For a power system, the reasons of the fault level calculations are: (a) Select circuit-breaker or fuses (b) Set protection system Modify the system to reduce fault level All the above (e) Both (a) and (b) C10. For a three phase transformer, V1, 11, and Nu are the line voltage, line current and phase winding turn of the primary side; and V2, 12, and Nz are the line voltage, line current and phase winding turn of the secondary side. The transformer, with a variety of winding connections such as Y-Y connection, D- D connection, D-Y connection and Y-D connection, has the following common formulae: V (a) 12 N V 1 N, V1, (b) 11 11 SININ (c) 12 V 1 13N, N N 13N, (d) V2 1 C11. In order to reduce power losses, power electronics devices (transistors) are usually operated in the following regions: (a) Active and saturation Active and cut-off Saturation and cut-off Saturation and active
Answers
Fault level calculations in a power system are carried out to select appropriate circuit breakers or fuses and set up a protection system, ensuring safe and efficient operation.
The fault level calculations in a power system serve multiple purposes, including: (a) selecting circuit-breakers or fuses capable of handling the fault current, (b) setting up a protection system to detect and isolate faults, and (c) modifying the system to reduce the fault level. Therefore, the correct answer is (e) Both (a) and (b).
For a three-phase transformer with various winding connections such as Y-Y, D-D, D-Y, and Y-D, the following common formulae apply:
(a) V1 / V2 = N1 / N2, where V1 and V2 are the line voltages and N1 and N2 are the phase winding turns of the primary and secondary sides, respectively.
(b) I1 / I2 = N2 / N1, where I1 and I2 are the line currents of the primary and secondary sides, respectively.
(c) V2 / V1 = N2 / (N1 / √3), where N is the number of turns.
(d) V2 / I2 = 1 / C, where C is the coupling coefficient.
To reduce power losses, power electronic devices (transistors) are typically operated in the active and saturation regions, where they exhibit good efficiency and control over power flow. Therefore, the correct answer is (a) Active and saturation.
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Related Questions
what's better than a trophy truck and an ultra 4
Answers
Answer:
A ultra 4. that would be amazing to have that.
Answer:
I have know idea
Explanation:
List 5 cutting actions of sawing machines
pls help
Answers
Thin metal blades or flexible bands with teeth on one edge, thin grinding wheels, or thin metal disks with teeth on their edges can all be used as sawing machine cutting tools.
What is sawing machine?Sawing machine is defined as a device for cutting forms out of raw material plates or cutting apart bars of material. It is used to sever material, usually wood, but occasionally metal or stone. The material is cut by pressing the toothed edge against it and pushing it swiftly forward, slowly backward, or continually forward.
Rotating blades, reciprocating blades, and circulating blades are the three basic types of power sawing machines.
Thus, thin metal blades or flexible bands with teeth on one edge, thin grinding wheels, or thin metal disks with teeth on their edges can all be used as sawing machine cutting tools.
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In a certain balanced three phase system each line current is a 5a and each line voltage is 220v . What is the approximate real power if the power factor is 0.7
Answers
Answer:
1,334
Explanation:
In a certain balanced three phase system each line current is a 5a and each line voltage is 220v . 3.87 kilowatts is the approximate real power if the power factor is 0.7.
The idea of real power in a balanced three-phase system is critical in electrical power systems. It denotes the actual power transferred and used by the system, which is usually measured in kilowatts (kW) or megawatts (MW). Understanding real power is critical for evaluating electrical system efficiency and performance. Real power is the component of power in a balanced three-phase system that does useful work, such as operating motors, generating heat, or powering appliances.
Real Power (P) = √3 × Line Current (I) × Line Voltage (V) × Power Factor (PF)
P = √3 × 5 A × 220 V × 0.7
P = 3.87 kilowatts (kW)
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Calculate the compression resistance of a compound column consisting of UC-305x305x198 with one cover plate
of 350mm x 20mm on each flange and having a length of 5m. assume that bottom of column is fixed and top is
pinned in both x & y axis?
Answers
Answer:
350×305π{^ not sure my answer please follow me
a transformer has 880 turns and 62 turns for the primary and secondary respectively. with no load on the secondary and a primary voltage of 2058.06 v, what is the output voltage of the secondary?
Answers
In a secondary coil, there are twice as many turns as there are in a main coil. A transformer with a turns ratio of 2:1 will have 100 primary turns and 50 secondary turns.
As a result, 60 volts will be impressed on the secondary if the primary is at 120 volts. Therefore, by multiplying both sides by N p, we may find N s, which equals N pV s over V p. The voltage drop is produced by a step-down transformer, which has a secondary coil with only 30 turns and 400 turns multiplied by 9.00 volts divided by 120 volts.
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A highway has the following pavement design
daily traffic: 300 single axles at 10,000 lb each, 120
single axles at 18,000 lb each, 100 single axles at
23,000 lb each, 100 tandem axles at 32,000 lb each,
30 single axles at 32,000 lb each, and 100 triple axles
at 40,000 lb each. A flexible pavement is designed to
have 4 inches of sand-mix asphalt wearing surface, 6
inches of soil-cement base, and 7 inches of crushed
stone subbase. The pavement has a 10-year design
life, a reliability of 85%, an overall standard
deviation of 0.30, drainage coefficients of 1.0, an
initial PSI of 4.7, and a TSI of 2.5. What is the
minimum acceptable soil resilient modulus?
Answers
Answer:
pay attention in class how about that
Explanation:
thats the answer
A. A solidified lava flow containing zircon mineral crystals is present in a sequence of rock layers that are exposed in a hillside.A mass spectrometer analysis was used to count the atoms of uranium-235 and lead-207 isotopes in zircon samples from thelava flow. The analysis revealed that 71% of the atoms were uranium-235, and 29% of the atoms were lead-207. Refer toFIGURE 8.11 to help you answer the following questions.1. About how many half-lives of the uranium-235to lead-207 decay pair have elapsed in the zircon crystals? ______________2. What is the absolute age of the lava flow based onits zircon crystals? Show your calculations.3. What is the age of the rocklayers above the lava flow? _______________4. What is the age of the rocklayers beneath the lava flow? _______________B. Astronomers think that Earth probably formed at the same time as
Answers
Answer:
1. 0.494
2. = 352.299 million years
3. It is between 0 years to 352.299 million years
4. greater than the 352.299 million years.
Explanation:
Given
Uranium 235 ———— lead 207( zircon sample)
t= 0 100%. 0%
t= t. 71%. 29%
1)- half lives elapsed = n
(1/2)n = 0.71
By taking log and solving n = 0.494
No of half lives = 0.494
2) Calculating the age of the larva
- age of lava flow = half life of uranium 235 x n
= 713 x 0.494
= 352.299 million years
3)- The rock layers was created above this lava flow is of later occurrence so the age will be lower than that of the age of the lava flow so the age of rock over the lava flow will lower than the 352.299 million years it will be in between 0 years to 352.299 million years.
4)- The rock layers created underneath this lava flow is of earlier occurrence so its age is more than that of the age of the lava flow so the age of rock will more than the lava flow is greater than the 352.299 million years.
B. The astronomers think the earth was created as all of the other rock materials in our solar system, including the oldest meteorites. The oldest meteorites ever found on Earth contain nearly equal amounts of both Uranium-238 and Lead-206.
The number of half-lives of the uranium-235to lead-207 decay pair have elapsed in the zircon crystals is; 0.494
What is the number of half lives?We are given;
The atoms of Uranium-235 and lead-207 which made up the zircon sample.
At t = 0; Uranium-235 is 100% while lead-207 is 0%
At t = t; Uranium-235 is 71% while lead-207 is 29%
1) Let the half lives that elapsed be n. Thus;
(¹/₂)ⁿ = 0.71
n*log0.5 = log 0.71
n = (log 0.71)/(log 0.5)
n = 0.494
Thus;
Number of half lives = 0.494
2) Formula to get the absolute age of the larva is;
Absolute age age of lava flow = half life of uranium-235 * n
The half life of uranium-235 is 713 million years. Thus;
Absolute age age of lava flow = 713 * 0.494
Absolute age of lava flow = 352.22 million years
3) The rock layers above the lava flow were created after the lava flow and so the age will be lower than that of the age of the lava flow. Thus, it's age will be between 0 years and 352.299 million years.
4) A: The rock layers beneath the lava flow were in existence earlier than the lava flow and as such, the age of rock layers beneath the lava flow will be greater than 352.22 million years.
B; The astronomers think the earth was created as all of the other rock materials in our solar system.
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draw the starting materials needed to synthesize the following compound using an aldol or similar reaction.
Answers
To synthesize the given compound using an aldol or similar reaction, the starting materials required are an aldehyde and a ketone or an enolizable carbonyl compound.
An aldol reaction is a type of organic reaction where an enolate ion reacts with a carbonyl compound to form a β-hydroxyaldehyde or β-hydroxyketone. The starting materials for this reaction are an aldehyde and a ketone or an enolizable carbonyl compound.The aldehyde provides the carbonyl group, while the ketone or enolizable carbonyl compound provides the α-carbon for the enolate ion formation. The enolate ion is formed by removing the α-hydrogen of the ketone or enolizable carbonyl compound. Once the enolate ion is formed, it can attack the carbonyl group of the aldehyde to form the β-hydroxyaldehyde or β-hydroxyketone. The reaction is called an aldol reaction when the carbonyl compound used is an aldehyde.
The starting materials needed to synthesize the given compound using an aldol or similar reaction are specific to the reaction conditions and the desired product. If the desired product is a β-hydroxyaldehyde, then the starting materials required are an aldehyde and a ketone or an enolizable carbonyl compound. For example, formaldehyde and acetone can be used to synthesize 3-hydroxybutanal. If the desired product is a β-hydroxyketone, then the starting materials required are a ketone and an enolizable carbonyl compound. For example, acetone and benzaldehyde can be used to synthesize 3-phenyl-2-butanone. The choice of starting materials can also be influenced by the reaction conditions. For example, in a crossed aldol reaction, where two different carbonyl compounds are used, the enolate ion is formed from the carbonyl compound that is more acidic. In this case, the starting materials required are two carbonyl compounds, and the reaction conditions should be chosen accordingly.
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In poor weather you should___ your following distance
Answers
(a) (6 points) Find the integer a in {0, 1,..., 26} such that a = -15 (mod 27). Explain. (b) (6 points) Which positive integers less than 12 are relatively prime to 12?
Answers
a. a = 12 is the solution to the given congruence relation. b. the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.
(a) The main answer: The integer a that satisfies a ≡ -15 (mod 27) is 12.
To find the value of a, we need to consider the congruence relation a ≡ -15 (mod 27). This means that a and -15 have the same remainder when divided by 27.
To determine the value of a, we can add multiples of 27 to -15 until we find a number that falls within the range of {0, 1,..., 26}. By adding 27 to -15, we get 12. Therefore, a = 12 is the solution to the given congruence relation.
(b) The main answer: The positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.
Supporting explanation: Two integers are relatively prime if their greatest common divisor (GCD) is 1. In this case, we are looking for positive integers that have no common factors with 12 other than 1.
To determine which numbers satisfy this condition, we can examine each positive integer less than 12 and calculate its GCD with 12.
For 1, the GCD(1, 12) = 1, which means it is relatively prime to 12.
For 2, the GCD(2, 12) = 2, so it is not relatively prime to 12.
For 3, the GCD(3, 12) = 3, so it is not relatively prime to 12.
For 4, the GCD(4, 12) = 4, so it is not relatively prime to 12.
For 5, the GCD(5, 12) = 1, which means it is relatively prime to 12.
For 6, the GCD(6, 12) = 6, so it is not relatively prime to 12.
For 7, the GCD(7, 12) = 1, which means it is relatively prime to 12.
For 8, the GCD(8, 12) = 4, so it is not relatively prime to 12.
For 9, the GCD(9, 12) = 3, so it is not relatively prime to 12.
For 10, the GCD(10, 12) = 2, so it is not relatively prime to 12.
For 11, the GCD(11, 12) = 1, which means it is relatively prime to 12.
Therefore, the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.
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Calculate the terminal velocity and the minimum fluidization velocity of filter sand with an effective size of 0. 50 mm, a uniformity coefficient of 1. 5, a specific gravity of 2. 63, and a porosity of 0. 45? Also, determine the appropriate backwash rate at a temperature of 5 and 35 0C
Answers
For 5°C and For 35°C the backwash velocity can be between 1.5-2 times the minimum fluidization velocity. backwash rate will be between 0.069 m/s and 0.092 m/s for For 5°C and 0.078 m/s and 0.104 m/s For 35°C.
The terminal velocity and minimum fluidization velocity of filter sand can be calculated using the following equations:
Terminal velocity (Vt):
Vt = [4 × (ρp - ρf) × g × dp²] / (3 × Cd × ρf)
Minimum fluidization velocity (Umf):
Umf = [((1 - ε) × g × dp³ × (ρp - ρf)) / (150 × μ × ε³)]¹/⁴
Where:
ρp is the density of the filter sand particles (assumed to be 2650 kg/m³)
ρf is the density of the fluid (water, assumed to be 1000 kg/m³)
g is the acceleration due to gravity (9.81 m/s²)
dp is the effective diameter of the filter sand (0.50 mm)
Cd is the drag coefficient (assumed to be 0.44 for a smooth sphere)
ε is the porosity of the filter bed (0.45)
μ is the dynamic viscosity of the fluid (1.787 x 10⁻³ Pa s at 5°C, and 1.138 x 10⁻³ Pa s at 35°C)
Substituting the given values, we get:
For 5°C:
Vt = [4 × (2650 - 1000) × 9.81 × (0.0005)²] / (3 × 0.44 × 1000)
= 0.037 m/s
Umf = [((1 - 0.45) × 9.81 × (0.0005)³ × (2650 - 1000)) / (150 × 1.787 × 10⁻³ × 0.45³)]¹/⁴
= 0.046 m/s
Backwash velocity can be between 1.5-2 times the minimum fluidization velocity, thus the appropriate backwash rate will be between 0.069 m/s and 0.092 m/s.
For 35°C:
Vt = [4 × (2650 - 1000) × 9.81 × (0.0005)²] / (3 × 0.44 × 1000)
= 0.042 m/s
Umf = [((1 - 0.45) × 9.81 × (0.0005)³ × (2650 - 1000)) / (150 × 1.138 x 10⁻³ × 0.45³)]¹/⁴
= 0.052 m/s
Backwash velocity can be between 1.5-2 times the minimum fluidization velocity, thus the appropriate backwash rate will be between 0.078 m/s and 0.104 m/s.
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if a binary signal is sent over a 3-khz channel whose signal-to-noise ratio is 20 db, what is the maximum achievable data rate?
Answers
19.97kbps is the maximum achievable data rate.
The maximum data rate in a noisy channel as = B*log_2^(1+S/N)
where B is the bandwidthS/N is the signal-to-noise ratio. Usually, S/N is given in "decibel", not just a ratio. decibel is calculated by dB=10log_10^(S/N)
Therefore, we get S/N first by 20dB=10log_10^(S/N) ==> S/N=10^2=100
Substitude S/N
we get the maximum bps as 3k*log2^(1+S/N)=
3log2^101kbps = 19.97kbps.
The maximum achievable data rate is 19.97kbps.
What are Binary signals ?
The binary signal has only two possible values, making it the simplest signal of any kind that may be used to carry messages. The binary numbers, or bits, 1 and 0, are used to represent these values. A simple method of generating a random binary signal is to take Gaussian white noise, filter the noise for the desired spectra and then convert the noise to a binary signal by taking the sign of the filtered signal.
The data rate is the number of bits transmitted per second from one device to another or across a network. Typically, data rates are expressed in bits per second or bytes per second. Bit rate is defined as the transmission of a number of bits per second. Baud rate is defined as the number of signal units per second . Bit rate is also defined as per second travel number of bits. Baud rate is defined as the number of signal units per second. Baud rate is also defined as per second number of changes in signal. Baud rate can determine the amount of bandwidth necessary to send the signal.
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The maximum achievable data rate is 19.97kbps. The binary signal is the simplest signal that may be used to transmit messages because there are only two possible values for it.
What are binary signals?The binary signal is the simplest signal that may be used to transmit messages because there are only two possible values for it. These values are represented by the bits 1 and 0, which are binary numbers. Determining Gaussian white noise, filtering it for the desired spectra, and then converting the noise to a binary signal by taking the sign of the filtered signal are three straightforward ways to create a random binary signal. The amount of bits sent from one device to another or via a network in a second is known as the data rate. The most common units for data rates are bits per second or bytes per second. The transmission of a certain number of bits per second is referred to as bit rate.The maximum data rate in a noisy channel as = B*log_2^(1+S/N)
where B is the bandwidth
S/N is the signal-to-noise ratio. Usually, S/N is given in "decibel", not just a ratio. decibel is calculated by dB=10log_10^(S/N)
Therefore, we get S/N first by 20dB=10log_10^(S/N) ==> S/N=10^2=100
Substitude S/N
we get the maximum bps as 3k*log2^(1+S/N)=
3log2^101kbps = 19.97kbps.
The maximum achievable data rate is 19.97kbps.
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when welding which steps should be taken to protect the welder and/or others in the area
Answers
Answer:
eye protection safety gloves and rubber shoes and a safe ground
Explanation:
list the components of a typical Foundation drainage system and their functions.
Answers
Explanation:
In this series, the professionals at the B.O.L.D. Company will take you through the process of building a custom home in the Greater Cincinnati – Northern Kentucky area. From plan and lot selection, to mortgage approval, to the actual construction, we’ll take you behind-the-scenes each week for an inside look at a different part of the process.
Class II locations are those tha are hazardous because of the presence of ________________.
500.5 (C)
Answers
According to the National Electrical Code (NEC) 500.5(C), Class II locations are those that are hazardous because of the presence of combustible dust.
Class II locations are those that are hazardous because of the presence of combustible dusts. This is defined in section 500.5 (C) of the National Electrical Code (NEC). Combustible dusts can ignite and cause fires or explosions if they are not properly managed and controlled. Examples of materials that can create combustible dusts include grain, sugar, metals, and plastics. Special electrical equipment and wiring methods are required in Class II locations to prevent sparks and arcs from igniting the dust.
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Choose Odd one out of the options ?
A) PSRQ
B) SVUT
C) MNPO
D) KNML
Answers
3Px=y−y2p2
first order higher dgree
Answers
Answer:
the order higher is 3p79g5t88=yv5379
Your by-laws provide for what trade classifications?
Answers
Your by-laws provide a kind of trade classification known as Harmonized System, Standard International Trade Classification and North American Industry Classification System,
What are trade classifications?Trade classification is the process of categorizing goods and services into different groups based on various criteria, such as their nature, purpose, or industry. This eases the process of trade by creating standardized categories that can be used to track and analyze trade activities.
There are several different trade classification systems used around the world. Harmonized System is a standardized system of names and numbers that are used to classify products in international trade. There are 21 sections that allow for categorizations.
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The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint o. determine the magnitude r of the resultant r of the two forces and the angle θ which r makes with the positive x axis (measured counterclockwise from the x axis).
Answers
\alpha = one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN
sin \beta /3 = sin(eighty)/three.304 = 63.4 stages
3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4
Which of the following is not a source of income?
Answers
Answer:
the answer is the "income tax"
Answer:
The correct answer would be:Income tax.
Explanation:
Hoped I helped!! :)
An aircraft engine operates on a simple ideal Brayton Cycle with a pressure ratio of 10. Heat is added to the cycle at a rate of 500 kW; air passes through the engine at a rate of 1 kg/s; and the air at the beginning of the compression is at 70 kPa and 0oC. Determine the power produced by this engine and its thermal efficiency. Use constant specific heats at room temperature.
Answers
Answer: look at the screenshot
The power and thermal efficiency of this engine is equal to 241 Kilowatts and 48.2% respectively.
How to calculate the power and thermal efficiency?
First of all, we would determine the thermal efficiency of this engine by applying the following formula:
\(\eta= 1-\frac{1}{r_p^{k-1/k}} \\\\\eta= 1-\frac{1}{10^{1.4-1/1.4}} \\\\\eta= 1-\frac{1}{10^{0.4/1.4}}\\\\\eta= 1-\frac{1}{10^{0.4/1.4}}\\\\\eta= 1-\frac{1}{10^{0.2857}}\\\\\eta = 0.482\)
Thermal efficiency = 48.2%.
Now, we can determine net power output as follows:
\(W_{out}=nq_{in}\\\\W_{out}= 0.482 \times 500\\\\W_{out}=241\;kW.\)
Power = 241 Kilowatts.
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Which of the following is true about silicosis?
A. The damage it causes can be reversed
B. It is not a serious concern for construction workers
C. It causes only minor damage to the lungs
D. The damage it causes is irreversible
Answers
Answer:
D. The damage it causes is irreversible
Explanation:
Silicosis is a long term lung disease caused by crystalline silica dust inhalation. There is no cure, and once the damage is done it cannot be reversed.
------------------
Like stated above, the damage is irreversible. Option A is incorrect.
Construction workers are constantly moving to build whatever they're working on. The disease will make it hard to breathe and will have a heavy effect on their lungs, preventing them from properly doing their jobs. Additionally, it's possible to get the disease from this job since you're constantly inhaling dust particles.
Silicosis does major damage to the lungs. The dust particles are attacked by the immune system which causes inflammation and eventually leads to areas of hardened and scarred lung tissue.
Thus, the best option is D.
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Answer every question of this quiz
Please note: you can answer each question only once.
Which number shows the intake valve?
OK
Answers
I'd say number 4, number 3 looks like an exhaust valve
Mention any four thermodynamic properties.
Answers
Answer:
They are pressure, temperature, volume, entropy, internal energy, enthalpy, Gibbs function and Helmholtz functions
Create a Blackjack (21) game. Your version of the game will imagine only a SINGLE suit of cards, so 13 unique cards, {2,3,4,5,6,7,8,9,10,J,Q,K,A}. Upon starting, you will be given two cards from the set, non-repeating. Your program MUST then tell you the odds of receiving a beneficial card (that would put your value at 21 or less), and the odds of receiving a detrimental card (that would put your value over 21). Recall that the J, Q, and K cards are worth ‘10’ points, the A card can be worth either ‘1’ or ‘11’ points, and the other cards are worth their numerical values. FOR YOUR ASSIGNMENT: Provide two screenshots, one in which the game suggests it’s a good idea to get an extra card and the result, and one in which the game suggests it’s a bad idea to get an extra card, and the result of taking that extra card
Answers
The probability of getting 21, when first card is an ace and the second card is a queen = 0.024133.
The term blackjack means that you get a value of 21 with only two cards.
Number of cards in a deck of cards = 52
There are 4 types of cards in a deck of cards - spades, clubs, hearts, and diamonds, out of which spades and clubs are black in colour.
Given that first card is Ace and second one is a Queen.
Odds of getting an Ace are 4/52, odds of the next being Queen is 16/51.
P(blackjack)=4×16/(52/2).
where P is used for probability .
Probability: Probability is simply how likely something is to happen. Whenever we are unsure about the outcome of an event, we can talk about the probabilities of certain outcomes. The analysis of events governed by probability is called statistics.
Probability of getting an ace followed by a queen card: 4/52 * 16/51 = 0.024133.
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while analyzing an intermittent error, james, an independent contractor for hkv infrastructures, finds that the destination host is constantly asking the source to retransmit the data. he finds that the bug might be related to the transport layer of the osi model. since the tcp provides reliable delivery protocols, analyze which of the following characteristics of the tcp protocol james should check to fix this error.
Answers
If James suspects that the issue is related to the transport layer of the OSI model, then he may want to focus on the Transmission Control Protocol (TCP), which is one of the most commonly used transport protocols.
Based on the symptom of the destination host constantly asking for retransmission, it sounds like there may be issues with reliable data delivery. Here are a few characteristics of TCP that James could investigate:
Sequence numbers: TCP assigns a sequence number to each segment it sends, and uses acknowledgement numbers to confirm receipt of those segments by the receiver. If there are errors in the sequence numbers, or if acknowledgements are not being sent or received correctly, this could cause issues with reliable delivery.
Flow control: TCP uses a sliding window mechanism to manage flow control, which means that the sender will only send as much data as the receiver can handle at any given time. If there are issues with this mechanism, such as incorrect window sizes or problems with the receiver's buffer, this could also impact reliable delivery.
Retransmission timers: If a packet is lost or damaged in transit, TCP will initiate a retransmission of that packet after a certain amount of time has elapsed. If these timers are not set correctly, or if they are not being triggered when they should be, this could lead to repeated requests for retransmission.
By investigating these and other characteristics of TCP, James may be able to identify the root cause of the reliability issues and implement a solution to fix the problem.
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These standards dictate how tests are written: a) test reporting standards b) naming conventions c) document standards d) test coding standards These standards dictate how artifacts are labeled for electronic storage:
a) test reporting standards b) test coding standards c) naming conventions d) document standards If a test case is a candidate for automation, then a test script must be written in the automation language. a) True b) False These standards pertain mostly to automated testing: a) naming conventions b) test reporting standards c) document standards d) test coding standards
Answers
The answers of the given question based on Standard testing are given below ,
What is a Testing?Testing refers to the process of verifying and validating software or a system to ensure that it meets the specified requirements and works as expected. The main goal of testing is to identify defects or errors in the system before it is released to the end-users or customers.
Testing can be done manually or automatically, and it can cover different aspects of the software or system, such as functional, performance, security, usability, and compatibility testing.
These standards dictate how tests are written:
d) test coding standards
These are standards dictate how artifacts are labeled for the electronic storage:
c) naming conventions
If test case is candidate for automation, then test script must be written in automation language.
a) True
These standards pertain mostly to automated testing:
d) test coding standards
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CAN I GET ANSWERS PLEASE, I TRY THE FORMULA AND MY TEACHER HAS A FAMILY EMERGENCY SO HE CANT RESPOND BACK SO PLEASE HELP ME
Answers
Explanation:
I won't answer each of these, but will give you an explaination of how to solve for each.
You'll need to use Ohm's Law and Kirchhoff's Voltage Law.
Remember Ohm's Law as \(V = IR\).
Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.
\(E_T = E_1 + E_2 + E_3\)
A couple of other helpful notes:
These three resistors are in series which means that the current flowing through them is equal.
So it is easy to see that... \(V = IR \rightarrow E_1 = 4*2 = 8 V\)
Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).
1. In a base bias configuration with a supply voltage is 15v, what does Ver equal when reverse biased?
a. 7.5V
b. OM
c. 15V
d. the Q point
Answers
According to astm d2487, a piece of stone with a 1.5-inch diameter is considered:______.
Answers
Answer: Your answer friend is Boulder. Good luck man
Explanation: