I need answers ASAP please

Answer:

- Banking Operations salary in India with less than 1 year of experience to 10 years ranges from ₹ 1.4 Lakhs to ₹ 7 Lakhs with an average annual salary of ₹ 3.1 Lakhs based on 261 latest salaries

Probability = # of desired options / # of total options

Our desired option is blue and there are 9 blue marbles in the bag.

There are 32 total marbles (options) in the bag.

P(blue) = 9 / 32 = 0.28125 = 28.125%

Hope this helps!

The difference between 884,283 - 349,407 is calculated to be 534,876

The difference is a term used to represent subtraction, hence in the problem is solved using the mathematical operation known as subtraction

To subtract in mathematics is to take something away from a group or a number of objects. The group's total number of items decreases or becomes lower when we subtract from it.

The operation is done as follows

= 884,283 - 349,407

= 534,876

The subtraction gives 534,876

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Answer:

30 divided by 0.08 will get you 375

Step-by-step explanation:

Answer:

The depreciation tax shield for this project in year 4 is $178.24.

Explanation:

To calculate the depreciation tax shield for this project in year 4, we need to first determine the depreciation expense for year 4 using the MACRS three-year class life category and the double-declining balance (DDB) method.

From Table 12.8 on page 415 of the textbook, we can see that the depreciation rate for year 1 is 33.33%, for year 2 it is 44.45%, for year 3 it is 14.81%, and for year 4 it is 7.41%.

Using the DDB method, we can calculate the depreciation expense for each year as follows:

Year 1: Depreciation expense = $14,000 x 33.33% = $4,667

Year 2: Depreciation expense = ($14,000 - $4,667) x 44.45% = $3,554

Year 3: Depreciation expense = ($14,000 - $4,667 - $3,554) x 14.81% = $830

Year 4: Depreciation expense = ($14,000 - $4,667 - $3,554 - $830) x 7.41% = $557

The total depreciation expense over the four years is the sum of the individual year's depreciation expenses, which is:

$4,667 + $3,554 + $830 + $557 = $9,608

Now, we can calculate the depreciation tax shield in year 4. The depreciation tax shield is the amount of the depreciation expense that reduces the firm's taxable income, multiplied by the tax rate. In year 4, the depreciation tax shield is:

Depreciation tax shield = Depreciation expense in year 4 x Tax rate

Depreciation tax shield = $557 x 32% = $178.24

Therefore, the depreciation tax shield for this project in year 4 is $178.24.

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U thought this was a professional answer?!!!!??????

You're wrong!!!!!!!!!!!!!!!!!

But the answer is correct though...

:))

PEW PEW PEW

Bing Chilling

It's over...

No more to read

Happy birthday if it's ur birthday...

Have a nice day my king:)

Answer:

3

Step-by-step explanation:

you have 1/3, to find out how many ninths you have, you must multiply the denominator by three (because 3*3=9). whatever you multiply on the bottom you must multiply on the top (if you don't do that then it's not the same as 1/3 anymore)

therefore 1/3 == (1*3)/(3*3) == 3/9

if you want to know how many twelves it was then you multiply by 4 to get 12 on the bottom:

1/3 == (1*4)/(3*4) == 4/12

therefore 1/3 == 3/9 == 4/12. they are all the same fraction

There are a total of 3 forwards on the team.

A fraction represents a part of the whole or group of objects.In a fraction, numerator and denominator are separated by a horizontal bar known as the fractional bar

Given:

2/8 of the players are forwards.

Total number of players on the team = 12

We will determine the total number of forwards on the team by multiplying the total number of players by the fraction representing the forwards.

Fraction representing the forwards:

= 2/8

= 1/4

Total forwards on the team:

= 12 * (1/4)

= 3.

Translated question:

Of the 12 players on the team, 2/8 are forwards. What are the total forward in the team?

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Answer:0.34 or .34

Step-by-step explanation:

Answer: A

Step-by-step explanation:

\(-\frac{4}{x}+1=0\\\\1=\frac{4}{x}\\\\x=4\)

The linear equations in slope-intercept form are  y=2x+3 ,  y=-1x-2 , y=-3x+4 and y = 3x .

What is linear equation ?

Linear equation can be defined as equation in which highest degree is one.

Given ,

We have to write linear equations in slope intercept form.

So,

An equation in the slope-intercept form is written as

y = mx + b

Where m is the slope of the line and b is the y-intercept. You can use this equation to write an equation if you know the slope and the y-intercept.

