For resonance to occur, the object must experience a frequency equal to its what?


period


wavelength


amplitude


natural frequency

Answers

Answer 1

Answer:

natural frequency

Explanation:

Answer 2

Answer: correct answer is {d}

Explanation: i got it right on my assesment

For Resonance To Occur, The Object Must Experience A Frequency Equal To Its What?periodwavelengthamplitudenatural

Related Questions

do you think your real?

Answers

Answer: Yes I am alive.

Yes I am not a robot

The most powerful empire between the 1500s and 1600s was the __________ Empire.
A.
Ottoman
B.
Mauryan
C.
Roman
D.
Persian

Answers

Answer:

A

Explanation:

Answer:

Ottoman

Explanation:

siri told me after I asked

Why are materials liquids at higher temperatures in terms of Gibbs free energy

Answers

The reason why materials become liquids at higher temperatures can be explained in terms of Gibbs free energy.

At higher temperatures, the entropy or disorder of the material increases, which leads to a decrease in Gibbs free energy. In other words, the system becomes more energetically favorable in the liquid state than in the solid state, resulting in a phase transition from solid to liquid. This is due to the fact that in the liquid state, the molecules have more freedom of movement and can occupy a greater number of microstates, which leads to an increase in entropy and a decrease in Gibbs free energy. Therefore, as the temperature increases, the Gibbs free energy of the liquid state becomes lower than that of the solid state, resulting in a phase transition from solid to liquid.

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Highway safety engineers build soft barriers along the sides of highways so that cars hitting them will slow down at a safe rate. Suppose a car traveling at 110 km/h hits the barrier, and the barrier decreases the car’s velocity at a rate of 32 m/s^2. What distance would the car travel along the barrier before coming to a stop?

Highway safety engineers build soft barriers along the sides of highways so that cars hitting them will

Answers

The distance the car would travel along the barrier before coming to a stop 14.6 m.

What is the distance travelled by the car?

The distance travelled by the car before stopping is determined by applying the following kinematic equation.

v² = u² - 2as

where;

v is the final velocity of the car before stoppingu is the initial velocity of the cara is the acceleration of the cars is the distance travelled by the car before stopping

when the car stops, v = 0

0 = u² - 2as

2as = u²

s = u²/2a

Given;

u = 110 km/h = 30.56 m/s

a = 32 m/s²

s = (30.56²) / (2 x 32)

s = 14.6 m

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An argon gas processor has a first cost of $20,000 with a $5,000 salvage value after 5 years. What is the Book Value at year 3;BV3=? Select one: a. BV3= $13,000 b. BV3= $10,000 c. BV3= $12,000 d. BV3= $11,000 An argon gas processor has a first cost of $20,000 with a $5,000 salvage value after 5 years. What is the Depreciation at year 3, D3=? Select one: a. D3= $4,000 b. D3= $3,000 c. D3= $2,000 d. D3= $5,000

Answers

To calculate the book value at year 3 (BV3), we need to determine the accumulated depreciation at year 3. The depreciation is calculated by subtracting the salvage value from the initial cost and dividing it by the number of years.

Initial cost: $20,000

Salvage value: $5,000

Number of years: 5

Depreciation per year = (Initial cost - Salvage value) / Number of years

Depreciation per year = ($20,000 - $5,000) / 5 = $3,000

Accumulated depreciation at year 3 = Depreciation per year * Number of years

Accumulated depreciation at year 3 = $3,000 * 3 = $9,000

Book value at year 3 = Initial cost - Accumulated depreciation at year 3

Book value at year 3 = $20,000 - $9,000 = $11,000

Therefore, the Book Value at year 3 (BV3) is $11,000 (option d).

To calculate the depreciation at year 3 (D3), we can simply use the depreciation per year, which is $3,000. Therefore, the Depreciation at year 3 (D3) is $3,000 (option b).

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T/F: will density be higher or lower if there are air bubbles on an object

Answers

If there are air bubbles on an object, then the density will be lower.

If there are air bubbles on an object, the density of the object will be lower. In general, density is defined as the amount of mass present in an object per unit volume of the object.

The volume of the object is fixed and the amount of mass present in it decides its density.In the case of an object containing air bubbles, the volume of the object remains the same, but the amount of mass present in it is less due to the air bubbles. This decrease in mass results in a lower density of the object.Therefore, the given statement that the density will be lower if there are air bubbles on an object is True.

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If an object is in motion, then the object will ______
because ______________________.

Answers

This is Newton’s first law of motion. If an object is in motion it stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

Answer:

If an object is in motion, then the object will stay in motion because they go the same direction unless acted upon by an unbalanced force.

Explanation:

i got it right . :)

Your new motorcycle weighs 2450 N.
What is
its mass in kilograms?


i understand the answer is 250kg because mass times gravity thing but why isn’t the answer negative cause gravity pulls down so wouldn’t be Negative answer not a positive answer

i was taught FW is always negative why isn’t it negative here

Answers

Answer:

Explanation:

The negative only matters reallly if you are dealing with a 2d system. I could even define down as positive and up as negative. However, usually you are taught that down is negative. It really doesn't matter because a force is a force. It is only given a direction relative to another force or vector direction.

Two loudspeakers (A and B) are 3.20m apart and emitting a sound with a frequency of 400Hz. An observer is 2.10m directly in front of A. If the speed of sound in this room is 340m/s will the observer hear a loud sound or a quiet sound?

Answers

Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

\(d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m\)

Next, you calculate the wavelength of the sound waves by using the following formula:

\(\lambda=\frac{v_s}{f}\)

vs: speed of sound =  343 m/s

f: frequency of the waves = 400Hz

λ: wavelength

\(\lambda=\frac{343m/s}{400Hz}=0.8575m\)

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

\(\Delta d=3.827m-2.10m=1.727m\)

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

\(\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2\)

Then, there will be a constructive interference, and the sound who the observer hears is loud.

an object of mass 2000m covers a max vertical distance from the ground calculate the velocity with which it was thrown. take g= 10m/s^2​

Answers

An object of mass m to covers 2000m max vertical distance from the ground thrown at the velocity of 197 m/s

What is velocity & Acceleration ?

Velocity is "rate of change of displacement with respect to time".

i.e. v= dx/dt

it is also defined as displacement over time. i.e. v=Displacement/Time.

Velocity shows how much distance can be covered in unit time. It's SI unit m/s.

Acceleration is rate of change of velocity with respect to time.

i.e. a = dv/dt

if an object changes its velocity in short time, we can say that it has grater acceleration.

a= dv/dt =Δv/Δt = \(\frac{v_{2} - v_{1}}{t_{2} - t_{1}}\)  

where    v₂= initial velocity

              v₁= final velocity

              t₂= initial time

              t₁ = final time  

Given,

Distance = 2000m

Acceleration due to gravity 10 m/s²

By the equation of kinematics,

v² = u² + 2as....... 1)

where v = final velocity

           u = Initial velocity

           a = acceleration

           s = distance

in this case when an object of mass m is thrown vertically it attains max distance at that point final velocity becomes zero. We are performing this experiment on earth so our acceleration will be acceleration due to gravity g.

ie. v=0 and a = g

equation 1) becomes

0=u² + 2×9.8×2000

u²+ 39200 = 0

u = √39200 = 197 m/s

u= 197 m/s

Hence calculated velocity with which it was thrown is 197 m/s

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The engine of the car develops a driving force of 4000N. Air resistance also acts on the car, with a force of R. If the car has a mass of 1000kg, and is accelerating at 1.5m/s^2, calculate the magnitude of R.

Answers

Answer:

R = -2500N

Explanation:

Use formula ΣF = Ma. We can split the Net Force into two parts: Fe - Ff  =  Ma.

Fe is the force developed by the engine: 4000N

Ff (R) is the air resistance projected on the vehicle. This is the value we're looking for.

Mass: 1000kg

Acceleration: 1.5m/s^2

Next, just plug in the values and solve.

▪4000N - Ff  =  (1000kg)(1.5m/s^2)

▪Ff = 1500N - 4000N

▪Ff = -2500N

R = -2500N.

The air resistance acting on the car is R = -2500N.

What are the temperature and energy changes for segment A (red line) on the heating curve for water?

What are the temperature and energy changes for segment A (red line) on the heating curve for water?

Answers

The region marked segment A occurs at 100 degrees Celsius and is the latent heat of vaporization.

What is the latent heat of vaporization?

The latent heat of vaporization is the amount of heat energy required to change the state of a substance from a liquid to a gas (vapor) at a constant temperature and pressure.

During the phase transition, the energy supplied to the substance is used to overcome the intermolecular forces of attraction between the particles, which allows the particles to escape from the liquid phase and enter the gaseous phase. This results in an increase in the internal energy of the substance, but with no change in temperature.

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why is it important for the input voltage of a transformer to be ac?

Answers

The input voltage of a transformer must be AC (alternating current) because transformers rely on the property of AC for effective electromagnetic induction, which is essential for their operation.

Electromagnetic induction occurs when a varying magnetic field induces an electric voltage in a conductor. In the case of a transformer, an alternating current passing through the primary coil generates a changing magnetic field, which, in turn, induces a voltage in the secondary coil.

AC is particularly well-suited for this process due to its constant change in direction, resulting in a continuously fluctuating magnetic field. This dynamic magnetic field induces a voltage in the secondary coil, facilitating efficient energy transfer from the primary coil to the secondary coil.

Conversely, if a transformer were to be powered by DC (direct current), the magnetic field produced by the unidirectional current would remain constant. As a result, there would be no continuous alteration in the magnetic field to induce a voltage in the secondary coil, severely limiting the transformer's functionality.

Hence, the utilization of AC input voltage is critical for transformers as it enables efficient energy transfer and voltage transformation between various circuits or power systems.

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In a sugar factory bagasse (the remains of the cane after the juice is extracted) is burned to provide electricity. The types of energy involved are W thermal energy X chemical energy Y electrical energy Z kinetic energy. In what order are these forms of energy converted in this process?A) WXZYB) XWZYC) WZXYD ZXWY

Answers

Given:

Thermal energy is denoted by W

Chemical energy is denoted by X

Electrical energy is denoted by Y

Kinetic energy is denoted by Z

To find the order of energy while converting bagasse to electricity.

Explanation:

The bagasse has chemical energy stored in it.

The bagasse is burned, so chemical energy gets converted into thermal energy.

The thermal energy gets converted into kinetic energy.

The kinetic results in the motion of electrons.

Thus, producing electrical energy.

Hence, the conversion order is XWZY

Sarah's twist angular momentum increases from 0 to 50 kg x m^2/s in 0.25 s as she initaties a twisting jump on the ice. During this 0.25 s, her moment of inertia about her twist axis is 2.2 kg x m^2.
A. How large is the average torque that produces this change in angular momentum?
B. How fast is Sarah's twist angular velocity at the end of the 0.25 s?

Answers

To calculate the average torque that produces this change in angular momentum, we can use the formula: Average Torque = Change in Angular Momentum / Time, Change in Angular Momentum = 50 kg x m^2/s (final) - 0 kg x m^2/s (initial) = 50 kg x m^2/s and Time = 0.25 s

Average Torque = (50 kg x m^2/s) / 0.25 s = 200 Nm
The average torque that produces this change in angular momentum is 200 Nm.
Angular velocity at the end of the 0.25 s, we can use the formula:
Angular Velocity = Angular Momentum / Moment of Inertia
Angular Momentum = 50 kg x m^2/s
Moment of Inertia = 2.2 kg x m^2
Angular Velocity = (50 kg x m^2/s) / (2.2 kg x m^2) ≈ 22.73 rad/s
At the end of the 0.25 s, Sarah's twist angular velocity is approximately 22.73 rad/s.

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Convert 7.5 g/cm3 to kg/m3

Answers

Answer:

7500

Explanation:

multiply the mass / volume value by 1000

what effect does an unbalanced force have on an object?

Answers

Answer:

An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.

A passenger aeroplane accelerates from rest along a runway. It accelerates at a uniform rate for 3.5s. At this point it reaches a speed of 84 m/s and then takes off. Calculate the acceleration of the aeroplane along the runway.

Answers

Please find attached photograph for your answer. Do comment whether it is useful or not. Mark as Brainliest if you like my answer.

A passenger aeroplane accelerates from rest along a runway. It accelerates at a uniform rate for 3.5s.

What force is responsible for how magma flows and rocks stack up on top of one another?

Question 6 options:

Electroweak and Strong


Nuclear


Electromagnetic


Gravitational

Answers

Gravitational force is responsible for how magma flows and rocks stack up on top of one another.

Gravitational force is the force hat attracts all objects to the center of the earth. The force of gravity accounts for the fact that when an object is thrown up, it falls back to the earth.

The force that is responsible for how magma flows and rocks stack up on top of one another is the gravitational force.

Hence, it is the gravitational force that is responsible for how magma flows and rocks stack up on top of one another.

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A bike starts from rest and accelerates to a speed of 15 m/s
over the course of 5 seconds. The average acceleration of the
bike is m/s2

Answers

Answer:

please find attached pdf

Explanation:

The picture below shows a person swinging a toy plane attached to a string in
uniform circular motion,
Which vector points in the direction of the centripetal acceleration of the
plane?

The picture below shows a person swinging a toy plane attached to a string inuniform circular motion,Which

Answers

Answer:The answer is option C, the point A

Explanation:Just did it

c. A  is the correct answer.

What is centripetal acceleration?

It is the acceleration of a body traversing a circular path. Because velocity is a vector quantity (that is, it has both a magnitude, the speed, and a direction), when a body travels on a circular path, its direction constantly changes and thus its velocity changes, producing an acceleration.

According to the question.

In the picture , a person swinging a toy plane attached to a string in uniform circular motion.

The direction of velocity is perpendicular to the direction of the position and tangent to the circular orbit.

When an object moves in a circular orbit, the direction of the velocity changes and the speed may change as well.

Direction of velocity is constantly changing.

The tangent at any point gives the direction of velocity at that point, where as acceleration is always directed towards the recent in a uniform circular motion.

Therefore, vector A  points in the direction of the centripetal acceleration of the plane.

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A cube measures 3cm on each side has a mass of 25 grams. what it its density and relative density.​

Answers

Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels

A ball is thrown down from the edge of a cliff on the moon (g = 1.6 m/s2, down) with a speed of 10 m/s. If the cliff is 150 m tall, how long does it take the ball to hit the lunar surface?

Answers

The time taken by the ball to hit the lunar surface is 13.7 seconds.

What is free fall?

Free fall is the motion of a body that is allowed to fall freely under the influence of gravity alone.

Free-falling objects are given zero velocity initially, but once they start falling, they are accelerated by a factor known as acceleration due to gravity, g.

The acceleration due to gravity is a constant on the earth but varies from one planetary body to another.

The acceleration due to gravity on the earth's surface has a value of 9.81 m/s².

The acceleration due to gravity in the moon, g = 1.6 m/s².

Calculating the time taken for the ball to hit the lunar surface:

time taken, t = √(2 * h / g)

h = 150 m

t = √(2 * 150 / 1.6)

t = √(300 / 1.6)

t = 13.7 seconds.

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biot-savart law: a point charge q moves on the x-axis in the positive direction with a speed of a point p is on the y-axis at the magnetic field produced at point p, as the charge moves through the origin, is equal to when the charge is at what is the magnitude of the magnetic field at point p? (μ0

Answers

The magnitude of the magnetic field at point P, located on the y-axis, due to a point charge q moving along the positive x-axis with speed v when the charge is at the origin, can be determined using the Biot-Savart law.

The Biot-Savart law describes the magnetic field produced by a current-carrying wire. In this case, we can consider the point charge q as a moving point source of current. The Biot-Savart law states that the magnetic field at a point P due to a current element dl is given by:

\(\[\vec{B} = \frac{\mu_0}{4\pi} \frac{q\vec{v} \times \vec{r}}{r^3}\]\)

where \(\(\vec{B}\)\) is the magnetic field,\(\(\mu_0\)\) is the permeability of free space, q is the charge, \(\(\vec{v}\)\) is the velocity of the charge,  \(\(\vec{r}\)\)  is the position vector from the charge to the point P, and r is the magnitude of  \(\(\vec{r}\)\) . In this scenario, the charge q is at the origin (x = 0) and moves along the positive x-axis. The position vector \(\(\vec{r}\)\) from the charge to point P is given by \(\(\vec{r} = y\hat{j}\)\), where y is the distance of point P from the origin. The velocity of the charge is \(\(\vec{v} = v\hat{i}\)\), where v is the speed of the charge. Plugging these values into the Biot-Savart law, we get:

\(\[\vec{B} = \frac{\mu_0}{4\pi} \frac{qv(y\hat{j}) \times (y\hat{j})}{(y^2)^{3/2}}\]\)

Simplifying the expression, we find that the magnitude of the magnetic field at point P is given by:

\(\[B = \frac{\mu_0qv}{4\pi y^2}\]\)

Therefore, the magnitude of the magnetic field at point P, as the charge moves through the origin, is inversely proportional to the square of the distance y from the origin.

