For the following exercises, solve the system of linear equations using Cramer's Rule. 4x - 3y + 4z = 10 5x – 2z = -2 3x + 2y - 5z = -9

Answer:

AD = 10

Step-by-step explanation:

It's given that ABCE is a rectangle.

Therefore, measure of opposite sides of the rectangle will be equal.

AB = EC

AB = ED + DC

12 = ED + 4

ED = 8

Measure of side AE = 6

Since, measure of interior angles of a rectangle = 90°

Therefore, ΔEAD will be a right triangle.

By Pythagoras theorem,

AD² = AE² + ED²

      = 6² + 8²

AD = \(\sqrt{36+64}\)

      = \(\sqrt{100}\)

      = 10

Therefore, measure of side AD = 10 units

Answer:

52ft

Step-by-step explanation:

You divide the box in 2 pieces and multiply the numbers by the separate boxes that you made, then you add them.

5x2= 10

8-2= 6 -----> 7x6= 42

10 + 42 = 52

Answer: The first box is 56 The second box is 4 and the last is 52

Step-by-step explanation: The total area of the full rectangle is 8×7=56

The area of the small cut out portion is 2×2=4

The area of the remaining figure is 56-4=52

Answer:

Step-by-step explanation:

Candice = 25mph for 4 hours.

Candice has driven= 25 * 4= 100miles.

Liz =50mph

Liz time to catch up to candice= 50 * 2= 100miles.

Therefore, It would have taken Liz two hours to catch up with Candice

The intermediate result is  \(C= \left[\begin{array}{cc}18&14\\62&66\end{array}\right]\).

In linear algebra, the Strassen algorithm, named after Volker Strassen, is an algorithm for matrix multiplication. It is faster than the standard matrix multiplication algorithm for large matrices, with a better asymptotic complexity, although the naive algorithm is often better for smaller matrices.

To use Strassen's algorithm to compute the matrix product C = AB, we need to divide the matrices into smaller submatrices and apply the algorithm recursively.

First, we need to pad both matrices A and B with zeros to make them both 2x2 matrices:

\(A= \left[\begin{array}{cc}1&3\\7&5\end{array}\right]\)

\(B= \left[\begin{array}{cc}6&8\\4&2\end{array}\right]\)

Next, we divide each matrix into four submatrices of size 1x1:

A11 = 1,   A12 = 3

A21 = 7, A22 = 5

B11 = 6,  B12 = 8

B21 = 4, B22 = 2

We can then apply Strassen's algorithm to compute the product C = AB:

P1 = A11 * (B12 - B22) = 1 * (8 - 2) = 6

P2 = (A11 + A12) * B22 = (1 + 3) * 2 = 8

P3 = (A21 + A22) * B11 = (7 + 5) * 6 = 72

P4 = A22 * (B21 - B11) = 5 * (4 - 6) = -10

P5 = (A11 + A22) * (B11 + B22) = (1 + 5) * (6 + 2) = 48

P6 = (A12 - A22) * (B21 + B22) = (3 - 5) * (4 + 2) = -12

P7 = (A11 - A21) * (B11 + B12) = (1 - 7) * (6 + 8) = -84

Using these intermediate results, we can compute the submatrices of C:

C11 = P5 + P4 - P2 + P6 = 48 - 10 - 8 - (-12) = 18

C12 = P1 + P2 = 6 + 8 = 14

C21 = P3 + P4 = 72 - (-10) = 62

C22 = P5 + P1 - P3 - P7 = 48 + 6 - 72 - (-84) = 66

Finally, we can combine these submatrices to obtain the matrix C:

\(C= \left[\begin{array}{cc}18&14\\62&66\end{array}\right]\)

Therefore, the product C = AB using Strassen's algorithm is:

\(C= \left[\begin{array}{cc}18&14\\62&66\end{array}\right]\)

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Answer:

Answer:

Step-by-step explanation:

\sqrt{11x+5}

11x+5

= 7 ( square both sides )

11x + 5 = 7² = 49 ( subtract 5 from both sides )

11x = 44 ( divide both sides by 11 )

x = 4

substitute x = 4 into the left side of the equation and if equal to the right side , then it is the solution.

\sqrt{11(4)+5}

11(4)+5

= \sqrt{44+5}

44+5

= \sqrt{49}

49

= 7 ← equals right side

then x = 4 is the solution

Answer: x =4, not extraneous.

