Help with both questions I’ll mark brainliest

In an optics experiment, the three possible reasons to account for the absence of an image on the screen. are:

Image out of focus - The picture is frequently just out of focus. Perhaps you over-focused on one area, making it impossible for you to see a clear picture. Some folks struggle to locate a clear image and repeatedly turn the focus knob. The focus can be lost considerably more readily at higher magnifications, which is a special issue.

Incorrect focus plane - It's possible that you can see a clear image, but not of the thing you're trying to see. In this instance, it's likely that you were more interested in the dust on the slide's or cover glass' surface than the object itself. With the low magnification objective in place, it is preferable to start anew in this situation and refocus.

Lastly, Uncentered slides - This is yet another frequent issue. Are you attempting to study a region of the slide that does not include the object of interest or are you truly gazing at the specimen? Perhaps you cannot see anything because you are looking at a region of the slide that is completely devoid of specimens.

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Rock: Weight in air (N): 1.2, Apparent weight (N): 1.0, Buoyant Force (N): 0.2, Mass of beaker and water (kg): 0.069, Mass of beaker (kg): 0.048, Mass of displaced water (kg): 0.021 and Weight of displaced water (N): 0.21.

Buoyant force is the upward force exerted on an object when it is submerged in a fluid. This force is caused by the pressure differences between the top and bottom of the object, due to the fact that the pressure at the bottom of the object is greater than the pressure at the top. This pressure difference is caused by the fluid’s weight, which is pushing down on the object from above.

Styrofoam:

Weight in air (N): 0.85

Apparent weight (N): 0.13

Buoyant Force (N): 0.72

Mass of beaker and water (kg): 0.123

Mass of beaker (kg): 0.048

Mass of displaced water (kg): 0.075

Weight of displaced water (N): 0.75

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

The insights to be used in creating a primary message is that; Electric vehicle demand is skyrocketing. Option C

We can see that the demand for electric vehicles has increased in the recent times. Why has the demand for electric vehicles increased? We know that in the recent times there has been a push for the use of cleaner energy.

This has made a strong impressions upon governments around the would and has led to an increase in the rate at which any kind of research that tries to fund the use of devices that use alternative energy to fossil fuels is concerned.

As a result of this, there has been an increase in the demand and the use of the electric vehicles especially in the developed countries where more people can be able to afford the vehicles.

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Answer:

They are inversely related

Explanation:

The mass of an object and its ability to pick up speed or accelerate is inversely proportional.

According to newton's second law of motion "the force on an object is the product of its mass and acceleration".

force  = mass x acceleration

 So;  for an object to pick up speed faster, it must have a lower mass. The higher the mass of a body, the lower its acceleration.

At constant speed, there is no acceleration and the mass of the body is not relevant to the motion.

Answer:

you increase the force on the mass and then it will hit the acceleration u seet for it

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 800 × 35

We have the final answer as

Hope this helps you

W = 25 J

Explanation:

Work done on an object is defined as

\(W = Fd = (10\:\text{N})(2.5\:\text{m}) = 25\:\text{J}\)

Answer: Ok so We already know that velocity is on the x-axis.

Since acceleration = Force / Mass

Here the Force is downward due to the gravitational pull or we can say it is along y-axis.

Since acceleration is directly proportional to force, so acceleration is also along y-axis. This means that velocity & acceleration are perpendicular to each other.

Example:

Let us assume that an aeroplane is flying parallel to the horizontal plane. The aeroplane will experience the acceleration in several directions. One of them here is the gravitational pull which is perpendicular to the the apparent velocity. So the net velocity & its direction will depend upon the vector sum total of all the forces/acceleration acting on it. Also because of this gravitational pull the aeroplane rotates along with the earth, which is a proof that the force/g experienced by it does not go waste.

Explanation:

Answer:

How to write a powerful design brief in 9 easy steps

Start with an overview of the business.

Cover the scope.

Define the audience.

Understand the competition.

Set specific goals.

Take inventory of what you already have.

Set the schedule.

Determine the budget.

Explanation:

Answer: Climate change poses to the tourism development in Fiji islands. It shows the adverse effects of the changing climate and the dangers pose by the tourism activities and also pose a major hazard for the local people in the region. It also deals with the dangerous carbon emissions and CO2 effect on the landscape, food, water, energy.

The pacific is the world`s largest ocean with a surface area of 175 million sq km and constitutes for 40% of the planet`s waters. Located in the tropical latitudes, it covers more than half the globe`s circumference. Temperature of the surface water in the western tropical regions is always more than 28 ÌŠC over a depth of several hundred meters. This makes up the world`s storage of thermal energy for exchange with atmosphere. Here the interaction between atmosphere and ocean is most extreme and influences the climate not only regionally but planet-wide. The nations of the pacific are obscured human settlements absorbed in this vast fluid universe. The ocean is the most important factor controlling the environment and life.

Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

Answer:

slender-bodied non-stinging insect having iridescent wings that are outspread at rest; adults and nymphs feed on mosquitoes etc.

Explanation:

I hope this works. I have a snake and it helps to know this stuff

The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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Answer:

The first and the last answer

Weight is best defined as C) the force of gravity on an object.

2.50 m above the water's surface, a person is resting on a diving board in a swimming pool. The penny appears to be seven meters away from her in her field of vision.The depth of water from this point is 6m.  

                  The distance of board from water surface is given as 2.50m and appeared distance of penny from eyes of the person in board is given as 7.00m so this means apparent distance of penny from eyes of the person is:-

Total appeared distance from eyes of the person when its above the board- distance of the board from surface of the water.

Which is given as

=7.00m - 2.50m

=4.5m.

As we look at something from rarer to denser medium the apparent depth of that object which appears to us decreases.

So real depth of water can be given to us by:-

Apparent depth=Real depth / vdr,

here vdr is refractive index of denser medium with respect to refractive index of rarer medium which is given by

vdr=vd / dr

=Refractive index of water / Refractive index of air

=43  

Therefore apparent depth is

=4.54/3

=6m.

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\(g = \frac{GM}{r {}^{2} } \\ g = \frac{6.673 \times 10 {}^{ - 11} \times 10 {}^{18} }{(10 {}^{3}) {}^{2} } \\ g = \frac{6.673 \times 10 {}^{7} }{10 {}^{6} } \\ g = 6.673 \times 10 \\ g = 66.73 \: m.s {}^{ - 2} \)

Answer:

A major challenge in the drug delivery field is to enhance transport of therapeutics across biological barriers such as the blood brain barrier (BBB), the small intestine, nasal, skin and the mouth mucosa.

Answer:

An aqueous stagnant layer that overlies the apical membrane and the subepithelial blood flow are potential barriers to the absorption of drugs that readily penetrate the absorbing cell of the epithelium. The apical, basal, and basement membranes are potential barriers to the absorption of less permeable drugs

Answer:

spirit animal?

Explanation:

Explanation:

To determine the velocity and pressure head at position B in a horizontally converging pipe, we can use the principle of conservation of mass and Bernoulli's equation.

According to the principle of conservation of mass, the mass flow rate remains constant throughout the pipe. Therefore, we can write:

A₁V₁ = A₂V₂

where A₁ and A₂ are the cross-sectional areas at positions A and B, respectively, and V₁ and V₂ are the velocities at positions A and B, respectively.

Given:

A₁ = (π/4)(d₁)² = (π/4)(200 cm)² = 31416 cm²

A₂ = (π/4)(d₂)² = (π/4)(150 cm)² = 17671 cm²

V₁ = 2 m/s

We can calculate V₂ using the equation:

V₂ = (A₁V₁) / A₂

Substituting the values:

V₂ = (31416 cm² * 2 m/s) / 17671 cm² ≈ 3.54 m/s

Therefore, the velocity at position B is approximately 3.54 m/s.

Next, to determine the pressure head at position B, we can use Bernoulli's equation:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂² + ρgh₂

Assuming the datum is at position B, where the pressure head (h₂) is zero, the equation simplifies to:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂²

Given:

g = 10 m/s² (acceleration due to gravity)

Z = 0 m (datum)

ρ = density of the liquid (not given)

Since the density (ρ) of the liquid is not provided, we cannot determine the absolute pressure at position B or calculate the pressure head. The information given is insufficient to determine the pressure head at position B.

In summary:

- The velocity at position B is approximately 3.54 m/s.

- The pressure head at position B cannot be determined with the given information.

The minimum velocity for the meteorite before entrance into earth's atmosphere is 36.8 m/s.

To calculate the minimum velocity the meteorite must have had before it entered Earth's atmosphere, the equation for heat transfer is:

Q = mcΔT

Where Q = the heat transferred,

m = the mass of the meteorite,

c = the specific heat capacity of iron, and

ΔT = the change in temperature.

The specific heat capacity of iron is approximately = 0.45 J/g°C.

Temperature of the meteorite changes from -105°C to the melting point of iron, which is approximately = 1535°C.

So: Q = mc(1535 - (-105))

Mass of the meteorite unknown, but we know it is made of iron, so assume a value for the mass, such as 100 g.

Q = 100 x 0.45(1535 - (-105))

Solving for Q:

Q = 67875 J

To calculate the kinetic energy of the meteorite, which is given by the equation: Ek = 1/2mv²

where Ek is kinetic energy,

m = the mass of the meteorite and

v = the velocity of the meteorite.

Therefore, the velocity of the meteorite is given by the following equation: v = √(2Ek/m)

Substituting the values of Ek and m, we get

v = √(2 x 67875/100)

Solving for v:

v = √1357.5

The minimum velocity the meteorite must have had before it entered Earth's atmosphere is approximately 36.8 m/s.

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Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

The number of distinct ways of placing four indistinguishable balls into five distinguishable boxes is 20.

To solve this problem, we can use the stars and bars method, which is a combinatorial technique used to count the number of ways to distribute indistinguishable objects into distinguishable containers. In this case, we have four indistinguishable balls and five distinguishable boxes.

The stars and bars method works by representing each ball as a star and using bars to separate the balls into different boxes. For example, if we wanted to distribute two balls into three boxes, we could use the following diagram:

* | * * | *

In this diagram, the first and last bars represent the boundaries of the containers, while the stars represent the balls.

The second bar separates the first two balls from the last ball, indicating that the first two balls are in the first container and the last ball is in the third container.

To distribute four balls into five boxes, we need to use three bars to separate the balls into four groups. We have a total of six spaces to place the bars (including the boundaries), and we need to choose three of them to place the bars.

Therefore, the number of distinct ways to place four indistinguishable balls into five distinguishable boxes is the same as the number of ways to choose three spaces out of six, which is:

6 choose 3 = (6!)/(3!3!) = 20

Therefore, there are 20 distinct ways to place four indistinguishable balls into five distinguishable boxes using the stars and bars method.

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Answer:

Ussually, soft metals. or solid objects that allow the flow of eletrons.

Explanation:

Electric Current is the flow of electrons through a wire or solution. In a solid the electrons are passed from one positively charged metallic atom to next but in solution the electron is carried by the ions present in the solution. A solution capable of carrying charge is called an electrolyte.

In solid conductors, electron mobility is responsible for the flow of electrical current.

Electron mobility is principally responsible for the flow of electrical current in solid conductors. The subatomic particles known as electrons orbit the atomic nuclei of atoms and are negatively charged. The outermost energy levels of the atoms in a solid conductor, such as a metal like copper or aluminum, have numerous free or loosely bound electrons.

The conductor experiences an electric field that pulls on the free electrons when an electric potential difference (voltage) across its ends is applied (for example, by connecting it to a battery or power source). The electrons are propelled by this force toward the direction of the electric field.

Hence, in solid conductors, electron mobility is responsible for the flow of electrical current.

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A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.

A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.

Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience

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Sure, that sounds great! What kind of math are we studying? Do you have any specific topics you want to focus on?

A topic is a subject or issue that forms the basis of a discussion, paper, speech, or other form of communication. It is typically used to focus the ideas and facts presented in the communication, making it easier for the audience to understand and remember. It can be an essay, a research paper, a presentation, or any other type of communication that is intended to present and discuss a particular idea. By choosing a specific topic, the author is able to narrow down the scope of the discussion and focus on the main ideas more efficiently.

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The two sentences that best state the central ideas of Wiesel's speech are:

Elie Wiesel's speech focuses primarily on the Holocaust and the atrocities that were committed during that time, particularly at Auschwitz. The central ideas of his speech are:

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