How many protons does the element Li have

Answer:the plastic bag will attract the cloth

Explanation:

Answer:

c

Explanation:

hope this helps

Answer:

3.840 atm

Explanation:

We use Boyle's law, which relates the pressure (P) and the volume (V) of a gas at a constant temperature. The change from initial P and V (P₁ and V₁) to final P and V (P₂ and V₂) is expressed as:

P₁V₁ = P₂V₂

We have the following data:

P₁= 0.960 atm

V₁= 200.0 mL

V₂ = 50.0 mL

Thus, we introduce the data in the equation and calculate the final pressure P₂:

P₂ = P₁V₁/V₂= (0.960 atm x 200.0 mL)/50.0 mL = 3.840 atm

Therefore, a pressure of 3.840 atm is needed to reduce the volume of the gas from 200.0 mL to 50.0 mL.

Because ethanol dissociates into OCH3-, its weak conjugate basic, and H+ in acetic acid, their ions are free to react, but because the product of the reaction is the same, an equilibrium has been created between both acids, and therefore the reaction has no impact on the solution.

The pH of ethanol is 7.33.As a result, the pH value will barely change after the addition of it.Hence, the solution's pH level is not greatly changed when ethanol is added to water.

Fermentation is a method that can be used to produce ethanol.Plant-based sugar (glucose) is transformed into ethanol as well as carbon dioxide during fermentation.Around 30°C is the usual temperature for this to occur.Plant-based sugar is a renewable resource, unlike ethene.

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Answer:

The equilibrium constant (Keq) for a reaction is a measure of the relative concentrations of the products and reactants at equilibrium. The equation for the equilibrium constant (Keq) is:

Keq = [H2O(g)][CO(g)] / [H2(g)][CO2(g)]

In order to find the Keq, we need to substitute the equilibrium concentrations of the species into the equation.

At equilibrium, there are 0.106 moles of H2, 0.106 moles of CO2, 0.094 moles of water and 0.094 moles of CO.

Keq = [0.094 moles H2O][0.094 moles CO] / [0.106 moles H2][0.106 moles CO2]

By canceling out the moles unit and substituting the number we got the value of Keq as:

Keq = 0.0940.094 / 0.1060.106

Keq = 0.87

Therefore, the Keq for this reaction is 0.87.

It is worth to note that the temperature, pressure and volume don't affect the Keq value but they affect the position of equilibrium.

Answer:

I would say ether the first one or the third one because on those questions you always want to choose the one that gives the most information or sound more believe

Hope this helped

To find the density of each filled balloon, we need to use the ideal gas law equation:

PV = nRT

Where:

P = Pressure (in atm)

V = Volume (in L)

n = Number of moles

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature (in Kelvin)

We can rearrange the equation to solve for the number of moles (n):

n = PV / RT

Given that the mass of each balloon is 10.0 g and we know the molar mass of each gas, we can calculate the number of moles (n) using the formula:

n = mass / molar mass

Finally, we can calculate the density using the equation:

Density = mass / volume

Let's calculate the density for each gas:

1. Helium (He):

Molar mass of helium (He) = 4.00 g/mol

Number of moles (n) = 10.0 g / 4.00 g/mol = 2.50 mol

Density = 10.0 g / 20.0 L = 0.50 g/L = 0.00050 g/mL

2. Neon (Ne):

Molar mass of neon (Ne) = 20.18 g/mol

Number of moles (n) = 10.0 g / 20.18 g/mol = 0.495 mol

Density = 10.0 g / 20.0 L = 0.50 g/L = 0.00050 g/mL

3. Carbon monoxide (CO):

Molar mass of carbon monoxide (CO) = 28.01 g/mol

Number of moles (n) = 10.0 g / 28.01 g/mol = 0.357 mol

Density = 10.0 g / 20.0 L = 0.50 g/L = 0.00050 g/mL

4. Nitrogen monoxide (NO):

Molar mass of nitrogen monoxide (NO) = 30.01 g/mol

Number of moles (n) = 10.0 g / 30.01 g/mol = 0.333 mol

Density = 10.0 g / 20.0 L = 0.50 g/L = 0.00050 g/mL

Now, let's compare the density of air (0.00117 g/mL) with the density of each filled balloon:

- Helium: 0.00050 g/mL

- Neon: 0.00050 g/mL

- Carbon monoxide: 0.00050 g/mL

- Nitrogen monoxide: 0.00050 g/mL

Since the density of each filled balloon is lower than the density of air, all four balloons (helium, neon, carbon monoxide, and nitrogen monoxide) will float in the given air.

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The molarity of the NH3 solution is 0.0576 M.

We can use the following steps to calculate the molarity of the NH3 solution:

Determine the mass of 1 mL of the NH3 solution using the given density:

mass of 1 mL of NH3 solution = density x volume of 1 mL

mass of 1 mL of NH3 solution = 0.982 g/mL x 1 mL = 0.982 g

Determine the number of moles of NH3 in 1 mL of the solution using the molar mass of NH3 (17.03 g/mol):

moles of NH3 in 1 mL of solution = mass of NH3 / molar mass of NH3

moles of NH3 in 1 mL of solution = 0.982 g / 17.03 g/mol = 0.0576 mol

Calculate the molarity of the NH3 solution using the number of moles of NH3 in 1 liter of the solution (1000 mL):

molarity of NH3 solution = moles of NH3 / volume of solution in liters

molarity of NH3 solution = 0.0576 mol / 1 L = 0.0576 M

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a. Consistency is a term that matches the description: The agreement between several measurements of the same quantity.

b. Density matches the description: Ratio between the mass and volume of a substance.

c. Outlier matches the description: In a series of measurements of the same quantity, one that is significantly different from the others.

d. Mean matches the description: Mathematical value reported when a quantity is measured multiple times.e. Immiscible is a term describing two liquids that do not mix together.

Definition: Immiscibility is the property of not being miscible. When two or more liquids are not able to form a homogeneous solution when combined, they are immiscible. The term "miscible" refers to the property of being mixed. Therefore, immiscible liquids cannot be mixed together or dissolved in one another.

Limiting reagent (also known as limiting reactant) is a chemical reaction term that refers to the substance that limits the quantity of product that can be formed in a chemical reaction. It is the substance that is entirely consumed first, preventing the other reactants from reacting further. The amount of product generated is determined by the quantity of the limiting reagent. In a chemical reaction, the quantity of the product produced is determined by the limiting reactant, and the rest of the excess reagents will remain unchanged.

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The concentration of acetate ions ([Ac-]) is equal to the concentration of hydronium ions ([H3O+]). This implies that acetate ion concentration is directly proportional to the hydronium ion concentration.

Additionally, the equation states that the concentration of acetic acid ([HAc]) is equal to the difference between the labeled concentration and the hydronium ion concentration ([H3O+]). This implies that the concentration of acetic acid is inversely proportional to the hydronium ion concentration. Using these relationships, you can perform calculations and data analysis in the experiment.

For example, if you measure the pH of a solution and convert it to the hydronium ion concentration ([H3O+]) using the pH scale, you can substitute this value into the equations to determine the concentrations of acetate ions ([Ac-]) and acetic acid ([HAc]). By analyzing the concentrations of these species, you can gain insights into the behavior of acetic acid and its dissociation in solution.

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Answer:

Crudeoil is a mixture and it comprises of compounds mostly hydri carbons i think

Solubility of lead sulfate in water at 25.0°C is approximately 0.0425 grams per liter.

To calculate the solubility of lead sulfate in grams per liter at 25.0°C with a molar solubility of 1.40×10^−4 M, follow these steps:

1. Determine the molar mass of lead sulfate (PbSO4):
Lead (Pb): 207.2 g/mol
Sulfur (S): 32.07 g/mol
Oxygen (O): 16.00 g/mol (there are 4 oxygen atoms in PbSO4, so multiply 16.00 by 4)

Molar mass of PbSO4 = 207.2 + 32.07 + (4 * 16.00) = 303.27 g/mol

2. Multiply the molar solubility by the molar mass of lead sulfate to find the solubility in grams per liter:

Solubility (g/L) = Molar solubility (M) × Molar mass (g/mol)

Solubility (g/L) = 1.40×10^−4 M × 303.27 g/mol ≈ 0.0425 g/L

Therefore, the solubility of lead sulfate in water at 25.0°C is approximately 0.0425 grams per liter.

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Answer:

a new substance was forming

Explanation:

The balanced chemical equation of the Haber process is:

N2 + 3H2 → 2NH3

To calculate the mass of ammonia produced when 35.0g of nitrogen reacts with 12.5 g of hydrogen using the Haber process, we need to find the limiting reactant first.

Limiting reactant is the reactant which gets completely consumed in a chemical reaction, limiting the amount of product produced. Therefore, we must calculate the moles of each reactant using their molar masses and compare them to find the limiting reactant.

For nitrogen, the molar mass = 28 g/mol

Number of moles of nitrogen = 35.0 g / 28 g/mol = 1.25 mol

For hydrogen, the molar mass = 2 g/mol

Number of moles of hydrogen = 12.5 g / 2 g/mol = 6.25 mol

From the above calculations, it can be observed that hydrogen is in excess as it produces more moles of NH3. Thus, nitrogen is the limiting reactant.

Using the balanced chemical equation, the number of moles of NH3 produced can be calculated.

Number of moles of NH3 = (1.25 mol N2) × (2 mol NH3/1 mol N2) = 2.50 mol NH3Now,

to find the mass of NH3 produced, we can use its molar mass which is 17 g/mol.Mass of NH3 produced = (2.50 mol NH3) × (17 g/mol) = 42.5 g

Therefore, the mass of ammonia produced when 35.0g of nitrogen reacts with 12.5 g of hydrogen using the Haber process is 42.5 g.

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if you want to avoid reactions with these ions, you should use H2SO4.

Out of the given acids, H2SO4 will not react with any of the mentioned ions (Ag+, Pb2+, Cu2+). This is because H2SO4 is a strong acid that dissociates completely in water to form H+ and SO42- ions. The H+ ions are already present in the solution, and the SO42- ions are not reactive towards the mentioned ions. On the other hand, both HCl and HNO3 are strong acids that will react with Ag+, Pb2+, and Cu2+ to form insoluble chlorides and nitrates. Therefore, if you want to avoid reactions with these ions, you should use H2SO4.

