help me with this i tried it 4 times

Recall that

sin²(θ) + cos²(θ) = 1

for all θ, and given that cos(θ) < 0, we find that

cos(θ) = -√(1 - sin²(θ)) = -√(1 - (2/5)²) = -√(21)/5

Now,

csc(θ) = 1/sin(θ) = 1/(2/5) = 5/2

and

cot(θ) = cos(θ)/sin(θ) = (-√(21)/5)/(2/5) = -√(21)/2

Answer: fourth choice

Step-by-step explanation:

Answer:

formula for circle is

(x-h)^2+(y-k)^2=r^2

so the answer is sixth

Answer:

\(-4\)

Step-by-step explanation:

\(8-2 \times 6\)

Multiplication comes first.

\(8-12\)

Subtract.

\(=-4\)

Answer:

8-2 x 6= -4

Step-by-step explanation:

2 x 6= 12

8 - 12 = -4

PEMDAS: in this equation, you should multiply first then subtract.. hope this helps!

Answer:

7x + 14

Step-by-step explanation:

Answer:

Step-by-step explanation:

7(x + 2)

Answer: 11

Step-by-step explanation:

9(2) - 4 - 5(2) + 7
18 - 4 - 10 + 7
14 - 10 + 7
4 + 7
11

The sum of the first 20 terms of the Arithmetic sequence is 1490

The first is 27

The common difference is 5

n= 20

The first 20 terms can be calculated as follows

Sn= n/2[2a+(n-1) d]

S20= 20/2(2×27 + (20-1) 5

S20= 10(54 + 95)

S20= 10(149)

S20= 1,490

Hence the sum of the first 20 terms is 1490

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We are given the radius of the scoop and asked to find the volume of ice cream in one scoop. By using the formula for the volume of a sphere and substituting the given radius, we can calculate the volume. The final answer is approximately 33.49 cubic inches.

a) The problem asks for the volume of ice cream in one scoop.

b) The given fact is that the radius of the scoop is 2 inches.

c) The formula to be used is the volume of a sphere, which is given by V = (4/3)πr³, where V is the volume and r is the radius.

d) Number Sentence:

  - Given: Radius (r) = 2 inches

  - Formula: V = (4/3)πr³

  - Substituting the value: V = (4/3)π(2)³

  - Simplifying: V = (4/3)π(8)

  - Evaluating: V = (4/3)(3.14)(8)

  - Multiplying: V = 33.49333333 (approx.)

e) Final answer: The volume of ice cream in one scoop is approximately 33.49 cubic inches.

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Answer:

D. An angle measuring 285 degrees

Step-by-step explanation:

An angle that is coterminal is congruent to the other angle whether negative or positive or more than 360.

An angle that is 645 degrees can be broken down into 360 + 285.

Since 360 is one revolution the angle would finish with 285 degrees.

Therefore the coterminal angle to 645 is 285.

Answer:144

Step-by-step explanation:

Use a calculator

or 1/2 x 288 =  288/2 = 144

Answer: 144

Step-by-step explanation:

I'm assuming that the "x" in this statement is a multiplication symbol.

Multiplying any number by 1/2 or 0.5 is the same thing as dividing it by 2.

Therfore the answer is 288/2 which is 144.

Answer:

15.30

Step-by-step explanation:

use code tiko

Answer:

ayo what

Step-by-step explanation:

Step-by-step explanation:

it is totally simple : you need to put the x-value into every place of the x-variable, and then we calculate.

and then the same for the next x-value. and the next. ...

-2

-2×-2 + 9 = 4 + 9 = 13

0

-2×0 + 9 = 0 + 9 = 9

2

-2×2 + 9 = -4 + 9 = 5

4

-2×4 + 9 = -8 + 9 = 1

Answer:

A=3

B=4

C=81

Step-by-step explanation:

Just did it

Answer:

a =

✔ 3

b =

✔ 4

c =

✔ 81

Each side of the square would have to be 6 cm to have an area of 36 cm^2.  However, as a side can never be 0, and you never gave a starting size for the square, the question is unanswerable.

Answer:

NO

Step-by-step explanation:

NO

Answer:

126

Step-by-step explanation:

Let the no. of hamburger be n

Then the no. of cheeseburgers = 3n

3n + n = 504

4n = 504

n = 504 / 4

n = 126

The vertex of the graph is a maximum at (-2, 4)

From the question, we have the following parameters that can be used in our computation:

The graph

The graph is a quadratic function

From the graph, we can see that the graph has a maximum value

This maximum value represents the vertex of the graph

And it is located at (-2, 4)

So, we have

Maximum = (-2, 4)

Hence, the maximum value of the function is (-2, 4)

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Answer:

2/12 or 1/6

Step-by-step explanation:

Make common denominators, 3/4 turns into 9/12. Take away 9/12 from 11/12, simplify if needed, and boom! done!

Recalling that SAT scores are always expressed as multiples of 10, then the points we get on the test will be 628.

In statistics, Standard deviation is a measure of the variation of a set of values.

σ = standard deviation of population

N = number of observation of population

X = mean

μ = population mean

WE have been given that SAT scores are normally distributed, with a mean of 500 points and a standard deviation of 100 points.

The solution as follows;

Let be X: scores of SAT

P(X ≥ x) = 0.9

P((X - 500)/100 ≥ (x - 500)/100) = 0.9

P(Z ≥ z) = 0.9

z = 1.28

1.28 = (x - 500)/100

128 + 500 = x

x = 628

Recalling that SAT scores are always expressed as multiples of 10, then the points we get on the test will be 628.

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The simplification of the expressions in the question using the rules of indices are as follows;

1.) 6·e⁰ + (11·f)⁰ - 5/g⁰ = 2

2. (3⁻⁴ + 5⁻³)⁻¹ = \(49\frac{31}{206}\)

3. (3⁻⁴ + 5⁻³)⁻² = \(2415\frac{32685}{42436}\)

4.) \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{10\cdot c^{-5} \cdot d^6 \cdot e^{-8}}\) = \(\dfrac{c^5\cdot e^8}{2\cdot d^5}\)

5.)  \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5}\right)^{-3 }}{7\cdot \left(p^{-6} \cdot q^8\right)^{-4}} =\dfrac{-5\cdot m^{12}\cdot n^{15}\cdot q^{32}}{7\cdot p^{24}}\)

An index or indices is the power by which a number or variable or expression raised.

1.) 6·e⁰ + (11·f)⁰ - 5/g⁰

6·e⁰ + (11·f)⁰ - 5/g⁰ = 6 × 1 + 1 - 5/1

6 × 1 + 1 - 5/1 = 6 + 1 - 5 = 2

Therefore;

6·e⁰ + (11·f)⁰ - 5/g⁰ = 2

2.) (3⁻⁴ + 5⁻³)⁻¹

(3⁻⁴ + 5⁻³)⁻¹ = (1/(3⁴) + 1/(5³))⁻¹ = 1/(1/(3⁴) + 1/(5³))

1/(1/(3⁴) + 1/(5³)) = 1/(1/81 + 1/125) = 1/((125 + 81)/(81×125))

1/((125 + 81)/(81×125)) = (81 × 125)/(125+81) = 10125/209

10125/206 = 49 + 31/206

(3⁻⁴ + 5⁻³)⁻¹ = \(49 \frac{31}{206}\)

3.) (3⁻⁴ + 5⁻³)⁻²

(3⁻⁴ + 5⁻³)⁻² = 1/((1/3⁴ + 1/5³)²)

1/((1/3⁴ + 1/5³)²) = 1/((1/81 + 1/125)²)

1/((1/81 + 1/125)²) = 1/(((125 + 81)/(81 × 125))²)

1/(((125 + 81)/(81 × 125))²) = 1/((206/10125)²)

1/((206/10125)²) = (10125)²/(206)² = 102515625/42436

102515625/42436 = 2415 32685/42436

(3⁻⁴ + 5⁻³)⁻² = \(2415\frac{32685}{42436}\)

4.)  \(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}}\)

\(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}} = \dfrac{5\times 1}{10\times \left(\frac{1}{c^5}\times d^6 \times \frac{1}{e^8} \right) }\)