Explanation:

\(\sqrt{11x + 5} = 7\), square all sides.

Because the square root is squared, it is reversed: \(11x+5 =7^{2}\)

(72 = 49)

Subtract 5 from all sides: 11x = 44

(49 - 5 = 44)

(11x is an unknown so we cannot subtract 5 from it)

To get rid of the unknown, divide 11 on all sides: x = 4

(11x ÷ 11 = 1, x is written as one) (44 ÷ 11 = 4)

x = 4

The solution is not extraneous.

The probability of selecting a sample of 5 lightbulbs without any defective bulbs is then given by p^5, where p is the probability of not having a defective bulb.

In this situation, the probability of selecting a sample of 5 lightbulbs without any defective bulbs is calculated using the binomial distribution. The probability of success, p, is the probability that a single lightbulb is not defective, and the probability of failure, q, is the probability that a single lightbulb is defective. The probability of selecting 5 lightbulbs with no defective bulbs is then given by the equation:

P(x=0) = (p^5)*(q^0) = p^5

In this case, p is the probability of not having a defective bulb, and q is the probability of having a defective bulb. The probability of selecting 5 lightbulbs without any defective bulbs is then given by p^5.

For example, if the probability of not having a defective bulb is 0.95 and the probability of having a defective bulb is 0.05, then the probability of selecting a sample of 5 lightbulbs without any defective bulbs is 0.95^5 = 0.7737. This means that there is a 77.37% chance of selecting a sample of 5 lightbulbs without any defective bulbs.

To sum up, the probability of selecting a sample of 5 lightbulbs without any defective bulbs is calculated using the binomial distribution. The probability of success is the probability of not having a defective bulb, and the probability of failure is the probability of having a defective bulb. The probability of selecting a sample of 5 lightbulbs without any defective bulbs is then given by p^5, where p is the probability of not having a defective bulb.

The correct question is:

A box contains 100 bulbs, out of which 10 are defective. If a sample of 5 lightbulbs is selected, find the probability that none in the sample are defective

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Answer:

339.336 m^2

Step-by-step explanation:

Given data

Radius= 6meters

We know that the surface area of a half-sphere is given as

A=3πr^2

A= 3*3.142*6^2

A= 3*3.142*36

A=339.336 m^2

Answer: 72π meters squared.

Step-by-step explanation: Given that the radius is 6 meters, use the sphere surface area formula to find the surface area of the half-sphere;

The two unit vectors orthogonal to both (0, 1, 2) and (1, -2, 3) are:

Unit Vector 1 = (-4/√21, 2/√21, -1/√21)

Unit Vector 2 = (-10/√21, 0, 0)

To find two unit vectors that are orthogonal (perpendicular) to both vectors (0, 1, 2) and (1, -2, 3), we can use the cross product of the two vectors.

Let's denote the given vectors as vector A = (0, 1, 2) and vector B = (1, -2, 3).

Calculate the cross product of A and B.

To find the cross product, we perform the following calculation:

A × B = (A2 * B3 - A3 * B2, A3 * B1 - A1 * B3, A1 * B2 - A2 * B1)

= (1 * 2 - 2 * 3, 2 * 1 - 0 * 3, 0 * (-2) - 1 * 1)

= (-4, 2, -1)

Normalize the resulting vector to obtain a unit vector.

To normalize a vector, we divide each component by the magnitude of the vector. In this case, the magnitude of (-4, 2, -1) can be calculated as:

|A × B| = sqrt((-4)^2 + 2^2 + (-1)^2) = sqrt(21)

To obtain a unit vector, we divide each component of (-4, 2, -1) by the magnitude:

Unit Vector 1 = (-4/√21, 2/√21, -1/√21)

Find another vector orthogonal to both A and B.

To find a second unit vector orthogonal to A and B, we can take the cross product of A and the first unit vector we calculated.

A × Unit Vector 1 = (0, 1, 2) × (-4/√21, 2/√21, -1/√21)

Performing the cross product calculation, we get:

(2 * (-1/√21) - (-4/√21) * (2/√21), (-4/√21) * (0) - (0) * (-1/√21), (0) * (2/√21) - 1 * (-4/√21))

= (-2/√21 - 8/√21, 0, 0)

Simplifying, we have:

Unit Vector 2 = (-10/√21, 0, 0)

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Answer:

The answer is actually B.

