Is the solution shown below correct? Explain.
9x+2=8x2+6x
Negative 8 x squared + 3 x + 2 = 0. x = StartFraction negative 3 plus-or-minus StartRoot (3) squared minus (4) (negative 8) (2) EndRoot Over negative 16 EndFraction. x = StartFraction negative 3 plus-or-minus StartRoot 9 minus (64) EndRoot Over negative 16 EndFraction. x = StartFraction 3 plus-or-minus StartRoot 55 Endroot i Over 16 EndFraction.
Answer:
It is wrong
Step-by-step explanation:
What we have is as follows;
9x + 2 = 8x^2 + 6x
Bringing 9x + 2 yo the right hand side, we have;
8x^2 + 6x -9x -2 = 0
8x^2 -3x -2 = 0
So what is used here is the quadratic formula and we want to try to see if it was used correctly.
The form we have in the question is however;
-8x^2+ 3x + 2 = 0
which is obtained by taking the right hand side of the equation to the left
Now;
using the quadratic formula;
x = -b ± √(b^2 -4ac)/2a
where a is -8
b = 3
c = 2
Thus we have
-3 ± √(9 - 4(-8)2)/2(-8)
-3 ± √(9 + 64)/(-16)
So where is wrong is in the square root
what we are supposed to have is 9 + 64 = 73 and not otherwise
Answer:
Step-by-step explanation:
No. The correct values of a, b, and c were substituted in, but the formula was simplified wrong. The 64 should be added so the radicand is 73. There should be 2 real roots.
Help needed ASAP will give BRAINLIEST
Answer:
1) I believe the answer is D
Explanation: The square root of 7 is approximately 2.64 which then gets divided by 3 which results in approximately 0.88, then you have to factor in that the problem has only one negative sign; therefore, the answer should be Point D.
Step-by-step explanation:
For the second one turn them into decimals
5/8 = 0.625
2√5 = 4.472
-pi/3 = -1.047
Then rearrange them 2√5, 5/8, -pi/3
The abominable snowman is trying to
give lemon snow cones to Mike. He has
six snow cones. He already has eaten
1/3 of the snow cones. How many snow
cones are left?
Using the given fractions if the abominable snowman has six snow cones and has already eaten 1/3 of them, there are four snow cones left for him to give to Mike.
To solve this problem, we need to subtract the number of snow cones that the abominable snowman has already eaten from the total number of snow cones that he started with.
If the abominable snowman started with six snow cones and already ate 1/3 of them, then we need to find 1/3 of 6 to determine how many snow cones he has already eaten:
1/3 x 6 = 2
So, the abominable snowman has already eaten two snow cones.
To find out how many snow cones are left, we subtract 2 from the total number of snow cones:
6 - 2 = 4
Therefore, there are four snow cones left that the abominable snowman can give to Mike.
In summary, if the abominable snowman has six snow cones and has already eaten 1/3 of them, there are four snow cones left for him to give to Mike.
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the body mass of a man is xkg.thebody mass of his two children are five-sixth and four_fifths of their father5 x over 6 + 4 x over 5 5 x over 6 + 4 x over 5
56/120
Step-by-step explanation:
The body masses of the two children in terms of their father's body mass, x, are:
First child's body mass = 5x/6 kg
Second child's body mass = 4x/5 kg
To express the body mass of the man's two children in terms of their father's body mass, we can use the given ratios.
Let the body mass of the man be x kg.
The first child's body mass is five-sixths of their father's body mass:
Body mass of the first child = (5/6) * x
= 5x/6 kg.
The second child's body mass is four-fifths of their father's body mass:
Body mass of the second child = (4/5) * x
= 4x/5 kg.
Therefore, the body masses of the two children in terms of their father's body mass, x, are:
First child's body mass = 5x/6 kg
Second child's body mass = 4x/5 kg
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Cho M (1, -2), N (3, -4), cho biết M là ảnh của N qua phép tịnh tiến ve tơ u.
Answer:
u(-2;2)
Step-by-step explanation:
What is the slope of the line that passes through the point (8, - 4) and (6, 2) ? Write your answer in simplest form.
Answer:
y= -3x + 20
Step-by-step explanation:
just graph it out
The area of a door is 3024 square inches. If
the length of the door is 48 inches longer
than the width of the door, what is the
width of the door?