So, from given graphs we can say that

y - 3 = 2x

y=2x+3

y + 2 = -x

y=-1x-2

y - 4 = -3x

y=-3x+4

y - 0 = 3x

y=3x+0

y = 3x

Therefore, The linear equations in slope-intercept form are  y=2x+3 ,  y=-1x-2 , y=-3x+4 and y = 3x .

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Answer:

If that's the whole question then what exactly are we trying to solve here?

Step-by-step explanation:

Since we are only interested in the positive solution, the time it will take for her to land safely on the net is:

t = 1 second.

To write a quadratic function to represent the height h of the acrobat t seconds after the jump, we can use the following formula:

\(h(t) = -16t^2 + vt + h0\)

Where h0 is the initial height of the acrobat, which is 25 feet, and v is the initial vertical velocity, which is 4 ft/s. Plugging in these values, we get:

\(h(t) = -16t^2 + 4t + 25\)

To find how long it will take for her to land safely on the net, we need to find the time at which h(t) = 5. In other words, we need to solve the equation:

\(-16t^2 + 4t + 25 = 5\)

Simplifying this equation, we get:

\(-16t^2 + 4t + 20 = 0\)

Dividing both sides by -4, we get:

\(4t^2 - t - 5 = 0\)

Now we can use the quadratic formula to solve for t:

\(t = (-b ± \sqrt(b^2 - 4ac)) / 2a\)

Where a = 4, b = -1, and c = -5. Plugging in these values, we get:

\(t = (1 ± \sqrt(1 + 4(4)(5))) / 8\)

Simplifying this equation, we get:

\(t = (1 ± 9) / 8\)

So, the two solutions are:

\(t = 1 and t = -5/4\)

Since we are only interested in the positive solution, the time it will take for her to land safely on the net is:

t = 1 second.

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Answer:

Step-by-step explanation:

Circle degrees total 360 .  

360 - 126 -54-54 (other side of vertical angles) equals 126 degrees left for the other two remaining sections.  

14x+4  +15x+6 =126

19x+10 = 126

29x = 116

x=4 .  answer .

Tan(angle) = opposite/ adjacent

tan(42) = 67/x

x =67/tan(42)

X = 74.411

rounded to nearest tenth : x = 74.4

Surely you mean

\(x^4 + 2x^3 + 7x^2 - 6x + 44\)

The coefficients are integers, so the conjugate of any complex root to the quartic is also a root. In particular,

\(-2 + i\sqrt7 \text{ and thus } -2 - i\sqrt7\)

are roots, as are

\(1 - i\sqrt3 \text{ and } 1 + i\sqrt3\)

Then the complete factorization is

\(\boxed{(x - (-2 + i\sqrt7)) (x - (-2 - i\sqrt7)) (x - (1 + i\sqrt3)) (x - (1 - i\sqrt3))}\)

which we can simplify to get a factorization involving only integer coefficients,

\((x^2 + 4x + 11) (x^2 - 2x + 4)\)

A factorization of \(x^4+2x^3+7x^2-6x+44\) is \((x^2+4x+11)(x^2-2x+4)\).

If the roots of the polynomial \(p(x)=ax^4+bx^3+cx^2+dx+e\) are \(r_1,r_2,r_3,r_4\), then it can be factorized as \(p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4)\).

Here, we are to find a factorization of \(p(x)=x^4+2x^3+7x^2-6x+44\). Also, given that \(-2+i\sqrt{7}\) and \(1-i\sqrt{3}\) are roots of the polynomial.

Since \(p(x)=x^4+2x^3+7x^2-6x+44\) is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, \(-2-i\sqrt{7}\) and \(1+i\sqrt{3}\) are also roots of the given polynomial.

Thus, all the four roots of the polynomial \(p(x)=x^4+2x^3+7x^2-6x+44\), are: \(r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}\).

So, the polynomial \(p(x)=x^4+2x^3+7x^2-6x+44\) can be factorized as follows:

\(\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)\)

Therefore, a factorization of \(x^4+2x^3+7x^2-6x+44\) is \((x^2+4x+11)(x^2-2x+4)\).

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Around 0.000125 or 0.0125% of the time, the song will be played exactly six out of seven days.

Every day represents a trial in this binomial probability issue, and there are only two potential results:

either the music is played (a success), or it is not (failure). We're looking for the likelihood that exactly 6 out of 7 trials will be successful.

The likelihood of success (performing the song) is 1/6, while the likelihood of failure (not playing the song) is 1 - 1/6 = 5/6, on any given day.

We can use the binomial probability formula to find the probability of exactly 6 successes in 7 trials:

P(6 successes) = (7 choose 6) * (1/6)⁶ * (5/6)¹

where (7 choose 6) is the number of ways to choose 6 days out of 7 to play the song, and is calculated as:

(7 choose 6) = 7! / (6! * 1!) = 7

Plugging in the values, we get:

P(6 successes) = 7 * (1/6)⁶ * (5/6)¹

P(6 successes) ≈0.00012502

Therefore, the probability that the song will be played on exactly 6 days out of 7 is approximately 0.000125 or 0.0125%.

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Answer:

mZCAD=310°

Step-by-step explanation:

M2BAC=1,m2DAE=3 and m-BAE=0 therefore solution will be 310°

Answer: x = -1

Step-by-step explanation:

simplify 2(x + 7) 2 / 3 = 8 to 4x + 28 = 24 and then solve it from there

Answer:

12(a+b+c)

Step-by-step explanation:

how to verify:

Distribute 12 and you'll get the original expression

I hope my answer was helpful!

Answer:

x = 8 or x = -2

Step-by-step explanation:

x^2 - 6x + 9 = 25

x^2 - 6x - 16 = 0

The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a

with a = 1

b = -6

c = -16

substitute in the formula

x = [-(-6) +/- √(-6^2 - 4(1)(-16))]/2(1)

x = [6 +/- √(36 + 64)]/2

x = [6 +/- √10]/2

x = [6 +/- 10]/2

x1 = [6 + 10]/2 = 16/2 = 8

x2 = [6 - 10]/2 = -4/2 = -2

Answer:

x = 8,-2

Step-by-step explanation:

First, complete the square on LHS (Left-Handed Side).

\(\displaystyle \large{x^2-6x+9=(x-3)^2}\)

Make sure to recall the perfect square formula. Rewrite another equation with (x-3)² instead.

\(\displaystyle \large{(x-3)^2 = 25}\)

Square both sides of equation.

\(\displaystyle \large{\sqrt{(x-3)^2}=\sqrt{25}}\)

Because x² = (-x)² which means that it’s possible for x to be negative. Thus, write plus-minus beside √25 and cancel square of LHS.

\(\displaystyle \large{x-3=\pm \sqrt{25}}\\ \displaystyle \large{x-3=\pm 5}\\ \displaystyle \large{x=\pm 5+3}\)

Therefore, x = 5+3 or x = -5+3

Thus, x = 8,-2

The method above is called completing the square method.

1. The zeros of the given quadratic function are -4 and 0

2. The axis of symmetry is at x = -2

3. The vertex of the quadratic function is (-2, 4)

4. The quadratic function opens down

5. Maximum

6. The maximum value is y = 4

From the question, we are to determine the given properties of the quadratic function

1. The zero(s) of a quadratic function is(are) the point(s) where the curves intersect(s) with the x-axis

The zeros of the given quadratic function are -4 and 0

2. The axis of symmetry is at x = -2

3. The vertex of a quadratic function is the coordinates of the lowest or highest point of the function. The vertex of the quadratic function is (-2, 4)

4. The quadratic function opens down

5. Maximum

6. The maximum value is y = 4

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The length of the zip wire is approximately 25.42 meters.

To calculate the length of the zip wire, we can use trigonometry and the given information about the angle and the distance between the two posts.

Given:

Distance between the two posts: 25m

Angle of the zip wire to the horizontal: 10°

We can use the trigonometric function cosine (cos) to find the length of the zip wire. Cosine relates the adjacent side to the hypotenuse of a right triangle.

In this case, the adjacent side is the distance between the two posts (25m) and the hypotenuse is the length of the zip wire that we want to calculate.

Using the cosine function:

cos(angle) = adjacent/hypotenuse

cos(10°) = 25m/hypotenuse

To find the hypotenuse (length of the zip wire), we can rearrange the equation:

hypotenuse = 25m / cos(10°)

Using a calculator or trigonometric tables, we can find the value of cos(10°) to be approximately 0.9848.

Therefore, the length of the zip wire is:

hypotenuse = 25m / 0.9848 ≈ 25.42m

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Answer:

\(S_{1893} =5632.98\)

Step-by-step explanation:

The correct form of the question is:

\(S = 1.001^{1892} + ... + 1.001^2 + 1.001 + 1\)

Required

Solve for Sum of the sequence

The above sequence represents sum of Geometric Sequence and will be solved using:

\(S_n = \frac{a(1 - r^n)}{1 - r}\)

But first, we need to get the number of terms in the sequence using:

\(T_n = ar^{n-1}\)

Where

\(a = First\ Term\)

\(a = 1.001^{1892}\)

\(r = common\ ratio\)

\(r = \frac{1}{1.001}\)

\(T_n = Last\ Term\)

\(T_n = 1\)

So, we have:

\(T_n = ar^{n-1}\)

\(1 = 1.001^{1892} * (\frac{1}{1.001})^{n-1}\)

Apply law of indices:

\(1 = 1.001^{1892} * (1.001^{-1})^{n-1}\)

\(1 = 1.001^{1892} * (1.001)^{-n+1}\)

Apply law of indices:

\(1 = 1.001^{1892-n+1}\)

\(1 = 1.001^{1892+1-n}\)

\(1 = 1.001^{1893-n}\)

Represent 1 as \(1.001^0\)

\(1.001^0 = 1.001^{1893-n}\)

They have the same base:

So, we have

\(0 = 1893-n\)

Solve for n

\(n = 1893\)

So, there are 1893 terms in the sequence given.

Solving further:

\(S_n = \frac{a(1 - r^n)}{1 - r}\)

Where

\(a = 1.001^{1892}\)

\(r = \frac{1}{1.001}\)

\(n = 1893\)

So, we have:

\(S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{1 -\frac{1}{1.001} }\)

\(S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{\frac{1.001 -1}{1.001} }\)

\(S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{\frac{0.001}{1.001} }\)

\(S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001^{1893}})}{\frac{0.001}{1.001} }\)

Simplify the numerator

\(S_{1893} =\frac{1.001^{1892} -\frac{1.001^{1892}}{1.001^{1893}}}{\frac{0.001}{1.001} }\)

\(S_{1893} =\frac{1.001^{1892} -1.001^{1892-1893}}{\frac{0.001}{1.001} }\)

\(S_{1893} =\frac{1.001^{1892} -1.001^{-1}}{\frac{0.001}{1.001} }\)

\(S_{1893} =(1.001^{1892} -1.001^{-1})/({\frac{0.001}{1.001} })\)

\(S_{1893} =(1.001^{1892} -1.001^{-1})*{\frac{1.001}{0.001}}\)

\(S_{1893} =\frac{(1.001^{1892} -1.001^{-1}) * 1.001}{0.001}\)

Open Bracket

\(S_{1893} =\frac{1.001^{1892}* 1.001 -1.001^{-1}* 1.001 }{0.001}\)

\(S_{1893} =\frac{1.001^{1892+1} -1.001^{-1+1}}{0.001}\)

\(S_{1893} =\frac{1.001^{1893} -1.001^{0}}{0.001}\)

\(S_{1893} =\frac{1.001^{1893} -1}{0.001}\)

\(S_{1893} =5632.97970294\)

Hence, the sum of the sequence is:

\(S_{1893} =5632.98\) ----- approximated

Answer:

Avicenna can expect to lose money from offering these policies. In the long run, they should expect to lose 57 dollars on each policy sold.

Explanation:

If a person lives to the age of 70, they will earn $765. So, there is a 97% chance to earn $765. On the other hand, if a person dies before age of 70, they will lose $26635 because

$27,400 - $765 = 26,635

Then, there is a 3% chance to lose $26635.

Now, we can find the expected value, multiplyion each option by its probability, so:

E = $765(0.97) - (26635)(0.03)

E = $742.05 - $799.05

E = - $57

Since the sign is negative they can expect to lose money, so the answer is:

Avicenna can expect to lose money from offering these policies. In the long run, they should expect to lose 57 dollars on each policy sold.

The point C is equidistant to (b) CL = CM = CN

From the question, we have the following parameters that can be used in our computation:

The triangle

From the triangle, we can see that the point C is the centroid of the triangle

As a general rule:

The centroid is the geometric centre of a triangle. It is equidistant from all the points present on the triangle.

This means that point C is equidistant from L, M and N

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Observe that

\(\displaystyle \frac1{e^{2\pi x} - 1} = \frac{e^{-\pi x}}{e^{\pi x} - e^{-\pi x}} = \frac{\cosh(\pi x) - \sinh(\pi x)}{2\sinh(\pi x)} = \frac{\coth(\pi x) - 1}2\)

We have the following series expansion due to Mittag-Leffler:

\(\displaystyle \pi \coth(\pi z) = \frac1z + 2 \sum_{n=1}^\infty \frac z{z^2+n^2}\)

The proof of this is easy to follow. (I'll try to include a link)

With some simple rearrangement, we get the desired result.

\(\displaystyle \sum_{n=1}^\infty \frac1{n^2 + x^2} = -\frac1{2x^2} + \frac{\pi \coth(\pi x)}{2x} \\\\ ~~~~~~~~ = -\frac1{2x^2} + \frac\pi{2x} + \frac\pi{x(e^{2\pi x}-1)}\)