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Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.

Answers

No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.

This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.

i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.

ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.

The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.

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(b) The student's results are shown in Figure 2.
45
angle of
refraction in
degrees (º)
40
35-
30-
25
20
15
10-
5-
20
40
80
angle of incidence in degrees (º)
Figure 2
Explain whether any of the readings are anomalous.
x
09
(2)

Answers

Answer:

tiny Tim once said "drop out of school"

Explanation:

be a mechanic or an architect

a planet with the same mass as earth orbiting at a distance of 1 au from a star with thirty six times the sun's mass.

Answers

To determine the orbital period of a planet with the same mass as Earth orbiting at a distance of 1 AU from a star with thirty-six times the mass of the Sun, we can use Kepler's third law of planetary motion.

Kepler's third law states that the square of the orbital period (T) is proportional to the cube of the semi-major axis (a) of the orbit. The semi-major axis of the Earth's orbit is approximately 1 AU, which is equivalent to about 149.6 million kilometers. Given: Mass of the star (M_star) = 36 times the mass of the Sun. To calculate the orbital period, we need to find the value of the semi-major axis of the planet's orbit around the star. Using Kepler's third law equation: T^2 = (4π^2 / G * M_star) * a^3 Where: T is the orbital period in seconds, G is the gravitational constant (approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2), M_star is the mass of the star in kilograms, a is the semi-major axis of the orbit in meters. We need to convert the distance from AU to meters: 1 AU = 149.6 million kilometers = 149.6 x 10^9 meters. Substituting the values: T^2 = (4π^2 / (6.67430 x 10^-11) * (36 * (1.989 x 10^30)) * (149.6 x 10^9)^3 Simplifying the equation and solving for T: T^2 = 4π^2 * (36 * (1.989 x 10^30)) * (149.6 x 10^9)^3 / (6.67430 x 10^-11) Taking the square root of both sides to find T: T = √(4π^2 * (36 * (1.989 x 10^30)) * (149.6 x 10^9)^3 / (6.67430 x 10^-11)) Evaluating this expression will give us the orbital period of the planet.

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Final answer:

To calculate the gravitational force between a planet with the same mass as Earth and a star with thirty-six times the sun's mass at a distance of 1 AU, we can use Newton's law of universal gravitation.

Explanation:

If a planet with the same mass as Earth orbits at a distance of 1 AU from a star with thirty-six times the sun's mass, we can calculate the gravitational force between them using Newton's law of universal gravitation. The formula is F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two bodies, and r is the distance between them.

In this case, the mass of the planet is the same as Earth's mass (let's call it m), the mass of the star is 36 times the sun's mass (36M), and the distance between them is 1 AU. Plugging these values into the formula, we get F = G * (m * 36M) / (1 AU)^2.

To find the force, we need the values of G and the masses. The value of G is approximately 6.67430 × 10^-11 N(m/kg)^2. The mass of the sun is about 1.989 × 10^30 kg. Substituting these values, we can calculate the force between the planet and the star.

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A 3-column table with 1 row. The first column titled distance travelled (meters) has entry 6. 1. The second column labeled lower track elapsed time (seconds) has entry 4. 92. The third column labeled higher track elapsed time (seconds) has entry 3. 36. Based on the time measurements in the table, what can be said about the speed of the car on the lower track as compared to the higher track? How can the reasoning for the above answer be best explained? On the higher track, the elapsed time is. Calculate speeds for each track. How much faster was the car on the higher track than the lower track?.

Answers

Answer:

B,A,A

Explanation:

Answer:

Other guy is correct b,a,a

Explanation:

imagine no girls awnser this question ://

Answers

Answer:

im confused

Explanation:

wdym I am answering rn

Which object will have greater acceleration? Why?​

Which object will have greater acceleration? Why?

Answers

Answer:

Object D

Explanation:

Use Newton's Second Law to determine the acceleration that each object has.

F = ma

The force applied in both cases is 50 N, but the mass for object C and object D is different.

Let's start with object C first:

F = ma 50 N = 10 kg · a 50 = 10a 5 = a

The acceleration object C undergoes is 5 m/s².  

Now let's calculate object D next:

F = ma 50 N = 2 kg * a 50 = 2a25 = a

The acceleration object D undergoes is 25 m/s².

Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.

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