A: Translate the problem into an equation.
B: Solve
Answer:
Lets take all factors into consideration first
The door is a rectangle and the area of a rectangle is length times width
Let the width be w
Let the length be l
Equation length × breadth = area
(w+48)w = 3024
w^2 + 48w = 3024
w^2 + 48w - 3024 = 0
w^2 + 84w - 36w - 3024 = 0
w(w + 84) -36 ( w + 84) = 0
(w + 84) (w - 36) = 0
w + 84 = 0 AND w - 36 =0
w = -84 and w = 36
Since width cannot be negative, the right answer is 36
How did I get 84 and 36? Well, I had to factorize 3024 and since 84 times 36 is 3024 and 84 minus 36 is 48, I chose them.
TRUE / FALSE. roofs having a span of 40 feet or less and a pitch of ? or greater, and roofs having a span of more than 40 feet and a pitch of 1/4 or greater are considered to be pitched.
The statement is true. Roofs with a span of 40 feet or less and a pitch of ? or greater, as well as roofs with a span of more than 40 feet and a pitch of 1/4 or greater, are considered to be pitched.
In roofing terminology, the pitch refers to the steepness or slope of a roof. A pitched roof has a slope that allows water to drain efficiently. The pitch is typically measured as a ratio of vertical rise to horizontal span.
According to the statement, roofs with a span of 40 feet or less and a pitch of ? (undefined or not specified) or greater are considered to be pitched. This means that as long as the roof has a certain degree of slope or steepness, it is categorized as a pitched roof.
Similarly, roofs with a span of more than 40 feet and a pitch of 1/4 or greater are also considered to be pitched. In this case, the requirement for a minimum pitch of 1/4 (or a steeper slope) applies to roofs with a larger span.
The classification of roofs as pitched or not pitched depends on their span and the minimum pitch requirements specified. Roofs that meet the specified criteria for span and pitch are considered to be pitched roofs.
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How do you know if triangles are congruent in SAS?
With the help of the figure we can say that triangles are congruent by SAS Rule
What is Congruence of Triangle?
Triangle congruence: Two triangles are said to be congruent if all three of their corresponding sides are equal and all three of their corresponding angles are equal in size. These triangles can be moved, rotated, flipped, and turned to look exactly the same.
Solution:
By SAS rule, two triangles are said to be congruent if any two sides and the angle included between the sides of one triangle are comparable to the corresponding two sides and the angle included between the sides of the second triangle.
In given figure, sides AB= PQ, BC=QR and angle between AB and BC equal to angle between PQ and QR i.e. ∠B = ∠Q. Hence, Δ ABC ≅ Δ PQR.
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Find the slope of the line below.
Answer:
The slope is 1/3
Ella and Iris are planning trips to nine countries this year. There are 12 countries they would like to visit. They are deciding which countries to skip, how many ways are there?
Using the combination formula, it is found that there are 220 ways to decide which countries to skip.
The order in which the countries are skipped is not important, hence the combination formula is used to solve this question.
What is the combination formula?\(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by:
\(C_{n,x} = \frac{n!}{x!(n-x)!}\)
In this problem, 3 countries are skipped from a set of 12, hence the number of ways is given by:
\(C_{12,3} = \frac{12!}{3!9!} = 220\)
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Given f(x)= raiz 6x and g(x)= 1/x-6 Which value is in the domain of f g
The domain of the composition function fog(x) when f(x)= √6x and g(x)= 1/ (x-6) is equal to (-∞, 6) U (6, ∞).
Function f(x) = √6x
And g(x)= 1/ (x-6
Composition function fog is ,
fog(x) = f(g(x))
Domain of fog(x),
First, find the domain of g(x),
Here,
g(x) = 1/(x-6)
The denominator of g(x) cannot be equal to zero,
So we must exclude x = 6 from the domain of g(x).
The domain of g(x) is equal to ,
domain of g(x) = {x | x ≠ 6}
The range of g(x) is,
As x approaches 6 from the left, g(x) approaches negative infinity,
And as x approaches 6 from the right, g(x) approaches positive infinity.
Range of g(x) = (-∞, 0) U (0, ∞)
Now, the domain of fog(x),
fog(x)
= f(g(x))
= √6g(x)
=√ 6 (1 /(x - 6 ) )
Square root sign must be non-negative.
Since the range of g(x) does not include zero,
Exclude the part of the range that is less than zero.
The domain of fog(x) is,
domain of fog(x)
= {x | g(x) > 0}
= {x | x < 6} U {x | x > 6}
The domain of fog(x) consists of all real numbers except x = 6.
Therefore, the domain of fog(x) is (-∞, 6) U (6, ∞).
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The above question is incomplete, the complete question is :
Given f(x)= √6x and g(x)= 1/ (x-6) Which value is in the domain of fog.
pls help ill give 15 brainliest and 5 starts question is down below
Answer:
1 is 9 sq units
2 is 12
3 is 24cm^2
Step-by-step explanation:
Solve the following question:
Answer:
x = 2, x = 8
Step-by-step explanation:
reminder that f'(x) = \(m_{tangent}\)
Differentiate f(x) term by term using the power rule
\(\frac{d}{dx}\) (a\(x^{n}\) ) = na\(x^{n-1}\)
f(x) = \(\frac{1}{3}\) x³ - 5x² + 2x + 10
f'(x) = x² - 10x + 2
Equating f'(x) to - 14
x² - 10x + 2 = - 14 ( add 14 to both sides )
x² - 10x + 16 = 0 ← in standard form
(x - 2)(x - 8) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x - 8 = 0 ⇒ x = 8
AB =
Round your answer to the nearest hundredth.
С
4
A
25°
?
В
Answer:
Question not properly explained
please help and give answers order according to the sheet
0² = 0 ( zero to the power of any no. equals to zero )
0-² = 1/0² = 1/0 ( numerator can't be zero , it's undefined )
0⁰ is undefined
Skills
a) P² × P⁵ = P⁷
b)P¹²÷P⁴ = P³
c) (P³)⁷ = P²¹
d) P⁰× q³ = 1 × q³ = q³
e) 3P⁴×5P² = 15P⁶
f) 6Pq³×2P⁹q² = 12P¹⁰q⁵
g)P⁷/P² = P⁵
h)8P¹¹/2P⁹ = 4P²
i) (2P⁴)³=2³×P¹² = 8P¹²
j) (8q²×3q⁷)/6q⁸ = 24q⁹/6q⁸ = 4q
Stretch
a) 2²⁰÷4¹⁰= 1048576÷1048576 = 1
b) (2⁶)²÷4⁵ = 2¹²÷4⁵ = 4096 ÷ 1024 = 4
c) 3⁷ ÷ 9³ = 2187 ÷ 729 = 3
d) 27⁵ ÷ 3¹² = 14348907 ÷ 531441 = 27
Please give brainliest
\(\textsf {Skills :}\)
\(\mathsf {a) p^{2} \times p^{5} = p^{7}}\)
\(\mathsf {b) p^{12} \div p^{4} = p^{8}}\)
\(\mathsf {c) (p^{3})^{7} = p^{21}}\)
\(\mathsf {d) p^{0} \times q^{3} = q^{3}}\)
\(\mathsf {e) 3p^{4} \times 5p^{2} = 15p^{6}}\)
\(\mathsf {f) 6pq^{3} \times 2p^{9}q^{2} = 12p^{10}q^{5}}\)
\(\mathsf {g)\frac{p^{7}}{p^{2}} = p^{5}}\)
\(\mathsf {h) \frac{8p^{11}}{2p^{9}}=4p^{2}}\)
\(\mathsf {i) (2p^{4})^{3} = 8p^{12}}\)
\(\mathsf {j) \frac{8q^{2} \times 3q^{7}}{6q^{8}} = 4q}\)
\(\textsf {Stretch :}\)
\(\mathsf {a) 2^{20} \div 4^{10} = 2^{20} \div 2^{20} = 1}\)
\(\mathsf {b) (2^{6})^{2} \div 4^{5} = 2^{12} \div 2^{10} = 2^{2} = 4}\)
\(\mathsf {c) 3^{7} \div 9^{3} = 3^{7} \div 3^{6} = 3}\)
\(\mathsf {d) 27^{5} \div 3^{12} = 3^{15} \div 3^{12} = 3^{3} = 27}\)
an insurance company checks police records on 582 accidents selected at random and notes that teenagers were at the wheel in 91 of them. (a) (8 pts) find the 95% confidence interval for , the true proportion of all auto accidents that involve teenage drivers. (note: for full credit, show all your work. no credit
The 95% confidence interval for the true proportion of all auto accidents involving teenage drivers is approximately (0.1205, 0.1927).
To find the 95% confidence interval for the true proportion of all auto accidents involving teenage drivers, we can use the formula for the confidence interval for a proportion.
The formula for the confidence interval is:
CI = p1 ± Z * √((p1 * (1 - p1)) / n)
Where:
CI is the confidence interval,
p1 is the sample proportion (proportion of accidents involving teenage drivers),
Z is the Z-score corresponding to the desired confidence level (95% confidence level corresponds to Z ≈ 1.96),
n is the sample size (number of accidents checked).
Given:
Number of accidents checked (sample size), n = 582
Number of accidents involving teenage drivers, x = 91
First, we calculate the sample proportion:
p1 = x / n = 91 / 582 ≈ 0.1566
Now we can calculate the confidence interval:
CI = 0.1566 ± 1.96 * √((0.1566 * (1 - 0.1566)) / 582)
Calculating the standard error of the proportion:
SE = √((p1 * (1 - p1)) / n) = √((0.1566 * (1 - 0.1566)) / 582) ≈ 0.0184
Substituting the values into the formula:
CI = 0.1566 ± 1.96 * 0.0184
Calculating the values:
CI = 0.1566 ± 0.0361
Finally, we can simplify the confidence interval:
CI = (0.1205, 0.1927)
Therefore, the 95% confidence interval for the true proportion of all auto accidents involving teenage drivers is approximately (0.1205, 0.1927).
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factorise: 8m-2+4mn-n
Answer:
(4m - 1) × (2n + n)
Step-by-step explanation:
8m - 2 + 4mn - n
2(4m - 1) + 4mn - n
2(4m - 1) + n × (4m - 1)
= (4m - 1) × (2n + n)
The answer is (4m - 1) × (2n + n)
How to factorize?The simplest way of factorizing is:
Find the highest common factor of each of the terms in the expression.Write the highest common factor (HCF) in front of any brackets.Fill in each term in the brackets by multiplying out.Factorise: 8m-2+4mn-n
⇒ 8m - 2 + 4mn - n
⇒ 2(4m - 1) + 4mn - n
⇒ 2(4m - 1) + n × (4m - 1)
⇒ (4m - 1) × (2n + n)
Factorising is a way of writing an expression as a product of its factors using brackets.
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find the slope between the given two points
Slope can be found using the following equation:
slope (m) = \(\frac{y_2 - y_1}{x_2 - x_1}\)
7) Let:
\((x_1 , y_1) = (-1 , -11)\\(x_2 , y_2) = (-6 , -7)\)
Plug in the corresponding numbers to the corresponding variables:
m = \(\frac{-7 - (-11)}{-6 - (-1)} = \frac{-7 + 11}{-6 + 1} = \frac{4}{-5} = -\frac{4}{5}\)
Slope: \(-\frac{4}{5}\)
8) Let:
\((x_1 , y_1) = (-7 , -13)\\(x_2 , y_2) = (1 , -5)\)
Plug in the corresponding numbers to the corresponding variables:
m = \(\frac{-5 - (-13)}{1 - (-7)} = \frac{-5 + 13}{1 + 7} = \frac{8}{8} = 1\)
Slope: \(1\)
9) Let:
\((x_1 , y_1) = (-5 , 3)\\(x_2 , y_2) = (8 , 3)\)
Plug in the corresponding numbers to the corresponding variables:
m = \(\frac{3 - (3)}{8 - (-5)} = \frac{0}{8 + 5} = \frac{0}{13} = 0\)
Slope: \(0\)
10) Let:
\((x_1 , y_1) = (3 , -2)\\(x_2 , y_2) = (15 , 7)\)
Plug in the corresponding numbers to the corresponding variables:
m = \(\frac{7 - (-2)}{15 - 3} = \frac{7 + 2}{15 - 3} = \frac{9}{12}\)
Simplify the slope. Divide common factors from both the numerator and denominator:
\((\frac{9}{12})/(\frac{3}{3} ) = \frac{3}{4}\)
Slope: \(\frac{3}{4}\)
11) Let:
\((x_1 , y_1) = (-5 , -10)\\(x_2 , y_2) = (-5 , -1)\)
Plug in the corresponding numbers to the corresponding variables:
m = \(\frac{-1 - (-10)}{-5 - (-5)} = \frac{-1 + 10}{-5 + 5} = \frac{9}{0} =\) undefined.
