How to find the solution for 3x-11=x+3 ?​

Answer:

11i= √-1

Step-by-step explanation:

So first take 1 to the other side so we can leave the numbers with I on one section. So when we take 1 to the other side it becomes negative so 0-1 = -1. Since the 8 is squared to get rid of it were going to put a square root on the whole equation. √8i² + 9i = √-1 and we have to put the square root on the other side of the equation to make it equal. So on the other side we now have 8i + 3i *because the square root of 9 is 3* and then the -1 stays like that so its 11i= √-1 because we combine the 8i and 3i. Happy I could help!!!

To maximize the sugar you can gain from street vendors and satisfy your sweet tooth, you can use the following expression:

m[i] = max(m[i-1] + s[i], s[i])

Here, m[i] represents the maximum sugar you can consume so far on the i-th vendor, and s[i] denotes the sugar content of the i-th vendor's offering.

The expression utilizes dynamic programming to calculate the maximum sugar consumption at each step. The variable m[i] stores the maximum sugar you can have up to the i-th vendor.

The expression considers two options: either including the sugar content of the current vendor (s[i]) or starting a new consumption from the current vendor.

To calculate m[i], we compare the sum of the maximum sugar consumption until the previous vendor (m[i-1]) and the sugar content of the current vendor (s[i]) with just the sugar content of the current vendor (s[i]). Taking the maximum of these two options ensures that m[i] stores the highest sugar consumption achieved so far.

By iterating through all the vendors and applying this expression, you can determine the maximum sugar you can gain from the street vendors and satisfy your sweet tooth.

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Answer:

The answer is 3x + 17w - 18

The points that represents a viable solution to the system of inequalities include the following:

A. (−10, 170)

B. (80, 90)

C. (250, −50)

In order to determine which points are true and viable with respect to a solution of the given system of inequalities, we would have to test the each of the points by substituting their values into the inequalities as follows;

For points (-10, 170), we have:

x + y ≥ 150

-10 + 170 ≥ 150

160 ≥ 150 (Viable).

1.5x + 3.5y ≤ 600

1.5(-10) + 3.5(170) ≤ 600

-15 + 595 ≤ 600

580 ≤ 600 (Viable).

For points (80, 90), we have:

x + y ≥ 150

80 + 90 ≥ 150

170 ≥ 150 (Viable).

1.5x + 3.5y ≤ 600

1.5(80) + 3.5(90) ≤ 600

120 + 315 ≤ 600

435 ≤ 600 (Viable).

For points (250, -50), we have:

x + y ≥ 150

250 - 50 ≥ 150

200 ≥ 150 (Viable).

1.5x + 3.5y ≤ 600

1.5(250) + 3.5(-50) ≤ 600

375 - 175 ≤ 600

200 ≤ 600 (Viable).

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Answer:

a  19  

b 798 dollars

Step-by-step explanation:

a you just plug in a random nuber in

b all you have to do is plug 6 for x

900-17(6)=798

The SQL aggregate function that gives the arithmetic mean for a specific column is `AVG()`.

SQL (Structured Query Language) aggregate functions are functions that operate on a set of values and return a single value as a result. These functions are used in SQL queries to perform calculations on groups of rows in a database table.

There are several common aggregate functions in SQL, including:

1. `COUNT()` - returns the number of rows in a table or the number of non-null values in a specific column.

2. `SUM()` - calculates the sum of values in a specified column.

3. `AVG()` - calculates the average value of values in a specified column.

4. `MAX()` - returns the maximum value in a specified column.

5. `MIN()` - returns the minimum value in a specified column.

Aggregate functions are typically used with the `GROUP BY` clause in SQL queries to group the data based on one or more columns and then apply the aggregate function to each group.

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The SQL aggregate function for calculating the arithmetic mean of a specific column is AVG.

The SQL aggregate function that gives the arithmetic mean for a specific column is AVG.

For example, if you have a table called 'students' with a column called 'grades', you can use the AVG function in SQL to calculate the average grade:

SELECT AVG(grades) FROM students;

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The point of maxima of any function can be known by equating its derivative to zero. The rocket will take 1.5 sec to reach the maximum height and the maximum height is 27 feet.

The differentiation of a function is defined as rate of change of its value at a point. It can be written as g'(x) = (g(x + h) - g(x)) /(x + h - x).

Its geometric aspect is the slope of the function at a given point.

Given that,

Initial height of the launching pad is 4 feet,

Initial velocity of rocket is 48 feet/sec,

Height of the rocket as a function of time, h(t) = -16t² + 48t + 3

In order to find the time for maximum height equate h'(t) = 0 as follows,

-32t + 48 = 0

⇒ t = 48 / 32

⇒ t = 3 / 2

⇒ t = 1.5

To find the maximum height find h(t) for t = 1.5 as follows,

h(1.5) = -16 × 1.5² + 48 × 1.5 + 3

= -36 + 60 + 3

= -36 + 63

= 27

Hence, the time taken by the rocket to reach the maximum height is 1.5 sec and the maximum height reached is 27 feet.

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Answer: 24 ft³

Step-by-step explanation:

To calculate the amount of space that the box will take up in the moving truck, we are simply meant to calculate the volume. This will be:

= Length × Width × Height

= 2 × 4 × 3

= 24 ft³

Therefore, the space that the box will take up in the moving truck is 24 ft.

a) The center of G and determining the distinct conjugacy classes, we can calculate the class equation of the finite group G.

b) We have shown both implications: if a Sylow p-subgroup is normal, then it is unique, and if it is unique, then it is normal.

(a) Deriving the class equation of a finite group G involves partitioning the group into conjugacy classes. Conjugacy classes are sets of elements in the group that are related by conjugation, where two elements a and b are conjugate if there exists an element g in G such that b = gag^(-1).

To derive the class equation, we start by considering the group G and its conjugacy classes. Let [a] denote the conjugacy class containing the element a. The class equation is given by:

|G| = |Z(G)| + ∑ |[a]|

where |G| is the order of the group G, |Z(G)| is the order of the center of G (the set of elements that commute with all other elements in G), and the summation is taken over all distinct conjugacy classes [a].

The center of a group, Z(G), is the set of elements that commute with all other elements in G. It can be written as:

Z(G) = {z in G | gz = zg for all g in G}

The order of Z(G), denoted |Z(G)|, is the number of elements in the center of G.

The conjugacy classes [a] can be determined by finding representatives from each class. A representative of a conjugacy class is an element that cannot be written as a conjugate of any other element in the class. The number of distinct conjugacy classes is equal to the number of distinct representatives.

By finding the center of G and determining the distinct conjugacy classes, we can calculate the class equation of the finite group G.

(b) To prove that a Sylow p-subgroup of a finite group G is normal if and only if it is unique, we need to show two implications: if it is normal, then it is unique, and if it is unique, then it is normal.

If a Sylow p-subgroup is normal, then it is unique:

Assume that P is a normal Sylow p-subgroup of G. Let Q be another Sylow p-subgroup of G. Since P is normal, P is a subgroup of the normalizer of P in G, denoted N_G(P). Since Q is also a Sylow p-subgroup, Q is a subgroup of the normalizer of Q in G, denoted N_G(Q). Since the normalizer is a subgroup of G, we have P ⊆ N_G(P) ⊆ G and Q ⊆ N_G(Q) ⊆ G. Since P and Q are both Sylow p-subgroups, they have the same order, which implies |P| = |Q|. However, since P and Q are subgroups of G with the same order and P is normal, P = N_G(P) = Q. Hence, if a Sylow p-subgroup is normal, it is unique.

If a Sylow p-subgroup is unique, then it is normal:

Assume that P is a unique Sylow p-subgroup of G. Let Q be any Sylow p-subgroup of G. Since P is unique, P = Q. Therefore, P is equal to any Sylow p-subgroup of G, including Q. Hence, P is normal.

Therefore, we have shown both implications: if a Sylow p-subgroup is normal, then it is unique, and if it is unique, then it is normal.

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Answer:y =4x + 8

Step-by-step explanation:

X-0/0-1 = y-8/8-12

Or,-4x = -y +8

So, y-4x = 8

Answer:

EG = 16

Step-by-step explanation:

Given a segment joining the midpoints of 2 sides , then the segment is half the measure of the third side, thus

EG = 2 × BC = 2 × 8 = 16

A statement that compares two expressions that are not equal is called an inequality. An inequality is a mathematical expression that shows that two quantities are not the same, unlike an equation which shows that two quantities are equal. Inequalities use symbols such as "<" (less than), ">" (greater than), "<=" (less than or equal to), ">=" (greater than or equal to) to compare two expressions.

For example, 4 < 7 is an inequality because 4 is less than 7. Inequalities are commonly used in algebra and real-world scenarios to represent situations where there are limits, ranges or restrictions. Solving inequalities involve finding the values of the unknown variable that make the inequality true. There are several methods to solve inequalities, including adding or subtracting the same value to both sides of the inequality, multiplying or dividing by a positive or negative number, and graphing the inequality on a number line.

Understanding inequalities is crucial for various fields such as economics, engineering, physics, and computer science.

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The p-value for the given test is approximately 0.067, rounded to two significant digits. This was calculated by finding the area to the right of z=1.5 under the standard normal distribution.

It is given that Null hypothesis: H0: μ ≤ 0, Alternative hypothesis: H1: μ > 0, Population standard deviation: σ = 1, Test statistic: z = 1.5

To find the p-value, we need to calculate the probability of observing a z-value of 1.5 or greater under the null hypothesis. Since the population follows the standard normal distribution, we can use a standard normal table or a calculator to find this probability.

Using calculator, we can find that the area to the right of z = 1.5 is approximately 0.0668 (rounded to four decimal places).

Since this is a one-tailed test with the alternative hypothesis in the right tail, the p-value is equal to the area in the right tail beyond the observed z-value. Therefore, the p-value for the test is approximately 0.067 (rounded to two significant digits).

So, the p-value for the given test is 0.067 (rounded to two significant digits).

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Answer:

The Median is 75

Step-by-step explanation:

median is the middle number in a set of given numbers

arranging in order will be

30,64,70,80,90,110

the middle numbers are 70 and 80

Median=80+70/2

=150/2

Median=75

Answer:

.05

Step-by-step explanation:

Answer: 1/2

Step-by-step explanation:

6 hours long is a job for which both companies will charge the same amount and the cost will be $410.

a) Let 'x' stand for the number of hours required to complete the task.

350 + 10x = 300 + 15x

350-300=15x-10x

50=5x

x=6

Thus both the companies will charge the same for a task that takes 6hours.

b) The price will be 350+10(6) =  

=350+60

= $410

How to simplify  algebraic expression?

Finding a simplified version of an expression is the act of simplifying it. In order to factor or simplify the phrase, we also need to know how to combine like terms and factor a number in addition to the order of operations.

You gather the variables with the same degree that are like terms, or together. The constant terms should be separated to provide simplification.

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The probability of x being exactly 48 when it is uniformly distributed between 45 and 150 is 1/105

Since x is uniformly distributed between 45 and 150, the probability of x taking any particular value in this range is the same. Let this probability be denoted by P(x).

To find P(x = 48), we need to first check if 48 lies within the range of values that x can take. In this case, 48 lies within the range of 45 and 150, so it is a possible value for x.

Since the distribution is uniform, the probability of x taking any particular value between 45 and 150 is given by

P(x) = 1 / (150 - 45) = 1 / 105

Therefore, the probability of x being exactly 48 is

P(x = 48) = 1 / 105

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The given question is incomplete, the complete question is:

A random variable x is uniformly distributed between 45 and 150. what is the probability of x = 48?

1. $0.5 is 1/2 of a dollar

2. The fraction of her times at a bat that she get a hit is 1/4

Decimals are the numbers, which consist of two parts namely, a whole number part and a fractional part separated by a decimal point.

For example, 0.4 is 0 + 4/10 = 4/10,/. This means the conversion of 0.4 to fraction is 4/10.

1. The fraction of $0.5 to $1 is calculated as;

representing the fraction by x

x of 1 = 0.5

0.5 = 5/10

therefore

x= 5/10 = 1/2

Therefore the fraction of $1 that gives $0.5 is 1/2

2. converting 0.250 to fraction

= 0 + 250/1000

= 250/1000

= 25/100 = 5/20 = 1/4

therefore the fraction of Sue's hit is 1/4.

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The definite integral that represents the area of the region enclosed by the polar curve r = 1 sin θ is ∫[a, b] 1/2 r^2 dθ

To determine the definite integral that represents the area of the region, we integrate the expression 1/2 r^2 with respect to θ over the interval [a, b], where a and b are the limits of the region.

In this case, the polar curve r = 1 sin θ represents a circle with radius 1 centered at the origin. As θ varies from 0 to π, the curve traces half of the circle in the positive direction. To find the area of the region enclosed by this curve, we integrate the expression 1/2 r^2 over this interval.

The expression 1/2 r^2 represents the area of a sector of the circle with radius r and central angle θ. Integrating this expression with respect to θ gives us the total area enclosed by the curve.

By evaluating the definite integral over the interval [a, b], we can find the area of the region enclosed by the polar curve r = 1 sin θ.

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Answer:

b and d

Step-by-step explanation:

the image depicts a vertical line. because the line is going straight upward, the x-coordinate (horizontal axis) is not changing. this means both x-coordinates in the points given must be the same.

Step-by-step explanation:

Use the slope-intercept form to find the slope and y-intercept.

Slope:

−

1

3

y-intercept:

(0 , 3)

Any line can be graphed using two points. Select two

x

values, and plug them into the equation to find the corresponding

y

values

Graph the line using the slope and the y-intercept, or the points.

Slope:

−

1

3

y-intercept:

(0 , 3)

Answer:

\((a + 1) ^{2} + 1\)

\(a ^{2} + 2a + 2\)

Answer: 3
________________________________
initial value = starting value when x is 0

as you can see when x is 0 y is 3

so your initial value is 3

________________________________

Hoped this helped.

Answer: 5/6, 3/4, 4/12

Step-by-step explanation:

Convert them all into a common denominator, 12.

5/6=10/12, 3/4=9/12, and 4/12 stays the same. 10>9, and 9>4

The MAD of the hourly wages given would be $ 0.48. The range would be $ 2.00. Q1 would be $8.25. Q3 would then be $9.25. The IQR would be $1.00

Calculate the MAD:

First, find the mean of the data set:

mean = (sum of all values) / (number of values)

mean = (8.25 + 8.50 + 9.25 + 8.00 + 10.00 + 8.75 + 8.25 + 9.50 + 8.50 + 9.00) / 10

mean = 88.00 / 10 = 8.80

Then, find the mean of these absolute deviations:

MAD = (sum of absolute deviations) / (number of values)

MAD = (0.55 + 0.30 + 0.45 + 0.80 + 1.20 + 0.05 + 0.55 + 0.70 + 0.30 + 0.20) / 10

MAD = 4.10 / 10 = 0.41

Calculate the range:

range = maximum value - minimum value

range = 10.00 - 8.00 = 2.00

Find Q1 and Q3:

{8.00, 8.25, 8.25, 8.50, 8.50, 8.75, 9.00, 9.25, 9.50, 10.00}

Q1 is the median of the lower half, and Q3 is the median of the upper half.

Lower half: {8.00, 8.25, 8.25, 8.50, 8.50}

Upper half: {8.75, 9.00, 9.25, 9.50, 10.00}

Q1 = median of lower half = 8.25

Q3 = median of upper half = 9.25

Calculate the IQR:

IQR = Q3 - Q1

IQR = 9.25 - 8.25 = 1.00

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The choice of dedicating all the available resources to the production of only bagels presents the lowest opportunity cost.

Profit, in accounting, is an income distributed to the owner in a profitable market production process. Profit is a measure of profitability which is the owner's major interest in the income-formation process of market production. There are several profit measures in common use.

here, we have,

The expected profit per unit is the only data provided about the production process in the pastry shop. Therefore, those the two figures provided already contain information about the production costs of donuts and bagels, the market prices and the sold quantities, in order to deduce the profit that each product would generate.

In this situation, as the bagels make a higher profit per unit, the best option for the company would be chosing to dedicate all its resources to the production of bagels, because if not, when selling a donut the opportunity cost per unit of product would be 0.25, plus the things that the company will not be able to purchase that would have been possible if they had those extra 0.25 per unit.

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The more powerful the motor is, the greater the ability to do the work (option b).

A more powerful motor has a higher capacity to generate energy and produce output, allowing it to exert more force and perform work more efficiently. With greater power, the motor can overcome resistance or load with ease and accomplish tasks that may be challenging for less powerful motors.

On the other hand, the time interval for doing the work (option a) and the workload (option c) are not directly dependent on the motor's power. These factors are influenced by other variables such as the specific task, operational conditions, and the requirements of the work itself.

While a more powerful motor may complete a task faster due to its efficiency, the duration of the work and the workload are not determined solely by the motor's power.Therefore, option b, "the greater the ability to do the work is," accurately reflects the relationship between motor power and work capability.

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