help pls what is he surface area measured in square centimeters, of the shape
below do not include units in your answer

There are 200 raffle tickets, so the probability of winning is

The probability of losing is, therefore,

The gain when winning is

The loss is

The Expected payoff is, therefore,

Answer:

Step-by-step explanation:

3x - 13 + 58 = 90. [Complementary Angles]

=> 3x + 45 = 90

=> 3x = 90 - 45

=> 3x = 45

\( = > x = \frac{45}{3} \)

=> x = 15 (Ans)

Answer:

X=15

Step-by-step explanation:

The Square means the 2 angles = 90 degrees so we do this

90 - 58 = 32

so now we KNOW the second angle has to be 32.

so

3x-13=32

now we solve

3x-13=32

  +13  +13

3x=45

/3  /3

x=15

Hope I helped :D

In the  word problem above, 0 small pizzas, 1 medium pizza, and 5 large pizzas were delivered to the college.

Let  S = number of small pizzas delivered

Let M = number of medium pizzas delivered

Let L = number of large pizzas delivered

We'll start by solving equation 1 for one variable and substituting it into the other equations.

S + M + L = 12

We can rewrite this equation as -

S = 12 - M - L

Now, substitute this value of S in equations 2 and 3 -

4S + 10M + 15L = 109

4(12 - M - L) + 10M + 15L = 109

48 - 4M - 4L + 10M + 15L = 109

6M + 11L = 61

2S + 4M + 13L = 81

2(12 - M - L) + 4M + 13L = 81

24 - 2M - 2L + 4M + 13L = 81

2M + 11L = 57

Now we have a system of two equations with two variables -

6M + 11L = 61 ...(4)

2M + 11L = 57 ...(5)

Subtract  equation   (5)from equation (4) -

(6M +   11L) - (2M +11L) = 61 - 57

4M = 4

M = 1

Substitute the value of M into equation (5) -

2(1) + 11L = 57

2 + 11L = 57

11L = 55

L = 5

Now substitute the values of M and L into equation (1) -

S + 1 + 5 = 12

S + 6 = 12

S = 6 - 6

S = 0

Therefore, the solution is -

S = 0 (no small pizzas)

M = 1 (1 medium pizza)

L = 5 (5 large pizzas)

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Full Question:

Although part of your question is missing, you might be referring to this full question:

a pizza shop delivered 12 pepperoni pizzas to a college on the first night of final exams. the total cost of the pizzas was $109. a small pizza costs $4 and contains 2 ounces of pepperoni. a medium pizza costs $10 and contains 4 ounces of pepperoni. a large pizza cost $15 and contains 13 ounces of pepperoni. the owner of the pizza shop used 5 pounds 1 ounces of pepperoni in making the 12 pizzas. how many pizzas of each size were delivered to the college?

Answer:

5/28

Step-by-step explanation:

So first find a common denominator

4/7 + 1/4 can be translated as 16/28+7/28

16/28+7/28=23/28

NOw we have to subtract 23/28 from1, or 28/28, and that is 5/28

Answer: 5/28 left over.

Step-by-step explanation:

Make both of the fractions have the same denominator:

4/7 x 4/4 = 16/28

1/4 x  7/7 = 7/28

Combine:

16/28 + 7/28 = 23/28

So on Friday you have 5/28 of the item left over.

Basically everything but statement IV is true

Horizontal lines always have a slope of 0 to indicate no rise is going on.

Vertical lines have undefined slopes which you can see through the slope formula (recall that you cannot divide by zero).

Line 'a' goes through the point (5,0) making statement III true. However, statement IV is false because (-5,0) is not on line b. Line b is parallel to the x axis, so it does not have an x intercept.

The equation for the cost of n t-shirts is c = 15 + 9(n + 1), the term 9(n + 1) represents the cost of additional shirts beyond the first shirt, and the coefficient 9 represents the amount by the cost decreases for each additional shirt.

The cost of n t-shirts is given by the equation:

c = 15 + 9(n + 1)

c is the cost in dollars and n is the number of t-shirts.

The cost for 2 t-shirts, we substitute n = 1 into the equation:

c = 15 + 9(1 + 1) = 33

So it will cost \($33\) for 2 t-shirts.

The cost for 5 t-shirts, we substitute n = 4 into the equation:

c = 15 + 9(4 + 1) = 51

So it will cost \($51\) for 5 t-shirts.

The cost of additional shirts after the first one is \($9\) per shirt.

The equation for the cost of n t-shirts is c = 15 + 9(n + 1), the term 9(n + 1) represents the cost of additional shirts beyond the first shirt, and the coefficient 9 represents the amount by which the cost decreases for each additional shirt.

The following formula calculates the price of n t-shirts: c = 15 + 9(n + 1).

n is the quantity of t-shirts, and c represents the price in dollars.

We change n = 1 to represent the price of 2 t-shirts:

c = 15 + 9(1 + 1) = 33

the price will be.

t-shirts for two.

We enter n = 4 to get the price for 5 t-shirts: c = 15 + 9(4 + 1) = 51

the price will be.

Five t-shirts worth.

After the first shirt, additional shirts cost each shirt.

The cost of n t-shirts is given by the equation c = 15 + 9(n + 1), where the phrase 9(n + 1) denotes the price of subsequent shirts after the first shirt and the coefficient 9 denotes the amount by which the cost increases.

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Answer:

One thousand three hundred forty eight

Step-by-step explanation:

Answer: B

Step-by-step explanation:

The horizontal change is 6.

The vertical change is 5.

So, the distance is \(\sqrt{6^2 + 5^2}=\sqrt{61}\)

A 1.5 standard deviations above the mean IQ score is 122.5.

An expression that depicts the relationship between two or more numbers and variables is called an equation.

A dependent variable is one that depends on another variable, whereas an independent variable does not depend on any other variable for its value.

Giving the z score are:

z is calculated as (raw score - mean) / standard deviation.

with a standard deviation of 15 and a mean of 100. The z-score of 1.5 is equal to the IQ score that is 1.5 standard deviations above the mean, so:

1.5 = (x - 100)/15

x = 122.5

A 1.5 standard deviations above the mean IQ score is 122.5.

The Complete Question is IQ score.

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Bryan invested $1600 in the first account (earning 11% interest) and $4900 (6500 - 1600) in the second account (earning 7% interest).

Let's assume that Bryan invested an amount of x dollars in the first account, which earns 11% interest, and (6500 - x) dollars in the second account, which earns 7% interest.

The interest earned from the first account can be calculated as 0.11x, and the interest earned from the second account can be calculated as 0.07(6500 - x).

According to the problem, the total interest earned after one year is $519. So we can set up the equation:

0.11x + 0.07(6500 - x) = 519

Simplifying the equation:

0.11x + 455 - 0.07x = 519

0.04x + 455 = 519

0.04x = 64

x = 64 / 0.04

x = 1600

Therefore, Bryan invested $1600 in the first account (earning 11% interest) and $4900 (6500 - 1600) in the second account (earning 7% interest).

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The Nearest tenth of a second, the flag is in the air for approximately 0.1 seconds before Zack catches it.

To determine the time the flag is in the air before Zack catches it, we can use the kinematic equation for vertical motion:

h = 16t^2 + vt + s

Where:

h is the height of the flag,

t is the time in seconds,

v is the initial vertical velocity of the flag,

s is the initial height of the flag.

In this case, the flag is thrown into the air from a height of 5 feet (s = 5) with an initial vertical velocity of 30 feet per second (v = 30). Zack catches it at a height of 7 feet (h = 7).

We can rewrite the equation as:

7 = 16t^2 + 30t + 5

To find the time (t) when the flag is at a height of 7 feet, we can rearrange the equation and solve for t. However, since this is a quadratic equation, we can also use the quadratic formula.

The quadratic equation in this case is:

16t^2 + 30t + 5 - 7 = 0

16t^2 + 30t - 2 = 0

Now, we can use the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

Applying the values from the quadratic equation, we have:

t = (-30 ± √(30^2 - 4 * 16 * (-2))) / (2 * 16)

Simplifying further:

t = (-30 ± √(900 + 128)) / 32

t = (-30 ± √1028) / 32

Using a calculator, we find two solutions:

t ≈ -1.08 seconds or t ≈ 0.06 seconds

Since time cannot be negative in this context, we discard the negative solution.

Therefore, to the nearest tenth of a second, the flag is in the air for approximately 0.1 seconds before Zack catches it.

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By using the substitution method, we will see that the value of y is 23.

Here we have a system of linear equations, the system is:

y - x = 11

x = 12

The second equation is trivial, it just gives the value of x. Then we can use the substitution method and replace it in the first equation, then we will get:

y - 12 = 11

Now we can solve this for y, we will get:

y = 11 + 12

y = 23

That is the value of y.

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Step-by-step explanation:

The circumference of a WHOLE circle = pi * d

   you have 1/2 of this  and d = 10 ft

     so   1/2 pi * 10      PLUS the two straight sides + 8+6

       1/2 pi * 10   + 8 + 6

         5 pi + 8 + 6

        5 * 3.14   + 14 = 29.7 ft

SOLUTION:

Case:

Given:

Required:

Method:

Final answer:

Answer:

If the borrower defaults on the loan, the lender can collect the collateral outlined in the loan agreement. But the lender can’t go after the borrower for further compensation, even if the value of the collateral doesn’t cover the full amount of debt owing.

Step-by-step explanation:

Answer:Wuts the answer

Step-by-step explanation:

Answer:

26

Step-by-step explanation:

104 divided by the 4 sides (for perimeter) equals 26

Answer:

The builder will use 5.28 acres of land for baseball fields.

Step-by-step explanation:

This question can be solved using a rule of three.

The property has 16.1 acres of land. This is 100% = 1. 33% will be used for baseball fields. How much is 0.33?

16.1 - 1

x - 0.33

\(x = 16*0.33 = 5.28\)

The builder will use 5.28 acres of land for baseball fields.

Answer:

3 represent growth it is the ans of this qn

Step-by-step explanation:

bcz 3 is increasing eqn by 3

1. In this case, we want the reliability to be 95%, so the probability of not breaking down is 0.95.

2. Probability of no breakdowns = (reliability of a single machine)^3. Probability of at least one breakdown = 1 - Probability of no breakdowns

1. To determine how often the computer should be scheduled for maintenance, we need to consider the reliability and the desired level of operational condition. Since the duration for trouble-free operation follows a gamma distribution with a mean of 40 days, this means that, on average, the computer can operate for 40 days before a breakdown occurs.

To ensure operational condition with a 95% probability, we can calculate the maintenance interval using the concept of reliability. The reliability represents the probability that the machine will not break down within a certain time period. In this case, we want the reliability to be 95%, so the probability of not breaking down is 0.95.

Using the gamma distribution parameters, we can find the corresponding reliability for a specific time duration. By setting the reliability equation equal to 0.95 and solving for time, we can find the maintenance interval:

reliability = 0.95

time = maintenance interval

Using reliability and the gamma distribution parameters, we can calculate the maintenance interval.

2. To calculate the probability that at least one of the three machines will break down within the first scheduled maintenance time, we can use the complementary probability approach.

The probability that none of the machines will break down within the first scheduled maintenance time is given by the reliability of a single machine raised to the power of the number of machines:

Probability of no breakdowns = (reliability of a single machine)^3

Since the breakdown times between the machines are statistically independent, we can assume that the reliability of each machine is the same. Therefore, we can use the reliability calculated in the first part and substitute it into the formula:

Probability of at least one breakdown = 1 - Probability of no breakdowns

By calculating this expression, we can determine the probability that at least one of the three machines will break down within the first scheduled maintenance time.

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Answer:

40

Step-by-step explanation:

\(8=2^3 \\ \\ 20=2^2 \times 5 \\ \\ \lcm(8,20)=2^3 \times 5=40\)

Answer:

260?

Step-by-step explanation:

I used the equation (4)13+(16)13 and plugged it into my calculator and got 260.

The sum of 4 thirteens and 16 thirteens is 260.

What is the meaning of sum?

You add up all the numbers to arrive at the sum. When you summarise something, you pay attention to all of its crucial components. A specific sum of money can also be referred to using the word sum. You might have to spend a sizable sum of money on a new car. However, you might be able to justify spending so much if you add up or total all of its advantages. When you add up the costs of everything you ordered, the total on a restaurant bill is determined. Sum need not be restricted to numbers. When you summarise something, you're providing a summary or overarching statement about it.

Here, 4 thirteens = 4 × 13 = 52

16 thirteens = 16 × 13 = 208

Sum of 4 thirteens and 16 thirteens = 52 + 208 = 260

Hence, 260 is the correct answer.

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Answer:

7200

Step-by-step explanation:

7000

200

the seven is in thousand spot and 2 is in hundreds spot

Answer:

2.04

Step-by-step explanation:

\(5.33-3.29=2.04\)

Answer:

2.04

Step-by-step explanation:

5.33-3.29=2.045.33−3.29=2.04

Answer:

A. 76

B. x^2 +21x + 96

C. x^2 - 9x + 6

Step-by-step explanation:

For this problem, just plug in the number in f(x) for x in the function.

A. f( 5 ) -> Plug in 5 for every x and then simplify

(5)^2 + 9(5) + 6

= 25 + 45 + 6

= 76

B. f( x+6 ) -> Plug in (x+6) for every x and then simplify

(x+6)^2 + 9(x+6) + 6

x^2 + 12x +36 + 9x+ 54 + 6

x^2 +21x + 96

C. f( -x ) -> Plug in -x for every x and then simplify

(-x)^2 + 9(-x) + 6

x^2 - 9x + 6

Answer: 5.5% decrease

Step-by-step explanation:

The correct answer is Confidence interval lower bound: 32.52 cm,Confidence interval upper bound: 37.48 cm

To calculate the confidence interval for the true mean height of the loaves, we can use the t-distribution. Given that the sample size is small (n = 10) and the population standard deviation is unknown, the t-distribution is appropriate for constructing the confidence interval.

The formula for a confidence interval for the population mean (μ) is:

Confidence Interval = sample mean ± (t-critical value) * (sample standard deviation / sqrt(sample size))

For the first situation:

n = 15

Confidence level is 95% (which corresponds to an alpha level of 0.05)

x = 35 (sample mean)

s = 2.7 (sample standard deviation)

Using RStudio or a t-table, we can find the t-critical value. The degrees of freedom for this scenario is (n - 1) = (15 - 1) = 14.

The t-critical value at a 95% confidence level with 14 degrees of freedom is approximately 2.145.

Plugging the values into the formula:

Confidence Interval = 35 ± (2.145) * (2.7 / sqrt(15))

Calculating the confidence interval:

Lower Bound = 35 - (2.145) * (2.7 / sqrt(15)) ≈ 32.52 (rounded to 2 decimal places)

Upper Bound = 35 + (2.145) * (2.7 / sqrt(15)) ≈ 37.48 (rounded to 2 decimal places)

Therefore, the lower bound of the confidence interval is approximately 32.52 cm, and the upper bound is approximately 37.48 cm.

For the second situation:

n = 37

Confidence level is 99% (which corresponds to an alpha level of 0.01)

x = 82 (sample mean)

s = 5.9 (sample standard deviation)

The degrees of freedom for this scenario is (n - 1) = (37 - 1) = 36.

The t-critical value at a 99% confidence level with 36 degrees of freedom is approximately 2.711.

Plugging the values into the formula:

Confidence Interval = 82 ± (2.711) * (5.9 / sqrt(37))

Calculating the confidence interval:

Lower Bound = 82 - (2.711) * (5.9 / sqrt(37)) ≈ 78.20 (rounded to 2 decimal places)

Upper Bound = 82 + (2.711) * (5.9 / sqrt(37)) ≈ 85.80 (rounded to 2 decimal places)

Therefore, the lower bound of the confidence interval is approximately 78.20 cm, and the upper bound is approximately 85.80 cm.

For the third situation:

n = 1009

Confidence level is 90% (which corresponds to an alpha level of 0.10)

x = 0.9 (sample mean)

s = 0.04 (sample standard deviation)

The degrees of freedom for this scenario is (n - 1) = (1009 - 1) = 1008.

The t-critical value at a 90% confidence level with 1008 degrees of freedom is approximately 1.645.

Plugging the values into the formula:

Confidence Interval = 0.9 ± (1.645) * (0.04 / sqrt(1009))

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