Answer:
4.93804*10^24 atoms
Explanation:
Hope this helped!
When balancing redox reactions under acidic conditions, hydrogen is balanced by adding: Select the correct answer below:
a. hydrogen gas
b. water molecules
c. hydrogen atoms
d. hydrogen ions
Answer:
water molecules
Explanation:
Redox reactions are carried out under acidic or basic conditions as the case may be.
If the reaction is carried out in an acid medium, then we must balance the hydrogen ions on the lefthand side of the reaction equation with water molecules on the righthand side of the reaction equation.
For instance, the equation for reduction of MnO4^- under acidic condition is shown below;
MnO4^-(aq) + 5e + 8H^+(aq) --------> Mn^2+(aq) + 4H2O(l)
please help me please help me
What is the calibration of this graduated cylinder? calibration
A. 5 mL
B. 2 mL
C. 1 mL
D. 10 mL
The answer is 1ml. The answer is 1ml because of calibration of this graduated cylinder
Answer:
1 mL
Explanation:
According to your definition, it is the difference between marked spaces divided by the # of spaces between marked values.
Difference between 2 marked values: 5 mL
# Of Spaces between marked values: 5
Calibration: 5 mL / 5 mL = 1 mL
b. How many kJ of heat are needed to completely vaporize 50.0g of water at 100°C? [Ans:113. kJ]
The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.
Heat of vaporization of waterThe heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:
q = m x Hv
where:
q is the heat needed in joules (J)m is the mass of water in grams (g)Hv is the heat of vaporization of water which is approximately 40.65 kJ/mol at standard temperature and pressure.First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:
moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol
Thus:
q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ
In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.
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A person has a standing order for 6 doses of acetaminophen in a 24 hour period for fevers
acetaminophen requires what type of reporting?
ut of
Select one:
a. Routine
estion
b. Emergent
C. Certain Time
d. Urgent
4
A change in the type of seizure the person usually experiences that causes them to stop brea
Acetaminophen is used to treat patients with aches and fever. It is safe to give a dose of 4 grams in 24 hours period.
It is an effective medicine which does not require much time to provide relief to the patient.
Usually tylenol is the best medicine which consists of Acetaminophen in appropriate quantity to provide relief from pain and fever.
The reporting for the doses introduced to the patient must be routine since it is not an emergency case.
The correct answer is a. Routine
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when electric current is applied externally, which of the following produces a redox reaction: A wood. B. electrolytic C. Solid
Answer:
the answer is a
Explanation:
moles of each product that would form as a result of the decomposition of aspirin
The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).
The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:
\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)
From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.
Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.
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Calculate the concentration (in molarity) of an NaH solution if 25.0 mL of the solution is needed to neutralize 19.7 mL of a 0.463 M HCI solution.
Answer:
0.11 m
Explanation:
H Ci + NaOH H2 O+ NaC1
by titration
0.0025 L of 0.13 mol Na OH = 0.00325 Mol NaOH
L
0.00325 Mol NaOH 1 Mol Hcl/I Mol NaOH = 0.00325 Mol hcl
now 0.00325 mol Hcl/ 0.030 L = 0.0108 M hcl
sketch an enthalpy diagram for the combustion of cyclopropane, 36().
36() +9/2 2 () → 32 () + 32 ()
° = −2091.3 /
The attached graphic displays the enthalpy diagram for the combustion of cyclopropane.
Does the reaction produce heat?The enthalpy diagram for a combustion reaction typically displays the change in reaction enthalpy (H) throughout the reaction route.
An enthalpy diagram normally has two sides: the reactant side and the product side. Reactant species like gasoline or hydrocarbons have a higher enthalpy on the reactant side when compared to the products. As the reaction gets nearer to the products, the enthalpy decreases.
