Answer: Chemical
Explanation: because it is changeing its chemical structure if its wrong sorry .
Answer:
chemical, chemical, chemical, mechanical, chemical, mechanical, chemical. im still trying to figure out the rest!
Explanation:
A grandfather clock uses a pendulum that is 62.0 cm long. It is accidentally broken, and when repaired the length isshorter by 2.90 mm. Treating the clock's pendulum as a simple pendulum, by how much will the repaired clock differ from the correct time every 24 hours?
The Time difference in the period of a simple pendulum is 11.6 s
The period of a simple pendulum is given as follows,
\($$T=2\pi \sqrt{\frac{L}{g}}$$\)
Where
T = time period
L = length of the pendulum
g = acceleration due to gravity = 9.8 m/s²
The period of the original pendulum is given as:
T = 2π√(L/g)
The time period of the shortened pendulum is given as:
T' = 2π√(L'-g)
By comparing the above two equations, we have,
T' = 2π√[(L-2.90 mm)/g] ≈ T
[As 2.90mm is very small compared to 62cm]
Therefore, the time difference,
ΔT = T' - T= 0Hr. 00min. 11.6s (approx)≈ 11.6s (approx)
Thus, the clock will be slower by approximately 11.6s every 24 hours.
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What is the speed of a wave that has a frequency of 110 Hz and a wavelength
of 0.21 m?
OA. 23.1 m/s
OB. 0.04 m/s
O C. 523 m/s
OD. 0.002 m/s
The speed of the wave of wavelength 0.21 m is 23.1 m/s. And the correct answer is 0A. 23.1 m/s.
How to calculate the speed of a wave?The speed of a wave is calculated by multiplying the wavelength and the frequency of the wave.
To calculate the speed of the wave, we use the formula below.
Formula:
s = λf......................................Equation 1Where:
s = Speed of the waveλ = Wavelength of the wavef = Frequency of the waveFrom the question,
Given:
f = 110 Hzλ = 0.21 mSubstitute these values into equation 1
s = 110×0.21s = 23.1 m/sHence, the speed of the wave is 23.1 m/s.
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A particle moves along the x-axis so that its acceleration at any time t≥0 is given by a(t)=12t−4. At time t=1, the velocity of the particle is v(1)=7 and its position is x(1)=4.
Given that a particle moves along the x-axis so that its acceleration at any time t0 is given by a(t) = 12t - 4, At time t = 1, the velocity of the particle is v(1) = 7, and its position is x(1) = 4.
To find the velocity and position of the particle, we need to integrate the acceleration, a(t), and then solve the resulting equations for the constants of integration.
To solve for C, we use the fact that v(1) = 7:v(1) = 6(1)^2 - 4(1) + Cv(1)
= 2 + C
Thus, C is 5. Now, we can write the velocity of the particle as:
v(t) = 6t^2 - 4t + 5
To find the position of the particle, we integrate the velocity.
v(t) = dx(t)/dt ⇒ dx(t)
= v(t)dt∫dx(t)
= ∫v(t)dtx(t)
= ∫(6t^2 - 4t + 5)dt
X(t) = 2t^3 - 2t^2 + 5t + K
where K is the constant of integration. To solve for K, we use the fact that
x(1) = 4:X(1)
= 2(1)^3 - 2(1)^2 + 5(1) + KX(1)
= 5 + K
Thus, K = -1.
Now, we can write the position of the particle as:
X(t) = 2t^3 - 2t^2 + 5t - 1
Hence, the velocity of the particle is v(t) = 6t2 - 4t + 5, and the position of the particle is X(t) = 2t3 - 2t2 + 5t - 1.
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Suppose the surface temperature of the Sun were about 12,000K, rather than 6000K. How much more thermal radiation would the Sun emit?
The required thermal radiation emitted by the Sun is calculated to be 16 times greater than the radiation.
We know that the energy emitted from the thermal radiation is is proportional to temperature raised to the power 4.
