For which function is f(5) = 2?

Answer:

\(x = \frac{3\pi}{2} + 4k\pi\)

\(x = \frac{5\pi}{2} + 4k\pi\)

Step-by-step explanation

Answer:

270 and 450

Step-by-step explanation:

Honestly I guessed and got it right :/

-1x+5=2

_5. -5

-1x=7

-1. -1

x=-7

The vertical difference between a stair tread nosing and any structure or ceiling above the stairway is known as the "headroom" or "clearance."

Headroom refers to the vertical space between the nosing of a stair tread (the front edge of the step) and any overhead structure or ceiling above the staircase. It is an important consideration in stair design to ensure safe and comfortable passage for individuals using the stairs.

Sufficient headroom allows people to navigate the staircase without bumping their heads or feeling confined. Building codes typically specify minimum headroom requirements to ensure safety and to prevent accidents. Adequate headroom is essential to provide a clear and unobstructed pathway for individuals moving up or down the stairs.

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Answer:  See below

Step-by-step explanation:

A.  Point C is the y-intercept, the value of y when x = 0.  We know x = 0 for this point, (0,?).  To find y, wither find it on the graph (y = -6) or calculate it with the equation:

y = \(x^{2}\) +x-6

For x = 0, y becomes -6

Point C is (0,-6)

B.   Y is zero at both points A and B.  We want the values of x that will make the equation equal to zero.  We can read them from a graph (where the line crosses the x axis), or factor the equation and set each factor to zero:

y = \(x^{2}\) +x-6

y = (x + 3)(x - 2)

For y to be zero, either  (x + 3) or (x - 2) must equal zero.  That would occur for bot x = -3 and x = 2.

The points A and B are therefore:  

A (-3,0)

 B  (2,0)

We can find the minimum of this function by taking the first derivative and setting it equal to zero, the point at which the slope of the line is zero.

y = \(x^{2}\) +x-6

y' = 2x + 1

2x = -1

x = -(1/2)

At x = - 1/2, y becomes -6.25

The minimum is (-(1/2), - 6.25)

See the attachment.

The quality which a taylor polynomial have that the tangent line does not necessarily have is that Taylor polynomial has a far better approximation of f(x) near x = a than is the tangent line

Taylor polynomial function simply refers to an infinite sum of terms that are expressed in terms of the function's derivatives at a single point.

So therefore, the quality which a taylor polynomial have that the tangent line does not necessarily have is that Taylor polynomial has a far better approximation of f(x) near x = a than is the tangent line

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Answer:

No it is not the same

Step-by-step explanation:

A real number is any number, positive or negative, whole number or decimal.

(EX) 1, 1.00567, -2, -2.659365

Any number!

In permutation, ³¹C₅  are there to select 5 scoops of ice cream to put into a bowl .

What are some examples of permutation?

Total ice cream flavor n = 31 flavor

selection of (r) = 5 scoop

total number of ways to select 5 scoops of ice cream from 31 flovers

                                                   = ³¹C₅

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Answer:

First expression

Degree 3

Number of terms: 3

Second expression

Degree 5

Number of terms: 6

Third expression

Degree 4

Number of terms: 2

The Number line is attached below,

The horizontal straight lines in mathematics known as number lines are where integers are arranged in equal intervals. A number line can be used to represent every number in a sequence. The endpoints of this line go on forever.

Given:

Rebecca points in a video game.

let Rebecca point '0' at the 4th level.

After turn one, she will have 0 points.

After turn 2 she has 8 plants.

After turn 2 she has = 9-1 = 7 plants

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Answer:

mhmhmh

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

the qhfjibv clicks its 2

The probability that at least one of the three randomly selected people has been vaccinated is approximately  961/1000 as a fraction.

Percent of vaccinated people = 66%

Number of people randomly selected = 3

The probability that a person has been vaccinated is

= 66%

=  0.66 as a decimal.

The probability that at least one of three people has been vaccinated

= Total probability - Probability that none of them have been vaccinated

Total probability = 1

The probability that the first person selected has not been vaccinated is

1 - 0.66 = 0.34.

The probability that the second person selected has not been vaccinated is also 0.34.

And the same goes for the third person.

So, the probability that none of the three people have been vaccinated is,

= 0.34 x 0.34 x 0.34

= 0.039304

The probability that at least one of the three people has been vaccinated is ,

= 1 - 0.039304

= 0.960696

= 0.961

= 961/1000 as a fraction.

Therefore, the probability that at least one of the three people has been vaccinated is approximately  961/1000 as a fraction.

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Therefore, the distance covered by a passenger vehicle during one turn of the wheel is roughly 471.2 feet (rounded to the nearest tenth).

The ratio of a circle's circumference to width serves as the basis for the traditional meaning of Pi (). The diameter or extent of a circular is its circumference. A straight line connecting a spot on one point of the circular to a point at the other end, going through the middle, is the diameter.

The following algorithm determines a circle's circumference:

C = πd

where d is the diameter of the circle. In this case, the diameter of the Ferris wheel is 150 ft, so its circumference is:

C = π(150) ≈ 471.2 ft

This indicates that a full rotation of the Ferris wheel is equal to a passenger vehicle moving about 471.2 feet.

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The option that is not a factor of capacity planning is the option d

d) Proximity to suppliers

The process of ascertaining the production capacity an organization needs in order to meet changing demand for the products and services of the organization is known as capacity planning.

The factors considered in capacity planning are factors which include the capacity measurement approach, the economies of scale, preparedness to deal with the capacity in chunks, and activities towards identifying the best operating level.

Therefore, from the listed options, the option that is not a factor in capacity planning is the option (d) proximity to suppliers

Other aspects of the operations of an organization, such as supply chain management and logistics can be affected by the proximity of suppliers, but the proximity of suppliers is not directly linked to the determination process for the production capacity needed to meet the market demand.

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Answer:

-8 \(\leq\) -8

Step-by-step explanation:

-8\(\leq\)2-10

-8\(\leq\)-8

Answer:

-8

Step-by-step explanation:

-8≤2-10
2-10 = -8
-8≤-8

Answer:

When x = -3  y = -1

When x = -3/4  y = 7/2

Step-by-step explanation:

y = 4x^2 + 17x + 14

y = 2x + 5​

Set each equation equal to each other

4x^2 + 17x + 14  = 2x + 5​

Subtract 2x from each side

4x^2 + 17x-2x + 14  = 2x-2x + 5​

4x^2 + 15x + 14  =  5​

Subtract 5 from each side

4x^2 + 15x + 14-5  =  5​-5

4x^2 + 15x +9  = 0

Factor

(4x+3) ( x+3) =0

Using the zero product property

4x+3 =0    x+3 =0

4x = -3      x=-3

x = -3/4     x=-3

Now we need to find y for each x

x =-3   y = 2x+5  =2(-3)+5 = -6+5 = -1  

When x = -3  y = -1

x = -3/4   y = 2(-3/4) +5 = -3/2 +5 = 7/2

When x = -3/4  y = 7/2

Answer:

144 in^2

Step-by-step explanation:

Using the A = s^2 and the text says that s= 12in

 the answer is 12 in * 12 in = 144 in^2

At a continuous speed of 20 miles per hour, it takes 2 minutes to cross this bridge.

The unitary method is used to calculate the value of a single unit and then multiply that value by itself in order obtain the desired value. Unitary refers to a single, unique, or solitary unit. As a result,

this method's objective is to establish values in terms of a single unit. If a car can drive 44 kilometer two litres of gas, for instance, the unitary approach can be used to calculate how many kilometers it can travel on one litre of gas. The value of a single unit is determined by the unitary technique, and also the value of the required quantity of units can then be calculated using this value.

given,

 0.76 miles = (4024/5280) miles

Speed =20 miles per hour

Time: =(Distance / Speed) = (0.76/20)

= 0.038 ( in hours )

into minutes = 2 min

At a continuous speed of 20 miles per hour, it takes 2 minutes to cross this bridge

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Answer:

x > - 1

Step-by-step explanation:

- 10 < x - 9 ( add 9 to both sides )

- 1 < x , therefore

x > - 1

Answer:

x > -1

Step-by-step explanation:

why:

-10  < x-9         for exemple 2< 3

x-9  > -10                 3 > 2      

just add 9 to both sides

x-9 +9 > -10 +9

x > -1

meth2

x-9  > -10  

x > -10 +9       left  to right

x> -1

Answer:

Distance between Jackson and Symphony stations is 2.2 miles.

Step-by-step explanation:

From the given map,

Location of two stations can be represented by the ordered pairs Jackson(2, 4) and Symphony(1, 2)

Every unit of the map represents the distance of 1 mile.

Distance between two points is measured by the formula,

d = \(\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\)

Therefore, distance between the given stations will be,

d = \(\sqrt{(2-1)^2+(4-2)^2}\)

  = \(\sqrt{1+4}\)

  = \(\sqrt{5}\)

  = 2.236

  ≈ 2.2 miles

Distance between Jackson and Symphony stations is 2.2 miles.

Answer:

Lowest to highest

7/10 ,  11/15,   4/5

Step-by-step explanation:

Probably the easiest way to do this is to convert each of the fractions to decimals which will clearly indicate which is the highest and which the lowest etc.

4/5 = 0.80

11/15 = 0.73

7/10 = 0.7

0.7 is less than 0.73 is less than 0.80
So 7/10, 11/15, 4/5

However, I am assuming they want you to work with fractions

To compare fractions you have to get all the denominators equal and then compare the numerator

To get a common denominator find the Least Common Multiple of the denominators. This is the lowest number that can be divided by all three denominators

Looking at 5, 15 and 10 we can see that 30 is divisible by each denominator. So that becomes our common denominator

Now multiply each fraction denominator by a factor to make the denominator equal to the common denominator. At the same time multiply the numerator by the same factor

4/5 = (4 x 6) / (5 x 6) = 24/30    Highest

11/15 = (11 x 2) / (15 x 2) = 22/30

7/10 = (7 x 3) / (10 x 3) = 21/30      Lowest

Looking at the numerator alone we can see that 7/10 is the lowest, 11/15 is next lowest and 4/5 the highest

a) The relationship between b and c is that c cannot be zero.

b) b can be any nonzero constant and c is equal to 2.5 in this case.

In two dimensions, the compatibility equations for strain are,0

∂εx/∂y + ∂γxy/∂x = 0

∂εy/∂x + ∂γxy/∂y = 0

where εx and εy are the normal strains in the x and y directions, respectively, and γxy is the shear strain.

Using the given strain field, we can calculate the strains,

εx = -4.5cx² + 10.5cy

εy = 1.5cx² - 7.5cy²

γxy = 1.5bxy

Taking partial derivatives and plugging them into the compatibility equations, we get,

⇒ -9cx + 0 = 0

⇒ 0 + (-15cy) = 0

These equations must be satisfied for the strain field to be compatible. From the first equation,

We get cx = 0, which means c cannot be zero.

From the second equation, we get cy = 0,

Which means b can be any nonzero constant.

For part b:

We are asked to find the displacements u and v corresponding to the given strain field at points (3, 7), assuming they are zero at point (0, 0) and using c = 2.5.

To find the displacement components,

We need to integrate the strains with respect to x and y. We get,

u = ∫∫εx dx dy = ∫(10.5cy) dy = 5.25cy²

v = ∫∫εy dx dy = ∫(1.5cx² ) dx - ∫(7.5cy²) dy = 0.5cx³ - 2.5cy³

Plugging in the values of c and b, we get,

u = 5.25(2.5)(7)²  = 767.62

v = 0.5(2.5)(3)³ - 2.5(7)³ = -8583.75

Therefore,

The displacements at points (3, 7) are u = 767.62 and v = -8583.75.

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Answer:

20%

Step-by-step explanation:

Difference is 48

Hope this helps

Answer:

a mile and 2/4

Step-by-step explanation:

The correct statement about the correlation coefficient (r) that is TRUE is: c.) The correlation coefficient is always between -1 and +1.

The statement that is true about the correlation coefficient (t) is that it is always between -1 and +1.

The correlation coefficient is a statistical measure that quantifies the strength and direction of the linear relationship between two variables.

The range of the correlation coefficient is from -1 to +1, where -1 indicates a perfect negative correlation, +1 indicates a perfect positive correlation, and 0 indicates no correlation at all.

However,

Using a statistical software is more convenient and efficient, especially when dealing with large datasets.
The statement that a correlation coefficient of r = 0.75 shows a strong positive relationship between two variables is partially true.

A correlation coefficient of 0.75 indicates a moderate to strong positive correlation, but the strength of the correlation also depends on the context and the field of study. In some fields, a correlation coefficient of 0.75 may be considered weak, while in others, it may be considered strong.
Finally,

The statement that the stronger the strength of association, the lower the value of the correlation coefficient is false.

In fact, the stronger the association between two variables, the higher the value of the correlation coefficient.

This is because the correlation coefficient measures the degree to which the two variables move together, whether positively or negatively.

Therefore,

If two variables have a strong positive correlation, the correlation coefficient will be closer to +1, indicating a strong relationship.

Conversely, if two variables have a strong negative correlation, the correlation coefficient will be closer to -1, indicating a strong relationship.

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Answer:

-6 < y < ∞

Step-by-step explanation:

The range is the value of the output, in this case the value of y

The value is from -6 not including -6 to infinity

-6 < y < ∞

Answer:

C. from -6 to infinity

Step-by-step explanation:

The range is the set of the y-coordinates of the points of the function.

The lowest value of y is -6 or just greater than -6.

All values greater than y are also part of the range.

Answer: Choice C. from -6 or just greater than -6 to infinity

It is essential to encourage and support these girls to continue pursuing their interests and talents in math and science, as excelling in these fields can lead to successful careers and personal growth.

It is unfortunate that some girls may fear focusing on math and science during puberty due to concerns about popularity or attractiveness. However, it is important to remember that excelling in these subjects can lead to numerous opportunities and career paths in the future. It is also important to note that intelligence and academic achievement should be celebrated and valued regardless of gender stereotypes. Schools can play a role in promoting the importance of STEM subjects and encouraging girls to pursue their interests in these areas.

It has been observed that some girls who excelled in math and science during elementary school may develop concerns during puberty that focusing on these subjects might limit their popularity or attractiveness as girls. This could be due to societal stereotypes or peer pressure, which might influence their academic choices and priorities. It is essential to encourage and support these girls to continue pursuing their interests and talents in math and science, as excelling in these fields can lead to successful careers and personal growth.

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It is essential to encourage and support these girls to continue pursuing their interests and talents in math and science, as excelling in these fields can lead to successful careers and personal growth.

It is unfortunate that some girls may fear focusing on math and science during puberty due to concerns about popularity or attractiveness. However, it is important to remember that excelling in these subjects can lead to  and career paths in the future. It is also important to note that intelligence and academic achievement should be celebrated and valued regardless of gender stereotypes. Schools can play a role in promoting the importance of STEM subjects and encouraging girls to pursue their interests in these areas.

It has been observed that some girls who excelled in math and science during elementary school may develop concerns during puberty that focusing on these subjects might limit their popularity or attractiveness as girls.

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