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Answer:

for pH 13 it = strong based the ph 2 is= weak acid

Explanation:

The weight of Darragh's coin is lot 0.163 g.

The weight of a coin in circulation is 13.714 g, whereas Daragh's piece is 13.551 g. Simply deduct the volume of Daragh's piece first from mass of the uncirculated coin to determine the mass loss. Daragh's coin will therefore lose the following mass: (13.714 - 13.551) g = 0.163 g. I hope this is helpful.

A remarkable and uncommon sight to see is the golden eagle! However, Alaskan, Iceland, or the western portion of United States offer the best chances of seeing one. They are most frequently found in more isolated locations close to grasslands.

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Answer:

Explanation:

The pH of a solution can be found by using the formula

\(pH = - log [ {H}^{+} ]\)

From the question we have

\(ph = - log(9.3 \times {10}^{ - 11} ) \\ = 10.0315...\)

We have the final answer as

Hope this helps you

Answer:

Exothermic

Explanation:

Combustion reactions are almost always exothermic because it is an oxidation reaction that produces heat and in this case it would be considered to be exothermic but there are few cases in which it would be considered endothermic. Combustion of Nitrogen is endothermic because Δ  is positive despite being a combustion reaction.

Answer: The final volume in the balloon is \(68.818cm^3\)    

Explanation:

Charles' Law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

\(\text{Volume}\propto \text{Temperature}\)

Or,

\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)   (At constant pressure and number of moles)

\(V_1\) = initial volume = 52000 L

\(V_2\) = final volume = ?

\(T_1\) = initial temperature = \(500^0C=(500+273)K=773 K\)

\(T_2\) =  final temperature = \(750^0C=(750+273)K=1023 K\)

\(\frac{52000}{773}=\frac{V_2}{1023}\)

\(V_2=68818L=68.818ml=68.818cm^3\)       \((1L=1000ml=1000cm^3)\)

Thus final volume in the balloon is \(68.818cm^3\)    

The most appropriate reagent for converting cyclopentanol to cyclopentanone is the Jones reagent.

The oxidation of cyclopentanol to cyclopentanone involves the removal of two hydrogen atoms from the alcohol group, resulting in the formation of a carbonyl group.

Jones reagent, a mixture of chromic acid (H₂CrO₄) and sulfuric acid (H₂SO₄). This reagent is commonly used for the oxidation of alcohols to corresponding ketones. It is a strong oxidizing agent, facilitates this oxidation process effectively.

It oxidizes the alcohol group to a ketone, converting the -OH group to a carbonyl group (C=O). The reaction proceeds via the formation of an intermediate aldehyde, which is further oxidized to the desired ketone.

Other reagents like PCC (pyridinium chlorochromate) or Swern reagent (dimethyl sulfoxide (DMSO) and oxalyl chloride (COCl)2) can also be used for the oxidation of cyclopentanol to cyclopentanone, but Jones reagent is often preferred for its efficiency and selectivity.

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Ions are electrically charged molecules that play an important role in the functioning of neurons.

Here, correct answer will be

They are present in the intracellular and extracellular fluid surrounding neurons, and their movements across the cell membrane are responsible for changes in the electrical potential of a neuron. The resting potential of a neuron is the electrical charge of a neuron when it is not actively sending signals, and is maintained by the movement of ions across the cell membrane.

Hyperpolarization occurs when the electrical charge of the neuron is increased, and depolarization when the electrical charge is decreased. The threshold potential is the electrical charge required for the neuron to generate an action potential, which is an electrical impulse or "spike" that is sent down the neuron's axon.

The action potential is generated by the rapid movement of ions across the cell membrane, creating an electrical impulse that is then transmitted to other neurons.

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Yes.  Gay-Lussac's law states that at constant volume, the pressure and temperature of a gas are directly proportional.

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Answer:

N2H4

Explanation:

Impact Environmental drilling and oil extraction can have significant environmental effects on the water, soil, and air.

Water: During drilling and oil extraction, there is a risk of accidental spills or leaks, which can lead to water contamination. Spilled oil and drilling fluids can enter water bodies, polluting them and harming aquatic life. Additionally, the extraction process often requires large amounts of water, leading to water scarcity and ecosystem disruption.

Soil: The construction of drilling sites and infrastructure can result in soil disturbance and erosion. The clearing of land for drilling can lead to habitat destruction and loss of biodiversity. Spilled oil or chemicals can contaminate the soil, making it unsuitable for plant growth and disrupting the soil ecosystem.

Air: Drilling and oil extraction operations can release various pollutants into the air, including volatile organic compounds (VOCs), sulfur dioxide (SO₂), and particulate matter. These pollutants contribute to air pollution, leading to respiratory issues, smog formation, and damage to vegetation. Additionally, the flaring or burning of excess gas during oil extraction releases greenhouse gases, contributing to climate change.

Hence,  the environmental effects of Impact Environmental drilling and oil extraction on the water, soil and air environment are discussed above.

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