Step-by-step explanation:

3(1+4x)=12x

(3)(1)+(3)(4x)=12x(Distribute)

3+12x=12x

12x+3=12x

Step 2: Subtract 12x from both sides.

12x+3−12x=12x−12x

3=0

Step 3: Subtract 3 from both sides.

3−3=0−3

0=−3

(Can't be negative)

Answer:

Answer is C. 3s + 9

Step-by-step explanation:

The perimeter is the sum of all 3 sides in a triangle

which is s+3 + s+3 + s+3

= 3s + 9

To create a frequency distribution using the "2 to the power of k rule", we need to determine the value of k. The rule states that k should be equal to the largest value in the dataset. In this case, the largest value is 65.

Next, we calculate 2 to the power of k, which is 2^k. Since k = 6 (since 2^6 = 64), we have 2^6 = 64.

Now, we can create the frequency distribution. We start by dividing the range of the data (65 - 4 = 61) by 64 (2^k) to determine the interval size.

61 / 64 = 0.953125

Since the interval size is less than 1, we round it up to 1.

Now, we can start creating the frequency distribution table. We'll start with the lower limit of the first interval, which is 4. Then, we add the interval size to get the upper limit of the first interval, which is 4 + 1 = 5.

Now, we count how many values fall within this interval. From the given data, we have 4 values (4, 18, 19, 24). So, the frequency for this interval is 4.

We continue this process for the rest of the intervals until we reach the largest value in the data.

Here's the frequency distribution table:

Interval   Frequency
4-5           4
6-7           2
8-9           2
10-11       0
12-13       0
14-15       0
16-17       0
18-19       2
20-21       0
22-23       1
24-25       2
26-27       1
28-29       0
30-31       0
32-33       0
34-35       2
36-37       1
38-39       2
40-41       1
42-43       2
44-45       1
46-47       0
48-49       1
50-51       3
52-53       1
54-55       3
56-57       1
58-59       0
60-61       1
62-63       1
64-65       1

In conclusion, we used the "2 to the power of k rule" to create a frequency distribution for the number of families who used the tri-c day care service during a 30-day period. The frequency distribution table shows the intervals and the corresponding frequency of values falling within each interval.

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Answer:

cos

Step-by-step explanation:

its adjacent over hypotenuse

Answer: cos

Step-by-step explanation:

You don't have a value for the side opposite the angle, you only have your hypotenuse and your adjacent side. Hope this helps.

A store bought 5 dozen lamps at $30 per dozen and sold them all at $15 per lamp. the profit on each lamp was 83.33% of its selling price. To begin with, let's calculate how much the store went through to buy the lights:

5 dozen lights = 5 x 12 = 60 lights

Taken a toll per dozen = $30

Taken a toll per light = $30 / 12 = $2.50

Add up to fetched of 60 lights = 60 x $2.50 = $150

Another, let's calculate how much the store earned by offering the lights:

60 lights sold at $15 each = 60 x $15 = $900

To calculate the benefit, we got to subtract the taken toll from the income: Benefit = Income - Fetched = $900 - $150 = $750

To calculate the rate benefit on each lamp, we have to partition the benefit by the entire income and duplicate by 100:

Rate benefit = (Benefit / Income) x 100

Rate benefit = ($750 / $900) x 100

Rate benefit = 83.33D

thus, the benefit of each light was 83.33% of its offering cost. 

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The child advocate collects data by randomly selecting 4 out of the 25 state orphanages. In each of the four selected orphanages, the child advocate surveys every child.

This approach allows the child advocate to obtain information from a representative sample of children in state orphanages. By surveying every child in the selected orphanages, the child advocate ensures that no child is excluded from the data collection process. This method provides a comprehensive understanding of the experiences, needs, and concerns of the children in the four chosen orphanages.

By collecting data in this manner, the child advocate can gather valuable insights that can inform policies and interventions to improve the well-being and support for children in state orphanages.

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It is given that ABCD is a rectangle. We have to give reasonings for the statements.

What is the rectangle?

A rectangle is a four-sided polygon with four right angles. The opposite sides of a rectangle are equal in length (congruent) and the opposite angles are equal in measure (congruent). The opposite sides are parallel to each other. A rectangle can be defined as a special case of parallelogram where all angles are right angles.

Given: ABCD is a rectangle

Prove: triangle ADC is congruent to triangle BCD

1. Given ABCD is a rectangle

2. By definition of rectangle, opposite sides are congruent (AD is congruent to BC)

3. By definition of rectangle, opposite angles are right angles (angle ADC and angle BCD are right angles)

4. By definition of right angle, adjacent angles are congruent (angle ADC is congruent to angle BCD)

5. By reflexive property, an object is congruent to itself (DC is congruent to DC)

6. By SAS Congruence (Side-Angle-Side), if two triangles have two congruent sides and the included angle congruent, the two triangles are congruent. Since AD=BC and angle ADC= angle BCD, and DC=DC, then triangle ADC is congruent to triangle BCD.

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Answer:

to do this we have to divide 43 by 83

0.51807228915

so the frequency is about 51.8%

If Station 1 (at 74, 41) is 44 km away and Station 2( at 0,43 ) is 38 km away. The required approximate location of the GPS receiver is (42, 10).

The location of the GPS receiver can be determined with the help of trilateration. Trilateration is a process of determining absolute or relative locations of points by measurement of distances, using the geometry of circles, spheres, or triangles. If three stations (or more) are in known locations, with a known distance from the point of interest, we can determine the position of the GPS receiver with the help of trilateration.

It can be determined by the following method:

1: Plot the given stations on a coordinate plane. Stations are:

Station 1: (74, 41)

Station 2: (0, 43)

2: Calculate the distance of the GPS receiver from each station using the distance formula.

Distance Formula: The distance formula is used to find the distance between two points in the coordinate plane. The distance between points (x1,y1) and (x2,y2) is given by

d = √[(x2 - x1)² + (y2 - y1)²]

Station 1: Distance from station 1 = 44 kmSo, d1 = 44 km

Station 2: Distance from station 2 = 38 kmSo, d2 = 38 km

3: Plot the given distances as the circle on the coordinate plane.

Circle 1: Centred at (74, 41) with a radius of 44 km.

Circle 2: Centred at (0, 43) with a radius of 38 km.

4: The intersection of two circles. Circle 1 and Circle 2 intersect at point P (approx) (42, 10). So, the approximate location of the GPS receiver is (42, 10).

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Since the derivative is negative in the interval x > 0, the function y = 3x/(6x - 1) is decreasing on that interval.

To find the critical point(s) and determine if the function is increasing or decreasing on the given interval for the function y = 3x/(6x - 1), we need to first find the derivative of the function and then locate any values of x where the derivative is equal to zero or undefined.

Taking the derivative of y with respect to x:

y' = (d/dx)(3x/(6x - 1))

To simplify the derivative, we can use the quotient rule:

y' = [(6x - 1)(3) - (3x)(6)] / (6x - 1)^2

y' = (18x - 3 - 18x) / (6x - 1)^2

y' = -3 / (6x - 1)^2

To find the critical point(s), we set the derivative equal to zero:

-3 / (6x - 1)^2 = 0

Since the numerator is constant and nonzero (-3), the fraction can only be equal to zero if the denominator is equal to zero:

6x - 1 = 0

Solving for x:

6x = 1

x = 1/6

The critical point is at x = 1/6.

To determine if the function is increasing or decreasing on the interval x > 0, we can examine the sign of the derivative in that interval.

For x > 0, the denominator (6x - 1)^2 is always positive, and the numerator (-3) is negative. Dividing a negative number by a positive number gives a negative result. Therefore, the derivative y' = -3 / (6x - 1)^2 is negative for x > 0.

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To find the probability that a randomly selected employee will have more than ten years of experience and be a college graduate, we can use the principle of inclusion-exclusion.

Given that 66% of employees are college graduates and 65% have more than ten years of experience, we need to calculate the probability of the intersection of these two events.

Let's denote:

P(C) = Probability of being a college graduate = 0.66

P(E) = Probability of having more than ten years of experience = 0.65

P(C ∪ E) = Probability of being a college graduate or having more than ten years of experience = 0.67

Using the principle of inclusion-exclusion, we have:

P(C ∪ E) = P(C) + P(E) - P(C ∩ E)

We need to find P(C ∩ E), which represents the probability of both being a college graduate and having more than ten years of experience.

