here are the rest of my points (btw i barley logged in to brainly but now i am logging out of it) (sorry it only 13 points) :)

Note that the angle indicated by the question mark is 75°. See the explanation below.

Given that the angle at the vertex that they (the equilateral triangle and the square share) is a right angle or 90 degrees.

This means that the middle angle of the equilateral triangle is 60° this is because an "equilateral" triangle has 3 equivalent sides and, therefore, 3 equivalent angles.

Since the sum of the 3 angles of ANY triangle is 180°, then 180/3 = 60° for each angle.

Because the angle at the vertex is "splitting" a right angle, or 90 degrees which belongs to the square, then that leaves 2 smaller angles on each side of the 60° angle,

or 90 - 60

=30/2

=15° each.

That is the top angle of the triangle you are trying to solve.

Therefore, since that small triangle is a right triangle, then: 180 - 90 - 15 =75°, which is the angle with a question mark (?)

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Full Question:

An equilateral triangle and a square are inscribed in a circle as shown.  ABCis isosceles. The triangle and square share a common vertex. What is the number of degrees in the measure of the angle indicated by the question mark? (See attached)

Answer:

L = 12 inches

Step-by-step explanation:

Given the formula: V = LWH, where V = 7560 in³, W = 12 in., and H = 30 in.

To solve for L:

V = LWH

Divide both sides of the equation by WH to isolate L:

V = LWH

\(\frac{V}{WH} = \frac{LWH}{WH}\)

\(\frac{V}{WH} = L\)

Plug in the given values to solve for L:

\(L = \frac{V}{WH}\)

\(L = \frac{7560}{12(30)} = \frac{7560}{360} = 12\)

Therefore, the length of the suitcase is 12 inches.

Answer:

Sample response: If x represents the number of downloads, you can write the inequality 1.29x ≤ 20. Solving the inequality, you find that x is less than or equal to about 15.5. Since he can’t download part of a song, Joseph can download 15 or fewer songs.

Step-by-step explanation:

got right on edg

Answer:

16%

Step-by-step explanation:

12/75 = 0.16

The amount of milk needed for a 17-pound goat and a 55-pound goat are 55 and 87.5 cubic units, respectively

The equation is given as:

y =1.5x + 5

For a 17-pound goat, we have:

x = 17

This gives

y =1.5 * 17 + 5

y = 30.5

For a 55-pound goat, we have:

x = 55

This gives

y = 1.5 * 55 + 5

y = 87.5

Hence, the amount of milk needed for a 17-pound goat and a 55-pound goat are 55 and 87.5 cubic units, respectively

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Answer:

Step-by-step explanation:

Let w represent Felipe's walking speed in miles per hour. Then his total travel time is ...

  time = distance/speed

  3 = 3/w +3/(w+1.5) . . . . . total time is the sum of walking and jogging times

  1 = 1/w +1/(w +1.5) . . . . . divide by 3

  w(w +1.5) = (w+1.5) +w . . . . multiply by w(w+1.5)

  w^2 -0.5w -1.5 = 0 . . . . . . subtract 2w+1.5

  (w -1.5)(w +1) = 0 . . . . . . . factor

The values of w that make this equation true are w = 1.5 and w = -1. Only the value 1.5 makes any sense in this scenario. Felipe's jogging speed is then 1.5+1.5 = 3 mph.

Felipe walks at 1.5 mph and jogs at 3 mph.

The x-component of vector b is approximately -139 km.

To find the x-component of vector b, we need to consider the horizontal displacement of the airplane during its flight from the airport to city B.

Given:

Distance from the airport to city A = 96 km

Direction from the airport to city A = 34° North of East

Distance from city A to city B = 63.6 km

Direction from city A to city B = 32° West of North

Distance from city B to city C = 185 km

To determine the x-component of vector b, we can break down the distances and directions into their respective x and y components.

For the flight from the airport to city A, the x-component can be calculated as:

x-component of vector A = Distance from the airport to city A × cos(34°)

For the flight from city A to city B, the x-component can be calculated as:

x-component of vector B = Distance from city A to city B × sin(32°)

For the flight from city B to city C, since it is purely westward (in the negative x-direction), the x-component will be the negative of the distance:

x-component of vector C = - Distance from city B to city C

Adding up the x-components:

x-component of vector b = x-component of vector A + x-component of vector B + x-component of vector C

Substituting the given values and evaluating the expressions:

x-component of vector b = 96 km × cos(34°) + 63.6 km × sin(32°) - 185 km

Calculating the values:

x-component of vector b ≈ 62.73 km + 33.49 km - 185 km

x-component of vector b ≈ -88.78 km

Therefore, the x-component of vector b is approximately -139 km.

In summary, the airplane's x-component of vector b, which represents the horizontal displacement from the airport to city C, is approximately -139 km. This negative value indicates that the airplane has traveled towards the west, in the negative x-direction, during its journey from the airport to city C. The calculation involves considering the x-components of the individual vectors for each leg of the journey and adding them together to obtain the total x-component of vector b.

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The circulation integral of F around the given circle is 2π. To compute the circulation integral using the tangential vector form of Green's Theorem, we first need to parameterize the circle C.

The given circle has the equation x^2 + y^2 = 1, which can be parameterized as follows:

x = cos(t)

y = sin(t)

where t is the parameter ranging from 0 to 2π.

Next, we compute the tangential vector for the parameterization:

r(t) = cos(t)i + sin(t)j

Taking the derivative of r(t) with respect to t, we get:

r'(t) = -sin(t)i + cos(t)j

Now, we can compute the circulation integral using the formula:

∮C F · dr = ∫(F · T) ds

where F is the given vector field, T is the tangential vector, and ds is the differential arc length.

Plugging in the values, we have:

F · T = (-1 yi + 1 xj) · (-sin(t)i + cos(t)j) = -sin(t)y + cos(t)x

ds = ||r'(t)|| dt = dt

Now, we integrate over the parameter t from 0 to 2π:

∫[0 to 2π] (-sin(t)y + cos(t)x) dt

= ∫[0 to 2π] (-sin(t)sin(t) + cos(t)cos(t)) dt

= ∫[0 to 2π] (-sin^2(t) + cos^2(t)) dt

= ∫[0 to 2π] (1) dt

= [t] from 0 to 2π

= 2π

Therefore, the circulation integral of F around the given circle is 2π.

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the chicken farmer has 27 chickens.

Let's assume that the chicken farmer has x

chickens and y cows.Using the fact that the total number of animals is 30:x + y = 30 (Equation 1)Furthermore, each chicken has two legs, and each cow has four legs. Using the fact that the total number of legs is 74:2x + 4y = 74 (Equation 2)Using Equation 1, solve for y:y = 30 - xSubstitute y into Equation 2:2x + 4(30 - x) = 74Simplify and solve for x:2x + 120 - 4x = 742x = 54x = 27.

Therefore, the chicken farmer has 27 chickens.

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The farmer has 23 chickens.

To determine how many chickens the farmer has, we can use a system of equations. Let's denote the number of chickens as "c" and the number of cows as "x".

We know that the total number of animals is 30, so we have the equation:
c + x = 30    (Equation 1)

We also know that the total number of legs is 74. Since chickens have 2 legs and cows have 4 legs, we can express this relationship as:
2c + 4x = 74    (Equation 2)

To solve this system of equations, we can use the method of substitution. Rearrange Equation 1 to solve for c:
c = 30 - x

Substitute this expression for c into Equation 2:
2(30 - x) + 4x = 74

Simplify and solve for x:
60 - 2x + 4x = 74
2x = 14
x = 7

Now that we know the number of cows is 7, we can substitute this value into Equation 1 to find the number of chickens:
c + 7 = 30
c = 23

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Answer:

Hallelujah, hallelujah, Hallelujaaaahhh yes lord for the rest of our days.

YES

Step-by-step explanation:

Answer:  a) 110√2 meters

                b) 2.42 hectares

Step-by-step explanation:

a) Since it is a square, the diagonal cuts the square into two 45-45-90 triangles where the diagonal is the hypotenuse.  Therefore, the sides are length x and the diagonal is length x√2.

\(x\sqrt2=220\\\\\\x=\dfrac{220}{\sqrt2}\\\\\\x=\dfrac{220}{\sqrt2}\bigg(\dfrac{\sqrt2}{\sqrt2}\bigg)\\\\\\x=\large\boxed{110\sqrt2}\)

b) Area of a square is side squared.    10,000 meters² = 1 hectare

   \(A=(110\sqrt2)^2\\\\.\quad =(110)^2(\sqrt2)^2\\\\.\quad =12100(2)\\\\.\quad =24200\ \text{meters}^2\\\\.\quad =\large\boxed{2.42\ \text{hectares}}\)

Answer:

101

Step-by-step explanation: it is before 111 and after 91

Answer:

101

Step-by-step explanation:

91, 101, 111. 101 is above 91, but below 111, while it is also counting by tens starting from 21

Answer: $225

Step-by-step explanation:

Let the value of the bond at the purchase price be x.

Based on the information in the question, the equation to solve the question will be:

x + (8% × x) = $243

x + (8/100 × x) = $243

x + 0.08x = $243

1.08x = $243

x = $243/1.08

x = $225

Taylor's mom purchased the bond at $225

Answer:

16 in

Step-by-step explanation:

4 +4+4+4 = 16

Answer:

16

Step-by-step explanation:

since perimeter is the length of all the sides added up, and the sides of a square are all equal, you just add up all the sides!

Given:

The polynomial is

\(4x^3+25x^2+6x\)

To find:

The solutions of given polynomial by factoring.

Solution:

Let the polynomial be

\(P(x)=4x^3+25x^2+6x\)

It can be written as

\(P(x)=x(4x^2+25x+6)\)

Splitting the middle term, we get

\(P(x)=x(4x^2+24x+x+6)\)

\(P(x)=x(4x(x+6)+1(x+6))\)

\(P(x)=x(x+6)(4x+1)\)

For solutions, \(P(x)=0\).

\(x(x+6)(4x+1)=0\)

\(x=0\text{ and }(x+6)=0\text{ and }(4x+1)=0\)

\(x=0\text{ and }x=-6\text{ and }x=-\dfrac{1}{4}\)

Therefore, the solutions of given polynomial are 0, -6 and \(-\dfrac{1}{4}\). So, all options are incorrect because they are incomplete.

The five-number summary is:

Minimum: 9

First Quartile: 16.5

Median: 25.5

Third Quartile: 39

Maximum: 51

3. Range = 42

4. Interquartile range = 22.5

Given the data for the lengths as, 36, 15, 9, 22, 36, 14, 42, 45, 51, 29, 18, 20, to find the five-number summary of the data set, we would follow the steps below:

1. The numbers in ordered from the smallest to the largest would be:

9, 14, 15, 18, 20, 22, 29, 36, 36, 42, 45, 51

2. The five-number summary for the lengths in minutes would be:

3. Range of the data = max - min = 51 - 9 = 42

4. The interquartile range for the data set = Q3 - Q1 = 39 - 16.5

Interquartile range for the data set = 22.5

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To make  a departure timetable:

The simplest: download a predefined template from Microsoft Excel.

To create a template: select A1:E2 > Merge and Center > click WEEKLY SCHEDULE > select Center Alignment.

Add borders and titles. Type the time in A3. In A4 and A5, enter time > fill cell > add days > save template.

1. Start Excel and open a new blank workbook.

2. Select the range A1:E2 and on the Home tab, select Merge and Center in the Alignment group.

3.

Type "WEEKLY SCHEDULE" in A1:E2, change the font size to 18, and select Center Alignment in the Alignment group.

4. Select cells F1:H2, on the Home tab, in the Font group, select the Border drop-down menu, and then select All Borders.

5. Enter “Daily Start Time” into F1, “Time Interval” into G1, and “Start Date” into H1.

Select the Select All icon (between 1 and A on the worksheet), then double-click the line dividing two columns to resize all cells to fit the contents.

6. Select cell A3 and enter "TIME".

7. Select cell A4 and enter the time you want the program to start.

To follow this example, enter "7:00".

8. In cell A5, enter the next interval to be listed in the plan. To follow this example, enter "7:30". Select A4:A5 and drag the fill handle down to fill the time increment for the rest of the day.

9. In cell B3, enter the day of the week you want the schedule to start. To follow this example, enter "SUNDAY".

10. Drag the fill handle to the right to automatically fill the calendar with the remaining days of the week.

11. Select row 3. Make the font bold and change the font size to 14.

12. Change the hour font size in column A to 12.

13. Choose the Select All icon or press Ctrl+A and choose Center from the Alignment group on the Home tab.

14. Select cells A1:H2. In the Font group on the Home tab, select the Fill Color drop-down list and choose a fill color for the selected cells.

15. Select the body of the program. Select the Border drop-down menu in the Font group and select All Borders.

16. Save the program that  we have made as time table.

Complete Question:

How can we help the park manager to draw a departure timetable in excel?

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We need that the average is at least 84.6 points. Let x be the score of the final test, the average then will be:

And we need this to be at least 84.6, this can be written as:

Now we solve this inequality to find x:

Therefore John has to achieve at least 87 points in the fifth test to achieve an average of 84.6.

The relation that can be formed by obersving the Cartesian Plane is y = 5x

What is Co-ordinate Geometry?

The study of geometry using coordinate points is known as coordinate geometry (or analytic geometry). It is possible to estimate the distance between two points, divide lines in a m:n ratio, identify the midpoint of a line, calculate the area of a triangle in the Cartesian plane, and so on using coordinate geometry.

Solution:

By analysing the given Cartesian Plane

it can be observed that the rate of change of y with respect to x

is 5 times

Therefore, the relation that can be formed by obersving the Cartesian Plane is y = 5x

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Here, x value of 8 would be located on the left tail of the normal distribution curve, 3.67 standard deviations below the mean (μ=22.3) and with a very low value in terms of percentile or probability (0.015%).

To indicate where the given x value of 8 would be on the curve, we need to plot it on a normal distribution curve with a mean (μ) of 22.3 and a standard deviation (σ) of 3.9.
First, we need to convert the given x value of 8 into a z-score by using the formula:  z = (x - μ) / σ
Plugging in the values, we get: z = (8 - 22.3) / 3.9 = -3.67
This means that the value of 8 is located 3.67 standard deviations below the mean.
Next, we need to find this point on the normal distribution curve. We can use a z-score table or a graphing calculator to find the corresponding area under the curve.
If we use a z-score table, we can look up the area to the left of -3.67, which is 0.00015. This means that only 0.015% of the data falls below this point.
To plot this on the curve, we can locate the mean (μ) and mark it as the center of the curve. Then, we can count 3.67 standard deviations to the left of the mean and mark this as the point where the value of 8 would be located.

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Answer:

7/3

Step-by-step explanation:

use the rise over run formula

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Given expression 8x² − 144x + 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represents the number of years since 1998.

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Given expression is 8x² − 144x + 864

Let y = 8x² − 144x + 864

also,  y - 864 = 8x² - 144x

by Extracting common factor 8 on the right side

y - 864 = 8(x² - 18x)

Add (18/2)² on both sides, we get

y - 864 + 8(18/2)² = 8 (x² - 18x + 81²)

y - 864 + 648 = 8 (x² - 8x + 9)

on simplification

y - 216 = 8 (x - 9)²

y = 8(x - 9)² + 216

therefore, y = 8 (x - 9)² + 216

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

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Answer:

3 AB+BC=AC

Step-by-step explanation:

Because they add up to get AC

Answer:

None

Step-by-step explanation:

Answer & Step-by-step explanation:

-52-3+2+21-21 =

-55+2+21-21 =

-53+21-21 =

-32-21 =

-53 =

At a significance level of 0.05, the sample data is not consistent with the null hypothesis that the proportion of population who would respond "yes" is 0.5. The P-value of 0.0005 is less than 0.05, and also the sample proportion 0.4616 is not in the interval (0.477, 0.523) which we found as 95% Confidence interval.

Therefore, we reject the null hypothesis and conclude that the population proportion of "yes" responses is different from 0.5.

The P-value for a score test for H0: π = 0.5 can be found using the z-score and a standard normal table. The z-score is calculated as

\(z = \frac{x-0.5}{0.5\sqrt{\frac{x-0.5}{n} } }\), that is

z = (x - 0.5) / (√(0.5(1 - 0.5) / n)

where x is the sample proportion of "yes" responses (842 / (842 + 982) = 0.4616), π is the population proportion of "yes" responses, and n is the sample size (842 + 982 = 1824).

\(z = \frac{0.4616-0.5}{0.5\sqrt{\frac{0.4616-0.5}{1824} } }\)

= (0.4616 - 0.5)/ (√(0.5(1 - 0.5) / 1824)

This gives a z-score of -3.28.

To find the P-value, we can use the standard normal table to find the probability of observing a z-score less than -3.28. This P-value is approximately 0.0005, which is less than the commonly used significance level of 0.05. Therefore, we would reject the null hypothesis that π = 0.5.

To construct a 95% confidence interval for π, we can use the formula for a normal approximation interval:

π ± z×(√(π(1-π) / n)) that is

\(\pi \frac{+}{} z\frac{\pi (1 -\pi )}{n}\)

Where π = 0.5, z = 1.96 (for a 95% confidence level), and n = 1824.

This gives a 95% confidence interval of (0.477, 0.523)

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We have the next equation

42=6a

we need to clear a

a=42/6

a=7

the answer is 7

Answer:

They sold 10 videos and 30 CDs

Step-by-step explanation:

So, you need two different equations-

We will use c to represent CDs and v to represent videos

So-

c + v = 40

4c + 6v = 180

Single out a variable in the first equation-

v = 40 - c

Because this is equal to v, insert it where v is in the second equation-

4c + 6(40 - c) = 180

Multiply-

4c + 240 - 6c = 180

Solve-

-2c + 240 = 180

-2c = -60

c = 30

Now that you know c, use first equation to find v-

30 + v = 40

v = 10

So c = 30 and v = 10