Thermal radiation ∝ T⁴
where,
T is temperature
The energy of the hot sun can be written as σ Thot⁴ = σ(12000)⁴
The energy of the cold sun can be written as σ Tcold⁴ = σ(6000)⁴
The ratio of both the energies is calculated to be,
⇒ σ(12000)⁴/σ(6000)⁴ = 16
Thus, the required energy output of the Sun is 16 times greater.
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What type of relationship exists between the comma teasel and all of the other plant
Answer:
Parasitic Relationship
A symbiotic relationship that is mutualism exists between the comma teasel and all of the other plants.
What is a Symbiotic relationship?Symbiosis or symbiotic relationship is any type of close and long-term biological interaction which is present between two different biological organisms, be it mutualistic relationship, commensalistic relationship, or parasitic relationship. The organisms, each termed as a symbiont, must be of different species.
The comma teasel and all of the other plants share a relationship where, the comma teasel pollinates flowers of different plant species. Pollination is important for the reproduction in plants and in return, the plants provide nectar to the organism.
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for a wavelength at the peak of visual sensitivity, 550 nm , how many photons lead to an observable flash?
The total photons required to lead to an observable flash are 3.
At the peak of visual sensitivity, the energy of photon is given by:
E = hc/λ
Where h is plank's constant, c is speed of light and λ is the wavelength
Putting the values:
E = 6.63×10^-34 × 3×10^8 / 5.50 × 10^-7m
E =3.6×10^-19 J
This is the energy of one photon. The human eye can detect an amount of energy of 10^-18 J
Amount of photons contained in this energy is
E = 10^-18 J / 3.6×10^-19 J = 3 photons
Hence, The total photons required to lead to an observable flash are 3.
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Define time interval in your own words.
Answer:
An interval is a distinct measure of time or the physical or temporal distance between two things.
Explanation:
3.7 kg of a saturated water vapor at 0.4 MPa is isothermally cooled until it is a saturated liquid. Calculate the amount of heat rejected during this process in MJ. (Report your answer in 3 decimal places.)
Answer:
7.894 MJ
Explanation:
Given that:
The mass of the saturated water vapor = 3.7 kg
The pressure of the saturated water vapor = 0.4 MPa
From saturated properties of steam tables when the pressure is at 0.4 Mpa
The enthalpy in (kJ/kg);
hf = 604.7 kJ/kg
hg = 2738.1 kJ/kg
The rejected heat during this process is:
Q = m(hg - hf)
Q = 3.7(2738.1 - 604.7) kJ/kg
Q = 3.7(2133.4) kJ/kg
Q = 7893.58 kJ/kg
Q = 7.894 MJ
A part is specified with a tensile strength minimum only (no maximum specification).
It has a Cp = 1. 2. Please determine the reject rate. RR = _______________
1. A part is specified with a tensile strength 2 sided specifications. Assume process average is centered and two sided specifications. It has a Cpk = 1. 2. Please determine the reject rate. RR = _______________
2. A part is specified with a tensile strength 2 sided specifications.
It has a Cp = 0. 7. Please determine the reject rate. RR = _______________
3. A part is specified with a tensile strength minimum only (no maximum specification).
It has a Cp = 1. Please determine the reject rate. RR = _______________
4. A part is specified with a tensile strength minimum only (no maximum specification). Assume process average is centered and one-sided specifications.
It has a Cpk = 1. 3. Please determine the reject rate. RR = _______________
5. A part is specified with a tensile strength minimum only (no maximum specification).
It has a Cp = 1. 2. Please determine the reject rate. RR = _______________
6. A part is specified with a tensile strength 2 sided specifications. Assume process average is centered and two sided specifications. It has a Cpk = 1. 1. Please determine the reject rate. RR = _______________
7. A part is specified with a tensile strength 2 sided specifications.
It has a Cp = 0. 6. Please determine the reject rate. RR = _______________
8. A part is specified with a tensile strength minimum only (no maximum specification).
It has a Cp = 1. 25. Please determine the reject rate. RR = _______________
9. A part is specified with a tensile strength minimum only (no maximum specification). Assume process average is centered and one-sided specifications.
It has a Cpk = 0. 8. Please determine the reject rate. RR = _______________
To determine the reject rate (RR) for each scenario, we need to consider the capability indices Cp and Cpk along with the specifications for tensile strength. The reject rate represents the proportion of parts that do not meet the specifications.
1. RR = 0.27%
2. RR = 16.03%
3. RR = 0%
4. RR = 0.003%
5. RR = 0.27%
6. RR = 2.28%
7. RR = 29.93%
8. RR = 0%
9. RR = 5.87%
Please note that these calculations assume a normal distribution of tensile strength and that the process is in statistical control. The reject rate is obtained by evaluating the proportion of values falling outside the specified limits based on the process capability indices Cp and Cpk.
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a table tennis ball has a diameter of 3.80 cm and average density of 0.084 0 g/cm3. What force is required to hold ir completely submerged under water?
The amount of force necessary to keep it submerged in water is F=0.258N.
The force required to hold a table tennis ball submerged in water is calculated using the formula:
\(F =\frac{ (\rho * V * g) }{ A}\)
Where F is the force, ρ is the water's density, V is the ball's volume, g is its gravitational acceleration, and A is its cross-sectional area.
The following formula is used to determine the ball's volume:
\(V = \frac{4}{3}*pi*r^3\)
where r is the ball's radius.
The radius of the ball is half its diameter, thus:
\(r = 3.8 cm^2\)
Therefore,
\(V = \frac{4}{3}*pi *(3.8 cm ^2)3\\V = 0.5222 cm3\)
The cross-sectional area of the ball is calculated using the formula:
\(A = \pi * r^2\\\\A = \pi* (\frac{3.8 cm }{ 2})^2\\A = 4.5257 cm^2\)
Substituting the values in the above formula,
\(F =\frac{ (0.084 g/cm^3 * 0.5222 cm^3 * 9.8 m/s^2) }{4.5257 cm^2}\\F = 0.258 N\)
Hence, the force needed to keep it submerged in water is 0.258N
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Michael has a constant elasticity of substitution (CES) utility function, U(q 1
,q 2
)=(q 1
rho
+q 2
rho
) rho
1
, where rho
=0 and rho≤11 14
Given that Michael's rho<1, what are his optimal values of q 1
and q 2
in terms of his income and the prices of the two goods? Answer 1. Substitute the income constraint into Michael's utility function to eliminate one control variable. Michael's constrained utility maximization problem is max q 1
,q 2
U(q 1
,q 2
)=(q 1
rho
+q 2
rho
) rho
1
s.t. Y=p 1
q 1
+p 2
q 2
We can rewrite Michael's budget constraint as q 2
=(Y−p 1
q 1
)/p 2
. Substituting this expression into his utility function, we can express Michael's utility maximization problem as: max q 1
U(q 1
, p 2
Y−p 1
q 1
)=(q 1
rho
+[ p 2
Y−p 1
q 1
] rho
) 1/rho
. By making this substitution, we have converted a constrained maximization problem with two control variables into an unconstrained problem with one control variable, q 1
2. Use the standard, unconstrained maximization approach to determine the optimal value for q 1
. To obtain the first-order condition, we use the chain rule and set the derivative of the utility function with respect to q 1
equal to zero: rho
1
(q 1
rho
+[ p 2
Y−p 1
q 1
] rho
) rho
1−rho
(rhoq 1
rho−1
+rho[ p 2
Y−p 1
q 1
] rho−1
[−− p 2
p 1
])=0 Using algebra, we can solve this equation for Michael's optimal q 1
as a function of his income and the prices: 15 (3.18) q 1
= p 1
1−σ
+p 2
1−σ
Yp 1
−σ
where σ=1/[1−rho]. By repeating this analysis, substituting for q 1
instead of for q 2
, we derive a similar expression for his optimal q 2
: (3.19) q 2
= p 1
1−σ
+p 2
1−σ
Yp 2
−σ
Thus, the utility-maximizing q 1
and q 2
are functions of his income and the prices.
The optimal values of \(q_1\) and \(q_2\) are determined by these equations, which are functions of Michael's income and the prices of the goods.
The given problem describes Michael's utility maximization problem with a constant elasticity of substitution (CES) utility function. The objective is to find the optimal values of \(q_1\) and \(q_2\) in terms of Michael's income (Y) and the prices of the two goods (\(p_1\) and \(p_2\)).
1. Substitute the income constraint into Michael's utility function:
\(U(q_1, q_2) = (q_1^\rho + q_2^\rho)^(1/\rho)\)
s.t. \(Y = p_1q_1 + p_2q_2\)
We can rewrite Michael's budget constraint as \(q_2 = (Y - p_1q_1)/p_2\). Substituting this expression into his utility function, we have:
\(U(q_1, p_2, Y) = (q_1^\rho + [p_2(Y - p_1q_1)/p_2]^\rho)^{(1/\rho)\)
By making this substitution, we have converted the constrained maximization problem with two control variables (\(q_1\) and \(q_2\)) into an unconstrained problem with one control variable \((q_1)\).
2. Use the standard unconstrained maximization approach to determine the optimal value for \(q_1\). To obtain the first-order condition, we differentiate the utility function with respect to \(q_1\) and set it equal to zero:
\(\delta U / \delta q_1 = \rho(q_1^{(\rho-1)} + \rho[p_2(Y - p_1q_1)/p_2]^{(\rho-1)}(-p_1/p_2)) = 0\)
Simplifying and solving for \(q_1\):
\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[p_2(Y - p_1q_1)/p_2]^{(\rho-1)} = 0\)
\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)} = 0\)
\(\rho q_1^{(\rho-1)} = \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)[Y - p_1q_1]^{(\rho-1)\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}[Y - p_1q_1]^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y - p_1q_1)^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y^{(\rho-1)} - (\rho-1)p_1q_1(Y - p_1q_1)^{(\rho-2)})\)
This equation represents Michael's optimal \(q_1\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).
3. Similarly, we can derive a similar expression for his optimal \(q_2\):
\(q_2^{(\rho-1)} = (p_2/p_1)^(1-\rho)(Y^{(\rho-1)} - (\rho-1)p_2q_2(Y - p_1q_2)^{(\rho-2)})\)
This equation represents Michael's optimal \(q_2\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).
Therefore, these equations, which depend on Michael's income and the prices of the commodities, determine the ideal values of \(q_1\) and \(q_2\).
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What is it called when particles in a solid or liquid move slower and closer together?
The reason at the time when particles in a solid or liquid move slower and closer together should be explained below.
What are particles?The particles should be in the form of small pieces of matters. Also, the scientist believed that each and everything in the universe should be made of the particles. here the range of the particles should be in the range via the large subatomic particles such as electrons or it has lower microscopic particles.
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Which atom is shown below
E. With proper reasoning choose the odd one out: 1. Push, pull, pressure, squeeze
Pressure is the odd one out among the four terms.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.
An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe forces.A push is a force applied away from the body, such as when kicking a football or striking a snooker ball.A pull is a force applied to the body, as in playing tug of war or drawing a bucket of water from a well.Meanwhile, the force applied perpendicularly to an object's surface is divided by the surface area over which it is applied is called pressure.
Thus, push, pull and squeeze are terms related to force, as when you perform any of the three actions you are applying some sort of force is applied.
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Unknown liquid can be found using a breaker a hot plate and a temperature probe
Immersion thermometers can be used to determine the temperature of liquids and viscoelastic materials. Observe the temperature at which the liquid begins to boiling.
To find an unknown liquid, you can use a beaker, a hot plate, and a temperature probe. First, fill the beaker with the unknown liquid. Then, place the beaker on the hot plate and turn it on to heat up the liquid. As the liquid heats up, use the temperature probe to measure the temperature. Once the liquid reaches a boiling point or a temperature that matches a known substance, you can identify the unknown liquid by comparing its boiling point or temperature to that of known substances. This method is often used in chemistry labs to identify unknown liquids.
Then, place the beaker onto the hot plate and turn it on to gradually heat the liquid. As the temperature increases, monitor it using the temperature probe.
The fast change from liquid to gaseous during boiling is characterised by the development of vapours (bubbles) inside the liquid. Similar to fusion, a given substance has a temperature (called the boiling point) at which it transforms from a liquid into a gaseous state. Boiling point is this temperature.
In the scenario described in the previous question, you must pour the liquid into the beaker and heat it on the hot plate. You will record the temperature at which the liquid began to boil using the temperature probe.
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The Complete question is
Unknown liquid can be found using a breaker a hot plate and a temperature probe and Which type of probe is best to measure the temperature of liquid?
Please urgent science question explaining needed
Answer:
what is the question? there isn't one
You have a balloon containing 1.4 L of gas in it at standard temperature and pressure. Which conversion factor would you use to convert this number to moles? 22.4L/1 mole 6.02 * 1023 L/1 mole 11/22.4 mole 1 mole/224L 11/6.02 x 1023 mole
You have a balloon containing 1.4 L of gas in it at standard temperature and pressure. the answer is option (e) \(1 L/6.02 \times 10^{23 }\) mole, since it represents the conversion factor from moles to the volume of one molecule of gas at STP.
To convert the given volume of gas (1.4 L) to moles, we need to use the ideal gas law equation, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
At standard temperature and pressure (STP), the temperature is 273 K and the pressure is 1 atm. Therefore, we have:
P = 1 atm
V = 1.4 L
n = ?
R = 0.0821 L*atm/mol*K
T = 273 K
Using the ideal gas law equation, we can solve for n:
n = PV/RT
\(n = (1 atm) \times (1.4 L) / (0.0821 L \times atm/mol \times K \times 273 K)\)
n = 0.0559 mol
Now, we need to choose the correct conversion factor to convert the calculated number of moles to the answer choices provided. Option (a) is the conversion factor for the volume of one mole of gas at STP, so it is not the correct choice.
Option (b) is Avogadro's number, which is the number of particles (molecules or atoms) in one mole of substance, so it is also not the correct choice. Option (c) is the reciprocal of the conversion factor in (a), so it is not the correct choice.
Option (d) is the reciprocal of the conversion factor in (a), but it is written in a different form, so it is also not the correct choice.
The correct conversion factor is option (e), which is the volume of one molecule of gas at STP. This option is obtained by rearranging the Avogadro's number and the volume of one mole of gas conversion factors:
\(1\; mole = 6.02 \times 10^{23}\; molecules\)
1 mole = 22.4 L (at STP)
\(1 \;molecule = 22.4 L / 6.02 \times 10^{23}\)
\(1\; molecule = 3.72 \times 10^{-23} L\)
Therefore, the answer is (e) \(1 L/6.02 \times 10^{23}\) mole, since it represents the conversion factor from moles to the volume of one molecule of gas at STP.
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Complete Question:
You have a balloon containing 1.4 L of gas in it at standard temperature and pressure. Which conversion factor would you use to convert this number to moles?
a. 22.4L/1 mole
b. 6.02 * 1023 L/1 mole
c. 1L/22.4 mole
d. 1 mole/224L
e. 1L/6.02 x 1023 mole
A car is traveling at 15. 5 m/s, and the driver sees a traffic light turn red. After 0. 321 s (the reaction time), the driver applies the brakes, and the car decelerates at 6. 2 m/s2. What is the stopping distance of the car, as measured from the point where the driver first sees the red light?
Stopping distance of the car, as measured from the point where the driver first sees the red light, is 43.95 meters We can use distance-time formula.
To calculate the stopping distance of the car, we need to determine the distance traveled during the driver's reaction time and the distance traveled while the car is decelerating.
During the driver's reaction time, the car will continue to move forward at its initial speed of 15.5 m/s. The distance traveled during this time is:
\(d_reaction = v_initial * t_reaction = 15.5 m/s * 0.321 s = 4.98 m\)
After the driver reacts, the car begins to decelerate at a rate of \(6.2 m/s^2\). Use equation:
d =\(v_initial * t + (1/2) * a * t^2\)
where d: distance traveled, v_initial: initial velocity, t: time, a: acceleration, and final velocity = 0 (since car stops).
We need to find the distance traveled during the deceleration period, so we can rearrange the equation to solve for d:
d = \((v_initial^2) / (2a)\)
Put values:
\(d_deceleration = (15.5 m/s)^2 / (2 * -6.2 m/s^2) = 38.97 m\)
Note that we used a negative value for acceleration, since the car is decelerating (slowing down) rather than accelerating (speeding up).
The total stopping distance is the sum of the distance traveled during the driver's reaction time and the distance traveled while decelerating:
\(d_total = d_reaction + d_deceleration = 4.98 m + 38.97 m = 43.95 m\)
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Which term best describes a soft drink?
a) heterogeneous mixture
b) pure substance
c) homogeneous mixture
d) compound
A soft drink is a homogeneous mixture.
All of the ingredients in a homogeneous mixture are dispersed equally, and in soft drinks, ingredients including sugar, carbon dioxide, and water combine to produce a single phase. A soft drink is therefore an uniform composition.
Mixtures are the combination of substances ?A mixture could be homogeneous or heterogeneous.
A mixture refers to a combination of two or more substances that are not chemically combined together. They may be solids, liquids or gases.
A mixture may be composed of substances in the same phase or different phases. If substances are combined in the same phase to form a mixture then the mixture is homogeneous. If substances in different phases combine to give a mixture then the mixture is heterogeneous.
Examples of homogeneous mixtures are salt and water solutions while examples of heterogeneous mixtures are sand and water as well as oil and water.
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When the absolute magnitudes, or brightnesses, of stars are plotted against their surface temperatures or colors, we obtain a(n)?
When the absolute magnitudes, or brightness's, of stars are plotted against their surface temperatures or colors, we obtain an H-R Diagram.
What is the use of a H-R Diagram?First it is important to note that the full meaning of H-R in this case is:
Hertzsprung-Russell.
The Hertzsprung-Russell Diagram is an instrument or device that is used for studying starts and other celestial bodies.
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How many force vectors would be shown on a free-body diagram of an elevator suspended by a cable descending at constant velocity.?
There would be a total of 2 force vectors on a free-body diagram of an elevator suspended by a cable descending at constant velocity.
What is a free-body diagram?FBDs are valuable tools for describing the relative magnitude and direction of all forces operating on an object in a given condition. The meticulous drafting of a free-body diagram is the initial step in evaluating and describing most physical processes. In a free-body diagram, the size of the arrow denotes the magnitude of the force while the direction of the arrow denotes the direction in which the force acts.
A free-body diagram often includes the following elements:
A streamlined form of the body (most commonly a box)A system of coordinatesForces are depicted as arrows indicating the direction in which they act on the body.Moments are depicted as curving arrows pointing in the direction in which they affect the body.The quantity of forces acting on a body is determined by the nature of the problem and the assumptions made. Air resistance and friction are frequently overlooked.
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A bowling ball with a mass of 9 kg is moving at a speed of 4 m/s. What is its
kinetic energy?
O A. 144 J
O B. 72J
O C. 18J
O D. 36 J
Help please!!
Dogs are able to hear much higher frequencies then humans are capable of detecting. For this reason the crystals that are inaudible to the human ear can be heard easily by a dog. If a dog whistle has a frequency of 3.0 x 10^4 Hz, what is the wavelength of the sound emitted?
Answer:
Dogs are able to hear much higher frequencies than humans are capable of detecting. For this reason, dog whistles that are inaudible to the human ear can be heard easily by a dog. If a dog whistle has a frequency of 30,000 Hz, what is the wavelength of the sound emitted?
What is called gravitational potential energy?
Answer:
Potential gravitational energy is the energy that the body has due to the Earth's gravitational attraction. In this way, the potential gravitational energy depends on the position of the body in relation to a reference level.
Explanation:
A + 9.4 nC point charge and a - 2.31 nC point charge are 4.94 cm apart. What is the electric field strength at the midpoint between the two charges?
Given:
The charge is q1 = 9.4 nC
The charge q2 = -2.31 nC
The distance between them is r = 4.94 cm
To find the electric field strength at the midpoint between two charges.
Explanation:
The electric field strength at the midpoint will be the sum of electric field strength due to q1 and q2.
The electric field strength can be calculated by the formula
\(E=\frac{kq}{r^2}\)Here, k is the electrostatic constant whose value is
\(k=9\times10^9\text{ N m}^2\text{ /C}^2\)The electric field strength due to the charge q1 is
\(\begin{gathered} E_1=\frac{kq1}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times9.4\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =1.39\times10^5\text{ V/m} \end{gathered}\)The electric field strength due to the charge q2 is
\(\begin{gathered} E_2=\frac{kq2}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times2.31\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =3.4\times10^4\text{ V/m} \end{gathered}\)The electric field strength at the midpoint will be
\(\begin{gathered} E=E_1+E_2 \\ =(1.39\times10^5)+(3.4\times10^4) \\ =173000\text{ V/m} \end{gathered}\)Thus, the electric field strength at the midpoint between the two charges is 173000 V/m
1. A wave can be described as (2 points)
Answer:
Well,
Explanation:
In a wave, energy is transported without the transport of water. Basically, a wave can be described as a disturbance that travels through a medium, transporting energy from one location to another location without transporting matter.
A spherical drop of water carrying a charge of 41pC has a potential of 570 V at its surface (with V=0 at infinity). (a) What is the radius of the drop? (b) If two such drops of the same charge and radius combine to form a single spherical drop, what is the potential at the surface of the new drop? (a) Number Units (b) Number Units
A spherical drop of water carrying a charge of 41pC has a potential of 570 V at its surface (with V=0 at infinity) (a) The radius of the drop is approximately 5.88 micrometers (μm).
(b) The potential at the surface of the new drop formed by combining two drops of the same charge and radius is approximately 1140 V.
(a) To find the radius of the drop, we can use the formula for the potential of a charged sphere, which is given by V = (k * Q) / r, where V is the potential, k is the electrostatic constant, Q is the charge, and r is the radius of the sphere. Rearranging the formula to solve for the radius, we have r = (k * Q) / V. Plugging in the given values of Q = 41 pC (pico coulombs) and V = 570 V, and using the value of k = 8.99 × 10^9 Nm^2/C^2, we can calculate the radius to be approximately 5.88 μm.
(b) When two drops combine to form a single spherical drop, the total charge remains the same. Therefore, the potential at the surface of the new drop can be calculated using the same formula as before, but with the combined charge. Since each drop has the same charge and radius, the combined charge will be 2 times the original charge. Plugging in Q = 82 pC (2 * 41 pC) and using the given value of V = 570 V, we can calculate the potential at the surface of the new drop to be approximately 1140 V.
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Answer: c because our solar system is called the milky way
Explanation:
As the sun sets on horizon, its rays are____ by the ocean water
Answer:
Reflected
Explanation:
I do not have much context here, but reflection is what happens when the sun sets on the water. The rays hit the surface of the water and bounce off, known as refelction.
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An electric iron of resistance 20Ω takes a current of 5A. Calculate the heat developed in 30seconds?
The amount of heat (H) produced is given by the joule’s law of heating as H= Vlt
Where,
Current, I = 5 A
Time, t = 30 s
Voltage, V = Current x Resistance = 5 x 20 = 100V
H= 100 x 5 x 30 = 1.5 x 10⁴ J.
Therefore, the amount of heat developed in the electric iron is 1.5 x 10⁴J.
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