Rearranging the equation, we get:

P(C ∩ E) = P(C) + P(E) - P(C ∪ E)

Substituting the given values, we have:

P(C ∩ E) = 0.66 + 0.65 - 0.67 = 0.64

Therefore, the probability that a randomly selected employee will have more than ten years of experience and be a college graduate is 0.64.

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Answer:

50% smaller

Step-by-step explanation:

Answer:

-2x-24/6

pass the x susbtrating divided it by 6

a. The measure of <7 is 47 degrees.

b. The equation is written as 47+ 2x -1 = 180

c. The value of x is 67

It is important to note that corresponding angles are simply described as  angles that are formed by corresponding corners when the transversal that is between parallel lines intersect each other.

From the information given, we have that;

<5 and<7 are corresponding angles

Thus,

<7 = 47 degrees

When the expression for angle 6 is 2x - 5, then the equation is;

<5 + <6 = 180 because angles on a straight line equals 180 degrees

We then have;

47+ 2x -1 = 180

collect the like terms, we get;

2x = 180 - 46

Subtract the values

2x = 134

Divide the values

x = 67

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Answer:

0.81

Step-by-step explanation:

The absolute value of the expression is given by:

\(\[\left| \frac{2z_1 7z_2}{2z_1 - 7z_2} \right| = \frac{|k|\cdot |14i - 49k|\cdot |z_1^3|}{|z_1|\cdot |4 - 28ki + 49k^2|}.\]\)

Let's start by simplifying the expression inside the absolute value:

\(\[\frac{2z_1 \cdot 7z_2}{2z_1 - 7z_2}.\]\)

To make progress, we'll multiply both the numerator and denominator by the conjugate of the denominator:

\(\[\frac{2z_1 \cdot 7z_2}{2z_1 - 7z_2} \cdot \frac{2z_1 + 7z_2}{2z_1 + 7z_2}.\]\)

Expanding the numerator, we have:

\(\[2z_1 \cdot 7z_2 \cdot (2z_1 + 7z_2) = 14z_1^2z_2 + 49z_1z_2^2.\]\)

Expanding the denominator, we have:

\([(2z_1)(2z_1) + (2z_1)(7z_2)] + [(7z_2)(2z_1) + (7z_2)(7z_2)] = 4z_1^2 + 14z_1z_2 + 14z_1z_2 + 49z_2^2 = 4z_1^2 + 28z_1z_2 + 49z_2^2.\)

Putting it all together, the expression becomes:

\(\[\frac{14z_1^2z_2 + 49z_1z_2^2}{4z_1^2 + 28z_1z_2 + 49z_2^2}.\]\)

Now, we can take the absolute value:

\(\[\left| \frac{14z_1^2z_2 + 49z_1z_2^2}{4z_1^2 + 28z_1z_2 + 49z_2^2} \right| = \frac{|14z_1^2z_2 + 49z_1z_2^2|}{|4z_1^2 + 28z_1z_2 + 49z_2^2|}.\]\)

Since\($\frac{z_2}{z_1}$\) is pure imaginary, we have \($z_2 = ki z_1$\) for some real number \($k.$\) Substituting this into the expression, we get:

\(\[\frac{|14z_1^2(ki z_1) + 49z_1(ki z_1)^2|}{|4z_1^2 + 28z_1(ki z_1) + 49(ki z_1)^2|}.\]\)

Simplifying, we have:

\(\[\frac{|14kz_1^3i + 49k^2z_1^3i^2|}{|4z_1^2 + 28kz_1^2i - 49k^2z_1^2|} = \frac{|14kz_1^3i - 49k^2z_1^3|}{|z_1^2(4 - 28ki + 49k^2)|}.\]\)

Since\($2z_1 \neq 7z_2,$\) we have \($2 \neq 7ki,$\) which implies \($k \neq \frac{2}{7i}.$\)Therefore, \($4 - 28ki + 49k^2 \neq 0,$ so $z_1^2(4 - 28ki +49k^2) \neq 0,$\) which means we can cancel it from the expression:

\(\[\frac{|14kz_1^3i - 49k^2z_1^3|}{|z_1^2(4 - 28ki + 49k^2)|} = \frac{|14kz_1^3i - 49k^2z_1^3|}{|z_1^2|\cdot |4 - 28ki + 49k^2|}.\]\)

Since \($|ab| = |a|\cdot |b|,$\) we have:

