How do scientists use the evidence they gather?
A. The evidence supports scientists' personal opinions about
politics.
B. The evidence proves that scientists are always right.
C. The evidence helps scientists come up with explanations about
the natural world.
D. The evidence helps scientists write new laws for people to follow.

Answer:

The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.

Explanation:

Electric potential energy between two point charges is derived from concept of Work, Work-Energy Theorem and Coulomb's Law and described by the following formula:

\(U_{e} = \frac{k\cdot q_{A}\cdot q_{B}}{r}\) (1)

Where:

\(U_{e}\) - Electric potential energy, measured in joules.

\(q_{A}\), \(q_{B}\) - Electric charges, measured in coulombs.

\(r\) - Distance between charges, measured in meters.

\(k\) - Coulomb's constant, measured in kilogram-cubic meters per square second-square coulomb.

If we know that \(U_{e} = -24\,J\), \(q_{A} = 45\times 10^{-6}\,C+ q_{B}\), \(k = 9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}}\) and \(r = 0.29\,m\), then the electric charge is:

\(-24\,J = -\frac{\left(9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}} \right)\cdot (45\times 10^{-6}\,C+q_{B})\cdot q_{B}}{0.29\,m}\)

\(-6.96 = -405000\cdot q_{B}-9\times 10^{9}\cdot q_{B}^{2}\)

\(9\times 10^{9}\cdot q_{B}^{2}+405000\cdot q_{B} -6.96 = 0\) (2)

Roots of the polynomial are found by Quadratic Formula:

\(q_{B,1} = 1.327\times 10^{-5}\,C\), \(q_{B,2} \approx -5.827\times 10^{-5}\,C\)

Only the first roots offer a solution that is physically reasonable. The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.

Answer:

A) Golgi apparatus

Explanation:

B) v a c u o l e (C) m i t o c h o n d r i a ( E) cell wall

The speed of the artillery shell when it hits its target is approximately 118.0 m/s.

The problem is asking for the velocity of the artillery shell when it hits the target. Since it has already been given that the speed of the shell at a height of 100 m is 100 m/s, we can make use of the conservation of energy to find the final velocity.

The total energy of the artillery shell at a height of 100 m above the ground can be given as:

K + U = E(1)where K is the kinetic energy, U is the potential energy, and E is the total energy of the artillery shell.

The kinetic energy of the artillery shell at a height of 100 m is given as:

K = (1/2)mv²

where m is the mass of the artillery shell and v is its velocity at a height of 100 m above the ground.

The potential energy of the artillery shell at a height of 100 m is given as:

U = mgh

where m is the mass of the artillery shell, g is the acceleration due to gravity (taken to be 9.81 m/s²), and h is the height of the artillery shell above the ground (in this case, h = 100 m).

Substituting the values of K and U into Equation (1), we have:

(1/2)mv² + mgh = E

where E is the total energy of the artillery shell.

The total energy of the artillery shell when it hits the target can be given as:

E = K' + U'

where K' is the kinetic energy of the artillery shell just before it hits the target, and U' is its potential energy just before it hits the target.

Since the problem states that there is no air friction, the total energy of the artillery shell is conserved (i.e., E = K + U = K' + U').

Therefore:

(1/2)mv² + mgh = K' + U'(1/2)mv² + mgh = (1/2)mv'² + mgh'(where v' is the velocity of the artillery shell just before it hits the target, and h' is its height just before it hits the target).

Solving for v', we have:

v' = sqrt(v² + 2gh)

Substituting the given values, we get:

v' = sqrt((100 m/s)² + 2(9.81 m/s²)(200 m)) = sqrt(10000 + 3924.4) m/s = sqrt(13924.4) m/s = 118.0 m/s

Therefore, the speed of the artillery shell when it hits its target is approximately 118.0 m/s.

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The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.

The stiffer the spring is and the harder it is to stretch, the larger the spring constant.

