How many liters of water can be made from 55 grams of oxygen gas and an excess of
hydrogen at STP?

Answer:

a single compound

Explanation:

which is produced in a synthesis reaction

Answer:

B on edg

Explanation:

The balanced chemical equation is AlI₃(s) + 3 K(s) → 3 KI(s) + Al(s). The number of moles of aluminium will be 2.437moles.

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Answer:

Stay Healthy/ A

Explanation: k12

Answer: stay healthy

Explanation: got it in k12 have a g day

The fuel released 90 calories of heat.

Let suppose that water experiments an entirely sensible heating. Hence, the heat released by the fuel is equal to the heat absorbed by the water because of principle of energy conservation. The heat released by the fuel is expressed by the following formula:

\(Q = m\cdot c \cdot \Delta T\) (1)

Where:

If we know that \(m = 10\,g\), \(c = 1\,\frac{cal}{g\cdot ^{\circ}C}\) and \(\Delta T = 9\,^{\circ}C\), then the heat released by the fuel is:

\(Q = (10\,g)\cdot \left(1\,\frac{cal}{g\cdot ^{\circ}C} \right)\cdot (9\,^{\circ}C)\)

The fuel released 90 calories of heat.

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H₂O and CO₂ are the substances needed to carry out photosynthesis. Chlorophyll molecules absorb sunlight and break down molecules of H₂O, releasing O₂ and hydrogen. Then, hydrogen binds to CO₂ and forms glucose (C₆H₁₂O₆).

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

So this chemical reaction equation represents Photosynthesis.

hallo! heres you answer

^Extrusive igneous rocks are formed from the cooling lava that flows above the crust and Intrusive Igneous rocks are formed within the earth's interior.^

is the correct one because

-Intrusive, or plutonic, igneous rock forms when magma is trapped deep inside the Earth. ... Intrusive rocks have a coarse grained texture.

- Extrusive Igneous Rocks: Extrusive, or volcanic, igneous rock is produced when magma exits and cools above (or very near) the Earth's surface.

Answer:

The three major categories of energy for electricity generation are fossil fuels (coal, natural gas, and petroleum)

Explanation:

:)

Answer:

option A is correct  ( sodium, calcium and barium)

Explanation:

Given compounds:

Sodium chloride , calcium sulfide, barium oxide

We know that metals form positive ions. In order to solve the problem we must identify the metals from given compounds.

Na⁺Cl⁻

Ca²⁺S²⁻

Ba²⁺O²⁻

We can see that sodium, calcium and barium contain positive charges.

Thus option A is correct.

Because sodium have one valance electron. When it combine with chlorine sodium lose its one electron to complete the octet and chlorine accept it to complete its octet. Thus sodium form positive ion and chlorine form negative ion.

Similarly barium and calcium are present in group 2. Both have two valance electron. When they lose them cation are formed.

Other option are incorrect because,

Option B have sulfur and oxygen which are anion.

Option C have chlorine which is also anion

Option D have chlorine, sulfur and oxygen that are anions.

Answer:

option A is correct ( sodium, calcium and barium)

Explanation:

First, we consider 63.52% and 36.48% for 100g of the compound.

So there are 63.52 g of Iron and 36.48 g of Sulfur.

Now it is necessary to pass these values to the amount of matter (mol). We do this by dividing each of the values found by their respective molar masses:

Iron: 63.52/55.845 = 1.14

Sulfur: 36.48/32.065 = 1.14

Now we can divide by 1.14:

Iron: 1.14/1.14 = 1

Sulfur: 1.14/1.14 = 1

Thus, the mpirical formula of this unknown substance is equal to

FeS

Answer: FeS

Answer: A. 212

Explanation:

Answer:

b. 0.22 L

Explanation:

Step 1: Write the balanced equation

4 HNO₃(l) ⇒ 4 NO₂(g) + 2 H₂O(l) + O₂(g)

Step 2: Calculate the moles corresponding to 2.5 g of HNO₃

The molar mass of HNO₃ is 63.01 g/mol.

2.5 g × 1 mol/63.01 g = 0.040 mol

Step 3: Calculate the moles of O₂ produced from 0.040 moles of HNO₃

The molar ratio of HNO₃ to O₂ is 4:1. The moles of O₂ produced are 1/4 × 0.040 mol = 0.010 mol.