\(\[\frac{|14kz_1^3i - 49k^2z_1^3|}{|z_1^2|\cdot |4 - 28ki + 49k^2|} = \frac{|14ki - 49k^2|\cdot |z_1^3|}{|z_1^2|\cdot |4 - 28ki + 49k^2|}.\]\)

Finally, we can simplify the expression further:

\(\[\frac{|14ki - 49k^2|\cdot |z_1^3|}{|z_1^2|\cdot |4 - 28ki + 49k^2|} = \frac{|k|\cdot |14i - 49k|\cdot |z_1^3|}{|z_1|\cdot |4 - 28ki + 49k^2|}.\]\)

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Resulting function is y = -(1/5)e⁴ˣ - 4, which can be written in the form y = \(ce^{ax}\) + b as y = (-1/5)e⁴ˣ - 4.

To transform the given function y = e⁴ˣ according to the given conditions, we will perform the following steps:

1. Vertically compress With a factor of 5:
y = (1/5)e⁴ˣ

2. Reflect across the x-axis:
y = -(1/5)e⁴ˣ

3. Shift down 4 units:
y = -(1/5)e⁴ˣ - 4

So the resulting function is y = -(1/5)e⁴ˣ - 4, which can be written in the form y = ceᵃˣ + b as y = (-1/5)e⁴ˣ - 4.

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The pool's water is changing height at a pace of 0.283 feet per minute.

Given,

Right circular cylinder shaped pool.

The radius of the pool = 3 feet

The height of the pool = 8 feet

Imagine that 6 cubic feet of water per minute is continuously being poured into a swimming pool in the shape of a right circular cylinder.

We have to find the rate of change of the height of the water in the pool when the depth of the water in the pool is 6 feet;

Here,

Due to the swimming pool's right circular cylinder shape, its volume equals;

V(c) = π × r² ×h

Where r is the radius of the base and h the height

We take differentiation on both sides of the equation to get:

dV/dt  = π × r² × dh/dt

Since the pool is a right circular cylinder and dV/dt is constant at 6 ft3/min, the rate of change in water height in the pool is independent of water height.

Then:

6  = π × r² × dh/dt

dh/dt = 6 / π × 3²

dh/dt = 8/113,04

dh/dt = 0.283 ft/min

Therefore,

The rate of change of the height of the water in the pool is 0.283 feet/min

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When 8.0 X 10 is rewritten to the -2nd in standard form, 800 is obtained by comprehending negative exponents.

The amount of times a number has been multiplied by itself is referred to as an exponent. For instance, 2 to the third (written as 23) equals 2 x 2 x 2 = 8. 23 is not the same as 2 x 3 = 6. Keep in mind that a number raised to the power of one equals itself. Exponent is the process of expressing huge numbers in terms of powers. In other words, exponent refers to the number of times a number has been multiplied by itself. For instance, 6 is multiplied by itself four times, yielding 6 6 6 6. This can be expressed as 64.

given

This number is 10 to the power of 2, as the exponent is 2.

Due to the positive exponent, the answer is a number higher than the origin or base number.

We shift the decimal to the right twice to arrive at our conclusion:

8.0.0 -> 800

When 8.0 X 10 is rewritten to the -2nd in standard form, 800 is obtained by comprehending negative exponents.

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The polynomial function in factored form with real and rational coefficients is: P(x) = (x-2) (x+1) (x^2+9).

For the first polynomial, the given zeros are 0, 4, and √3. To write the polynomial in factored form, we'll use the fact that if x=a is a zero of a polynomial, then (x-a) is a factor. Therefore, the factored form of the polynomial is:

P(x) = (x-0)(x-4)(x-√3) = x(x-4)(x-√3)

For the second polynomial, the given zeros are 2, -1, and 3i. Since polynomials with irrational or complex roots must come in pairs, the conjugate of 3i, which is -3i, is also a zero of the polynomial. Now, we can write the polynomial in factored form:

P(x) = (x-2)(x+1)(x-3i)(x+3i)

Since we need real and rational coefficients, we'll multiply the last two factors to remove the imaginary part:

P(x) = (x-2)(x+1)((x-3i)(x+3i)) = (x-2)(x+1)(x^2+9)

Thus, the polynomial function in factored form with real and rational coefficients is:

P(x) = (x-2)(x+1)(x^2+9)

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