Springs are pliable mechanical devices that regain their previous shape after deforming, i.e. after being stretched or compressed. They are an essential part of many different mechanical devices.

The well-known metal coil has evolved into an essential element in the modern world, appearing in everything from engines to appliances to tools to automobiles to medical equipment and even basic ball-point pens. The spring's ability to store mechanical energy accounts for its widespread use and applications.

Therefore, The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.

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Answer: The daughter is named Susie.

Explanation: LIL SUSIE!!!

                      HUH? DIDN'T UNDERSTAND THE QUESTION!

                                        HAVE A GREAT DAY!!!!!

Answer:6/3 Li

Explanation:

I’m not sure what the person under me is talking about but yeah

Answer:

True

Explanation:

Answer:

4s.

Explanation:

Hello,

In this case, considering that the instantaneous acceleration is computed via the change in the velocity divided by the change in the time, at 4 s we can evidence that the instantaneous acceleration is -2m/s² since the initial velocity at t=0s is 8m/s and at t=4s the velocity is 0 m/s, meaning that such decrease accounts for a deceleration process which is represented by a negative acceleration, and the value is:

\(a=\frac{0m/s-8m/s}{4s-0s}\\ \\a=-2m/s^2\)

Best regards.

Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

Answer:

Mechanical Waves

Why I Know:

Science Class

A type of wave that needs a medium to travel is sound wave because it travels through oscillating molecules.

A sound wave can be defined as a form of mechanical wave that requires a medium for its propagation and it creates a disturbance in the medium. Also, the energy of a sound wave travels in a perpendicular direction.

This ultimately implies that, a sound wave needs a medium to travel and it creates a disturbance when it travels through any medium.

In conclusion, a type of wave that needs a medium to travel is sound wave because it travels through oscillating molecules.

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Hi there!

A)
Since the ball's velocity is initially only in the HORIZONTAL direction, there is NO vertical component of its velocity. Therefore, we can treat this like a free-fall scenario. (Dropped from rest).

We can rearrange the following kinematic equation to make solving for the time taken for the balls to hit the ground easier.

\(d_y = v_yt + \frac{1}{2}at^2\)

dy = vertical displacement (height of table, 0.85 m)

vy = initial vertical velocity (0 m/s, only horizontal)
a = acceleration (due to gravity in this situation, 9.8 m/s²)

t = time (? sec)
Simplify and rearrange the variables for 't'.

\(d_y = 0(t) + \frac{1}{2}at^2\\\\d_y = \frac{1}{2}at^2\\\\t^2 = \frac{2d_y}{a}\\\\t = \sqrt{\frac{2d_y}{a}}}\)

Plug in the given values.

\(t = \sqrt{\frac{2(0.85)}{9.8}} = \boxed{0.4165 s}\)

B)

Now, remember that the ball's acceleration in the vertical direction due to gravity does NOT impact its horizontal velocity. Its vertical and horizontal velocities are COMPLETELY independent. Thus, we can simply use the time solved for above and each ball's respective velocities in the following kinematic equation:
\(d_x = v_xt\)

dₓ= horizontal displacement (? m)

vₓ = horizontal component of velocity (3.5 and 5.3 m/s for A and B respectively)

t = time (0.4165 s)

Solve for the distance traveled by each ball:
Ball A:
\(d_x = 3.5 * 0.4165 = \boxed{1.458 m}\)

Ball B:
\(d_x = 5.3* 0.4165 = \boxed{2.207 m}\)

Answer:

C anterior and posterior

Explanation:

c

Answer:

Explanation:

The horizontal velocity is 1.61.

Answer:

Given that:

Time taken = 5 seconds

Distance = 15 meters

Force = 150 Newtons

Power = ?

Recall that power is the rate of work done per unit time

i.e Power = work / time

(since work is a product of force and distance, then

power = (force x distance)/ time

Power = (150 Newtons x 15 m) / 5 s

Power = 2250 / 5

Power = 450 joules per second

Answer:

450 joules/sec

Explanation:

150 x 15 = 2,250

2,250 / 5 = 450

                = 450 joules/sec

Answer:

m = 50 kg

Explanation:

The mass of the liquid water inside the cylinder can be given by the following formula:

\(\rho = \frac{m}{V}\\\\m = \rho V\)

where,

m = mass of the liquid water inside the cylinder = ?

V = Volume of the liquid water inside the cylinder = 0.05 m³

ρ = Density of the liquid water = 1000 kg/m³

Therefore,

\(m = (1000\ kg/m^3)(0.05\ m^3)\\\)

m = 50 kg

Answer:

Explanation:

Let d be the distance to the center of mass from the front wheels

Sum moments about the front wheel contact point to zero

1240(9.8)[d] - 1240(9.8)(1 - 0.67)[3.2] = 0

1240(9.8)[d] = 1240(9.8)(1 - 0.67)[3.2]

                d = (1 - 0.67)[3.2]

                d = 1.056 m

Removing the H₂0 as it forms would shift the equilibrium to produce the most H₂0 possible. This is due to the reaction producing more water to replace the water that has been removed.

In chemistry, equilibrium refers to a state where the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentrations of the reactants and products. Equilibrium is an important concept in many chemical reactions, including acid-base reactions, redox reactions, and complex formation reactions.

Le Chatelier's principle can be used to predict how changes in conditions such as temperature, pressure, and concentration can affect the position of the equilibrium. For example, increasing the concentration of a reactant will shift the equilibrium towards the products, while decreasing the concentration of a reactant will shift the equilibrium towards the reactants.

In some cases, equilibrium can be used to achieve a desired product concentration. For example, the Haber process is used to produce ammonia by reacting nitrogen and hydrogen gases at high pressure and temperature. By controlling the reaction conditions, the equilibrium can be shifted to produce a high yield of ammonia.

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The depth in the lake of pressure 173.693 lb/in² is 122.45 m.

Depth is the distance down either from the top of something to the bottom, or to a distance below the top surface of something.

To calculate the depth in the lake, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values in to equation 1

Hence, the depth in the lake is 122.45 m.

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Answer:

261.84 N.

Explanation:

From the question given above, the following data were obtained:

Energy (E) = work (W) = 741 J

Distance (d) = 2.83 m

Force (F) =?

Work is simply defined as the product of force and the distance moved in the direction of the the force. Mathematically, it is expressed as:

Work (W) = Force (F) × distance (d)

W = F × d

Thus, we obtained the weight of the object using the above formula.

Work (W) = 741 J

Distance (d) = 2.83 m

Force (F) =?

W = F × d

741 = F × 2.83

Divide both side by 2.83

F = 741 / 2.83

F = 261.84 N

Since force and weight has the same unit of measurement i.e Newton (N), the weight of the object is 261.84 N

Answer:

If a ray of light hits the surface of a sheet of glass, some light will be reflected by the surface of the glass. However, much of the light will pass through the glass, because glass is transparent. ... This 'bending of a ray of light' when it passes from one substance into another substance is called refraction.

Explanation:

Answer:

Explanation:  V = 3 cm/s = 0.03 m/s

                  BY THE FORmULA OF  K.E

                      K.E = 1/2 mV^2

                     300 =1/2 m (0.03)^2

                     m = 300 x 2/0.0009

                       m= 666666.66kg

Answer and Explaination:

To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.

1. Gravitational force:

The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.

2. Force exerted by the spring:

The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

Given:

Mass (m) = 5.0 kg

Compression of the spring (x) = 20.0 cm = 0.20 m

Angle of the inclined plane (θ) = 30°

First, let's find the force exerted by the spring (F_spring):

F_spring = -kx

To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.

Next, let's calculate the gravitational force components:

Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ

Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ

Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.

At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).

Therefore, we have:

F_perpendicular = F_spring

mg * cosθ = -kx

Now, let's substitute the known values and solve for k:

(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m

49.0 N * 0.866 = -k * 0.20 m

42.426 N = -0.20 k

k = -42.426 N / (-0.20 m)

k = 212.13 N/m

Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:

PE_spring = (1/2) * k * x^2

PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2

PE_spring = 4.243 J

The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.

KE_max = PE_spring = 4.243 J

Next, we can calculate the height (h) the mass reaches on the inclined plane:

KE_max = m * g * h

4.243 J = 5.0 kg * 9.8 m/s^2 * h

h = 4.243 J / (5.0 kg * 9.8 m/s^2)

h = 0.086 m

The height the mass reaches on the inclined plane is 0.086 m.

Now, we can calculate the distance traveled.

A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.

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According to the given statement:

I) acceleration a=2m/s²

ii) deceleration a=−1  m/s²

iii) the distance travelled =200  m.

Velocity's rate of change with time, in both terms of speed and direction. A point or object moving straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on the a circle increases because the orientation is always shifting.

Briefing:

You use the standard formulas for distance as a function of speed, acceleration and time:

st = v0t + 0.10at²  for acceleration ( a >0) and deceleration ( a <0), or at constant speed ( a =0).

Now  a  is not given for acceleration and deceleration, so we need to compute this from

vt=v₀+at

Acceleration:  

20=10a⟹a=2m/s²

Distance travelled:  

0.10∗10∗10²=100  m

Distance travelled while at constant speed:

s=vt=20∗20=400  m

Deceleration:  

0=20+20a⟺a=−1  m/s²

Distance travelled:

20∗20+0.1(−1)20²=400−2∗100

=200  m.

So the total distance travelled is  100+400+200=700m

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Answer:

89 m

Explanation:

Applying

v = 2d/t................... Equation 1

Where v = velocity of sound in air, d = distance of the wall from Karen, t = time taken to hear the echo.

make d the subject of equation 1

d = vt/2..................... Equation 2

From the question,

Given: v = 343 m/s, t = 0.519 s

Substitute these values into equation 2

d = (343×0.519)/2

d = 89.01 m.

d ≈ 89 m

Answer:

True

Explanation:

the independent variable would be like if the psychologist is experimenting the impact of sleep deprivation, sleep deprivation would be the independent variable that is being manipulated or changing its level systematically in the experiment.

The amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.

From the graph, the amplitude of the red colored wave is 1 unit.

From the graph, the amplitude of the red colored wave is 2.1 unit.

Thus, the amplitude of the red colored wave is 1 unit and the amplitude of the red colored wave is 2.1 unit.

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The position of the center of mass of the system is 13.0 cm from the left edge of square A.

The center of mass can be calculated by multiplying the masses you're trying to find the center of mass between by their positions. Then you add them all up and divide the total by the sum of the individual masses.

We use the formula for the center of mass of a system of particles,

\(x_c_m = (m_Ax_A + m_Bx_B + m_C*x_C) / (m_A + m_B + m_C)\)

\(m_A\) = mass of square A

\(m_B\) = mass of square B

\(m_C\) = mass of square C

\(x_A\) = distance of the center of mass of square A

\(x_B\) = distance of the center of mass of square B

\(x_C\) = distance of the center of mass of square C

Substitute values,

\(x_c_m = (100.0 cm^2 * 5.0 cm + 400.0 cm^2 * 10.0 cm + 900.0 cm^2 * 15.0 cm) / (100.0 cm^2 + 400.0 cm^2 + 900.0 cm^2)\)

\(x_c_m = 13.0 cm\)

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The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

HOW TO CALCULATE MASS:

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Answer:

C. Constant

Explanation:

The total energy of the cannonball remains constant as it travels through the air.

Answer:

Explanation:

hi my name is Ava

The answer is A The first law