Slope: undefined
12) Let:
\((x_1 , y_1) = (-4 , -2)\\(x_2 , y_2) = (-12, 16)\)
Plug in the corresponding numbers to the corresponding variables:
m = \(\frac{16 - (-2)}{-12 - (-4)} = \frac{16 + 2}{-12 + 4} = \frac{18}{-8} = -\frac{18}{8} = ((-\frac{18}{8})/( \frac{2}{2}) = -\frac{9}{4}\)
Slope: \(-\frac{9}{4}\)
~
Let f(x) = 2x² - 3x and g(x) = 5x - 1.
Find g[f(2)].
g[f(2)] =
Answer:
Step-by-step explanation:
To find g[f(2)], we need to evaluate the composite function g[f(2)] by first finding f(2) and then substituting the result into g(x).
Let's start by finding f(2):
f(x) = 2x² - 3x
f(2) = 2(2)² - 3(2)
= 2(4) - 6
= 8 - 6
= 2
Now that we have the value of f(2) as 2, we can substitute it into g(x):
g(x) = 5x - 1
g[f(2)] = g(2)
= 5(2) - 1
= 10 - 1
= 9
Therefore, g[f(2)] is equal to 9.
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What is the answer
To 7/9 divided by 1/8
Please help will give brainliest
Int operatenum(int x, int y){ int s, p; s = x y; p = x * y; return (s p);} if this function is called with arguements 4 and 10, what value will be returned?
The value that will be returned by the function if the values of x and y are 4 and 10 is 54.
The given code snippet is a CPP code to find the sum of the two parameters that are given as input in the parameter.
The given function operatenum takes two integer arguments x and y. It calculates the sum of x and y and assigns it to the variable s, then calculates the product of x and y and assigns it to the variable p. Finally, it returns the sum s concatenated with the product p.
int operatenum(int x, int y) { \\x and y are the parameter
int s, p; \\ local variable
s = x + y; \\ s stores the sum of the variable x and y
p = x * y; \\ p stores the product of x and y
return (s + p); \\ the function returns the sum of s and p
}
so after executing the code by passing 4 and 10 as the values of x and y respectively:
s= 4+10=14
p=4*10=40
the return statement returns (s*p) which is 14+40= 54.
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What is -6x+2=-5x+5? I WOULD LIKE TO KNOW!!!!!!!!!!!!!!!!!! THANK YOU!
Answer:
\(x=-3\)
Answer:
x=3
Step-by-step explanation:
-6x+2=-5x+5
You grab the -5 and make a positive 5. Since is going to the other side. You will have get -1.Then grab the 2 and make it negative and subtract it with 5. It will get 3.Then you divide 3 with -1 and give 3. Then 3 is your answer.When putting in the x's, (-6 x 3)=18, then you add 18 with 2 and get 20.Then (-5 x 3)=15, then add 15 with 5 and get 20.Both will be equal.-6x+2=-5x+5+5x . +5x
-1x+2=5-2 .-2
-1x = 3 . = 3-1 . -1
(-6 x 3) = 18 + 2 = 2020=-5x+5(-5 x 3)= 15 + 5 = 2020=20x= 3I need the answers ASAP ? No rocky ?
Answer:(-1,1) - (4,4)
Step-by-step explanation:
ez
Gushers Company produces 1000 packages of fruit snacks per month. The sales price is $6 per pack. Variable cost is $1.60 per unit, and fixed costs are $1700 per month. Management is considering adding a vitamin supplement to improve the value of the product. The variable cost will increase from $1.60 to $1.80 per unit, and fixed costs will increase by 10%. At what sales price for the new product will the two alternatives (sell as is or process further) produce the same operating income? (Round your answer to the nearest cent.)
a. $6.00
b. $6.37
c. $3.67
d. $2.70
Fruit Sushi Inc. produces 1000 packages of fruit sushi per month. The sales price is $4 per pack. Variable cost is $1.60 per unit, and fixed costs are $1700 per month. Management is considering adding a chocolate coating to improve the value of the product by making it a dessert item. The variable cost will increase from $1.60 to $1.90 per unit, and fixed costs will increase by 20%. The CEO wants to price the new product at a level that will bring operating income up to $3000 per month. What sales price should be charged? (Round your answer to the nearest cent.)
a. $2.40
b. $6.94
c. $4.00
d. $2.10
Fruit Computer Company makes a fruit themed computer. Variable costs are $220 per unit, and fixed costs are $32,000 per month. Fruit Computer Company sells 500 units per month at a sales price of $300. The company believes that it can increase the price if the computer quality is upgraded. If so, the variable cost will increase to $230 per unit, and the fixed costs will rise by 50%. The CEO wishes to increase the company's operating income by 30%. Which sales price level would give the desired results? (Round your answer to the nearest cent.)
a. $284.00 per unit
b. $316.00 per unit
c. $990.00 per unit
d. $346.80 per unit
Selling price = $6.37 .
Selling price = $6.94
Selling price = $346.80
1)
Sales revenue = 6,000
Less:-Variable costs ($1.5 per unit 1,000) = 1,500
Less:- Fixed costs = (1,700)
Operating Income = 2,800
Variable costs and Fixed costs have increased.
Hence, in order to maintain the same Operating Income, the selling price should be higher than the current selling price .
Thus to maintain same operating income the selling price should be $6.37 .
2)
The computation is given below:
Sales price = ( Total sales revenue ÷ packages sold)
Total sales revenue = ( Total Cost + Operating income )
Total Cost = ( Variable Cost + Fixed cost)
Now
Variable cost = 1,000 packages × $1.90 per unit
= $1,900
Fixed cost = $1,700 × 120%
= $2040
Total cost = $1,900 + $2,040
= $3,940
Now
Total sales revenue is
= $3,940 + $3,000
= $6,940
Now
Sales price = $6,540 ÷ 1,000 packages
= $6.94
3)
-Fruit Computer Company has variable costs of $220 per unit and fixed costs of $32,000 per month.
- The company currently sells 500 units per month at a sales price of $300.
Net margin = $8000
- The company wants to increase its operating income by 30%.
- If the company upgrades the computer quality, the variable cost per unit will increase to $240 and the fixed costs will rise by 50%.
Thus the selling price per unit will be $346.80 per unit.
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helppppp pleasee....
Find the Area! Need help asap
Answer:
5.6ft squared
Step-by-step explanation:
4x7 = 28 divided by 5 which is 5.6
One of the output functions of a three inputs 3x8 decoder combinational output function in sum-of- minterms form: F = (0,1,2,3,7). What is the c function of this output? a) (x + y) (y+z) b) (x+y)(x+z) c) (y + 2) (x + 2)
The correct option is a) (x + y) (y + z). Given the output function F in sum-of-minterms form as F = (0, 1, 2, 3, 7), we need to determine the corresponding Boolean expression for the output function.
A 3x8 decoder has three input variables (x, y, z) and eight output variables, where each output variable corresponds to a unique combination of input variables. The output variables are typically represented as minterms.
Let's analyze the given output function F = (0, 1, 2, 3, 7). The minterms represent the outputs that are equal to 1. By observing the minterms, we can deduce the corresponding Boolean expression.
From the minterms, we can see that the output is equal to 1 when x = 0, y = 0, z = 0 or x = 0, y = 0, z = 1 or x = 0, y = 1, z = 0 or x = 0, y = 1, z = 1 or x = 1, y = 1, z = 1.
By simplifying the above conditions, we get (x + y) (y + z), which is the Boolean expression corresponding to the given output function F.
In summary, the correct option is a) (x + y) (y + z).
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if AB= 7.2 m, what is C?
Based on the triangle midsegment theorem, the length of CZ is calculated as: 7.2 m.
How to Apply the Triangle Midsegment Theorem?The triangle midsegment theorem states that when two sides of a triangle are joined together by a line segment at their midpoint, the line segment is called the midsegment, and it is parallel to the third side whose measure is twice its length.
This implies that, AB is a midsegment in the image shown for triangle XYZ. It is parallel to YZ.
Therefore:
AB = 1/2(the length of YZ)
Substitute the value of AB into the equation:
7.2 = 1/2(YZ)
2(7.2) = YZ
YZ = 14.4 m.
The length of CZ = 1/2(the length of YZ) [this is because YC = CZ]
CZ = 1/2(14.4)
CZ = 7.2 m.
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