Step 4: Calculate the volume corresponding to 0.010 moles of O₂

Assuming the reaction takes place at standard temperature and pressure, the volume of 1 mole of O₂ is 22.4 L.

0.010 mol × 22.4L/1 mol = 0.22 L

The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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Answer:

A sample of 830 kg would contain 830000000 mg

Explanation:

1. The mole ratio of H2SO4 and H2O in the equation = 3:3

2. The mole ratio of Mg and Mn in the equation = 3:2

Given

Reaction

1. Fe2O3 + H2SO4 → Fe2(SO4)3 + H2O

2. Mg + Mn2O3 → MgO + Mn.

Required

Balanced equation

Solution

1. Fe₂O₃ + H₂SO₄ → Fe₂(SO₄)₃ + H₂O

aFe₂O₃ + bH₂SO₄ → Fe₂(SO₄)₃ + cH₂O

Fe, left = 2a, right=2⇒2a=2⇒a=1

S, left=b, right=3⇒b=3

H, left = 2b, right = 2c⇒2b=2c⇒2.3=2c⇒c=3

The equation becomes :

Fe₂O₃ + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂O

2. Mg + Mn₂O₃ → MgO + Mn.

aMg + Mn₂O₃ → bMgO + cMn.

Mn, left=2, right=c⇒c=2

O₂, left=3, right=b⇒b=3

Mg, left = a, right=b⇒a=b⇒a=3

The equation becomes :

3Mg + Mn₂O₃ → 3MgO + 2Mn.

Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.

Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.

Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.

Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.

Errors in measurements can be classified into two types: random errors and systematic errors.

Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.

Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.

In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.

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Answer:

illustrates ways things are similar and different

Explanation:

Answer:

illustrates ways things are similar and different

Answer:

Nonmetallic elements form ions by gaining valence electrons to complete their outer shell.

The more valence electrons an element has in its outer shell, the easier it is to complete.

The fewer electron shells an element has, the easier it is to fill its outermost shell.

Reactivity in nonmetals increases as you go from left to right in a group, and

decreases as you go from top to bottom.

Explanation:

Nonmetallic elements form ions by gaining valence electrons to complete

their outer shell.

The more valence electrons an element has in its outer shell, the easier it is to complete.

The fewer electron shells an element has, the easier it is to fill its outermost shell.

Reactivity in nonmetals increases as you go from left to right in a group, and decreases as you go from top to bottom.

When there are more valence electrons then it makes it easy for the element

to complete its outermost shell as against if it was less as it would be harder

due to a bigger number of electrons needed.

Non metals are elements which accepts valence electrons to complete its

outermost shell and becomes negatively charged when this happens.

When an element has fewer electron shells then filling the outermost shell

will be easier as the electron shells require a lesser number of electrons and

increases as the number of shells increases.

This is because the tendency to accept electrons increases from left to right

and decreases down the group.

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The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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Answer:

Explanation:

(The MW of CuSO4 is 250 g/mol).

Answer:

5 grams of CuSO4

Explanation:

First you make a stoichiometric relationship between the molarity and liters. So there is 2 mols per every liter. Then you put in the moleculur weight( for every mol there is 250 g). Then you have to get rid of the liters, so you times the equation by 0.01(this was found by 10ml converted into liters). After all of that you should end up with 5 grams of CuSo4

The molecule must possess dipolar bonds, exhibit suitable vibrational frequencies, and be in a form that can be analyzed using IR spectroscopy in order to be studied in an IR spectrum.

To study a molecule in an infrared (IR) spectrum, several criteria need to be considered. Firstly, the molecule should have a dipole moment, meaning it must have a separation of positive and negative charges within the molecule.

This is because IR spectroscopy primarily detects vibrations of covalent bonds, which are associated with changes in dipole moment.Additionally, the molecule should have covalent bonds that can undergo vibrational modes within the range of the instrument. IR spectroscopy typically covers the frequency range of 4000 to 400 cm⁻¹, which corresponds to the energies of molecular vibrations.

The molecule should also be able to be vaporized or dissolved in a suitable solvent to generate a homogeneous sample for analysis. Gaseous or liquid samples are commonly used in IR spectroscopy.

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One mole of radiant energy will supply 6.02 x 10^23 photons.

The number of photons is calculated by dividing the overall energy of a pulse by the energy of one photon included inside the pulse.

As a result, an electromagnetic energy particle is known as a photon. Photons have no mass, thus they move at the same rate as light.

we need to first calculate the total energy in one mole of photons,

By combining the energy per photon with Avogadro's number (6.022 x 1023), one may determine the energy of a mole of photons:

Energy per mole of photons = Energy per photon x Avogadro's number

we can calculate the energy per mole of photons:

Energy per mole of photons = 3.37 × 10−19 J x 6.022 x 10^23

Energy per mole of photons = 2.03 x 10^5 J/mol

Number of photons in one mole = Energy per mole of photons / Energy per photon

Number of photons in one mole = 2.03 x 10^5 J/mol / 3.37 × 10−19 J

Number of photons in one mole = 6.02 x 10^23 photons/mol

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Answer:

Constant-volume molar heat capacity of argon is 12.47 J K ⁻¹mol⁻¹

Explanation:

Argon is a monoatomic gas that behaves as an ideal gas at 298K.

Using the first law of thermodinamics you can obtain:

Work, Q, for constant pressure molar heat capacity,CP:

CP = (5/2)R

For constant-volume molar heat capacity,CV:

CV = (3/2)R

That means:

2CP/5 = 2CV/3

3/5 = CV / CP

As CP of Argon is 20.79 J K ⁻¹mol⁻¹, CV will be:

3/5 = CV / CP

3/5 = CV / 20.79 J K ⁻¹mol⁻¹

12.47 J K ⁻¹mol⁻¹ = CV

Heat would be required  : 1,670 J

Given

mass of H₂O=5 g

Required

Heat to melt

Solution

The heat to change the phase can be formulated :

Q = m.Lf (melting/freezing)

Lf=latent heat of fusion

The heat of fusion for water at 0 °C : 334 J/g

Input given values in formula :

\(\tt Q=5\times 334=\boxed{\bold{1,670~J}}\)

Answer:

Two constitutional isomers for the compound C3H8S are shown in the attachment below

Explanation:

Constitutional isomers are isomers that have the same molecular formula but different connectivity. Two constitutional isomers for the compound C3H8S are shown in the attachment below.

As per the concept of structural isomers, the  two constitutional isomers that share the molecular formula C₃H₈S are attached in attachment below.

Structural isomers are defined as the isomers  in which atoms are completely  arranged  in a different order but the molecular formula remains the same.

They are the molecules which have same molecular formula but different  connectivities  of atoms  which depend on the order they are put together. An increase in the number of carbon atoms leads to an increase  in the structural isomers.

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Answer:

Promethium

Pm 61

Discovered by Jacob .A. Marinsky

Answer:

Explanation:

The measure of energy used in electrochemistry is the cell potential (ecell), which is the difference in electrical potential between two electrodes. A common term for this difference in electrical potential is voltage or emf.

The evidence from the article highlights these practices as effective means of improving water quality. By implementing these measures, both individuals and governmental agencies can contribute to the preservation and protection of water resources.

According to the article, there are several practices that members of the public and governmental agencies can adopt to improve water quality:

Implementing proper wastewater management: This involves treating wastewater before it is released back into the environment. The article emphasizes the importance of implementing advanced treatment technologies to remove pollutants effectively.Promoting sustainable agriculture: The article highlights the significance of adopting practices that minimize the use of fertilizers and pesticides, such as precision agriculture techniques. These practices can reduce the runoff of agricultural chemicals into water bodies.Establishing buffer zones: Creating vegetated buffer zones along rivers, lakes, and streams can help filter and absorb pollutants, preventing them from entering the water bodies. The article suggests that buffer zones should be implemented to reduce sediment, nutrient, and pesticide runoff from adjacent fields.Encouraging responsible industrial practices: The article emphasizes the need for industries to adopt eco-friendly practices, including proper disposal of industrial waste and the use of environmentally friendly production techniques.

Raising awareness and education: Public education campaigns can play a crucial role in improving water quality. The article suggests that educating the public about the impact of their actions on water bodies and providing information on sustainable practices can lead to positive changes.

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Answer:

2. Chemical Reaction

Explanation:

I am pretty sure that is the only possible answer, but don't be mad if I am wrong.