\(\dfrac{5\times 1}{10\times \left(\frac{1}{c^5}\times d^6 \times \frac{1}{e^8} \right) } = \dfrac{5}{10\times \left(\frac{d^6}{c^5\times e^8} \right) }\)

\(\dfrac{5}{10\times \left(\frac{d^6}{c^5\times e^8} \right) } = \dfrac{1}{2\times \left(\frac{d^6}{c^5\times e^8} \right) }\)

\(\dfrac{1}{2\times \left(\frac{d^6}{c^5\times e^8} \right) } = \dfrac{c^5\times e^8}{2\cdot d^6}\)

\(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}}= \dfrac{c^5\times e^8}{2\cdot d^6}\)

5.) \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\rright)^{-4}}\)

\(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\right)^{-4}} =\dfrac{-5\cdot \dfrac{1}{\left(\frac{1}{m^{4}}\times \frac{1}{n^{5}} \right)^{3}} }{7\cdot \dfrac{1}{\left(\frac{1}{p^{6}}\times q^8\right)^{4}} }\)

\(\dfrac{-5\cdot \dfrac{1}{\left(\frac{1}{m^{4}}\times \frac{1}{n^{5}} \right)^{3}} }{7\cdot \dfrac{1}{\left(\frac{1}{p^{6}}\times q^8\right)^{4}} } = \dfrac{-5\cdot {\left(m^4\times n^5\right)^3} }{7\cdot \left( \dfrac{p^6}{q^8\right)^{4}} }\)

\(\dfrac{-5\cdot {\left(m^4\times n^5\right)^3} }{7\cdot \left( \dfrac{p^6}{q^8\right)^{4}} } = \dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^8}{p^6}\right)^4 }\)

\(\dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^8}{p^6}\right)^4 } = \dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^{32}}{p^{24}}\right) }\)

\(\dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^{32}}{p^{24}}\right) } = \dfrac{-5\times {m^{12}\times n^{15}\times q^{32}} }{7\times p^{24}}\)

\(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\right)^{-4}} = \dfrac{-5\times {m^{12}\times n^{15}\times q^{32}} }{7\times p^{24}}\)

6.) (3·x⁻⁴·y⁻⁵·z⁻²)⁻²

(3·x⁻⁴·y⁻⁵·z⁻²)⁻² = \(3\cdot \left(\dfrac{1}{\left(\dfrac{1}{x^4} \cdot \dfrac{1}{y^5} \cdot \dfrac{1}{z^2} } \right)^2\right)\)

\(3\cdot \left(\dfrac{1}{\left(\dfrac{1}{x^4} \cdot \dfrac{1}{y^5} \cdot \dfrac{1}{z^2} } \right)^2\right) = 3\cdot \left(x^4\cdot y^5\cdot x^2\right)^2\)

3·(x⁴·y⁵·x²)² = 3·x⁸·y¹⁰·x⁴

Therefore;

(3·x⁻⁴·y⁻⁵·z⁻²)⁻² = 3·x⁸·y¹⁰·x⁴

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Answer: 9x^2+15x-6

Step-by-step explanation: I did my test an it said this was right (Plato )

The solution of the function is 9x² + 15x -6. The correct option is C.

The expression that established the relationship between the dependent variable and independent variable is referred to as a function. In the function as the value of the independent variable varies the value of the dependent variable also varies.

Given function is F(x) = x² + 7x and g(x) = 3x - 1. The value of the function  (fg)(x) will be calculated as,

(fg)(x) =  x² + 7x

(fg)(x) = ( 3x - 1)² + 7(3x - 1)

(fg)(x) = 9x² -6x + 1 + 21x - 7

(fg)(x) = 9x² + 15x - 6

Therefore, the solution of the function is 9x² + 15x -6. The correct option is C.

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The solution set includes all real numbers less than -5, and all real numbers greater than 1, but does not include -5 or 1 themselves.

Option D is the correct answer.

We have,

We need to isolate the absolute value |x + 2| on one side of the inequality.

We subtract 7 from both sides.

|x + 2| > 3

Next, we can split this inequality into two separate inequalities, one for when the expression inside the absolute value is positive, and one for when it is negative:

x + 2 > 3

or

- (x + 2) > 3

Solving for x in the first inequality.

x > 1

Solving for x in the second inequality.

