=k_1 [B]^m,\\\\where k_1 =k[A]^m\)

Pseudo order reaction is the reaction in which the reactant concentration remains constant; its concentration is very high so it does not involve in the rate of the reaction. Here, the concentration of  A is sufficiently high so this reaction becomes the pseudo first order reaction.

The reaction is first order with respect to [B] with rate constant k1 .

Using the given table, concentration of  B is decreasing the rate also decreasing

Therefore, order of the reaction with respect to A  is 1.

The order of the reaction in reactant A is 1, means the value of m for given rate should be 1.

Pseudo order reactions are those reactions in which two reactants are present but the concentration of one of the reactant is present in excess quantity and it seems like first order reaction.

Given chemical reaction is: A + B +C

According to the question, given reaction is first order with respect to the reactant B and rate law will be represented as:

Rate = k[A]m[B]m

Also given that reactant A is present in high concentration in the reaction, so the rate of pseudo order reaction is:

Rate = k1[B]n, where

k1 = k[A]m

According to the given table with respect to concentration of reactant B and rate k1, it is clear that rate of the reaction decreases as the concentration of reactant B decreses. So, to get the required result order of the reaction or value of m with respect to the reactant A should be 1.

Hence option (B) is correct i.e. 1.

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From the solution that we have in the question;

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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There are approximately 3.47 x 10²² molecules in 5.657g H₂SO₄.

To calculate the number of molecules in 5.657g H₂SO₄, we need to use the Avogadro's number and the molar mass of H₂SO₄.

The molar mass of H₂SO₄ is 98.079 g/mol.

We need to calculate the number of moles of H₂SO₄:

Number of moles = mass/molar mass

                             = 5.657g / 98.079 g/mol

                            = 0.05767 mol.

Then, we can use Avogadro's number, which is 6.022 x 10²³ molecules/mol, to find the number of molecules:

Number of molecules = number of moles x Avogadro's number

                                   = 0.05767 mol x 6.022 x 10²³ molecules/mol

                                    = 3.47 x 10²² molecules

To calculate the number of molecules in a given sample of a substance, you need to use the Avogadro's number, which is 6.022 x 10²³ molecules/mol. This means that one mole of a substance contains 6.022 x 10²³ molecules.

We are given the mass of H₂SO₄, which is 5.657 g. To calculate the number of molecules, we first need to determine the number of moles of H₂SO₄ in the given sample. The molar mass of H₂SO₄ is 98.08 g/mol. So, the number of moles of H₂SO₄ can be calculated as follows:

moles = mass / molar mass

moles = 5.657 g / 98.08 g/mol

moles = 0.0576 mol

Now, we can use the Avogadro's number to determine the number of molecules of H₂SO₄ in 0.0576 moles:

number of molecules = moles x Avogadro's number

number of molecules = 0.0576 mol x 6.022 x 10²³ molecules/mol

number of molecules = 3.47 x 10²² molecules

As a result, in 5.657 g of the material, there are roughly 3.47 x 1022 molecules of H₂SO₄.

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