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1. 60.0 mL of 0.322 M lithium chloride, LICI (aq) are combined with 20.0 mL of 0.530 M Tin (II) nitrate,
Sn(NO₂)2 (aq), 0.632 g of precipitate are recovered.
a. Write a balanced chemical equation for the reaction.
b. Write a balanced net-ionic equation for the reaction.
c. Calculate the moles of precipitate that are actually produced in the reaction.
d. Calculate the moles of precipitate that should be produced if the reaction went to completion.
e. Calculate the percent yield of the reaction.
Answer:
60.0 mL of 0.322 M potassium iodide are combined with 20.0 mL of 0.530 M lead (II) nitrate.
How many grams of lead (II) iodide will precipitate? (you must write your own reaction)
Explanation:
Iron reacts with chlorine to form iron(III) chloride.
2Fe + 3Cl2 → 2FeCl3
What mass (in grams) of chlorine gas is needed to react with 251 grams of iron?
Select one:
a.
71 grams
b.
392 grams
c.
479 grams
d.
622 grams
The mass (in grams) of chlorine gas is needed to react with 251 grams of iron is 479 grams. Option C.
To determine the mass of chlorine gas needed to react with 251 grams of iron, we need to use the stoichiometry of the balanced chemical equation:
2Fe + 3Cl2 → 2FeCl3
From the balanced equation, we can see that 2 moles of iron (Fe) react with 3 moles of chlorine gas (Cl2) to produce 2 moles of iron(III) chloride (FeCl3).
To calculate the mass of chlorine gas, we can follow these steps:
Step 1: Convert the given mass of iron (Fe) to moles.
Using the molar mass of iron (Fe), which is approximately 55.85 g/mol, we can calculate the number of moles of iron:
moles of Fe = mass of Fe / molar mass of Fe
moles of Fe = 251 g / 55.85 g/mol
moles of Fe ≈ 4.5 mol (rounded to one decimal place)
Step 2: Use the mole ratio from the balanced equation to find the moles of chlorine gas (Cl2) needed.
From the balanced equation, we know that 2 moles of Fe react with 3 moles of Cl2. Therefore, the moles of Cl2 can be calculated as:
moles of Cl2 = (moles of Fe / 2) * 3
moles of Cl2 = (4.5 mol / 2) * 3
moles of Cl2 ≈ 6.75 mol (rounded to two decimal places)
Step 3: Convert the moles of chlorine gas to grams.
Using the molar mass of chlorine gas (Cl2), which is approximately 70.90 g/mol, we can calculate the mass of chlorine gas:
mass of Cl2 = moles of Cl2 * molar mass of Cl2
mass of Cl2 = 6.75 mol * 70.90 g/mol
mass of Cl2 ≈ 479 grams (rounded to the nearest whole number) Option C is correct.
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How can you use a barium chloride solution to help identify a sulfate solution?
answer explanation:
Sulfate ions in solution, SO 4 2 -, are detected using barium chloride solution. The test solution is acidified using a few drops of dilute hydrochloric acid, and then a few drops of barium chloride solution are added. A white precipitate of barium sulfate forms if sulfate ions are present.Answer:
Testing for sulfate ions
Sulfate ions in solution, SO 4 2 -, are detected using barium chloride solution. The test solution is acidified using a few drops of dilute hydrochloric acid, and then a few drops of barium chloride solution are added. A white precipitate of barium sulfate forms if sulfate ions are present.
Explanation:
what is the Thermodynamics of leaching of ilmenite in hydrochloric acid for titania pigment production?
The thermodynamics of leaching of ilmenite in hydrochloric acid for titania pigment production is an industrial production of nano-sized titanium dioxide (TiO2).
What is thermodynamics?Thermodynamics is defined as the change in the energy of system that brings about work in that system.
The leaching of ilmenite which is a titanium-iron oxide mineral with HCl can lead to the production of titanium dioxide (TiO2).
The use of thermodynamics in this process controls the heat and energy of the leaching system leading to a better yield of final products.
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Calculate the mass of boron present in 30 g of borax.
the mass of boron present in 30 g of borax is 1.991×10²⁴
Chemical element boron has the atomic number 5 and the letter B in its symbol. It is an amorphous brown powder and a brittle, black, glossy metalloid in its crystalline form. There may be antioxidant effects of boron. Boron is frequently used to treat vaginal yeast infections and boron insufficiency. Additionally, it is used to treat menstrual cramps, osteoarthritis, osteoporosis, and numerous other ailments, but many of these applications lack strong scientific backing.
Molar mass of B = 10.81g/mol
So, 1 mole of B = 10.81g
and 1 mole = NA= 6.023×10²³
By combining,
10.81g of B = 6.023×10²³ atoms of B thus,
35.76g of B = 6.023×10²³
10.81×35.76
35.76g of B
= 1.991*10²⁴
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Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K
At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
1: Write the balanced chemical equation:
\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)
2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.
Initial:
\(C_O\)(g) = 0.3500 mol
\(Cl_2\)(g) = 0.05500 mol
\(C_OCl_2\)(g) = 0 mol
Change:
\(C_O\)(g) = -x
\(Cl_2\)(g) = -x
\(C_OCl_2\)(g) = +x
Equilibrium:
\(C_O\)(g) = 0.3500 - x mol
\(Cl_2\)(g) = 0.05500 - x mol
\(C_OCl_2\)(g) = x mol
3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:
Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]
4: Substitute the given equilibrium constant (Kc) value into the expression:
1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)
5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:
1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x
6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.
7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.
8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):
\(Cl_2\)(g) = 0.05500 - x
9: Calculate the value of \(Cl_2\)(g) at equilibrium:
\(Cl_2\)(g) = 0.05500 - x
\(Cl_2\)(g) = 0.05500 - (positive value of x)
10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.
Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
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The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is ________ J. The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is ________ J. 0.950 145 113 1450 113000
The kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is 113.30 J. Option D
The kinetic energy of an object can be calculated using the formula: KE = (1/2)mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity or speed of the object.
Given:
Mass (m) = 23.2 g = 0.0232 kg
Speed (v) = 98.7 m/s
Substituting these values into the formula, we can calculate the kinetic energy:
KE = (1/2)(0.0232 kg)(98.7 m/s)^2
KE = (1/2)(0.0232 kg)(9756.09 m^2/s^2)
KE ≈ 113.30 J
Therefore, the kinetic energy of a 23.2-g object moving at a speed of 98.7 m/s is approximately 113.30 J.
It's worth noting that the question is repeated twice, but the answer remains the same. The kinetic energy of the object is determined by its mass and speed, and both calculations yield the same result. Option D
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Diffusion is the movement of water between the cell membrane.
O True
O False
it is true good friend chip chip cherrio
The number 0.000402 expressed in scientific notation is
Answer:
hope its help you
Explanation:
4.02 x 10-4
In a science demonstration, a teacher mixed zinc (Zn) with hydrogen chloride (HCl) in a flask and quickly attached a balloon over the mouth of the flask. Bubbles formed in the solution and the balloon inflated.
What most likely occurred during this demonstration?
a.The Zn and HCl both retained their identity.
b.Either Zn or HCl, but not both, retained its identity.
c.Evaporation of one of the substances occurred.
d.One or more new substances formed.
Answer:
a. The Zn and HCl both retained their identity.
How are the atmospheres on Jupiter and Saturn different than those on Uranus and Neptune?
Answer:
The atmospheres of Jupiter and Saturn are made almost entirely of hydrogen and helium, although there is some evidence they contain hydrogen compounds. The there is Uranus and Neptune that are made primarily of hydrogen compounds, with smaller traces of hydrogen, helium, metal and rock.
Explanation:
Hope this helps.
Calculate the specific heat (J/g∘C) for a 13.5-g sample of zinc heated from 24.2 ∘C to 83.6 ∘C that absorbs 312 J of heat.
Answer:
312j/13.5g×24.2°C+83.6°C
The specific heat capacity of a 13.5-g sample of zinc heated from 24.2 ∘C to 83.6 ∘C that absorbs 312 J of heat is 0.389 J/g°C.
HOW TO CALCULATE SPECIFIC HEAT CAPACITYThe specific heat capacity of a substance can be calculated by using the following expression:
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureAccording to this question, a 13.5-g sample of zinc heated from 24.2∘C to 83.6 ∘C absorbs 312 J of heat. The specific heat is as follows:
312 = 13.5 × c × (83.6 - 24.2)
312 = 801.9c
c = 312 ÷ 801.9
c = 0.389
Therefore, the specific heat capacity of a 13.5-g sample of zinc heated from 24.2 ∘C to 83.6 ∘C that absorbs 312 J of heat is 0.389 J/g°C.
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state the bond angle and the molecular shape of NH3 and H2O.
Answer:
H2O forms a bent structure due to the presence of 2 lone pairs over O Atom. This makes the bond angle 104.5° NH3 forms a pyramidal structure due to presence of 1 lone pair. This makes the bond angle 107°
Elements that accept electrons easily have a
Answer:
Greater electronegativity and these are non metals.
Explanation:
Given the balanced reaction: Zn + 2HCl H2 + ZnCl2 How many grams of zinc are needed to produce 5 grams of H2?
Answer:
\(161.9gZn\)
Explanation:
Hello there!
In this case, according the given balanced chemical reaction:
\(Zn + 2HCl\rightarrow H_2 + ZnCl_2\)
It is possible to evidence the 1:1 mole ratio of hydrogen (molar mass = 2.02 g/mol) to zinc (atomic mass = 65.41 g/mol) which is used to calculate the grams of the latter needed for the production of 5 grams of the former via stoichiometry:
\(5gH_2*\frac{1molH_2}{2.02gH_2}*\frac{1molZn}{1molH_2} *\frac{65.41gZn}{1molZn}\\\\=161.9gZn\)
Best regards!
what type of mixture is a sandstorm
Answer:homogeneous mixture
A sandstorm is a homogeneous mixture.
Explanation:
Answer:
homogeneous mixture
Explanation:
Which subatomic particle cannot change in an atom?
Proton, Neutron, Electron
Answer: Protons cannot change in an atom because that would change the identity of a particle. Electrons on the other hand can be added or removed creating an ion. Neutrons can also be added or removed to create an isotope.
With enough ____________,
_______________, and
__________, the original
sedimentary or igneous rock is
changed to ______________ rock.
Answer: with enough heat, pressure, and time, the original sedimentary or igneous rock is changed to metamorphic rock.
Explanation:
Which treatment(s) will help remove contaminants from minerals or from the pipes carrying water from a source? you can select more than one (Water Contamination Gizmos) **ONLY ANSWER IF YOU ACTUALLY KNOW ❗️❗️**
answer choices:
Sedimentation
Disinfection
Filtration
Coagulation
Sedimentation, filtration, and coagulation are the treatments that will help remove contaminants from minerals or from the pipes carrying water from a source.
Sedimentation is a process in which suspended particles settle out of water. It is one of the most basic techniques for removing particles from water. As particles settle, they become trapped in the bottom of a container or settle to the ground in an outdoor setting
Filtration is a method of removing particles from a fluid. It is a physical or chemical separation method that separates solids from fluids (liquids or gases) by adding a medium through which only the fluid can pass.
Coagulation is the process of using chemicals to remove contaminants from water. By creating a chemical reaction, coagulation destabilizes particles and causes them to clump together. This helps to remove the contaminants from the water.
Disinfection is the process of eliminating or destroying pathogens that cause infection. Disinfection eliminates harmful microorganisms by destroying or inactivating them. The disinfectant is a chemical or physical agent that is used to destroy or inactivate harmful microorganisms.
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Who developed a climate classification system in 1918?
What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?
we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.
To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.
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