-x - 2 > 3

Adding 2 to both sides and multiplying by -1.

x < -5

So the solution set for the inequality |x + 2| + 7 > 10 is the set of all x-values that satisfy either x > 1 or x < -5.

Using interval notation.

(-∞, -5) U (1, ∞)

Thus,

The solution set includes all real numbers less than -5, and all real numbers greater than 1, but does not include -5 or 1 themselves.

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Answer:

D. It would be less steep

Step-by-step explanation:

The first graph moves at a rate of 5/1 which is a greater fraction than 3/4

Answer:

D

Step-by-step explanation:

Answer:

Mode 4

Step-by-step explanation:

Mean x¯¯¯ 4.3333333333333

Median x˜ 4

Mode 4

Range 7

Minimum 2

Maximum 9

Count n 6

Sum 26

Quartiles Quartiles:

Q1 --> 3

Q2 --> 4

Q3 --> 4

Answer:

The area of the triangle is 24 \(\text{cm}^{2}\).

Step-by-step explanation:

We are given that the length of the base of a right-angle triangle ABC is 6 cm and the length of the hypotenuse is 10 cm.

And we have to find the area of the triangle.

As we know that the area of the triangle is given by the following formula;

Area of the triangle =  \(\frac{1}{2}\times \text{Base} \times \text{Height}\)

Firstly, we will find the height (perpendicular) of the triangle ABC bu using the Pythagoras Theorem.

\(\text{Hypotenuse}^{2} =\text{Perpendicular}^{2} +\text{Base}^{2}\)

\(\text{10}^{2} =\text{Perpendicular}^{2} +\text{6}^{2}\)

\(100=\text{Perpendicular}^{2} +36\)

\(\text{Perpendicular}^{2} =100-36\)

\(\text{Perpendicular}^{2} =64\)

\(\text{Perpendicular} =\sqrt{64}\)  = 8 cm.

Now, the area of the triangle =  \(\frac{1}{2}\times \text{Base} \times \text{Height}\)

                                                =  \(\frac{1}{2}\times \text{6} \times \text{8}\)

                                                =  24 \(\text{cm}^{2}\)

Hence, the area of the triangle is 24 \(\text{cm}^{2}\).

The proportion of Arts majors who have not found a job is 8%, rounded off to two decimal places.

To find the proportion of Arts majors who have not found a job, we first need to calculate the total number of students who have not found a job.

The total number of students who have not found a job would be 1500 - 1380 = 120.

To calculate the proportion of students who have not found a job, we can divide the number of students who have not found a job by the total sample size:

The proportion of students who have not found a job = 120 / 1500 = 0.08 or 8%.

Therefore, the proportion of Arts majors who have not found a job is 8%, rounded off to two decimal places. This suggests that a majority of the graduating Arts majors from the University of Western Cape have found employment before their graduation.

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The function g(x) in the form a(x-h)^2 + k is: \(g(x) = (x + 2)^2 - 4\)

Starting with\(f(x) = x^2\), the translation 2 units left and 4 units down would result in the following transformation:

g(x) = f(x + 2) - 4

Substituting\(f(x) = x^2:\)

\(g(x) = (x + 2)^2 - 4\)

Expanding the square:

\(g(x) = x^2 + 4x + 4 - 4\)

Simplifying:

\(g(x) = x^2 + 4x\)

Now we need to rewrite this expression in the form \(a(x-h)^2 + k.\) To do this, we will complete the square:

\(g(x) = x^2 + 4x\\g(x) = (x^2 + 4x + 4) - 4\\g(x) = (x + 2)^2 - 4\)

Therefore, the function g(x) in the form a(x-h)^2 + k is:

\(g(x) = (x + 2)^2 - 4\)

Where a = 1, h = -2, and k = -4.

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Answer:

D=8

Step-by-step explanation:

Answer:

1/2x

Step-by-step explanation:

Answer:

---------------------------------------------------

Let the numbers be x and y, where x is greater and y is lesser.

Given that x = 2y.

Find y: