How does a chronometer determine longitude?

The maximum angle theta at which the ramps should be built is approximately 3.92 degrees to ensure that the force directed up the ramp does not exceed 20N.

To determine the maximum angle theta at which the ramps should be built in the supermarket design, we need to consider the force required to push a 30-kg grocery cart up the ramp.

According to the survey conducted by the engineer, customers do not complain if the force directed up the ramp is no more than 20N.

To find the force required to push the cart up the ramp, we can use the formula:

Force = mass x gravitational acceleration x sin(Θ)

where mass is 30 kg and gravitational acceleration is approximately 9.8 m/s².

Rearranging the formula, we have:

sin(Θ) = Force / (mass x gravitational acceleration)

Plugging in the given values, we have:

sin(Θ) = 20 N / (30 kg x 9.8 m/s²)

sin(Θ) = 0.068

To find the maximum angle Θ, we need to find the inverse sine (also known as arcsine) of 0.068.

Using a calculator, we find:

Θ = arcsin(0.068)

Θ ≈ 3.92 degrees

Therefore, the maximum angle theta at which the ramps should be built is approximately 3.92 degrees to ensure that the force directed up the ramp does not exceed 20N.

In conclusion, to make it easier for customers to push grocery carts up the ramps in the supermarket, the ramps should be built with a maximum angle theta of approximately 3.92 degrees.

This angle ensures that the force required to push the carts up the ramps does not exceed 20N, based on the survey conducted by the engineer.

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Senior citizens should perform balance exercises because it reduces the chances of falls, hence option B is correct.

The ability to maintain balance, however, deteriorates with age, and poor balance is a key contributor to falls in older persons.

A fall can cause serious injuries, including fractures, which can lead to chronic pain, reduced quality of life, disability, or even death.

Seniors' mobility will significantly improve if their exercise regimen is increased.

Therefore, being solid and steady can improve your general confidence, ease various health concerns, and lessen your danger of falling.

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The hypothetical planet discovered orbiting the star has an orbital period of 4.44 Earth years.

When a hypothetical planet is discovered orbiting a star, its orbital distance is measured to be 300 million kilometers. The orbital period of the planet is determined by its distance from the star and the mass of the star.

The time taken by an object to complete a single orbit around another object is known as the orbital period. It is calculated based on the distance between the two objects and the mass of the central object. The formula for calculating the orbital period of a planet is:

Orbital period = 2π √(r³/GM)

Where r is the distance between the planet and the star, G is the gravitational constant, and M is the mass of the star.π is the mathematical constant pi whose value is 3.14.So, in the case of the hypothetical planet, the orbital period can be calculated as:

Orbital period\(= 2π √(r³/GM) = 2 x 3.14 √[(300,000,000)^3/ (6.67 x 10^-11 x M)]\)

Where the value of the gravitational constant is\(6.67 x 10^-11 Nm^2/kg^2\).

Assuming the mass of the star is one solar mass or \(1.989 x 10^30\)kg,

the orbital period can be calculated as:

Orbital period = \(2 x 3.14 √[(300,000,000)^3/ (6.67 x 10^-11 x 1.989 x 10^30)] = 4.44\) Earth years

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Answer: Different types of fuels have varying compositions and release different amounts of pollutants when burned. Here are some common types of fuels and the pollutants associated with them:

Fossil Fuels:

a. Coal: When burned, coal releases pollutants such as carbon dioxide (CO2), sulfur dioxide (SO2), nitrogen oxides (NOx), and particulate matter (PM).

b. Petroleum (Oil): Burning petroleum-based fuels like gasoline and diesel produces CO2, SO2, NOx, volatile organic compounds (VOCs), and PM.

Natural Gas:

Natural gas, which primarily consists of methane (CH4), is considered a cleaner-burning fuel compared to coal and oil. It releases lower amounts of CO2, SO2, NOx, VOCs, and PM.

Biofuels:

Biofuels are derived from renewable sources such as plants and agricultural waste. Their environmental impact depends on the specific type of biofuel. For example:

a. Ethanol: Produced from crops like corn or sugarcane, burning ethanol emits CO2 but generally releases fewer pollutants than fossil fuels.

b. Biodiesel: Made from vegetable oils or animal fats, biodiesel produces lower levels of CO2, SO2, and PM compared to petroleum-based diesel.

Renewable Energy Sources:

Renewable energy sources like solar, wind, and hydropower do not produce pollutants during electricity generation. However, the manufacturing, installation, and maintenance of renewable energy infrastructure can have environmental impacts.

It's important to note that the environmental impact of a fuel also depends on factors such as combustion technology, fuel efficiency, and emission control measures. Additionally, advancements in clean technologies and the use of emission controls can help mitigate the environmental impact of burning fuels.

Answer:

576.975 cubic feet of helium will be needed to fully inflate the balloon

Explanation:

To determine how many cubic feet of helium will be needed to fully inflate the balloon, we will determine the volume of the balloon.

From the question,

The balloon is shaped like a giant soda can.

A giant soda can is cylindrical.

Hence, we can determine the volume of the balloon shaped like a giant soda can by using the formula for finding the volume of a cylinder.

The formula for finding the volume of a cylinder is

V = πr²h

Where V is the volume of the cylinder

π is a constant (Take π = 3.14)

r is the radius of the cylinder

and h is the height of the cylinder

From the question, the balloon is 15 feet tall and 7 feet wide

Hence,

Height, h = 15 feet

Width = 7 feet

(NOTE: The width of a cylinder is the same as the diameter)

Then, diameter = 7 feet

Radius, r is given by

Radius = Diameter / 2

Then, Radius = 7 feet / 2 = 3.5 feet

∴ Radius, r = 3.5 feet

Now, for the volume of the balloon,

V = πr²h

V = 3.14 × (3.5)² × 15

V = 3.14 × 12.25 × 15

V = 576.975 cubic feet

This is the volume of the balloon.

Hence, 576.975 cubic feet of helium will be needed to fully inflate the balloon.

It will take 3.0 s

Step by step explanation:-

We want to find the time it will take the object to reach the land.

To do this, we apply one of Newtons equations of motion:

\(s = ut + \frac{1}{2}gt^{2} \)

where s= distance/height

u = initial velocity

g = acceleration due to gravity

t = time

From the given question, we have :

\(s = 180m \\ u = 45m/s \\ g = 9.8m/{s}^{2}\)

Now substitute the given values into the equation and solve for t :

\(180 = 45t + ( \frac{1}{2} \times 9.8 \times {t}^{2})\)

\( = > 180 = 45t + 4.9 {t}^{2} \)

\( = > 4.9 {t}^{2} + 45t - 180 = 0\)

Solving the above quadratic equation, using quadratic formula :

\( = > t≈3.0s;t = - 12.2s\)

Since time cannot be negative,

\(t = 3.0s\)

So, it will take 3.0 s to reach the land.

Answer:

330 Hz

Explanation:

edg2020

The best estimate of the frequency Suzy hears after the car passes her is govern by doppler effect and it is 330 Hz.

Frequency is the number of occurrences of a repeating event per unit of time.

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source.

According to the Doppler Effect, the frequency observed by an observer decreases for source going away.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The derivative is  \(v(r)' =  \sqrt{\frac{D}{r} }\)

The correct option is option 1

Explanation:

From  the question we are told that

   The equation of the speed of the wave of invasion is  \(v(r)  = 2 \sqrt{Dr}\)

=>  \(v(r)  = 2 (Dr)^{\frac{1}{2} }\)

=>  \(v(r)  = 2 * D^{\frac{1}{2} } r^{\frac{1}{2} }\)

    Here r is the reproductive rate and the D is the parameter qualifying dispersal

Generally the derivative of this speed is mathematically represented as

         \(v(r)' = \frac{2}{2}  *  D^{\frac{1}{2} } *  r^{-\frac{1}{2} }\)

=>     \(v(r)' =  \sqrt{\frac{D}{r} }\)  

This derivative of the speed represents the rate of change of the invasive speed with respect to the the reproductive rate of an individual

Answer:sdfasdf

Explanation:

safsdfasdfsfda

The velocity of the golf ball is 65.2 m/s

The principle of conservation of momentum is that the momentum before collision is equal to the momentum after collision.

Given that;

(0.2kg *  55 m/s) + (0.046kg * 0 m/s) = (0.2kg * 40 m/s) + (0.046kg  * v)

11 = 8 + 0.046v

v = 11 - 8/0.046

v = 65.2 m/s

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Answer:

18

Explanation:

12 - 5 + 8 = 15

12 - 8 = 4

7 - 4 = 3

15 + 3 = 18

The visual presentation of the data helps us to understand the information better, because: it provides clearer data which easier for us to identify patterns, trends, and outliers, especially in super large data.

In presenting data from experiments, it is strongly recommended to use visual presentation, such as graphics, diagrams, pictures, etc. The advantages of using visual presentations are as follows:

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The weight of the transformer is 138.46 N.

Weight can be calculated by dividing workdone by height

To calculate the weight of the transformer, we use the formula below.

Formula:

Where:

Substitute these values into equation 1

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The power rating of the engine is 150000 W.

Power can be defined as the rate at which energy is used or consumed by a body.

To calculate the power of the engine, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The power rating of the engine is 150000 W.

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Explanation:

uniform speed is just the consistent ratio of distance to time. it can a

so be thought as the speed of an object that does not change. an example is when a car moves at a speed of 60km/hrs without changing its speed. it keeps on moving at the same speed it started with

hope this becomes helpful

thanks

Answer:

Blankets

Explanation:

Answer:

the correct answers is blankets

Explanation:

Please give brainle

The distance between point O and point A is √19. The distance between point O and point S is √61. The distance between the ant and the spider is √34.

1. To find the distance between point O and point A, we can use the distance formula in three-dimensional space. The distance formula is:

d = √((x2 - x1)² + (y2 - y1)² + (z2 - z1)² )

Substituting the coordinates of point O (1, 0, 2) and point A (2, 3, 5) into the formula, we have:

d = √((2 - 1)²  + (3 - 0)²  + (5 - 2)² )
 = √(1²  + 3²  + 3² )
 = √(1 + 9 + 9)
 = √19

Therefore, the distance between point O and point A is √19.

To find the distance between point O and point S, we can follow the same steps. Substituting the coordinates of point O (1, 0, 2) and point S (6, 0, 8) into the distance formula, we have:

d = √((6 - 1)²  + (0 - 0)²  + (8 - 2)² )
 = √(5²  + 0 + 6² )
 = √(25 + 0 + 36)
 = √61

Therefore, the distance between point O and point S is √61.

2. To find the distance between the ant and the spider, we can use the distance formula once again. Substituting the coordinates of point A (2, 3, 5) and point S (6, 0, 8) into the formula, we have:

d = √((6 - 2)²  + (0 - 3)²  + (8 - 5)² )
 = √(4²  + (-3)²  + 3² )
 = √(16 + 9 + 9)
 = √34

Therefore, the distance between the ant and the spider is √34.

In conclusion,
1. The distance between point O and point A is √19.
2. The distance between point O and point S is √61.
3. The distance between the ant and the spider is √34.

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Answer:

450 kgm/s upward

Explanation:

From the question,

Change in monentum = mass× change in velocity

ΔM = mΔv....................... Equation 1

ΔM = m(v-u).................. Equation 2

Where ΔM = Change in momentum, m = mass of the gymnast, v = final velocity, u = initial velocity

Given: m = 50 kg, v = -4 m/s. u = 5 m/s

Substitute these values into equation 2

ΔM = 50(-4-5)

ΔM = 50(-9)

ΔM = -450 kgm/s

Hence the change in momentum of the gymnast is 450 kgm/s upward

Hi there!

\(\large\boxed{545N}\)

Since the object is being pulled at a constant velocity, the forces must be balanced.

Since there is no movement vertically, we must take into account the horizontal forces. We can also assume a positive acceleration to be in the direction of motion.

The acceleration and force due to gravity on an incline is:

a = gsinФ

F = MgsinФ

∑F = -MgsinФ + T

Since it is getting pulled at a constant velocity, ∑F = 0. So:

0  = -MgsinФ + T

MgsinФ = T

Solve for T by plugging in values. Let g = 10 m/s²

T = (120)(10)sin(27) ≈ 545 N

Answer:

C

Explanation:

compound is a substance made from two or more different elements that have been chemically joined

The moment of inertia of a small ball on the end of a thin rod rotating in a horizontal circle of radius 1.2 m is 0.504 kg m². To keep the ball rotating at a constant angular velocity in the presence of air resistance, a torque of 0.024 Nm is needed.

a. The moment of inertia of the ball about the center of the circle is given by I = mr², where m is the mass of the ball and r is the radius of the circle. Substituting the given values, we get I = 0.35 kg x (1.2 m)² = 0.504 kg m².

b. The torque needed to keep the ball rotating at constant angular velocity is given by τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration. Since the ball is rotating at a constant angular velocity, α = 0, and the torque needed is zero.

However, air resistance exerts a force on the ball, which tends to slow it down. To counteract this force, an external torque must be applied in the opposite direction.

The magnitude of this torque is given by τ = Fr, where F is the force of air resistance and r is the radius of the circle. Substituting the given values, we get τ = 0.020 N x 1.2 m = 0.024 Nm.

In summary, the moment of inertia of a small ball on the end of a thin rod rotating in a horizontal circle of radius 1.2 m is 0.504 kg m². To keep the ball rotating at a constant angular velocity in the presence of air resistance, a torque of 0.024 Nm is needed.

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The main factor that affects the amount and duration of geological activity on a terrestrial planet is its internal heat. This heat is generated through various processes such as radioactive decay and residual heat from planetary formation.

The presence of a molten core and active mantle circulation contributes to geological activity, including tectonic plate movements, volcanic eruptions, and mountain building. Other factors like the planet's size, composition, and distance from the Sun can also influence geological activity to some extent.

The main factors that affect atmospheric conditions on a terrestrial planet are its distance from the Sun, the composition of its atmosphere, and the presence of greenhouse gases. The proximity to the Sun determines the amount of solar energy received, which affects temperature and weather patterns. The composition of the atmosphere, including the presence of gases like oxygen, nitrogen, carbon dioxide, and water vapor, determines the planet's climate and the ability to support life. Greenhouse gases trap heat in the atmosphere, contributing to the greenhouse effect and influencing temperature regulation.

Based on what we know about the factors that affect geologic activity and atmospheres on terrestrial planets, we can expect that typical Jovian moons, being small rocky-metal bodies, would have limited geological activity and thin atmospheres, if any. The smaller size of these moons compared to terrestrial planets means that they have a lower heat-producing capability and less internal energy. Additionally, their lower gravitational forces make it challenging to retain substantial atmospheres. While some Jovian moons may have evidence of geological activity, such as cryovolcanism or tidal heating, they generally exhibit less dynamic geologic and atmospheric conditions compared to larger terrestrial planets.

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Answer:

10.4 m/s²

Explanation:

use the formula:  V² = Vo² - 2aΔx

Plug in the known values then solve for a.  Vo = 0 because the car starts from rest.

(25 m/s)² = 0 + 2a(30m)

a = (625 m²/s²)/(2)(30m) = 10.4 m/s²

The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:

F = ΔP / ΔT

where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.

Now, let's apply the given values to the above equation.

Final momentum (p2) = mass × final velocity (v2)

p2 = 0.15 kg × (-50 m/s)

p2 = -7.5 kg.m/s

Initial momentum (p1) = mass × initial velocity (v1)

p1 = 0.15 kg × (40 m/s)

p1 = 6 kg.m/s

Change in momentum (ΔP) = p2 - p1

ΔP = -7.5 kg.m/s - 6 kg.m/s

ΔP = -13.5 kg.m/s

Time of collision (ΔT) = 8.0 × 10³ s

Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:

F = ΔP / ΔT

F = -13.5 kg.m/s ÷ 8.0 × 10³ s

F = -1.7 × 10⁻³ N

Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

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Answer:

A - energy is absorbed in the reaction

Explanation:

Answer:

The mass of the air in a room can be calculated by multiplying the volume of the room by the density of the air. The volume of the room can be calculated by multiplying its length, width, and height. So, if the room has dimensions of 1m x 2m x 3m, its volume would be 1m x 2m x 3m = 6 cubic meters. If the density of the air in the room is 1.3kg/m³, the mass of the air in the room would be 6m³ x 1.3kg/m³ = 7.8kg.

The One strategy implemented to address the drug epidemic in Philadelphia is the creation of Comprehensive User Engagement Sites (CUES). These sites aim to tackle the widespread issue of drug addiction and related energy health concerns.

The CUES are safe spaces where individuals battling addiction can energy access various harm reduction services, such as clean syringes, medical support, and overdose prevention. These sites provide connections to addiction treatment programs and mental health services, helping people on their path to recovery. By offering safe and supervised spaces, CUES work to reduce public drug use, discarded syringes, and other related issues in the community. CUES also serve as educational hubs, raising awareness and providing information about the dangers of drug addiction and available resources for support. Lastly, these sites foster community engagement and collaboration, uniting various stakeholders in the fight against the drug epidemic. In summary, Comprehensive User Engagement Sites play a significant role in addressing the drug epidemic in Philadelphia. They provide harm reduction services, treatment programs, and community support, all while promoting a safer and healthier environment for the city's residents.

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